Answer:
I think it is B.
Explanation:
Hope my answer has helped you!
The following IUPAC name is incorrect. Explain why it is incorrect and give the correct IUPAC name. 2,2−dimethyl−4−ethylheptane
a. The compound name is alphabetized incorrectly.
b. The compound has an incorrectly labeled parent chain.
c. The compound has incorrectly labeled substituents.
d. The compound name is spelled incorrectly.
Answer:
Choice a. The compound name is alphabetized incorrectly.
The correct IUPAC name of this compound should be:
4-ethyl-2,2-dimethylheptane.
Explanation:
Draw the carbon backbone structure for "2,2-dimethyl-4-ethylheptane":
[tex]\begin{array}{ccccccccccccc}& &\text{C}\\& & |\\\text{C}&-&\text{C}&-&\text{C}&-&\text{C}&-&\text{C}&-&\text{C}&-&\text{C}\\&&|&&&&|\\&&\text{C}&&&&\text{C}\\&&&&&&|\\&&&&&&\text{C} \end{array}[/tex].
The seven-carbon backbone is indeed the longest chain in this compound.
[tex]\begin{array}{ccccccccccccc}& &\text{C}\\& & |\\\text{C}^1&-&\text{C}^2&-&\text{C}^3&-&\text{C}^4&-&\text{C}^5&-&\text{C}^6&-&\text{C}^7\\&&|&&&&|\\&&\text{C}&&&&\text{C}\\&&&&&&|\\&&&&&&\text{C} \end{array}[/tex].
Numbering from the end with the two methyl groups indeed minimizes the number on each group. However, the alphabetical order of the groups is not correct. There are two kinds of substitute groups in this compound:
Two methyl groups, andOne ethyl group.The name for them will be
2,2-dimethyl, and4-ethyl.Ignore the multiplier prefixes (di-, tri-, etc.) while alphabetizing.
The ethyl group shall be placed before the two methyl groups. The name of the compound shall be:
4-ethyl-2,2-dimethylheptane.
Answer:
It's a.
Explanation:
The substituents are not in alphabetical order. The ethyl substituent should come before the dimethyl ( Note the prefix 'di' is ignored).
The correct name is 4-ethyl-2,2-dimethylheptane.
If the amount of energy required to break bonds in the reactants is more than the amount of energy released in forming bonds in the products, the chemical reaction is endothermic.
True
False
The statement for, "endothermic reaction has high energy for breaking bonds" has been true.
The chemical reaction has been differentiated as the endothermic and exothermic reaction based on the energy absorbed or release by the system.
The chemical compounds have been consisted of the conserved energy that has been released by the chemical when they break the bond. The energy has been absorbed by the bonds for the formation of new bonds.
Do endothermic energy has high energy released?The endothermic reaction has been given as the reaction that has been absorbed the energy from the surrounding for the breaking of bonds.
In the endothermic reaction, the energy for breaking bonds has been higher than the energy required to form new bonds in the products.
Thus, the system absorbs the energy from the surrounding and result in the rise in temperature of the system.
Thus, the statement for, "endothermic reaction has high energy for breaking bonds" has been true.
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Answer:
True
Explanation:
Got it right on the quiz
Which is the basis of thin-layer chromatography?
A.) An electron beam excites atoms within the drug, which give off a characteristic X-ray spectrum.
B.) The drug gets carried through a stationary phase by a mobile phase and the retention time identifies the drug.
C.) The drug fragments have specific molecular weights that bind to the antibodies.
D.) The unknown amount of drug in a sample competes with a known amount of fluorescently labeled drug for binding to an antibody to that drug.
Answer:
B.) The drug gets carried through a stationary phase by a mobile phase and the retention time identifies the drug.
Explanation:
Chromatography is used in purifying complex mixtures of organic compounds. It uses the adsorption tendencies of compounds to seperate and identify them.
Chromatography is made up of two phases in contact, the stationary phase or non-mobile phase and the mobile phase. The movement of the mobile phase over the stationary phase causes the separation of a mixture into its constituents.
The stationary phase is made up of silica-gel or alumina in a solvent (an adsorbent) and the mobile phase or carrier is the organic solvent which is the drug.
Thin-layer chromatography is based on the separation of compounds as they move at different rates through a stationary phase under the influence of a mobile phase, due to their interactions with the stationary material.
Explanation:The basis of thin-layer chromatography (TLC) is the separation of compounds based on their differing rates of movement through a stationary phase, typically a slurry of solid beads of silica or a solid surface of these compounds, under the influence of a mobile phase. The substances are first dissolved in the mobile phase, and as the mobile phase moves through the stationary phase, the components of the mixture interact with the stationary phase to various extents. These interactions can result in different retention times, which are the times that solutes remain in the chromatography system before eluting. As a result, components with different chemical properties can be separated and identified.
TLC is characterized by its use of a stationary phase and a mobile phase, and relies on the physical and chemical interactions between the solute and these phases for separation. Compounds with different affinities for the stationary and mobile phases travel at different speeds, resulting in their separation.
A 250-g sample of copper is heated to 100∘∘C and placed into a cup containing 370 g of water initially at 30.0∘∘C. Ignore the container holding the water, assume no heat is lost or gained to the environment. 1) Find the final equilibrium temperature of the copper and water. (Express your answer to two significant figures.)
Answer:
The final equilibrium temperature of the copper and water, rounded to two significant figures, is 34. °CExplanation:
The solution involves the law of conservation of energy and the equation for heat, Q:
Q = m × Cs × ΔTDue to technichal problems with the editor, I attach the complete explanation in a pdf document.
Please, click on the image of the file to open it and see the full explanation.
To find the final equilibrium temperature of the copper and water, we can use the principle of conservation of energy. The heat gained by the water will be equal to the heat lost by the copper. We can use the equation: mass of copper × specific heat capacity of copper × (final temperature - initial temperature of copper) = mass of water × specific heat capacity of water × (final temperature - initial temperature of water). Solving this equation will give us the final equilibrium temperature of the copper and water.
Explanation:To find the final equilibrium temperature of the copper and water, we can use the principle of conservation of energy. The heat gained by the water will be equal to the heat lost by the copper. We can use the equation:
mass of copper × specific heat capacity of copper × (final temperature - initial temperature of copper) = mass of water × specific heat capacity of water × (final temperature - initial temperature of water)
Plugging in the given values:
0.250 kg × 0.385 kJ/kg°C × (final temperature - 100°C) = 0.370 kg × 4.18 kJ/kg°C × (final temperature - 30°C)
Solving this equation will give us the final equilibrium temperature of the copper and water.
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What is emitted when protons become neutrons
What are the choices?
A proton is changed over into a neutron by the emanation of a positron with a neutrino.
Explanation:In atomic material science, beta decomposition (β-rot) is a sort of radioactive rot wherein a beta molecule (quick lively electron or positron) is transmitted from a nuclear core, changing the first nuclide to its isobar.
For instance, beta rot of a neutron changes it into a proton by the discharge of an electron joined by an antineutrino; or, then again a proton is changed over into a neutron by the emanation of a positron with a neutrino in supposed positron outflow.
An atom of magnesium and two atoms of chloride react and yield the compound of magnesium chloride which option represents the scenario as a chemical equation?
Answer:
[tex]\boxed{\text{Mg + 2Cl $\longrightarrow$ MgCl$_{2}$}}[/tex]
Explanation:
Convert the word equation to a chemical equation.
one atom magnesium + two atoms Cl form magnesium chloride
Mg + 2Cl ⟶ MgCl₂
Answer:
Option E is correct.
Explanation:
An atom of magnesium and two atoms of chloride react and yield the compound of magnesium chloride
Mg + 2Cl -> MgCl₂
Therefore, the correct option is the option E.
Option A shows the decomposition of MgCl₂ to two Mg atom and 1 Cl atom. The reaction is unbalanced. The question has asked for the formation of MgCl₂. Option A is incorrect.
Similarly, option C shows the decomposition of MgCl₂, however, the reaction is balanced. Option C is incorrect.
Option B is incorrect as there are 2 Cl atoms on the reactant side but no Mg atom.
Option D is incorrect as there only 1 Mg atom on the reactant side but no Cl atoms.
the amount of water on Earth is _______but the form and location of the water _______ as it moves through the hydrologic cycle
Hey there!
I can't be sure my answers are the exact words, but it should be something along the lines of...
The amount of water on Earth is constant, but the form and location of the water changes as it moves through the water cycle.
This means that Earth has always had the same amount of water within in, along with it being the same water the whole time. No new water was introduced to our planet. Some of our water is liquid, some is solid, and some is gas. Some is deep in the soil and some is high up in the atmosphere. Some is in rain and some is in snow.
I hope this helps!
A chemist needs 90 milliliters of a 72% solution but has only 68% and 77% solutions available. Find how many milliliters of the 68% solution should be mixed with the 77% solution to get the desired strength.
Answer:
Mix 50 mL of the 68% solution with 40 mL of the 77% solution to make 90 mL of the 72% solution.
Explanation:
Let the volume required of the 68% solution be [tex]x[/tex] mL. The volume of the 68% solution and the 77% solution shall add up to 90 mL. Thus the volume required of the 77% solution shall be [tex](90- x)[/tex] mL.
The amount of solute in the 72% solution will be:
[tex]90\times 72\% = 64.8[/tex].
The [tex]x[/tex] mL of the 68% solution will contribute:
[tex]68\% \cdot x = 0.68\;x[/tex].
The [tex](90- x)[/tex] mL of the 77% solution will contribute:
[tex]77\% \cdot x = 0.77\;(90 - x) = 69.3 - 0.77\;x[/tex].
The two values shall add up to [tex]64.8[/tex]. That is:
[tex]0.68\;x + 69.3 - 0.77\;x = 64.8[/tex].
[tex]-0.09\;x = -4.5[/tex].
[tex]\displaystyle x = \frac{4.5}{0.09} = 50[/tex].
In other words, there need to be
[tex]\rm 50\;mL[/tex] of the 68% solution, and[tex]\rm 90 - 50 = 40\;mL[/tex] of the 77% solution.Carbon monoxide (CO) gas reacts with oxygen
(O2) gas to produce carbon dioxide (CO2) gas. If
1.00 L of carbon monoxide reacts with excess
oxygen at standard temperature and pressure,
what volume of carbon dioxide is produced?
What mass of carbon dioxide is produced?
Answer:
1.94 gExplanation:
1) Chemical equation (unbalanced)
CO (g) + O₂ (g) → CO₂ (g)2) Balanced chemical equation:
2CO (g) + O₂ (g) → 2CO₂ (g)3) Mole ratio:
2 mol CO : 2 mol CO₂, which is the same as 1 : 1.4) Volume ratio:
Since the reaction is carried out at constant pressure and temperature, the volume ratios are equal to the mole ratios. Then:
1 liter CO : 1 liter CO₂Hence, 1.00 liter of CO gas produces 1.00 liter of CO₂
3) Mass of carbon dioxide:
a) Use ideal gas equation to convert 1.00 liter CO₂ produced to moles:
pV = nRT ⇒ n = pV / (RT)R = 0.08206 atm-liter/k-molStandard temperature: T = 273.15 KStandar pressure: 0.986923 atmn = 0.986923 atm × 1.00 liter / (0.08206 atm-liter/K-mol × 273.15 K)n = 0.0440 molb) Convert moles to mass in grams
mass in grams = molar mass × number of molesmolar mass of CO₂ = 44.01 g/molmass = 0.0440 mol × 44.01 g/mol = 1.94 g ← answerAnswer:
1.00L
1.96G
0.500mol
0.750mol
16.8L
Explanation:
A 15.7 g aluminum block is warmed to 53.6 ∘C and plunged into an insulated beaker containing 32.1 g of water initially at 24.2 ∘C. The aluminum and the water are allowed to come to thermal equilibrium.
Assuming that no heat is lost, what is the final temperature of the water and aluminum?
Answer:
27.055 (°C)
Explanation:
the final temperature of the water and the aluminium has the same value: the aluminium block lost the heat, the water 'takes' the heat.
All the details are in the attached picture, the answer is marked with green.
Determine the enthalpy change of the following reaction: CO + H2O -> H2 + CO2
Given enthalpies:
CO: -110.525 kJ/mol
H2: 0 kJ/mol
H2O: -285.8 kJ/mol
CO2: -393.5 kJ/mol
A. 2.825 kJ/mol
B. 789.825 kJ/mol
C. 1.007 kJ/mol
I think A is correct:
deltaH=(Enthalpie of reactents)-(Enthalpie of products)=110.525+285.5-393.5=2.525~2.825
Answer:
A. The enthalpy change for the reaction is 2.825 kJ
Explanation:
The given reaction is:
CO + H2O → H2 + CO2
The enthalpy change for a reaction is given as:
[tex]\Delta H = \sum n(p)\Delta H_{f}^{0}(products)-\sum n(r)\Delta H_{f}^{0}(reactants)[/tex]
where np and nr are the number of moles of products and reactants
ΔH⁰f are the standard enthalpies of formation of the respective reactants and products
[tex]\Delta H = [1\Delta H_{f}^{0}(H2)+1\Delta H_{f}^{0}(CO2)]-[1\Delta H_{f}^{0}(CO)+1\Delta H_{f}^{0}(H2O)][/tex]
Substituting the given enthalpy data:
ΔH = [1(0) + 1(-393.5)] - [1(-110.525) + 1(-285.8)] = 2.825 kJ
which of the following causes tornadoes
1. cool, dry air meeting warm , moist air
2. cool, moist air meeting warm ,dry air
3. typhoons losing energy over land
4. eastern air meeting western air
Answer:
number 2 is correct
Explanation:
Among the options you provided, the correct answer for the cause of tornadoes is option 1: cool, dry air meeting warm, moist air.
What are tornado?Tornadoes typically form in severe thunderstorms where there is a significant clash between different air masses. The interaction of cool, dry air and warm, moist air sets up the conditions necessary for tornado development. This collision can create instability in the atmosphere, leading to the formation of a rotating column of air that extends from the base of a thunderstorm cloud to the ground.
Among the options you provided, the correct answer for the cause of tornadoes is option 1: cool, dry air meeting warm, moist air.
The correct option is 1.
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Which of the following values would you expect for the ratio of half-lives for a reaction with starting concentrations of 0.05M and 0.01M, t1/2 (0.05M) / t1/2 (0.01M), if a reaction is known to be first order?
Answer:
The ratio of half-lives for a reaction with starting concentrations of 0.05M and 0.01M, t1/2 (0.05M) / t1/2 (0.01M) = 1, if a reaction is known to be first order.
Explanation:
For a first- order reaction:the half-life of the reaction is constant and does not depend on the value of the initial concentration.
half-life (t1/2) = 0.693/k,
where, k is the rate constant of the reaction.
So, half;life of first-order reaction is constant whatever the initial concentration.
So the ratio of t1/2 (0.05M) / t1/2 (0.01M) = 1
can anyone check my work/ help me figure out how to do this?
Determine the pH of the following solution.
A 4.5 x 10^-3 M HBr solution
My Work:
all I did was -log(4.5x10^-3) and got 2.35 but I am not sure at all how to do this
Answer:
2.35.
Explanation:
∵ pH = - log[H⁺].
[H⁺] = 4.5 x 10⁻³ M.
∴ pH = - log(4.5 x 10⁻³ M) = 2.346 ≅ 2.35.
How much fluorine (in grams) did the second sample produce? ?Upon decomposition, one sample of magnesium fluoride produced 1.66 of magnesium and 2.56 of fluorine. A second sample produced 1.31 of magnesium.
Answer:
[tex]\boxed{\text{2.02 g F}}[/tex]
Explanation:
You get 2.56 g of F with 1.66 g of Mg.
[tex]\text{Mass of F} = \text{ 1.31 g Mg} \times \dfrac{\text{2.56 g F}} {\text{1.66 g Mg}} = \boxed{\textbf{2.02 g F}}[/tex]
Answer: The mass of fluorine produced in sample 2 will be 2.02 grams
Explanation:
The chemical formula of magnesium fluoride is [tex]MgF_2[/tex]
We are given:
Mass of magnesium in sample 1 = 1.66 grams
Mass of fluorine in sample 1 = 2.56 grams
Mass of magnesium in sample 2 = 1.31 grams
Applying unitary method:
When 1.66 grams of magnesium is produced, the mass of fluorine produced is 2.56 grams
So, when 1.31 grams of magnesium will be produce, the mass of fluorine produced will be = [tex]\frac{2.56}{1.66}\times 1.31=2.02g[/tex]
Hence, the mass of fluorine produced in sample 2 will be 2.02 grams
A sample of nitrogen is initially at a pressure of 1.7 kPa, a temperature of -10 C and a volume of 7.5 m3. Then the volume is decreased to 3.8 m3. the temperature is decreased to 200 K. What is the final pressure of the nitrogen gas?
A. 0.24 kPa
B. 2.55 kPa
C. 11.93 kPa
D. 232.19 kPa
Answer:
Option B is correct
Explanation:
The ideal gas formula can be used to find the Pressure of Nitrogen gas.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Here P is pressure, V is volume and T is temperature.
In the given question:
P₁ = 1.7 kPa
T₁ = -10°C Changing to Kelvin: 273.15 -10°C = 263.15 K
V₁ = 7.5 m^3
V₂ = 3.8 m^3
T₂ = 200 K
P₂ =?
Putting values in the formula
[tex]\frac{1.7 *7.5 }{263.15}=\frac{P_{2*3.8}}{200}\\\frac{12.75}{263.15}=\frac{P_{2}*3.8}{200} \\0.048 = \frac{P_{2}*3.8}{200}\\=> P_{2} = \frac{0.04845*200}{3.8}\\P_{2} = 2.55 \,\,kPa\\[/tex]
So, Option B is correct.
Answer:
B.) 2.55 kPa
Explanation:
I got it correct on founders edtell
Which of the following ions is in the lowest oxidation state?
Answer:
the answer is c :) hope this helps buddy:))
Answer:
C. Fe in Fe₂O₃
Explanation:
The sum of the oxidations states times the atomicity is equal to the charge of the molecule.
A.
2.H + 1.P + 4.O = -1
2.(1+) + 1.P + 4.(2-) = -1
P = +5
B.
2.Cr + 7.O = -2
2.Cr + 7.(-2) = -2
2.Cr = 12
Cr = +6
C.
2.Fe + 3.O = 0
2.Fe + 3.(-2) = 0
2.Fe = 6
Fe = +3
Fe has the lowest oxidation state (+3).
Which of the following best describes the molecular orbital theory of bonding? Choose one: A. A theory of bonding based on the mixing of atomic orbitals of similar shapes and energies to form molecular orbitals that extend to two or more atoms B. A theory where the bonds and lone pairs of valence electrons in a molecule are represented in two-dimensions C. A theory that predicts the arrangement of valence electron pairs around a central atom minimizing their mutual repulsion to produce the lowest-energy orientations D. A theory of bonding that describes bonds as the electrostatic attraction between species of opposite charge E. A theory of bonding that assumes covalent bonds form when half-filled orbitals on different atoms overlap or occupy the same region in space
Final answer:
The molecular orbital theory of bonding involves the combination of atomic orbitals to form molecular orbitals that can extend over multiple atoms, leading to the formation of stabilized and destabilized regions in a molecule depending on the phase of orbital combinations. So the correct option is A.
Explanation:
The molecular orbital theory of bonding is best described by option A: A theory of bonding based on the mixing of atomic orbitals of similar shapes and energies to form molecular orbitals that extend over two or more atoms. This theory utilizes quantum mechanics to describe how electrons are distributed in a molecule, leading to the formation of bonding and antibonding molecular orbitals. Bonding molecular orbitals, which are in-phase combinations of atomic wave functions, stabilize a molecule, while antibonding molecular orbitals, resulting from out-of-phase combinations, make a molecule less stable. Molecular orbitals can incorporate atomic 's' and 'p' wave functions to form σ and π orbitals, respectively. A molecular orbital can hold up to two electrons with opposite spins, analogous to atomic orbitals in isolated atoms.
When table salt (NaCl) is dissolved into water, it breaks into 2 ions, Na+ and Cl-. The water molecules are attracted to them because water is polar. Which of the following is true:
A. Negatively charged oxygen atoms are attracted to positively charged sodium atoms.
B. Positively charged oxygen atoms are attracted to positively charged sodium atoms.
C. Negatively charged hydrogen atoms are attracted to positively charged sodium atoms.
D. Positively charged hydrogen atoms are attracted to positively charged sodium atoms.
Answer:
A
Explanation:
According to Coulomb's Law, like charges repel each other, whereas unlike charges attract each other. This applies to all charged particles.
When NaCl dissociates into its ions in water, we observe the following ions in the system:
Na+ (positive)
Cl - (negative)
H+ (positive)
OH- (negative)
The only correct option is A where the negatively charged oxygen atoms are attracted to the positively charged sodium atoms.
In option B the charge of the oxygen atom is incorrectly mentioned as positive. In option C, the charge of hydrogen atoms is incorrectly mentioned as negative, and in option D the charges of the atoms are correct, but the pairing is incorrect as like charges repel each other.
Hope this helpsAnswer:
D. Positively charged hydrogen atoms are attracted to positively charged sodium atoms.
Explanation:
Founder Education
What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, C2H6 ?In this reaction, ethane is burned in the presence of oxygen (O2 ) to form carbon dioxide (CO2 ) and water (H2O ).____C2H6(g)+____O2(g)→____CO2(g)+____H2O(g)Recall that the coefficients of the final balanced equation should be whole numbers. Thus, you might need to multiply through the equation by a factor of two to obtain whole numbers in your last step.If you have trouble balancing the equation below, use the first hint to view a video of a similar equation being balanced. Then, use the rest of the hints to help you balance the equation, step-by-step.Express the coefficients as integers separated by commas.
2 C2H6(g) + 10O2 >4 CO2(g) + 6 H20
whixh equals
C4 H12 +O20 > C4O8(g) + H12O12
C4=C4
H12=H12
O20=O20
balanced
Final answer:
To balance the combustion of ethane, the final balanced equation with integer coefficients is 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O.
Explanation:
The combustion of ethane (C₂H₆) with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) can be balanced by following these steps:
Write the unbalanced equation: C₂H₆ + O₂ → CO₂ + H₂O.Balance the carbon atoms first: C₂H₆ + O₂ → 2CO₂ + H₂O.Balance the hydrogen atoms next: C₂H₆ + O₂ → 2CO₂ + 3H₂O.Finally, balance the oxygen atoms. Since there are 7 oxygen atoms on the right side (4 in CO₂ and 3 in H₂O), we need ½ that amount of O₂ molecules, because each O₂ contains 2 oxygen atoms. This results in a fractional coefficient for O₂, which is 3.5.To get rid of the fraction, multiply every coefficient by 2: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O.The balanced chemical equation for the combustion of ethane with integer coefficients is: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O.
If I have 3.5 moles of C, and excess Fe2O3 , how many moles of Fe can I produce?
2Fe2O3 + C → Fe + 300,
7 moles Fe
1.17 moles Fe
1.75 moles Fe
3.5 moles Fe
Answer:
3.5 moles Fe
Explanation:
From the equation, Reaction of 2 moles of Fe₂O₃ with 1 mole of C produces 1 mole of Fe. When excess Fe₂O₃ is used, the only liming factor is C.
The ratio of amount of C used to the amount of Fe produced is 1:1
Therefore, if 3.5 moles of C are used, 3.5 moles of Fe are also produced.
An atom of the same element that differs by the number of neutronsa) anionsb) cationsc) element d) isotope e) atom
Answer:
Option d) isotope.Explanation:
All atoms of a same element have equal number of protons (atomic number) but may differ in the number of neutrons.
The atoms that differ in the number of neutrons are named isotopes.
For example: carbon-12 and carbon-13 are diferent isotopes of the same element, carbon. They have the same number of protons (6, which is the atomic number of carbon). On the other hand, while carbon-12 has 6 neutrons, carbon-13 has 7 neutrons.
As per the other choices:
a) anions are ions with negative charges: atoms (or group of atoms) that have gained one or more electrons.b) cations are ions with positive charge: atoms (or group of atoms) that have lost one or more electrons.e) atoms are the individual minimum parts of an element that preserves the properties of such element. All atoms of the same element have the same number of protons and have, essentially, the same chemical properties.What is an ethical vacuum?
A. A scientific idea that lacks ethics.
B. A philosophy that ethics cannot exist in a vacuum, but need specific examples to be valid.
C. When technology has created something for which we do not have an ethical framework yet.
D. The situation of being without ethics.
An ethical vacuum is when technology has created something for which we do not have an ethical framework yet. That is option C.
What is an ethical vacuum?An ethical vacuum can be defined as the development of a structure by technology which lacks ethical framework backup.
Before a new innovation is approved in the society, it needs to be given an ethical backup to be fully assimilated into the society at large.
Therefore, an ethical vacuum is can be defined as when technology has created something for which we do not have an ethical framework yet.
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Order and rate law of a reaction The overall order of an elementary step directly corresponds to its molecularity. Both steps in this example are second order because they are each bimolecular. Furthermore, the rate law can be determined directly from the number of each type of molecule in an elementary step. For example, the rate law for step 1 is rate=k[NO2]2 The exponent "2" is used because the reaction involves two NO2 molecules. The rate law for step 2 is rate=k[NO3]1[CO]1=k[NO3][CO] because the reaction involves only one molecule of each reactant the exponents are omitted. Analyzing a new reaction Consider the following elementary steps that make up the mechanism of a certain reaction: 3A→B+C B+2D→C+F Part A What is the overall reaction? Express your answer as a chemical equation.
Answer:
[tex]\boxed{\text{3A + 2D $\longrightarrow$ 2C + F}}[/tex]
Explanation:
Add the two elementary reactions, cancelling species that occur on each side of the equation
3A ⟶ B + C
B + 2D ⟶ C + F
3A + 2D ⟶ 2C + F
The overall reaction is [tex]\boxed{\textbf{3A + 2D $\longrightarrow$ 2C + F}}[/tex]
The overall mechanism of the given reactions is 3A + 2D → 2C + F.
Explanation:The overall reaction is determined by adding the elementary reactions together and then cancelling out any species that appear on both sides of the reaction. Here, the two elementary steps given are: 3A→B+C and B+2D→C+F. Adding these two reactions gives: 3A + B + 2D → B + C + C + F. Cancel out the 'B' on both sides to get the overall reaction: 3A + 2D → C + C + F, simplified as 3A + 2D → 2C + F.
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There are three different possible structures (known as isomers) of a dibromoethene molecule, C2H2Br2C2H2Br2 . One of them has no net dipole moment, but the other two do. Draw Lewis structures for each of these structures. Include HH atoms.
Answer:
(See sketch attached.)
(E)-1,2-Dibromoethene. No net dipole moment.(Z)-1,2-Dibromoethene. Net dipole moment.1,1-Dibromoethene. Net dipole moment.Explanation:
The molecular formula of dibromoethene is [tex]\rm C_2H_2Br_2[/tex].
Consider the structure of this compound. A carbon-carbon double bond connects two carbon atoms. There are two hydrogen atoms and two bromine atoms attached to the two carbon atoms. The two bromine atoms might be on the same side of the double bond. Alternatively, they may be on opposite sides of the double bond. There are thus two structural isomers with this molecular formula:
1,1-dibromoethene, where the two bromine atoms are on the same side of the double bond; as well as1,2-dibromoethene, where the two bromine atoms are on opposite sides of the double bond.The C-Br bond is polar. There's no way that the dipole due to these bonds will balance each other in 1,1-dibromoethene.
However, these dipoles might indeed balance each other in 1,2-dibromoethene. The two bromine atoms might be either on the same side of the molecule (structure 2) or on opposite sides along the diagonal (structure 1). Besides, unlike groups on two ends of a single bond, groups on the two ends of a C=C double bond cannot rotate freely along the bonding axis. As a result, structure 1 and 2 cannot interconvert without breaking bonds. Structures 1 and 2 are configurational geometric isomers.
The dipoles due to the two C-Br bond balance each other along the diagonal in structure. Thus there's no net dipole in structure 1.
The dipoles due to the two C-Br bonds will not balance each other in structure 2. As a result, there will be net dipole in structure 2.
A Lewis structure is a graphic representation of a molecule's valence electrons and the chemical bonds holding its atoms together. It is sometimes referred to as an electron dot diagram or Lewis electron dot structure.
The Lewis structures for the three dibromoethene isomers are shown here. [tex](C_2H_2Br_2):[/tex]
1,1-Dibromoethene
H H
| |
C=C
| |
Br Br
Due to the dipole moments of the two Br-C bonds canceling one other out, this isomer has no net dipole moment.
1,2-Dibromoethene
H Br
| |
C=C
| |
Br H
Because the dipole moments of the two Br-C bonds do not cancel one other out, this isomer has a net dipole moment. From the Br atoms to the H atoms, the dipole moment is directed.
trans-1,2-Dibromoethene
Br H
| \
C=C
| /
Br H
Because the dipole moments of the two Br-C bonds do not cancel one other out, this isomer likewise possesses a net dipole moment. From the Br atoms to the H atoms, the dipole moment is directed.
Learn more about Lewis structures here : brainly.com/question/29606276
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equilibrium lab analysis questions: use what you learned in this lab to answer the following questions in complete sentences. 1. bromthymol blue, BTB is an acid which has a hydrogen ion, H+. for purposes of this question you will write it HBTB. HBTB ionizes in water to produce hydrogen ion, H+, and bromthymol blue ion, BTB-.a) what color appeared when you added HCL to BTB? b) what color appeared when you added NaOH? c) explain the shift in equilibrium in terms of le chatelier's principle
Answer:
See below
Explanation:
a) Adding HCl
HBTB is yellow in acid solution.
b) Adding NaOH
HBTB is blue in basic solution.
c) Explanation
HBTB is a weak acid in which the undissociated and ionized forms have different colours.
[tex]\underbrace{\hbox{\text{HBTB }}}_{\hbox{\text{yellow}}} + \text{{ H$_{2}$O}}\rightleftharpoons \text{H$_{3}$O$^{+}$} +\underbrace{\hbox{\text{ BTB$^{-}$}}}_{\hbox{\text{blue}}}[/tex]
Around pH 7 , the indicator consists of roughly equal amounts of the yellow and blue forms, so it appears green
According to Le Châtelier's Principle, if you apply a stress to a system at equilibrium, it will respond in a way that will relieve the stress.
When you added HCl, you increased the concentration of H₃O⁺. The system responded in a way that would decrease the H₃O⁺. That is, the position of equilibrium shifted to the left and produced more of the yellow form.
When you added NaOH, the base removed some of the H₃O⁺. The system responded in a way that would increase the H₃O⁺. That is, the position of equilibrium shifted to the right and produced more of the blue form