Answer:
0.0202
Step-by-step explanation:
I got this because there is 1000 millimeters in a meter. if you divide 20.2 by 1000, you get 0.0202.
Have a good day :3
Two bicyclists are 7/8 of the way through a mile long tunnel when a train approaches the closer end at 40 mph. The riders take off at the same speed in opposite directions and each escapes the tunnel as the train passes them. How fast did they ride?
The speed at which each bicyclist rides is 320 times the distance covered by each bicyclist.
Explanation:To solve this problem, we can consider the distance traveled by the train and by each bicyclist. Let's assume the distance covered by each bicyclist is x miles. The train covers the remaining 1 - 7/8 = 1/8 mile. We can set up an equation to represent the time it takes for the train and the bicyclists to travel their respective distances:
Time taken by train = distance traveled by train / speed of train = (1/8) mile / 40 mph = 1/320 hour
Time taken by each bicyclist = distance traveled by bicyclist / speed of bicyclist = x miles / v mph, where v represents the speed of the bicyclists
Since the train passes each bicyclist when they are 7/8 of the way through the tunnel, the time it takes for each bicyclist to travel their distance is equal to the time it takes for the train to travel its distance:
(x / v) = 1/320
To solve for v, we can rearrange the equation:
v = x / (1/320)
v = 320x mph
The speed at which each bicyclist rides is 320 times the distance covered by each bicyclist.
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Final answer:
To escape a train traveling at 40 mph through a tunnel, two bicyclists traveling in opposite directions must ride at a speed of exactly 35 mph to escape the tunnel safely. We derive this by setting up two inequalities based on the distances each cyclist must cover and then finding the minimum speed at which these conditions are satisfied.
Explanation:
We are discussing a classic algebra problem that utilizes rate, time, and distance calculations. Two bicyclists are 7/8 of the way through a mile-long tunnel when a train traveling at 40 mph approaches from behind. Each cyclist pedals at the same speed but in opposite directions to escape the tunnel as the train passes by them.
To solve the problem, we need to determine how far each bicyclist has to travel to escape the tunnel. One bicyclist has 1/8 mile to exit, while the other bicyclist has 7/8 mile. Since they travel at the same speed and need to escape before the train reaches them, we can set up a ratio based on distances and speeds. We know the train covers the mile in (1/40) hours since speed is distance over time.
The bicyclist closer to the exit (1/8 mile away) must bike this distance faster than the train covers the entire mile to avoid collision, and similarly for the second bicyclist (7/8 miles away). Let's assume their biking speed is 's'. Then, their times to escape are (1/8)/s and (7/8)/s respectively. These times must be less or equal to the time it takes for the train to travel the mile, which is 1/40 hours.
Setting up the first inequality: (1/8)/s ≤ 1/40
Which simplifies to: s ≥ 5 mph
And the second inequality: (7/8)/s ≤ 1/40
This second inequality simplifies to: s ≥ 35 mph
Since both conditions must be satisfied and s cannot be greater than 35 mph for both to be true, the speed at which both bicyclists must ride to escape is exactly 35 mph.
In a field there are cows, birds, and spiders. Spiders have 4 eyes and 8 legs each. In the field there are 20 eyes and 30 legs. All three animals are present, and there is an odd number of each animal. How many spiders, cows, and birds are present?
Answer:
1 spider, 3 cows, 5 birds.
Step-by-step explanation:
Cows (C): 4 legs, 2 eyes.
Birds (B): 2 legs, 2 eyes.
Spiders (S): 8 legs, 4 eyes.
The number of legs and eyes are given, respectively by:
[tex]30 = 4C+2B+8S\\20 = 2C+2B+4S[/tex]
Multiplying the second equation by -2 and adding it to the first one gives us the number of birds:
[tex]30 -40= 4C-4C+2B-4B+8S-8S\\-10 = -2B\\B=5[/tex]
Rewriting the original equations with B =5:
[tex]30 = 4C+2*5+8S\\20 = 2C+2*5+4S\\20 = 4C+8S\\10 = 2C+4S\\C=5-2S[/tex]
Since the number of cows cannot be negative, and both C and S must be odd numbers, the only possible value of S is 1:
[tex]C=5-2S\\S=1\\C=3[/tex]
There are 3 cows, 5 birds, and 1 spider in the field.
To solve this problem, we need to establish equations based on the given information
1. Define Variables
Let c be the number of cows,
b be the number of birds,
and s be the number of spiders
2. Create Equations
The total number of eyes is given to be 20, and knowing that spiders have 4 eyes, birds have 2 eyes, and cows have 2 eyes, we get:
2c + 2b + 4s = 20
Simplifying this, we get:
c + b + 2s = 10 (i)
The total number of legs is given to be 30, with cows having 4 legs, birds having 2 legs, and spiders having 8 legs, we get:
4c + 2b + 8s = 30
Simplifying this, we get:
2c + b + 4s = 15 (ii)
3. Solve Simultaneous Equations
We can subtract equation (i) from (ii):
(2c + b + 4s) - (c + b + 2s) = 15 - 10
c + 2s = 5 (iii)
Substituting (iii) into (i):
(5 - 2s) + b + 2s = 10
5 + b = 10
b = 5;
We know from (iii) that:
c + 2s = 5
Let’s check for odd values for s:
If s = 1, then c = 5 - 2(1) = 3 (valid since cows = 3)
Hence, the solution is:
c = 3, b = 5, s = 1
Checking:
Total eyes = 2(3) + 2(5) + 4(1) = 6 + 10 + 4 = 20 (correct)
Total legs = 4(3) + 2(5) + 8(1) = 12 + 10 + 8 = 30 (correct)
There are 3 cows, 5 birds, and 1 spider in the field.
anju plots points showing equivalent ratios on the coordinate plane below
The missing value in the table is 15.
Solution:
Ratio of x to y coordinate:
[tex]$\frac{x}{y}= \frac{1}{3}[/tex]
[tex]$\frac{x}{y}= \frac{2}{6}= \frac{1}{3}[/tex]
[tex]$\frac{x}{y}= \frac{8}{24}= \frac{1}{3}[/tex]
So, the ratios are equivalent ratios.
To find the missing value in the table:
Multiply the x-coordinate by 3, we get the y-coordinate.
x-coordinate = 5
y-coordinate = x-coordinate × 3
= 5 × 3
= 15
Hence the missing value in the table is 15.
Answer:
15
Step-by-step explanation:
1 multiplied by 5 equals 5. Do the same with the y-value. 3 multiplied by 5 is 15!
You are given the probability that an event will happen. Find the probability that the event will not happen.
1. P(E) = 0.7
2. P(E) = 0.36
3. P(E) = 1/4
4. P(E) = 2/3
Answer:
1) 0.3
2) 0.64
3) 0.75
4) 0.33
Step-by-step explanation:
We are given the following probabilities. We have to probability of that event not happening.
That is we have to find the complement of the event,
Complement of event:
The complement of event E is represented as E'.[tex]P(E') = 1 - P(E)[/tex]1. P(E) = 0.7
[tex]P(E') = 1 - P(E) = 1 - 0.7 =0.3[/tex]
2. P(E) = 0.36
[tex]P(E') = 1 - P(E) = 1 - 0.36 = 0.64[/tex]
3. P(E) = 1/4
[tex]P(E') = 1 = P(E) = 1 -\dfrac{1}{4} = \dfrac{3}{4} = 0.75[/tex]
4. P(E) = 2/3
[tex]P(E') = 1 = P(E) = 1 -\dfrac{2}{3} = \dfrac{1}{3} = 0.33[/tex]
A frequent flyer was interested in the relationship between dollars spent on flying and the distance flown. She sampled 20 frequent flyers of a certain airline. She collected the number of miles flown in the previous year and the total amount of money the flyer spent. A regression line of distance flown on money spent was fit to the data, and the intercept and slope were calculated to be a = 24,000 and b = 10.
A person who spent $ 2000 is predicted to have flown:
a) 34000 miles. b) 54000 miles. c) 44000 miles. d) 24000 miles.
Answer:
c) 44000 miles
Step-by-step explanation:
The regression line has the following format:
[tex]y = bx + a[/tex]
In which b is the slope(how much each mile costs) and a is the fixed number of miles flown.
In this problem, we have that:
[tex]a = 24000, b = 10[/tex]. So
[tex]y = 10x + 24000[/tex]
A person who spent $ 2000 is predicted to have flown:
This is y when x = 2000.
[tex]y = 10(2000) + 24000[/tex]
[tex]y = 44000[/tex]
So the correct answer is:
c) 44000 miles
To find the predicted distance flown by someone who spent $2000, you use the given intercept (a) and slope (b) in the straight line equation Y = a + bX. When $2000 is substituted for X in the equation, your solution is 44,000 miles.
Explanation:In this problem, you are asked to determine the distance a person is predicted to have flown, given that the person spent $2000. Based on our regression line information, we know that the intercept (a) is 24,000 and the slope (b) is 10. Therefore, we can use the equation of the straight line Y = a + bX, where X represents the amount of money spent, and Y is the distance traveled. If we substitute $2000 for X in our equation, we find that Y = 24000 + 10 * 2000 = 44,000 miles. Therefore, the correct answer is option c) 44000 miles.
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The relationship between the number of games won by a minor league baseball team and the average attendance at their home games is analyzed. A regression to predict the average attendance from the number of games won has an r = 0.73. Interpret this statistic.
Answer: There is a strong positive correlation between number of games won by a minor league baseball team and the average attendance at their home games is analyzed.
Step-by-step explanation:
The Pearson's coefficient 'r' gives the correlation between the predicted values and the observed values .
It tells the direction and the strength of the relation.When r is negative it means there is a negative relationship between the variables .When r is positive it means there is a positive relationship between the variables .When |r|=1 , strong correlation , When r=0 , there is no correlation.If 0.70<|r|<1 , there is a strong correlation.If 0.50<|r|<0.70 , there is a moderate correlation.If 0.30<|r|<0.50 , there is a low correlation.Given : A regression to predict the average attendance from the number of games won has an r = 0.73.
Since r=0.73 is positive and 0.70 <0.73 <1 , it means there is a strong positive correlation between number of games won by a minor league baseball team and the average attendance at their home games is analyzed.
In the 2012 National Football League (NFL) season, the first three weeks’ games were played with replacement referees because of a labor dispute between the NFL and its regular referees. Many fans and players were concerned with the quality of the replacement referees’ performance. We could examine whether data might reveal any differences between the three weeks’ games played with replacement referees and the next three weeks’ games that were played with regular referees. For example, did games generally take less or more time to play with replacement referees than with regular referees? The pair of dotplots below display data about the duration of games (in minutes), separated by the type of referees officiating the game.
Answer: for replacement total games = 47 more than 3.5 hours = 8 required proportion = 8/47 = 0.170212 for regular.
Step-by-step explanation:
1. What proportion of the 47 games officiated by replacement referees lasted for at least 3.5 hours (210 minutes)? What proportion of the 42 games officiated by regular referees lasted for this long?
2. What proportion of the 47 games officiated by replacement referees lasted for less than 3 hours (180 minutes)? What proportion of the 42 games officiated by regular referees lasted for this long?
3. Would you say that either type of referee tended to have longer games than the other on average, and if so, which type of referee tended to have longer games and by about how much on average?
i. Regular Referees have longer game times with games about 185 minutes on average.
ii. The game lengths for both referees seem to be the same.
iii. Replacement Referees have longer game times with games about 195 minutes on average.
iv. It is too hard to tell from the graph which type of referee has longer games.
4. Would you say that either type of referee tended to have more variability in game durations? If so, which type of referee tended to have more variability?
i. The two types of referees had the same amount of variability in the game lengths.
ii. There is no way to tell which group of referees had more variability in the game lengths.
iii. The regular referees tended to have more variability in the game lengths.
iv. The replacement referees tended to have more variability in the game lengths.
For replacement total games = 47 more than 3.5 hours = 8 required proportion = 8/47 = 0.170212 for regular.
Please help
The expression 16t2 approximates a skydiver’s distance, in feet, when in free- a skydiver at 15,000 ft needs to speed up 240 mph (352 ft/s) to join a formation, the expression 15,000 − 352t represents the skydiver’s height above ground after t seconds. Classify each polynomial by its degree and number of terms.
16t2
240
15,000 – 352t
t
Answer:
Step-by-step explanation:
The degree of a polynomial is the sum of the exponents of all of its variables. Where there is only one variable, the degree would be the highest power to which that variable is raised. The terms are the individual components that make up the polynomial. Therefore,
16t2 is a second degree because the variable, t is raised to 2 and the term is 1
240 is zero degree and 1 term.
15,000 – 352t is first degree and 2 terms.
If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in. beyond its natural length?
Answer:
0.375 feet-lb
Step-by-step explanation:
We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.
We can represent our given information as:
[tex]6=\int\limits^2_0 {F(x)} \, dx[/tex]
We will use Hooke's Law to solve our given problem.
[tex]F(x)=kx[/tex]
Substituting this value in our integral, we will get:
[tex]6=\int\limits^2_0 {kx} \, dx[/tex]
Using power rule, we will get:
[tex]6=\left[ \frac{kx^2}{2} \right ]^2_0[/tex]
[tex]6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}[/tex]
[tex]6=\frac{4k}{2}-0\\\\k=3[/tex]
We know that 6 inches is equal to 0.5 feet.
Work needed to stretch it beyond 6 inches beyond its natural length would be [tex]\int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx[/tex]
Using power rule, we will get:
[tex]\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0[/tex]
[tex]\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375[/tex]
Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.
A sociologist studying freshmen carried out a survey, asking, among other questions, how often students went out per week, how many hours they studied per day, and how many hours they slept at night.
The tables provide the answers on the time slept and the time spent studying by whether or not students went out.
Go out Hours/day studied Hours slept less than 6 Hours slept 6 or more Total Stay in dorm Hours/day studied Hours slept less than 6 Hours slept 6 or more Total Less than 2 3 9 12 Less than 2 40 120 160 2 or more 14 14 28 2 or more 20 20 40 Total 17 23 40 Total 60 140 200
When we examine the data, we find that students who studied more slept less, both among those who go out and among those who stay in the dorm.
When we combine both groups of students, we find that those who studied more also slept more.
This is an example of:
a. Simpson's Paradox.
b. Andersen's Paradox.
c. the Probability Paradox.
d. the Gaussian Paradox.
Answer:
This is called Simpson's Paradox.
Therefore the correct option is A.) Simpson's Paradox.
Step-by-step explanation:
i) This is called Simpson's Paradox.
ii) If there are trends that tend to appear in several different groups of data which apparently either disappear or tend to reverse when these data groups are combined.
This is an example of Simpson's Paradox, where a trend appears in different groups of data but disappears or reverses when the groups are combined.
Explanation:This is an example of Simpson's Paradox. Simpson's Paradox occurs when a trend appears in different groups of data but disappears or reverses when the groups are combined. In this case, although students who studied more slept less in both groups (those who went out and those who stayed in the dorm), when the groups are combined, those who studied more also slept more.
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Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allowed to overlap). Show that the number of possible choices of your team and the opponent’s team equals Pn−1 i=1 i 3 .
Answer:
The number of possible choices of my team and the opponents team is
[tex]\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}[/tex]
Step-by-step explanation:
selecting the first team from n people we have [tex]\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n[/tex] possibility and choosing second team from the rest of n-1 people we have [tex]\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1[/tex]
As { A, B} = {B , A}
Therefore, the total possibility is [tex]\frac{n(n-1)}{2}[/tex]
Since our choices are allowed to overlap, the second team is [tex]\frac{n(n-1)}{2}[/tex]
Possibility of choosing both teams will be
[tex]\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}[/tex]
We now have the formula
1³ + 2³ + ........... + n³ =[tex][\frac{n(n+1)}{2}] ^{2}[/tex]
1³ + 2³ + ............ + (n-1)³ = [tex][x^{2} \frac{n(n-1)}{2}] ^{2}[/tex]
=[tex]\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}[/tex]
Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velocity of the ball after 3 seconds. SOLUTION Through experiments carried out four centuries ago, Galileo discovered that the distance fallen by any freely falling body is proportional to the square of the time it has been falling. (This model for free fall neglects air resistance.) If the distance fallen after t seconds is denoted by s(t) and measured in meters, then Galileo's law is expressed by the equation s(t) = 4.9t2. The difficulty in finding the velocity after 3 s is that we are dealing with a single instant of time (t = 3), so no time interval is involved. However, we can approximate the desired quantity by computing the average velocity over the brief time interval of a tenth of a second from t = 3 to t = 3.1: average velocity = change in position time elapsed = s(3.1) − s(3) 0.1 = 4.9 2 − 4.9 2 0.1 = m/s. The table shows the results of similar calculations of the average velocity over successively smaller time periods. It appears that as we shorten the time period, the average velocity is becoming closer to m/s (rounded to one decimal place). The instantaneous velocity when t = 3 is defined to be the limiting value of these average velocities over shorter and shorter time periods that start at t = 3. Thus the (instantaneous) velocity after 3 s is the following. (Round your answer to one decimal place.) v = m/s
The velocity of the ball after 3 seconds will be 29.43 meters per second.
What is Algebra?The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground.
Then the velocity of the ball after 3 seconds will be given as,
We know that the first equation of motion.
v = u - gt
Where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time in seconds. Then we have
v = 0 - 9.81 x 3
v = -29.43 m/s
The velocity of the ball after 3 seconds will be 29.43 meters per second.
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Final answer:
The velocity of the ball after 3 seconds can be found using Galileo's law of free fall. By calculating the average velocity over a brief time interval, we can approximate the instantenous velocity. The velocity of the ball after 3 seconds is therefore m/s.
Explanation:
The velocity of the ball after 3 seconds can be found using Galileo's law of free fall. According to the given information, the distance fallen after t seconds is given by the equation s(t) = 4.9t², where s(t) is the distance fallen in meters and t is the time in seconds. To find the velocity, we can approximate it by computing the average velocity over a brief time interval. We can calculate the average velocity from t = 3 to t = 3.1 by finding the change in position divided by the time elapsed. Plugging the values into the equation, we get:
Average velocity = (s(3.1) - s(3)) / 0.1 = (4.9(3.1)² - 4.9(3)²) / 0.1 = m/s
Therefore, the velocity of the ball after 3 seconds is m/s, rounded to one decimal place.
Bob can go to work by one of four modes of transportation: 1.) bicycle, 2.) car, 3.) bus and 4.) train. If he takes his bicycle, Bob has a 25% chance of getting to work on time. Because of heavy traffic, there is a 43% chance of being late if he takes his car. If he goes by bus, which has special reserve lanes to help keep schedule, but can be over crowded forcing him to wait for the next bus, he has a 15% chance of being late. The train runs on a very specific schedule, so there is only 5% probability of being late if he decides to take the train. Suppose that Bob is late and his boss see's Bob coming in late. His boss tries to estimate the probability Bob took his car in. Not knowing Bob's travel habbits, what does the boss estimate Bob's probability of taking the car given that he was late.
Answer:
the probability is 0.311 (31.1%)
Step-by-step explanation:
defining the event L= being late to work :Then knowing that each mode of transportation is equally likely (since we do not know its travel habits) :
P(L)= probability of taking the bicycle * probability of being late if he takes the bicycle + probability of taking the car* probability of being late if he takes the car + probability of taking the bus* probability of being late if he takes the bus +probability of taking the train* probability of being late if he takes the train = 1/4 * 0.75 + 1/4 * 0.43 + 1/4 * 0.15 + 1/4 * 0.05 = 0.345
then we can use the theorem of Bayes for conditional probability. Thus defining the event C= Bob takes the car , we have
P(C/L)= P(C∩L)/P(L) = 1/4 * 0.43 /0.345 = 0.311 (31.1%)
where
P(C∩L)= probability of taking the car and being late
P(C/L)= probability that Bob had taken the car given that he is late
If Bob is late without considering the transportation mode, the total probability is 63%. Using Bayes' theorem, we find the probability that Bob was late because he took the car is approximately 17%.
Explanation:Firstly, it's essential to ascertain the total chances of Bob being late disregarding the mode of transport. And that is the sum of his possibilities of being late for each mode, which is 43% for the car, 15% for the bus, and 5% for the train: 43% + 15% + 5% = 63%. Thus, if Bob is late, there's a 63% chance that he took either car, bus, or train. To calculate the probability that Bob took the car given that he was late, we employ Bayes' Theorem.
The formula for Bayes' theorem is P(A|B) = P(B|A)P(A) / P(B). In this instance, event A is Bob travelling by car, event B is Bob being late. We want to estimate P(A|B), the chance of A happening given B has occurred. Hence we plug in values: P(A|B) = (0.43)(0.25) / (0.63) ≈ 0.17 or 17%. Thus, the boss would estimate that there's a 17% chance that Bob took his car if he observes Bob coming late.
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Suppose your statistics instructor gave six examinations during the semester. You received the following grades (percent correct): 79, 64, 84, 82,92, and 77. Instead of averaging the six scores, the instructor indicated he would randomly select two grades and report that grade to the student records office.
a. How many different samples of two test grades are possible?
b. List all possible samples of size two and compute the mean of each.
c. Compute the mean of the sample means and compare it to the population mean.
Answer:
a. 15
b.
Sr.no Samples Sample mean
1 (79,64) 71.5
2 (79,84) 81.5
3 (79,82) 80.5
4 (79,92) 85.5
5 (79,77) 78
6 (64,84) 74
7 (64,82) 73
8 (64,92) 78
9 (64,77) 70.5
10 (84,82) 83
11 (84,92) 88
12 (84,77) 80.5
13 (82,92) 87
14 (82,77) 79.5
15 (92,77) 84.5
c.
mean of sample mean=population mean=79.67
Step-by-step explanation:
a.
The different samples of two test grade are nCr, where n=6 and r=2.
nCr=6C2=6!/2!(6-2)!=6*5*4!/2!4!=30/2=15.
Thus, there are 15 different samples of two test grade.
b.
All possible samples are listed below:
Sr.no Samples
1 (79,64)
2 (79,84)
3 (79,82)
4 (79,92)
5 (79,77)
6 (64,84)
7 (64,82)
8 (64,92)
9 (64,77)
10 (84,82)
11 (84,92)
12 (84,77)
13 (82,92)
14 (82,77)
15 (92,77)
The sample means for each sample can be calculated as
Sr.no Samples Sample mean
1 (79,64) (79+64)/2=71.5
2 (79,84) (79+84)/2=81.5
3 (79,82) (79+82)/2=80.5
4 (79,92) (79+92)/2=85.5
5 (79,77) (79+77)/2=78
6 (64,84) (64+84)/2=74
7 (64,82) (64+82)/2=73
8 (64,92) (64+92)/2=78
9 (64,77) (64+77)/2=70.5
10 (84,82) (84+82)/2=83
11 (84,92) (84+92)/2=88
12 (84,77) (84+77)/2=80.5
13 (82,92) (82+92)/2=87
14 (82,77) (82+77)/2=79.5
15 (92,77) (92+77)/2=84.5
c.
The sample means of sample mean μxbar will calculated by taking average of sample means
μxbar=(71.5+ 81.5+ 80.5+ 85.5+ 78+ 74+ 73+ 78+ 70.5+ 83+ 88+ 80.5+ 87+ 79.5+ 84.5)/15
μxbar=1195/15=79.67
Population mean=μ=(79+64+84+82+92+77)/6
μ=478/6=79.67
Sample means of sample mean μxbar=Population mean μ.
The standard deviation of pulse rates of adult males is more than 11 bpm. For the random sample of 153 adult males the pulse rate have a standard deviation of 11 .3 bpm. Find the value of the test statistic.
Answer: 160.4040
Step-by-step explanation:
Here , the claim is "The standard deviation of pulse rates of adult males is more than 11 bpm." , i.e. [tex]\sigma>11[/tex]
We use Chi-square test statistic for the test statistic to test the standard deviations :
[tex]\chi^2=\dfrac{(n-1)s^2}{\sigma^2}[/tex] , where s= sample standard deviation , [tex]\sigma[/tex] = population standard deviations and n = sample size.
As per given , n=153 , s= 11.3
Then, Required test statistic will be :
[tex]\chi^2=\dfrac{(153-1)(11.3)^2}{11^2}=\dfrac{152\times127.69}{121}\approx160.4040[/tex]
Hence, the value of the test statistic. = 160.4040
A trough has a trapezoidal cross section with a height of 5 m and horizontal sides of width 5/2 m and 5 m. Assume the length of the trough is 10 m. Complete parts? (a) and? (b) below.
a) How much work is required to pump the water out of the trough? (to the level of the top of the? trough) when it is? full? Use 1000 kg/m3 for the density of water and9.8 m/s2 for the acceleration due to gravity. Draw a? y-axis in the vertical direction? (parallel to? gravity) and use the midpoint of the bottom of one edge of the trough as the location of the origin. For 0?y?5?, find the? cross-sectional area? A(y) in terms of y.
b) Set Up the integral that gives the work required to pump the water out of the tank.
Answer:
Step-by-step explanation:
Considering Volume of water inside this = Base area x HeightBase is trapezoid = 0.5 (2.5 + 5) X 5 = 18.75 m2Height = 10 mVolume = 10 * 18.75 = 187.5 m3Total mass of water = density X volume = 1000 kg/m3 x 187.5 m3
= 187500kgWork done to pump out the water = change in potential energy of system of waterWork = mg(H2 - H1)where H2 = initial position of centre of mass from ground
where H1 = final position of centre of mass from ground
here H2 = 2.78 m (from bottom) H1 = 0Work = 187500kg X 9.8 X (2.78 - 0) = 5.11 x 106 JThe detailed analysis of the (b) part is as shown in the attachmentThe work required to pump the water out of the trough is [tex]5.11\times 10^6[/tex] J and this can be determine by using the formula of work done.
Given :
A trough has a trapezoidal cross section with a height of 5 m and horizontal sides of width 5/2 m and 5 m. Assume the length of the trough is 10 m.a) The work required to pump the water out of the trough is given by:
[tex]\rm W=mg(H_2-H_1)[/tex] --- (1)
where m is the total mass of the water [tex]\rm H_1[/tex] is the initial position and [tex]\rm H_2[/tex] is the final position of the center of mass.
So. the mass of the water is given below:
[tex]=1000\times 187.5[/tex]
= 187500 Kg
Now, the value of the initial position of the center of mass is zero and the value of the final position of the center of mass is 2.78 m.
Now, substitute the known terms in the expression (1).
[tex]\rm W = 187500\times 9.8\times (2.78-0)[/tex]
[tex]\rm W = 5.11\times 10^{6}\;J[/tex]
b) The width of the cylinder is given by:
[tex]\rm w-5=\dfrac{5-2.5}{0-5}(x-0)[/tex]
Simplify the above expression.
w = -0.5x + 5
Now, the volume of the cylinder is given by:
[tex]\rm dv = 10wdx[/tex]
Substitute the value of w in the above expression.
[tex]\rm dv = 10(-0.5x+5)dx[/tex]
dv = (50-5x) dx
Now, the value of the force is given by:
[tex]\rm dF = 9800dv[/tex]
Substitute the value of dv in the above expression.
dF = 9800(50 - 5x) dx
Now, the expression of work is given by:
dW = x dF
Substitute the value of force in the above expression.
dW = x(9800(50 - 5x)) dx
Now, integrate the above expression.
[tex]\rm W = 9800\int^5_0(50x-5x^2)dx[/tex]
[tex]\rm W = 9800 \times \left(25x^2-\dfrac{5x^3}{3}\right)^5_0[/tex]
[tex]\rm W= 9800\left(625-\dfrac{625}{3} \right)[/tex]
W = 4083333.34 J
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If Mike does his mathematics homework today, the probability that he will do it tomorrow is 0.8. The probability that he will do his homework today is 7.0. What are the odds that he will do it both today and tomorrow?a. 4:1b. 8:7c. 3:2d. 14:11
Answer:
d. 14:11
Step-by-step explanation:
There is a 7 in 10 chance that Mike does his homework today and a 8 in 10 chance he will do it tomorrow, the probability that he will do it both today and tomorrow is:
[tex]P = \frac{7}{10}* \frac{8}{10}\\P=\frac{56}{100}=0.56[/tex]
The odds are the probability that an event occurs over the probability that it does not occur:
[tex]Odds = \frac{0.56}{1-0.56}=\frac{56}{44}=\frac{14}{11}[/tex]
The odds that he will do it both today and tomorrow are 14:11.
The odds that he will do it both today and tomorrow is 14:11.
What are the odds that he will do it both today and tomorrow?
Probability that he would do the assignement today and tomorrow = probability he would do the assignment today x probability he would do the assignment tomorrow
0.7 x 0.8 = 0.56
Odds he would do the assignment today and tomorrow = 0.56/ (1 - 0.56) = 0.56 / 0.44
= 14 : 11
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What expression is equivalent to 3•3•3•3
Answer: 3 to the 4 power
Step-by-step explanation:
Answer:
3^4
because it is 3 times it self 4 times
What is a real life word problem for the equation
y=2x
Answer:
y = 2x
Step-by-step explanation:
Claire is hungry. She buys 2 donuts each costing x $. How much should she pay?
Since one donut costs x $ 2 donuts cost 2x $.
Therefore, total amount Claire should pay, call it y = 2x.
Hence, we have y = 2x.
Final answer:
A real-life word problem for the equation y=2x could be renting a bike at a rate of $2 per hour, in which the cost (y) is proportional to the rental time (x). This scenario shows a linear relationship with the total cost increasing directly with the rental time.
Explanation:
A real-life word problem for the equation y=2x could involve a situation where the cost y (in dollars) to hire a bike is proportional to the number of hours x you rent it for. If it costs $2 per hour to rent a bike, then the total cost is represented by the equation y=2x. For example, renting the bike for 3 hours would cost y=2(3)=6 dollars.
Applying this equation, it follows that as the time of rental increases, the cost increases at a constant rate. This represents a linear relationship between time and cost.
Example Calculation:
Let x represent the time in hours you rent a bike.
The total cost y is twice the rental time (since it's $2 per hour).
To find the cost of renting a bike for 5 hours, substitute x=5 into the equation: y=2(5).
The total cost would be y=$10.
The equation y=2x is used here to model a simple proportional relationship where one variable increases directly as the other does. It does not represent a quadratic, hyperbolic, or any other non-linear relationship.
Sulfur compounds cause "off-odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compound that the human nose can detect. The odor threshold for dimethyl sulfide (DMS) in trained wine tasters is about 25 micrograms per liter of wine (μg/l). The untrained noses of consumers may be less sensitive, how ever. Here are the DMS odor thresholds for 10 untrained f students:
30 30 42 35 22 33 31 29 19 23
(a) Assume that the standard deviation of the odor threshold for untrained noses is known to be σ = 7 μg/l. Briefly discuss the other two "simple conditions, " using a stemplot to verify that the distribution is roughly symmetric with no outliers.
(b) Give a 95% confidence interval for the mean DMS odor threshold among all students.
Answer:
a) If we construct a stemplot for the data we have this:
Stem Leaf
1 | 9
2 | 2 3 9
3 | 0 0 1 3 5
4 | 2
Notation: 1|9 means 19
b) [tex]29.4-2.26\frac{6.75}{\sqrt{10}}=24.58[/tex]
[tex]29.4-2.26\frac{6.75}{\sqrt{10}}=34.22[/tex]
So on this case the 95% confidence interval would be given by (24.58;34.22)
Step-by-step explanation:
For this case we have the following data:
30 30 42 35 22 33 31 29 19 23
Part a
If we construct a stemplot for the data we have this:
Stem Leaf
1 | 9
2 | 2 3 9
3 | 0 0 1 3 5
4 | 2
Notation: 1|9 means 19
As we can see the distribution is a little assymetrical to the right since we have not to much values on the right tail. But we can approximate roughly the distribution symmetric and with no outliers.
Part b
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
In order to calculate the mean and the sample deviation we can use the following formulas:
[tex]\bar X= \sum_{i=1}^n \frac{x_i}{n}[/tex] (2)
[tex]s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}[/tex] (3)
The mean calculated for this case is [tex]\bar X=29.4[/tex]
The sample deviation calculated [tex]s=6.75[/tex]
In order to calculate the critical value [tex]t_{\alpha/2}[/tex] we need to find first the degrees of freedom, given by:
[tex]df=n-1=10-1=9[/tex]
Since the Confidence is 0.95 or 95%, the value of [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that [tex]t_{\alpha/2}=2.26[/tex]
Now we have everything in order to replace into formula (1):
[tex]29.4-2.26\frac{6.75}{\sqrt{10}}=24.58[/tex]
[tex]29.4-2.26\frac{6.75}{\sqrt{10}}=34.22[/tex]
So on this case the 95% confidence interval would be given by (24.58;34.22)
Consider this scatter plot.
(a) How would you characterize the relationship between the hours spent on homework and the test
scores? Explain.
(b) Paul uses the function y = 8x + 42 to model the situation. What score does the model predict for 3 h
of homework?
Answer:
a) For this case we can see on the y axis the test scores and on the x axis the hours of homework. And as we can see we have a proportional relationship, because when the hours of homework increase the test scores increases too. If we fit a lineal model between y and x we will see an slope positive and a correlation coefficient positive based on the data observed.
b) [tex] y = 8x +42[/tex]
And we want to predict the test score for x = 3hr of homework we just need to replace the value of x=3 in the linear model and we got:
[tex] y = 8*3 +42= 24+42=66[/tex]
And that would be our predicted value for 3 h of homework
Step-by-step explanation:
For this case we consider the scatter plot attached to solve the problem.
Part a
For this case we can see on the y axis the test scores and on the x axis the hours of homework. And as we can see we have a proportional relationship, because when the hours of homework increase the test scores increases too. If we fit a lineal model between y and x we will see an slope positive and a correlation coefficient positive based on the data observed.
Part b
Assuming the following linear model for the situation:
[tex] y = 8x +42[/tex]
And we want to predict the test score for x = 3hr of homework we just need to replace the value of x=3 in the linear model and we got:
[tex] y = 8*3 +42= 24+42=66[/tex]
And that would be our predicted value for 3 h of homework
Suppose you invest $2,500 in a fund earning 10% simple interest annually. After two years you have the option of moving your money to an account that pays compound interest at an annual effective rate of 7%. Should you move your money to the compound interest account (a) if you wish to liquidate in five more years?(b) if you are confident your money will stay on deposit for a total of ten years?
Answer:
account after 2 years of simple interest at 10%: (2,500 * 0.10 * 2) + 2500 = 3,000
Note that simple interest only pays interest on the original balance, NOT on the accrued (paid) interest....
a) 5 more years at 10% simple: (2500 * 0.10 * 5) + 3,000 = $4,250
or
5 years compound interest on $3k: 3,000(1.07^5) = $4,207.66
b) TOTAL of 10 years
simple interest: (2500 * 0.10 * 10) + 2500 = 5,000
compound interest: only 8 years remain of the total 10 year time horizon
3000(1.07^8) = $5,154.56
Step-by-step explanation:
After the initial 2 years with simple interest, moving the money to the account with compound interest yields a higher amount whether you liquidate in the next 5 years or keep it for a total of 10 more years.
Explanation:First, let's calculate the amount you will have after 2 years with a simple interest of 10%. Using the formula for simple interest, I = PRT, where P is the principal amount ($2,500), R is the rate of interest (10% as a decimal, 0.10), and T is the time in years (2): I = $2,500 * 0.10 * 2 = $500. Therefore, your total amount after 2 years would be $2,500 + $500 = $3,000.
To decide whether you should move your money, we need to calculate the final amount after the next 5 years and 10 years using compound interest formula, A = P(1 + r/n)^(nt), where P is the principal amount ($3,000), r is the annual interest rate (7% as a decimal, 0.07), n is the number of times interest applied per time period (1, for annual compounding), and t is the time the money is invested for.
(a) For 5 more years: A = $3,000 * (1 + 0.07/1)^(1*5) = $4,209.24.
(b) For a total of 10 more years: A = $3,000 * (1 + 0.07/1)^(1*10) = $5,922.58.
Therefore, If you intend to liquidate in five more years or you're confident your money will stay on deposit for a total of ten more years after the initial 2 years of simple interest, moving the money to the compound interest account is a good move as it results in a higher amount in both scenarios.
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The United Kingdom is about 900km long from north to south. By how many orders of magnitude (i.e. how many times) would you have to scale down a map of the United Kingdom so that it can fit on a sheet of paper 20cm long
Answer:
[tex]45*10^{6}[/tex] orders of magnitude.
Step-by-step explanation:
We know that 900 km is equivalent to 20 cm, because we need to fit the United Kingdom length on a sheet of paper. So:
1 cm in a paper will be 45 km in the real ground.Therefore, if we divide 45 km by 0.00001 km (1 cm) we will have [tex]45*10^{6}[/tex] times to scale down.
I hope it helps you!
ATM personal identification number (PIN) codes typically consist of four-digit sequences of numbers. Find the probability that if you forget your PIN, then you can guess the correct sequence (a) at random and (b) when you recall the first two digits.
Answer:
(a) 0.0001 or 0.01%
(b) 0.01 or 1%
Step-by-step explanation:
Since there are 10 possible numeric digits (from 0 to 9), and there is only one correct digit, there is a 1 in 10 change of getting each digit right.
The probability that if you forget your PIN, then you can guess the correct sequence
(a) at random:
[tex]P=(\frac{1}{10})^4=0.0001=0.01\%[/tex]
(b) when you recall the first two digits.
[tex]P=(\frac{1}{10})^2=0.01=1\%[/tex]
The probability of guessing a four-digit PIN code correctly is 1/10,000 if guessed randomly and 1/100 if the first two digits are recalled correctly.
Explanation:To find the probability of guessing a four-digit PIN code correctly, we need to consider the number of possible combinations and the number of favorable outcomes. There are 10 possible choices for each digit (0-9), so there are 10^4 = 10,000 possible four-digit PIN codes.
(a) If you forget your PIN and guess it randomly, there is only one correct sequence out of the 10,000 possibilities. Therefore, the probability of guessing the correct sequence is 1/10,000.
(b) If you recall the first two digits correctly, there are still 10 choices for each of the remaining two digits. So, the probability of guessing the correct sequence in this case is 1/10^2 = 1/100.
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Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Imagine you and your friends are making hot dogs. A complete hot dog consists of a wiener and a bun. At the store, you buy four packages of eight wieners and three bags of 10 buns. 1. How many total hot dogs can you make? ________________________________________ 2. Which ingredient limited the number of hot dogs you could make? ____________________ 3. Which ingredient will you have leftovers of? ______________________________________
Answer:
A. 8 complete hotdogs were made.
B. The wiener.
C. The bun.
Step-by-step explanation:
1 complete hotdog = 1 wiener + 1 bun
You have, 3*10 bun and 8 wiener
= 30 bun and 8 wiener
A. Since, we have 30 bun and 8 wiener and for 1 complete hotdog = 1 wiener + 1 bun
Therefore, 8 hotdogs = 8 wiener + 8 buns
= 8 complete hotdogs are made
B.
Since 8 complete hotdogs are made, 8 wiener and 8 buns are used.
Therefore, the limiting ingredient is the wiener because it is the smallest number of ingredient and none of it was left after making the 8 hotdogs.
C. Since 8 complete hotdogs are made, 8 buns were used
So, the leftover buns = (30 - 8) buns
= 22 buns
The buns is the leftover ingredient
At the store, you buy four packages of eight wieners and three bags of 10 buns, you can make 8 hotdogs.
There are 8 hotdogs you can make then the limited ingredient is wieners.
The buns are the leftover ingredient.
Given that,You and your friends are making hot dogs.
A complete hot dog consists of a wiener and a bun.
At the store, you buy four packages of eight wieners and three bags of 10 buns.
According to the question,Total number of buns = 30
Total number of wieners = 8
At the store, you buy four packages of eight wieners and three bags of 10 buns.
For every hot dog, 1 wiener one 1 buns are required. the calculation for the given question is given as follows;
1. The total number of hot dogs can you make is,
To make 1 hot dog 1 wiener and 1 bun
Then,
for 8 hot dogs, 8 wieners and 8 buns are required.
Therefore, you can make 8 hotdogs.
2. There are 8 hotdogs you can make then the limited ingredient is wieners.
3. After making 8 hot dogs only 8 buns are used,
Then,
Left buns = Total number of buns - used buns
Left buns = 30-8 = 22
The buns are the leftover ingredient.
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For two independent events, A and B, P(A)equals . 3 andP(B)equals . 2 . a. Find P(Aintersect B). b. Find P(A|B). c. Find P(Aunion B). a. P(Aintersect B)equalsnothing b.P(A|B)equals nothing c. P(Aunion B)equalsnothing. Any expert yet
Answer:
a) 0.06
b) 0.3
c) 0.44
Step-by-step explanation:
We are given the following in the question:
A and B are two independent events.
P(A) = 0.3
P(B) = 0.2
a) P(A intersect B)
[tex]P(A\cap B) = P(A)\times P(B) = 0.3\times 0.2 = 0.06[/tex]
b) P(A|B)
[tex]P(A|B) = \dfrac{P(A\cap B)}{P(B)} = \dfrac{0.06}{0.2} = 0.3[/tex]
c) P(A union B)
[tex]P(A\cup B) = P(A) + P(B) - P(A\cap B)\\P(A\cup B) = 0.3 + 0.2 - 0.06 = 0.44[/tex]
How many ways are there to pick a group of n people from 100 people (each of a different height) and then pick a second group of m other people such that all people in the first group are taller than the people in the second group
The total number of ways to choose the two groups, depending on the relationship between n and m, is:
M < N: C(100, n).
M ≥ N: Σ (C(100, k) * C(100 - k, m - k)) for k = n to 1.
Case 1: m < n (n tallest chosen first):
Choose the n tallest people from the 100. There are C(100, n) ways to do this.
The remaining 100 - n people are all shorter than the chosen n. Since m < n, we can simply choose all the remaining people (100 - n).
The total number of ways in this case is C(100, n).
Case 2: m ≥ n (not all n tallest need to be chosen):
This case requires considering all possible combinations of how many tall people to choose (from n down to 1).
For each value of k (n, n - 1, ..., 1), choose k tallest people from the 100. There are C(100, k) ways to do this.
The remaining 100 - k people are all shorter than the chosen k. Choose the remaining m - k people from this group. There are C(100 - k, m - k) ways to do this.
Sum the results for each value of k: Σ (C(100, k) * C(100 - k, m - k)) for k = n to 1.
Therefore, the total number of ways to choose the two groups, depending on the relationship between n and m, is:
M < N: C(100, n)
M ≥ N: Σ (C(100, k) * C(100 - k, m - k)) for k = n to 1
Complete question:
How many ways are there to pick a group of n people from 100 people, and then pick a second group of m people from the remaining 100 − n people, so that all the people you chose from the first group are taller than the people from the second group (assume that everyone in the group of 100 people has a different height.)
Note: it is implied in this question that 1 ≤ n ≤ 100 and 0 ≤ m ≤ 100 − n.
Delta Airlines quotes a flight time of 2 hours, 5 minutes for its flights from Cincinnati toTampa. Suppose we believe that actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes.
a. Show the graph of the probability density function for flight time.b. What is the probability that the flight will be no more than 5 minutes late?c. What is the probability that the flight will be more than 10 minutes late?d. What is the expected flight time?
Answer:
a) Figure attached
b) [tex] P(X<130 min)= F(130) = \frac{130-120}{20}=0.5[/tex]
c) [tex] P(X>135) =1-P(X<135) = 1- F(135) = 1- \frac{135-120}{20}= 0.25[/tex]
d) [tex] E(X) =\frac{a+b}{2}= \frac{120+140}{2}= 130min[/tex]
Step-by-step explanation:
2 hr = 120 min
2hr 20 min = 120+20 = 140 min
Let X the random variable that represent "flight time". And we know that the distribution of X is given by:
[tex]X\sim Uniform(120 ,140)[/tex]
For this case the density function for A is given by:
[tex] f(X) = \frac{1}{b-a}= \frac{1}{20} , 120\leq X \leq 140 [/tex]
And [tex] f(X)= 0[/tex] for other case
Part a
For this case we can see the figure attached. We see that the probability density function is defined between 120 and 140 minutes.
Part b
The arrival time is 2hr 5 min = 125 min. So then 5 minutes leate means 130 min
For this case we want to find this probability:
[tex] P(X<130 min)[/tex]
And we can use the cumulative distribution function for X given by:
[tex] F(X) = \frac{x-120}{140-120} = \frac{x-120}{20} , 120\leq X \leq 140 [/tex]
And if we use this formula we got:
[tex] P(X<130 min)= F(130) = \frac{130-120}{20}=0.5[/tex]
Part c
For this case more than 10 minutes late means 125 +10 = 135 min or more, so we want this probability:
[tex] P(X>135)[/tex]
And using the complement rule we have:
[tex] P(X>135) =1-P(X<135) = 1- F(135) = 1- \frac{135-120}{20}= 0.25[/tex]
Part d
The expected value for the uniform distribution is given by:
[tex] E(X) =\frac{a+b}{2}= \frac{120+140}{2}= 130min[/tex]
A department store sells sport shirts in three sizes (small, medium, and large), three patterns (plaid, print, and stripe), and two sleeve lengths (long and short). The accompanying tables give the proportions of shirts sold in the various category combinationsShort-sleeved Pattern Size Pl Pr StS 0.04 0.02 0.05M 0.07 0.10 0.12L 0.03 0.07 0.08Long-sleeved Pattern Size Pl Pr StS 0.03 0.02 0.03M 0.06 0.07 0.07L 0.04 0.02 0.08(a) What is the probability that the next shirt sold is a medium, long-sleeved, print shirt?(b) What is the probability that the next shirt sold is a medium print shirt?(c) What is the probability that the next shirt sold is a short-sleeved shirt?What is the probability that the next shirt sold is a long-sleeved shirt?(d) What is the probability that the size of the next shirt sold is a medium?What is the probability that the pattern of the next shirt sold is a print?(e) Given that the shirt just sold was a short-sleeved plaid, what is the probability that its size was medium?(f) Given that the shirt just sold was a medium plaid, what is the probability that it was short-sleeved? What is the probability that it was long-sleeved?
Answer and Step-by-step explanation:
a) probability of selling a medium, long sleeved printed shirt, P(M ∩LS ∩PR) = 0.07, directly from the table of probabilities
b) probability that the next shirt sold is a medium printed shirt, (M ∩Pr) = P(M,Pr,LS) + P(M,Pr,SS) = 0.07+0.10 = 0.17
c) probability that the next shirt is a short sleeved shirt, P(SS) = sum of 9 probabilities in Short Sleeved shirt table = 0.58
probability that the next shirt is a long sleeved shirt, P(LS) = 1 - 0.58 = 0.42 or add up the total probabilities in the long sleeved shirt table, P(LS) = sum of 9 probabilities in the long sleeved shirt table = 0.42
d) probability that the next shirt is a medium, P(M) = P(M,SS) + P(M,LS) = (0.07+0.10+0.12) + (0.06+0.07+0.07) = 0.49
probability that the next shirt sold is a print, P(Pr) = P(Pr,SS) + P(Pr,LS) = (0.02+0.10+0.07) + (0.02+0.07+0.02) = 0.40
e) probability that the shirt sold is a medium given that the shirt just sold was a short-sleeved plaid, P(M|SS,PL) = (P(M,SS,PL))/P(SS,PL) = 0.07/(0.04+0.07+0.03) = 0.5
f) probability that the shirt sold is short sleeved given that the shirt just sold was a medium plaid, P(SS|M,PL) = (P(M,SS,PL))/P(M,PL) = 0.07/(0.07+0.06) = 0.53846 = 0.54
probability that the shirt sold is long sleeved given that the shirt just sold was a medium plaid, P(LS|M,PL) = (P(M,LS,PL))/P(M,PL) = 0.06/(0.07+0.06) = 0.462 = 0.46
QED!
The following probabilities are as follow;
The probability of a medium, long-sleeved, print shirt is 0.07.The probability of a medium print shirt is 0.17.The probability of a long-sleeved shirt is 0.42.The probability of a medium print shirt is 0.17The probability of a short-sleeved plaid medium is 0.07.The probability of a medium plaid short-sleeved is 0.07.What is probability?Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.
(a) The next shirt sold is a medium, long-sleeved, print shirt.
Probability = 0.07
(b) The probability that the next shirt sold is a medium print shirt.
Probability = 0.7 + 0.10 = 0.17
(c) The probability that the next shirt sold is a long-sleeved shirt.
Probability = 0.42
(d) The probability that the size of the next shirt sold is medium. The probability that the pattern of the next shirt sold is a print.
Probability = 0.07 + 0.10 = 0.17
(e)The shirt just sold was a short-sleeved plaid, the probability that its size was medium.
Probability = 0.07
(f) The shirt just sold was a medium plaid, The probability that it was short-sleeved.
Probability = 0.07
More about the probability link is given below.
https://brainly.com/question/795909
Find the general solution to y' + 19t1$ y = t19 Use the variable I=∫et17dt where it occurs in your answer, since this integral is not easily computable. Note that the arbitrary constant C would come from actually computing the integral I, so you do not need to write it.
Answer:
y=\frac{ -\frac{\sqrt[9]{18} Г (10/9, -\frac{19t^{18}}{18})}{19^{10/9} {e^{\frac{19t^{18}}{18}}}
Step-by-step explanation:
From exercise we have:
C=0
y'+19t^{17} y=t^{19}
We know that a linear differential equation is written in the standard form:
y' + a(t)y = f(t)
we get that: a(t)=19t^{17} and f(t)=t^{19}.
We know that the integrating factor is defined by the formula:
u(t)=e^{∫ a(t) dt}
⇒ u(t)=e^{∫ 19t^{17} dt} = e^{\frac{19t^{18}}{18}}
The general solution of the differential equation is in the form:
y=\frac{ ∫ u(t) f(t) dt +C}{u(t)}
y=\frac{ ∫ e^{\frac{19t^{18}}{18}} · t^{19} dt + 0}{e^{\frac{19t^{18}}{18}}}
y=\frac{ -\frac{\sqrt[9]{18} Г (10/9, -\frac{19t^{18}}{18})}{19^{10/9} {e^{\frac{19t^{18}}{18}}}