Answer: 30
Step-by-step explanation: Start off by multiplying the two numbers.
3 x 10 = 30.
30 is a common multiple. Find any multiples below 30. Let’s start off using the biggest number of the two, which is 10, to see what other numbers can be multiples. 10, 20, and 30 can be. 3 can’t be divided into 10 or 20, so your least common multiple is 30.
The perimeter of a quadrilateral is 38 yards. If three of the sides measure 5.8 yards, 7 yards, and 11.2 yards, what is the length of the fourth side?
Answer:
14 yds
Step-by-step explanation:
To find the perimeter, we add up all the sides
P = s1 + s2+ s3 + s4
38 = 5.8+7+11.2 + s4
Combine like terms
38 = 24+s4
Subtract 24 from each side
38-24 = 24-24 +s4
14 = s4
The 4th side is 14 yds
Answer:
14yd
Step-by-step explanation:
Round the following decimal to the nearest tenth.
543.67
Answer:
543.7
Step-by-step explanation:
.67 is closer to .7 than to .6
Answer:
543.7
Step-by-step explanation:
The 7 rounds up to a 6 in the tenth place.
What is the range of this promblem
Answer:
3
Step-by-step explanation:
Range is the largest number minus the smallest number
4-1 = 3
The range is 3
Answer:
3
Step-by-step explanation:
The range of a set of data is the difference between the highest and lowest values in the set.
Sort your data from lowest to highest. You get
1, 2, 3, 4, 4, 4, 4, 4
Highest value = 4
Lowest value = 1
Range = 3 chocolate chips
Express 0.0000594 using scientific notation
Answer:
5.94×10^6
Step-by-step explanation:
you have to move the decimal 6 times before reaching the next number then you have to mutiply it by 10 and put the 6
Find the coordinates of point B that lies along the directed line segment from A(-5, 2) to C(11, 0) and partitions the segment in the ratio of 5:3.
A. (3, 1)
B. (5,3/4)
C. (10, 5)
D. (6, 2)
ANSWER
The correct answer is B.
EXPLANATION
If the point B(x,y) partitions
[tex]A(x_1,y_1)[/tex]
and
[tex]C(x_2,y_2)[/tex]
in the ratio m:n then, then we have
[tex]x = \frac{mx_2+nx_1}{m + n} [/tex]
and
[tex]y= \frac{my_2+ny_1}{m + n} [/tex]
We want to find the coordinates of the point B(x,y) that lies along the directed line segment from A(-5, 2) to C(11, 0) and partitions the segment in the ratio of 5:3.
This implies that:
[tex]x = \frac{5 \times 11+3 \times - 5}{5 + 3} [/tex]
[tex] \implies \: x = \frac{55 - 15}{8} [/tex]
[tex] \implies \: x = \frac{40}{8} = 5[/tex]
[tex]y = \frac{5 \times 0 + 3 \times 2}{5 + 3} [/tex]
[tex]y = \frac{0 + 6}{8} [/tex]
[tex]y = \frac{6}{8} = \frac{3}{4} [/tex]
Therefore the coordinates of B are
[tex](5, \frac{3}{4} )[/tex]
Answer:
B. (5,3/4)
Step-by-step explanation:
Since, when a segment having end points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is divided by or partitioned by a point, that lies on the segment, in the ratio of m : n,
Then the coordinates of that points are,
[tex](\frac{mx_2+nx_1}{m+n}, \frac{my_2+my_1}{m+n})[/tex]
Here, point B that lies along the directed line segment from A(-5, 2) to C(11, 0) and partitions the segment in the ratio of 5:3,
Thus, the coordinates of B are,
[tex](\frac{5\times 11+3\times -5}{5+3}, \frac{5\times 0+3\times 2}{5+3})[/tex]
[tex](\frac{55-15}{8}, \frac{0+6}{8})[/tex]
[tex](\frac{40}{8}, \frac{6}{8})[/tex]
[tex](5, \frac{3}{4})[/tex]
Option 'B' is correct.
2x+5y=20 select the ordered pair that is a solution to the equation
Answer:
The ordered pair that is a solution to the equation (5, 2)
Step-by-step explanation:
It is given that,
2x + 5y = 20
To find the ordered pairs
Multiples of 2 are,
2, 4, 6, 8, 10, 12....
Multiples of 5 are,
5, 10, 15, 20,...
20 can be written as,
20 = 2x + 5y
2x is the multiple of 2 and 5y is the multiple of 5
From the above data we get, 20 = 10 + 10
2x = 10 then x = 5
5y = 10 then y = 2
Therefore the ordered pair that is a solution to the equation (5, 2)
Final answer:
To determine if an ordered pair is a solution to the equation 2x + 5y = 20, substitute the values into the equation and check if the simplified result equals 20.
Explanation:
To find an ordered pair that is a solution to the equation 2x + 5y = 20, we need to check which pair (x, y) satisfies the equation when we substitute the values of x and y into it. This involves basic algebraic skills, including substitution and simplification.
Step-by-Step Explanation
Select a potential ordered pair solution.Substitute the x-value and the y-value into the equation.Simplify to see if the values satisfy the equation and make it true.If the left side of the equation equals the right side after substitution, then the ordered pair is a solution to the equation. For example, if we substitute x = 2 and y = 4, we get 2(2) + 5(4) = 20 which simplifies to 4 + 20 = 24, not equal to 20. Thus, (2,4) is not a solution. Find an ordered pair where, after the substitution and simplification, the equation is satisfied.
In which direction would you progress in order to find the terminal quadrant of a -400 degree angle?
Clockwise
Counterclockwise
Both
Neither
Answer:
negative angles are clockwise
Step-by-step explanation:
negative angel: An angle whose generating line is rotated clockwise.
hope this helps!!
Clockwise and counterclockwise are used to indicate the direction of an angle.
The terminal quadrant of -400 degrees is in the clockwise direction
The angle is given as:
[tex]\mathbf{\theta = -400^o}[/tex]
The condition for clockwise direction is: [tex]\mathbf{\theta < 0}[/tex]
While the condition for counterclockwise direction is:[tex]\mathbf{\theta > 0}[/tex]
By comparison:
[tex]\mathbf{-400 < 0}[/tex]
Hence, the terminal quadrant of -400 degrees is in a clockwise direction
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What is the following quotient?
sqr root 6 + sqr root 11/ sqr root 5+ sqr root 3
Answer:
[tex]\frac{\sqrt{30}-3\sqrt{2}+\sqrt{55}-\sqrt{33} }{2}[/tex]
Step-by-step explanation:
The given expression is
[tex]\frac{\sqrt{6}+\sqrt{11}}{\sqrt{5}+\sqrt{3} }[/tex]
To solve this quotient, we just have to apply a rationalization, which consists in eliminating every root in the denominator. To do so, we multiply and divide the expression by the opposite binomial of the denominator, as follows
[tex]\frac{\sqrt{6}+\sqrt{11}}{\sqrt{5}+\sqrt{3} }=\frac{\sqrt{5}-\sqrt{3} }{\sqrt{5}-\sqrt{3} }\\\\\frac{(\sqrt{6}+\sqrt{11})(\sqrt{5}-\sqrt{3})}{(\sqrt{5}+\sqrt{3})(\sqrt{5}-\sqrt{3})}\\\\\frac{\sqrt{30}-\sqrt{18}+\sqrt{55}-\sqrt{33} }{5-3}\\ \\\frac{\sqrt{30}-3\sqrt{2}+\sqrt{55}-\sqrt{33} }{2}[/tex]
Therefore, the right answer is the second option.
Find the solution of this system of equations.
Separate the x- and y-values with a comma.
x - 4y = -22
x- y=-10
Enter the correct answer.
DONE
Answer:
{-6,4}
Step-by-step explanation:
Given
x-4y=-22 Eqn 1
x-y=-10 Eqn 2
Subtracting both equations:
The left hand side of equation 2 will be subtracted from left hand side of eqn 1 and the right side of equation 2 will be subtracted from right hand side of eqn 1.
[tex](x-4y)-(x-y)=-22-(-10)\\x-4y-x+y=-22+10\\-4y+y=-12\\-3y=-12\\\frac{-3y}{-3}=\frac{-12}{-3}\\ y=4[/tex]
Putting y=4 in eqn 2
[tex]x-4=-10\\x=-10+4\\x=-6\\So,\\Solution Set = \{-6,4\}[/tex]
Answer:
{x, y} = {-6, 4}
Step-by-step explanation:
It is given that,
x - 4y = -22 ------(1)
x - y= -10 -------(2)
To ind the value of x and y
subtract eq(2) from eq(1)
x - 4y = -22 ------(1)
x - y= -10 -------(2)
0 -3y = -12
3y = 12
y = 12/3 = 4
Substitute the value of y in eq (1)
x - 4y = -22 ------(1)
x - (4*4) = -22
x - 16 = -22
x = -22 +16 = -6
Therefore {x, y} = {-6, 4}
There are 162 people waiting in line to ride a roller coaster when the line closes for the day. Each roller coaster car holds 12 people. After loading c cars on the roller coaster, there are 6 people still in line. Write an equation to represent the number of cars, c, that have been loaded on the roller coaster. Solve the equation to find the number of cars on the roller coaster.
Answer:
13 Cars Have Been Loaded, Equation: 12x + 6 = 162
Step-by-step explanation:
If a car holds 12 people, and there are 162 people waiting divide 162 by 12. This gives you 13.5, which means that 13 total cars have been loaded, while .5 or 6 are left waiting on the line. So 13!
Answer:
162
Step-by-step explanation:
ADD EMMM UPPP GIRLLLLLGET IT TOGETHER
If x + y = 12 and xy = -5, calculate the value of 1/x + 1/y.
[tex]\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{y}{xy}+\dfrac{x}{xy}=\dfrac{x+y}{xy}=\dfrac{12}{-5}=-\dfrac{12}{5}=-2,4[/tex]
20p!!!ill mark you as brain please help!!! hurry
Answer:
[tex]\boxed{\text{1172 in}^{2}}[/tex]
Step-by-step explanation:
SA = SA(prism) + SA(cylinder) – 2SA(cylinder base)
1. Surface area of rectangular prism
The formula for the surface area of a rectangular prism is
S = 2(lw + lh + wh)
Data:
l = 16 in
w = 11 in
h = 11 in
Calculations:
2(Top + Bottom) = 2lw = 2 × 16 × 11 = 352 in²
2(Front + Back) = 2lh = 2 × 16 × 11 = 352 in²
2(Left + Right) = 2wh = 2 × 11 × 11 = 242 in²
Total area = 946 in²
2. Surface area of cylinder
A = A(top) + A (base) + A(side) = 2A(base) + A(side)
Data:
d = 8 in
h = 9 in
Calculations:
r = ½d = ½ × 8 = 4 in
[tex]\begin{array}{rcl}SA & = & 2\pi r^{2}+ 2\pi rh \\& = & 2 \times 3. 14\times 4^{2} +2\times 3. 14 \times 4\times 9\\& = & 6.28\times 16 + 226.08\\& = & 100.48 + 226.08\\& = & 326.56 \text{ in}^{2}\\\end{array}[/tex]
3. Excluded area
Excluded area = 2A(base) = 100.48 in²
4. Total area
[tex]A = 946 + 326.56 - 100.48 \approx \boxed{\textbf{1172 in}^{2}}[/tex]
Solve log x = 4. Please show all the work!
Answer:
x = 10000
Step-by-step explanation:
Using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Given
log x = 4 ( noting that log x has base 10 ), then
x = [tex]10^{4}[/tex] = 10000
Help pls !! A survey asked students wether they have any siblings and pets
Answer:
The correct answer option is B. 60%.
Step-by-step explanation:
We are given the results of a survey which asked the students whether they have any siblings and pets.
We are to determine the likelihood that student has a pet, given that he or she does not have a sibling.
Assuming A to be the event showing that a student does not have a sibling and B to be the event that a students has a pet.
Then P(B|A) is:
[tex]P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}[/tex]
Substituting the given values, P(A)=0.25 and P(A∩B)=0.15:
[tex]P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6[/tex]
So the percentage will be:
[tex]0.6\times 100 = [/tex] 60%
What is linear equation?
What is quadratic equation?
Final answer:
A linear equation represents a straight line and is written in the form y = mx + b. A quadratic equation represents a parabolic curve and is written in the form y = ax² + bx + c.
Explanation:
A linear equation is an equation that represents a straight line when graphed. It is typically written in the form y = mx + b, where m is the slope of the line and b is the y-intercept. The slope describes the rate of change between the independent and dependent variables, while the y-intercept is the point where the graph crosses the y-axis.
On the other hand, a quadratic equation is an equation that represents a parabolic curve when graphed. It is typically written in the form y = ax² + bx + c, where a, b, and c are constants. The graph of a quadratic equation is symmetric around a vertical line called the axis of symmetry, and it has either a maximum point or a minimum point.
PLEASE I NEED HELP AGAIN ATTACHMENT BELOW
Answer:
A.) 1/81
Step-by-step explanation:
This is your equation:
f(x) = 9^x
They want you to solve for x = -2, so substitute -2 in for x.
f(-2) = 9^-2
When you solve this, you get, 1/81.
So, the answer is A.)
I hope this helps! :)
what is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27
Answer with explanation:
[tex]\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}[/tex]
→y²+5y+6
=y²+3 y+2 y+6
=y×(y+3)+2×(y+3)
=(y+2)(y+3)
→y² -3 y-10
=y² -5 y+2 y -10
=y×(y-5)+2×(y-5)
=(y+2)(y-5)
Answer:
B. 3(y-5)/2 on edge
Step-by-step explanation:
help me: solve the simultaneous equation y-2x= -8 and x²- 3x - y = 2
Answer:
(2,-4) And (3,-2)
Step-by-step explanation:
Here we have to solve one linear equation and a quadratic equation.
First we find the value of y in terms of x from linear equation and then substitute this value in our quadratic equation to solve it for x , Let us see how :
we have y-2x=8
y=2x-8
Now we substitute this in [tex]x^2-3x-y=2[/tex]
Hence we have
[tex]x^2-3x-(2x-8)=2\\x^2-3x-2x+8=2\\x^2-5x+8=2\\x^2-5x+8-2=0\\x^2-5x+6=0\\x^2-2x-3x+6=0\\x(x-2)-3(x-6)=0\\(x-2)(x-3)=0\\[/tex]
Thus we have
either (x-2)= 0 or (x-3)=0
or x=2 or x=3
Now let us find the value of y by substituting them in y=2x-8 one by one.
y=2(2)-8= 4-8=-4
y+2((3)-8=6-8=-2
Hence our coordinates are
(2,-4) and (3,-2)
Answer:
(2, - 4), (3, - 2)
Step-by-step explanation:
Given the 2 equations
y - 2x = - 8 → (1)
x² - 3x - y = 2 → (2)
Rearrange (1) expressing y in terms of x
y = 2x - 8 → (3)
Substitute y = 2x - 8 in (2)
x² - 3x - 2x + 8 = 2
x² - 5x + 6 = 0 ← in standard form
(x - 2)(x - 3) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 3 = 0 ⇒ x = 3
Substitute these values into (3) for corresponding values of y
x = 2 : y = (2 × 2) - 8 = 4 - 8 = - 4 ⇒ (2, - 4)
x = 3 : y = (2 × 3) - 8 = 6 - 8 = - 2 ⇒ (3, - 2)
The quotient of two numbers is negative. What must be true about the two numbers?
If the quotient of two numbers is negative, it means that the result of dividing one number by the other is negative.
This situation can only occur if the two numbers have opposite signs. In other words, one number must be positive, and the other must be negative.
When we divide a positive number by a negative number or a negative number by a positive number, the resulting quotient will always be negative. So, to satisfy the given condition, the two numbers must have opposite signs—one positive and one negative.
Therefore, If the quotient of two numbers is negative, it means that the result of dividing one number by the other is negative.
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Final answer:
For the quotient of two numbers to be negative, one of the numbers must be positive and the other must be negative. This principle follows the general rules for multiplication and division involving signed numbers.
Explanation:
For a quotient of two numbers to be negative, one number must be positive and the other negative. This rule aligns with the multiplication and division rules for signs, whereby the product or quotient of two numbers with opposite signs results in a negative outcome.
Essentially, this can be understood by considering examples of multiplication, such as (-3) x 2 = -6 and 4 x (-4) = -16, which similarly apply to division. The same principle holds when dividing two numbers; if their signs are opposite, the result is negative.
This mathematical rule is fundamental and applies universally across mathematics, ensuring consistency in the calculation and understanding of operations involving signed numbers.
Which is the value of this expression when a=5 and k=-2
Answer:
Option C is correct.
Step-by-step explanation:
We are given the expression:
[tex](\frac{3^2a^{-2}}{3a^{-1}})^k[/tex]
The value of a =5 and k = -2
Putting the values and solving
[tex]=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}[/tex]
Option C is correct.
How do I solve for x ?
Answer:
x=30
Step-by-step explanation:
The two angles form a straight line
4x+2x = 180
6x= 180
Divide each side by 6
6x/6 = 180/6
x = 30
Answer:
X=30
Step-by-step explanation:
the degree of a straight line is 180
Add 2x and 4x together = 6x
Then divide 6x = 180 by 6 to get the x value.
The answer is 30
Two bikers leave the same shopping center at the same time traveling in
opposite directions. If the first biker travels 2 mph faster than the second,
how fast is each riding if after 3 hours they are 78 miles apart?
The faster biker travels
mph
The slower biker travels
mph
Answer:
fast bike speed = 41/3= 17mph
slower bike speed = 37/3 =12.33 mph
Final answer:
The slower biker's speed is 12 mph and the faster biker's speed is 14 mph, determined by setting up an equation with their combined distances equating to 78 miles after 3 hours.
Explanation:
To resolve the puzzle of the two bikers departing from the same location and traveling in opposite directions, we can apply concepts of rate, time, and distance. We are given that the two bikers are 78 miles apart after 3 hours and that one biker is traveling at a speed that is 2 mph faster than the other.
Let's denote the speed of the slower biker as $x$ mph. Consequently, the speed of the faster biker would be $x + 2$ mph. Considering that they have been traveling for 3 hours, the slower biker would have covered 3$x$ miles and the faster biker 3($x + 2$) miles. The sum of these distances is the total distance between the bikers after 3 hours, which is 78 miles.
Mathematically, we can represent the situation as:
3$x$ + 3($x + 2$) = 78
Simplifying the equation:
3$x$ + 3$x$ + 6 = 78
6$x$ + 6 = 78
6$x$ = 72
$x$ = 12
Thus, the slower biker's speed is 12 mph and the faster biker's speed is 12 mph + 2 mph = 14 mph.
Answer: The faster biker travels at 14 mph and the slower biker travels at 12 mph
Given 4 coordinate points A(2,0), B(4,0), C(5,-2), D(1, -2), click in the figure until the image that is rotated by 180° about
the origin O appears.
The origin O appears rotated by 180° about ’( -2,0), (-4,0), (-5,2) , ’(-1,2).
What is coordinate geometry?Coordinate geometry (or analytic geometry) is described as the examination of geometry and the use of coordinate factors. using coordinate geometry.
Coordinate using the horizontal and vertical distances from the two reference axes. generally represented by way of (x,y) the x-price and y-cost.
Coordinate geometry is used to control and regulate air visitors. The coordinates of the flight are used to describe the plane's modern location. despite the fact that a plane actions a tiny distance (up, down, forward, or backward), the machine updates the coordinates of flight for each small change in its role.
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Use the function f(x) = 15 - x to answer the question.
Evaluate. (f · f)(2)
A) 0
B) 2
C) 4
D) 13
Answer:
B
Step-by-step explanation:
To evaluate (f ○ f)(2) substitute x = 2 into f(x) and evaluate. Then substitute this value into f(x)
f(2) = 15 - 2 = 13, then
f(13) = 15 - 13 = 2
Hence (f ○ f)(2) = 2
which of the following is the complex conjugate of the complex number below? 4+51i
a. -4-51i
b. 4+51i
c. 4-51i
d. -4+51i
if you could give a dumbed down explanation as well that would be great
The conjugate of the complex number a+bi is a-bi
you just reverse the sign of the imaginary part of the number; so it is 4 -51i
The complex conjugate of the complex number is Option C. 4-51i
How do you simplify a complex conjugate?To simplify this fraction we multiply the numerator and the denominator by the complex conjugate of the denominator. When we change the sign of the imaginary part, we have the complex conjugate. Another way to think of this is to return all the i with -i. As we can see here, the complex conjugate of 3 - 4i is 3 + 4i.
How do you conjugate complex?You find the complex conjugate simply by reversing the sign of the imaginary part of the complex number. To find the complex conjugate of 4+7i we change the sign of the imaginary part. Thus the complex conjugate of 4+7i is 4 - 7i.
Complex conjugate is when "Each of two complex numbers having their real parts equal and their imaginary parts of equal magnitude but opposite sign."
What is the complex conjugate of z?The notation for the complex conjugate of z is either ˉz or z∗. The complex conjugate has the exact real part as z and the same imaginary part but with the opposite sign.
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When 30% of a number is added to the number, the result is 130.
Answer:
100
Step-by-step explanation:
100% of a number + 30% of a number is 130% of a number.
This means 130 = 1.3x.
Now we simplify:
130=1.3x
/1.3 /1.3
100=x
x=100
Therefore, the number is 100.
The unknown number is 100.
Given that, 30% of a number is added to the number, the result is 130.
What is a percentage?The term "percentage" was adapted from the Latin word "per centum", which means "by the hundred". Percentages are fractions with 100 as the denominator. In other words, it is the relation between part and whole where the value of the whole is always taken as 100.
Let the unknown number be x.
30% of x+x=130
⇒0.3x+x=130
⇒1.3x=130
⇒x=100
Therefore, the unknown number is 100.
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TO BILL CUSTOMERS FOR WATER USAGE ONE CITY CONVERTS THE NUMBER OF GALLONS USED INTO UNITS THIS RELATIONSHIP IS REPRESENTED BY THE EQUATION G=748 U WHERE G IS THE TOTAL NUMBER OF GALLONS OF WATER USED AND U IS THE NUMBER OF UNITS. DETERMINE WHICH STATEMENT IS TRUE ABOUT RELATIONSHIP SELECT TWO
G IS A DEPENDENT VARIABLE
U IS A DEPENDENT VARIABLE
G IS THE INDEPENDENT VARIABLE
U IS THE INDEPENDENT VARIABLE
THE TWO VARIABLES CANNOT BE LABELED AS INDEPENDENT OR DEPENDENT WITHOUT A TABLE OF VALUES.
THE TWO VARIABLES CANNOT BE LABELED AS INDEPENDENT OR DEPENDENT SINCE ANY VALUE CAN BE SELECTED FOR EITHER
Answer:
1. G IS A DEPENDENT VARIABLE
2.U IS THE INDEPENDENT VARIABLE
Step-by-step explanation:
G is a dependent variable because its values will rely on the values of U multiplied by 748. A dependent variable in most cases is isolated on one side of an equation ( mostly the left-hand side) and it value is affected by the values selected on the other side of the equation.
U is an independent variable because it stands on its own such that it does not rely on the behavior of another variable to determine its value/characteristic.Characteristic here i mean , U is freely selected without considering the behavior of other variable, thus it does not face any restrictions as compared to G.
The graph shown here is the graph of which of the following rational functions?
Answer:
there is no graph
Step-by-step explanation:
What is answer to the equation 81x=x^2 ?
For this case we have the following equation:
[tex]81x = x ^ 2[/tex]
Rewriting we have:
[tex]x ^ 2-81x = 0[/tex]
We take common factor "x" from both terms:
[tex]x (x-81) = 0[/tex]
It is observed that equality is fulfilled when x = 0 and when x = 81
So, the roots are:
[tex]x_ {1} = 0\\x_ {2} = 81[/tex]
Answer:
[tex]x_ {1} = 0\\x_ {2} = 81[/tex]
Simplify. x-2/x^2+4x-12
a. 1/x+6; where x= -6
b. 1/x+6; where x= -6, 3
c. 1/x+2; where x= -2
d. x+2
[tex]\bf \cfrac{x-2}{x^2+4x-12}\implies \cfrac{\begin{matrix} x-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }{(x+6)~~\begin{matrix} (x-2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies \cfrac{1}{x+6}\qquad \{x|x\in \mathbb{R};x\ne 2,x\ne -6\}[/tex]