Chemistry High School

Nitrogen gas is transformed into ammonia C. Ammonification Release of ammonia during decomposition A. Denitrification The conversion of ammonia to nitrate and nitrite B. Nitrificaiton The reduction of nitrate into N2O, NO, and N2 D. Nitrogen fixation

Answers

Answer 1

Answer:

D. Nitrogen Fixation

Explanation:

Nitrogen fixation is a process by which molecular nitrogen in the air is converted into ammonia (NH

3) or related nitrogenous compounds in soil.

Related Questions

Suppose paper pulp mills are permitted to emit harmful pollutants, free of charge, into the air. How will the price and output of paper in a competitive market compare with their values under conditions of ideal economic efficiency

Answers

Answer:

The price will be too low, and the output will be too large.

Explanation:

How much HCl is produced from the reaction of an excess of HSbCl4 with 3 moles H2S in the following reaction? HSbCl4 + H2S → Sb2S3 + HCl (Remember to balance the equation.)

Answers

Answer:

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Explanation:

Step 1: Data given

Number moles of H2S = 3.0 moles

Step 2: The balanced equation

2HSbCl4 + 3H2S → Sb2S3 + 8HCl

Step 3: Calculate moles HCl

For 2 moles HSbCl4 we need 3 moles H2S to produce 1mol Sb2S3 and 8 moles HCl

For 3.0 moles H2S we'll have 8.0 moles HCl

Step 4: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 8.0 moles * 36.46 g/mol

Mass HCl = 291.7 grams

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Final answer:

From the balanced equation, it is determined that 2 moles of HCl are produced from 1 mole of HSbCl4. Therefore, 6 moles of HCl will be produced from the reaction of an excess of HSbCl4 with 3 moles of H2S.

Explanation:

The balanced equation for the reaction is:

HSbCl4 + H2S → Sb2S3 + 2HCl

The mole ratio between HSbCl4 and HCl is 1:2, which means that for every 1 mole of HSbCl4, 2 moles of HCl are produced.

Since there is an excess of HSbCl4, we can assume that all 3 moles of H2S will react.

Therefore, the number of moles of HCl produced will be:

(3 moles H2S) x (2 moles HCl/1 mole HSbCl4) = 6 moles HCl

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