Nitrogen has a proton number of 7, it also hos 7 neutrons What is the nucleon number of nitrogen?​

Answer:

The equilibrium constant for the reaction comes out to be 7.145

Explanation:

Given concentration of all the species at equilibrium are shown below

[tex]\left [ SO_{2} \right ] = 0.42 \textrm{ M}, \left [ O_{2} \right ] = 0.21 \textrm{ M}, \left [ SO_{3} \right ] = 0.072 \textrm{ M}[/tex] \\

Given reaction is shown below

[tex]2\textrm{SO}_{3}\left ( g \right )\rightleftharpoons 2\textrm{SO}_{2}\left ( g \right )+\textrm{O}_{2}\left ( g \right )[/tex]

[tex]K_{eq} = \displaystyle \frac{\left [ SO_{2} \right ]^{2}\times \left [ O_{2} \right ]}{\left [ SO_{3} \right ]^{2}} \\K_{eq} = \displaystyle \frac{\left ( 0.42 \right )^{2}\times 0.21}{\left ( 0.072 \right )^{2}} \\K_{eq} = 7.145[/tex]

[tex]K_{eq}[/tex] for the reaction is 7.145

The equilibrium constant (Keq) for the reaction 2SO3(g) -> 2SO2(g) + O2(g) is calculated using the equilibrium concentrations of the reactants and products and the formula Keq = ([SO2]^2 * [O2]) / ([SO3]^2), yielding an approximate value of 7.15.

The student is asking how to calculate the equilibrium constant (Keq), also referred to as the equilibrium constant Kc, for the reverse reaction 2SO3(g) -> 2SO2(g) + O2(g) given the equilibrium concentrations of the reactants and products. To calculate Keq, we use the following equilibrium expression:

Keq = ([SO2]^2 * [O2]) / ([SO3]^2)

Substituting the equilibrium concentrations into the expression gives:

Keq = (0.422 * 0.21) / (0.0722)

Keq = (0.1764 * 0.21) / (0.005184)

Keq = 0.037044 / 0.005184

Keq = 7.146 (rounded to three significant figures)

Therefore, the value of the equilibrium constant (Keq) for the reaction 2SO3(g) -> 2SO2(g) + O2(g) is approximately 7.15.

Answer:

The coefficient of [tex]KClO_{3}[/tex]  , KCl and [tex]O_{2}[/tex] are 2, 2 and 3 respectively.

Explanation:

The heating of [tex]KClO_{3}[/tex] to give KCl and oxygen gas is an example of decomposition reaction.

The balanced reaction for the decomposition of [tex]KClO_{3}[/tex] is shown below

[tex]2KClO_{3}\rightarrow 2KCl+3O_{2}[/tex]

The coefficient of [tex]KClO_{3}[/tex] is 2

The coefficient of KCl is 2

The coefficient of [tex]O_{2}[/tex] is 3

Final answer:

In Chemistry, the decomposition of potassium chlorate (KClO₃) is balanced to show that 2 moles of KClO₃ produce 3 moles of O₂. Therefore, 1.65 moles of KClO₃ will produce 2.475 moles of O₂.

Explanation:

The question involves balancing a chemical equation, which is a fundamental concept in Chemistry. You are seeking to find the coefficients for the decomposition of potassium chlorate (KClO₃) into potassium chloride (KCl) and oxygen (O₂). The balanced equation for this decomposition is:

2 KClO₃(s) 2 KCl(s) + 3 O₂(g)

According to the stoichiometry, 2 moles of KClO₃ produce 2 moles of KCl and 3 moles of O₂. Thus, 1.65 moles of KClO3 will produce:

1.65 moles KClO₃ x (3 moles O₂ / 2 moles KClO₃) = 2.475 moles O₂

Answer: 2.475 moles of O₂ will be formed from 1.65 moles of KClO₃.

Answer:

it is important because in that way chemist can see lowest possible number of reactants in chemical reaction needed to form product of reaction. Coefficients with the lowest ratio indicate the relative amounts of substances in a reaction.

Explanation:

Answer:

1. Nitric Acid

2. Hydrochloric Acid

3. Acetic Acid

4. Hydrogen bromide

5. Nitrous Acid

Explanation:

1. H2SO4

2. HF

3. H3PO4

4. H2CO3

5. H2S

P.S. make the numbers smaller ok?

Answer:

I'm pretty sure it's B

Explanation:

Blood flung off swinging objects creates a type of spatter known as cast-off, different from arterial spray, expirated blood patterns, or void patterns. Option C is correct.

Blood that is flung off of swinging objects creates a type of spatter known as cast-off. This typically occurs when blood on an object, such as a weapon, is flung into the surrounding area when the object is quickly swung or moved.

It can be distinguished from other types of spatter, such as arterial spray, which is characterized by the pulsating pattern of blood that spurts out with each heartbeat, or expirated blood patterns, which are caused by blood that is expelled from the mouth or nose from an internal injury. Void patterns occur when an object blocks the deposition of blood spatter onto a surface or object, creating a blank space within the bloodstained area.

Hence, C. is the correct option.

Answer:

sodium atom

Explanation:

the sodium ion loses a valence shell when it ionizes. The sodium atom retains this valence shell which adds to its radius

Answer:

mg3n2

Explanation:

Answer:

3Mg + N2 —> Mg3N2

Explanation:

The reaction between Mg and N2 is given below:

Mg + N2 —> Mg3N2

Now let us balance the equation:

There are 3 atoms of Mg on the right side and 1atom on the left side. It can be balance by putting 3 in front of Mg as shown below:

3Mg + N2 —> Mg3N2

Now the equation is balanced

Answer:

a. 2.7 mol of water

b CH2.

c. O2

Explanation:

The complete equation of the reaction should be:

2CH2(g) + 3O2(g) → 2 CO2(g) + 2 H2O(g)

a) how many moles of water will be  made?

To make 2 molecules of water (H2O) we need 2 molecules of CH and 3 molecules of O2.

We have 2.7 mol of CH2, the possible yield of water produced if it all used up will be:

2.7 mol * 2/2= 2.7 mol

We have 6.3 mol of O2, the possible yield of water produced  if it all used up will be:

6.3 mol * 2/3 = 4.2 mol

Since the maximum yield of CH2 lower, we can have 2.7 mol of water and have some excess oxygen at the end of the reaction.

b) What is the limiting reactant?

A limiting reactant is a reactant that will be used up in the reaction. This reactant has the lowest stoichiometric ratio compared to other reactants, which make them the one depleted out first. Since they depleted, the reaction will stop. Thus they limit the number of reactions and called limiting reactants. If you add the limiting reactant, the reaction will continue.

The limiting reactant in this reaction is the CH2. When producing water molecules, all 2.7 mol of CH2 will be used while we still have O2 left.

c) What is the excess reactant?

The excess reactant will have some remains after the reaction stop. That is because the excess reactant has more mass than needed for the reaction that will use all limiting reactants. Since we still have remains, adding excess reactant won't continue the reaction.

The excess reactant in this question is O2 since it still has remained after we make 2.7 mol of water. The O2 remaining, in this case, will be:

6.3 mol - 2.7mol * 3/2= 2.25 moles

Answer:

Answer of question a is 345J.

Explanation:

In question a following is given in data:

-mass of iron (m) = 10.0 g

-temperature (ΔT) = final temperature- initial temperature= 100-25=  75 degree Celsius

-Specific Heat capacity of iron (c)= 0.46J/g°C.

Heat (Q)=?

Solution:

Formula for Heat is :

Q=m x c x ΔT

Q= 10 x 0.46 x 75

Q= 345 J.  

so, 345 joules of heat is needed to increase the temperature of 10 grams of iron.

To find the amount of heat required or released, use the formula q = m × c × ΔT, applying the given values for mass, specific heat capacity, and temperature change.

To solve the heat calculation problems, we use the formula q = m × c × ΔT, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature (final temperature minus initial temperature).

For example, to calculate how much heat is required to raise the temperature of 10.0 g of iron from 25°C to 100.0°C, given that the specific heat capacity of iron is 0.46 J/g°C, we apply the formula: q = (10.0 g) × (0.46 J/g°C) × (100.0°C - 25°C). Calculating this gives q = 345 J, meaning 345 Joules of heat is required.

Answer: Elements in the same column are similar in their properties

Explanation: The columns on the periodic table are also know as group of the periodic table elements in the same group of the periodic table tends to have similar chemical properties because they all have the same number of valence electrons in their outermost shell. This plays an important roles in their reactivity and properties

Answer:

1. elements in the same column are similar in their properties

Explanation:

I got it right :)

Answer:

A

Explanation:

The barcode is being read by a laser that scans along the length of the sequence, reflecting more light from the white strips and less from the  black strips. Hope this helps!

Answer:

The Answer is A

Explanation:

Had it before

Answer:

Cell membrane

Cellulose cell wall

Explanation:

The cell membrane is the structure that contains what goes in out of a cell. It is made up of double phospholipid layers.

This cell membrane is also known as the plasma membrane. It is found in both plants and animal cells.

They regulate the movement of materials in and out of the cell. They also provide structural support.

The cellulose cell well is a strong layer found in most plant cells. They are not found in animal cells. These structures are found just outside of the cell membrane in plants. They provide additional support for the cell They are rigid and not flexible.

Answer: 1: membrane 2: wall

Explanation: I got it wrong but it show me the answer

Answer:

Color is emitted from an atom when an electron jumps from a higher energy level to a lower energy level

Explanation:

According to Bohr's model of the atom, electrons are arranged into circular orbits, each orbit corresponding to a precise energy level.

In this model of the atom, electrons cannot be between two orbits: this means that the energy level of the atom are discrete, so they can only assume certain values.

As a result, when an electron jumps between two energy levels, it emits/absorbs a photon whose energy is equal to the difference in energy between the two levels.

In particular:

- If an electron jumps from a lower energy level to a higher energy level, it absorbs a photon

- If an electron jumps from a higher energy level to a lower energy level, it emits a photon

The energy of the emitted photon is equal to the difference in energy between the two levels, and it is related to the wavelength [tex]\lambda[/tex] of the photon by

[tex]E=\frac{hc}{\lambda}[/tex]

where h is the Planck's constant and c the speed of light.

For usual gases, the value of the energy E is such that the value of the wavelength [tex]\lambda[/tex] falls within the visible light range of the electronmagnetic spectrums, so we observe light emitted as different colors, depending on the wavelength.

The decrease in the volume of gas at constant pressure results in the final temperature of the gas is 115.05 K.

The Charles law states that with the gas constant pressure there has been a proportional relationship between the volume and temperature.

At constant pressure, the relationship between the temperature and volume can be given by:

[tex]\rm \dfrac{Initial\;volume}{\Initial\;Temperature}\;=\;\dfrac{Final\;Volume}{Final\;Temperature}[/tex]

For the given gas, the final temperature can be calculated as:

[tex]\rm \dfrac{350\;ml}{298.15\;K}\;=\;\dfrac{135\;ml}{Final\;temperature}[/tex]

1.173 = [tex]\rm \dfrac{135\;ml}{Final\;temperature}[/tex]

Final temperature = [tex]\rm \dfrac{135\;ml}{1.173\;K}[/tex]

Final temperature = 115.05 K.

The reduction in the volume of gas at constant pressure results in the final temperature of the gas is 115.05 K.

For more information about the volume of gas at constant pressure, refer to the link:

https://brainly.com/question/24691513

Using Charles's Law, we can calculate that the final temperature of the gas at constant pressure when its volume is decreased from 350 mL at 25°C to 135 mL is -157.95°C.

The student is asking about the relationship between the volume and temperature of a gas held at constant pressure, which can be described using Charles's Law. According to this law, at constant pressure, the volume of a gas is directly proportional to its absolute temperature (measured in Kelvin). To find the final temperature when the volume of 350 mL of gas at 25°C is decreased to 135 mL, we can set up the proportion:

V1 / T1 = V2 / T2

where:

First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15 (T1 in Kelvin is 298.15 K). Then we can solve for T2:

(350 mL / 298 K) = (135 mL / T2)

Multiplying both sides by T2 and then by 298 K, we get:

T2 = (135 mL * 298 K) / 350 mL = 115.2 K

Converting back to Celsius, we subtract 273.15 from 115.2 K to get -157.95°C, which is the final temperature of the gas at constant pressure.

Answer:

1.54x10^24

Explanation:

To convert moles to molecules, multiply the number of moles by Avagadro's number (6.02x10^23).

2.56mol × 6.02x10^23 = 1.54x10^24

To find the number of molecules in 2.56 moles of water, we multiply the number of moles (2.56) by Avogadro's number (6.022 x 10²³), resulting in 1.54 x 10²⁴ molecules of water.

The question asks, what are the number of molecules in 2.56 moles of water? To answer this, we need to understand Avogadro's number, which is a fundamental concept in chemistry representing the number of units in one mole of any substance. Specifically, Avogadro's number is 6.022 x 10²³. Therefore, to find the number of molecules in 2.56 moles of water, we multiply the number of moles by Avogadro's number:

This calculation gives us: 1.54 x 10²⁴ molecules of water in 2.56 moles.

Answer:

c both

Explanation:

the table is pushing up so the pushing force and gravity is the pulling force as its pulling it towards the ground

Answer:

basic

Explanation:

A solution of copper (I)hydroxide is a base and it will form a basic solution no matter what.

A base is a compound the produces hydroxyl ions in aqueous solutions. Most known bases always have the OH⁻ group attached to them in a compound.

Copper(I) hydroxide is a an alkali as it can dissolve in water. It shares all the unique characteristics of a typical base and it will turn red litmus paper blue.

Answer: oxygen=2.547g

Explanation:

Based on the question,it was observed that the reaction is reversible

2 moles of KClO3 gives 2 moles of KCl and three moles of O2

Molar mass for KClO3 is 245 g/mol

Molar mass for O2 is 96 g/mol

We are to find the mass of O2 and we Are given the mass KCLO3 is 6.50g

245g of KClO3 gives 96g of O2

6.50g of KClO3 gives xg of O2

Cross multiply

245x=624

X=624/245

X=2.547g

Therefore the gram of oxygen is 2.547g

When 6.50 grams of potassium chlorate (KClO3) are heated, approximately 2.54 grams of oxygen gas should be given off.

When potassium chlorate (KClO3) is heated, it decomposes to produce potassium chloride (KCl) and oxygen gas (O2). The balanced chemical equation for this reaction is:

2KClO3(s) → 2KCl(s) + 3O2(g)

In order to determine the amount of oxygen gas produced, we need to calculate the theoretical yield of oxygen gas. This can be done using stoichiometry and the molar mass of KClO3.

First, calculate the molar mass of KClO3:

39.10 g/mol (K) + 35.45 g/mol (Cl) + 3(16.00 g/mol) (O) = 122.55 g/mol

Next, use the molar mass of KClO3 to convert grams of KClO3 to moles:

6.50 g KClO3 * (1 mol KClO3 / 122.55 g KClO3) = 0.053 mol KClO3

According to the balanced chemical equation, 2 moles of KClO3 produce 3 moles of O2. Therefore, the number of moles of O2 produced can be calculated as:

0.053 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 0.0795 mol O2

Finally, convert moles of O2 to grams:

0.0795 mol O2 * (32.00 g/mol O2) = 2.54 g O2

Therefore, when 6.50 grams of KClO3 are heated, approximately 2.54 grams of oxygen gas should be given off.

Answer:

The pH value comes out to be 9.03. We will get an alkaline solution by the hydrolysis of the salt of a weak acid and a strong base.

Explanation:

[tex]KC_{2}H_{3}O_{2}[/tex]  is a salt of a weak acid acetic acid and a strong base KOH. This salt will hydrolyze in water to give an alkaline solution.

Assuming concentration (C) of the salt to be 0.2 M as it is not given.

[tex]K_{a}[/tex] of acetic acid = [tex]1.8\times 10^{-5}[/tex]

[tex]\textrm{pK}_{a} = -\textrm{ log}\left ( K_{a} \right ) \\\textrm{pK}_{a} = -\textrm{ log}\left ( 1.8\times 10^{-5} \right ) \\\textrm{pK}_{a} = 4.75[/tex]

The formula of pH on hydrolysis of salt of weak acid and strong base is given below

[tex]pH = \displaystyle \frac{1}{2}\left ( pK_{w}+pK_{a}+\textrm{log}C \right ) \\pH = \displaystyle \frac{1}{2} \left ( 14+4.75+\textrm{log}0.2 \right ) \\pH = 9.03[/tex]

The pH of solution comes out to be 9.03

To calculate the pH of a KC2H3O2 solution, determine the Kb of the acetate ion using the provided Ka for acetic acid and then calculate the concentration of hydroxide ions to finally find the pH of the solution through the formula pH = -log[H+].

To calculate the pH of a potassium acetate (KC2H3O2) solution, we must first understand the relationship between the acid dissociation constant (Ka) of acetic acid (HC2H3O2) and the base dissociation constant (Kb) of its conjugate base, the acetate ion (C2H3O2-). Using the formula Kw = Ka × Kb, where Kw is the ion-product constant for water (1.0 × 10^-14 at 25°C), we can calculate Kb with the given Ka for acetic acid (1.8 × 10^-5).

First, solve for Kb:

Kb = Kw / Ka

Kb = (1.0 × 10^-14) / (1.8 × 10^-5)

Kb = 5.56 × 10^-10

Knowing the Kb value, we can then use the given concentration of the KC2H3O2 solution to find the hydroxide ion concentration [OH-] and subsequently the hydrogen ion concentration [H+]. The pH is then calculated using the formula pH = -log[H+]. The complete solution would include detailed calculations of [OH-], [H+], and pH, factoring in the initial concentration of the KC2H3O2 solution.

The first ingredient to run out would be the chocolate chips.

A limiting reactant is a reactant that determines the amount of product that would be formed in a reaction.

In this scenario, the ratio of flower to chocolate chips to sugar to milk for a 100 cookies is 1:100:1:0.5.

The ratio of the same ingredients bought in the store is  5:300:6:16

Note: 16 cups = a gallon

To the lowest ratio: 5:300:6:16 = 1:60:1.2:3.02

Since the ratio of flour to chocolate chips is 1:100, it means that the chocolate chips would be the first to run out first and thus, the limiting reactant.

More on limiting reactants can be found here: https://brainly.com/question/14225536?referrer=searchResults

Answer:

Anything in the environment that causes a change is called a stimulus.

Explanation:

Answer:

Anything in the environment that causes a change is called a stimulus.

Explanation:

Organisms react to many stimuli, including light, temperature, odor, sound, gravity, heat, water, and pressure. The ability of living things to react to stimuli is known as irritability.

Answer:

2.42L

Explanation:

Given parameters:

V₁  = 1.8L

T₁ = 293K

P₁  = 101.3kPa

P₂ = 67.6kPa

T₂  = 263K

Unknown:

V₂ = ?

Solution:

To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;

               [tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]

All the units are in the appropriate form. We just substitute and solve for the unknown;

         101.3 x 1.8 / 293    =     67.6 x V₂  /  263

          V₂   = 2.42L

Answer:

Option C. $1.79

Explanation:

From the question, were told that the total cost of 8 protein bar is $14.32.

Therefore, the cost of 1 protein bar will be = $14.32/8 = $1.79

Answer :

the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

Explanation:

The answer can be calculated using the formula

Q = mCрΔT

where

Q is the amount of heat required in joules to raise the temperature.

m is the mass of the sample in Kg.

Cp is the specific heat of the sample in J/Kg°C.

ΔT is the change in temperature required.

Here, m = 49.5-gram = 0.0495 kg

Cp = 4.18 J/Kg°C (for water)

T₁ = 22°C  ; T₂ = 66°C

ΔT =  66 - 22 = 44

Substituting values in Q = mCрΔT

Q = (0.0495)(4.18)(44)

                  Q = 9.104 J

Answer:

Change in volume on changing temperature from 33[tex]^{\circ}C[/tex] to 5[tex]^{\circ}C[/tex] is 5.49 mL

Explanation:

Initial volume of gas = V = 60 mL

Assuming final volume of gas to be V' mL

Initial temperature = T = 33[tex]^{\circ}C[/tex] = 306 K

Final temperature = T' = 5[tex]^{\circ}C[/tex] = 278 K

The relationship between volume and temperature of gas at constant pressure is shown below

[tex]\displaystyle \frac{V}{V'}=\displaystyle \frac{T}{T'} \\\displaystyle \frac{60\textrm{ mL}}{V'} = \displaystyle \frac{306\textrm{ K}}{T} \\V' = 54.51 \textrm{ mL} \\\textrm{Change in volume} = \left ( V-V' \right ) \\\textrm{Change in volume} = \left ( 60-54.51 \right )\textrm{ mL} \\\textrm{Change in volume} = 5.49 \textrm{ mL}[/tex]

Change in volume on changing temperature = 5.49 mL

Sunlight/light from the sun

Cl2(s); oxidation number 1 is the incorrect choices in oxidation number.

Explanation:

In the elemental form oxidation state is zero. Here chlorine is present in elemental form so oxidation state is zero.

Oxidation number depends on the number of electrons gained or lost by an atom of the element say in compound formation.

If electron is gained oxidation number becomes negative.

If electron is lost then oxidation number is positive.

If the octet rule is fulfilled that valence shell is filled them atomic number gets zero. Since Cl2 is in neutral state the oxidation number is 0.

Oxidation number in general can be made out by checking the valency of the element as oxidation number is also equal to the valency.

Answer:

the answer would be "B"

Explanation:

Elements with the same number of valence electrons are found in the same column of the Periodic Table. All elements in the first column of the Periodic Table have 1 valence electron in an s orbital. These elements are known as Group 1A metals or alkali metals.

All elements within the same group  tend to possess the same number of outer electrons and the correct option is option B.

The periodic table is organized into groups (vertical columns), periods (horizontal rows), and families (groups of elements that are similar). Elements in the same group have the same number of valence electrons.

Meanwhile, elements in the same period have the same number of occupied electron shells.

Elements are typically classified as either a metal or nonmetal.

Metal elements are usually good conductors of electricity and heat. The subgroups within the metals are based on the similar characteristics and  chemical properties of these collections

Therefore, All elements within the same group  tend to possess the same number of outer electrons and the correct option is option B.

Learn more about Groups in Periodic Table, here:

https://brainly.com/question/30858972

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