Jennifer works part time making crafts. She is paid $12 for each plaque that she completes. One particular week, she made 30 plaques. Find her gross income for the week.

Answer:

B. False

Step-by-step explanation:

Given an equation of the type x = a(y-x)^2 + h, We know that If the "y" is squared, it is horizontal (opens left or right). If a is positive, the parabola opens up or to the right. If it is negative, it opens down or to the left.

Like the y is squared and the "a" is positive then it opens to the right, so it's false

its either a half or part of what its worth

Answer:

Step-by-step explanation:

The actual definition of a fractional equation could be:

[tex]\frac{a}{x}+\frac{b}{x+1}=c[/tex]

In words, fractional equations are those which has variables in the denominator of a fractional term, that doesn't mean that all fractions must have a unknown denominator, but at least one of the denominators should have a variable.

Therefore, according to its definition, the right answer is third option.

In addition, other options don't make sense, multiple variables is not necessarily the case for fractional equations. Similarly, not all denominators must have variables. And, having variable only in the numerators don't define the equation as fractional.

To solve the inequalities by graphing, transform each inequality into an equation form, plot the lines on the graph, and identify the overlapping region that satisfies both inequalities. The lines are 5x + 2y ≥ 3 and y ≥ x, with appropriate slopes and y-intercepts.

To solve the inequalities by graphing, we need to transform each inequality into a graphable equation form and then use the properties of the lines to find the solution set. The inequalities in question are:

Let's graph each inequality one by one:

The solution to the system of inequalities will be the region on the graph where both conditions are satisfied, typically above the lines in this case because both inequalities are greater than or equal to.

Always label your graph with f(x) and x, and select an appropriate scale for the x and y axes to ensure all important points and lines are visible on the graph.

The provided figures and instructions on slope and graphing help us understand how to plot each line based on their equations. Using the slope-intercept form, we graph the lines and identify the intersection or overlapping regions that satisfy both inequalities.

Answer:what is the table

Step-by-step explanation:

Answer:

The area of each section of the circle is [tex]A=25\pi\ m^{2}[/tex]

Step-by-step explanation:

we know that

Each section represent a quarter of circle

The area of a quarter of circle is equal to

[tex]A=\frac{1}{4}\pi r^{2}[/tex]

we have

[tex]r=10\ m[/tex]

substitute

[tex]A=\frac{1}{4}\pi (10)^{2}[/tex]

[tex]A=25\pi\ m^{2}[/tex]

To simplify negative 5 minus the square root of negative 44, you need to use imaginary numbers. The expression simplifies to -5 minus 2i√11. Hence, the correct answer is Option B.

To simplify
negative 5 minus the square root of negative 44, we need to work with imaginary numbers. Recall that the square root of -1 is defined as i, which is the imaginary unit. Using this, we can simplify the given expression step-by-step:

Recognize that
√-44 can be written as
√(-1 × 44).

Since
√(-1 × 44) = √(-1) × √44, and
√(-1) = i, we get
i × √44.

Now, we simplify
√44:
√44 = √(4×11) = 2√11.

Therefore,
i × √44 = 2i√11.

Putting it all together,
-5 - √-44 becomes
-5 - 2i√11.

Hence, the correct answer is
Option B. negative 5 minus 2 i times the square root of 11.

The fully simplified form of the expression is [tex]-25 - 14i \sqrt{11}[/tex]

To simplify the expression [tex]-5 - \sqrt{-44} - 5 - 4 \cdot \sqrt{11} i - 5 - 4i \cdot \sqrt{11} - 5 - 2i \cdot \sqrt{11} - 5 - 2 \cdot \sqrt{11} i[/tex], we will follow these steps:

Understanding Square Roots of Negative Numbers:
The square root of a negative number can be written using the imaginary unit [tex]i[/tex], where [tex]i = \sqrt{-1}[/tex].

Thus, we can rewrite [tex]\sqrt{-44}[/tex] as follows:
[tex]\sqrt{-44} = \sqrt{-1 \cdot 44} = \sqrt{-1} \cdot \sqrt{44} = i \cdot \sqrt{44}[/tex]
Note that [tex]\sqrt{44} = \sqrt{4 \cdot 11} = 2\sqrt{11}[/tex].

Thus,
[tex]\sqrt{-44} = 2i \sqrt{11}[/tex]
Now substituting this into the expression gives us:
[tex]-5 - 2i \sqrt{11} - 5 - 4 \cdot \sqrt{11} i - 5 - 4i \cdot \sqrt{11} - 5 - 2i \sqrt{11} - 5 - 2\sqrt{11} i[/tex]  

Combining Like Terms:
Now combine all the real parts and the imaginary parts separately in the expression:  

Real Part:
[tex]-5 - 5 - 5 - 5 - 5 = -25[/tex]

Imaginary Part:
[tex]-2i\sqrt{11} - 4i\sqrt{11} - 4i\sqrt{11} - 2i\sqrt{11} - 2i\sqrt{11}[/tex]
Combining these gives:
[tex]-2i \sqrt{11} - 4i \sqrt{11} - 4i \sqrt{11} - 2i \sqrt{11} - 2i \sqrt{11} = -14i\sqrt{11}[/tex]

Final Result:
Combining the real and imaginary parts, we get:
[tex]-25 - 14i \sqrt{11}[/tex]

Answer:

Step-by-step explanation:

By my definition, no. There's a continuity up to and including just before 1 approaching from the left, and there's a continuity just after 1 going to the right. But 1 itself has a special definition h(x) = 4 when x = 1 and that makes it discontinuous.

Answer:

Step-by-step explanation:

There's only 1 '6' on an ordinary die with 6 sides, so the probability of rolling a 6 is 1/6.

That of NOT rolling a 6 is the complementary probability:  1 - 1/6 = 5/6.

Answer:

hope it helps you!!!!!!!!

The volume of a cylinder with a height of 8 and a radius of 3.8 is 115.52π cubic units, and with a height of 14 and a radius of 5, it is 350π cubic units.

The formula for the volume of a cylinder is V = πr²h, where r is the radius and h is the height of the cylinder.

For question 4 with a height of 8 and a radius of 3.8, the volume would be: V = π(3.8)²(8) = 115.52π cubic units.

For question 5 with a height of 14 and a radius of 5, the volume would be: V = π(5)²(14) = 350π cubic units.

These calculations illustrate how to determine the volume of cylinders using their respective dimensions, providing a fundamental understanding of geometric principles and applications.

the radius of this question 25pi

Answer:

Step-by-step explanation:

(1) The formula for the area of a circle of radius r is A = πr².

If the radius is 5 units, then the exact area of the circle is A = π(5 units)², or A = 25π units².

The third possible answer is the correct one.

(2) To solve -2x > -10, we must isolate x.

Divide both sides by -2, remembering that if we divide an inequality by a negative number, we must reverse the direction of the inequality sign:

-2x > -10

-----   -------  →  x < 5

 -2      -2

The first possible answer is the correct one:  Divide both sides by -2.

Answer:

31.8 in^2

Step-by-step explanation:

The area of a circle is pi×radius^2.

r=.5d=18/2=9

A=(3.14159)(9^2)=(3.14159)(81)=254.5

And if each peice is of equal area, the area of one peice will equal:

254.5/8=31.8

The area of single slice is 31.7925  inch².

The area of a circle is pi times the radius squared (A = π r²). Learn how to use this formula to find the area of a circle when given the diameter.

Given:

diameter= 18 inches

radius= 9 inches

Area of pizza

=πr²

=3.14*9*9

=254.34 inch²

Now, area of  8 equal slices=254.34 inch²

area of 1 equal slices=254.34 /8

                                     = 31.7925  inch²

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Answer:

The answer in the procedure

Step-by-step explanation:

Let

x-----> the number of snacks

we  know that

The inequality that represent this situation is

[tex]9.50+3.50x\leq 35[/tex]

Solve for x

[tex]3.50x\leq 35-9.50[/tex]

[tex]3.50x\leq 25.50[/tex]

[tex]x\leq 7.3\ snacks[/tex]

The maximum number of snacks is 7

The solution for the inequality is all real numbers less than or equal to 7.3 snacks

The solution for the problem situation is all whole positive numbers less than or equal to 7 snacks

Verify each case

case 1) 4 snacks

Is a solution to both the inequality and the problem situation

case 2) 314 snacks

Is not a solution

case 3) 912 snacks

Is not a solution

case 4) 4.25 snacks

Solution to the inequality ONLY

Answer:

solution to both: 2,4

solution to inequality ONLY: -2,4.25,3 1/4

NOT a solution: 9 1/2

Step-by-step explanation:

yw ;)

Answer:  d) Easton

Step-by-step explanation:

Let's evaluate Round 1 (blue) for each bowler:

Jimmy --> the lowest score is 0.5 SD below the mean

Claudia --> the lowest score was the mean

Easton --> the lowest score is 0.75 SD below the mean

Cynthia --> the lowest score was the mean

The person that had the worst game is: Easton

Answer:

easton

Step-by-step explanation:

I did the test

First combine the roots:

[tex]\sqrt[7]{x^5}\cdot\sqrt[7]{x^5}=\sqrt[7]{x^5\cdot x^5}=\sqrt[7]{x^{10}}[/tex]

Now use the fact that [tex]\sqrt[n]{x^n}=x[/tex] (for odd [tex]n[/tex]):

[tex]\sqrt[7]{x^{10}}=\sqrt[7]{x^7\cdot x^3}=\sqrt[7]{x^7}\cdot\sqrt[7]{x^3}=x\sqrt[7]{x^3}[/tex]

Answer:

1) The lateral area is LA=95 cm²

2) The surface area is SA=275  cm²

The answer is the option D) 95 cm² ; 275 cm²

Step-by-step explanation:

we know that

The surface area of the box (rectangular prism) is equal to

SA=2B+LA

where

B is the area of the base

LA is the lateral area of the box

Find the lateral area

LA=PH

where

P is the perimeter of the base

H is the height of the box

substitute

LA=2[15+6](2.26)=94.92 cm²

Round to the nearest whole number

LA=95 cm²

Find the area of the base B

B=(15)(6)=90 cm²

Find the surface area of the box

SA=2B+LA

substitute the values

SA=2(90)+95=275  cm²

Answer:

The result [tex]6x^4-x^3-19x^2+2x+12[/tex].

is a polynomial.

Step-by-step explanation:

The first polynomial is [tex]3x^2-2x-4[/tex].

The second polynomial is [tex]2x^2+x-3[/tex]

The closure property of multiplication states that if we multiply two polynomials the result must be a polynomial.

The product of these two polynomials is :

[tex](3x^2-2x-4)(2x^2+x-3)=6x^4-x^3-19x^2+2x+12[/tex].

We can see that the result is still a polynomial.

Answer: I believe the answer is C) The result 6x4 − x3 − 19x2 + 2x + 12 is a polynomial. !!!!!!!!

Answer:

 2 a^4 -2a^2b^2 -6b^4

Step-by-step explanation:

C = 7a^4 + 5a^2b^2 -3b^4

D = 5a^4 +7a^2b^2 +3b^4

C-D = 7a^4 + 5a^2b^2 -3b^4 - ( 5a^4 +7a^2b^2 +3b^4)

Distribute the minus sign

   7a^4 + 5a^2b^2 -3b^4 -  5a^4 -7a^2b^2 -3b^4

I like to line them up vertically

 7a^4 + 5a^2b^2 -3b^4

-  5a^4 -7a^2b^2 -3b^4

--------------------------------------

 2 a^4 -2a^2b^2 -6b^4

Answer:

The graph of [tex]y=cos(x)[/tex] is:

*Stretched vertically by a factor of 3

*Compressed horizontally by a factor  [tex]\frac{1}{10}[/tex] .

*Moves horizontally [tex]\pi[/tex] units to the rigth

The transformation is:

[tex]y=3f(10(x-\pi))[/tex]

Step-by-step explanation:

If  the function [tex]y=cf(h(x+b))[/tex]  represents the transformations made to the graph of [tex]y= f(x)[/tex]  then, by definition:

If  [tex]0 <c <1[/tex] then the graph is compressed vertically by a factor c.

If  [tex]|c| > 1[/tex] then the graph is stretched vertically by a factor c

If [tex]c <0[/tex]  then the graph is reflected on the x axis.

If [tex]b> 0[/tex] The graph moves horizontally b units to the left

If [tex]b <0[/tex] The graph moves horizontally b units to the rigth

If [tex]0 <h <1[/tex] the graph is stretched horizontally  by a factor [tex]\frac{1}{h}[/tex]

If [tex]h> 1[/tex] the graph is compressed horizontally by a factor [tex]\frac{1}{h}[/tex]

In this problem we have the function [tex]y=3cos(10(x-pi))[/tex] and our parent function is [tex]y = cos(x)[/tex]

The transformation is:

[tex]y=3f(10(x-\pi))[/tex]

Then [tex]c =3>1[/tex]  and [tex]b =-\pi < 0[/tex] and [tex]h=10 > 1[/tex]

Therefore the graph of [tex]y=cos(x)[/tex] is:

Stretched vertically by a factor of 3.

Also as [tex]h=10[/tex] the graph is compressed horizontally by a factor  [tex]\frac{1}{10}[/tex] .

Also, as [tex]b =-\pi < 0[/tex] The graph moves horizontally [tex]\pi[/tex] units to the rigth

Answer:

The best dimension to use to have the least cost to make 100 boxes is 5 x 5 x 4. It only costs $6.50 to make 100 boxes.

Step-by-step explanation:

Answer: Derrick’s mean test score= 74.4

Derrick’s median test score = 81.5

Better picture of his scores is given by Median.

Step-by-step explanation:

The given data : 25, 40, 68, 85, 95, 98, 70, 78, 85, 100

[tex]\text{Mean}=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}\\\\\Rightarrow\ \text{Mean}=\dfrac{744}{10}=74.4[/tex]

For Median , Arrange the data in order

25, 40, 68, 70, 78, 85, 85, 95, 98, 100

Median = Mean of two middle most value

[tex]\text{Median}=\dfrac{78+85}{2}=81.5[/tex]

Since the data set has outlier (25) and mean is affected by outlier.

So the better picture of his scores given by median value.

Answer:

(A) 74.4 (B) 81.5 (C) Median  (Look below or dont)

Step-by-step explanation:

Answer:

The trigonometric equation  (sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^3 can be simplified by:Using x for Θ: (sinx - cosx)^2 - (sinx + cosx)^2 = (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x) = - 2 sinx cosx - 2 sinx cosx = - 4 sinx cosx = - 2sin(2x)

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Expand (sinΘ + cosΘ)²

= sinΘ - cosΘ - (sin²Θ + 2 sinΘcosΘ + cos²Θ)

= sinΘ - cosΘ - sin²Θ - 2sinΘcosΘ - cos²Θ

= sinΘ - cosΘ - 2sinΘcosΘ - (sin²Θ + cos²Θ)

= - 2sinΘcosΘ - cosΘ + sinΘ - 1 → D

Answer:

(x+5)^2-20

(-5,-20)

Step-by-step explanation:

Use the formula (b/2)^2 in order to create a new term to complete the square.

Answer:

The correct answer is 12.5.

Step-by-step explanation:

When looking at the x axis, you locate the 2. After 2 minutes, the point connects at (2,12.5). Therefore, the correct answer is 12.5.

Answer:

At t = 2 minutes, remaining quantity of the radioactive element is 12.5 mg.

Step-by-step explanation:

To get the answer of this question we will solve this further with the help of the equation [tex]A_{t}=A_{0}e^{-kt}[/tex]

where k = decay constant

t = time for decay

[tex]A_{0}[/tex] = Initial quantity taken

From the graph attached we can say that 50 mg of a radioactive element remained half in 1 minute.

So the equation becomes

[tex]50=25e^{-k(1)}[/tex]

Now we take natural log on both the sides of the equation

ln50 = ln[25.[tex]e^{-k}[/tex]

3.912 = ln25 + [tex]ln(e^{-k})[/tex]

3.912 = 3.219 + (-k)lne

3.912 - 3.219 = -k [since lne = 1]

0.693 = -k

k = -0.693

Now we will calculate the remaining quantity of the element after 2 minutes

[tex]A_{t}=50.e^{-(0.693)(2)}[/tex]

              = [tex]50.e^{-1.386}[/tex]

              = [tex]\frac{50}{e^{1.386}}[/tex]

              = [tex]\frac{50}{3.9988}[/tex]

              = 12.50 mg

Now we confirm this value from the graph.

At t = 2 minutes, remaining quantity of the radioactive element is 12.5 mg.

Answer:

D.64

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Givens

A = 8 square meters.

B = 1/4 meter

h = ?

Formula

A = 1/2 B * h

Solution

8 = 1/2 1/4 * h     Combine

8 = 1/8 * h           Multiply by 8

8*8 = 1/8 * 8 * h

h =64 m

D answer

==============

I had to edit this to get it. Give the brainliest to the other responder.

ANSWER

The area of the floor is 696 square feet.

EXPLANATION

It was given that, the volume inside a rectangular storage room is 2,088 cubic feet.

The rectangular room is a rectangular prism.

The volume of a rectangular prism is

[tex]V = floor \: area \times height[/tex]

The height of the room is 3 ft.

This implies that,

[tex]2088= floor \: area \times3[/tex]

Divide both sides by 3.

[tex] \frac{2088}{3} = floor \: area [/tex]

[tex]floor \: area = 696 {ft}^{2} [/tex]

The area of the floor is 696 square feet.

Answer:

The probability that exactly one switch is good is

[tex]P(x) =0.0392[/tex]

Step-by-step explanation:

The probability that a switch is defective is:

[tex]P(D) = \frac{2}{100} =0.02[/tex]

The probability that a switch is not defective is

[tex]P(D') = 1-P(D)=0.98[/tex]

Therefore, if two switches are selected, the probability that exactly 1 is good is:

[tex]P(1=1)=P (D) P (D ') + P (D') P (D)[/tex]

[tex]P(x)=(0.02)(0.98) + (0.98)(0.02)[/tex]

[tex]P(x) =0.0392[/tex]

Answer:

P (exactly one good switch) = 0.0392

Step-by-step explanation:

We know that 2% of all switches are defective.

P (defective) = [tex]\frac{2}{100} =0.02[/tex]

So P (not defective) = 1 - P (defective) = [tex]1-0.02=0.98[/tex]

Now we have to find the probability of one good switch out of 2 that are used in a device.

P (exactly one good switch) = [tex] (0.02 \times 0.95) + (0.02 \times 0.95) [/tex] = 0.0392

Answer:

24 π

Step-by-step explanation:

First step is to determine the radius of the base.  We have the area, so we can easily determine the radius.  The base is a circle, and the area of a circle is given by A = π * r² , so r² = A / π

r² = (36 π) / π = 36

So, r = 6

The lateral surface of a cylinder is given by the following:

L = 2* π * r * 2

Now that we have r, we can easily calculate it:

L = 2 * π * 6 * 2 = 24π, second choice listed

ANSWER

Step 3

EXPLANATION

The given polynomial expression is:

[tex]2 {p}^{2} - 3p - 7 - (3 {p}^{2} + p - 5)[/tex]

Fatau correctly expanded the parenthesis in the first step.

[tex]2 {p}^{2} - 3p - 7 - 3 {p}^{2} - p + 5[/tex]

Fatau also correctly grouped the like terms to obtain:

[tex](2- 3) {p}^{2} + (- 3 - 1)p + (- 7 + 5)[/tex]

Fatau committed a mistake at the third step.

Instead of obtaining,

[tex] - {p}^{2} - 4p - 2[/tex]

He mistakenly got:

[tex]{p}^{2} - 2p +2[/tex]

Answer:

[tex]y=-\frac{1}{2}+7\frac{1}{2}[/tex]

Step-by-step explanation:

Let

x ----> the time in hours

y ----> the height of the candle in inches

we have the points

(1,7) and (4,5.5)

step 1

Find the slope m

[tex]m=(5.5-7)/(4-1)\\ m=-1.5/3=-0.5[/tex]

step 2

Find the equation of the line into slope point form

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=-0.5\\ (x1,y1)=(1,7)[/tex]

substitute

[tex]y-7=-0.5(x-1)\\ y-7=-0.5x+0.5+7[/tex]

[tex]y=-0.5+7.5[/tex]

[tex]y=-\frac{1}{2}+7\frac{1}{2}[/tex]

Answer:

7

Step-by-step explanation:

The full solution is:  

1 |...1.....3.....-5.....7  

.............-1....-2......7  

__________________  

.......1.....2.....-7.....14  

So the answer is 7

The question doesn't provide enough information to answer it properly, as it doesn't specify the polynomial or the divisor necessary for synthetic division. Synthetic division involves dividing a polynomial by a linear divisor, but without the set polynomial and divisor, the number that would belong in the place of the question mark can't be determined.

Unfortunately, the information provided doesn't clearly indicate the format or context of a synthetic division problem. Synthetic division typically involves dividing a polynomial by a linear divisor. The elements of the polynomials are numbers, specifically the coefficients of the polynomial terms. The repetition in your question about various Car X, Car Y and dots at various hash marks appears to be irrelevant data as it does not correlate with the synthetic division problem.

However, to apply synthetic division, we would need a specific polynomial to carry out the process. In synthetic division, a box is drawn, the coefficients of the polynomial are written in that box, and then the divisor is placed outside the box. From there, the numbers inside the box are manipulated, in a step-by-step manner, based on the divisor. The numbers derived from this process are the coefficients of the answer. Without this specific data, we cannot accurately determine what number belongs in the place of the question mark.

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