Kinsley's age is 7 years less than twice Jacobs age if kensley is 13 years old how old is Jacob

Answers

Answer 1

Answer:

Age of Jacob is 10 years.

Step-by-step explanation:

Let the age of Jacob = x years and age of Kinsley = y years

Then by first statement " Kinsley's age is 7 years less than twice of Jacob's age"

y = 2x - 7

By second statement " Kensley is 13 years old "

y = 3 years

By putting y = 13 years in the equation

13 = 2x - 7

2x = 13 + 7

2x = 20

x = [tex]\frac{20}{2}[/tex] = 10 years

Therefore, age of Jacob is 10 years.

Answer 2

Answer:

The Answer is B. 10

Hope This Helps!


Related Questions

Sam predicted that he would sell 15 mugs, but he actually sold 20 mugs, which expression would find the percent error? Use
the table below to help answer the question
Percent Error

Answers

Answer:

A

Step-by-step explanation:

The percentage error is 25%.

We have,

The percent error can be calculated using the following expression:

Percent Error = (|Predicted Value - Actual Value| / Actual Value) * 100%

In this case,

Sam predicted he would sell 15 mugs, but he actually sold 20 mugs.

Plugging these values into the expression, we get:

Percent Error = (|15 - 20| / 20) * 100%

Simplifying further:

Percent Error = (5 / 20) * 100%

Percent Error = (1/4) * 100%

Percent Error = 25%

Therefore,

The percent error is 25%.

Learn more about percentages here:

https://brainly.com/question/11403063

#SPJ2

What is the product of (5r+2)(3r-4)

Answers

Answer:

[tex]\large\boxed{(5r+2)(3r-4)=15r^2-14r-8}[/tex]

Step-by-step explanation:

[tex](5r+2)(3r-4)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(5r)(3r)+(5r)(-4)+(2)(3r)+(2)(-4)\\\\=15r^2-20r+6r-8\qquad\text{combine like terms}\\\\=15r^2+(-20r+6r)-8\\\\=15r^2-14r-8[/tex]

What is the equation for the hyperbola shown? PLEASE HELP

Answers

ANSWER

[tex]\frac{ {y}^{2} }{ 25} - \frac{ {x}^{2} }{ 64} = 1 [/tex]

EXPLANATION

The given hyperbola has a vertical transverse axis and its center is at the origin.

The standard equation of such a parabola is:

[tex] \frac{ {y}^{2} }{ {a}^{2} } - \frac{ {x}^{2} }{ {b}^{2} } = 1 [/tex]

Where 2a=10 is the length of the transverse axis and 2b=16 is the length of the conjugate axis.

This implies that

[tex]a = 5 \: \: and \: \: b = 8[/tex]

Hence the required equation of the hyperbola is:

[tex]\frac{ {y}^{2} }{ {5}^{2} } - \frac{ {x}^{2} }{ {8}^{2} } = 1 [/tex]

This simplifies to,

[tex]\frac{ {y}^{2} }{ 25} - \frac{ {x}^{2} }{ 64} = 1 [/tex]

Answer:

[tex]\frac{(y^2}{25}-\frac{x^2}{64}=1[/tex]

Step-by-step explanation:

We have been given an image of a hyperbola. We are asked to write an equation for our given hyperbola.

We can see that our given hyperbola is a vertical hyperbola as it opens upwards and downwards.

We know that equation of a vertical hyperbola is in form [tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1[/tex], where, [tex](h,k)[/tex] represents center of hyperbola.

'a' is vertex of hyperbola and 'b' is co-vertex.

We can see that center of parabola is at origin (0,0).

We can see that vertex of parabola is at point [tex](0,5)\text{ and }(0,-5)[/tex], so value of a is 5.

We can see that co-vertex of parabola is at point [tex](8,0)\text{ and }(-8,0)[/tex], so value of b is 8.

[tex]\frac{(y-0)^2}{5^2}-\frac{(x-0)^2}{8^2}=1[/tex]

Therefore, our required equation would be [tex]\frac{(y^2}{25}-\frac{x^2}{64}=1[/tex].

As a laboratory assistant, you measure chemicals using the metric system. For your current research, you need to measure out 45 grams of sodium chloride. The bottle you are using lists the amount in ounces. About how many ounces of sodium chloride will you need?

Answers

Answer: 1.587 ounces of sodium chloride

Step-by-step explanation:

We know that 1 ounce is equivalent to 28.35 gr.

So we use this as a conversion factor to find the equivalent amount of sodium chloride in ounces.

If we need 45 grams of sodium chloride then this equals to:

[tex]45\ g* \frac{1\ ounces}{28.35\ gr} = 1.587\ ounces[/tex]

Finally you need 1.587 ounces of sodium chloride

Answer:

1.587 ounces

Step-by-step explanation:

We need to measure out 45 grams of sodium chloride using the bottle mentioning units of measure in units.

We are to find the number of ounces of sodium chloride that we will need.

We know that:

1 ounce = 28.35 grams

So using the ratio method to find the number of ounces of Sodium Chloride needed.

[tex]\frac{1 ounce}{x} =\frac{28.35 g}{45 g}[/tex]

[tex]= \frac{45}{28.35} = [/tex] 1.587 ounces

Speed typist #1 can type 95 words each minute. Speed typist #2 can type 98 words each minute. Working together, how many minutes will it take them to type 2,895 words?

Answers

Answer:

It will take them 15 minutes.

Step-by-step explanation:

1. Since you are given the information that the two typists are typing a certain amount of words in the same time frame (ie. one minute), you can add the two values together to obtain the total number of words the typists would type together in one minute:

95 + 98 = 193 words

2. To calculate how many minutes it would take them to type 2,895 words, you would simply take this total number of words and divide it by the number of words they collectively type in one minute (found in 1.). Thus:

2895/193 = 15

Therefor, it will take them 15 minutes to type 2,895 words.

Final answer:

To type 2,895 words, they would need approximately 15 minutes.

Explanation:

To solve this problem, we must first find the combined typing speed of both typists when working together.

Speed typist #1 can type 95 words per minute, and speed typist #2 can type 98 words per minute.

Together, they can type 95 + 98 = 193 words per minute.

Next, we need to calculate how many minutes it will take for them to type 2,895 words at this combined rate.

So, we divide the total number of words by the words per minute:

2,895 / 193 = 15 minutes

Therefore, it will take both typists working together approximately 15 minutes to type 2,895 words.


What's the common difference of the sequence 0, 5, 10, 15, 20, . . . ?



A. d = –5
B. d = 3
C. d = –2
D. d = 5

Answers

Common difference of a sequence is difference between any two consecutive terms in the sequence.

So let's pick up any two consecutive terms,

0 and 5,

difference between 0 and 5 is 5-0 = 5

so common difference is 5

The answer is D d=5 because it increases by 5 every time

Find x in the following right triangle.

Helppppp

Answers

12 dm.

The key to solve this problem is using the Pythagoras theorem given by the formula c² = a² + b², where a, b, and c are the sides of the right triangle.

Solving with the values given in the image:

With a = x , b = 5 dm, and c = 13 dm

(13dm)² = (x)² + (5 dm)²

169 dm² = (x)² + 25 dm²

(x)² = 169 dm² - 25 dm²

(x)² = 144 dm²

x = √144 dm²

x = 12 dm

I have like no idea how to do any of this please help!

Answers

Tan(angle) = Opposite leg / Adjacent leg

Tan (Angle) = 50/30

Angle = arctan(50/30)

Angle = 59.0 degrees.

Find the length of the ladder using the Pythagorean theorem:

50^2 + 30^2 = X^2

2500 + 900 = x^2

x^2 = 3400

x = √3400

x = 58.3 inches.

Answer:

59.03 deg

58.31 in

Step-by-step explanation:

The wall and the floor form a right angle. The parts of the wall and the floor from the corner until they intersect the ladder are the legs of a right angle. The ladder is the hypotenuse of the right angle.

You can use trigonometry to find the measure of the angle.

For the angle where the ladder touches the floor, the leg along the wall is the opposite leg, and the leg along the floor is the adjacent leg.

Use the tangent ratio.

[tex] \tan A = \dfrac{opp}{adj} [/tex]

[tex] \tan A = \dfrac{50}{30} = \dfrac{5}{3} [/tex]

[tex] A = \tan^{-1} \dfrac{5}{3} [/tex]

[tex] A = 59.03^\circ [/tex]

To find the length of the ladder, which is the hypotenuse of the triangle, you can use trigonometry again or the Pythagorean Theorem.

I'll use the Pythagorean Theorem.

[tex] a^2 + b^2 = c^2 [/tex]

[tex] (50~in)^2 + (30~in)^2 = c^2 [/tex]

[tex] 2500~in^2 + 900~in^2 = c^2 [/tex]

[tex] c^2 = 3400~in^2 [/tex]

[tex] c = \sqrt{3400~in^2} [/tex]

[tex] c = 10\sqrt{34}~in [/tex]

[tex] c \approx 58.31~in [/tex]

what is measure of egf?​

Answers

Answer:

∠EGF = 65°

Step-by-step explanation:

Since EF = EG the triangle is isosceles and the base angles are equal, that is

∠EGF = ∠GEF

∠EGF = [tex]\frac{180-50}{2}[/tex] = [tex]\frac{130}{2}[/tex] = 65°

the answer to this question would have to be 65 degrees hope this answer helped!!

An unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds. What is the approximate average weight of one pallet of cargo?

Answers

Answer:

The approximate average weight of 1 pallet is 1131 pounds.

Step-by-step explanation:

Given is -  the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

So, total weight bore by 18 tires = [tex]18\times3300=59400[/tex] pounds

Now given that the fully loaded truck holds 26 pallets.

And the unloaded truck weighs = 30000 pounds

So, weight of the load = [tex]59400-30000=29400[/tex] pounds

This is the weight of 26 pallets.

So, weight of 1 pallet = [tex]29400/26=1130.76[/tex] pounds

Hence, the approximate average weight of 1 pallet is 1131 pounds.

The approximate average weight of one pallet of cargo is 1,130.76 pounds.

To find the approximate average weight of one pallet of cargo, we first need to determine the total weight of the fully loaded truck and trailer. We know that the unloaded truck and trailer weigh 30,000 pounds.

Each of the 18 tires bears approximately 3,300 pounds when the truck is fully loaded.

The weight borne by the tires includes the weight of the truck, trailer, cargo, and the weight that would be supported by the 18th tire if it were present.

 First, we calculate the total weight supported by the 18 tires:

[tex]\[ 18 \text{ tires} \times 3,300 \text{ pounds/tire} = 59,400 \text{ pounds} \][/tex]

 However, this total includes the weight of the truck and trailer without the cargo.

To find the weight of the cargo alone, we need to subtract the weight of the unloaded truck and trailer from the total weight supported by the tires:

[tex]\[ 59,400 \text{ pounds} - 30,000 \text{ pounds} = 29,400 \text{ pounds} \][/tex]

 This 29,400 pounds is the total weight of the cargo carried by the 18 tires.

Since there are 26 pallets of cargo, we divide the total cargo weight by the number of pallets to find the average weight per pallet:

[tex]\[ \frac{29,400 \text{ pounds}}{26 \text{ pallets}} = 1,130.76\\[/tex]

 Therefore, the approximate average weight of one pallet of cargo is  1,130.76 pounds.

On the coordinate plane below, quadrilaterals TRAP and HELP are similar to each other.

Which of the following options best describes the relationship of the areas of the quadrilaterals?

Quadrilateral TRAP has an area that is half the area of quadrilateral HELP.
Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.
Quadrilateral TRAP has an area that is twice the area of quadrilateral HELP.
Quadrilateral TRAP has an area that is four times the area of quadrilateral HELP.

Answers

Answer:Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.

Step-by-step explanation: Because you rearrange the squares and it is 1/4

Answer:

Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.

Step-by-step explanation:

Rewrite the parametric equation by eliminating the parameter x=4t+1 and y=t-3

Answers

Answer:

The equation is x = 4y + 13

Step-by-step explanation:

* Lets talk about the parametric equations

- Parametric equations are a set of equations that express a set

 of quantities as explicit functions of a number of independent

 variables

- Ex: x = at + b and y = ct + d are parametric equations

- We use them to find relation between the variables x and y

* Lets solve the problem

∵ x = 4t + 1 ⇒ (1)

∵ y = t - 3 ⇒ (2)

- The parameter is t to eliminate it find t in terms of x or y

- We will use equation (2) to find t in terms of y

∵ y = t - 3 ⇒ add 3 to both sides

∴ t = y + 3 ⇒ (3)

- Substitute the value of t in equation (3) in equation (1)

∵ x = 4t + 1

∵ t = y + 3

∴ x = 4(y + 3) + 1 ⇒ open the bracket

∴ x = 4y + 12 + 1 ⇒ add like term

∴ x = 4y + 13

* The equation is x = 4y + 13

To eliminate the parameter t from the parametric equations x=4t+1 and y=t-3, solve for t in one equation and substitute into the other. This results in a linear equation y=(1/4)x-13/4, revealing a linear relationship between x and y.

To rewrite the parametric equation by eliminating the parameter, we start with the given equations x=4t+1 and y=t-3. To eliminate the parameter t, we solve one of the equations for t and substitute into the other. From the first equation, we express t as t=(x-1)/4.

We can now substitute this expression for t into the second equation to get y=((x-1)/4)-3. With further simplification, we find the relationship between x and y to be y=(1/4)x-(1+12)/4, which simplifies to y=(1/4)x-13/4. This is a linear equation in x and y showing that the set of points defined by the parametric equations lies on a line.

Click through and select the graph of y=-5x+1.

Answers

Answer:

The Graph Should Be Going Down Pretty Sharp and Intersects the Y-Axis at 1

Step-by-step explanation:

There isn't a visual graph so I can't directly pick which one, but I can describe it to you.

Answer: There should be a point at (6, -1), (0, 1), (4, 1)

Step-by-step explanation:

Graph the line using the slope and y-intercept, or two points.

− 5

y-intercept:  

( 0,1)

x   y

0  1

1 −4

Hope this helps!

Please mark brainiest!:)

Use the properties of exponents to rewrite the expression.
3•b•b•b•b•b•c•c•c•c•c

Answers

Answer:

3 b^5 c^5

Step-by-step explanation:

3•b•b•b•b•b•c•c•c•c•c

There is 1 number 3  = 3

There are 5 letter b   = b^5

There are 5 letter c  = c^5

3 * b^5 * c^5

3 b^5 c^5

Answer:

In 3•b•b•b•b•b•c•c•c•c•c, there is one three, five b's, and five c's. By simplifying the expression, we get 3[tex]b^{5}c^{5}[/tex].

The function (x)=1 xl written as a piecewise function looks like

Answers

Answer:

False.

Step-by-step explanation:

This is the absolute value of x  so if x < 0 then f(x) will be x not -x.

The function f(x) = 1/x can be represented as a piecewise function with different cases for x > 0, x < 0, and x = 0. It is not defined at x = 0, and it approaches positive or negative infinity as x approaches 0 from either side.

To represent the function f(x) = 1/x as a piecewise function, we need to consider the nature of the function around x = 0. The function is undefined at x = 0, and it approaches positive infinity as x approaches zero from the negative side and negative infinity from the positive side.

Piecewise Representation:

When x > 0, the function is f(x) = 1/x.When x < 0, the function is also f(x) = 1/x.When x = 0, the function is not defined.

This can be written as a piecewise function:

f(x) = { 1/x,    x > 0
        { 1/x,    x < 0
        { undefined,    x = 0

The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.

What is the approximate difference between m∠C and m∠A?

Answers

Answer:

The approximate difference between m∠C and m∠A is 45° to the nearest degree

Step-by-step explanation:

* Lets talk about the right triangle

- It has one right angle and two acute angles

- The side opposite the the right angle is called hypotenuse

- The other sides are called the legs of the right angle

- In ΔABC

∵ AC is the hypotenuse

∴ ∠B is the right angle

∴ AB and BC are the legs of the right angle

∴ Angles A and C are the acute angles

∵ m∠B = 90°

- The sum of the measures of the interior angles of a Δ is 180°

∴ m∠A + m∠C = 180° - 90° = 90°

- We will use trigonometry to find the measures of angles A and C

- sin A is the ratio between the opposite side to angle ∠A and the

  hypotenuse

∵ BC is the opposite side of angle A

∴ sin A = BC/AC

∵ BC = 5 cm

∵ AC = 13 cm

∴ sin A = 5/13

- Lets find m∠∠A by using sin ^-1

∴ m∠A = [tex]sin^{-1}\frac{5}{13}=22.62[/tex]

- Lets use the rule of the sum of angles A and C to find the measure

 of the angle C

∵ m∠A + m∠C = 90°

∴ 22.62° + m∠C = 90 ⇒ subtract 22.62 from both sides

∴ m∠C = 67.38°

- Lets find the difference between m∠C and m∠A

∴ The approximate difference between m∠C and m∠A is:

  67.38° - 22.62° = 44.78° ≅ 45° to the nearest degree

Help please ASAP !!! It’s worth 15 points!!!!!

Answers

The answer is A. The new weight room has an area of 480 ft.

Since the area of the gym is 4x^2, they are adding 480 ft^2, which is the area of the new weight room.

Hope this helps!

Answer:

A. The new weight room has an area of 480ft^2

Step-by-step explanation:

Area of gym = 4x^2

Area of weight room = 480

Area of gym + weight room = 4x^2 + 480

480 is a constant because its value cannot and will not change whereas x is an unknown


In what form is the following linear equation written?
3x – 2y=4
O
A. Point-slope
O
B. Standard
Slope-intercept
O
D. Rise-run
SUBMIT

Answers

Answer:

B. Standard

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

(x₁, y₁) - point

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

The standard form of an equation of a line:

[tex]Ax+By=C[/tex]

The general fom of an equation of a line:

[tex]Ax+By+C[/tex]

We have the equation 3x - 2y = 4 in standard form.

If an acute angle increases, then its supplement

Answers

Answer:

gets smaller.

Step-by-step explanation:

Quick Answer

To give you a short quick answer, the supplement is going to have to decrease or get smaller.

Example

Suppose the acute angle is 10 (anything under 90 will do).

Then the supplement is going to be 180 - 10 = 170

Now suppose the acute angle increase to 50 degrees.

That means the supplement will go from 180 - 50 = 130

Conclusion

As the acute angle gets bigger, the supplement gets smaller. This is an important idea to get clear. Bigger and Smaller or More or Less can be ugly little words, so anytime you come across them, pay attention. It will make your life in science so much easier.

Craig has 72 feet of material to build a fence around a rectangular flower bed on his property. If the width of the fence must be 3 feet, what is the length of the fence in yards if he uses all 72 feet of material

Answers

Answer:

33 feet.

Step-by-step explanation:

Perimeter of a rectangle = 2*width + 2*length.

So here we have:

2*3 + 2*L = 72  where L = the length.

2L = 72 - 6 = 66

L = 33 feet.

Final answer:

Craig has 72 feet or 24 yards of material, with a stated width of 3 feet (1 yard). Subtracting the width of two sides from the total perimeter (24 yards), we find that the length of Craig's fence is 22 yards.

Explanation:

Craig has 72 feet of material to build a fence around a rectangular flower bed, with the width required to be 3 feet. To calculate the length of the fence in yards, we first need to find out the total perimeter in yards. Since Craig is using all 72 feet of material, this is the perimeter of the fence. We know that 1 yard is equal to 3 feet, so we convert 72 feet to yards.

To do this division, 72 feet ÷ 3 feet per yard = 24 yards. So, Craig has 24 yards of fencing material in total.

If one side (width) of the flower bed is 3 feet, which is equivalent to 1 yard, we must subtract the width of the two opposite sides from the total perimeter to find the total length of the fence. 24 yards total perimeter - 2 yards total width = 22 yards total length. Therefore, the length of Craig’s fence in yards is 22 yards.

In the diagram,the dashed figure is the image of the solid figure.What is the image of

Answers

It would be a rotation I believe

Answer:

<R It rotates than flips look at the corners

Step-by-step explanation:

Look at the corners

Let f(x) = x + 1 and G(x)=1/x What is the range of (F*G)(X)

Answers

[tex]

f(x)=x+1 \\

g(x)=\dfrac{1}{x} \\

(f\cdot g)(x)=(x+1)\dfrac{1}{x} \\

(f\cdot g)(x)=\underline{\dfrac{x+1}{x}} \\ \\

0=\dfrac{x+1}{x} \\

0=\dfrac{x}{x}+\dfrac{1}{x} \\

0=1+\dfrac{1}{x} \\

-1=\dfrac{1}{x} \\

-x=1 \\

x=1

[/tex]

ANSWER

[tex]y \ne1[/tex]

EXPLANATION

The given functions are

[tex]f(x) = x + 1[/tex]

and

[tex]g(x) = \frac{1}{x} [/tex]

We want to find

[tex](f \times g)(x)[/tex]

We use function properties to obtain:

[tex](f \times g)(x) = f(x) \times g(x)[/tex]

[tex](f \times g)(x) = (x + 1) \times \frac{1}{x} = \frac{x + 1}{x} [/tex]

There is a horizontal asymptote at:

[tex]y = 1[/tex]

Let

[tex]y = \frac{x + 1}{x} [/tex]

[tex]xy = x + 1[/tex]

[tex]xy - x = 1[/tex]

[tex]x(y - 1) = 1[/tex]

[tex]x = \frac{1}{y - 1} [/tex]

The range is

[tex]y \ne1[/tex]

Or

[tex]( - \infty ,1) \cup(1, \infty )[/tex]

two secants meet outside the circle, forming an angle of 42 degrees. if the larger intercepted arc is 120 degrees, find the smaller intercepted arc

Answers

Answer:

36°

Step-by-step explanation:

An angle whose vertex lies outside a circle whose sides are 2 secants of the circle is

angle = [tex]\frac{1}{2}[/tex] ( larger arc - smaller arc ), that is

42 = [tex]\frac{1}{2}[/tex] ( 120 - smaller ) ← multiply both sides by 2

84 = 120 - smaller, hence

smaller = 120 - 84 = 36°

Jessica and Martha each have a bag of cookies with unequal quantities. They have 30 cookies total between the two of them. Each of them ate 6 cookies from their bag. The product of the number of cookies left in each bag is not more than 80.
How many more cookies will Jessica have Martha?
If x represents the number of cookies Jessica started with, complete the statements below.

The inequality that describes the relationship between the number of cookies each one of them has is x^2 - ____ x +224 >= 0.
Jessica has at least ____ cookies more than Martha.​

Answers

Answer:

Part 1) The inequality that describes the relationship between the number of cookies each one of them has is [tex]x^{2} -30x+224\geq 0[/tex]

Part 2) Jessica has at least 2 cookies more than Martha

Step-by-step explanation:

Part 1) Find the inequality that describes the relationship between the number of cookies each one of them has

Let

x----> the number of cookies when Jessica started

30-x ----> the number of cookies when Martha started

we know that

Each of them ate 6 cookies from their bag

so

The cookies left in each bag are

(x-6)  ----> Jessica

and (30-x-6)=(24-x) ---> Martha

The product is equal to (x-6)(24-x)

The product of the number of cookies left in each bag is not more than 80.

so

[tex](x-6)(24-x)\leq 80\\ \\24x-x^{2}-144+6x\leq 80\\ \\-x^{2} +30x-144-80\leq 0\\ \\-x^{2} +30x-224\leq 0[/tex]

Multiply by -1 both sides

[tex]x^{2} -30x+224\geq 0[/tex]

Part 2) Solve the quadratic equation

[tex]x^{2} -30x+224\geq 0[/tex]

Solve by graphing

The solution is x=16 cookies

so

(30-x)=30-16=14 cookies

therefore

The number of cookies when Jessica started was 16 cookies

The number of cookies when Martha started was 14 cookies

The number of cookies left in each bag  is equal to

Jessica

16-6=10 cookies

Martha

14-6=8 cookies

Jessica has at least 2 cookies more than Martha

part 1- 30

part 2- 2

To simplify it at least those are the answers

which of the following points are solutions to the system of inequalities shown below?

check all that apply

y≥ 4x+3
x>1
answers:
a. (1,19)
b. (1,-1)
c. (4,11)
d. (4,19)
e. (1,11)
f. (2,11)

Answers

Answer:

f

Step-by-step explanation:

4x+3

x>1  x=2

4*2+3= 11

y>or = to 11

The cost of a jacket increased from $95.00 to $112.10. What is the percentage increase of the cost of the jacket?

Answers

Answer:

18%

Step-by-step explanation:

We are given that the cost of a jacket increased from $95.00 to $112.10 and we are to find the percentage increase in the cost of the jacket.

We know that the formula of percentage increase if given by:

Percentage increase = (new value - initial value)/initial value × 100

So substituting the given values to get:

Percentage increase = [tex] \frac { 1 1 2 . 1 0 - 9 5 . 0 0 } { 9 5 . 0 0 } \times 1 0 0 [/tex] = 18%

Point K(-2,1) is rotated 90 degrees about the origin. What are the coordinates of k'?

Answers

The coordinates of k' after k is rotated 90 degrees about the origin is (-1, -2)

How to determine the coordinates of k'?

From the question, we have the following parameters that can be used in our computation:

K = (-2, 1)

Transformation:

rotated 90 degrees about the origin

The rule of rotation by 90 degrees about the origin is represented as

(x,y)→(−y,x) .

Substitute the known values in the above equation, so, we have the following representation

K' = (-1, -2)

Hence, the image of K is (-1, -2)

Read more about transformation at

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What is the value of x?
Enter your answer in the box.

Answers

Answer:

x = 5

Step-by-step explanation:

Since the triangle is right with hypotenuse of 13

Use Pythagoras' identity to solve for x

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 12² = 13²

x² + 144 = 169 ( subtract 144 from both sides )

x² = 25 ( take the square root of both sides )

x = [tex]\sqrt{25}[/tex] = 5

Adimas found the mean of her 11 math test scores for the first semester.

x = ≈ 81
Using 81 as the mean, find the variance of her grades rounded to the nearest hundredth.

σ2 =

Find the standard deviation of her grades rounded to the nearest hundredth.

σ =

Answers

Answer: O^2= 71.36

               O=8.45  

Answer:

The complete question is attached.

To find the variance and deviation, we have to use their definition or formulas:

Standard deviation.

[tex]\sigma=\sqrt{\frac{\sum (x- \mu)^{2} }{N}}[/tex]

So, first we have to find the difference between each number and the mean:

76-81=-5

87-81=6

65-81=-16

88-81=7

67-81=-14

84-81=3

77-81=-4

82-81=1

91-81=10

85-81=4

90-81=9

Now, we have to elevate each difference to the squared power and then sum all:

[tex]25+36+256+49+196+9+16+1+100+16+81=785[/tex]

Then, we replace in the formula:

[tex]\sigma=\sqrt{\frac{785}{11}} \approx 8.45[/tex]

Variance.

The variance is just the squared power of the standard deviation. So:

[tex]\sigma^{2}=(8.45)^{2}=71.40[/tex]

Write the following phrase as an expression.
x to the 9th

Answers

The answer is x^9 pretty simple.
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