Joe, Megan, and Santana are salespeople. Their sales manager has 21 accounts and must assign seven accounts to each of them. In how many ways can this be done?

We start with the parent function

[tex]f(x)=x^2[/tex]

The first child function would be

[tex]g(x)=(2x)^2[/tex]

We have multiplied the input of the function by a constant: we have

[tex]g(x)=f(2x)[/tex]

This kind of transformation result in a horizontal stretch/compression. If the multiplier is greater than 1, we have a compression. So, this first child causes a horizontal compression with compression rate 2.

The second child function would be

[tex]h(x)=(2x+6)^2[/tex]

We added 6 to  the input of the function: we have

[tex]h(x)=g(x+6)[/tex]

This kind of transformation result in a horizontal translation. If the constant added is positive, we translate to the left. So, this second child causes a translation 6 units to the left.

The third child function would be

[tex]l(x)=-(2x+6)^2[/tex]

We changed the sign of the previous function (i.e. we multiplied it by -1): we have

[tex]l(x)=-h(x)[/tex]

This kind of transformation result in a vertical stretch/compression. If the multiplier is greater than 1 we have a stretch, if it's between 0 and 1 we have compression. If it's negative, we reflect across the x axis, and then apply the stretch/compression. In this case, the multiplier is -1, so we only reflect across the x axis.

The fourth child function would be

[tex]m(x)=-(2x+6)^2+3[/tex]

We added 3 to previous function: we have

[tex]m(x)=l(x)+3[/tex]

This kind of transformation result in a vertical translation. If the constant added is positive, we translate upwards. So, this last child causes a translation 3 units up.

Recap

Starting from the parent function [tex]y=x^2[/tex], we have to:

Note that the order is important!

Answer:

B

Step-by-step explanation:

i know the other answer was a little confusing, but they did more, so feel free to give them brainliest, just wanted to help clarify :)

edgenuity 2020

Answer:

equivalent price/ gallon = 13.98 US$ / gallon

Step-by-step explanation:

Assuming that the exchange rate is 1.762 US$ /€ , then

thus

equivalent price/ gallon =   liters/gallon * euros / liter * dollars/euro

equivalent price/ gallon = 3.78541178 liters/ gallon *  2.096 € /liter * 1.762 US$ /€ = 13.98 US$ / gallon

equivalent price/ gallon = 13.98 US$ / gallon

if the actual price would be different from the equivalent , then there would be an arbitrage opportunity ( profit with no risk)

To find the price per gallon in France converted to dollars, multiply the price per liter by liters per gallon to get the Euro amount, then convert to dollars using the exchange rate. The result is approximately $13.97 per gallon.

The question asks to determine the price of gasoline per gallon in France when converted to Euros, considering the given petrol price per liter and the exchange rate. To calculate this, we will first convert the price from liters to gallons and then convert Euros to the equivalent value in using the exchange rate.

Therefore, the equivalent price of gasoline per gallon in France, when converted to dollars, is approximately $13.97.

Answer:

The normal vector is [tex]{\bf n} \ =\ 3{\bf i} -8{\bf j} +4{\bf k}[/tex]

Step-by-step explanation:

Let

[tex]{\bf b}=\langle\,x_1,\,y_1,\,z_1\, \rangle\,, \ \ {\bf r} = \langle\,x_2,\,y_2,\,z_2\, \rangle\,, \ \ {\bf s} = \langle\,x_3,\,y_3,\,z_3\, \rangle.[/tex]

The vectors

[tex]\overrightarrow{QR} \ = \ {\bf r} - {\bf b} \,, \qquad \overrightarrow{QS} \ = \ {\bf s} - {\bf b} \,,[/tex]

then lie in the plane. The normal to the plane is given by the cross product

[tex]{\bf n} = ({\bf r} - {\bf b})\times ( {\bf s} - {\bf b})[/tex]

We have the following points:

[tex]Q(-6,\,-4,\,-6)\,, \ \ R(-2,\,0,\,-1)\,, \ \ S(-2,\,1,\,1)\,.[/tex]

when the plane passes through [tex]Q,\, R[/tex], and [tex]S[/tex], then the vectors

[tex]\overrightarrow{QR} = \langle\, -2-(-6),\, 0-(-4),\, -1-(-6)\, \rangle\,, \overrightarrow{QS}= \langle\, -2-(-6),\, 1-(-4),\, 1-(-6)\, \rangle\,,\\\\\overrightarrow{QR} = \langle\, 4,\, 4,\, 5\, \rangle\,,\qquad \overrightarrow{QS}= \langle\, 4,\, 5,\, 7\, \rangle\,[/tex]

lie in the plane. Thus the cross-product

[tex]{\bf n} \ = \ \left|\begin{array}{ccc}{\bf i} & {\bf j} & {\bf k} \\ 4 & 4 & 5 \\ 4 & 5 & 7 \end{array}\right| \ = \begin{pmatrix}4\cdot \:7-5\cdot \:5&5\cdot \:4-4\cdot \:7&4\cdot \:5-4\cdot \:4\end{pmatrix} \ = \ 3{\bf i} -8{\bf j} +4{\bf k}[/tex]

is normal to the plane.

The normal vector to the plane passing through the points (-6,-4,-6), (-2,0,-1), and (-2,1,1) is (-6, -8, 4). This is found by obtaining two vectors from the given points and then taking the cross product of these vectors.

To find the vector normal to the plane passing through the points (-6, -4, -6), (-2, 0, -1), and (-2, 1, 1), we first need to find two vectors lying in the plane that originate from the same point. Let's take the first point as common and obtain the vectors AB and AC:

AB = B - A = (-2 - (-6), 0 - (-4), -1 - (-6)) = (4, 4, 5)

AC = C - A = (-2 - (-6), 1 - (-4), 1 - (-6)) = (4, 5, 7)

Now, we can find the normal vector to the plane by taking the cross-product of these two vectors. The cross product of two vectors provides a new vector which is perpendicular to the original vectors:

N = AB x AC = (4*7 - 5*5, 5*4 - 4*7, 4*5 - 4*4) = (-6, -8, 4)

Therefore, the normal vector to the plane is (-6, -8, 4).

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Answer:

[tex]\bar X = \frac{\sum_{i=1}^n x_i f_i}{n} = \frac{1220750}{500}=2441.5[/tex]

[tex] s= \sqrt{\frac{N \sum x^2 f -[\sum xf]^2}{N(N-1}}= \sqrt{\frac{500*3408029125 -[1220750]^2}{50*49}}=9341.2405[/tex]

Step-by-step explanation:

In order to find the mean and standard deviation we can create the following table:

Limits            Frequency(f)      x(midpoint)      x*f           x^2 *f

__________________________________________________

0-499                   9                   249.5         2245.5    560252.3

500-999              13                  749.5         9743.5     7302753

1000-1499           33                 1249.5       41233.5    51521258.25

1500-1999           115                1749.5       201192.5   351986278.8

2000-2499         125               2249.5      281187.5   632531281.3

2500-2999          81                2749.5      222709.5  612339770.3

3000-3499          47                3249.5      152726.5   496284761.8

3500-3999          45                3749.5      168727.5   632643761.3

4000-4499          22                4249.5      93489       397281505.5

4500-4999          10                 4749.5       47495      225577502.5

_____________________________________________________

Total                    500                               1220750     3408029125

We can calculate the mean with the following formula:

[tex]\bar X = \frac{\sum_{i=1}^n x_i f_i}{n} = \frac{1220750}{500}=2441.5[/tex]

And the standard deviation would be given by:

[tex] s= \sqrt{\frac{N \sum x^2 f -[\sum xf]^2}{N(N-1}}= \sqrt{\frac{500*3408029125 -[1220750]^2}{50*49}}=9341.2405[/tex]

Answer:

Lowest Cost is for Drum set, when compared to others instruments of same type.

Highest cost is for Guitar,when compared to others  instruments of same type.

Order:

Guitar>Piano>Drum Set

Step-by-step explanation:

Consider the normal distribution for all cases.

Formula we are going to use is:

[tex]z=\frac{\bar x-\mu}{\sigma}[/tex]

where:

[tex]\bar x[/tex] is the purchasing cost

[tex]\mu[/tex] is the mean

[tex]\sigma[/tex] is the standard deviation

For Piano:

[tex]z=\frac{3000-4000}{2500}\\ z=-0.4[/tex]

For Guitar:

[tex]z=\frac{550-500}{200}\\ z=0.25[/tex]

For Drum Set:

[tex]z=\frac{600-700}{100}\\ z=-1[/tex]

Lowest Cost is for Drum set, when compared to others instruments of same type.

Highest cost is for Guitar,when compared to others  instruments of same type.

Order:

Guitar>Piano>Drum Set

The drum set, priced at $600, costs the least compared to the average drum set price, being 1.0 standard deviation below the mean. The guitar, priced at $550, costs the most compared to the average guitar price, at 0.25 standard deviation above the mean. These conclusions are drawn using the z-score method to compare the instruments' prices to their respective averages and standard deviations.

To determine which musical instrument costs the least and the most when compared to others of the same type, we calculate how many standard deviations below or above the mean each instrument's cost falls. For the piano, guitar, and drum set, we will use the z-score formula, which is (z = (X - μ) / σ), where X is the observed value, μ is the mean, and σ is the standard deviation.

For the piano, the z-score is ($3,000 - $4,000) / $2,500 = -0.4.

For the guitar, the z-score is ($550 - $500) / $200 = 0.25.

For the drum set, the z-score is ($600 - $700) / $100 = -1.0.

The drum set's cost is the lowest compared to other drums because it is 1.0 standard deviations below the mean. The guitar's cost, being 0.25 standard deviations above the mean, is the highest compared to other guitars. Therefore, Matt's drums cost the least in comparison to his own instrument type, and Becca's guitar costs the most compared to her own instrument type.

Answer:

A or C

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

0.50

Step-by-step explanation:

The probability that a customer has purchased a cup of coffee given that they have also purchased a piece of cake is determined by the percentage of customers who purchase both coffee and cake (20%) divided by the percentage of customers who purchase cake (40%):

[tex]P(Coffee|Cake) = \frac{P(Coffee\cap Cake)}{P(Cake)}\\P(Coffee|Cake) =\frac{0.20}{0.40}=0.50[/tex]

50% of the customers also purchased coffee given that they have purchased a piece of cake.

Final answer:

To find the probability that a customer purchased a cup of coffee given they purchased a cake, we use conditional probability, resulting in a 50% chance.

Explanation:

The question requires us to use conditional probability to find the probability that a customer who purchased a piece of cake also purchased a cup of coffee. The known probabilities are that 70% of customers purchase coffee, 40% purchase cake, and 20% purchase both.

To find the probability that a customer purchased coffee given they purchased cake, we use the formula for conditional probability: P(A|B) = P(A ∩ B) / P(B), where A is the event 'customer buys coffee' and B is the event 'customer buys cake'. Given P(A ∩ B) = 20% or 0.2, and P(B) = 40% or 0.4, the calculation is P(A|B) = 0.2 / 0.4.

So, the conditional probability is 0.5 or 50%.

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

[tex]\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416[/tex]

Answer:

the probability is 0.32 (32%)

Step-by-step explanation:

defining the event W= has extended warranty , then

P(W)= probability of purchasing the basic model * probability of purchasing extended warranty given that has purchased the basic model + probability of purchasing the deluxe model * probability of purchasing extended warranty given that has purchased the deluxe model = 0.3 * 0.44 + 0.7 * 0.40 = 0.412

then using the theorem of Bayes for conditional probability and defining the event B= has the basic model , then

P(B/W)= P(B∩W)/P(W)= 0.3 * 0.44/0.412 =0.32 (32%)

where

P(B∩W)= probability of purchasing the basic model and purchasing the extended warranty

P(B/W) = probability of purchasing the basic model given that has purchased the extended warranty

Final answer:

Using Bayes' theorem, there is approximately a 32% chance that a customer who purchased an extended warranty has a basic model camera.

Explanation:

The question asks us to calculate the probability of a randomly selected purchaser having a basic model given that they have an extended warranty. We can use Bayes' theorem to solve this. Let's denote B as the event of buying a basic model, D as the event of buying a deluxe model, and W as the event of purchasing an extended warranty. From the information provided, we can infer :

P(B) = 0.30 (30% of cameras sold are basic models)

P(D) = 1 - P(B) = 0.70 (since if it's not a basic model, it's a deluxe model)

P(W|B) = 0.44 (44% of basic model buyers purchase an extended warranty)

P(W|D) = 0.40 (40% of deluxe model buyers purchase an extended warranty)

We are interested in P(B|W), the probability that a randomly selected purchaser who bought an extended warranty has a basic model. Using Bayes' theorem:

P(B|W) = (P(W|B) * P(B)) / ((P(W|B) * P(B)) + (P(W|D) * P(D)))

Plugging in the values:

P(B|W) = (0.44 * 0.30) / ((0.44 * 0.30) + (0.40 * 0.70))

P(B|W) = (0.132) / (0.132 + 0.28)

P(B|W) = 0.132 / 0.412 = approximately 0.320

So, there is approximately a 32% chance that a customer with an extended warranty has purchased a basic model camera.

Answer:

The weight of the citation designation should be at 4.8432 pounds.

Explanation:

Given

Mean [tex]= 3.2 pounds.[/tex]

Standard deviation[tex]= 0.8 pound.[/tex]

Step 1:

Consider 'y' as one of the top weight, that is, [tex]y = 2 \% = 2.054 pounds.[/tex]

Let 'x' be the weight of the citation designation.

[tex]y = \frac{x-mean}{standard\ deviation}[/tex]

[tex]=2.054 = \frac{x-3.2}{0.8}[/tex]

[tex]=2.054\times 0.8 = x-3.2[/tex]

[tex]=1.6432 = x-3.2[/tex]

[tex]x = 1.6432+3.2[/tex]

 [tex]x = 4.8432[/tex]

Thus, at 4.8432 pounds citation designation be established.

To learn more about citation, refer:

Final answer:

The citation catfish designation should be established at a weight of at least 4.84 pounds, which corresponds to the top 2% of a normal distribution given the mean is 3.2 pounds and the standard deviation is 0.8 pounds.

Explanation:

The weight at which a citation catfish designation should be established is calculated by identifying the z-score that corresponds to the top 2% of a normal distribution. Given that the average weight of a catfish is 3.2 pounds with a standard deviation of 0.8 pounds, we can use a z-table to find the z-score for the 98th percentile, which typically is around 2.05.

Using the z-score formula: z = (X - mean) / standard deviation, we rearrange to solve for the unknown X (catfish weight): X = z * standard deviation + mean. Plugging in the numbers: X = 2.05 * 0.8 + 3.2, we find that the citation catfish should weigh at least 4.84 pounds.

Final answer:

To find the probability of someone with periodontal disease having a heart attack, we can use conditional probability and Bayes' theorem. The probability of having a heart attack given that someone has periodontal disease is 79%. Using Bayes' theorem, we can calculate the probability of a person with periodontal disease having a heart attack.

Explanation:

To answer part A, we can use conditional probability. The probability of having a heart attack given that someone has periodontal disease is represented by P(heart attack | periodontal disease). According to the given information, 79% of people who have suffered a heart attack had periodontal disease. Therefore, P(heart attack | periodontal disease) = 0.79.

To answer part B, we can use Bayes' theorem. The probability of a person with periodontal disease having a heart attack is represented by P(heart attack | periodontal disease). According to the given information, the probability of having a heart attack in the community is 38%.

Therefore, P(heart attack) = 0.38. Let's use Bayes' theorem: P(heart attack | periodontal disease) = (P(periodontal disease | heart attack) × P(heart attack)) / P(periodontal disease). We know that P(periodontal disease | heart attack) = 0.79 from part A.

The probability of having periodontal disease in the community is represented by P(periodontal disease). In the given information, it says that only 33% of healthy people have periodontal disease. Therefore, P(periodontal disease) = 0.33. Substituting these values into Bayes' theorem, we can calculate P(heart attack | periodontal disease).

Answer:

hi guada!

Step-by-step explanation:

well the answer i think is 35.

180-155= 25

180-120-25=35

Answer:

7

Step-by-step explanation:

Since the goal is to draw three marbles of the same colour, regardless of which colour that is, the worst possible scenario would be drawing two marbles of each color in the first six picks (2 red, 2 white and 2 blue). At this point, with the 7th pick, no matter what colour marble the student picks will form three of the same kind.

Therefore, the minimum number of marbles which students should take from the box to ensure that at least three of them are of the same colour is 7.

Final answer:

To ensure at least three marbles of the same color, a minimum of 349 marbles must be drawn from the box.

Explanation:

Question: What is the minimum number of marbles which students should take from the box to ensure that at least three of them are of the same color?

When considering the worst-case scenario, you would need to take marbles until you have at least 3 of the same color.

For this situation, where you have 203 red, 117 white, and 28 blue marbles:

It's possible that you could pick 202 red, 117 white, 27 blue, and still not have 3 of the same color. The next pick would guarantee 3 of the same color, giving a minimum of 349 marbles in total.

Answer:

Therefore,

[tex]AB=16.25\ units[/tex]

The Measurement of AB is 16.25 units.

Step-by-step explanation:

In Right Angle Triangle ABC

m∠C=90°

AC = 10.01    .....(Adjacent Side to angle A)

m∠A=52°

cos 52 ≈ 0.616

To Find:

AB = ? (Hypotenuse)

Solution:

In Right Angle Triangle ABC, Cosine Identity,

[tex]\cos A= \dfrac{\textrm{side adjacent to angle A}}{Hypotenuse}\\[/tex]

Substituting the values we get

[tex]\cos 52= \dfrac{AC}{AB}=\dfrac{10.01}{AB}[/tex]

But cos 52 ≈ 0.616 ....Given

[tex]AB=\dfrac{10.01}{0.616}=16.25\ units[/tex]

Therefore,

[tex]AB=16.25\ units[/tex]

The Measurement of AB is 16.25 units.

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let Y = the time taken to deliver a pizza.

The random variable Y follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

[tex]f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.[/tex]

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

[tex]P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70[/tex]

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let X = results of a certain blood test.

It is provided that the random variable X follows a Normal distribution with parameters [tex]\mu = 60[/tex] and [tex]s = 18[/tex].

The probabilities of a Normal distribution are computed by converting the raw scores to z-scores.

The z-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

[tex]P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z<0.833)=0.7967[/tex]

The percentage of results more than 45 is: [tex]0.7967\times100=79.67\%[/tex]

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

[tex]P(X<85)=P(\frac{X-\mu}{\sigma}< \frac{85-60}{18})=P(Z<1.389)=0.9177[/tex]

The percentage of results less than 85 is: [tex]0.9177\times100=91.77\%[/tex]

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

[tex]P(75<X<90)=P(\frac{75-60}{18}<\frac{X-\mu}{\sigma}< \frac{90-60}{18})\\=P(0.833<Z<1.67)\\=P(Z<1.67)-P(Z<0.833)\\=0.9525-0.7967\\=0.1558[/tex]

The percentage of results are between 75 and 90 is: [tex]0.1558\times100=15.58\%[/tex]

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

[tex]P(20<X<100)=P(\frac{20-60}{18}<\frac{X-\mu}{\sigma}< \frac{100-60}{18})\\=P(-2.22<Z<2.22)\\=P(Z<2.22)-P(Z<-2.22)\\=0.9868-0.0132\\=0.9736[/tex]

Then the probability that the results outside the range 20 to 100 is: [tex]1-0.9736=0.0264[/tex].

The percentage of results outside the range 20 to 100 is: [tex]0.0264\times100=2.64\%[/tex]

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

Answer:

Option 1

Step-by-step explanation:

(3m/n)⁴ = (3⁴×m⁴)/n⁴

= 81m⁴/n⁴

Answer:

You want to buy some golden apples. Each golden apple cost $2. How much much does golden apples pass cost?

y = total cost

x = amount of apple

Answer:

32

Step-by-step explanation:

32 X 2 = 64. 64 - 9 = 55.

Answer:

There is a 33.67% probability that exactly one of them is defective.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Here, we can have different formats. For example, D-ND-ND is the same as ND-D-ND, that is, the ordering is not important. So we use the combinations formula.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Desired outcomes

One defective(one from a set of 55) and two non defective(two from a set of 45). So

[tex]D = C_{55,1}*C_{45,2} = \frac{55!}{54!1}*\frac{45!}{43!2!} = 55*45*22 = 54450[/tex]

Total outcomes

Three from a set of 100. So

[tex]T = C_{100,3} = \frac{100!}{97!3!} = 161700[/tex]

What is the probability that exactly one of them is defective

[tex]P = \frac{D}{T} = \frac{54450}{161700} = 0.3367[/tex]

There is a 33.67% probability that exactly one of them is defective.

Answer:

Correct option (A).

Step-by-step explanation:

The probability of an individual catching a flu when he or she has taken vitamin C is, P (F|C) = 0.0342.

The probability of an individual catching a flu when he or she has not taken vitamin C is, P (F|C') = 0.2653.

Th ratio of individuals who caught the flu when they did not take vitamin C to those who took vitamin C is:

[tex]=\frac{P(F|C')}{P(F|C)}\\ =\frac{0.2653}{0.0342} \\=7.7573[/tex]

This implies that:

[tex]P(F|C')=7.7573\times P(F|C)[/tex]

Thus, the the individuals not taking vitamin C are 7.7573. Times more likely to catch the flu than individuals taking vitamin C.

The statement is True.

The statement that individuals not taking vitamin C are 7.7573 times higher at risk of catching flu than those taking it, is true based on the provided numbers in the question.

To determine if the statement is true or false, we need to divide the odds of catching the flu among individuals not taking vitamin C by the odds of those taking it:

To do this, you divide 0.2653 (odds for those not taking vitamin C) by 0.0342 (odds for those taking vitamin C). This calculation results in approximately 7.7573.

Therefore, the statement 'individuals not taking vitamin C are 7.7573 times more likely to catch flu than individuals taking vitamin C is true as the calculation matches the provided number in the statement.

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Answer:

1.242% probability that the second one selected is defective given that the first one was defective

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have

484 containers

7 are defective

a) What is the probability that the second one selected is defective given that the first one was defective?

After the first one was selected(defective), we have

483 containers

6 defective

6/483 = 0.01242

0.01242 = 1.242% probability that the second one selected is defective given that the first one was defective

Answer:

a) Sample co-variance = -1.5

b) Sample correlation = -0.4404152

c) Weak negative relationship between X and Y.

Step-by-step explanation:

a) by sample co-variance = sum ((x - xbar)* (y-ybar)/n-1

#.... use the following program in R

x = c(7,8, 5, 3, 9)

y = c(7,5,9,7,7)

sv = sum((x-mean(x))*(y-mean(y)))/4

cor(x,y)

####################################

Answer:

Step-by-step explanation:

given that the operations manager of a plant that manufactures tires wishes to compare the actual inner diameter of two grades of tires, each of which has a nominal value of 575 millimeters. A sample of five tires of each grade is selected, and the results representing the inner diameters of the tires, ranked from smallest to largest, are as follows:

Grade X

568 570 575 578 584

Mean = Total/5 = 575

Median = middle entry = 575

Mode = nil

Grade Y

573 574 575 577 578

Mean = sum/5 = 575.4

Median = middle entry =575

Mode = nil

Final answer:

The number of tickets drawn at random can be calculated using the formula for the number of combinations.

Explanation:

To determine the number of tickets drawn at random in this scenario, we need to calculate the total number of possible outcomes. In this case, Maria is drawing marbles without replacement, meaning that the number of marbles in the bag decreases with each draw. We can use the formula for the number of combinations to calculate the total number of outcomes. The formula is nCr = n! / (r!(n-r)!), where n is the total number of marbles in the bag and r is the number of marbles drawn. In this case, n = 5+8+3 = 16 and r = 2. Therefore, the number of tickets drawn at random is 16C2 = 120.

Answer:

This is an "Experiment" type of study

Step-by-step explanation:

Researchers use various methods or techniques to conduct research and draw conclusions from it. Some of these methods are given below

1. Experiment

2. Observational study

3. Anecdotal evidence

1. Experiment: In this type of study, researchers have control over their setup and they can give directions or apply any treatment on their subjects.

2. Observational study: In this type of study, researchers cannot give directions or apply any treatment on their subjects but rather they can only observe what is going on.

3. Anecdotal evidence: Also refers to experience and can be defined as personal experience based on something.

The study that we are given is clearly an example of "experiment" since half of the participants were to told walk 2 miles a day for 6 weeks. The researchers have control over their subjects in this case and they gave directions to their subjects to do this and that.

This could have been an observational study if researchers had selected 10 people who walked 2 miles a day for 6 weeks and 10 people who did not walk 2 miles a day for 6 weeks and simply measured their blood pressure and come to a conclusion. This way, it would have been a case of observational study.

Answer:

Experiment

Step-by-step explanation:

Experimental study design is a type of study design in which the investigator or researcher is in complete control of the research environment. For example, a researcher may want to assess the effects of certain treatments on some experimental units. The researcher or investigator decides the type of treatment, the type of experimental unit to use, the time, the allocation and assessment procedures of the treatment and effects respectively. In Experimental study design, the investigator or researcher is in complete control of the exposure and the result should therefore provide a stronger evidence of an association or lack of association between an exposure and a health problem than would an observational study where the investigator or researcher is usually a passive observer as he only observes and analyses facts and events as they occur  naturally or anecdotal evidence which is just someones personal experience or testimony without scientific proof that can be based on some measurement or experimentation.

Answer:

16 ways

Step-by-step explanation:

We are given that

Total cards=52

Total queen in deck of cards=4

Total cards of heart=13

We know 1 card of queen is heart

Number of ways drawing one card of heart out of 13=[tex]13C_1[/tex]

Using combination formula ;[tex]nC_r=\frac{n!}{r!(n-r)!}[/tex]

Number of ways drawing one card of heart out of 13=[tex]\frac{13!}{1!12!}=\frac{13\times 12!}{12!}=13[/tex]

Number of ways of drawing one card of queen out of 4=[tex]4C_1=\frac{4!}{3!}[/tex]

Number of ways of drawing one card of queen out of 4=[tex]\frac{4\times 3!}{3!}=4[/tex]

Total number of ways of drawing one card out of 52 cards=[tex]13+4-1=16[/tex]

Answer:

15.87% probability that no more than 80 customers walk into the coffee shop next Monday

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 100, \sigma = 20[/tex]

What is the probability that no more than 80 customers walk into the coffee shop next Monday?

This is the pvalue of Z when X = 80. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 100}{20}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a pvalue of 0.1587.

So there is a 15.87% probability that no more than 80 customers walk into the coffee shop next Monday

Answer:

Step-by-step explanation:

Please kindly check the attached

(p(x))/(q(x))=f(x)+(r(x))/(q(x))

Answer:

Step-by-step explanation:

f(x) = 3x-2

g(x) = 1/2(x²)

f(0) = 3x-2 = 3(0)-2 = 0-2 = -2

f(-1) = 3x-2 = 3(-1)-2 = -3-2 = -5

g(4) = 1/2(4²) = 1/2(16) = 8

g(-1) = 1/2(-1²) = 1/2(1) = 1/2

Answer:

68% of the dinosaurs' ages were within 1 standard deviation of the mean.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

What percentage of the dinosaurs' ages were within 1 standard deviation of the mean?

By the Empirical Rule, 68% of the dinosaurs' ages were within 1 standard deviation of the mean.