Answer:
(a) Mass flow rate is 2528.75 kg/min
(b) Molar flow rate is 458.1 mol/s
(c) Toulene is in-compressible at standard temperature and pressure
Explanation:
The volume flow rate of liquid toulene is given:
Volume Flow Rate = 175 m^3/h
Density of Liquid Toulene = 867 kg/m^3
Molar mass of Toulene = 92 g/mol = 0.092 kg/mol)
(a)
Thus, the mass flow rate of toulene will be:
Mass Flow Rate = (Volume Flow Rate)(Density)
Mass Flow Rate = (175 m^3/h)(867 kg/m^3)
Mass Flow Rate = (151725 kg/h)(1 h/60 min)
Mass Flow Rate = 2528.75 kg/min
(b)
Now, for molar flow rate we use formula:
Molar Flow Rate = (Mass Flow Rate)/(Molar Mass)
Molar Flow Rate = (2528.75 kg/min)/(0.092 kg/mol)
Molar Flow Rate = (27486.41 mol/min)(1 min/60sec)
Molar Flow Rate = 458.1 mol/s
(b)
The assumption is that Toulene is in-compressible at standard temperature and pressure. So, that its density can be taken constant.
Ultra-thin semiconductor materials are of interest for future nanometer-scale transistors, but can present undesirably high resistance to current flow. How low must the resistivity of a semiconductor material be, to ensure that the resistance of a 2nm-thick, 10nm-long, 100nm-wide region does not exceed 100 ohms?
Answer:
p = 2*10^(-7) ohm m
Explanation:
The resistivity and Resistance relationship is:
[tex]p = \frac{R*A}{L}[/tex]
For lowest resistivity with R < 100 ohms.
We need to consider the possibility of current flowing across minimum Area and maximum Length.
So,
Amin = 2nm x 10 nm = 2 * 10^(-16) m^2
Lmax = 100nm
Using above relationship compute resistivity p:
[tex]p = \frac{100*2*10^(-16)}{100*10^(-9)} \\\\p = 2 * 10^(-7)[/tex]
Answer: p = 2*10^(-7) ohm m
for the given sand, the maximum and minimum dry unit weights are 108 lb/ft3 and 92 lb/ft3, respectively. given that Gs=2.65, determine the moist unit weight of the soil when the relative density is 60% and moisture content is 8%.
Answer:
The moist unit weight of compaction = 109.05 lb/ft3
Explanation:
In order to determine the moist unit weight, the dry unit weight has to be evaluated first. If Y is the moist unit weight, then:
Y = Yd (1 + m)
Where:
Yd = dry unit weight
m = moisture content of soil = 8% = 0.08
But the dry unit weight is unknown. In order to calculate the dry unit weight, we will make use of the formula for relative density R;
R = [(Yd — Ydmin) ÷ (Ydmax — Ydmin)] × [Ydmax ÷ Yd]
Where:
R = relative density = 60% = 0.6
Yd = dry unit weight
Ydmin = minimum dry weight = 92 lb/ft3
Ydmax = maximum dry weight = 108 lb/ft3
Therefore R = 0.6 = [(Yd — 92) ÷ (108 — 92)] × [108/Yd]
0.6 = [(Yd — 92)/16] × [108/Yd], or
0.6 = (0.0625Yd — 5.75) × [108/Yd]
0.6Yd = 6.75Yd — 621
6.75Yd — 0.6 Yd = 621
6.15Yd = 621
And Yd = 100.98 lb/ft3 = dry unit weight
But we are asked to find the moist unit weight = Y = Yd (1 + m)
where Yd = dry unit weight and m = moisture content of soil = 8% = 0.08
Therefore, Y = 100.98 (1 + 0.08) = 109.05 lb/ft3.
The Program Manager (PM) should request a Counterintelligence (CI) analysis when an acquisition program containing Critical Program Information (CPI) is initiated. The CI analysis focuses on _____________________ and on how to counter the opposition's collection efforts.
Based on the provided information, The CI analysis focuses on how the opposition sees the program and on how to counter the opposition's collection efforts.
According to the given question, we are to discuss about Program Manager and how he should request a Counterintelligence analysis in case of acquisition program containing Critical Program Information.
As a result if this we can see that how the opposition sees the program should be the first thing that should be considered by Program Manager.
Therefore, The CI analysis focuses on how the opposition sees the program and on how to counter the opposition's collection efforts.
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A Counterintelligence (CI) analysis, requested by a Program Manager (PM) for acquisition programs with Critical Program Information (CPI), primarily focuses on identifying potential threats like foreign intelligence entities, understanding how these entities may seek to compromise the CPI, and devising strategies to counter such threats.
Explanation:A Program Manager (PM) should indeed request a Counterintelligence (CI) analysis when initiating an acquisition program involving Critical Program Information (CPI). The primary focus of a CI analysis is threat identification and mitigation. It is centered on identifying potential threats such as foreign intelligence entities and determining how these entities might access or compromise the CPI.
Additionally, the CI analysis also develops strategies on how to effectively counter the adversary's collection attempts to ensure the safeguarding of sensitive information.
For example, if the program involves the development of a military technology, the CI team would determine the potential adversaries who might be interested in the technology, their possible collection methods, and ways to counter such collection efforts. This could entail securing communication lines, implementing stricter access control, or even disseminating misinformation to confuse potential spies.
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Air flows through a device in which heat and work is exchanged. There is a single inlet and outlet, and the flow at each boundary is steady and uniform. The inlet flow has the following properties: flowrate 50 kg/s, T 25 °C, and velocity 150 m/s. Heat is added to the device at the rate of 42 MW, and the shaft work is -100 kW (assume the efficiency is 100 %). The exit velocity is 400 m/s Calculate the specific stagnation enthalpy (J/kg or kJ/kg) at the inlet, and use the 1st Law to calculate the specific stagnation enthalpy at the exit. Assume constant cp1.0 kJ/kg -K. Calculate the temperature of the air at the exit. Was the assumption of constant cp a good one?
Answer:
11548KJ/kg
10641KJ/kg
Explanation:
Stagnation enthalpy:
[tex]h_{T} = c_{p}*T + \frac{V^2}{2}[/tex]
given:
cp = 1.0 KJ/kg-K
T1 = 25 C +273 = 298 K
V1 = 150 m/s
[tex]h_{1} = (1.0 KJ/kg-K) * (298K) + \frac{150^2}{2} \\\\h_{1} = 11548 KJ / kg[/tex]
Answer: 11548 KJ/kg
Using Heat balance for steady-state system:
[tex]Flow(m) *(h_{1} - h_{2} + \frac{V^2_{1} - V^2_{2} }{2} ) = Q_{in} + W_{out}\\[/tex]
Qin = 42 MW
W = -100 KW
V2 = 400 m/s
Using the above equation
[tex]50 *( 11548- h_{2} + \frac{150^2 - 400^2 }{2} ) = 42,000 - 100\\\\h_{2} = 10641KJ/kg[/tex]
Answer: 10641 KJ/kg
c) We use cp because the work is done per constant pressure on the system.
A floor in an office building is made of a reinforced concrete slab 10 in. deep and spans 20 ft. For the purposes of calculating the tributary load you can assume the slab is 10 ft. wide. This scenario can be modelled as a simply supported beam, 20 ft. long, 10 in. deep and 10 ft. wide.
Calculate the maximum factored maximum moments and shears on this structure using the appropriate load combinations discussed in class.
Note which loading combination is critical.
You can assume the uniform live load is 50 psf.
Hint: since this is not a member that carries lateral load, there are no significant wind or earthquake loads contributing to the shear and moments in the member.
Since this is not on the roof there are no roof or snow loads. h = 10 in. 20 ft.
Hi, your question didn't have any images, hence I am attaching the complete question in the attachment below.
Answer:
Please refer to the attachment below for answers.Explanation:
Please refer to the attachment for explanation.CHALLENGE ACTIVITY 2.8.1: Using constants in expressions. The cost to ship a package is a flat fee of 75 cents plus 25 cents per pound. 1. Declare a const named CENTS_PER_POUND and initialize with 25. 2. Get the shipping weight from user input storing the weight into shipWeightPounds. 3. Using FLAT_FEE_CENTS and CENTS_PER_POUND constants, assign shipCostCents with the cost of shipping a package weighing shipWeightPounds.
Answer:
int CENTS_PER_POUND = 25;
shipWeightPounds = scnr.nextInt();
shipCostCents = (shipWeightPounds * CENTS_PER_POUND) + FLAT_FEE_CENTS;
Explanation:
We declare a constant named CENTS_PER_POUND in the first line of ode as the answer.
scnr.nextInt(); is how we get our imput, then we declare it to shipWeightPounds.
and lastly the math, we get the weight and multiply it by how much the money costs per weight, and then lastly add the flat fee bc its mandatory fee.
Full Code:
import java.util.Scanner;
public class ShippingCalculator {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int shipWeightPounds;
int shipCostCents = 0;
final int FLAT_FEE_CENTS = 75;
int CENTS_PER_POUND = 25;
shipWeightPounds = scnr.nextInt();
shipCostCents = (shipWeightPounds * CENTS_PER_POUND) + FLAT_FEE_CENTS;
System.out.println("Weight(lb): " + shipWeightPounds);
System.out.println("Flat fee(cents): " + FLAT_FEE_CENTS);
System.out.println("Cents per pound: " + CENTS_PER_POUND);
System.out.println("Shipping cost(cents): " + shipCostCents);
}
}
What is a coarse-grained rock composed of intermediate plagioclase feldspar and pyroxene? a. graniteb. gabbro c. andesited. peridotitee. diorite
Answer:
B.gabbro
Explanation:
Gabbro is a coarse-grained, dark-colored igneous
rock . It is usually black or dark green in color and composed mainly of the minerals plagioclase and augite. It is the most abundant rock in the deep oceanic crust. Gabbro is used in construction.
Felix has placed some Copper wire (where the official looked up inferred absolute temperature is 234.5 Celsius) 28 gauge wire in a freezer at 15.3 degrees Fahrenheit. He measures the resistance of the COLD wire to be 15.3 ohms. What is the length of the wire in units of feet?
Answer:
2.14 ft
Explanation:
We will use the following equation:
[tex]L = \frac{R_{T} * A}{p_{20C}*(1+\alpha _{20C}*dt ) }[/tex]
Data obtained:
[tex]R_{15.3 F , -9.27 C} = 15.3 ohms\\A_{28-gauge} = 8.2*10^(-8) m^2\\p_{20 C} = 1.723*10^(-6)\\\alpha _{20C} = 0.00393\\ dt = 20 - (-9.27) = 29.28[/tex]
Using the above equation:
[tex]L = \frac{15.3 * 8.2*10^(-8)}{1.723*10^(-6)*(1+0.00393*29.28 ) }\\\\L =0.6530 m = 2.14 ft[/tex]
A polymeric extruder is turned on and immediately begins producing a product at a rate of 10 kg/min. An operator realizes 20 minutes later that the production rate is too low, and increases the production rate to an immediate 15 kg/min. An hour later, an emergency causes the outlet valve to rapidly adjust to 1 kg/min. One minute later, the emergency is resolved, and the outlet valve is allowed to rapidly readjust to 10 kg/min. Plot production rate m(t) in kg/min against time t in min. Determine the production rate function m(t) in the time domain, and then determine the Laplace transform of m(t).
Answer:
The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.
The production rate function M(t) is:
[tex]m(t)=[H(t)\cdot10+H(t-20)\cdot5-H(t-80)\cdot14+H(t-81)\cdot9]kg/min[/tex] (1)
The Laplace transform of this function is:
[tex]\displaystyle m(s)=[\frac{10+5e^{-20s}-14e^{-80s}+9e^{-81s}}{s}]kg/min[/tex] (2)
Explanation:
The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.
For the Laplace transform we use the following rules:
[tex]\mathcal{L}[f(x)+g(x)]=\mathcal{L}[f(x)]+\mathcal{L}[g(x)]=F(s)+G(s)[/tex] (3)
[tex]\mathcal{L}[aH(x-b)]=\displaystyle\frac{ae^{-bs}}{s}[/tex] (4)
Write a simple calculator program. Your program should ask for three things two whole numbers and an operator in the form of an expression like: 3 * 2 Use a select case structure to determine what operation needs to be performed on the two numbers. Your program should handle the arithmetic functions Add, Subtract, Multiply, and Divide (Depending on the operator entered).
Answer:
The solution code is written in Java.
Scanner input = new Scanner(System.in); System.out.print("Enter operator: "); String operator = input.nextLine(); System.out.print("Enter first integer: "); int num1 = input.nextInt(); System.out.print("Enter second integer: "); int num2 = input.nextInt(); int result = 0; switch(operator){ case "+": result = num1 + num2; break; case "-": result = num1 - num2; break; case "*": result = num1 * num2; break; case "/": result = num1 / num2; break; default: System.out.println("Invalid operator"); } System.out.println(result);Explanation:
To ask for the user input for two whole numbers and an operator, we can use Java Scanner class object. Since the input operator is a string, we can use nextLine() method to get the operator string (Line 3). We use nextInt() method to get whole number input (Line 5 & 7).
Next we use the switch keyword and pass the operator into the switch structure to determine which case statement should be executed. For example, if the input operator is "*" the statement "result = num1 * num2; " will run and multiply num1 with num2.
a(n)___ branch circuit supplies two or more receptacles or outlets for lighting and appliances
Answer: General purpose branch circuit
Explanation:
General purpose branch circuit are the type of circuits that are used mainly to supply light to two or more receptacle outlets for small appliances. This circuits are about 120v can be used either in residential, commercial and industrial buildings.
What is the minimum hose diameter of an ideal vacuum cleaner that could lift a 14 kg dog off the floor?
To determine the minimum hose diameter for lifting a 14 kg dog with a vacuum cleaner, physics principles related to pressure and force are applied. The calculation involves the dog's weight and the pressure difference a vacuum needs to create over the hose's cross-sectional area. However, without specific vacuum specifications, an exact diameter cannot be determined.
Explanation:Calculating the Minimum Hose Diameter for a Vacuum Cleaner to Lift a Dog
To determine the minimum hose diameter of an ideal vacuum cleaner that could lift a 14 kg dog off the floor, we need to understand the principles of pressure and force in a vacuum system. This involves a bit of physics, specifically relating to the pressure difference created by the vacuum and the surface area over which this pressure acts.
The force required to lift the dog can be calculated using the formula F = m × g, where m is the mass of the dog (14 kg) and g is the acceleration due to gravity (approximately 9.8 m/s2). This gives us a force of approximately 137.2 N (newtons).
To lift the dog, the vacuum cleaner must create a pressure difference greater than the weight of the dog distributed over the area of the hose's opening. The pressure (Π) required can be found using Π = F/A, where A is the cross-sectional area of the hose. To find the minimum diameter, we rearrange the area formula A = πr2 (where r is the radius of the hose) to solve for diameter, taking into account that the area must be sufficient to create a pressure difference capable of lifting the dog.
Without specific pressure values from a vacuum cleaner, we cannot calculate an exact diameter but can assert the importance of a vacuum cleaner's pressure capability and the diameter's role in generating enough lift. In an ideal scenario, the vacuum would have to reduce the air pressure significantly inside the hose compared to the atmospheric pressure outside to create enough lift force.
Therefore, while this offers a theoretical framework, the practical application would depend on specific vacuum cleaner specifications, including its ability to create a low enough pressure and maintain a high flow rate, which were not provided in this question.
A geothermal pump is used to pump brine whose density is 1050 kg/m3 at a rate of 0.3 m3/s from a depth of 200 m. For a pump efficiency of 90 percent, determine the required power input to the pump. Disregard frictional losses in the pipes, and assume the geothermal water at 200 m depth to be exposed to the atmosphere.
Answer:
Input power of the geothermal power will be 686000 J
Explanation:
We have given density of brine [tex]\rho =1050kg/m^3[/tex]
Rate at which brine is pumped [tex]V=0.3m^3/sec[/tex]
So mass of the pumped per second
Mass = volume × density = [tex]1050\times 0.3=315[/tex] kg/sec
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Depth h = 200 m
So work done [tex]W=mgh=315\times 9.8\times 200=617400J[/tex]
Efficiency is given [tex]\eta =0.9[/tex]
We have to fond the input power
So input power [tex]=\frac{617400}{0.9}=686000J[/tex]
So input power of the geothermal power will be 686000 J
Explain the conductivity results observed for ionic compounds in the solid state and in aqueous solution.i.Solid ionic compounds don’t have a conductivity because there isn’t any free space. However, in an aqueous solution ionic compounds have free space causing it to be conductive
Answer:
Aqueous solution of ionic compounds conduct electricity while solid ionic compounds don't.
Explanation:
Ionic compound conduct electricity when liquid or in aqueous solution that is resolved in water because the ionic bonds of the compound become weak and the ions are free to move from place to place.
Ionic compounds don't conduct electricity while in solid state because the ionic bonds are to strong and ions cannot move around with lack of space for movement which makes the electric conductivity zero.
Solid ionic compounds don't have any electrical conductivity as they are not free to move. Hence they lack the free space as compared to the molten or aqueous solution where there exist some gaps and pockets.
Since the melting of the ions takes up lots of heat they are in a molten state and such ions can conduct electricity when they are dissolved in water. Hence they can move around freely.The solids ions that dissolve in the water are called electrolytes as compounds such as acids.
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A rectangular weir is in a rectangular channel 2.9 m wide. The length of the weir is 1.9 m and is centered in the channel. If the water level is 0.2 m above the surface of the weir, what is the discharge in the channel (m3/sec)
Answer:
discharge = 0.310976 m³/s
Explanation:
given data
rectangular channel wide = 2.9 m
length of weir L = 1.9 m
water level H = 0.2 m
solution
we get here discharge that is express as
discharge = [tex]\frac{2}{3} * C_d * L* \sqrt{2g} * H^{\frac{3}{2} }[/tex] ............................1
we consider here Coefficient of discharge Cd = 0.62
put here value we get
discharge = [tex]\frac{2}{3} * 0.62 * 1.9* \sqrt{2*9.8} * 0.2^{\frac{3}{2} }[/tex]
discharge = 0.310976 m³/s
Suppose that a bank only permits passwords that are strings from the alphabet = {a, b, c, d, 1, 2, 3, 4} that follow the rules:
The length is at least five characters
It begins with a letter {a, b, c, d}
It ends with two digits {1, 2, 3, 4}
The set of legal passwords forms a regular language L. Construct a regular expression r such that L(r) = L.
Answer:
#Python
import re
password = input("Enter password: ")
p = re.compile('^[ABCDabcd]+.*[^e-zE-Z5-9_]{2,}[1-4][1-4]+$')
match = p.search(password)
if match == None:
print('L(r) != L -> Incorrect password')
else:
print('L(r) = L -> Correct password')
Explanation:
The regular expression needed is:
^[ABCDabcd]+.*[^e-zE-Z5-9_]{2,}[1-4][1-4]+$
To understand why see the step by step of the regex:
^[ABCDabcd]: Here we use ^ to indicate the first character of the class, then we use [] to specify a character class, then we punt ABCDabcd to indicate that the first character has to begin with a letter from a to d and finally we use a + to continue our expression.*[^e-zE-Z5-9_]{2,}: Here we use .* to specify the sequence of characters that comes after the first letter, then we put ^e-zE-Z5-9_ inside brackets, the first character, ^, tell us that the characters coming are forbidden, so the user can not use a number, letter or special character outside of the sequence defined, and finally, we have curly brackets to indicate the length of the expression, where '2,' represents that the length in the middle is at least two characters long[1-4][1-4]+$: With the two brackets in this expression the string must ends with two digits from one to fourth and the $ refers to the end of the expressionNote: if you don't have python you can use an online regex checker like myregextester, note that the string must be at least five characters long because you need one letter at the beginning, at least two characters in the middle and two numbers at the end.
The rigid bar CDE is attached to a pin support at E and rests on the 30 mm diameter brass cylinder BD. A 22 mm diameter steel rod AC passes through a hole in the bar and is secured by a nut which is snugly fitted when the temperature of the entire assembly is 20oC. The temperature of the brass cylinder is then raised to 50oC while the steel rod remains at 20oC.
Assuming that no stresses were present before the temperature change,
determine the stress in the cylinder.
The stress in the brass cylinder can be calculated using a thermal stress formula that considers the modulus of elasticity, coefficient of linear expansion, and temperature change of the brass. Specific material properties for brass are needed to plug into the formula.
Explanation:The stress in the cylinder can be found by considering that an increase in temperature will cause the brass cylinder BD to expand, while the steel rod AC remains the same length. This will cause an extra stress in the brass cylinder due to the constraints. The stress can be calculated using the formula σ = EαΔT where:
E is the modulus of elasticity for the material, α is the coefficient of linear expansion of the material, and ΔT is the temperature change.In order to use this thermal stress formula, you will need to look up the specific properties for brass in a materials textbook or reliable online resource. Substitute these values into the formula to get the stress in the brass cylinder caused by the temperature change.
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A particle is moving along a straight line with an initial velocity of 3 m/s when it is subjected to a deceleration of a = - 1.1 v^1/2 m/s^2 .A. Determine how far it travels before it stops.B. How much time does it take?
Answer:
Explanation:
Given that
initial velocity ,[tex]v= 3 m/s[/tex]
[tex]a=-1.1v^{\dfrac{1}{2}}[/tex]
We know that
[tex]a=v\dfrac{dv}{dx}[/tex]
Lets take x is the distance before coming to the rest.
The final speed of the particle = 0 m/s
[tex]v\dfrac{dv}{dx}=-1.1v^{\dfrac{1}{2}}[/tex]
[tex]\dfrac{dv}{dx}=-1.1v^{-\dfrac{1}{2}}[/tex]
[tex]v^{\dfrac{1}{2}}{dv}=-1.1dx[/tex]
[tex]\int_{3}^{0}v^{\dfrac{1}{2}}{dv}=-\int_{0}^{x}1.1dx[/tex]
[tex]\left [v^{\dfrac{3}{2}}\times \dfrac{2}{3}\right]_3^0=-1.1x[/tex]
[tex]3^{\dfrac{3}{2}}\times \dfrac{2}{3}=1.1x[/tex]
[tex]x=\dfrac{3.46}{1.1}\ m\\x=3.14\ m[/tex]
(b)time taken by it
[tex]a=\frac{\mathrm{d} v}{\mathrm{d} t}=-1.1\sqrt{v}[/tex]
[tex]\int_{3}^{0}\frac{dv}{\sqrt{v}}=-1.1\int_{0}^{t}dt[/tex]
[tex]\int_{0}^{3}\frac{dv}{\sqrt{v}}=1.1\int_{0}^{t}dt[/tex]
[tex]2\times 3\sqrt{3}=1.1t[/tex]
[tex]t=9.44\ s[/tex]
An inductor (L = 400 mH), a capacitor (C = 4.43 µF), and a resistor (R = 500 Ω) are connected in series. A 44.0-Hz AC generator connected in series to these elements produces a maximum current of 385 mA in the circuit.
(a) Calculate the required maximum voltage ΔVmax.
(b) Determine the phase angle by which the current leads or lags the applied voltage.
Answer:
(A) Maximum voltage will be equal to 333.194 volt
(B) Current will be leading by an angle 54.70
Explanation:
We have given maximum current in the circuit [tex]i_m=385mA=385\times 10^{-3}A=0.385A[/tex]
Inductance of the inductor [tex]L=400mH=400\times 10^{-3}h=0.4H[/tex]
Capacitance [tex]C=4.43\mu F=4.43\times 10^{-3}F[/tex]
Frequency is given f = 44 Hz
Resistance R = 500 ohm
Inductive reactance will be [tex]x_l=\omega L=2\times 3.14\times 44\times 0.4=110.528ohm[/tex]
Capacitive reactance will be equal to [tex]X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 44\times 4.43\times 10^{-6}}=816.82ohm[/tex]
Impedance of the circuit will be [tex]Z=\sqrt{R^2+(X_C-X_L)^2}=\sqrt{500^2+(816.92-110.52)^2}=865.44ohm[/tex]
So maximum voltage will be [tex]\Delta V_{max}=0.385\times 865.44=333.194volt[/tex]
(B) Phase difference will be given as [tex]\Phi =tan^{-1}\frac{X_C-X_L}{R}=\frac{816.92-110.52}{500}=54.70[/tex]
So current will be leading by an angle 54.70
Write a program to store numbers from 1 to 100 in an array. Print out all the even numbers from the array. Use the enhanced FOR loop for printing out the numbers.
Answer:
The java program to print all even numbers from 1 to 100 is given below.
import java.util.*;
public class Program
{
// integer array of size 100
static int[] num = new int[100];
public static void main(String[] args) {
// array initialized using for loop with values from 1 to 100
for(int j=0; j<100; j++)
{
num[j] = j+1;
}
System.out.println("Even numbers from 1 to 100 are ");
// enhanced for loop
for(int n : num)
{
// testing each element of the array
// only even numbers will be displayed
if( (n%2) == 0)
System.out.print(n + " ");
}
}
}
OUTPUT
Even numbers from 1 to 100 are
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100
Explanation:
The program works as described.
1. An integer array, num, of size 100 is declared.
2. Inside for loop which executes 100 times, array is initialized with numbers from 1 to 100.
3. An enchanced for loop differs from normal for loop such that it doesn't has initialization and increment or decrement conditions.
4. The syntax for an enchanced for loop is shown below.
for( datatype variable_name : array_name )
{ }
In the above syntax, the datatype of the variable_name should be the same as that of the array_name.
The array used in program is shown below.
for(int n : num)
5. Inside enhanced for loop, if statement is included to test each element of array, num, for even or odd number.
if( (n%2) == 0)
6. If the number is even, it is displayed followed by a space.
System.out.print(n + " ");
7. The method println() differs from print() such that new line is inserted after the message is displayed.
8. This program can also be used to display odd numbers by changing the condition inside if statement.
Provide an argument justifying the following claim: The average (as defined here) of two Java ints i and j is representable as an int, regardless of the lower and upper bounds on the value of an int.
Answer:
public static int average(int j, int k) {
return (int)(( (long)(i) + (long)(j) ) /2 );
}
Explanation:
The above code returns the average of two integer variables
Line 1 of the code declares a method along with 2 variables
Method declared: average of integer data type
Variables: j and k of type integer, respectively
Line 2 calculates the average of the two variables and returns the value of the average.
The first of two integers to average is j
The second of two integers to average is k
The last parameter ensures average using (j+k)/2
Given an array of primitive integers named grades, fill in the blank to complete the following code that calculates the average of all the grades: double average = 0; average + grades[ average (= grades.length; Use proper spacing per the course style guide. Do not include additional spaces at the beginning or end.
Answer:
C++ snippet is given below with appropriate comments and explanation
Explanation:
Code snippet:
double average=0;//declaring variable
//using for loop
for(int i=0;i<grades.length;i++)
{
average+=grades[i];//add each grade to average
}
average/=grades.length;//find average
Explanation :
Above code snippet need a for loop to add each grade from the array to the variable average,
average/=grades.length; this will compute average.
For the following pairs of sinusoidal time functions, determine which one leads/lags and by how much. (a) ????1(????)=4sin(6π×104????+60°) V and ????2(????)=2cos(6π×104????−20°) V. (b) ????(????)=10cos(400????−75°) V and ????(????)=4sin(400????+30°) A.
Answer:
The question is incomplete, the complete question is given below
"For the following pairs of sinusoidal time functions, determine which one leads/lags and by how much. (a) V1(t) =4sin(6π×10^4t+60°)V and V(t)2=2cos(6π×10^4t−20°)V. (b) V(t)=10cos(400t−75°) V and I(t)=4sin(400t+30°) A.
Answer
A. V2(t) leads V1(t) by 10°
B. I(t) leads V(t) by 15°
Explanation:
First we express the relationship between sine and cosine of a value.
The expression is giving below Cos (wt) =Sin(wt+90)
Hence for the equations above, we write
a. We can v(t) as
V1(t)=4Sin(6π*10^4+90°-30°)
V1(t)=4Cos(6π*10^4-30°)
Comparing to
V2(t)=4Cos(6π*10^4-20°)
Comparing the angle, we notice that V2(t) leads V1(t) by 10°
b. We can write the current wave form as
I(t)=4sin(400t+90°-60°)
I(t)=4Cos(400t-60°)
If we compare with V(t)=10cos(400t−75°)
I.e 4Cos(400t-60°)=10cos(400t−75°)
We can conclude that I(t) leads V(t) by 15°
Given A = {1,2,42,57,99,538,677}, B = {1,5,6,7,{2,3} , and C ={1,{7}, {8,9}}, answer the following questions, use the proper notation:Write an inequality that represents the cardinality of any proper subset of A. Let’s say the cardinality of the subset is C.
Answer:
c < 7
Explanation:
The cardinal indicates the number or quantity of the elements of a set, be this finite or infinite quantity.
Given, A = {1, 2, 42, 57, 99, 538, 677}
B = {1, 5, 6, 7, {2, 3} }
C = {1, {7}, {8, 9} }
Let's say the cardinality of the subset is: c
Inequality that represents the cardinality of any proper subset of A is: c < 7
Hope this helps!
An inequality that represents the cardinality of any proper subset of A is c<7.
Given, A = {1, 2, 42, 57, 99, 538, 677}
B = {1, 5, 6, 7, {2, 3} }
C = {1, {7}, {8, 9} }
Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
Let's say the cardinality of the subset is: c
Inequality that represents the cardinality of any proper subset of A is: c < 7
Therefore, an inequality that represents the cardinality of any proper subset of A is c<7.
To learn more about the inequalities visit:
https://brainly.com/question/20383699.
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A 0.9% solution of NaCl is considered isotonic to mammalian cells. what molar concentration is this?
Answer:
58.44 g/mol The Molarity of this concentration is 0.154 molar
Explanation:
the molar mass of NaCl is 58.44 g/mol,
0.9 % is the same thing as 0.9g of NaCl , so this means that 100 ml's of physiological saline contains 0.9 g of NaCl. One liter of physiological saline must contain 9 g of NaCl. We can determine the molarity of a physiological saline solution by dividing 9 g by 58 g... since we have 9 g of NaCl in a liter of physiological saline, but we have 58 grams of NaCl in a mole of NaCl. When we divide 9 g by 58 g, we find that physiological saline contains 0.154 moles of NaCl per liter. That means that physiological saline (0.9% NaCl) has a molarity of 0.154 molar. We can either express this as 0.154 M or 154 millimolar (154 mM).
Water needs to be turned into steam in a high altitude lab where the atmospheric pressure is 84.6 KPa. Computte the heat energy (in calories) required to evaporate 900g of water at 15 degree C under these conditions.
Answer:
558.1918 kilocalories = 558191.8 calories
Explanation:
Data provided in the question:
Atmospheric pressure = 84.6 KPa
Mass of water, m = 900 g = 0.90 kg
Temperature = 15°C
Now,
Temperature at 84.6 KPa = 94.77°C
Therefore,
Heat energy required = m(CΔT + L)
here,
C is the specific heat of the water = 4.2 KJ/kg.°C
L = Latent heat of water = 2260 KJ/kg
Thus,
Heat energy required = 0.90[ 4.2 × (94.77 - 15) + 2260 ]
= 2335.53 KJ
also,
1 KJ = 0.239 Kilocalories
Therefore,
2335.53 KJ = 0.239 × 2335.53 Kilocalories
= 558.1918 kilocalories = 558191.8 calories
Universal Containers (UC) has a requirement to expose a web service to their business partners. The web service will be used to allow each business partner to query UC's Salesforce instance to retrieve the status of orders. The business partner should only be allowed access to orders for which the business partner is the fulfillment vendor. The Architect does not want the business partners to utilize the standard APIs and would prefer a custom API be developed. Which three design elements should the Architect consider in order to ensure the data security of the solution?
Answer:
"- Set the Orders object's sharing settings to Private in the Org-Wide Defaults
_Provide each partner with their own Salesforce login set to API Enabled on the profile
-Develop a custom Apex web service using the "With Sharing" keyword"
Explanation:
Universal Containers (UC) has a requirement to expose a web service to their business partners. The web service will be used to allow each business partner to query UC's Salesforce instance to retrieve the status of orders. The business partner should only be allowed access to orders for which the business partner is the fulfillment vendor. The Architect does not want the business partners to utilize the standard APIs and would prefer a custom API be developed. Which three design elements should the Architect consider in order to ensure the data security of the solution?
A. Query the Orders object with Dynamic SOQL based upon the fulfillment ID.
B. Set the Orders object's sharing settings to Private in the Org-Wide Defaults
C. Provide each partner with their own Salesforce login set to API Enabled on the profile.
D. Develop a custom Apex web service with a fulfillment ID input attribute
E. Develop a custom Apex web service using the "With Sharing" keyword.
The above should be a follow up option to the question
The Architect should consider the following design
"- Set the Orders object's sharing settings to Private in the Org-Wide Defaults
_Provide each partner with their own Salesforce login set to API Enabled on the profile
-Develop a custom Apex web service using the "With Sharing" keyword"
There is need for some sharing rule between the architect and the user
Suppose that the voltage is reduced by 10 percent (to 90 VV). By what percentage is the power reduced? Assume that the resistance remains constant.
Answer:
The power is reduced by 19 percent.
Explanation:
The formula of power is given by:
[tex]P = \frac{V^{2}}{R}[/tex]
In which V is the voltage, and R is the resistance.
I am going to use R = 1 in both cases.
With the original voltage, V = 1, we have
[tex]P = \frac{V^{2}}{R} = \frac{1}{1} = 1[/tex]
With the modified voltage, V = 0.9, we have:
[tex]P = \frac{V^{2}}{R} = \frac{0.9^{2}}{1} = 0.81[/tex]
So the power is reduced by 1-0.81 = 0.19 = 19 percent.
A 220-V electric heater has two heating coils that can be switched such that either coil can be used independently or the two can be connected in series or parallel, for a total of four possible configurations. If the warmest setting corresponds to 2,000-W power dissipation and the coolest corresponds to 300 W, find the resistance of each coil.
Answer:
The resistances of both coils are 131.7 Ω and 29.64 Ω.
Explanation:
Since, there are two coils, they can be used independently or in series or parallel. The power is given as:
Power = P = VI
but, from Ohm's Law:
V = IR
I = V/R
therefore,
P = V²/R
R = V²/P
Hence, the resistance (R) and (P) are inversely proportional. Therefore, the maximum value of resistance will give minimum power, that is, 300 W. And the maximum resistance will be in series arrangement, as in series the total resistance gets higher than, any individual resistance.
Therefore,
Rmax = V²/Pmin = R1 + R2
R1 + R2 = (220 V)²/300 W
R1 + R2 = 161.333 Ω ______ en (1)
Similarly, the minimum resistance will give maximum power. And the minimum resistance will occur in parallel combination. Because equivalent resistance of parallel combination is less than any individual resistance.
Therefore,
(R1 R2)/(R1 + R2) = (220 V)²/2000 W
using eqn (1), we get:
(R1 R2) / 161.333 Ω = 24.2 Ω
R1 R2 = 3904.266 Ω²
R1 = 3904.266 Ω²/R2 _____ eqn (2)
Using this value of R1 in eqn (1), we get:
3904.266/R2 +R2 = 161.333
(R2)² - 161.333 R2 +3904.266 = 0
Solving this quadratic eqn we get two values of R2 as:
R2 = 131.7 Ω OR R2 = 29.64 Ω
when ,we substitute these values in eqn (1) to find R1, we get get the same two values as R2, alternatively. This means that the two coils have these resistance, and the order does not matter.
Therefore, the resistance of both coils are found to be 131.7 Ω and 29.64 Ω
List four (or more) issues addressed by Information Assurance that are often not addressed by Information Security.
Answer:
Issues addressed by Information Assurance (AI) that are often not addressed by Information Security:
- Ensures the quality of information
- Ensures reliability of information
- Ensures retrievability of information
- Provides information restoration systems
- Provides an assorted response options for retrieving information
Explanation:
Both, Information Assurance and Information Protection (or Information Security as defined by the NIST), provide preventive measures to uphold information systems´ integrity, confidentiality for protecting personal privacy and proprietary information with authorized restrictions on access and disclosure, and availability, ensuring protection of information systems from unauthorized access, use, disclosure, disruption, modification, or destruction.
Information protection also uses security solutions, like encryption and other technologies. It can be considered as a sub-component of information assurance.
Differentiating both terms can be tricky, as the terms are inherently linked and both aim integrity of information preservation.
In addition to the benefits provided by information protection, information assurance also focuses on data integrity, authenticity, reliability, usability, non-repudiation, confidentiality, availability and timely access to information. It means a broader strategic initiative comprised of a wide range of information protection and management processes.