Jay J runs of a 1/3 mile in 4 minutes. A. If Jay J continues at the same speed, how long will it take her to run one mile?

Answer:

  Not justified

Step-by-step explanation:

ADA requirements are for a slope of 1 in 12 or less, an 8.3% grade, or an angle of 4.8° (actually, 4.764° when rounded to 3 decimal places). The ramp angle found by the assessor is compliant.

  The tenant complaint does not seem justified.

Answer:

Answer: You could have an infinite amount of triangles with these measurements.

Unless, you are missing something in the problem, there is not enough information that would narrow it down to a single triangle. Angle A is fixed and the height is fixed. However, Angle B and C could be anything as long as they formed a triangle and had side a of 15 in between them.

Answer:

j

Step-by-step explanation:

i know this isnt anything that has to do with this question but i was wondering if you had the answers to the precal "lets dance! portfolio" i couldnt contact you through messaging so this is the only way lol i hope you see this

Answer:

n=11 or n=-3

Step-by-step explanation:

Consider the quadratic equation [tex]n^2-8n-27=6.[/tex]

First, remind the formula

[tex](a-b)^2=a^2-2ab+b^2[/tex]

To complete the square, note that

[tex]8n=2\cdot n\cdot 4[/tex]

Hence, we need [tex]+4^2[/tex]

Add 16 to both sides of equation:

[tex]n^2-8n+16-27=6+16\\ \\(n-4)^2-27=22\\ \\(n-4)^2=49\\ \\n-4=7\text{ or }n-4=-7\\ \\n=11\text{ or }n=-3[/tex]

Answer:

  4.95 in

Step-by-step explanation:

The area is the same, no matter how you find it.

  (11 in)h = (9.9 in)(5.5 in) . . . . . area = base·height

  h = (9.9·5.5/11) in = 4.95 in . . . . divide by 11 in

43% = 'Piano'

28% = 'Guitar'

15% = 'Harmonica'

12% = 'Drums'

2% = ...Other Instruments

- '2' Does seems as to be the smallest but it could be a trick.

- '43' Is the largest percentage out of the whole group.

- '100' Is what you get when you add all of the percentages together.

- And if you try to evaluate the percentages together in either way it'll end up to be '0.00004334' so that executes '250' and '150' from out of the question.

I'm not sure exactly what the actual answer could be but I'm assuming since it said "What is the smallest number of people required for the sample to meet the conditions for performing inference" Then my assumption is '2'.

250

Remember there are 2 conditions to perform a goodness of fit chi-test:

Simple random sample: The data must come from a random sample or a randomized experiment.

Expected counts: All expected counts are at least five. You must state the expected counts.

To explain expected counts a bit better, imagine I surveyed 100 people about their ice cream preferences. Before beginning it is believed that 50% like chocolate, 47% like vanilla, and 3% like strawberry.

That means our expected counts are:

100(.50) = 50

100(.47) = 47

100(.03) = 3

This is a problem, because 3 < 5 and so we can not perform a goodness of fit chi-test.

So how do you find the minimum sample size? Use this formula:

sample size (n) * smallest proportion (p) = 5

In the context of ice cream:

n*.03 = 5

n = 5 / .03

n = 167 (because you can't interview 2/3s of a person)

In the context of the problem:

n* .02 = 5

n = 5 / 0.02

n = 250

This means we need to sample at least 250 people to meet our expected count condition.

Answer:

Step-by-step explanation:

Answer:c

Step-by-step explanation:

3m. The wall of the building is 3m far from the base of the ladder.

The key to solve this problem is use trigonometric ratios.

The cosine of the angle is the adjacent leg divided by the hypotenuse.

From the image attached we can modeling the problem as a right triangle, where we can see that the adjacent leg is the unknown, hypotenuse is 6m (long of the ladder), and the ladder make an angle of 60°  leans againts the building's wall, and x is the long of the adjacent leg. To calculate how far is the base of the ladder from the wall:

Cos 60° = adjacent leg/hypotenuse

adjacent leg = cos 60° x hypotenuse

x = cos 60° (6m) = (0.5)(6m) = 3m

13:5 is the ratio of speed to skid mark

Answer: 2

Step-by-step explanation:

The reason is for each meal to have one thing of food for every lunch special. So then you would go one by one, theres 2 appetizers so that means it'll only reach to 2 lunches. Then theres 5 main courses and you seperate those having 2 of the 5 with the appetizers. Onto the desserts, there are 5 desserts and 2 out of the 5 you put it together with the lunches that have a main course and appetizers. Next, there are 3 drinks and 2 of those 3 you would put it with the 2 meals that has an appetizer,main course,dessert, and now a drink. In the end, Its only possible that there are 2 lunch special being able to be made. With all the food

Answer: 150

Step-by-step explanation:

We know that a complete lunch meal consist of an appetizer , a main course , a dessert and a drink.

Given: The number of appetizers=2

The number of main courses=5

The number of desserts=5

The number of drinks=3

Therefore, the number of possible lunch meals will be :

[tex]2\times5\times5\times3=150[/tex]

Hence, there are 150 lunch meals are possible.

Answer:

2

Step-by-step explanation:

The only factors for this even numbers is itself and one. Other even numbers are composite because they can be divided by 2, but this number is 2 so it can only be divided by two numbers.

-Hello There-

If the probabilities are independent, the probability that a left-handed person will bring a glove is ...

 0.08×0.12 = 0.0096 ≈ 0.01

Hope This Helped!

Have A Great Day!

Stay Safe,

TheBlueFox

the answer would be 0.1

Answer: OPTION A

Step-by-step explanation:

We need to remember that Product of powers property, which states that:

[tex](a^m)(a^n)=a^{(m+n)}[/tex]

Let's check the options:

A. For [tex]5^9*5^{\frac{9}{10}}*5^{\frac{6}{100}}*5^{\frac{9}{1000}}[/tex] you can  apply the property mentioned before. Then:

[tex]5^{(9+\frac{9}{10}+\frac{6}{100}+\frac{9}{1000})=5^{9.969}[/tex]

(It is the equivalent expression)

 B. Add the exponents:

 [tex]5^9*5^{(\frac{9}{10}+\frac{9}{10}+\frac{6}{1000})=5^{10.806}[/tex]

(It is not the equivalent expression)

C. For [tex]5^9*5^{\frac{96}{10}}*5^{\frac{9}{100}}}[/tex] you can  apply the property mentioned before. Then:

 [tex]5^{(9+\frac{96}{10}+\frac{9}{100})=5^{18.69}[/tex]

(It is not the equivalent expression)

D. We know that [tex]5^{9.969}=9,290,347.808[/tex] and we maje the addition indicated in this option, we get:

 [tex]5^9+5^{\frac{9}{10}}+6^{\frac{6}{100}}=1,953,130.37[/tex]

(It is not the equivalent expression)

Answer: A, i just took this test

Answer:

Step-by-step explanation:

Put the appropriate values of n in the formula and do the arithmetic.

  a(1) = 3·1 -7 = -4

  a(5) = 3·5 -7 = 8

The 1st and 5th terms are -4 and 8.

_____

The first few terms of the sequence are ...

  -4, -1, 2, 5, 8, 11, 14, ...

To find the sum of the 1st and 5th terms of the sequence defined by the function a(n) = 3n - 7, calculate each term using their respective n value and add the results together, resulting in a sum of 4.

When you are given the function a(n) = 3n - 7, which represents the value of the nth term in a sequence, the sum of the 1st and 5th terms of the sequence can be calculated by plugging in the values for n into the function for each term and adding the results.

For the 1st term (n = 1):

For the 5th term (n = 5):

The sum of the 1st and 5th terms is then:

-4 + 8 = 4

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70 shirts per day

We simply need to find how many shirts would have been produced on the 8th day. This can be done by multiplying the number of extra shirts produced per day by the number of days extra shirts were produced. Since one day was skipped due to finishing early, there were 7 days of producing extra shirts.

7 times 10 equals 70. This means that 70 shirts would have been produced on the 8th day, which means the factory was planning on producing 70 shirts for every other day as well.

Answer:

[tex]\theta=101.3\degree[/tex] to the nearest tenth

Step-by-step explanation:

The given vectors are;

u = – 3i + 3j and v = 3i + 2j

We use the dot product to find the angle between the two vectors.

[tex]u\bullet v=|u| |v|\cos \theta[/tex]

[tex](-3i+3j)\bullet (3i+2j)=|-3i+3j| |3i+3j|\cos \theta[/tex]

[tex](-3i+3j)\bullet (3i+2j)=\sqrt{(-3)^2+3^2} \sqrt{3^2+2^2}\cos \theta[/tex]

[tex]-9+6=3\sqrt{2} \sqrt{13}\cos \theta[/tex]

[tex]-3=3\sqrt{2} \sqrt{13}\cos \theta[/tex]

[tex]-1=\sqrt{26} \cos \theta[/tex]

[tex]-\frac{1}{\sqrt{26}}= \cos \theta[/tex]

[tex]\cos^{-1}(-\frac{1}{\sqrt{26}})= \theta[/tex]

[tex]\theta=101.3\degree[/tex]

Answer:

  {x| x≤ 1/2 or x ≥ 3/4}

Step-by-step explanation:

The values of x that make the factors zero are 3/4 and 1/2. The product of these factors will be positive when both factors are negative (for x < 1/2) or when both factors are positive (x > 3/4). The matching answer selection is the third one.

Answer:

[tex]661.4\ rpm[/tex]

Step-by-step explanation:

we know that

1 mile=63,360 inches

step 1

Find the circumference of the wheels

[tex]C=2\pi r[/tex]

we have

[tex]r=30/2=15\ in[/tex] -----> the radius is half the diameter

substitute

[tex]C=2\pi(15)[/tex]

[tex]C=30\pi\ in[/tex]

assume

[tex]\pi =3.14[/tex]

[tex]C=30(3.14)=94.2\ in[/tex]

Remember that    

The circumference of the wheels represent one revolution

Convert 59 miles per hour to inches per minute

[tex]59\ mi/h=59*63,360/60=62,304\ in/min[/tex]

using proportion find the number of revolutions  

[tex]\frac{1}{94.2}\frac{rev}{in}=\frac{x}{62,304}\frac{rev}{in}\\ \\x=62,304/94.2\\ \\x=661.4\ rev[/tex]

therefore

substitute

[tex]62,304\ in/min=661.4\ rev/min=661.4\ rpm[/tex]

the angular velocity of the truck's wheels is approximately 661.03 rpm

We need to first convert 59 mph into in/h. For this we can use the conversion factor:

[tex]1\ mile = 63360\ in[/tex]

Thus, 59 mph in ft/h will be:

[tex]59 \times 63360 = 3738240\ in/h[/tex]

Now we need to convert this into in/min for which we can use the conversion factor:

[tex]1\ hour = 60\ minute[/tex]

So, on converting we get:

[tex]\frac{3738240}{60} = 62304\ in/min[/tex]

Radius of tire will be half of its diameter. Thus radius = 15 in

Circumference of tire can be calculated by using the formula:

[tex]circumference = 2 \pi r[/tex]

Putting in values we get:

[tex]Circumference = 2 \times \pi \times 15 \approx 94.25\ in[/tex]

To determine the number of rotations per minute we need to divide speed of tire by the circumference of tire as follows:

[tex]rpm = \frac{speed}{circumference}\\\\\\rpm = \frac{62304}{94.25} \approx 661.03\ rpm[/tex]

Therefore, the angular velocity of the truck's wheels is approximately 661.03 rpm

Answer:

t = 6: It takes 6 seconds for the object to hit the ground

Step-by-step explanation:

So, we need to find t when the height is 0. Since -5t² + 20t + 60 represents the height, that needs to equal 0.

Equation: -5t² + 20t + 60 = 0

Divide by -5: t² - 4t - 12 = 0

Find two numbers that add up to -4t and multiply to -12t²: -6t, 2t

Substitute: t² - 6t + 2t - 12 = 0

Factor: (t - 6)(t + 2) = 0

Answers: t = 6, t = -2

Since time can't be negative, t = 6.

To determine the time it takes for the object to hit the ground, the quadratic equation -5t^2 + 20t + 60 = 0 is solved, leading to the conclusion that it takes 6 seconds for the object to reach the ground.

The question asks, "How many seconds does it take for the object to hit the ground?" given the function f(t) = -5t2 + 20t + 60. To find when the object hits the ground, we need to determine when the height f(t) is equal to 0. This involves solving a quadratic equation.

Steps to Solve:

Set the equation equal to zero: -5t2 + 20t + 60 = 0.

Divide the entire equation by -5 to simplify: t2 - 4t - 12 = 0.

Use the quadratic formula: t = (-B ± √(B2 - 4AC)) / 2A, where A = 1, B = -4, and C = -12.

Calculate the discriminant: √((-4)2 - 4(1)(-12)) = √(16 + 48) = √64 = 8.

Substitute values into the formula: t = (4 ± 8) / 2, yielding t = 6 seconds or t = -2 seconds.

Dismiss the negative value, as time cannot be negative, leaving t = 6 seconds as the solution.

Therefore, it takes the object 6 seconds to hit the ground after it is launched.

Answer:

3x (3x-2)(4x+1)

Step-by-step explanation:

36x^3 – 15x^2 – 6x

factor out the "3x"

3x (12x^2-5x-2)

3x(3x - 2) (4x + 1)

= 9x^2 - 6x (4x + 1)

= 36x^3 + 9x^2 + -  24x^2 - 6x

= 36x^3 - 15x^2 - 6x

hope this helps!

The product of prime polynomials is equivalent to Option (A)  [tex]3x(3x - 2)(4x + 1)[/tex].

In mathematics, an irreducible polynomial (or prime polynomial) is approximately a non-constant polynomial that cannot be factored into the product of two non-constant polynomials. The expression can be expressed in product of prime polynomial by converting it into the factored form.

Given polynomial expression = [tex]36x^{3} - 15x^{2} - 6x[/tex]

Solving the polynomial expression in factored form -

⇒ [tex]3x(12x^{2} - 5x - 2)[/tex]

⇒ [tex]3x(12x^{2} - 8x + 3x - 2)[/tex]

⇒ [tex]3x[4x(3x - 2) + 1(3x - 2)][/tex]

⇒ [tex]3x(3x - 2)(4x + 1)[/tex]

Therefore the product of prime polynomial is [tex]3x(3x - 2)(4x + 1)[/tex]

To learn more about product of prime polynomial, refer -

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The answer is V≈4.01×105

I believe the correct answer to this question is 42 and 288. If im not wrong.

Answer:

the answer is 42 and 228

Step-by-step explanation:

165x165=27,225 and 123x123=15,129

27,225-15,129=12,096

if you multiply 4x288 you get 12,096 which is your answer from before.

Answer: D.

Step-by-step explanation:

The answer is 20 hamburgers and 25 hot dogs.

20(.5)+25(.25)<16.5

         10+6.25<16.5

             16.25<16.5

The budget is $16.50 and $16.25 is $.50 less therefore making it a possible option for Enrique.

With his budget of $16.50, Enrique can afford to buy the fourth option, 20 hamburgers and 25 hot dogs, which totals $16.25.

Let's calculate the cost of each option and see which ones Enrique can afford with his $16.50:

Looking at these calculations, we can see that Enrique could only afford to buy the fourth option, 20 hamburgers and 25 hot dogs, with his $16.50 as that totals $16.25, which is within his budget.

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To increase equilibrium price while lowering equilibrium quantity, the supply curve needs to be shifted to the left.

To increase equilibrium price while lowering equilibrium quantity in a supply and demand graph for a new gaming system, we need to shift the supply curve to the left. This can be done by adding a new supply curve, Supply 2, to the left of the original supply curve, Supply 1. Therefore, the correct answer is option C: Add Supply 2 to the left of Supply 1.

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Answer:

See Explanation

Step-by-step explanation:

To write an equivalent expression, we can combine like terms. So m +7m is 8 and we get 6(8m+2).

Here are a few others:

48m+12

6(m+m+m+m+m+m+m+m+2)

3(16m+4)

6m+12+42m

6m+6m+6m+6m+6m+6m+6m+6m+2

and the list goes on...

[tex]\text{Hey there!}[/tex]

[tex]\text{In order for you to solve this equation, you need to DISTRIBUTE}[/tex]

[tex]\text{Formula: a(b + c) = ab + ac  / if this equation: a(b + c + d) = ab + ac + ad}[/tex]

[tex]\text{6(m + 2 + m)}[/tex]

[tex]\text{6(m) = 6m}[/tex]

[tex]\text{6(2) = 12}[/tex]

[tex]\text{6(7m) = 42m}[/tex]

[tex]\text{Next, combine your like terms}\downarrow \\ \text{6m + 42m}\\ \text{The 12 stays the same because they AREN'T any like terms to compare it with}[/tex]

[tex]\text{6m + 42m = 48m}[/tex]

[tex]\text{12 = 12}[/tex]

[tex]\boxed{\boxed{\text{Answer: 48m + 12}}}\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{LoveYourselfFirst:)}[/tex]

Answer:

So for every ounce of granola she uses a quarter ounces of raisins so a quarter of 24 is 6

Answer:6

Step-by-step explanation:

Answer:

[tex]\sqrt[3]{-0.064}=-0.4[/tex]

Step-by-step explanation:

An on-line calculator can do this if your own doesn't.

For a cube root, you may have to use the exponentiation function with an exponent of 1/3. Usually, that fraction will need to be put in parentheses. (See the second attachment for the result from a TI-84 calculator.)

The order of the sides of the triangle is bc>ab>ac as per the rule that side opposite to the larger angle is larger

According to the rule that the side opposite to the larger angle is larger. The order of the sides of the triangle is bc>ab>ac .

Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side.

Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,

Then, if these three values satisfy the relation:

[tex]a < b +c\\b < a + c\\c < a + b[/tex]

Then they are for sure the side length of a triangle.

In scalene triangle ABC, m∠b=45° and m∠c=55°.

The order of the sides of the triangle is bc>ab>ac according to the rule that the side opposite to the larger angle is larger.

Learn more about the triangle inequality theorem here:

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Answer:

x = 5/(10 - a - b)

Step-by-step explanation:

Solve for x:

4 + 3 x - a x = 9 - 7 x + b x

Collect in terms of x:

x (3 - a) + 4 = 9 - 7 x + b x

Collect in terms of x:

x (3 - a) + 4 = x (b - 7) + 9

Subtract (b - 7) x + 4 from both sides:

x (10 - a - b) = 5

Divide both sides by 10 - a - b:

Answer:  x = 5/(10 - a - b)

Answer:

S = 13 - x

T = (18 + x) / 2

Step-by-step explanation:

S = 18

T= 18

Sue gives away x, so subtract it from 18. But Tony gets x, so add it to 18 in his expression.

S = 18 - x

T= 18 + x

Sue eats 5 so subtract 5 from her expression. Tony eats half, so divide his expression by 2.

S = 18 - x - 5

T = 18 + x / 2

Simplify 18-5.

S = 13 - x

T = (18 + x) / 2

Answer:

The radius of the semicircle is 4 cm

Step-by-step explanation:

The diameter of the semicircle is 8 cm

The radius is 1/2 of the diameter

1/2 *8 = 4 cm

The radius of the semicircle is 4 cm

[tex]\text{Hey there!}[/tex]

[tex]\text{In order for you to find the radius of the circle (in this equation you would)}[/tex] [tex]\text{have to multiply one half from the number 8}[/tex]

[tex]\frac{1}{2}\times8=?\\ \frac{1}{2}\times\frac{8}{1} \\ \\1\times8=8\\2\times1=2\\\\8\div2=4[/tex]

[tex]\boxed{\boxed{\text{Answer: 04 cm}}}\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{LoveYourselfFirst:)}[/tex]