Latex-free gloves can be purchased in a box of 100 for $44.95 or a box of 50 for $23.50. Which one would be the better deal

The unit rate for a bagel at Fresh side is $0.09 cheaper than the unit rate at

Value mart for bagels.

A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.

Given, Fresh side grocery sells 7 bagels for $4.41.

∴ The cost of one bagel at Fresh side is $(4.41/7) = $0.63.

Value mart sells 5 bagels for $3.60.

∴ The cost of one bagel at Value mart is

= $(3.60/5).

= $0.72

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The answer 108 degrees.

Answer: [tex]108^{\circ}[/tex]

Step-by-step explanation:

The sum of all the angles in a regular polygon with sides n , is given by :-

[tex]S_n=180^{\circ}(n-2)[/tex]

Now, the sum of all the angles in a regular pentagon with 5 sides will be :-

[tex]S_5=180^{\circ}(5-2)=180^{\circ}(3)=540^{\circ}[/tex]

We know that all the interior angles of a regular polygon are equal .

Therefore, the measure of each interior angle in a pentagon is given by :-

[tex]x=\dfrac{540^{\circ}}{5}=108^{\circ}[/tex]

Hence, the measure of each interior angle in a pentagon=[tex]108^{\circ}[/tex]

The standard deviation decreases and the sampling distribution becomes more normal as the sample size increases in x bar distribution.

The variability of the x bar distribution changes as the sample size increases. As the sample size increases, the standard deviation of the sampling distribution of the means will decrease, approaching the standard deviation of X. The sampling distribution of the mean becomes more normal as the sample size grows, showing less variability.

the answer would be 6 i did my calculations on paper then misplaced it but checked answer and it said 6

Final answer:

A variable is a name assigned to a quantity that can take on various values, and is used by mathematicians, economists, and statisticians in different contexts to represent data or elements of an equation.

Explanation:

A variable is the name given to a quantity that may assume a range of values. Mathematicians and economists often use variables in equations to represent different aspects of a problem or scenario. For example, in the equation of a line, commonly expressed as y = mx + b, the variables are 'x' and 'y'. Here, 'x' typically represents values on the horizontal axis, and 'y' represents values on the vertical axis, while 'b' is the y-intercept, and 'm' is the slope of the line. To understand how an equation with variables functions, we can look at a numerical example.

In statistics, variables can also refer to characteristics or measurements that can be determined for each member of a population. These variables can be numerical or categorical. A numerical variable, such as 'X' representing the number of points earned by a math student, allows for mathematical calculations like averaging. A categorical variable, like 'Y' indicating a person's political party affiliation, places individuals into categories and doesn't lend itself to mathematical operations like averaging.

Answer:

Option 1 - Division Property of Equality

Step-by-step explanation:

Given : If  [tex]4x=20[/tex], then x=5.

To find : Which property justifies this statement?

Solution :

The equation is  [tex]4x=20[/tex]

To make variable separate we have to remove 4 which is in multiple of variable x.

So, We divide both side by 4,

Applying division property of equality,

We can divide both sides of an equation by the same number and preserve equality.

[tex]\frac{4x}{4}=\frac{20}{4}[/tex]

[tex]x=5[/tex]

Therefore, The property justifies the statement is 'Division Property of Equality'.

So, Option 1 is correct.

Answer:

a = 0.75

b= 0.4375

d= 0.6

e=0.175

f= 2.55

Step-by-step explanation:

By simple division method, the following answers can be calculated:

a.

=[tex]\frac{3}{4}[/tex]

=0.75

b.

= [tex]\frac{7}{16}[/tex]

=0.4375

d.

= [tex]\frac{3}{5}[/tex]

=0.6

e.

= [tex]\frac{7}{40}[/tex]

=0.175

f.

=[tex]\frac{51}{20}[/tex]

=2.55

Thus, the answer are :

a = 0.75

b= 0.4375

d= 0.6

e=0.175

f= 2.55

Answer:

A.0.75 B.0.4375 C. 14.4 D. 0.6 E. 0.175 F. 2.55

Step-by-step explanation:

Answer:

B 3 times

C. 4 times

Step-by-step explanation:

For Tristan to  jog between 2 and 3 miles, the number of times he would have to jog the route that is 7/10 mile must be such that the product of the number of times and 7/10 miles gives a number between 2 and 3.

Considering the options given

A. 2 * 7/10 = 1.4 miles (this is not within the range)

B. 3 * 7/10 = 2.1 miles (this is within the range)

C. 4 * 7/10 = 2.8 miles (this is within the range)

D. 5 * 7/10 = 3.5 miles (this is not within the range)

Answer:

[tex](f-g)(x) = -x^{3} - 3\cdot x + 2[/tex]

Step-by-step explanation:

The new function is:

[tex](f-g) (x) = -3\cdot x + 2 -x^{3}[/tex]

[tex](f-g)(x) = -x^{3} - 3\cdot x + 2[/tex]

Answer:  [tex]\tan \theta=\dfrac{1}{\sqrt3}.[/tex]

Step-by-step explanation:  Given that

[tex]\sin\theta=-\dfrac{1}{2}[/tex] and [tex]\theta[/tex] lies in Quadrant III.

We are to find the value of [tex]\tan \theta.[/tex]

We will be using the following trigonometric identities:

[tex](i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.[/tex]

We have

[tex]\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.[/tex]

Since [tex]\theta[/tex] lies in Quadrant III, so tangent will be positive.

Thus,

[tex]\tan \theta=\dfrac{1}{\sqrt3}.[/tex]

The missing x-values are 9, 24, 12, and 16, ensuring proportions remain equal in each ratio set.

To find the missing values that make the sets of ratios equivalent, we can use proportions.

1. Tiles 2 : 3 = 6 : x

  Cross multiplying, we get: 2x = 18

  So, x = 9

2. 4 : 7 = x : 42

  Cross multiplying, we get: 7x = 168

  So, x = 24

3. 2x : 48 = 3 : 12

  Cross multiplying, we get: 12x = 144

  So, x = 12

4. 12 : 15 = x : 20

  Cross multiplying, we get: 15x = 240

  So, x = 16

Therefore, the x-values that make the sets of ratios equivalent are:

1. x = 9

2. x = 24

3. x = 12

4. x = 16

To find the difference in weight between the Newfoundland and the Springer Spaniel, subtract the weight of the Springer Spaniel from the weight of the Newfoundland.

To find the difference in weight between the Newfoundland and the Springer Spaniel, we need to subtract the weight of the Springer Spaniel from the weight of the Newfoundland. The Newfoundland weighs 52 kilograms 656 grams more than a Cocker Spaniel. So, we first need to find the weight of a Cocker Spaniel by subtracting 7,590 grams from the weight of the Springer Spaniel. We then add this weight to the weight of the Newfoundland to get the final answer. Let's calculate:

We can now substitute the given values into these equations and solve.

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The simplification of the given expression is 0.6i.

Complex numbers are those numbers that contain the imaginary and the real part.

A Complex value z is written in a rectangular form as z = x+iy where (x, y) is the rectangular coordinates.

where r is the modulus of the complex number and θ is the argument

r =√x²+y² and θ = tan⁻¹y/x

Usually the simplification involves proceeding with the pending operations in the expression.

We need to simpify the 0.4i - i

= i(0.4-1)

= 0.6i

Therefore, the simplification of the given expression is 0.6i.

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A function [tex]f[/tex] from a set [tex]A[/tex] to a set [tex]B[/tex] is a relation that assigns to each element [tex]x[/tex] in the set [tex]A[/tex] exactly one element [tex]y[/tex] in the set [tex]B[/tex]. The set [tex]A[/tex] is the domain (also called the set of inputs) of the function and the set [tex]B[/tex] contains the range (also called the set of outputs).

[tex]We \ denote \ the \ \mathbf{exponential \ function} \ f \ with \ base \ a \ as: \\ \\ f(x)=a^x \\ \\ where \ a>0, \ a\neq 1, \ and \ x \ is \ any \ real \ number[/tex].

We have the following equation:

[tex]y=100(1-12)^t[/tex]

That can be written as:

[tex]y=100(-11)^t[/tex]

Recall that the definition of exponential functions establishes that:

[tex]We \ denote \ the \ \mathbf{exponential \ function} \ f \ with \ base \ a \ as: \\ \\ f(x)=a^x \\ \\ where \ a>0, \ a\neq 1, \ and \ x \ is \ any \ real \ number[/tex].

That is:

[tex]a \ \mathbf{must} \ be \ greater \ than \ 1[/tex]

In this problem, [tex]a=-11[/tex], therefore this is not an exponential function.

The function:

[tex]y=0.1(1.25)^t[/tex]

is an exponential function because is a function of the form [tex]f(t)=ka^t \\ \\ where \ a>0 \ and \ k \ constant[/tex]

So [tex]k=0.1 \ and \ a=1.25[/tex]. Since [tex]a \ is \ greater \ than \ 1[/tex] and being raised to the power of [tex]t[/tex], the function increases. This means that [tex]y[/tex] increases as [tex]t[/tex] increases as illustrated in Figure 1. This represents a growth.

The function:

[tex]y=((1-0.03)12)^{2t}[/tex] can be written as:

[tex]y=11.64^{2t}[/tex]

and is an exponential function because is a function of the form [tex]f(t)=a^{bt} \\ \\ where \ a>0 \ and \ b \ constant[/tex]

So [tex]a=11.64 \ and \ b=2[/tex]. Since [tex]a \ is \ greater \ than \ 1[/tex] and being raised to the power of [tex]2t[/tex], the function increases. As in the previous exercise, this means that [tex]y[/tex] increases as [tex]t[/tex] increases as illustrated in Figure 2. This represents a growth.

The function:

[tex]y=426(0.98)^t[/tex]

is an exponential function because is a function of the form [tex]f(t)=ka^t \\ \\ where \ a>0 \ and \ k \ constant[/tex]

So [tex]k=426 \ and \ a=0.98[/tex]. Since [tex]a \ is \ less \ than \ 1[/tex] and being raised to the power of [tex]t[/tex], the function decreases. Here this means that [tex]y[/tex] decreases as [tex]t[/tex] increases as illustrated in Figure 3. This represents a decay.

The function:

[tex]y=2050(12)^t[/tex]

is an exponential function because is a function of the form [tex]f(t)=ka^t \\ \\ where \ a>0 \ and \ k \ constant[/tex]

So [tex]k=2050 \ and \ a=12[/tex]. Since [tex]a \ is \ greater \ than \ 1[/tex] and being raised to the power of [tex]t[/tex], the function increases. So in this function [tex]y[/tex] also increases as [tex]t[/tex] increases as illustrated in Figure 4. This represents a growth.

Answer:

1. isn't an exponential function

2. growths

3. growths

4. decay

5. growths

Step-by-step explanation:

The exponential functions has the form: y = k1*k2^(k3*t), where k1, k2 and k3 are a constants, and k2>0. Graph of exponential functions always decrease or always increase. To know if a function growths or decay just evaluate the function in 2 points, for example t = 0 and t = 1, and compare their results.

1.

y = 100*(1−12)^x = 100*(−11)^x

Since (-11) is negative, then y is not an exponential function

2.

y(0) = 0.1*(1.25)^(0) = 0.1

y(1) = 0.1*(1.25)^(1) = 0.125

y(1) > y(0) -> growths

3.

y(0) =((1−0.03)12)^2(0) = 1

y(0) =((1−0.03)12)^2(1) = 135.4896

y(1) > y(0) -> growths

4.

y(0) = 426(0.98)^(0) = 426

y(1) = 426(0.98)^(1) = 417.48

y(1) < y(0) -> decay

5.

y(0) = 2050(12)^(0) = 2050

y(1) = 2050(12)^(1) = 24600

y(1) > y(0) -> growths