The complete statements of the expression are
In the first term, 5 is a coefficientIn the second term, (3y+ 13) is a factorIn the third term, -1 is a constantHow to complete the statements in the expression
From the question, we have the following parameters that can be used in our computation:
5x - 8(3y + 13) - 1
Consider an expression
Ax + b
Where x is the variable, we have
A is a coefficientA is a factorb is a constantUsing the above as a guide, we have the following:
In the first term, 5 is a coefficient
In the second term, (3y+ 13) is a factor
In the third term, -1 is a constant
Question
Use the given expression to complete the statements.
5x– 8(3y + 13) – 1
In the first term, 5 is a _____
In the second term, (3y+ 13) is a ______
In the third term, -1 is a ______
algebra II engenuity
Answer:
First Option
Step-by-step explanation:
Given expression is:
[tex]\sqrt[4]{x^{10}}[/tex]
The radicand's exponent will be made multiple of 4 to make the calculations easy
So,
[tex]= \sqrt[4]{x^8 * x^2}[/tex]
The 4 outside the radical means that the power that will be multiplied with the exponents will be 1/4
So,
[tex]= x^{(8*\frac{1}{4})} * x^{(2*\frac{1}{4})}\\=x^2 \sqrt[4]{x^2}[/tex]
As x^2 couldn't be solved using radical, it will remain inside the radical.
So the correct answer is first option..
Answer: First option.
Step-by-step explanation:
Knwing that we must find which is the equivalent expression of the expression [tex]\sqrt[4]{x^{10}}[/tex], it is important to remember the Product of powers property, which states the following:
[tex](a^m)(a^n)=a^{(m+n)}[/tex]
The we can rewrite the expression:
[tex]=\sqrt[4]{x^8x^2}[/tex]
Remember that:
[tex]\sqrt[n]{a^n}=a[/tex]
Then we get this equivalent expression:
[tex]=x^2(\sqrt[4]{x^2})[/tex]
Divide simplify your answer
Answer:
[tex]\large\boxed{\dfrac{2s-6}{s+3}}[/tex]
Step-by-step explanation:
[tex]s^2-9=s^2-3^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(s-3)(s+3)\\\\s^2+6s+9=s^2+2(s)(3)+3^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\=(s+3)^2[/tex]
[tex]\dfrac{s^2-9}{2s}\div\dfrac{s^2+6s+9}{4s}=\dfrac{s^2-9}{2s\!\!\!\!\diagup_1}\cdot\dfrac{4s}{s^2+6s+9}\\\\=\dfrac{(s-3)(s+3)}{2s\!\!\!\!\!\diagup_{_1}}\cdot\dfrac{4s\!\!\!\!\!\diagup^{^2}}{(s+3)^2}=\dfrac{2(s-3)(s+3)}{(s+3)(s+3)}\qquad\text{cancel}\ (s+3)\\\\=\dfrac{2(s-3)}{s+3}=\dfrac{2s-6}{s+3}[/tex]
On which number line are -3 and its opposite shown?
Answer:
The number line should look like this;
<---- -3 -------- 0 ------- 3 ----->
It must have both 3 and -3 shown
Step-by-step explanation:
Step-by-step explanation:how do you feguire this out because the left of a number line is always negative and the right is always posittive easy right i hope it helped you just like when i learned it it helped me.
y+1=-3x(x+4)
help me solve please
What is the solution of the graph?
Answer:
no solution
Step-by-step explanation:
The solution to a system of equations given graphically is at the point of intersection of the 2 graphs.
The given lines are parallel ( both have a slope = 2 )
Hence the lines never intersect thus there is no solution.
Which function is negative for the interval (–1, 1]?
⇒The Interval in which we have to find the function is Negative is (-1,1].
→(-1,1]=Semi closed or Semi Open Interval, Point -1, is not included in the set, but 1 is included in the set.
⇒ The meaning of negative here is,that either for positive or negative value of x , the value of f(x), that is y Should be negative.
⇒y is negative in third and fourth Quadrant.
Graph -(2), is the function , in which the function is negative for the interval (–1, 1].
Add.
3x2 - 5x+1
2x2 +9x-6
+
Answer:
The sum of the two expressions is 5x^2 + 4x - 5
Step-by-step explanation:
Rewrite
3x2 - 5x+1
2x2 +9x-6
as
3x^2 - 5x+1
2x^2 +9x-6 " ^ " indicates exponentiation
-----------------
5x^2 + 4x - 5
Answer:
[tex]5x^2+4x-5[/tex]
Step-by-step explanation:
[tex]3x^2-5x+1 \ and \ 2x^2 + 9x -6[/tex]
Add both the polynomials
To add both the polynomials we combine like terms
[tex]3x^2-5x+1 +2x^2 + 9x -6[/tex]
3x^2 and 2x^2 are like terms . it becomes 5x^2
-5x and 9x are like terms . it becomes 4x
[tex]3x^2-5x+1 +2x^2 + 9x -6[/tex]
[tex]5x^2+4x-5/tex]
Hamid has gained weight. He now weighs 88kg, which is 10% higher than his normal weight. What is his normal weight?
Please help, this question is on reverse percentage.
Answer:
79.2kg
Step-by-step explanation:
So first step is to find 10% of 88, which is 8.8. And 88kg is higher than his normal weight, so his original weight would be lower than 88kg. So you subtract. 88-8.8=79.2. His normal weight is 79.2kg.
Three families went to the movies together. The Smiths ordered two tubs of popcorn, one plate of nachos, and three drinks. They spent $65. The Langes ordered three tubs of popcorn, two plates of nachos, and five drinks. They spent $85. The Radfords ordered one tub of popcorn, one plate of nachos, and two drinks. They spent $40. Which system of equations matches their night at the movies?
Answer:
2t + n + 3d = 65
3t + 2n + 5d = 85
t + n + td = 40
Step-by-step explanation:
tubs of popcorn = t
plates of nachos = n
drinks = d
The Smiths: 2t + n + 3d = 65
The Langes: 3t + 2n + 5d = 85
The Radfords: t + n + td = 40
So, the correct answer would be the one including all 3 of these equations. :)
Answer:
The system of equations are:
[tex]2t + n + 3d = 65[/tex]
[tex]3t + 2n + 5d = 85[/tex]
[tex]t + n + 2d = 40[/tex]
Step-by-step explanation:
Consider the provided information.
let "t" represents tubes of popcorn, "n" represents nachos and "d" represents drink.
The Smiths ordered two tubs of popcorn, one plate of nachos, and three drinks. They spent $65. Which can be represents as:
[tex]2t + n + 3d = 65[/tex]
Langes ordered three tubs of popcorn, two plates of nachos, and five drinks. They spent $85. Which can be represents as:
[tex]3t + 2n + 5d = 85[/tex]
The Radfords ordered one tub of popcorn, one plate of nachos, and two drinks. They spent $40. Which can be represents as:
[tex]t + n + 2d = 40[/tex]
Thus, the system of equations are:
[tex]2t + n + 3d = 65[/tex]
[tex]3t + 2n + 5d = 85[/tex]
[tex]t + n + 2d = 40[/tex]
One fourth of all telephones at the office have built in speaker phones. One -half the phones with the built-in speaker phones have conference-call capability,how many of the phones in the office have both a speaker phone and a conference-call capability?
Answer:
[tex]\frac{1}{8}[/tex] of the phones in office has both a speaker phone and a conference-call capability
Step-by-step explanation:
Since total number of phones in the office is not given, the answer will be "in that terms".
let it be x
So built in speaker phones is (1/4)x
Hence conference call phones would be (1/2)(1/4x) = (1/8)x
Hence "1/8th of the phones in office has both a speaker phone and a conference-call capability"
Answer:
(1/8)x phones have both speaker phone and a conference call capability
Step-by-step explanation:
Let the total phones be x
It is given that one forth of the phones have in built speaker = (1/4)x
It is also given that one half of the phone having built in speaker also have conference call capability = (1/2) of (1/4)x
= (1/8)x
Therefore, (1/4)x - (1/8)x
= (1/8)x
(1/8)x phones have both speaker phone and a conference call capability.
What is the value of p in the equation y^ = -4x?
ANSWER
p=-1
EXPLANATION
The given equation is
[tex] {y}^{2} = - 4x[/tex]
We compare with the general equation of the parabola with vertex at the origin.
[tex]{y}^{2} =4px[/tex]
Comparing the right hand side we have,
[tex]4px = - 4x[/tex]
Divide both sides by 4x
[tex] \frac{4px}{4x} = \frac{ - 4x}{4x} [/tex]
This implies that,
[tex]p = - 1[/tex]
Simplify the expression.
(7.46)** . (7.46)
Answer:
D. 7.46
Hope this helps and have a nice day!!
If I'm wrong pleaseeee tell me
Step-by-step explanation:
the perimeter of a rectangle swimming pool is 486 feet. The width of the pool is 35 feet less than the length. Find the length and the width
Answer:
Length: 139 feet
Width: 104 feet
Step-by-step explanation:
The formula for the perimeter of a rectangle can be given by [tex]P = 2l + 2w[/tex]. We are given the perimeter of the pool along with the width.
[tex]P = 486[/tex]
[tex]w = l - 35[/tex]
From here, all we have to do is plug back into the original formula:
[tex]486 = 2l + 2(l - 35)[/tex]
Which can be further simplified as:
[tex]486 = 2l + 2l - 70[/tex]
[tex]486 = 4l - 70[/tex]
From here, all we have to do is add 70 to both sides of the equation and divide by four:
[tex]556 = 4l[/tex]
[tex]139 = l[/tex]
To make sure that this answer is accurate, we can find that the width of the rectangle should then be 104 (given by 139 - 35). All we have to do is plug back into the original equation:
[tex]P = 2l + 2w[/tex]
[tex]P = 2(139) + 2(104)[/tex]
[tex]P = 278 + 208[/tex]
[tex]P = 486[/tex]
And the substitution works, so the length of the rectangle would be 139 feet and the width would be 104 feet.
Answer:
Length = 139 and Width = 104 .
Step-by-step explanation:
Given: The perimeter of a rectangle swimming pool is 486 feet. The width of the pool is 35 feet less than the length.
To find: Find the length and the width .
Solution: We have given that
Let the length = x
According to question
The width of the pool is 35 feet less than the length.
width = x-35
perimeter = 2(length + width)
plugging the values
486 = 2(x + x-35)
486 = 2x + 2x - 70
486 = 4x - 70
On adding by 70 both side
486 +70 = 4x-70 +70
556 = 4x
On dividing by 4 both side
139 = x
so, length = 139 .
width = x -35 = 139- 35 = 104
Therefore, length = 139 and width = 104.
A sequence is defined by the recursive function
f(n + 1) = f(n) - 2
if f(1) = 10, what is f(3)?
1
6
8
30
Answer:
6Step-by-step explanation:
[tex]f(n+1)=f(n)-2\\\\f(1)=10\\f(2)=f(1)-2=10-2=8\\f(3)=f(2)-2=8-2=6[/tex]
Answer:
B) 6
Step-by-step explanation:
If there are 6 serving in a 2/3 pound lb package of pound is in each serving
Answer:
[tex]\boxed{\math{\frac{1}{9}\text{ lb}}}[/tex]
Step-by-step explanation:
[tex]\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}[/tex]
[tex]\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}[/tex]
On the coordinate plane shown below, points H and I have coordinates (-2,-3) and (3,2), respectively.
on
Use the Pythagorean theorem to determine the distance between points Hand I on the coordinate plane.
Answer:
[tex]5\sqrt{2}[/tex]
Step-by-step explanation:
Here we are given two coordinates and we are required to fin d the distance between them not by using the distance formula but by using Pythagoras theorem.
Let us see how we do that.
We will take the help of graph in this. We draw a line parallel to x axis passing through H (-2,-3) and a vertical line passing through I(3,2)
Let us assume that these two lines intersect at point J whose coordinates will be (-3,-3)
Now using scale of the graph we can see that Distance HJ = 5 units and IJ= 5 units and ΔHIJ makes and Right angle triangle where ∠IJH = 90°
Hence we can apply Pythagoras theorem in this.
[tex]HJ^{2}+JI^{2}=HI^{2}[/tex]
[tex]5^2+5^2=HI^{2}[/tex]
[tex]HI^{2}=25+25[/tex]
[tex]HI^{2}=50\\HI=\sqrt{50}\\HI=\sqrt{25*2}\\HI=5\sqrt{2}\\[/tex]
Please refer to graph in attachment for further clarification.
What is the surface area?
Answer:
Surface Area of Cone = 200π cm^2
Surface Area of Right Prism = 17.5 ft^2
Step-by-step explanation:
32. We are given a figure of a cone and we are to find its surface area.
We know that the formula for the S.A. of cone is given by:
Surface Area of cone = [tex]\pi r(r+\sqrt{h^2+r^2} )[/tex]
Substituting the given values in the above formula.
Surface Area of cone = [tex]\pi \times 8(8+\sqrt{15^2+8^2} )[/tex] = 200π cm^2
25. We are to find the surface area of a right prism.
Surface Area of Right Prism = Base Perimeter × height + 2(Base Area)
Base Perimeter = 2(4 + 1.5) = 11 ft
Height = 0.5 ft
Base Area = 4 × 1.5 = 6 ft
Substituting these values in the above formula.
Surface Area of Right Prism = 11 × 0.5 + 2(6) = 17.5 ft^2
Answer:
Surface area of cone = 200π cm
Surface area of prism = 17.5 ft²
Step-by-step explanation:
To find the slant height of cone
slant height l = √(r² + h²)
= √(8² + 15²) = 17
To find the surface area of cone
Surface are = πr² + πrl
= π*8² + π*8*17
= 64π + 136π
= 200π cm²
To find the surface area of prism
l = 4 ft
b = 1.5 ft and h = 0.5 ft
Surface area = 2(lb + lh + bh)
= 2[(4* 1.5) + (4*0.5) + (1.5*.5)
= 2(6 + 2 +0.7.5)
= 17.5 ft²
The area of a compact disc is 452 4/7 square centimeters. What is the diameter of a compact disc ? Use 22/7 as an approximation for pie?
[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} A=452\frac{4}{7} \end{cases}\implies 452\frac{4}{7}=\pi r^2\implies \cfrac{3168}{7}=\pi r^2 \implies \cfrac{3168}{7\pi }=r^2 \\\\\\ \stackrel{\pi =\frac{22}{7}}{\cfrac{3168}{7\cdot \frac{22}{7}}}=r^2\implies \cfrac{3168}{22}=r^2\implies 144=r^2\implies \sqrt{144}=r\implies 12=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{diameter=2r}{d=24}~\hfill[/tex]
Simplify 3(2x - 5).for me please
Answer:
6x-15
Step-by-step explanation:
3*2x= 6x
3*5=15
6x-15
Answer:
6x - 15
Step-by-step explanation:
3(2x - 5)
Distributive property
= 3(2x) + (3)(-5)
= 6x - 15
There were 425 tickets sold for the annual everglades middle school talent show. If this is 85% of the tickets available, how many tickets went unsold? A. 15. B. 75. C. 55. D. 35.
Answer:
425/85*100 = 500 thus: 500-425 =75 Tickets.
Step-by-step explanation:
Answer:
75
Step-by-step explanation:
Find the image of (-2, 1) obtained by
translating 3 units down, followed by a
reflection over the y-axis.
Please help it is urgent!!!
The y-axis runs vertically, so changing the y-coordinate moves a figure up or down. Adding a number to the y-coordinate shifts the image up, while subtracting a number shifts the figure down.
So to translate 3 units down, we just subtract 3 from the y-coordinate.
Instead of (-2, 1) it's now (-2, -2) since 1 - 3 (units) = -2
Now, another way to say "reflect across the y-axis" is to say "reflect across the line x=0" since the line created by graphing x=0 is the same as the y-axis.
An image that is a reflection across the y-axis, or across the line x=0, will have opposite x-coordinates from the pre-image but identical y-coordinates.
Therefore, the rule for reflecting an image across the y-axis can be described as (x, y) → (−x, y).
So using our translated point (-2, -2) it now becomes (2, -2).
You didn't provide an image, however, all you need to find is the translated and reflected point that lies on (2, -2).
Answer:
( 2 , 1 )
Step-by-step explanation:
literally have no idea how the other person got -2 as the second answer lol
its 1 not -2 , ik cause i had this problem on my acellus and had to guess until i got it
Consider the paragraph proof.
Given: D is the midpoint of AB, and E is the midpoint of AC.
Prove:DE = BC
It is given that D is the midpoint of AB and E is the midpoint of AC. To prove that DE is half the length of BC, the distance formula, d = , can be used to determine the lengths of the two segments. The length of BC can be determined with the equation BC = , which simplifies to 2a. The length of DE can be determined with the equation DE = , which simplifies to ________. Therefore, BC is twice DE, and DE is half BC.
Which is the missing information in the proof?
a
4a
a2
4a2
Answer:
a
Step-by-step explanation:
You're trying to find the distance between D and E so u use the distance formula.
sqrt (a+b-b^2)+(c-c)^2=sqrt a^2=a
Answer:
a
Step-by-step explanation:
We are given that
D is the mid-point of AB and E is the mid-point of AC.
We have to find the missing information in given proof of DE is equal to half of BC.
Proof:
D is the mid-point of AB and E is the mid-point of AC.
The coordinates of A are (2b,2c)
The coordinates of D are (b,c)
The coordinates of E are (a+b,c)
The coordinates of B are (0,0)
The coordinates of C are (2a,0)
Distance formula:[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the formula
Length of BC=[tex]\sqrt{(2a)^2+(0-0)^2}=2a[/tex] units
Length of DE=[tex]\sqrt{(a+b-b)^2+(c-c)^2}=a[/tex] units
[tex]BC=2a=2\times DE[/tex]
[tex]DE=\frac{1}{2}BC[/tex]
Hence, proved.
Option A is true.
Which expression will simplify to 1?
Let us check each Option :
[tex]\mathsf{First\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{m - 9}\right)}[/tex]
[tex]\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)^2\;\neq\;1}[/tex]
[tex]\mathsf{Second\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m - 9}{m + 9}\right)}[/tex]
[tex]\mathsf{\implies 1}[/tex]
[tex]\mathsf{Third\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{9 + m}{9 - m}\right)}[/tex]
[tex]\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{-(m - 9)}\right)}[/tex]
[tex]\mathsf{\implies-\left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{m - 9}\right)}[/tex]
[tex]\mathsf{\implies-\left(\dfrac{m + 9}{m - 9}\right)^2\;\neq\;1}[/tex]
[tex]\mathsf{Fourth\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{9 - m}{9 + m}\right)}[/tex]
[tex]\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{-(m - 9)}{9 + m}\right)}[/tex]
[tex]\mathsf{\implies -\left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m - 9}{9 + m}\right)}[/tex]
[tex]\mathsf{\implies -1\;\neq\;1}[/tex]
Answer : Option (2)
Answer:
B.⁽[tex](\frac{m}{m}\frac{+9}{-9} ) (\frac{m}{m} \frac{- 9}{+ 9} )[/tex]
Step-by-step explanation:
The graph of relation r is shown. Which of the following graphs represents the relation and it’s inverse
Answer:
To easily solve this question, we must realize that the graph of the relation is very similar to that of the expression
y = √(x-a) , where a>0
If we take a look at the image attached, we have plotted the graph of
y = √(x-1) , and its correspondent inverse function.
This means that the answer is the first option
Your phone plan charges you an initial fee and then a certain amount depending on the amount of data you use they send you periodic updates of your insiste and your current bill cost. After using 3 GB of data you owe $30. After 5 GB of data you owe $40. What is the initial fee prior to the data usage charge ?
Answer:
5
Step-by-step explanation:
dot
The plane that contains points C and T can also be named plane .
Answer:
False
Step-by-step explanation:
You need 3 points to name a plane. 2 points is required to name a line
Answer:
It would be CUB
Step-by-step explanation:
I need help finding the answer
Answer:
32
Step-by-step explanation:
The formula is base x hight.
The base is 8.
The hight is 4.
You just multiply the two.
8x4=32
Simple. :)
Hope this helps!
Answer: 42 inches squared
Step-by-step explanation:
To find the total area you will find the area of the rectangle and then add that to the area of the triangle. (Remember a triangle is half of a rectangle!) First we will find the area of the rectangle...
4x8=32 inches squares
Now let’s find the area of the triangle, find the rectangle then divide it in half...
5x4=20 inches squared
20/2=10 inches squared
Now add 32 to 10 and you’ll have your answer!
32+10=42 inches squared
Judy works at a candy factory that makes Sugar Rush candy bars. She is in charge of quality control and has to make sure each candy bar has the correct mass. Each candy bar is required to weigh 12 grams, with a tolerance of 0.45 grams. What is the acceptable weight range for each candy bar?
1. Define a variable for this situation.
2. Write the absolute value inequality that describes the acceptable weight range for each candy bar.
3.Solve the absolute value inequality to find the acceptable weight range for each candy bar using numbers and symbols.
4. Using words, describe the possible acceptable weight range for each candy bar.
Step-by-step explanation:
1. x = acceptable weight of candy bar
2. |x - 12| ≤ 0.45
3. x - 12 ≤ 0.45, x - 12 ≥ -0.45
x ≤ 12.45, x ≥ 11.55
4. The acceptable weight range for each candy bar is between 11.55 grams and 12.45 grams.
Can someone help me plz and the last two that you couldn’t see was ( c- 1 1/3 ) and ( D- 1 1/9)
Answer:
B 9/10
Step-by-step explanation:
3/5 ÷2/3
Copy dot flip
3/5 * 3/2
9/10
Which congruence theorems prove tht
MNP and QRS are be congruent?
Word Bank:
AAS theorem, ASA postulate, SAS postulate,
SSS postulate, HA, AA, HL, LA, LL, HH
Answer
AAS
Step-by-step explanation: