Jeanette wants to tile the floor of a room in her house. The square tiles measure 3/4 ft on each side. The room is 10 ft wide.
a. Write an inequality to describe how many tiles are needed to make one row of tiles across the width of the room.
b. Solve the inequality.
c. How many tiles should Jeanette buy to form one row?

Answers

Answer 1

Answer:

a.  The inequality will be:  [tex]\frac{3}{4}x\geq 10[/tex]

b.  Solving the inequality:  [tex]x\geq 13.333...[/tex]

c.  Jeanette should buy 14 tiles to form one row.

Step-by-step explanation:

Suppose, the number of tiles needed to make one row [tex]=x[/tex]

Each square tiles measure [tex]\frac{3}{4}[/tex] ft on each side.

So, the total length of [tex]x[/tex] number of tiles [tex]=\frac{3}{4}x\ ft[/tex]

Given that, the room is 10 ft wide.

So, the inequality will be:  [tex]\frac{3}{4}x\geq 10[/tex]

Solving the above inequality.....

[tex]\frac{3}{4}x\geq 10\\ \\ 3x\geq 4(10)\\ \\ 3x\geq 40\\ \\ x\geq \frac{40}{3}\\ \\ x\geq 13.333...\\ \\ x\approx 14[/tex]

So, Jeanette should buy 14 tiles to form one row.


Related Questions

What are the real-number solutions of the equation 2x5 = 12x3 - 16x ?

Answers

10=36-16x
Subtract 36 on both sides of equation to get: -26= -16x
Divide by -16 on both sides of equation.

Answer should be: x= 26/16

what are the steps to solve
7x − 1/2 (8x + 4) = 6

Answers

We simplify the equation to the form, which is simple to understand
7x-1/2(8x+4)=6
Simplifying:
7x-0.5*(8x+4)=6
Reorder the terms 
7x+(-4x-2)=6
Remove unnecessary parentheses
+7x-4x-2=+6
We move all terms containing x to the left and all other terms to the right.
+7x-4x=+6+2
We simplify left and right side of the equation.
+3x=+8
We divide both sides of the equation by 3 to get x.
x=2.66666666667
1) distribute -1/2
7x - 4x -2 = 6
2) combine like terms
3x - 2 = 6
3) use the addition properties of equality
3x = 8
4) use the division properties of equality
x = 8/3

An arc of length 8 in. is intersected by a central angle in a circle with a radius of 3 in. What is the measure of the angle? Round your answer to the nearest tenth.

Answers

Radius r = 3inches
Arc A = 8 inches

We need formula that connects lenght of arc with central angle. That one is fallowing one:

A = 2*r*pi*α/360   where α is central angle. we can see that if α=360, A = 2*r*pi which is exactly the formula for parimeter of circle.

Further more we can express 360 in radians which is 2* pi and get

A = r*α as simpler formula

α = A/r = 8/3 = 2.66666667 ≈ 2.7

Alex wants to have $3000 in his bank account after 4 years. If the account earns 6% interest compounded 2 times per year, how much should he put in?

Answers

A=p(1+i/k)^kn,,3000=p(1+0.06/2)^2*4==2,368.23

Find the weighted average of these values

Value Weight
5.00 75.0 %
6.00 15.0 %
7.00 10.0 % ...?

Answers

Final answer:

To find the weighted average of given values, multiply each value by its weight, sum the results, yielding a weighted average of 5.35.

Explanation:

The question is asking to find the weighted average of given values with their corresponding weights. To calculate a weighted average, each value is multiplied by its weight, and then the results are summed up. The formula used is \(Weighted\ Average = (Value_1 \times Weight_1) + (Value_2 \times Weight_2) + \cdots + (Value_n \times Weight_n)\).

Applying the given values and weights:

\(5.00 \times 75.0\% = 3.75\)\(6.00 \times 15.0\% = 0.90\)\(7.00 \times 10.0\% = 0.70\)

Summing the results: \(3.75 + 0.90 + 0.70 = 5.35\).

Therefore, the weighted average of these values is 5.35.

The weighted average of the item is 5.35 weight units

The steps used to find the weighted average are as follows;

The weighted average is a technique or method used to find the average of a list of items, where the contribution of each item to the sum of the measurements are different or proportional to a specified measurement of the quantity

The mass and percentage by weight of the items indicates that we get;

The contribution of the item with a value of 5.00 is; 5 × 75% = 3.75

The contribution of the item with a value of 6.00 is; 6 × 15% = 0.9

The contribution of the item with a value of 7 is; 7 × 10% = 0.7

The weighted average of the substance is therefore; 3.75 + 0.9 + 0.7 = 5.35

Choose the function that is a “parent function”.

ƒ(x) = x + 3
ƒ(x) = (x - 3)2
ƒ(x) =
ƒ(x) = |x - 3|

Answers

I believe it is F(x)=x+3

Answer:

F(x)=x+3

Step-by-step explanation:

Which answer describes the type of sequence?

−99, −88, −66, −55, ...

A. arithmetic

B. neither arithmetic nor geometric

C. geometric

Answers

Here, Geometric ratio, r = -88/-99 or -66/-88 which is 8/9 or 6/8. As they are not equal, it is not a geometric.

Now, Arithmetic difference, d = -88-(-99) or -66-(-88) which is 11 or 22. As they are not equal, it is not a Arithmetic.

So, it's neither an Arithmetic nor a Geometric.

Option B is your answer!

Hope this helps!

Answer:

b

Step-by-step explanation:

took the test thx to the other answer thought it deserved 5 starts good luck

. If you saved $2.00 on january 1, $4.00 on february 1, $8.00 on march 1, $16.00 on april 1, and so on. how much money would you save in one year?

Answers

$4096 

$2.00^12 

12 months in a year, doubles every month

By following a pattern of doubling the saved amount each month, the total amount saved in one year would be approximately $8190.00.

Use the concept of geometric sequence defined as:

A unique kind of sequence called a geometric sequence has a constant ratio between every two succeeding words. This ratio is regarded as one of the geometric sequence's frequent ratios.

Amount saved on January 1: $2.00

Amount saved on February 1: $4.00

Amount saved on March 1: $8.00

Continuing the pattern, the saved amount on April 1 would be $16.00

Since it can be seen that,

The pattern is that the saved amount doubles each month.

Therefore,

To calculate the total amount saved in one year,

Sum up the amounts for each month.

In this case, it would be

$2.00 + $4.00 + $8.00 + $16.00 + $32.00 + $64.00 + $128.00 + $256.00 + $512.00 + $1024.00 + $2048.00 + $4096.00 = $8190

Hence,

The saved amount in one year is $8190

To learn more about sequence visit:

brainly.com/question/12373434

#SPJ5

Which statements are true about the ordered pair (−1,−4) and the system of equations?
x−y=3
7x−y=−3
Select each correct answer.

When ​ (−1,−4)) ​ is substituted into the second equation, the equation is true.

When ​ (−1,−4) ​ is substituted into the first equation, the equation is true.

When ​ (−1,−4) ​ is substituted into the second equation, the equation is false.

The ordered pair ​ (−1,−4) ​ is not a solution to the system of linear equations.

The ordered pair ​ (−1,−4) ​ is a solution to the system of linear equations.

When ​ (−1,−4) ​ is substituted into the first equation, the equation is false.

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the answers:

When ​ (−1,−4) ​ is substituted into the first equation, the equation is true.

The ordered pair ​ (−1,−4) ​ is a solution to the system of linear equations.

When ​ (−1,−4) ​ is substituted into the second equation, the equation is false.

how many sides does a regular polygon have if each exterior angle measures 30 degree

Answers

As the exterior angles always add up to 360, you can find the number of sides by dividing 360 by the measure of your exterior angle, 30. This gives you 360/30=12, meaning your polygon has 12 sides.

Use the three steps to solve the problem.

A "Local" train leaves a station and runs at an average rate of 35 mph. An hour and a half later an "Express" train leaves the station and travels at an average rate of 56 mph on a parallel track. How many hours after it starts will the Express overtake the Local?

Answers

The rate that train 1 is going plus the distance:

35x+52.5

The rate that train 2 is going plus the distance:

56x+0

X=number of hours

Solve for X to find where the 2 trains have gone the same distance:

35x+52.5=56x
52.5=21x
2.5=x

The express train will overtake the local train 2 and a half hours after it leaves

Answer:

It will take 2.5 hours

Step-by-step explanation:

one zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

Answers

Answer:

Answer:

x=-2, x=1, x=3

Step-by-step explanation:

Step-by-step explanation:

one zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

the following polynomials have the function  

f(x)=x^3-2x^2-5x+6

note 2 is not a zero of the function

but x=-2

to find the other zeros we say  

f(x)/x+2=x^3-2x^2-5x+6/(x+2)

we have the quadratic equation  

x^2-4x+3

factorizing the above, using factorization method

(x^2-3x-x+3)

(x^2-3x)(-x+3)

x(x-3)-1(x-3)

(x-1)(x-3)

x=1, x=3

the zeros of the function are  

x=-2, x=1,x=3

substituting the values back into the function

we have zero

f(1)=1^3-2(1)^2-5(1)+6

F(1)=0

Answer:

-1 and -3 are the other zeroes

39% of 50 is what number

Answers

Convert percent into a decimal by moving the percent sign two places to the left.

39% => 0.39

'Of' in math means multiply.

0.39 * 50 = 19.5
you do decimal multipliers
50 x 0.39
= 19.5

hope this helps you

The period of f(x)=cos (2pi/3)x is ...?

Answers

Well lets see. if you're  being specific about the rigor,  then the period means that cos(2Π÷3(x+α))=cos(2Π÷3(x))Therefore this gives 2π÷3α=2πso α = 3.
Hope this can help you



Raisins sell for $3.50 per pound, and granola sells for $5.90 per pound. Terri bought some raisins and some granola. The total weight was 2.1 pounds and cost $8.79.


How many pounds of raisins and how many pounds of granola did Terri buy?

A.
0.6 pounds of raisins; 1.5 pounds of granola

B.
1.1 pounds of raisins; 1 pound of granola

C.
1 pound of raisins; 1.1 pounds of granola

D.
1.5 pounds of raisins; 0.6 pounds of granola

Answers

The answer is D. 1.5 pounds of raisins; 0.6 pounds of granola

r - the weight of raisins
g - the weight of granola
The total weight was 2.1 pounds: r + g = 2.1

Raisins sell for $3.50 per pound: 3.50r
Granola sells for $5.90 per pound: 5.90g
The total cost was $8.79: 3.50r + 5.90g = 8.79

r + g = 2.1
3.50r + 5.90g = 8.79
________
r = 2.1 - g
3.50r + 5.90g = 8.79
________
3.50(2.1 - g) + 5.90g = 8.79
7.35 - 3.50g + 5.90g = 8.79
7.35 + 2.4g = 8.79
2.4g = 8.79 - 7.35
2.4g = 1.44
g = 1.44 : 2.4
g = 0.6 pounds

r = 2.1 - g = 2.1 - 0.6
r = 1.5 pounds

If f(x) = 3a|2x – 4| – ax, where a is some constant, find f ′(2).

Answers

|x| is x if x>0
|x| is -x if x<0
|x| is 0 if x=0
so
(|x|)'=1 when x>0
so
(|x|)'=-1 when x<0

(|2x-4|)'=2 when x>2
and
(|2x-4|)'=-2 when x<2

Therefore the left derivative doesn't equal the right derivative as x approaches 2.

Answer:

so would the answer be DNE?

Step-by-step explanation:


solve for x... 4(-2x+3)=-5x

Answers

-8x+12=-5x,,12=8x-5x,,12=3x ,,x=4

Two Tibetan monks are having a race along a straight path. They both start at the same time, and the race ends in a tie. Prove that at some time during the race the two monks have exactly the same speed.

Answers

This is so provided that the velocity changes continuously in which case we can apply the mean value theorem. 
Velocity (v) is the derivative of displacement (x) : 
v = dx/dt 
Monk 1 arrives after a time t* and Monk 2 too. 
Name v1(t) and v2(t) their respective velocities throughout the trajectory. 
Then we know that both average velocities were equal : 
avg1 = avg2 
and avg = integral ( v(t) , t:0->t*) / t* 
so 
integral (v1(t), t:0->t*) = integral (v2(t), t:0->t*) 
which is the same of saying that the covered distances after t* seconds are the same 
=> integral (v1(t) - v2(t) , t:0->t*) = 0 
Thus, name v#(t) = v1(t) - v2(t) , then we obtain 
=> integral ( v#(t) , t:0->t*) = 0 
Name the analytical integral of v#(t) = V(t) , then we have 
=> V(t*) - V(0) = 0 
=> V(t*) = V(0) 
So there exist a c in [0, t*] so that 
V'(c) = (V(t*) - V(0)) / (t* - 0) (mean value theorem) 
We know that V(0) = V(t*) = 0 (covered distances equal at the start and finish), so we get 
V'(c) = v#(c) = v1(c) - v2(c) = 0 
=> v1(c) = v2(c) 
So there exist a point c in [0, t*] so that the velocity of monk 1 equals that of monk 2. 

The elimination method is useful when you can eliminate one of the variable terms from an equation by adding or subtracting another equation. True or False

Answers

The answer is True. Hope this helps :)

What is the slope of the line represented by the equation y+3=-4(x-5)
A. -4
B. 3
C. -3
D. 4

Answers

Correct choice is, D. 4
y + 3 = -4(x - 5) is in point slope form.
Point slope form (attachment)

In slope intercept form, or y = mx + b, we know that m represents the slope and b represents the y-intercept.

In the equation you mentioned in your question, -4 is the slope.
The ordered pair would be (5, -3).

The answer is A. -4.

Identify the like terms in the expression -4x2-2x+8+6x-9

Answers

the like terms would be (-2x) and 6x, the other one would be 8 and (-9)

A farmer grows two types of grain in his fields. He has a seed budget of $15,000.00 and has spent $5,800.00 to plant wheat seed so far. If barley seed costs $53.00 per acre to plant, what is the maximum number of acres of barley the farmer can plant and still be under budget?
A.283 acres
B.109 acres
C.173 acres
D.174 acres

Answers

The answer to the question is C.173

Answer:

The answer is option D.

Step-by-step explanation:

Total seed budget is = $15000

Amount paid for wheat seeds = $5800

So, amount left is = [tex]15000-5800=9200[/tex]

Now, lets suppose the number of acre of land to be planted by barley seeds be = x

Barley seed costs = $53 per acre.

This means for 53x acres $9200 will be used.

Therefore, [tex]x=\frac{9200}{53}[/tex] = 173.58 acres ≈ 174 acres

What value of x is in the solution set of 3(x – 4) ≥ 5x + 2?

Answers

3(x-4)>5x+2

3x-12>5x+2

Subtract 2

3x -10 > 5x

Subtract 3x

2x -10

divide 2

x=-5

Answer:

Step-by-step explanation:

B) -5

What is -5/8 times -8 plus 10

Answers

The answer will be 15..

Answer:

The answer is 15.

Please help! Find the value of C such that each expression is a perfect-square trinomial.

p^2-30p+c


k^2-5k+c

Answers

for ax^2+bx+c
when a=1
take 1/2 of b and square it
that is what c should be ideally

p^2-30p=c
-30/2=-15
(-15)^2=225
c=225
(p-15)^2 is factored form


k^2-5k+c
-5/2
(-5/2)^2=25/4
c=25/4
factored form is (x-5/2)^2

Sam Monte deposits $21,500 into Legal Bank which pays 6 percent interest that is compounded semiannually. What will Sam have in his account at the end of 6 years?

Answers

=P(1+r)twhere P is the principal, r is the rate (over the compounding period, expressed as a decimal), and t is the number of periods to compound over.

its A=P(1+/n)^nt

Santa has lots of mixed up socks in his sack! If he has 6 green socks, 4 gold socks, 8 black socks and 2 red socks, what is the minimum he needs to pull out of his sack to get a matching pair?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Based on the problem above, the minimum he needs to pull out of his sack to get a matching pair is 5

Simplify equation -2b^3 +2^3

Answers

The answer should be  -2b^{3}+8
Raise 2 to the power of 3 to get 8.−2b3+8 Hope this will help ;-;

The sum of two consecutive even integers is 234. What is the larger integer?

A. 114
B. 116
C. 118
D. 124

Answers

If the two integers are even and consecutive, then the only two numbers you could have that add to 234 under those constraints is 116 and 118. Since 118 is the bigger of the two, c is the answer.

Answer: 118. I took the test

Step-by-step explanation:

help me with algebra 2

Answers

What is it that you need help in?

Final answer:

Algebra 2 involves solving simultaneous equations through a multi-step process, simplifying where possible and carefully verifying solutions to ensure reasonableness.

Explanation:

Algebra 2, typically taught in high school, involves solving simultaneous equations for unknown values. The process includes several algebraic steps, where students are advised to eliminate terms where possible to simplify the algebra and carefully check their work at each step. After finding the potential solutions, it's crucial to check the answers to ensure they are reasonable within the context of the problem. This systematic approach to solving algebraic problems, such as equations in one variable, is a methodical and critical part of Algebra 2's curriculum.

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