One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second containet is 50%larger than the first and that twocontainers are are emptied into a third what percent of acid is the third container

Answers

Answer 1

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container [tex]=x \times \frac{30}{100}[/tex] = 0.3 x

The amount of acid in second container [tex]=1.5x \times \frac{50}{100}[/tex]  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = [tex]\frac{1.05x}{2.5x} \times 100%[/tex] %

                                                                     = 42%

Answer 2

Final answer:

By calculating the total acid content and total volume when two containers with different acid concentrations are mixed, we find that the third container has an acid concentration of 42%.

Explanation:

The question involves mixing two solutions of different acid concentrations and calculating the final concentration of acid. Let's assume the first container has 1 unit of volume. Since the second container is 50% larger, it has 1.5 units of volume. The first container has 30% acid, so it contains 0.3 units of acid. The second container has 50% acid, resulting in 0.75 units of acid. Together, the total volume of the solution is 2.5 units, and the total amount of acid is 1.05 units.

Therefore, the percentage of acid in the third container is calculated by dividing the total acid by the total volume: (1.05 units of acid / 2.5 units of volume) x 100% = 42%.


Related Questions

a. Is the statement​ "Every elementary row operation is​ reversible" true or​ false? Explain. A. ​True, because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement. B. ​False, because only scaling and interchanging are reversible row operations. C. ​True, because​ replacement, interchanging, and scaling are all reversible. D. ​False, because only interchanging is a reversible row operation.

Answers

The statement "Every elementary row operation is​ reversible" is true because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement (Option A is correct).

The statement "Every elementary row operation is​ reversible" is true.

The correct choice is: A. True, because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement.

- Interchanging rows (row swapping) can be reversed by another interchange.

- Scaling a row by a non-zero scalar can be reversed by scaling it by the reciprocal of that scalar.

- Replacement operations (adding or subtracting multiples of one row from another) can also be reversed by adding or subtracting the same multiples in the opposite direction.

So, all three elementary row operations (replacement, interchanging, and scaling) are reversible, which makes option A the correct choice.

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Final answer:

The statement 'Every elementary row operation is reversible' is true. All the three types of elementary row operations, i.e., scaling, interchanging, and replacement, can be reversed using appropriate methods.

Explanation:

The statement 'Every elementary row operation is reversible' is indeed true. The three types of elementary row operations, i.e., scaling, interchanging, and replacement, are all reversible. Scaling can be reversed by multiplying the row by the reciprocal of the scale factor. Interchanging rows can be undone by simply interchanging them again. Replacement can be reversed by applying a replacement operation with the opposite sign.

For example, if you multiply a row by a factor of 3 (scaling), you can reverse this by multiplying the row by 1/3. If you interchange row 1 and row 2, you can reverse this by interchanging these two rows again. Finally, if you replaced row 1 by adding 2*row 2 to it, you could reverse this by replacing row 1 by subtracting the same 2*row 2 from it.

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1. Type an equation in the equation editor that uses 2 fractions with parentheses around one of them. Example: [tex]\frac{2}{3}[/tex] + (- [tex]\frac{1}{2}[/tex]) = [tex]\frac{4}{6} - \frac{3}{6} = \frac{1}{6}[/tex]

2. Type an expression that has two terms with exponents, and one with a square root. Example: [tex]2^{3}[/tex] + [tex]9^{2}[/tex] + [tex]\sqrt{16}[/tex]

3. Type a compound inequality similar to the one below, but with different numbers. It should be set up the same, with all the symbols in the same places. [tex](\frac{3}{5} )^{2}[/tex] · [tex]^{3} \sqrt{10} \leq x^{3} - 2x + 5 \leq \sqrt{\frac{1}{3}[/tex]

Answers

Answer:

i) [tex]\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex]    [tex]\Rightarrow[/tex] \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)[tex]4^{3} + 8^{2} + \sqrt{9}[/tex]   [tex]\Rightarrow[/tex]  4^{3} + 8^{2} + \sqrt{9}

iii) [tex](\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}[/tex]    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

Step-by-step explanation:

i) [tex]\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex]    [tex]\Rightarrow[/tex] \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)[tex]4^{3} + 8^{2} + \sqrt{9}[/tex]   [tex]\Rightarrow[/tex]  4^{3} + 8^{2} + \sqrt{9}

iii) [tex](\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}[/tex]    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

The point P(21,35) is on the terminal side of an angle in standard position. What is the distance from P to the origin?

Answers

Answer:

The distance from P to origin is approximately 40.82 units.                                  

Step-by-step explanation:

We are given the following in the data:

The point P(21,35)

We have to find the distance of point P from the origin.

Coordinates of origin: (0,0)

Distance formula:

[tex](x_1,y_1),(x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

Putting the values, we get,

[tex](21,35), (0,0)\\\\d = \sqrt{(0-21)^2 + (0-35)^2} = \sqrt{1666} = 7\sqrt{34} \approx 40.82\text{ units}[/tex]

The distance from P to origin is approximately 40.82 units.

A three-phase lesson format provides a structure for students to have inquiry on a topic, engage in the content through action and discussion and time to reflect and make connections. What statement below demonstrates the Before related agendas?
A) Be sure the task is understood.
B) Let go
C) Provide extensions.
D) Identify future problems.

Answers

Answer:

A) Be sure the task is understood.

Step-by-step explanation:

The principle "Make sure the mission is understood, performed, and achieved."

Another way we talk about this principle in the Navy is through the idea of "intrusive leadership." In some respects both "micromanagement" and "intrusive leadership" sound terrible.

Think about certain great managers and leaders you have had in your career yet again. Probability are they will be the ones who asked you those difficult questions, too.

They moved everyone to new technical levels, and eye for detail. When you said you knew what you were doing or when you announced the progress of a project, they didn't necessarily take it to face value.

What is the pressure difference Δp=pinside−poutside? Use 1.28 kg/m3 for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answers

This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, [tex]1.11\times 10^3Pa[/tex]

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = [tex]\rho=1.28kg/m^3[/tex]

Area = A = 7.00 m × 12.0 m

Formula used :

[tex]\Delta P=\frac{1}{2}\times \rho \times v^2[/tex]

Now put all the given values in this formula, we get:

[tex]\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2[/tex]

[tex]\Delta P=1.11\times 10^3Pa[/tex]

Thus, the pressure difference will be, [tex]1.11\times 10^3Pa[/tex]

If the probability is 0.54 that Stock A will increase in value during the next month and the probability is 0.68 that Stock B will increase in value during the next month, what is the greatest possible value for the probability that neither of these two events will occur.

Answers

P(A) =0.54

P(B)= 0.68

P'(A)= 1-0.54 = 0.46

P'(B)= 1- 0.68 = 0.32

The probability of neither of both event will occur:

= P'(A)×P'(B)

=0.46 × 0.32

=0.1472

A test of intelligence is given to a subject. The subject scores 110 on the first administration. Six months later, the same subject is given the same test again and receives a score of 75. After another six months has passed, the subject is given the test one last time and receives a score of 138. What conclusions can be drawn from these scores?The scores are not valid.

Answers

Answer:

True, the scores are not valid.

Step-by-step explanation:

The test supposed to be measuring intelligence. We can assume that the intelligence of most people relatively stable (will not change too much over a short amount of time), and can expect it should go upward with brain growth and education. But the test seems to give a huge decrease from the first and second results. Then the third result is a huge increase that even higher than the first test.  

We don't know the true value of the subject, but seeing the huge gap for every repetition we can tell that the test result lacks precision.

X minus 12 is 30 what’s the answer

Answers

Answer:

x=42

Step-by-step explanation:

x-12=30

x=30+12

x=42

X - 12 = 30

To solve for x in this equation, we want to get x by itself on the left side of the equation. Since 12 is being subtracted from x, to get x by itself, we need to add 12 to the left side of the equation. If we add 12 to the left side, we must also add 12 to the right side.

On the left side, -12 and +12 cancel each other out so we are simply left with x. On the right side, 30 + 12 is 42 so we have x = 42.

It's important to understand that we can check our answer by substituting 42 back into the original equation.

So we have (42) - 12 = 30.

42 - 12 is 30 so we have 30 = 30 which is a true statement so our answer, x = 42, is correct.

Melody has hired a new accountant. He has gathered her pay stubs and is trying to determine how many CDs were sold during each month of the previous year. Her pay stub for June indicates that she made $4,889 in that month. Write an equation her accountant could use to determine how many CDs were sold in June

Answers

Answer:

The required equation is [tex]4889=4850 +3n[/tex].

Step-by-step explanation:

Consider the provided information.

Melody has a new job recording for the All-Time Favorites record label.

She is paid a monthly base salary of $plus $3 for each CD sold.

Her pay stub for June indicates that she made $4,889 in that month.

Let n represents the number of CDs she sold.

Therefore, the required equation is [tex]4889=4850 +3n[/tex].

A pizza chain was willing to pay $1 to each person interviewed about his or her likes and dis- likes of types of pizza crust. Of the people interviewed, 200 liked thin crust, 270 liked thick crust, 70 liked both, and 50 did not like either type of crust. What was the total cost of the survey?

Answers

Answer:

Total cost of the survey = $450

Step-by-step explanation:

Given:

Cost for each person = $1

Liked thin crust = 200 people

Liked thick crust = 270 people

Both crust like = 70 people

50 people did not like either type of crust.

We need to find the total cost of the survey.

Solution:

Number of people who like thin crust or thick crust.

⇒ 200 + 270 - 70

⇒ 470 - 70

⇒ 400

So, 400 people likes thin crust OR thick crust.

And, also 50 peoples did not likes either thin crust OR thick crust.

So, we add 50 people who did not like any type of pizza.

⇒ 400 + 50

Therefore, total cost of the survey = $450

A Norman window is a rectangle with a semicircle on top. Suppose that the perimeter of a particular Norman window is to be 24 feet. What should the rectangle's dimensions be in order to maximize the area of the window and, therefore, allow in as much light as possible?

Answers

Final answer:

To maximize the area of the Norman window, solve for the dimensions of the rectangle. Substitute the expression for 'h' in terms of 'w' into the area formula. Take the derivative of A with respect to 'w', set it equal to zero, and solve for 'w'.

Explanation:

To maximize the area of the Norman window, we need to find the dimensions of the rectangle. Let's denote the width of the rectangle as 'w' and the height as 'h'. The perimeter of the rectangle can be expressed as 2w + h + πh = 24 feet. Rearranging the equation, we have (2 + π)h + 2w = 24. Since we want to maximize the area, we can solve for 'h' in terms of 'w' using this equation.

Next, we can substitute the expression for 'h' in terms of 'w' into the area formula for the window, which is A = wh + (π/4)w^2. Simplifying this expression, we get A = (w(2 + πw))/4. To find the dimensions that maximize the area, we can take the derivative of A with respect to 'w', set it equal to zero, and solve for 'w'. This will give us the width of the rectangle. Once we have the width, we can substitute it back into the equation for 'h' to find the height.

By solving these equations, we can find the dimensions of the rectangle that will maximize the area of the Norman window, allowing in as much light as possible.

An inelastic collision occurs between a large truck and smaller sedan. Calculate the final velocity of the objects and explain the direction they will be traveling with the following data from before the collision: Small sedan mass = 1300 kg initial velocity = 20 m/s Truck mass = 7100 kg Initial Velocity 15 m/s

Answers

The final velocity is 15.8 m/s in the forward direction

Step-by-step explanation:

An inelastic collision occurs when the two object after the collision stick together.

In any case, the total momentum of the system is conserved before and after the collision, in absence of external forces. Therefore, we can write:

[tex]p_i = p_f\\m u + MU = (m+M)v[/tex]

where in this problem:

m = 1300 kg is the mass of the small sedan

u = 20 m/s is the initial velocity of the small sedan

M = 7100 kg is the mass of the truck

U = 15 m/s is the initial velocity of the truck

v is the final combined velocity of the small sedan + truck

Here we have taken both the velocity of the sedan and the truck in the positive (forward) direction

Solving the equation for v, we find the final velocity:

[tex]v=\frac{mu+MU}{m+M}=\frac{(1300)(20)+(7100)(15)}{1300+7100}=15.8 m/s[/tex]

And since the sign is positive, this means that is direction is the same as the initial direction of the sedan and the truck, so forward.

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having trouble with this and 3 others (part 3)

Answers

Answer:

a.) 23

b.) y=14

c.) 23

d.) -23

e.) T=8

f.) f=1/8

Step-by-step explanation:

a.) general equation is Asin((2π/T))

A is the amplitude. It's A value is 23

b.)  Midline = vertical_shift = 14

c.) max = positive amplitude value = 23

d.) min = negative amplitude = -23

e.) Factor out 2π from your angular frequency to get the period.

ω = π/4 = (2π)/8 = (2π)/T

Period = 8

f.) Frequency is just the inverse of the period.

f = 1/T = 1/8

The hourly operating cost of a certain plane, which seats up to 295 passengers, is estimated to be $3,945. If an airline charges passenger a fare of $95 per hour of flight, find the hourly profit P it earns operating the plane as a function of the number of passengers x. P(x) = Specify the domain. 0 lessthanorequalto x lessthanorequalto infinity 0 lessthanorequalto x lessthanorequalto 295 0 < x < 295 295 lessthanorequalto x lessthanorequalto infinity What is the least number of passengers it must carry to make a profit? The Metropolitan Company sells its latest product at a unit price of $3. Variable costs are estimated to be 50% of the total revenue, while fixed costs amount to $6,600 per month. How many units should the company sell per month to break even, assuming that it can sell up to 5,000 units per month at the planned price? units

Answers

Answer:

42 passengers 4400 units

Step-by-step explanation:

Please refer to the picture below

Study Island: Gina has 24 more barrettes than Holly. The equation g = 24 + h, where g represents the number of barrettes Gina has, and h represents the number of barrettes Holly has, shows this relationship. If Gina has 51 barrettes, how many barrettes does Holly have?

Answers

See picture for solution and answer.

Triangle A''B''C'' is formed by a reflection over x=-3 and dilation by a scale factor of 3 from the origin. Which equation shows the correct relationship between ABC and A''B''C'?

Answers

Answer: Segments AB / A"B" = √13 / 2 x √13

Step-by-step explanation:

The Triangle's vertices are at points A(-3,3), B(1,-3) and C(-3,-3).

• The reflection over x = 1 shows vertices A, B and C below:

A(-3,3)→A'(5,3);

B(1,-3)→B'(1,3);

C(-3,-3)→C'(5,-3).

• The Dilation by a scale factor of 2 from the origin is expressed as:

(x,y)→(2x,2y)

Therefore,

A'(5,3)→A''(10,6);

B'(1,3)→B''(2,6);

C'(5,-3)→C''(10,-6)

The attachment below completed the calculations and shows the segment in a simple graph.

If you have a bank account that is modeled bybthe following equation, how much money would you have after 10 years. A=5000e 0.10t. Using the problem solving Temple with rational functions.

Answers

The money after 10 years is $ 13591.4091

Solution:

Given that,

If you have a bank account that is modeled by the following equation:

[tex]A = 5000e^{0.10t}[/tex]

To find: Money after 10 years

How much money would you have after 10 years

Substitute t = 10 in above given equation

[tex]A = 5000 \times e^{0.10 \times 10}\\\\A = 5000 \times e^{1}\\\\A = 5000 \times 2.71828\\\\A = 13591.4091[/tex]

Thus money after 10 years is $ 13591.4091

A certain solution of salt water is 10% salt and weighs 50 pounds. more salt must be added to produce a solution that is 25% salt. if x represents the pounds of salt to be added, which of the following expressions represents the number of pounds of salt in the 25% solution?
a) 0.25 (x+50)
b) 0.25x
c) 1.25 (x+50)

Answers

Answer

7.5 pounds

Step-by-step explanation:

Since adding x grams of salt will bring th percentage of the salt to 25

Hence. 10% of the 50 gram gives. 5 gram initial salt before it is added.

5+ x/ 50 * 100= 25/

5+x /50 = 0.25

5+x = 12.5

X= 12.5- 5

X= 7.5pounds

Evaluate 13−0.5w+6x13-0.5w+6x 13−0.5w+6x 13, minus, 0, point, 5, w, plus, 6, x when w=10w=10 w=10 w, equals, 10 and x=12x=\dfrac12 x= 2 1 ​ x, equals, start fraction, 1, divided by, 2, end fraction .

Answers

Answer: 6x^13-1.5w+156x+13 is the answer to the first equation and is that another equation?

Final answer:

The expression 13 - 0.5w + 6x evaluates to 11 when substituting w=10 and x=1/2.

Explanation:

The problem is to evaluate the expression 13 - 0.5w + 6x given the values w=10 and x=1/2. Following the order of operations, we first substitute the given values into the expression.

13 - 0.5(10) + 6(1/2) = 13 - 5 + 3 = 11.

The result of the evaluated expression is 11.

The nieces is it a ladder to clean the outside of her second-story windows the lashes is it is 24 feet long and she puts the base of the lead 13 feet away from the house in order to avoid her flower girl that's how high up the side of the house does the Ladder reach

Answers

Answer: 20 feet

Step-by-step explanation:

in the attachment

Final answer:

The ladder reaches approximately 19.8 feet up the side of the house, as determined using the Pythagorean theorem.

Explanation:

The question is asking us to find the height the ladder reaches up the side of the house. This is a problem dealing with right triangles and can be solved using the Pythagorean theorem, which is a^2 + b^2 = c^2, where 'a' and 'b' are the shorter sides (base and height of the house) and 'c' is the hypotenuse (the ladder).

In this case, the ladder is 24 feet long (this is our c), and the base of the ladder is 13 feet from the house (this is our a). We are trying to find b (the height of the house the ladder reaches).

Substitute these values into the Pythagorean theorem and solve for 'b':

13^2 + b^2 = 24^2
b^2 = 24^2 - 13^2
b = sqrt(24^2 - 13^2)

So, the height that the ladder reaches up the side of the house is approximately 19.8 feet.

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The perimeter of a rectangular note card is 18 inches. The area is 18 square inches. What are the dimensions of the note card?

Answers

Answer:

6 by 3

Step-by-step explanation:

a rectangle as 2 equal sides. so if we know that it is 6 by 3, then 6+6+3+3

=12+6=18

the area of a rectangle is base * height. so 6 * 3 = 18

Answer: the length is 6 inches and the width is 3 inches.

Step-by-step explanation:

Let L represent the length of the rectangular note card.

Let W represent the width of the rectangular note card.

The formula for determining the area of a rectangle is expressed as

Area = L × W

Area of the note card would be

LW = 18 - - - - - - - - - - - - 1

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

Perimeter of the note card would be

2(L + W) = 18

(L + W) = 9 - - - - - - - - - - - - 2

Substituting L = 9 - W into equation 1, it becomes

W(9 - W) = 18

9W - W² = 18

W² - 9W + 18 = 0

W² - 6W - 3W + 18 = 0

W(W - 6) - 3(W - 6) = 0

W - 6 = 0 or W - 3 = 0

W = 6 or W = 3

Substituting W = 3 into equation 1, it becomes

3L = 18

L = 18/3 = 6

use multiplier method to increase £88 by 14%. you must show all your working out

Answers

Answer:

  £100.32

Step-by-step explanation:

£88 + 14% × £88 = £88×(1 +0.14)

  = 1.14×£88

  = £100.32 . . . . using a calculator

£100.32 is £88 increased by 14%.

Final answer:

£100.32

Explanation:

To increase an amount by a certain percentage using the multiplier method, you can use the following steps:

Convert the percentage increase to a decimal by dividing by 100. In this case, 14% becomes 0.14.Add 1 to the decimal to get the multiplier. Here, 1 + 0.14 = 1.14.Multiply the original amount by the multiplier. So, £88 multiplied by 1.14 gives us the increased amount.

Let's do the calculation:

Step 1: Convert the percentage to a decimal. 14% / 100 = 0.14Step 2: Calculate the multiplier. 1 + 0.14 = 1.14Step 3: Multiply £88 by the multiplier. £88 x 1.14 = £100.32

x-6y +4z=-12
x+y-4z=12
2x + 2y + 5z =-15
Systems of equations with three variables and three equations

Answers

Answer:

x = 0 , y = 0 , z = -3

Step-by-step explanation:

Solve the following system:

{x - 6 y + 4 z = -12 | (equation 1)

x + y - 4 z = 12 | (equation 2)

2 x + 2 y + 5 z = -15 | (equation 3)

Swap equation 1 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

x + y - 4 z = 12 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - (13 z)/2 = 39/2 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Multiply equation 2 by 2/13:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 7 y + (3 z)/2 = -9/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 14 y + 3 z = -9 | (equation 3)

Swap equation 2 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y - z = 3 | (equation 3)

Multiply equation 3 by -1:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by -14:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{2 x + 0 y+5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 5 × (equation 3) from equation 1:

{2 x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer: {x = 0 , y = 0 , z = -3

Final answer:

To solve the given system of equations, use the method of elimination to eliminate one variable at a time and solve for the remaining variables.

Explanation:

To solve the system of equations:

x - 6y + 4z = -12

x + y - 4z = 12

2x + 2y + 5z = -15

We can use the method of substitution or elimination. Let's use the method of elimination:

Multiply the second equation by 2:Multiply the third equation by 3:Add the new second and third equations to the first equation:Solve the resulting equation:

Therefore, the solution is x = -5, y = 4, and z = 1.

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What proportional segment lengths verify that XZ¯¯¯¯¯∥PQ¯¯¯¯¯ ?

Fill in the boxes to correctly complete the proportion.

Answers

Answer:

[tex]\frac{16}{21}=\frac{8}{10.5}[/tex]

or

[tex]\frac{16}{8}=\frac{21}{10.5}[/tex]

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its corresponding sides is proportional

In this problem

triangle YPQ and triangle YXZ are similar by AA Similarity Theorem

so

[tex]\frac{YP}{YX}=\frac{YQ}{YZ}[/tex]

substitute the given values

[tex]\frac{16}{21}=\frac{8}{10.5}[/tex]

Rewrite

[tex]\frac{16}{8}=\frac{21}{10.5}[/tex]

The boxes should be filled with [tex]\frac{16}{21} = \frac{8}{10.5}\\\\\frac{16}{8} = \frac{21}{10.5}[/tex]

The calculation is as follows:

As we know that

In the case when two figures are similar so the ratio of its corresponding sides is proportional

In this given situation  

triangle YPQ and triangle YXZ are similar by AA Similarity Theorem

So,

[tex]\frac{YP}{YX} = \frac{YQ}{YZ}[/tex]

[tex]\frac{16}{21} = \frac{8}{10.5}\\\\\frac{16}{8} = \frac{21}{10.5}[/tex]

It can be any of the both.

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Find the first 3 Iterations of the function here: g(x)=1/3x+1 if you have an initial value of 2.

An example on how to complete it below.

Answers

Answer:

1st it: g(2)=1/3(2)+1=0.67+1=1.67

2nd it: g^2(2)=1/3(1.67)+1=0.56+1=1.56

3rd it: g^3(2)=1/3(1.56)+1=0.52+1=1.52

Answer:

The first three iterations are 1.67, 1.56 and 1.52

Step-by-step explanation:

Given the function g(x)=1/3x+1

To get the first threw iteration with initial value of x = 2

First iteration at x= 2:

g(2) = 2/3+1

g(2) = (2+3)/3

g(2) = 5/3 = 1.67

Second iteration will be when x = g(2) = 5/3

g²(2) = g(5/3) = 1/3(5/3) + 1

g²(2) = g(5/3) = 5/9 + 1

g²(2) = g(5/3) = 14/9 = 1.56

Third iteration will be at when

x = g²(2) = 14/9

g³(2) = g(14/9) = 1/3(14/9) + 1

g³(2) = g(14/9) = 14/27 + 1

g³(2) = g(14/9) = 41/27 = 1.52

The first three iterations are 1.67, 1.56 and 1.52

The US GDP (Gross Domestic Product) for 2014 was a reported 17.555 trillion dollars. The current US population is about 320 million people. Round all answers to the nearest hundredth.

Answers

Answer:

1. 1.76x10^13,

2. 3.20x10^8,

3. 5.5x10^4

Step-by-step explanation:

Answer:

Step-by-step explanation:

GDP/POPULATION

1755x10^13/3.2x10^8 = .05484x10^5

=5.484x10^4

= 5.49x10^4

Suppose you are choosing between two roads. The first route is 40 miles at 25 mph, and the second road is 65 miles at 55 mph. Which route would get you there faster, and in what amount of time?
The second route, in 1.6 hours
B. The first route, in 1.6 hours
C. The first route, in 1.18 hours
D. The second route, in 1.18 hours

Answers

Answer:

  D. The second route, in 1.18 hours

Step-by-step explanation:

The appropriate relation is ...

  time = distance/speed

The time required on the first route is ...

  time1 = (40 mi)/(25 mi/h) = 40/25 h = 1.6 h

The time required on the second route is ...

  time2 = (65 mi)/(55 mi/h) = 65/55 h = 1 2/11 h ≈ 1.18 h

__

The second route requires a shorter time, so will get you there faster. The second route will get you there in 1.18 hours.

A Cepheid variable star is a star whose brightness alternately increases and decreases. Suppose that Cephei Joe is a star for which the interval between times of maximum brightness is 6.6 days. Its average brightness is 2.6 and the brightness changes by /-0.6. Using this data, we can construct a mathematical model for the brightness of Cephei Joe at time t, where t is measured in days:

(a) Find the rate of change of the brightness after t days.
(b) Find the rate of increase after one day.

Answers

Answer:

a) Rate of brightness after t days = B(t) = 2.6 + 0.6sin(2×3.142 t /6.6)

b) 0.57

Step-by-step explanation:

Given

Number of days=6,6 days

Average brightness =2.6

B(t)= 2.6 + 0.6 sin (2× 3.142t/6.6)

b) B(1day) = 0.6 ×(2×3.142/6.6)cos (2×3.142/6.6)

B(1 day) = 0.6 × (6.248/6.6)cos 0.952

B(1 day) =0.6 × 0.952 ×0.9999

B(1day) = 0.5711

= 0.57

From January to June, a company spent $60 per month on office supplies. In July the price of office supplies increased by 15% and remained the same for the rest of the year. How much did the company spend an office supplies for the year

Answers

Answer:

$774

Step-by-step explanation:

We have been given that from January to June, a company spent $60 per month on office supplies. In July the price of office supplies increased by 15% and remained the same for the rest of the year.

Let us find increased cost of supplies as shown below:

[tex]\text{Increased cost of supplies}=60+\frac{15}{100}\times 60[/tex]

[tex]\text{Increased cost of supplies}=60+0.15\times 60[/tex]

[tex]\text{Increased cost of supplies}=60+9[/tex]

[tex]\text{Increased cost of supplies}=69[/tex]

There are 6 months from January to June, so cost of supplies on these 6 months would be 6 times $60.

There are 6 months from July to December, so cost of these months would be 6 times $69.

Total cost will be equal to sum of these two amounts.

[tex]\text{Amount spent on office supply in the year}=6\times \$60+6\times \$69[/tex]

[tex]\text{Amount spent on office supply in the year}=6( \$60+\$69)[/tex]

[tex]\text{Amount spent on office supply in the year}=6( \$129)[/tex]

[tex]\text{Amount spent on office supply in the year}=\$774[/tex]

Therefore, $774 were spent on office supplies.

How many possible combined page count and color choices are possible? How does this number relate to the number of page size choices and to the number of color choices

Answers

ANSWER:

1. How many possible combined page count and color choices are possible?

There are  3 choices for page size and 4 choices for color, and also, there are 3*4=12 possibilities to combine page size and color.

Number possibilities to combine and number of choices for size is: 12:3=4:1

Number of possibilities to combine and number of choices for color is 12:4=3:1

2. How does this number relate to the number of page size choices and to the number of color choices

There are 12 possibilities to combine size and color.

Number of possibilities to combine and number of choices for size is 4:1

Number of possibilities to combine and number of choices for color is 3:1

Answer:

We have 12 possibilities to combine page size and color.

Number of possibilities and number of choices is 12:4 that is 3:1

Step-by-step explanation:

have a nice day.

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