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Bicarbonate of soda (sodium hydrogen carbonate) is used in many commercial preparations. Its formula is NaHCO3. Find the mass percentages (mass %) of Na, H, C, and O in sodium hydrogen carbonate. You may use whole numbers for the masses.

The mass of one mole of NaHCO3 is:

Answer:

Approximately 352 liters of water vapor will be produced.

Assumption: the water vapor here behaves like an ideal gas.

Explanation:

Relative atomic mass data from a modern periodic table:

Burning methane [tex]\rm CH_4[/tex] in excess oxygen will produce carbon dioxide and water. The balanced equation will be

[tex]\rm CH_4\; (g) + 2\; O_2\;(g) \to CO_2\;(g) + 2\; H_2O\;(g)[/tex].

Hint: start by assign "1" to methane while balancing this equation.

How many moles of molecules in 108 gram of methane?

Molar mass of methane:

[tex]M(\rm CH_4) = 12.011 + 4\time 1.008 =16.043\;g\cdot mol^{-1}[/tex].

[tex]\displaystyle n(\rm CH_4) = \frac{m}{M} = \frac{108}{16.043} = 6.73191\;mol[/tex].

How many moles of water molecules will be produced?

Consider the ratio between the coefficient in front of water and that in front of methane in the equation:

[tex]\displaystyle \frac{n(\mathrm{H_2O})}{n(\mathrm{CH_4})} = 2[/tex].

[tex]\displaystyle n(\mathrm{H_2O}) = n(\mathrm{CH_4})\cdot \frac{n(\mathrm{H_2O})}{n(\mathrm{CH_4})} = \rm 2\times 6.73191\;mol = 13.4638\;mol[/tex].

Assume that water vapor here behaves like an ideal gas.

Ideal gas constant in liters and [tex]\rm atm[/tex]:

[tex]R \rm \approx 0.0820573\;L\cdot atm \cdot K^{-1}\cdot mol^{-1}[/tex]. (NIST.)

Make sure that the temperature here is in degrees Kelvins.

[tex]\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P} \\ &= \rm \frac{13.4638\;mol\times 0.0820573\;L\cdot atm \cdot K^{-1}\cdot mol^{-1}\times 312\; K}{0.98\; atm}\\ &\rm \approx 352\; L\end{aligned}[/tex].

Answer:

32) A. 1

33) E. 2

34) C. 12

35) D. Sb₄O₆

Explanation:

32. N₂O₅ + __H₂O → 2HNO₃

left side: 2 H , 2 N, 6 O

right side: 2 H, 2 N, 6 O

Nothing needs to change, so put a 1

33. P₂O₅ + 3H₂O → __H₃PO₄

left side: 6 H, 2 P, 8 O

right side: 3 H, 1 P, 4 O

everything on the right needs to double, so put a 2

34. Sb₄O₆ + __HCl → 4SbCl₃ + 6H₂O

left side: 4 Sb, 6 O, 1 H, 1 Cl

right side: 4 Sb, 6 O, 12 H, 12 Cl

the H and Cl on the left both need to be multiplied by 12, so put a 12

35. ____ + 4NaOH → 4NaSbO₂ + 2H₂O

left side: 4 Na, 4 O, 4 H

right side: 4 Na, 10 O, 4 H, 4 Sb

the left side needs 6 more O and 4 Sb, so add Sb₄O₆

Answer:

1 mole of any gas has a volume of 22.4 at STP

Avogadro's law states 1 mole of any gas at standard temperature and pressure (STP) occupies a volume of 22.4 liters. This statement is applicable to all gases.

According to Avogadro's law, one very important characteristic of 1 mole of gas at standard temperature and pressure (STP) is that it occupies a volume of 22.4 liters. This is applicable to any gas, regardless of the type. Avogadro's law states that equal volumes of different gases, at the same temperature and pressure, contain the same number of molecules. Therefore, irrespective of whether it is oxygen, hydrogen, or nitrogen, if you have 1 mole of gas at STP, it will occupy a volume of 22.4 liters.

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Answer:

The molecules align with the electric field

Explanation:

Polar molecules have dipoles (parts of the molecules have partial charges). This is because the atoms with a larger atomic mass attract more of the electron cloud of the molecule hence become partially electronegative. The other part of the molecule becomes partially positive. Therefore these parts of the molecule will align with opposite charges including in this case based on the charged metal plates. The positive dipole will align with the negative plate while the negative dipoles will align with the positive plate.

Answer:

The molecules align to the electric field.

Explanation:

A polar molecule is one that is neutral, that is, it does not have a net charge. But it has an internal distribution of charges that form a partially positive region and a partially negative region.

Coulomb's law indicates that charged bodies suffer a force of attraction or repulsion when approaching. The value of this force is proportional to the product of the value of its loads. The force is of attraction if the charges are of opposite sign and of repulsion if they are of the same sign. The force is inversely proportional to the square of the distance that separates them.

Then, following Coulomb's Law, the negatively charged end of the polar molecule will be attracted to the positively charged metal plate. And the positively charged end of the polar molecule is attracted to the negatively charged metal plate.

Then, the molecules align to the electric field.

Answer:

3065.63 J = 3.066 kJ.

Explanation:

Q = m.c.ΔT,

where, Q is the amount of heat needed to warm Fe (Q = ??? J).

m is the mass of Fe (m = 125.0 g).

c is the specific heat capacity of Fe (c = 0.45 J/g.°C).  

ΔT is the difference in T (ΔT = final temperature - initial temperature = 78.0°C - 23.5°C = 54.5°C).

∴ Q = m.c.ΔT = (125.0 g)(0.45 J/g.°C)(54.5°C) = 3065.63 J = 3.066 kJ.

Answer:

c) Cu⁺(g)⟶ Cu²⁺(g) + e⁻

Explanation:

Ionization energy is the energy needed to remove a valence electron from a gaseous atom.

b) Cu(g) ⟶ Cu⁺(g)  + e⁻ represents the first ionization energy, the energy needed to remove the first electron.

c) Cu⁺(g)⟶ Cu²⁺(g) + e⁻ represents the second ionization energy of Cu, the energy needed to remove the second electron after the first one is gone.

a) is wrong. The charge is not balanced.

d) is wrong. It represents the electron gain energy of a Cu⁻ ion (highly unlikely).

e) is wrong. It represents the electron gain energy of a Cu⁺ ion (the reverse of the first ionization energy).

The second ionization of copper, where copper(I) loses an extra electron to become copper(II), is correctly represented by the option c) Cu+ (g) → Cu2+ (g) + e-.

The correct answer to the question of which of the following correctly represents the second ionization of copper is c) Cu+ (g) → Cu2+ (g) + e-. During the second ionization process, a copper(I) ion, also called a cuprous ion, loses an additional electron to become a copper(II) ion or cupric ion with a 2+ charge. This process can be observed in various redox reactions where copper transitions from a +1 oxidation state to a +2 oxidation state.

Answer:

[tex]\boxed{\text{131 g}}[/tex]

Explanation:

When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.  

That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.

[tex]\begin{array}{r|l}101.& \text{g}\\25. & \text{01 g}\\5. & \text{05 g} \\\mathbf{131.} & \text{06 g}\\\end{array}[/tex]

The measurement of 101 g has no digits after the decimal point, so you round off the answer to give no digits to the right of the decimal.

[tex]\text{The sum is }\boxed{\textbf{131 g}}[/tex]

Answer:

Vietnamese.

Correct for plato

Answer:

Group 7 or the Halogens

Explanation:

The halogens occupies the 7th group on the periodic table. The group is made of F, Cl , Br, I and At.

The elements in this group are the most reactive of all elements. They are very reactive because they have just 7 electrons in their outermost shell and they only require an electron to complete their electronic configuration to produce an octet which typically mimics the stable group VIII elements.

This makes them very highly reactive.

Answer:

7

Explanation:

Answer:

Most likely stoves and fire places.

Explanation:

Answer: carbon monoxide is found in fumes produced any time you burn fuel in cars or trucks, small engines, stoves, lanterns, grills, fireplaces, gas ranges, or furnaces.

Answer:

• Earth and space science, life science, physical science is the correct answer.

Explanation:

natural science is the branch of science that deals with the study of natural events, based on experimental proof from research and experimentation.

The three major branches of natural science are

Earth and space science: is the study of the Earth, oceans, land, solar system and atmosphere. it covers all fields of the natural science that are associated with the Earth planet.

life science:The life sciences include the parts of science that include the scientific understanding of living organisms and life( plants, animals , microbes and human beings).

physical science:it deals with studies of non-livings things.

Answer:

React it with CH₃MgBr and work up the product with saturated ammonium chloride solution

Explanation:

Grignard reagents convert esters into tertiary alcohols.

The general equation is

[tex]\text{RCOOR}' \xrightarrow[\text{2. H}^{+}]{\text{1. R$^{\prime \prime}$MgBr}}\text{RR$_{2}^{\prime \prime}$C-OH}[/tex]

The Grignard reagent in this synthesis is methylmagnesium bromide. You prepare it by reacting a solution methyl bromide in anhydrous ether with magnesium and a few crystals of iodine.

The reaction consumes 3 mol of CH₃MgBr per mole of dimethyl carbonate, and everything happens in the same pot.

Acid workup of the product usually involves the addition of a saturated aqueous solution of ammonium chloride and extraction with a low-boiling organic solvent.

The mechanism involves:

Step 1. Nucleophilic attack and loss of leaving group

(a) The Grignard reagent attacks the carbonyl of dimethyl carbonate, followed by (b) the loss of a methoxide leaving group.

Step 2. Nucleophilic attack and loss of leaving group

(a) A second mole of the Grignard reagent attacks the carbonyl of methyl acetate, followed by (b) the loss of a methoxide leaving group.

Step 3. Nucleophilic attack and protonation of the adduct.  

(a) A third mole of the Grignard reagent attacks the carbonyl of acetone, followed by (b) protonation of the alkoxide to form 2-methylpropan-2-ol.

The Grignard reagent serves as a very important tool in the synthesis of many other compounds.

The Grignard reagent serves as a very important tool in the synthesis of many other compounds. Grignard reagent are used in the synthesis of alcohols, ethers etc.

All the reagents and compounds required for the synthesis of 2-methyl-2-propanol via a Grignard reagent  with dimethyl carbonate  are shown in the image attached to this answer.

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To find the volume of Leon's tire, we use the Ideal Gas Law: PV = nRT. Given the pressure, temperature, and moles of air, we calculate the volume to be approximately 53.5 liters. Therefore, the tire's volume is 53.5 liters.

Leon uses a pressure gauge to measure the air pressure in one of his car tires. The gauge shows that the pressure is 220 kilopascals. The temperature is 297 K, and the outdoor air is at standard pressure. If the tire contains 4.8 moles of air, what is the volume of the tire? The volume of the car tire is liters.

To find the volume of the tire, we can use the Ideal Gas Law: PV = nRT.

Where:

Rearranging the Ideal Gas Law to solve for V, we get:

V = nRT / P

Substitute the known values:

V = (4.8 moles) * (8.314 J/(mol·K)) * (297 K) / (220,000 Pa)

V = 11.781 / 220

V ≈ 0.0535 m³

To convert cubic meters to liters: 0.0535 m³ * 1000 = 53.5 liters

Therefore, the volume of the car tire is approximately 53.5 liters.

Answer:

once they are leaked into the environment, could cause serious health hazards to all living organisms

Answer:

can do all of these

Explanation:

A radioactive material may exist in any given state of matter; solid, liquid or gas. Some radioactive materials have very long half lives. Half life refers to the period of time it takes for the amount of radioactive material in a sample to decrease by half of its original content of radioactive material.

Most radioactive materials produce ionizing radiation which causes ill effects on human and animal cells.

These are two questions and two answers

Question 1.

Answer:

Explanation:

1) Data:

a) m = 9.11 × 10⁻³¹ kg

b) λ =  3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

2) Formula:

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

3) Solution:

Solve for s:

Substitute:

To express the speed relative to the speed of light, divide by c =  3.00 10⁸ m/s

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

Explanation:

1) Data:

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ =  ?

2) Formula:

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

3) Solution:

Substitute:

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.  

Answer:

C. 481 °C.

Explanation:

The amount of heat absorbed by water = the amount of heat released by copper.

Q = m.c.ΔT,

where, Q is the amount of energy.

m is the mass of substance.

c is the specific heat capacity.

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T).

∵ Q of copper = Q of water

∴ - (m.c.ΔT) of copper = (m.c.ΔT) of water

m of copper = 220.0 g, c of copper = 0.39 J/g °C, ΔT of copper = final T - initial T = 42.00 °C - initial T.

m of water = 500.0 g, c of water = 4.18 J/g °C, ΔT of water = final T - initial T = 42.00 °C - 24.00 °C = 18.00 °C.

∴ - (220.0 g)( 0.39 J/g °C)(42.00 °C - Ti) = (500.0 g)(4.18 J/g °C)(18.00 °C)

∴ - (85.8)(42.00 °C - Ti) = 37620.

∴ (42.00 °C - Ti) = 37620/(- 85.8) = - 438.5.

∴ Ti = 42.00 °C + 438.5 = 480.5°C ≅ 481°C.

So, the right choice is: C. 481 °C.

Answer:

Explanation:

Ground-state is the configuration of the electrons when every electron of the atom occupies the lowest possible energy level.

The rank of energy of the orbitals may be remembered using Aufbau rules, and it is:

1s² < 2s² < 2p⁶ < 3s² < 3p⁶ < 4s² < 3d¹⁰ < 4p⁶ < 5s² < 4d¹⁰ < 5p⁶ < 6s² < 4f¹⁴ < 5d¹⁰ < 6p⁶ < 7s² < 5f¹⁴ < 6d¹⁰ < 7p⁶

Then, to find whether an electron configuration corresponds to a ground-state one, you must check that the previous order is preserved.

Option A). 1s² 1p⁶ 2d²

The orbital 1p does not exist. So this one is discarded.

Option B) 1s² 2s⁴ 2p⁶

The maximum number of electrons in an s orbital is 2, so 2s⁴ is impossible, and this option is discarded.

Option C) 1s² 2s² 2p⁵

This is correct because the orbitals are filled in the correct increasing energy order, without jumping any one.

Option D) 1s² 2s² 2d⁶

Orbital 2d does not exist, so this option is also discarded.

Answer:

The formula of the compound will be:[tex] [Ru(Cl)_1(H_2O)_5]Cl_2[/tex].

Explanation:

Coordination sphere is an array of ions or ligands around central atom or or an ion. Ions and ligands linked to central atom forms primary coordination sphere and ions or molecules linked to primary coordination sphere forms secondary coordination sphere.

Given: If one mole of [tex]RuCl_3.5H_2O[/tex] reacts with [tex]AgNO_3[/tex] to produce two moles of AgCl precipitate.

This means that in primary coordination sphere there is a 1 chloride ion and 5 water molecules. And remaining 2 chloride ions present in secondary sphere which are available to react with silver ions of silver nitrate solution.

This why on reaction with silver nitrate 2 molecules or silver chloride are formed.

[tex][Ru(Cl)_1(H_2O)_5]Cl_2+2AgNO_3(aq)\rightarrow 2 AgCl(s)+[Ru(Cl)_1(H_2O)_5](NO_3)_2(aq)[/tex]

The formula of the compound will be:[tex] [Ru(Cl)_1(H_2O)_5]Cl_2[/tex].

Final answer:

The proper coordination sphere in the formula RuCl3·5H2O, after reacting with AgNO3 to produce AgCl, is represented by [Ru(H2O)5Cl]Cl2·H2O, indicating one chloride in the sphere, two as counterions, and one water molecule of crystallization.

Explanation:

To rewrite the formula RuCl3·5H2O to show the proper coordination sphere, we need to understand the stoichiometry of the reaction with AgNO3. This compound reacts to form two moles of AgCl, which indicates that two chloride ions are involved in the precipitation reaction. Since only those chloride ions are directly involved in the reaction to form AgCl with AgNO3, they must be in the coordination sphere of the ruthenium complex. The water molecules are assumed to complete the coordination sphere. Therefore, the proper way to write the formula indicating the coordination sphere would be [Ru(H2O)5Cl]Cl2·H2O, showing one chloride in the coordination sphere and two chloride ions outside as counterions with one crystallization water molecule.

Answer:

(a) 13.7 g.

(b) 28.91 g.

Explanation:

∴ m = (no. of moles of solute)/(mass of water (kg))

∴ m = (mass/molar mass of solute)/(mass of water (kg)).

(a) Calculate the mass of CaCl₂·6H₂O needed to prepare 0.125 m CaCl₂(aq) by using 500. g of water.

∵ m = (mass/molar mass of CaCl₂·6H₂O)/(mass of water (kg)).

m = 0.125 m, molar mass of CaCl₂·6H₂O = 219.0757 g/mol, mass of water = 500.0 g = 0.5 kg.

∴ 0.125 m = (mass of CaCl₂·6H₂O / 219.0757 g/mol)/(0.5 kg).

∴ mass of CaCl₂·6H₂O = (0.125 m)(219.0757 g/mol)(0.5 kg) = 13.7 g.

(b) What mass of NiSO₄·6H₂O must be dissolved in 500. g of water to produce 0.22 m NiSO₄(aq)?

∵ m = (mass/molar mass of NiSO₄·6H₂O)/(mass of water (kg)).

m = 0.22 m, molar mass of NiSO₄·6H₂O = 262.84 g/mol, mass of water = 500.0 g = 0.5 kg.

∴ 0.125 m = (mass of NiSO₄·6H₂O / 262.84 g/mol)/(0.5 kg).

∴ mass of NiSO₄·6H₂O = (0.22 m)(262.84 g/mol)(0.5 kg) = 28.91 g.

Final answer:

The answer provides a balanced chemical equation and guides through calculating the mass of Na2CO3 needed and finding the osmolarity of the solution after the reaction. It covers stoichiometry and solution concentration concepts.

Explanation:

(a) Balance the chemical equation:

Ca(NO3)2(aq) + Na2CO3(aq) → CaCO3(s) + 2NaNO3(aq)

(b) How many grams of Na2CO3 are needed:

Use the molarity and volume to find moles of Ca(NO3)2, then use the mole ratio to find moles of Na2CO3, and finally convert moles to grams.

(c) Find the osmolarity of the NaNO3 solution:

Since Na2CO3 doesn't affect volume significantly, find moles of Na2CO3 reacting, and use that to calculate the moles of NaNO3 left in the solution for osmolarity.

Answer:

Hey how are you all doing the answer is 8.93 g

Explanation:

The theoretical yield of carbon dioxide is 8.93 g​

Before performing chemical reactions, it is helpful to know how much product will be produced with given quantities of reactants. This is known as the theoretical yield. This is a strategy to use when calculating the theoretical yield of a chemical reaction. The same strategy can be applied to determine the amount of each reagent needed to produce a desired amount of product.

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Answer:

[tex]\boxed{\text{656.3 kJ/mol}}[/tex]

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is:

[tex]\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})[/tex]

                         CaCO₃(s) ⟶ CaO(s) + CO₂(g)

ΔH°f/kJ·mol⁻¹:    -1207.1          -157.3    -393.5

[tex]\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-157.3 + (-393.5)] - (-1207.1)\\& = & -550.8 +1207.1\\& = & \textbf{656.3 kJ/mol}\\\end{array}\\\\\text{The enthalpy of decomposition is } \boxed{\textbf{656.3 kJ/mol}}[/tex]

The enthalpy of decomposition is  656.3  KJ/mol.

Given that the enthalpy of decomposition is obtained from;

ΔHrxn = ∑ΔHf(products) -  ∑ΔHf(reactants)

Now, the species involved in the reaction are;

ΔHf(CaO)(s)) = -157.3 KJ/mol

ΔHf((CO2)(g)) = -393.5  KJ/mol

ΔHf(CaCO3)(s)) = -1207.1 KJ/mol

Substituting values;

ΔHrxn = [(-393.5) + ( -157.3)] - ( -1207.1) KJ/mol

ΔHrxn =(( -550.8) + 1207.1)  KJ/mol

ΔHrxn = 656.3  KJ/mol

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Final answer:

The energy required to produce 1 mole of He+ ions is 567.07 kcal/mol and for He++ ions is 1255.07 kcal/mol. The total energy to produce He++ ions from neutral He atoms is 1822.14 kcal/mol.

Explanation:

To calculate the energy in calories required to produce 1 mole of He+ ions and He++ ions from neutral helium (He) atoms, we employ Bohr's equations which relate the energy levels of electrons in hydrogen-like atoms. The first ionization energy (I1) is the energy needed to remove one electron, resulting in a He+ ion, and the second ionization energy (I2) is the energy required to remove a second electron, creating a He++ ion. The given first ionization energy for He is 24.59 eV and the second is 54.42 eV. Since 1 eV is equivalent to 23.06 kcal/mol, we can convert these ionization energies into calories per mole. Thus,

Adding these two amounts gives us the total energy to produce 1 mole of He++ ions from neutral He:

Total energy = 567.07 kcal/mol + 1255.07 kcal/mol = 1822.14 kcal/mol

Remember, this calculation assumes that all atoms are initially at ground state and that we are dealing with a single mole of atoms.

Answer:

A radical is a group of atoms that remains bonded together and behaves as a single atom in a chemical reaction. True (a.)

Answer:

I  can answer some of these.

Explanation:

Q 36.  B. Is false.

Q. 37  C. is false.

Q. 28.

All the  numbers are 1.

Answer:

yes

Explanation:

because they can become more stable by doing so. ... Two or more atoms of different elements that are chemically bonded together are known as: Compounds 6.

pls make brainliest thx

Carbon atoms have four valence electrons and are likely to react with other atoms because they can become more stable by doing so.

An atom is any particle of matter at its most basic level which contains at least one proton.

The four valence electrons in a carbon atom can do this by forming four single bonds, or by forming two single bonds and a double bond, by forming one single bond and a triple bond, or by forming two double bonds.

Carbons covalently bond with one another, also, forming chains of various lengths, and rings.

Hence, carbon atoms have four valence electrons and are likely to react with other atoms because they can become more stable by doing so.

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Answer:

Thermal decomposition or cracking

Explanation:

Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.

Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.

When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.

Example is given below:

                  C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄

Answer:

[tex]\boxed{\text{520 g H$_{2}$O}}[/tex]

Explanation:

(a) Unbalanced equation

[tex]\rm LiOH + CO$_{2} \longrightarrow \,$ Li$_{2}$CO$_{3}$ + H$_{2}$O[/tex]

(b) Balanced equation

[tex]\rm 2LiOH + CO$_{2} \longrightarrow \,$ Li$_{2}$CO$_{3}$ + H$_{2}$O[/tex]

(c) Molar masses

The only compound for which you need an atomic mass is water.

You look up the atomic masses of each element in the Periodic Table, multiply by their subscripts in the formula, and add.

[tex]\begin{array}{rcrcr}\text{2H} & = & 2 \times 1.008 & = & 2.02\\\text{1O} & = & 1 \times 16.00 & = & 16.00\\\text{H$_{2}$O} & = & & & \mathbf{18.02}\\\end{array}[/tex]

(d) Molar Ratio

You want to convert moles of carbon dioxide to moles of water.

The balanced equation tells you that the molar ratio is 1 mol H₂O:1 mol CO₂.

(e) Significant figures

The only measurement you are given is "about 650 L." That tells you that the trailing zero is not significant.

The volume has only two significant figures, so the mass of water can have only two significant figures.

Note: Intermediate calculations should carry at least one extra digit (a guard digit) to prevent cumulative round-off errors, answers to be reported must have the correct number of significant figures.

(f) The calculation

You don't give the temperature and pressure of the gas, so I shall assume STP (1 bar and 0 °C). At STP, the molar volume of a gas

is 22.71 L.

[tex]\text{Moles of CO$_{2}$} = \text{650 L CO$_{2}$} \times \dfrac{\text{1 mol CO$_{2}$}}{\text{22.71 L CO$_{2}$ }} = \text{28.6 mol CO$_{2}$}\\\\\text{Moles of H$_{2}$O} = \text{28.6 mol CO$_{2}$} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{1 mol CO$_{2}$}} = \text{28.6 mol H$_{2}$O}\\\\\text{Mass of H$_{2}$O} = \text{28.6 mol H$_{2}$O} \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \boxed{\textbf{520 g H$_{2}$O}}[/tex]

The mass of water produced when CO2 reacts with LiOH can be determined using the balanced chemical equation and the molar mass of the compounds.

The unbalanced chemical equation for the reaction between carbon dioxide (CO2) and lithium hydroxide (LiOH) is:
CO2 + LiOH → H2O + Li2CO3

To find the molar mass of a compound, you add up the atomic masses of each element in the compound. The molar mass of CO2 can be calculated by adding the atomic masses of carbon (12.01 g/mol) and oxygen (16.00 g/mol).

The balanced chemical equation allows you to determine the ratio of moles of reactants and products. In this case, you can see that for every 1 mole of CO2 reacted, 1 mole of H2O is produced.

The answer needs to have the same number of significant figures as the given data, which is 3 significant figures. Therefore, the mass of water produced when 650 L of CO2 reacts with LiOH is 2.35 kg.

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Answer: The mass number will be 23

Explanation: The mass number refers back to the number of protons and neutrons.