Load the titanic sample dataset from the Seaborn library into Python using a Pandas dataframe, and visualize the dataset. Create a distribution plot (histogram) of survival conditional on age and gender

Final answer:

To calculate the caffeine level after a certain number of half-lives, use the formula: Caffeine level = Initial caffeine amount * (0.5)^(number of half-lives).

Explanation:

The caffeine level after 6, 12, and 24 hours can be calculated using the concept of half-life. The half-life of caffeine in humans is about 6 hours, which means that after every 6 hours, the amount of caffeine is reduced by half. To calculate the caffeine level after a certain number of half-lives, you can use the formula:

Caffeine level = Initial caffeine amount * (0.5)^(number of half-lives)

For example, if the initial caffeine amount is 200 mg, the caffeine level after 6 hours would be 200 * (0.5)^(6/6) = 100 mg, after 12 hours would be 200 * (0.5)^(12/6) = 50 mg, and after 24 hours would be 200 * (0.5)^(24/6) = 25 mg. Keep in mind that this is a simplified model and real-world factors may affect the actual caffeine levels.

Final answer:

To calculate the caffeine levels after a certain amount of time has passed, you can use the formula: final amount = initial amount × (1/2)^(number of half-lives).

Explanation:

The question is asking for the caffeine levels after a certain amount of time has passed. The half-life of caffeine is about 6 hours in humans. To calculate the caffeine level after 6, 12, and 24 hours, you can use the formula:

final amount = initial amount × (1/2)^(number of half-lives)

Using this formula, you can substitute the given time values to find the caffeine levels. For example, after 6 hours, the caffeine level will be 0.5 times the initial amount, after 12 hours it will be 0.25 times the initial amount, and after 24 hours it will be 0.0625 times the initial amount.

Answer:HUMAN RESOURCES AND PROCEDURE COMPONENTS

Explanation: Information systems are known to contain five components, these components help to describe the various aspects and importance of Information systems.

They Include The DATABASE AND DATA WAREHOUSE components(act as the store for all data), The COMPUTER HARDWARE(the physical components of the information systems such as computer harddrive etc)

THE COMPUTER SOFTWARE( the software which includes all the non physical and intangible assets of the information system),

THE HUMAN RESOURCES AND PROCEDURES COMPONENT( which gives instructions to the users).

THE TELECOMMUNICATIONS.

The procedure component in the five-component model of information systems serves as the essential instructions for users operating the system, guiding them through interactions with both the hardware and software.

According to the five-component model of information systems, the procedure component functions as instructions for the people who use information systems. This component is crucial, as it relates to the operation of hardware and the application of software by guiding users through decision-making processes and ensuring effective interaction between users and the system. Procedures can often dictate how data is entered, how users interact with the hardware and software, and how outputs are interpreted, thus influencing the overall efficiency and accuracy of an information system.

Answer:

The solution code is written in Java.

Explanation:

Firstly, we need to create an array to hold a list of letters (Line 6). In this solution, only letters A - J are given for simplicity.

Next, we declare all the variables that we need, numRows, numColumns, currentRow and currentColumn (Line 8 - 11).

Next, we use Scanner object, scnr to prompt user to input integer for numRows and numColumns (Line 12-13).

At last, we use two-layer for loops to traverse through the number of rows and columns and print out the currentRow and currentColumn (Line 15-19). Please note the currentRow is added by 1 as the currentRow started with 0. To print the letter, we use currentColumn as an index to take out the letter from the array.

Answer:

False

Explanation:

That's not true about an embedded system.

To compare the values of compareNumber and userNumber and display the appropriate message, one need to use the strict equality operator (==).

So, The current code is using the loose equality operator (===), which compares both the values and the types of the operands.

In the case of 3 and "3", they are considered equal using the strict equality operator, but not using the loose equality operator.

Below is the code to compare the values using the strict equality operator is:

JavaScript

let compareNumber = 3; // Code will be tested with: 3, 8, 42

let userNumber = '3'; // Code will be tested with: '3', 8, 'Hi'

if (compareNumber === userNumber) {

 console.log('Variables are identical');

} else if (compareNumber == userNumber) {

 console.log('Numbers are equal');

} else {

 console.log('Numbers are not equal');

}

See text below

Compare userNumber with compareNumber and display 'Numbers are not equal' if the numbers are different. Then, display 'Variables are identical' if the variables are identical (strictly equal).

Code provided to complete the assignment:

let compareNumber = 3; // Code will be tested with: 3, 8, 42

let userNumber = '3'; // Code will be tested with: '3', 8, 'Hi'

Code I have so far:

if (compareNumber === userNumber){

  console.log("Variables are identical");

  }

else{

  if (compareNumber == userNumber){

     }

  console.log("Numbers are not equal");

}

Results:

✖

Testing log when compareNumber = 3 and userNumber = "3"

Yours and expected differ. See highlights below.

Yours

Numbers are not equal

Expected

Expected no output

Testing log when compareNumber = 8 and userNumber = 8

Yours

Variables are identical



Testing log when compareNumber = 42 and userNumber = "Hi"

Yours

Numbers are not equal

Answer:

Explanation:

  p := FIRST(L);

  while p <> END(L) do begin

      q := p;

      while q <> END(L) do begin

          q := NEXT(q, L);

          r := FIRST(L);

          while r <> q do

              r := NEXT(r, L)

      end;

      p := NEXT(p, L)

  end;

To enable remote VPN logins to Active Directory domain controllers using Kerberos and LDAP, you must open ports389 and 88 for LDAP and Kerberos, respectively, and port 636 if secure LDAP is used.

To support remote logins via VPN to the Active Directory domain controllers using Kerberos and LDAP, specific ports need to be opened to facilitate this functionality. For LDAP, you would typically need to open port 389 for standard LDAP communications or port 636 if you require secure LDAP (LDAPS) over SSL/TLS. Kerberos, which is an authentication protocol that Active Directory uses, typically runs on port 88. Therefore, to support VPN remote logins to AD domain controllers, ports 389, 636, and 88 are necessary to be opened in your firewall.

Answer:

Option B: tan (x) sin^2 (x) / (cos(x) + 1).  is best.

Following is attached the image describing the reason or choosing option B.

Explanation:

Answer:

   while(userNum>=1){

       System.out.print(userNum/2+" ");

       userNum--;

        }

Explanation:

This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

   Scanner in = new Scanner (System.in);

       System.out.println("Enter the number");

   int userNum = in.nextInt();

   while(userNum>=1){

       System.out.print(userNum/2+" ");

       userNum--;

        }

   }

}

The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of   userNum until reaching 1 (Hence userNum>=1)

Answer:

1. C) Embedded Style

2. C) User Agent Style

Explanation:

1. Alex will use Embedded style to create styles that apply only to the HTML document that the style was created. With Embedded styling; the rules can be embedded into the HTML document using the <style> element.

2. Since Alex has forgotten to give any style for all of his pages, the style that will be applied to his pages is User Agent Style. User Agent Style is the default style of a browser. The browser has a basic style sheet that gives a default style to any document and this style is called User Agent.

Alex should use embedded styles for each of his HTML pages, as these styles apply only to the specific page they are defined on. If no style is specified for any of the pages, the browser applies its default style, known as the user agent style.

For Alex to apply styles only to the HTML document in which they are created, embedded styles (also known as internal styles) is the way to go. Embedded styles are defined within the <style> tag found in the <head> section of the HTML file. These styles are only active on the specific page they are defined on.

Now, for the style that would automatically apply to his pages if Alex forgets to give any style, the answer is the user agent style. This is the default style provided by the browser, which it uses when no specific style is defined by the webpage.

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Answer:

The Program is written in C++

#include<iostream>

using namespace std;

int main()

{

//Variable declaration

double m2;

cout<<"Input your mass (in kilogram): ";

cin>>m2;

//Constant declaration and initialisation

double G = 0.00000000006673;

double m1 = 5974200000000000000000000;

double r = 6378000;

double g = 9.8;

//Calculating Gravitational Force

double F = G * m1 * m2 / (r * r);

//Print Gravitational Force

cout<<"Gravitational Force = "<<F;

// Calculating Force exerted on earth

F = m2 * g;

cout<<"Force = "<<F;

//Calculating acceleration due to gravity (g) caused by the

// gravitational force exerted on him/her by the Earth.

g = G * m2 / (r * r);

cout<<"Gravity Exerted on Earth: "<<g;

return 0;

}

//End of Program

//Comments were used to explain some lines of codes

//Program was implemented using C++

Explanation:

Answer:

Explanation:

Answer:

Answers explained below

Explanation:

(a) Construction of a heap of size n , where the keys are not known in advance.

Worst Case Time complexity - O(n log n)

Two procedures - build heap, heapify

Build_heap takes O(n) time and heapify takes O(log n) time. Every time when an element is inserted into the heap, it calls heapify procedure.

=> O(n log n)

(b) Selection-sort on a sequence of size n.

Worst Case Time complexity - O(n^2)

Selection sort finds smallest element in an array repeatedly. So in every iteration it picks the minimum element by comparing it with the other unsorted elements in the array.

=> O(n^2)

(c) Merge-sort on a sequence of size n.

Worst Case Time complexity - O(n log n)

Merge sort has two parts - divide and conquer. First the array is divided (takes O(1) time) into two halves and recursively each half is sorted (takes O(log n) time). Then both halves are combines (takes O(n) time).

=> O(n log n)

(d) Radix sort on a sequence of n integer keys, each in the range of[ 0 , (n^3) -1]

Worst Case Time complexity - O (n log b (a))

b - base of the number system, a - largest number in that range, n - elements in array

Radix sort is based on the number of digits present in an element of an array A. If it has 'd' digits, then it'll loop d times.

(e) Find an element in a red-black tree that has n distinct keys.

Worst Case Time complexity - O (log n)

Red-black tree is a self-balancing binary tree => The time taken to insert, delete, search an element in this tree will always be with respect to its height.

=> O(log n)

Final answer:

Suitable colors for building the pits on a compact disc, based on their wavelengths compared to pit dimensions, are violet, indigo, blue, and cyan. Green, yellow, orange, and red are unsuitable due to their longer wavelengths.

Explanation:

To determine which colors from the visible spectrum could be used for building the pits on a compact disc, we must consider the wavelength of light compared to the size of the pits. The pits on the disc measure 850 nm long by 500 nm wide. Visible light has wavelengths that range from approximately 400 nm for violet to 740 nm for red.

Based on this, colors that have a wavelength shorter than the size of the pits can be used to read the information. Using longer wavelengths would lead to diffraction and an inability to resolve the individual pits. Therefore, the suitable colors consist of violet, indigo, blue, and cyan, as their wavelengths are all shorter than or close to the dimensions of the pits. Green, yellow, orange, and red have wavelengths that are too long to be used effectively for this purpose.

It should be noted that CD technology specifically uses light with a wavelength of 780 nm, DVDs use 650 nm, and Blu-ray discs use 405 nm, indicating that different types of optical media require specific wavelengths of light based on the size of the pits and the spacing between them.

Explanation:

A system specific firewall has certain restrictions. Just as its name the system specific firewall works for a single host.

It is important to note that in networking Firewalls are very important inorder to safeguard the networking system.

Therefore, using an appliance firewall will be a better option because it can work on all operating system since it is open source; meaning it is customizable to fit the large enterprise needs.

An appliance firewall, such as pfSense, is a better fit for a large enterprise than an operating system-specific firewall due to its scalability, customization options, and performance.

An appliance firewall, such as pfSense, might be a better fit for a large enterprise than an operating system-specific firewall, such as Windows Firewall, for several reasons:

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Answer:

FALSE

Explanation:

The blanket purchase agreement (BPA) can not serves as an agreement that documents the technical requirements of interconnected assets but the Interconnection service agreement (ISA).

Answer:

Option A is the correct answer for the above question.

Explanation:

Final answer:

The appropriate method to set the window width to 100 pixels and the height to 200 pixels is A) setSize(100, 200).

Explanation:

The correct option that sets the window width to 100 pixels and the height to 200 pixels is A) setSize(100, 200). This typically corresponds to a method in a graphical user interface (GUI) library in programming, where the first value passed to setSize represents the width and the second value represents the height. Hence, to set the width to 100 pixels and the height to 200 pixels, setSize(100, 200) would be the suitable method call.

Answer:

Following is attached the code as well as the output according to the requirements. I hope it will help you!

Explanation:

Answer:

Internet protocol network layer is referred to as that service that connects the computer, or another connecting modem to the internet network.

Explanation:

Internet protocol network layer is referred to as that service that connects the computer, or another connecting modem to the internet network.

The Internet layer is comprised of protocols,  methods that are used to transmit the data packets across the network boundaries. The basic motive on which internet layer work is to modify the internet working, it allows transparency in internet working.

Answer:

The answer is "Option D".

Explanation:

Linear hierarchical systems are like: that employer only has once supervisor (manager), the main purpose to use this model to link between both the layers of the organization is hierarchical, supervisors are not qualified, conceptual model is relatively low and centralization large, and other choices were wrong, that can be described as follows:

Answer:

// Program is written in C++ Programming Language

/) Comments are used for explanatory purpose

#include <iostream>

#include <string>

#include <cctype>

#include <ctime>

using namespace std;

int main() {

// Declare and accept input for string variable passCode

string passCode;

cin >> passCode;

// declaring character array

char ch[2];

// copying the contents of the string to char array

strcpy(ch, passCode.c_str());

// Iterate char arrray ch

for(int i=0; i<2;i++)

{

// Check if first and second element is an alphabet

if((ch[i]>='a' && ch[i]<='z') || (ch[i]>='A' && ch[i]<='Z'))

{

// Replace if the condition above is true

ch[i] = '_';

}

}

// Print passCode

for (int i = 0; i < n; i++)

cout << ch[i];

return 0;

}

Explanation:

Answer:

// Program is written in C++ Programming Language

/) Comments are used for explanatory purpose

#include <iostream>

#include <string>

#include <cctype>

#include <ctime>

using namespace std;

int main() {

// Declare and accept input for string variable passCode

string passCode;

cin >> passCode;

// declaring character array

char ch[2];

// copying the contents of the string to char array

strcpy(ch, passCode.c_str());

// Iterate char arrray ch

for(int i=0; i<2;i++)

{

// Check if first and second element is an alphabet

if((ch[i]>='a' && ch[i]<='z') || (ch[i]>='A' && ch[i]<='Z'))

{

// Replace if the condition above is true

ch[i] = '_';

}

}

// Print passCode

for (int i = 0; i < n; i++)

cout << ch[i];

return 0;

}

Explanation:

Answer:

Explanation:

1. double ***alloc3dArrayOfInts( int length, int width, int depth) {

2. double ***array3d = malloc(length * sizeof(double **) );

3. for(int i=0; i< length ;i++) {

4. array3d[i] = malloc(width * sizeof(double *) );

5. for(int j=0; j< width;j++) {

6. array3d[i][j] = malloc(depth * sizeof(double) );

7. }

8. }

9. return array3d;

10. }

Answer:

#include<iostream>

using namespace std;

int main()

{

   char a;  

   char b;  

   char c;

cin >> a;  

cin >> b;  

cin >> c;

 cout<<a<<b<<c<<endl;

 cout<<a<<c<<b<<endl;

 cout<<b<<a<<c<<endl;

 cout<<b<<c<<a<<endl;

 cout<<c<<a<<b<<endl;

 cout<<c<<b<<a<<endl;

cout << endl;

}

Explanation:

Note: code is hard coded it does not contain any logic based coding

The C++ program requires concatenation of character variables a, b, and c in specific patterns to output all combinations. The provided code snippet correctly orders and outputs all permutations of these characters, which fulfills the task requirements.

The task is to create a C++ program that outputs all combinations of three character variables in a specified order. The student is asked to write the code that would display every permutation of the variables a, b, and c. To achieve this, the code within the main function should directly output the combinations by concatenating the variables in the correct sequence using cout.

Here's the solution for the main part of your code:

When you input 'x', 'y', 'z' as the values for a, b, and c, respectively, the output will be: xyz xzy yxz yzx zxy zyx. This code will generate the correct combinations for any set of three unique characters provided at the input.

Answer:

#include <stdio.h>

int main() {    

   const float square_feet;

   printf("Enter area in square feets: ");  

   // reads and stores input  area

   scanf("%f", &square_feet);

   float acres= square_feet/43560;

   // displays area in acres

   printf("area in acres is: %.2f", acres);

   return 0;

}

Explanation:

code is in C language.

double slashed '//'  lines are  not code but just comments to understand what it mean in code or for explanation purpose

Final answer:

The student's question involves creating a program to convert square feet into acres using a constant value for the conversion. The provided pseudocode example uses a constant variable to store the number of square feet in an acre and outputs the result in acres formatted to two decimal places.

Explanation:

The question pertains to writing a program that calculates the number of acres based on the total square feet of a piece of land. Given that one acre of land is equivalent to 43,560 square feet, the student is asked to use this figure as a constant value within the algorithm. The result should be formatted to display the answer to two decimal places. Here is a simple example of how such a program could be structured in pseudocode:

CONSTANT SQFT_PER_ACRE = 43560
function convertToAcres(sqft):
   acres = sqft / SQFT_PER_ACRE
   return format(acres, '.2f')

// Prompt user for input
total_sqft = input('Enter the total square feet of land: ')
// Convert and display the result
print(convertToAcres(float(total_sqft)), 'acres')

This program will first define the constant SQFT_PER_ACRE, which holds the value 43,560. It will then define a function convertToAcres that takes the square footage as an input, performs the conversion by dividing it by SQFT_PER_ACRE, and returns the formatted value. The user is prompted to enter the total square feet, and the result is outputted in acres formatted to two decimal places.

Answer:

Option A, Option B, and Option C are the correct options.

Explanation:

The following options are correct because when any person is facing a problem related to its laptop and he wanted to contact with the customer service agent to solve his problem of the Laptop that is his Laptop battery does not work more than the half-hour and his Laptop's battery not charge more than 15%.

So, his laptop will be facing the problems related to Battery, LCD power inverter, or AC adapter.

Answer:

Model B should be deployed.

Explanation:

(a) I would deploy the model that does well on generalizing well on validation data and does considerably well on training data, Hence, Model B should be deployed because it has less BIAS and the problem of overfitting the training set is evaded.

(b) Model A does well on the training dataset and not very well on test/validation dataset because it has OVERFITTED the training set.

OVERFITTING is a scenario where the model has large variance and low bias, that is has a perfect representation of the training set and performs woefully on generalizing validation set. For instance when a neural network has too much hidden layers and no regularization or dropout.

OVERFITTING is a common scenario in model Development.

Final answer:

Model B is slightly less accurate on the training data but more accurate on validation data, suggesting better generalization capabilities and making it a better candidate for final deployment. Model A's overfitting to the training data likely causes its reduced accuracy on validation data.

Explanation:

When comparing two models applied to a data set, the choice for final deployment depends not just on accuracy but on the model's ability to generalize. In this scenario, Model B may be preferred for final deployment because while it is less accurate on the training data, its higher accuracy on validation data suggests better generalization, which means it could perform more reliably with new, unseen data. The higher accuracy of Model A on training data may indicate overfitting, where the model is too closely tailored to the training set and doesn't perform well in predicting outcomes for data it hasn't seen before.

The phenomenon where a model is highly accurate on training data but performs worse on unseen data is common in machine learning and is a classic symptom of overfitting. Overfitting occurs because the model learns the noise in the training data alongside the actual signal. This noise does not generalize to new data, hence the dip in accuracy when applied to validation data. In contrast, Model B's slightly lower performance on training data but marginally better performance on validation data suggests it may have struck a better balance between bias and variance, leading to a potentially more robust model that is less likely to overfit.

Answer:

Explanation:

1. If we enter to the BIOS we can enable or disable components, we can find the issue with this option.

2. In the BIOS we can set or reset power-on passwords, this option is really important to administrate our access and passwords.

3. We can change the date and time of the system, some troubles are only for that.

Complete Question

Write a method so that the main() code below can be replaced by the simpler code that calls method calcMiles() traveled.

Original main():

public class Calcmiles {

public static void main(string [] args) {

double milesperhour = 70.0;

double minutestraveled = 100.0;

double hourstraveled;

double milestraveled;

hourstraveled = minutestraveled / 60.0;

milestraveled = hourstraveled * milesperhour;

System.out.println("miles: " + milestraveled); } }

Answer:

import java.util.Scanner;

public class CalcMiles

{

public double CalculateMiles (double miles, double minutes)

{ //Method CalculateMiles defined above

//Declare required variables.

double hours = 0.0;

double mile = 0.0;

//Calculate the hours travelled and miles travelled.

hours = minutes / 60.0;

mile = hours * miles;

//The total miles travelled in return.

return mile;

}

public static void main(String [] args)

{

double milesPerHour = 70.0;

double minsTravelled = 100.0;

CalculateMiles timetraveles = new CalculateMiles();

System.out.println("Miles: " + timetravels.CalculateMiles(milesPerHour, minsTraveled));

}

}

//End of Program

//Program was written in Java

//Comments are used to explain some lines

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Answer:

   public static double convertToInches(double numFeet, double numInches){

       return (numFeet*12)+numInches;

   }

Explanation:

This technique of having more than one method/function having the same name but with different parameter list is called method overloading. When the method is called, the compiler differentiates between them by the supplied parameters. The complete program is given below

public class FunctionOverloadToInches {

   public static void main(String[] args) {

       double totInches = 0.0;

       totInches = convertToInches(4.0, 6.0);

       System.out.println("4.0, 6.0 yields " + totInches);

       totInches = convertToInches(5.9);

       System.out.println("5.9 yields " + totInches);

       return;

   }

   public static double convertToInches(double numFeet)

       {

           return numFeet * 12.0;

       }

       /* Your solution goes here */

   public static double convertToInches(double numFeet, double numInches){

       return (numFeet*12)+numInches;

   }

}

Answer:

7

Explanation:

class width=(largest value-smallest value)/k

where k is the number of classes.

According to 2^k>n rule

We choose different value of k till we get the 2^k greater than number of observation.

The given value of n=60

Now,

2^1=2 <60

2^2=4 <60

2^3=8 <60

2^4=16 <60

2^5=32 <60

2^6=64 >60

So, k=6.

Now class width=(largest value-smallest value)/k

class width=72-30/6

class width=42/6=7

class width=7

Final answer:

The estimated class width for a data set of 60 observations using the 2k > n rule is 7.

Explanation:

To determine the estimated class width using the 2k > n rule, where k is the number of classes and n is the number of observations, we begin by finding a value for k such that 2k > n. Since there are 60 observations (n = 60), we look for the smallest k that satisfies this inequality.

We can start checking values of k starting from 1:

Now that we have found that 26 = 64 is greater than 60, we take k = 6 as the number of classes. Next, we calculate the range by subtracting the minimum value from the maximum value (72 - 30 = 42). The class width can be estimated by dividing the range by the number of classes, so our estimated class width is 42 / 6 = 7.

Answer:

C++ code given below with appropriate comments

Explanation:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

{

int i,j,k;

if(n%2) //odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i || j==(n-i+1))

cout<<j;

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i || j==(n-i+1))

{

cout<<" "<<j<<" ";

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

void printForwardSlash(int n)

{

if(n%2)

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==n-i+1)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==(n-i+1))

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

void printBackwardSlash(int n)

{

if(n%2) // odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

int main()

{

int num;

char ch;

cout<<"Create a numberes shape that can be sized."<<endl;

cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;

cin>>num>>ch;

if(ch=='x' || ch=='X')

printCross(num);

else if(ch=='f' || ch=='F')

printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}