Answer: Option A
[tex]h(x) = -0.01 (x-150) (x + 4)[/tex]
Step-by-step explanation:
The javelin will have reached its maximum horizontal distance when it touches the ground.
Then the maximum horizontal distance occurs when the height h (x) is equal to zero.
So we must equal h(x) to zero and solve the equation for x.
Therefore the form that is most useful to determine the horizontal distance that the javelin covers is the one that is factored. Because it allows us to find the zeros of the quadratic function more easily
[tex]h(x) = -0.01 (x-150) (x + 4) = 0[/tex]
[tex]-0.01 (x-150) (x + 4) = 0[/tex]
The equation is equal to zero when [tex]x = 150[/tex] or when [tex]x = -4[/tex]
Therefore the solution is [tex]x = 150[/tex].
The horizontal distance that covers the javelin is 150 feet
Answer:
The answer is A
Step-by-step explanation:
I am 100% sure cuz I just did the test:)
Need help with math question
Answer:
1.4%
Step-by-step explanation:
You can only include 7 and 8 in the answer because it didn't include 6 in the question. add the frequency for both of those sizes (14) and divide by the total (1000) to get the probability. multiply by 100 to get answer as a percent. 1.4%
Answer:
1%
Step-by-step explanation:
We are given the results of survey of one thousand families to determine the distribution of families by their size.
We are to find the probability (in percent) that a given family has more than 6 people.
Frequency of people with more than 6 people = 10 + 4 = 14
Total frequency = 1000
P (families with more than 6 people) = (14 / 1000) × 100 = 1.4% ≈ 1%
Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.
A. 2.6334 × 10–5
B. 2.6334 × 10–7
C. 2.6334 × 10–1
D. 2633.4 × 10–5
Answer:
A
Step-by-step explanation:
10-6 X 10-1 = 10-7
5.7*46.2=263.34
263.34=2.6334 x 10^2
10^2 x 10^-7 = 10^-5
so
=2.6334 x 10-5
The standard form of the product of the mathematical expression (46.2×10⁻¹)(5.7×10⁻⁶) is 2.6334×10⁻⁵ option (A) is correct.
What is an arithmetic operation?It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
We have a mathematical expression:
= (46.2×10⁻¹)(5.7×10⁻⁶)
= 46.2×5.7×10⁻⁷
= 263.34×10⁻⁷
= 2.6334×10⁻⁵
Thus, the standard form of the product of the mathematical expression (46.2×10⁻¹)(5.7×10⁻⁶) is 2.6334×10⁻⁵ option (A) is correct.
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Complete the equation to show two equivalent expressions.
g2 – 4g – 21 = (g – )(g + )
Answer:
[tex]g^2-4g-21=(g-7)(g+3)[/tex]
Step-by-step explanation:
To complete the left side of the equation, we need to bring it to the form
[tex](g-a)(g+b)[/tex]
expanding this expression we get:
[tex]g^2+bg-ag-ab[/tex]
[tex]g^2+(b-a)g-ab[/tex]
Thus we have
[tex]g^2-4g-21=g^2+(b-a)g-ab[/tex]
from here we see that for both sides of the equation to be equal, it must be that
[tex]b-a=-4[/tex]
[tex]-ab=-21[/tex].
Getting rid of the negative signs we get:
[tex]a-b=4[/tex]
[tex]ab=21[/tex]
At this point we can either guess the solution to this system (that's how you usually solve these types of problems) or solve for [tex]a[/tex] and [tex]b[/tex] systematically.
The solutions to this set are [tex]a=7[/tex] and [tex]b=3[/tex]. (you have to guess on this—it's easier)
Therefore, we have
[tex](g-a)(g+b)=(g-7)(g+3)[/tex]
which completes our equation
[tex]\boxed{ g^2-4g-21=(g-7)(g+3)}[/tex]
Answer: -7 and +3
did the assignment
Which of the following represents the translation of D(−5,4) along vector <6,−8> and its reflection across the y-axis?
Answer:
D (-5 , 4) → D' (1 , -4) → D" (-1 , -4) ⇒ 2nd answer
Step-by-step explanation:
* Lets revise some transformation
- If the point (x , y) translated horizontally to the right by h units
∴ Its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units
∴ Its image is (x - h , y)
- If the point (x , y) translated vertically up by k units
∴ Its image is (x , y + k)
- If the point (x , y) translated vertically down by k units
∴ Its image is(x , y - k)
- If point (x , y) reflected across the x-axis
∴ Its image is (x , -y)
- If point (x , y) reflected across the y-axis
∴ Its image is (-x , y)
* Now lets solve the problem
- The point D is (-5 , 4)
- The vector of the translation is <6 , -8>
∵ 6 is positive number
∴ Point D will translate horizontally 6 units to the right
∵ x-coordinate of D = -5
- Add the x-coordinate of D by 6 to find the x-coordinate of D'
∴ The x-coordinate of D' = -5 + 6 = 1
∴ The x-coordinate of D' = 1
∵ -8 is negative number
∴ Point D will translate vertically 8 units down
∵ y-coordinate of D = 4
- Add the y-coordinate of D by -8 to find the y-coordinate of D'
∴ The y-coordinate of D' = 4 + -8 = -4
∴ The y-coordinate of D' = -4
∴ The coordinates of D' are (1 , -4)
- If point (x , y) reflected across the y-axis then its image is (-x , y)
∵ D' is reflected across the y-axis
∵ D' = (1 , -4)
- Change the sign of its x-coordinate
∴ D" = (-1 , -4)
∴ The coordinates of D" are (-1 , -4)
* D (-5 , 4) → D' (1 , -4) → D" (-1 , -4)
Answer:
D (−5, 4) → D ′(1, −4) → D ″(−1, −4)
Step-by-step explanation:
Use the translation vector <6,−8> to determine the rule for translation of the coordinates: (x,y)→(x+6,y+(−8)).
Apply the rule to translate point D(−5,4).
D(−5,4)→(−5+6,4+(−8))→D'(1,−4).
To apply the reflection across y-axis use the rule for reflection: (x,y)→(−x,y).
Apply the reflection rule to point D'(1,−4).
D'(1,−4)→D''(−1,−4).
Therefore, D(−5,4)→D'(1,−4)→D''(−1,−4) represents the translation of D(−5,4) along vector <6,−8> and its reflection across the y-axis.
Counting back from 5 what number follows 4
I believe your answer should be 3.
Really?
5 down to 4 down to 3.
I think 3 is the best answer.
WILL MARK BRAINLIEST!
Which relation is a function?
Answer:
A
Step-by-step explanation:
A function is not allowed to have two Y values for the same X value. Any table with the same X value appearing more than once is not a function. Only table A qualifies as a function.
Which function has an inverse that is a function?
A. b(x)=x^2+3
B. d(x)=-9
C. -7x
D. p(x)=lxl
Answer:
C. -7x
Step-by-step explanation:
Only one of the offered choices passes the horizontal line test: at most one point of intersection with any horizontal line.
__
A: a parabola opening upward, so will have two points of intersection with a general horizontal line (only one at the vertex).
B: a horizontal line, so will have an infinite number of points of intersection with a horizontal line.
D. A "V-shaped" graph that will generally have two points of intersection with a horizontal line (only one at the vertex).
Answer:
m(x)=-7x C
Step-by-step explanation:
Edge
The height of the rectangle is multiplied by 4. What is the effect on the area?
Answer:
The new area is 4 times the original area
Step-by-step explanation:
we know that
The area of a rectangle is equal to
[tex]A=bh[/tex]
where
b is the base
h is the height
If the height is multiplied by 4
then
the new area is equal to
[tex]A=(b)(4h)[/tex]
[tex]A=4bh[/tex]
therefore
The new area is 4 times the original area
Two students from a group of eight boys and 12 girls are sent to represent the school in a parade.If the students are chosen at random, what is the probability that the students chosen are not both girls?a. 12/190b. 33/95c. 62/95d. 178/190
Answer:
The probability that the students chosen are not both girls is 62/95 ⇒ (c)
Step-by-step explanation:
* Lets explain how to find the probability of an event
- The probability of an Event = Number of favorable outcomes ÷ Total
number of possible outcomes
- P(A) = n(E) ÷ n(S) , where
# P(A) means finding the probability of an event A
# n(E) means the number of favorable outcomes of an event
# n(S) means set of all possible outcomes of an event
- Probability of event not happened = 1 - P(A)
- P(A and B) = P(A) . P(B)
* Lets solve the problem
- There is a group of students
- There are 8 boys and 12 girls in the group
∴ There are 8 + 12 = 20 students in the group
- The students are sent to represent the school in a parade
- Two students are chosen at random
∴ P(S) = 20
- The students that chosen are not both girls
∴ The probability of not girls = 1 - P(girls)
∵ The were 20 students in the group
∵ The number of girls in the group was 12
∴ The probability of chosen a first girl = 12/20
∵ One girl was chosen, then the number of girls for the second
choice is less by 1 and the total also less by 1
∴ The were 19 students in the group
∵ The number of girls in the group was 11
∴ The probability of chosen a second girl = 11/19
- The probability of both girls is P(1st girle) . P(2nd girl)
∴ The probability of both girls = (12/20) × (11/19) = 33/95
- To find the probability of both not girls is 1 - P(both girls)
∴ P(not both girls) = 1 - (33/95) = 62/95
* The probability that the students chosen are not both girls is 62/95
A group of numbers arranged in a specific order is called a sequence. Create two groups of numbers- one that can be classified as a sequence and another that cannot. Use complete sentences to differentiate between the two groups of numbers. In your final answer, include both groups of numbers and your explanation.
Answer:
1, 3, 6, 7, 9...
1, 4, 8, 7, 11...
Step-by-step explanation:
(1, 3, 6, 7, 9...)
This one is the sequence because it follows a specific pattern, which is 2n-1, or (2 x figure number) - 1. 1x2-1=1. 2x2-1=3. 3x2-1=7. And so on.
(1, 4, 8, 7, 11...)
This one, no matter how you look at it, has no pattern. Its not a proper sequence of numbers.
What is magma? a. The molten mixture of rock-forming substances, gases, and water from the mantle.. c. Hardened lava on the surface of the Earth. b. Liquid rock that reaches the surface. d. All of the above Please select the best answer from the choices provided A B C D
Answer: A. The molten mixture of rock-forming substances, gases, and water from the mantle
Magma is a mass of molten rock that is found in the deepest layers of the Earth at high temperature and pressure, and that can flow out through a volcano.
The composition of this mass is a mixture of liquids, volatile and solids that when they reach the surface in an eruption becomes lava, which when cooled crystallizes and gives rise to the formation of igneous rocks.
Find the possibility of rolling even numbers three times, using a six-side die number from 1 to 6
Answer:
[tex]\frac{1}{8}[/tex]
Step-by-step explanation:
Number of sides of die = 6
Number of sides with even numbers = 3
P( rolling an even number 1 time) = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]
P(rolling even number 3 times) = [tex]\frac{1}{2}[/tex] x [tex]\frac{1}{2}[/tex] x [tex]\frac{1}{2}[/tex] = [tex]\frac{1}{8}[/tex]
The total cost to rent a row boat is $14 times the number of hours the boat is used. Write an equation to model this situation if c= total cost and h= number of hours.
Answer:
14h=c
Step-by-step explanation:
14 times total hours boat of used (h) is the total cost of the boat > 14h=c
in order to come up with a realistic schedule, a manager wants to know how long it usually takes an employee to complete a task. which statistical measurement is the manager most likely to use? A. mean B. median C. mode D. sum
Answer:
A. mean
Step-by-step explanation:
The mean of data is given by the ratio of the sum of all the values to the total number of values. It gives the average value of the set of values.
[tex]\bar{x}=\frac{1}{n}}\left(\sum _{i=1}^{n}{x_{i}}\right)[/tex]
Here, the manager wants to get an estimate of how much time it takes by each employee to complete a task. The mean will be the sum of time taken by each person to complete a task divided by the number of employees.
Hello, I need help in a compound inequality word problem:
Emily is three years older than twice her sister Mary's age. The sum of their ages is less than 30.
Let x represent Mary's age.
Which inequality represents Mary's possible age?
1. 0
2.0
3.0
4.0
Answer:
3+2x<30
Step-by-step explanation:
3 represents that Emily is 3 years older than 2x
2x represents twice Mary's age
<30 represents that it's always less than 30
Answer:
The compound inequality is [tex]0<x<9[/tex]
Step-by-step explanation:
Consider the provided information.
It is given that Emily is three years older than twice her sister Mary's age.
Let x represent Mary's age.
Then the age of Emily is: 2x+3
The sum of their ages is less than 30.
This can be written as:
[tex]2x+3+x<30[/tex]
[tex]3x+3<30[/tex]
[tex]3x<27[/tex]
[tex]x<9[/tex]
As we know the age can't be a negative number.
Therefore, the age of Mary must be a positive number greater than 0.
Thus, the compound inequality is [tex]0<x<9[/tex]
I'm terrible at math any help here is appreciated.
Answer:
d. 12 units, 14 units, 10 units
Step-by-step explanation:
The side lengths differ by 2 units from one to the next larger one:
(2t+2) - (2t) = 2
(2t+4) - (2t+2) = 2
So, you're looking for answer numbers that can make a sequence with differences of 2, and that add to 36. Only the last choice matches that description.
_____
You can solve this "directly" by adding up the side lengths and setting that result to the perimeter length.
(2t+2) + (2t+4) + (2t) = 36
6t +6 = 36 . . . . . collect terms
6t = 30 . . . . . . . . subtract 6
t = 30/6 = 5 . . . . divide by 6
The shortest side is 2t, so is 2·5 = 10 units. Only the last answer choice matches this.
Side lengths are 12 units, 14 units, 10 units.
A circle is centered at the point (-7, -1) and passes through the point (8, 7). The radius of the circle is units. The point (-15, ) lies on this circle.
Answer:
Part 1) The radius of the circle is [tex]r=17\ units[/tex]
Part 2) The point (-15,14) and the point (-15,-16) lies on the circle
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
To find the radius of the circle calculate the distance between the center of the circle and the point (8,7)
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex](-7,-1)\\(8,7)[/tex]
substitute
[tex]r=\sqrt{(7+1)^{2}+(8+7)^{2}}[/tex]
[tex]r=\sqrt{(8)^{2}+(15)^{2}}[/tex]
[tex]r=\sqrt{289}[/tex]
[tex]r=17\ units[/tex]
step 2
Find the equation of the circle
The equation of the circle in standard form is equal to
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the center
r is the radius
substitute
[tex](x+7)^{2}+(y+1)^{2}=17^{2}[/tex]
[tex](x+7)^{2}+(y+1)^{2}=289[/tex]
step 3
Find the y-coordinate of the point (-15.y)
substitute the x-coordinate in the equation of the circle and solve for y
[tex](-15+7)^{2}+(y+1)^{2}=289[/tex]
[tex](-8)^{2}+(y+1)^{2}=289[/tex]
[tex]64+(y+1)^{2}=289[/tex]
[tex](y+1)^{2}=289-64[/tex]
[tex](y+1)^{2}=225[/tex]
square root both sides
[tex](y+1)=(+/-)15[/tex]
[tex]y=-1(+/-)15[/tex]
[tex]y1=-1(+)15=14[/tex]
[tex]y2=-1(-)15=-16[/tex]
therefore
The point (-15,14) and the point (-15,-16) lies on the circle
see the attached figure to better understand the problem
Answer:
plato users the answer is 17 units and (-15,14)
Step-by-step explanation:
NEED HELP WITH A MATH QUESTION
Answer:
[tex]x =18.0[/tex]
Step-by-step explanation:
To solve this problem use the Law of cosine.
The law of cosine says that:
[tex]c^2 = a^2 + b^2 -2abcos(C)[/tex]
In this case we have that:
[tex]c = x\\\\a=30\\\\b=16\\\\C=30\°[/tex]
Therefore
[tex]x^2 = 30^2 + 16^2 -2(30)(16)cos(30\°)[/tex]
[tex]x = \sqrt{30^2 + 16^2 -2(30)(16)cos(30\°)}[/tex]
[tex]x = \sqrt{1156 -831.38}[/tex]
[tex]x = \sqrt{324.62}[/tex]
[tex]x =18.0[/tex]
The area of a parking lot is 805 square meters. A car requires 5 meters and a bus requires 32 square meters of space. There can be at most 80 vehicles parked at one time. If the cost to park a car is $2.00 and a bus is $6.00, how many should be in the lot to maximize income?
Answer:
80 cars will maximize revenue
Step-by-step explanation:
The revenue per square meter for parked cars is ...
$2.00/5 = $0.40
The revenue per square meter for buses is ...
$6.00/32 = $0.1875
Thus the available space should be used to park the maximum number of cars.
80 cars should be in the lot to maximize income.
To maximize income, the parking lot should have 69 cars and 11 buses parked, resulting in a total income of $282.
To maximize income, we need to maximize the revenue generated from parking fees. Let's denote the number of cars as x and the number of buses as y.
Given:
- Area of parking lot: 805 square meters
- Space required for a car: 5 square meters
- Space required for a bus: 32 square meters
- Maximum number of vehicles: 80
We have the following constraints:
1. [tex]\( 5x + 32y \leq 805 \)[/tex] (total area constraint)
2. [tex]\( x + y \leq 80 \)[/tex] (maximum number of vehicles constraint)
The objective function to maximize income is:
Income [tex]\( I = 2x + 6y \)[/tex]
To solve this problem, we'll analyze the feasible region defined by these constraints and find the combination of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] that maximizes income.
By solving these constraints, we find that the maximum income occurs at the vertex where [tex]\( x = 69 \) and \( y = 11 \)[/tex].
Therefore, to maximize income, there should be 69 cars and 11 buses parked in the lot.
Which circle shows AB that measures 60 degrees?
I say the third circle from the top down. The central angle is the measure of minor arc AB.
The central angle here is 60 degrees, shown by the third circle down from the top. This is the right answer.
The circle that shows chord AB to measure 60 degrees is Option(C).
What is minor chord ?A chord of a circle divides the circle into two regions, which are called the segments of the circle. The minor chord is the shorter arc connecting two endpoints on a circle . The measure of a minor chord is always less than 180° .
How to identify chord AB to measure 60° ?In the four Options given alongside diagram, Option(C) represents a minor chord with its central angle subtended by the minor segment as 60°.
Thus AB is the minor sector of the circle and the angle measures 60° with that chord itself. The other three options do not define the minor chord or segment AB therefore not measuring its central angle.
Therefore, the circle that shows chord AB to measure 60 degrees is Option(C).
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Let f(x) = x + 7 and g(x) = x − 4. Find f(x) ⋅ g(x).
For this case we have the following functions:
[tex]f (x) = x + 7\\g (x) = x-4[/tex]
We must find the product of the functions:
[tex]f (x) * g (x) = (x + 7) (x-4)[/tex]
We apply distributive property:
[tex]f (x) * g (x) = x ^ 2-4x + 7x-28\\f (x) * g (x) = x ^ 2 + 3x-28[/tex]
Finally, the product of the functions is:
[tex]x ^ 2 + 3x-28[/tex]
Answer:
[tex]x ^ 2 + 3x-28[/tex]
what is the exponential form of log5 9 = x?
Step-by-step explanation:
log₅ 9 = x
5^(log₅ 9) = 5^x
9 = 5^x
the function f(x)=18000(0.7)^x represents the penguin population on an island x years after it was first studied.what was the original population of the penguins on island?
Answer:
1800
Step-by-step explanation:
The original population occurs when time (i.e x) is zero.
hence we substitute x = 0 into the function
Original population, f(0),
= 1800 [tex](0.7)^{0}[/tex] .......... recall anything raised to power of zero is 1
= 1800 (1)
= 1800
The original population of the penguins on island be, 1800.
The correct option is (c)
What is function?A function is defined as a relation between a set of inputs having one output each. Every function has a domain and codomain or range. A function is generally denoted by f(x) where x is the input.
Given: f(x)=18000[tex](0.7)^{x}[/tex]
The original population will occurs when time is zero.
So, put x = 0 into the function f(x),
we have,
f(0)= 1800[tex](0.7)^{0}[/tex]
f(0)= 1800*1
f(0)=1800
Hence, the original population of the penguins on island is 1800.
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What conic section is defined by all points in a plane where the difference between the lengths of segments x and y remains constant?
Answer:
hyperbola
Step-by-step explanation:
If the sum is constant, the figure is an ellipse.
If the difference is constant, you get a hyperbola.
If one length is constant, you get a circle.
If the length to a point is the same as the length to a line, you get a parabola.
Answer:
There are four type of conic generated when a double napped cone is cut by a plane
1.Circle
2.Parabola
3.Ellipse
4.Hyperbola
Among these four, Hyperbola is the conic , ,all points in a plane where the difference between the lengths of segments x and y remains constant.
A point on Semi major Axis=(a,0),lying on the Hyperbola.
A point on Semi Minor axis =(0,b),not lying on the Hyperbola.
Take a point D lying on the hyperbola,and two points M and N not lying on the hyperbola.
DM-DN=2a(Length of major axis)
A vegetable garden and a surrounding path are shaped like a square together are 12 ft wide. The path is 1 feet wide. If one bag of gravel covers 8 square feet, how manu bags are needed to cover the path? Round your answers to the nearest tenth.
Step-by-step answer:
There are two squares, the inner one of which is a garden, surrounded by a path 1 foot wide.
The outer square represents the periphery of the path, as shown in the attached image.
One bag of gravel covers 8 square-feet. Need the number of bags required to cover the path.
Solution:
We first need to find the total area of the path by subtracting the area of garden from the overall area, namely the outer square.
Area of path = 12^2 - 10^2 = 144-100 = 44 sq. ft.
Number of bags required
= area (sq.ft) / area each bag covers
= 44 sq.ft / 8 (sq.ft / bag)
= 5.5 bags
Answer: 6 bags need to be purchased.
Consider the sequence 130, 143, 156, 169, ... Write an explicit formula to represent the arithmetic sequence and use it to find the 13th term.
A. A(n) = 130 + (n-1)13; 286
B. A(n) = 130 + 13n; 299
C. A(n) = 130 + 13n; 286
D. A(n) = 130 + (n-1)13; 299
please help
Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
The amount that two groups of students spent on snacks in one day is shown in the dot plots below.
Which statements about the measures of center are true? Check all that apply.
The mean for Group A is less than the mean for Group B.
The median for Group A is less than the median for Group B.
The mode for Group A is less than the mode for Group B.
The median for Group A is 2.
The median for Group B is 3.
Answer:
I got B as my answer, hope it helps
The statements that are true about the measures of center are: Option B. The median for Group A is less than the median for Group B and Option C. The mode for Group A is less than the mode for Group B.
What is the median of a data set?The median of a data set is the middle value when the values are arranged in numerical order, or the average of the two middle values if the data set has an even number of elements.
For group A, the median falls between 1 and 2, thus, we can say the median = 1 + 2/2 = 1.5.
For group B, the median falls between 2 and 3, thus, we can say the median = 2 + 3/2 = 2.5.
The mode for group A is 1, while that of group B is 3, therefore, we can conclude that:
B. The median for Group A is less than the median for Group B, and
C. The mode for Group A is less than the mode for Group B.
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I posted a question similar to this yesterday and I understand how to do it now, but I want to make sure that I did this question correctly.
Answer:
Your choice is correct.
Step-by-step explanation:
magnitude = √(6² +5²) = √61 ≈ 7.81
direction = arctan(5/6) ≈ 39.81°
The polar coordinates are (7.81, 39.81°).
how much larger then 1/4 mile is 9/10 mile please show work
Answer:
13/20 = 0.65 mile
Step-by-step explanation:
Finding the difference of two fractions is usually done by first expressing each of them using a common denominator. Here, both 4 and 10 are factors of 20, so 20 is a suitable common denominator.
9/10 - 1/4 = 18/20 - 5/20 = (18 -5)/20 = 13/20
This can be expressed as a decimal:
13/20 = (13·5)/(20·5) = 65/100 = 0.65
9/10 of a mile is 13/20 of a mile larger than 1/4 of a mile. In decimal, that is 0.65 miles larger.
Please answer this question correctly for 35 points and brainliest!!
Answer:
11
Step-by-step explanation:
49-5=44
44/4=11