Objects with higher temperatures:________________.1. emit only shortwave radiation. 2. emit most of their energy in the form of longwave energy. 3. radiate less total energy than cooler objects radiate. 4. emit more shortwave radiation than cooler objects do.

25.55 grams of tetraphosphorus decaoxide could be produced by the reaction.

Explanation:

First the balanced chemical reaction of the production of tetraphosphorus decaoxide is to be known.

The chemical equation is

10 KClO3 + 3P4⇒ 3 P4010 + 10 KCl

The number of moles of KCLO3 will be calculated by the formula:

number of moles = mass of the compound given ÷ atomic mass of the compound

n = 37.1 ÷ 122.55     ( atomic mass of KClO3 is 122.55 gm/mole)

   = 0.30 moles

From the stoichiometry

10 moles of KClO3 is required to produce 3 moles of P4O10

when 0.30 moles of KClO3 is used x moles of P4O10 is formed

thus, 3 ÷ 10 = x ÷ 0.30

   = 0.09 moles of KClO3 is produced

To know the mass of P4O10 apply the formula

mass = number of moles × atomic mass

        = 0.09 × 283.886   ( atomic mass of P4O10 is 283.88 gram/mole)

         = 25.55 grams of P4O10 could be produced.

To calculate the time required for the reactant concentration to drop to 18% of its initial value in a first-order reaction, we can use the integrated rate law equation and solve for time.

The given question is about a first-order reaction and the task is to calculate the time required for the reactant concentration to drop to 18% of its initial value. In order to solve this, we can use the first-order integrated rate law equation: ln([A]/[A]0) = -kt, where [A] is the reactant concentration at a given time, [A]0 is the initial reactant concentration, k is the rate constant, t is the time, and ln is the natural logarithm function. Rearranging the equation, we get t = -ln(18/100)/k. Substituting the given rate constant (k = 5.50×10−3 s−1) into the equation, we can calculate the time required.

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The time for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] in a first-order reaction is about 378 seconds.

To find out how long it will take for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value in a first-order reaction, we can use the integrated rate law formula:

Here, [A] is the final concentration, [A]₀ is the initial concentration, k is the rate constant, and t is the time. Given that the rate constant (k) is 5.50 × 10⁻³ s⁻¹ and for the concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value, we need [tex]\frac{[A]}{[A]_0} = \frac{1}{8}[/tex]:

Therefore, it will take approximately 378 seconds for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value.

Complete Question: -

A certain first-order reaction has a rate constant of 5.50×10⁻³ s⁻¹. How long will it take for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value?

Answer:

The answer to your question is   P N₂ = 11.67 atm  

Explanation:

Data

He  1737 torr

N₂  = ?

Ar 2087 mmHG

Total pressure = 16.7 atm

Process

1.- Convert torr to atm

             1 atm --------------- 760 torr

             x        -------------- 1737 torr

             x = (1737 x 1)/760

             x = 2.29 atm

2.- Convert mmHg to atm

             1 atm ----------------- 760 mmHg

             x         ---------------- 2087 mmHG

             x = (2087 x 1)/760

             x = 2.74

3.- Find the Partial pressure of N₂

       Total pressure = He pressure + N₂ pressure + Ar pressure

- Substitution

        16.7 = 2.29 + P N₂ + 2.74

- Solve for P N₂

        P N₂ = 16.7 - 2.29 - 2.74

        P N₂ = 11.67 atm      

Answer:

it is acidified with concentrated hydrochloric acid.

Final answer:

Humans contribute to excessive levels of phosphorus through the use of phosphorus-containing detergents, artificial fertilizers, and runoff from animal husbandry. This leads to eutrophication in aquatic ecosystems.

Explanation:

Humans contribute to excessive levels of phosphorus through activities such as using detergents that contain phosphorus, using artificial fertilizers that contain phosphorus, and runoff from animal husbandry. When phosphorus-containing detergents were introduced in the 1950s, it increased the amount of phosphorus available to algae and other plant life in wastewater. This led to excessive growth of algae in lakes, which decreased oxygen levels and caused harm to fish and other aquatic organisms.

43.56 grams of  are produced if 16g of  CH4 reacts with 64g of O2.

Explanation:

Balance equation for the reaction:

CH4 + 2O2⇒ CO2 +2H2O

Data given : mass of CH4 =16 grams  atomic mass = 16.04 grams/mole

                    mass of water 36 gram  atomic mass = 18 grams/moles

                   mass of CO2=?                atomic mass = 44.01 grams/mole

number of moles = [tex]\frac{mass}{atomic mass of one mole}[/tex]    equation 1

number of moles in CH4

   n = [tex]\frac{16}{16.04}[/tex]

       = 0.99 moles

Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.

From the equation

1 mole of CH4 gave 1 mole of CO2

O.99 moles of CH4 will give x moles of CO2

[tex]\frac{1}{1}[/tex] = [tex]\frac{x}{0.99}[/tex]

x = 0.99 moles of carbon dioxide

grams of CO2 = number of moles x atomic mass

                         = 0.99 x 44.01

                          = 43.56 grams of CO2 is produced.

(a)  9.4 X 10¹³s⁻¹

(b) 240 W

Explanation:

Given-

Current, i = 15μA

Electrons, e = 16 MeV

(a) The rate at which the deuterons strike the block, r = ?

We know,

[tex]i = \frac{dq}{dt} = e\frac{dN}{dt}[/tex]

[tex]\frac{dN}{dt} = \frac{i}{e} \\\\\frac{dN}{dt} = \frac{15 X 10^-^6 A}{1.6 X 10^-^1^9C}[/tex]

[tex]\frac{dN}{dt} = 9.4 X 10^1^3 s^-^1[/tex]

Therefore, the rate at which the deuterons strike the block is 9.4 X 10¹³s⁻¹

(b) Rate at which thermal energy is produced in the block

Now that we have [tex]\frac{d_{N} }{d_{t} }[/tex], we can use it with the equation of power to solve for the thermal energy production rate.

[tex]P = \frac{dN}{dt} U\\\\P = (9.4 X 10^1^3 s^-^1) (16MeV) \frac{(1.6 X 10^-^1^3 J}{1MeV} )\\\\P = 240W[/tex]

Therefore, the rate at which thermal energy is produced in the block is 240 W.

Answer:

NaNO₃ and AgCl are the two products that can be formed.

Sodium nitrate, an aqueous solution and a solid silver chloride (precipitate)

Explanation:

We determine the dissociation of both salts

AgNO₃ (aq) → Ag⁺ (aq) + NO₃⁻ (aq)

NaCl (aq) →  Na⁺ (aq) + Cl⁻ (aq)

We make the ionic equation:

Ag⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) → NaNO₃(aq) + AgCl (s) ↓

NaNO₃ and AgCl are the two products that can be formed on exchanging ions.

Sodium nitrate, an aqueous solution and a solid silver chloride (precipitate)

We determine the dissociation of both salts.

AgNO₃ (aq) → Ag⁺ (aq) + NO₃⁻ (aq)

NaCl (aq) →  Na⁺ (aq) + Cl⁻ (aq)

Ionic equation:

Ag⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) → NaNO₃(aq) + AgCl (s) ↓

Thus, NaNO₃ and AgCl are the two products that can be formed.

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Answer : The enthalpy of this reaction is, 0.975 kJ/mol

Explanation :

First we have to calculate the heat produced.

[tex]q=m\times c\times (T_2-T_1)[/tex]

where,

q = heat produced = ?

m = mass of solution = 126 g

c = specific heat capacity of water = [tex]4.18J/g^oC[/tex]

[tex]T_1[/tex] = initial temperature = [tex]21.00^oC[/tex]

[tex]T_2[/tex] = final temperature = [tex]24.70^oC[/tex]

Now put all the given values in the above formula, we get:

[tex]q=126g\times 4.18J/g^oC\times (24.70-21.00)^oC[/tex]

[tex]q=1948.716J=1.95kJ[/tex]

Now we have to calculate the enthalpy of this reaction.

[tex]\Delta H=\frac{q}{n}[/tex]

where,

[tex]\Delta H[/tex] = enthalpy change = ?

q = heat released = 1.95 kJ

n = moles of compound = 2.00 mol

Now put all the given values in the above formula, we get:

[tex]\Delta H=\frac{1.95kJ}{2.00mole}[/tex]

[tex]\Delta H=0.975kJ/mol[/tex]

Thus, the enthalpy of this reaction is, 0.975 kJ/mol

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

[tex]\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c}[/tex] where

[tex]v_r[/tex] = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

[tex]\lambda_{rw}[/tex] = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

[tex]\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458}[/tex] or [tex]v_r[/tex] = 68518.7699 m/s or 68.52 km/s

Answer:

Explanation:

1) An aerosol can contains gases under a pressure of 4.50 atm at 20.0 degrees Celsius. If the can is left on a hot, sandy beach, the pressure of the gases increases to 4.78 atm. What is the Celsius temperature on the beach?

Given data:

Initial pressure = 4.50 atm

Initial temperature = 20.0°C (20 +273 = 293 K)

Final pressure = 4.78 atm

Final temperature = ?  (in °C)

Solution:

According to the Gay-Lussac law,

The temperature of given constant amount of a gas at constant volume is directly proportional to its absolute temperature.

Mathematical expression:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

Now we will put the values:

P₁/T₁ = P₂/T₂

4.50 atm / 293 k = 4.78 atm / T₂

T₂ = 4.78 atm. 293 k / 4.50 atm

T₂ = 1400.54  atm.K  / 4.50 atm

T₂ = = 311.23 k

K to °C

311.23 k - 273.15 = 38.08°C

2) A sample of gas contains NO, NO2, and N2O. The pressure of the gas mixture is 4.68 atm. The pressure of NO is 501.6 mm Hg, whereas the pressure of NO2 is 2.54 atm. What is the pressure of N2O? HINT: All pressure units must be the same.

Given data:

Total pressure of gaseous mixture = 4.68 atm

Pressure of NO = 501.6 mmHg

Pressure of NO₂ = 2.54 atm

Pressure of N₂O = ?

Solution:

The given problem will be solve through the Dalton law of partial pressure.

According to this law,

" The total pressure of mixture of a gas is equal to the sum of partial pressure of all the component of gas"

Now we will convert the pressure of NO₂  in to atm.

Pressure of NO = 501.6/760 = 0.66 atm

Formula:

Total pressure = partial pressure of NO +  partial pressure of NO₂  +  partial pressure of N₂O

4.68 atm = 0.66 atm +  2.54 atm +  partial pressure of N₂O

4.68 atm = 3.2 atm +  partial pressure of N₂O

Partial pressure of N₂O = 4.68 atm - 3.2 atm

Partial pressure of N₂O = 1.48 atm

To confirm the answer:

Total pressure = partial pressure of NO +  partial pressure of NO₂  +  partial pressure of N₂O

4.68 atm =  0.66 atm +  2.54 atm +  1.48 atm

4.68 atm = 4.68 atm

Answer:

the correct option is 3 = 10−12 mol/cm2 moles of Na+ must move per unit area of membrane.

Explanation:

The capacitance is given by ;

the specific capacitance ;

it is said that the potential changes from -70 mV to +30 mV

= 100mV

The charge moving per unit area;

= 100mV X 10^-3V/1mV X 1microF X 10^-6F/1microF

= 1 X 10^-7C/m^2

= 10^-12mol/cm^2

As such, the correct option is 3 = 10−12 mol/cm2  moles of Na+ must move per unit area of membrane.

c. [tex]\( 10^{-12}\ \text{mol/cm}^2 \)[/tex] are the number of moles of Na⁺.

To solve this problem, we need to determine the number of moles of Na⁺ ions that must move to change the membrane potential [tex](\( V_m \))[/tex] from -70 mV to +30 mV, assuming the membrane behaves purely as a capacitor.

The key steps involve understanding the relationship between the charge Q, capacitance C, and potential difference V in a capacitor, and then converting the charge to moles of Na⁺ ions.

1. Determine the change in membrane potential [tex](\( \Delta V_m \))[/tex]:

  [tex]\[ \Delta V_m = V_{\text{final}} - V_{\text{initial}} = 30 \, \text{mV} - (-70 \, \text{mV}) = 100 \, \text{mV} \][/tex]

2. Calculate the charge required to change the membrane potential Q using the capacitance C:

  Given:

  [tex]\( C = 1 \, \mu\text{F/cm}^2 = 1 \times 10^{-6} \, \text{F/cm}^2 \)[/tex]

  [tex]\( \Delta V_m = 100 \, \text{mV} = 100 \times 10^{-3} \, \text{V} \)[/tex]

  The relationship between charge, capacitance, and potential difference is given by:

  [tex]\[ Q = C \cdot \Delta V_m \][/tex]

  Substituting the values:

  [tex]\[ Q = (1 \times 10^{-6} \, \text{F/cm}^2) \cdot (100 \times 10^{-3} \, \text{V}) \][/tex]

  [tex]\[ Q = 1 \times 10^{-6} \times 100 \times 10^{-3} \, \text{C/cm}^2 \][/tex]

  [tex]\[ Q = 1 \times 10^{-8} \, \text{C/cm}^2 \][/tex]

3. Convert the charge to moles of Na⁺ ions:

  The Faraday constant F is given as [tex]\( 10^5 \, \text{C/mol} \)[/tex]. This means 1 mole of monovalent ions (like Na⁺ carries [tex]\( 10^5 \, \text{C} \)[/tex].

  To find the number of moles of Na⁺ ions that correspond to the charge calculated, we use:

  [tex]\[ \text{Moles of } \text{Na}^+ = \frac{Q}{F} \][/tex]

  Substituting the values:

  [tex]\[ \text{Moles of } \text{Na}^+ = \frac{1 \times 10^{-8} \, \text{C/cm}^2}{10^5 \, \text{C/mol}} \][/tex]

[tex]\[ \text{Moles of } \text{Na}^+ = 1 \times 10^{-13} \, \text{mol/cm}^2 \][/tex]

However, it seems there may be a small numerical adjustment to match the provided answer options more closely.

Thus, the correct answer is c. [tex]\( 10^{-12} \text{mol/cm}^2 \)[/tex].

Complete Question:

Upon fertilization, the eggs of many species undergo a rapid change in potential difference across their outer membrane. This change affects the physiological development of the eggs. The potential difference across the membrane is called the membrane potential, Vm, which is the potential inside the membrane minus the potential outside it. The membrane potential arises when enzymes use the energy available in ATP to expel three sodium ions (Na+) actively and accumulate two potassium ions (K+) inside the membrane making the interior less positively charged than the exterior. The egg membrane behaves as a capacitor with a capacitance of about 1 μF/cm2. The concentration of Na+ is about 30 mmol/L in the eggs' interior but 450 mmol/L in the surrounding seawater. The K+ concentration is about 200 mmol/L inside but 10 mmol/L outside. A useful constant that connects electrical and chemical units is the Faraday number, which has a value of approximately 105 C/mol; that is, Avogadro's number (a mole) of monovalent ions, such as Na+ or K+, carries a charge of 10⁵ C.

How many moles of Na+ must move per unit area of membrane to change Vm from -70 mV to +30 mV, if we assume that the membrane behaves purely as a capacitor?

a. 10⁻⁴ mol/cm²

b. 10⁻₉ mol/cm²

c. 10⁻¹² mol/cm²

d. 10⁻¹⁴ mol/cm²

Answer:

           [tex]\large\boxed{\large\boxed{24.6kJ}}[/tex]

Explanation:

1. Energy to heat the liquid water from 55ºC to 100ºC

     [tex]Q=m\times C\times \Delta T[/tex]

     [tex]Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J[/tex]

2. Energy to change the liquid to steam at 100ºC

      [tex]L=\lambda \times n[/tex]

      [tex]L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J[/tex]

3. Total energy

       [tex]1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ[/tex]

To heat and vaporize 10.1 g of water from 55 ℃ to 100 ℃, 1.893 kJ is required for heating and 22.7643 kJ for vaporization, resulting in a total energy requirement of 24.6573 kJ.

The student is asking about the calculation of energy to heat and vaporize water. To perform the calculation, we will use two different properties of water: its specific heat capacity and its molar heat of vaporization.

Firstly, we need to calculate the energy required to heat the water from 55 ℃ to 100 ℃. The specific heat capacity of liquid water is 4.184 J/g°C. Using the formula q = mcΔT, where q is the heat energy, m is the mass of the water, and ΔT is the temperature change, we can calculate the required energy to heat the water.

q = (10.1 g)(4.184 J/g°C)(100 ℃ - 55 ℃)= (10.1 g)(4.184 J/g°C)(45 ℃)= 1892.964 J or 1.893 kJ

Secondly, we calculate the energy required to vaporize the water at 100 ℃. We need the molar heat of vaporization of water, which is 40.6 kJ/mol. To do this, we convert the mass of water to moles (given that the molar mass of water is approximately 18.02 g/mol), and then multiply by the molar heat of vaporization.

Moles of water = mass of water / molar mass of water
= 10.1 g / 18.02 g/mol≈ 0.5605 mol

Energy for vaporization = moles of water × molar heat of vaporization
= 0.5605 mol × 40.6 kJ/mol≈ 22.7643 kJ

The total energy required is the sum of the energy to heat the water and the energy to vaporize it:
Total energy = energy to heat + energy to vaporize
= 1.893 kJ + 22.7643 kJ≈ 24.6573 kJ

Answer:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

Explanation:

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] (1)

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

x = 0.000859

As [H₃O⁺] = x; [H₃O⁺] = 0.000859M

I hope it helps!

Answer: D.

Explanation: Condenser and Evaporator

Condenser: is a unit used in condensing a gaseous substance into a liquid state through cooling. By so doing, the latent heat is released by the substance and transferred to the surrounding environment.

Evaporator;  is a device thats turns the liquid form of a chemical substance such as water into its gaseous-form/vapor.

In the refrigeration cycle, the condenser and evaporator are used to convert vapor to liquid and then back to vapor.

In the refrigeration cycle, the components used to convert vapor into a liquid and then change the liquid back into vapor are the condenser and evaporator. The condenser facilitates the transformation of the refrigerant from a hot gas to a cooler liquid, and the evaporator helps transform that liquid back into a gas or vapor.

The entire process of the refrigeration cycle involves many more steps and components, but primarily, the condenser and evaporator perform the changes in states of matter.

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Answer: The given statement is false.

Explanation:

When there is more difference in the ratio or number of protons and neutrons then nucleus of the atom becomes unstable in nature. This unstability is caused due to greater repulsion between the like charges of sub-atomic particles.

As a result, this force of repulsion becomes greater than the binding energy. And, this force is known as the weak force because it is unable to bind the neutrons and protons together.

The proton and neutron ratio for smaller elements is 1:1 and for higher elements it has to be 1:5. Since, [tex]^{8}Be[/tex] is a smaller element with 4 protons and 4 neutrons. Hence, the proton and neutron ratio is 1:1.

Therefore, [tex]^{8}Be[/tex] is stable in nature.

Thus, we can conclude that the statement nucleus of 8Be, which consists of four protons and four neutrons, is very unstable and spontaneously breaks into two alpha particles (helium nuclei, each consisting of two protons and two neutrons), is false.

Answer:

1. Hydrogen

Explanation:

These planets contain liquid hydrogen in their interior, while the earth has liquid iron in it.

When liquid hydrogen is in tremendous pressure enviroments, the electrons  that make up each atom of this element end up "jumping" to other atoms. These "jumps" allow liquid hydrogen to behave like a metal.

In addition, with the constant energy released by the nucleus of planets like Jupiter and Saturn, as well as their rotations, the liquid hydrogen receives induction of currents, giving rise to extremely powerful magnetic fields.

The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's magnetism is hydrogen. Therefore the correct option is 1.

The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's magnetism is hydrogen. In the giant planets such as Jupiter and Saturn, pressures become so immense that hydrogen changes from a gaseous state to a liquid state. Deeper inside these planets, the liquid hydrogen is further compressed until it begins to exhibit metallic properties, such as the ability of its electrons to move freely, which enables it to conduct electricity. This transition occurs because, in a metal, electrons are not bound tightly to their parent nuclei, allowing for easier movement. This property of liquid metallic hydrogen is crucial for the generation of magnetic fields in Jupiter and Saturn.

Valence electrons are located in the highest energy level of an atom and they participate in the formation of chemical bonds. They do not occupy the inner shell orbitals. These properties make them crucial for chemical reactions.

Valence electrons are the electrons that are present in the outermost shell of an atom. These electrons are the ones that participate in chemical bonding as they are at the highest energy level. However, valence electrons do not occupy the inner shell orbitals. The inner shell orbitals are occupied by what we call core electrons.

In the context of bonding, it's incorrect to say that valence electrons are not involved. One of the key properties of valence electrons is that they are involved in the formation of bonds between atoms. This is because their position in the outermost shell enables them to be easily transferred or shared with other atoms to achieve a stable electron configuration.

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Answer:

The answer to the question is

The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.

Explanation:

To solve the question, we write out the chemical equation as follows

NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)

From the above equation, it is observed that only the gaseous products contribute to the partial pressure

Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases

However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S

Then PNH₃  = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.

Answer:

[tex]FeCl_{3}[/tex]

Explanation:

[tex]Moles =\frac {Given\ mass}{Molar\ mass}[/tex]

mass of Fe = 55.85 g

Molar mass of Fe = 55.85 g/mol

Moles of Fe = 55.85 / 55.85 = 1

mass of Cl = 106.5 g

Molar mass of Cl = 35.5 g/mol

Moles of Cl = 106.5 / 35.5 = 3

Taking the simplest ratio for Fe and Cl as:

1 : 3

The empirical formula is = [tex]FeCl_{3}[/tex]

Answer:

see explain

Explanation:

Given that,

Water pressure  P 1 = 20 psia

Water temperature  T 1 = 80F

Steam pressure  P 2 = 20 psia

Calculating the enthalpy of steam and water at given pressure and temperature by using a steam table

h 1 = 48.07 BTU/lb

h 2 = 1156.20  BTU/lb

The enthalpy of water is determine using the saturated liquid approximation for the given temperature with the data from A -4E. the enthalpy of the vapor is determine from A - 5E for given pressure .the enthalpy of the mixture is determine from the energy balance.

[tex]m_1h_1 + m_2h_2 = m_3h_3\\m_1h_1 + m_2h_2 =2mh_3\\h_3 = \frac{h_1 + h_2}{2} \\= \frac{48.07 + 1156.2}{2} \\602.135\frac{btu}{ibm} \\[/tex]

the quality of the mixture is determine from the total enthalpy and the enthaipies of the constituent at the given pressure obtained from A - 5E

[tex]q = \frac{h_3 - h_l_i_q_2_0}{h_e_v_a_p_2_0} \\ = \frac{602.135 - 196.27}{959.93} \\ = 0.423[/tex]

≅ 0.4

the mixture temperature is simply the saturation temperature for the given pressure obtain from A - 5E

T₃ = 227.92°F

≅ 230°F

Answer:

Rods and Cone can best fill in the spaces.

Explanation:

Bipolar cells exist between photoreceptors (rod cells and cone cells) and ganglion cells. They act, directly or indirectly, to transmit signals from the photoreceptors to the ganglion cells.

Bipolar cells receive synaptic input from either rods or cones, or both rods and cones, though they are generally designated rod bipolar or cone bipolar cells. There are roughly 10 distinct forms of cone bipolar cells, however, only one rod bipolar cell, due to the rod receptor arriving later in the evolutionary history than the cone receptor.

In the dark, a photoreceptor (rod/cone) cell will release glutamate, which inhibits the ON bipolar cells and excites (depolarizes) the OFF bipolar cells. In light, however, light strikes the photoreceptor which causes the photoreceptor to be inhibited (hyperpolarized) due to the activation of opsins which activate All trans-Retinal, giving energy to stimulate G-Protein coupled receptors to activate phosphodiesterase (PDE) which cleaves cGMP into 5'-GMP. That is the mechanism of reaction.

Multiple photoreceptor cells send combined messages to a bipolar cell, and a single photoreceptor may directly link to a single bipolar cell.

The correct answer to the question is: Multiple photoreceptor cells send combined messages to a bipolar cell, whereas a single photoreceptor may link directly to a single bipolar cell. Photoreceptor cells are sensitive to light and transmit signals to ganglion cells that carry the signal to the brain. The communication between photoreceptors and bipolar cells in the retina is essential for visual processing.

Certain photoreceptors directly synapse onto bipolar cells, leading to direct effects, whereas other photoreceptors can synapse onto multiple bipolar cells, contributing to combined messages being sent through their graded postsynaptic potentials.

Answer:

C(CH3)3 I  - iodide

Explanation:

The alkyl halide forming the alkene cis-2-pentene as the only product in an elimination reaction is 2-chloropentane. The elimination reaction causes the removal of the halogen (chlorine) and a hydrogen on adjacent carbons, resulting in a pi bond between them, producing the alkene cis-2-pentene.

The alkyl halide that would form the alkene cis-2-pentene as the only product in an elimination reaction would be 2-chloropentane. The elimination reaction involves the removal of a halogen (chlorine) and a hydrogen on adjacent carbons, creating a pi bond between them.

This is called a beta-elimination reaction, and specifically for 2-chloropentane, it's dehydrohalogenation the process forming the alkene cis-2-pentene as the sole product.

The IUPAC name of the alkyl halide is 2-chloropentane, and the product of the halogenation reaction is cis-2-pentene.

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Answer:

0.2, relatively inelastic

Explanation:

Price elasticity of demand is the degree of responsiveness of demand for a product/service to a unit change in the price of that product/service. Mathematically:

Price elasticity of demand = change in demand/change in price.

Price elasticity of demand can be perfectly elastic if elasticity is infinity, perfectly inelastic if elasticity is 0, relatively elastic if elasticity is greater than 1, unitary elastic if it is equal to 1 and relatively inelastic if it is less than 1.

For gasoline,

Change in price = 5%

Change in quantity demanded = 1%

Hence,

Price elasticity of demand for gasoline = 1/5 = 0.2

The price elasticity of demand for gasoline is 0.2 and can be described as being relatively inelastic.

The complete question is:

An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.

The net ionic equation contains which of the following species (when balanced in standard form)?

a. 2NO3-(aq)

b. Ca2+(aq)

Answer:

b. Ca2+(aq)

Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)

Explanation:

The overall ionic equation is:

Ca2+(aq) + 2NO3-(aq) + 2NH4+(aq) + SO4^2-(aq) ---------------> CaSO4(s) + 2NH4NO3(aq)

The NO3- and NH4+ are spectator ions as they do not participate in the formation of the precipitate CaSO4.

The net ionic equation is:

Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)

The spectator ions form the soluble ammonium trioxonitrate V

Answer:

The correct answer is 4. gives the relative number of atoms of each element per formula unit.

Explanation:

Empirical formula shows the ratio of elements of which a compound is composed. It is a minimal formula: it does not show the actual number of atoms of each element in the compound, but it shows the relative number of each element in the molecule. For example: butane has the molecular formula C₄H₁₀. It means that it is composed by 4 atoms of C and 10 atoms of hydrogen (actual number of atoms in the molecule). The ratio C:H is 4:10, so the simplest ratio is 2:5 (if we divide by 2). Thus, the empirical formula is C₂H₅ (there are 2 atoms of C for every 5 atoms of H).

Answer:

4

Explanation:

It gives the lowest ratio of the number of atoms of each element per formula unit. This is usually derived by dividing common multiples of the molecular formula thereby reducing the value.

Answer: The heat of combustion of the organic material is -69.88 kJ/g

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

[tex]q=c\Delta T[/tex]

where,

q = heat absorbed

c = heat capacity of calorimeter = 44.51 kJ/°C

[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(29.28-23.13)^oC=6.15^oC[/tex]

Putting values in above equation, we get:

[tex]q=44.51kJ/^oC\times 6.15^oC=273.74kJ[/tex]

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the enthalpy change of the reaction, we use the equation:

[tex]\Delta H_{rxn}=\frac{q}{m}[/tex]

where,

q = amount of heat released = -273.74 kJ

m = mass of organic material = 3.917 g

[tex]\Delta H_{rxn}[/tex] = enthalpy change of the reaction

Putting values in above equation, we get:

[tex]\Delta H_{rxn}=\frac{-273.74kJ}{3.917g}=-69.88kJ/g[/tex]

Hence, the heat of combustion of the organic material is -69.88 kJ/g

Answer:

Autobiographical memory  

Explanation:

Autobiographical memory is the memory of specific events that you experienced personally earlier in your life.  

Answer:

25.0 grams

Explanation:

Answer:

25.o grams needed to react to 50 grams of nitrogen

Explanation:

[tex]Na_2O + H_2O[/tex] → [tex]2NaOH[/tex]

[tex]Na_2O + 2HCl[/tex] → [tex]2NaCl +H_2O[/tex]

     2. Sulphur trioxide

[tex]SO_3 + H_2O[/tex] → [tex]H_2SO_4[/tex]

The oxides of period 3 elements from Sodium to Argon have different acid-base character. Generally, metal oxides like Sodium Oxide are basic and react with water to form bases, whereas non-metal oxides like Sulphur Trioxide are acidic and react with water to form acids.

The oxides of the period 3 elements from Sodium (Na) to Argon (Ar) present different acid-base character. In general, the metal oxides like Sodium Oxide (Na2O) are basic whereas the non-metal oxides like Sulphur Trioxide (SO3) are acidic.

Starting with Sodium Oxide, it is a basic oxide and when reacted with water, forms a base. The balanced equation is as follows:
Na2O(s) + H2O(l) -> 2NaOH(aq)

On the other hand, Sulphur Trioxide is an acidic oxide because it reacts with water to form an acid. The balanced equation for this reaction is:
SO3(g) + H2O(l) -> H2SO4(aq)

This difference in acid-base character has to do with the nature of the elements themselves: metals tend to form basic oxides, whereas non-metals form acidic or neutral oxides.

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