In the diagram below, G is the incenter of DEF. m
In the previous question, what is m

Answers

Answer 1

Final answer:

The question involves Physics concepts such as vector addition, moment of inertia, and gravitational force calculations. The incenter mentions seem irrelevant to the Physics calculations related to inertia and force.

Explanation:

The question asked is about calculating the moment of inertia for a specific geometric object (a cylinder) and involves understanding the mass distribution relative to an axis of rotation. This is a common concept in the field of Physics, particularly when dealing with rotational dynamics and inertia.

The mention of the incenter of a triangle appears to be unrelated to the main question, which is more focused on moments of inertia, vector addition, and gravitational force equations as indicated by the provided reference information.

For example, the moment of inertia of a cylinder about a given axis can be calculated using established mathematical formulas. Moreover, vector addition (such as Đ = Ả + 2B - F) includes principles such as scaling, displacement and direction, which are crucial in Physics for predicting the outcomes of combined vector forces.

Lastly, the reference to the mass m of an object cancelling in the equation for g is related to calculating the acceleration due to gravity on Earth, which does not depend on the mass of the falling object.

Answer 2
Final Answer:

In the previous question, m represents the measure of an angle, and without specific information about which angle in Δ DEF is being referred to, a precise value cannot be determined.

Explanation:

The symbol m in geometry typically denotes the measure of an angle. In the context of the given diagram, G being the incenter of Δ DEF suggests that G is the point where the angle bisectors of the triangle intersect. However, to determine the specific measure (m) of an angle, additional details about which angle in Δ DEF is being considered are required.

In geometry, the measure of an angle can vary based on its location within a triangle. The incenter is where the angle bisectors meet, ensuring that the angle formed by connecting G to the vertices of Δ DEF is bisected equally. Without information about the specific angle being referenced, a numerical value for m cannot be provided.

Understanding angle measures and the role of an incenter in bisecting angles is crucial in geometry. Precision in describing angles requires clarity on the specific angle under consideration, allowing for accurate calculations and conclusions.

In The Diagram Below, G Is The Incenter Of DEF. MIn The Previous Question, What Is M

Related Questions

Which must be true in order for the relationship △ZYV ~ △XWV to be correct?

Answers

z = to x
y = to w
v = to v
triangle ZYV is = to triangle XWV

∠Z ≅ ∠X and ∠W ≅ ∠Y is the correct answer

D

The solution set for -p^2 − 11p = 0 is

Answers

There are two solutions. If you factor a -p out of the equation, you can easily see this. (-p)(p + 11) = 0. The values of p that make this true are 0 and -11.

{0, -11}

Answer:

the solution set is {0,-11}

Step-by-step explanation:

The equation is [tex]-p^2-11p=0[/tex]

The GCF of the left hand side of the expression is -p. Hence, factored out the GCF

[tex]-p(p+11)=0[/tex]

Now, apply the zero product property, we get

[tex]-p=0,p+11=0[/tex]

Now, solve the equations for p

[tex]p=0,p=-11[/tex]

Thus, the solution set is {0,-11}

Answer correct for brainliest and also a thanks ! Don't answer if you don't know it please . CHOOSE ALL THAT ARE CORRECT .
Answer choices :
A. QP
B. EJ
C. PR
D. RA
E. TQ

Answers

Perpendicular is an object that is at 90 degrees of a surface (opposite of parallel).

Question: What edges are perpendicular to the edge QE?

This is slightly confusing because they didn't say if they have to be adjustant..I'm guessing not. It also is confusing because there are so many edges..

Edges perpendicular to QE:

QP, EH, PR, HA, QT, EJ, TR, JA

Edges that are perpendicular to QE that are options:

QP, EJ, PR, TQ


What is the greatest common factor of 84 and 108?

Answers

The greatest common factor would be 12.
The greatest common factor of 84 and 108 is 12.
Hope this helped!!

What does 4.87×10^12 equal?

Answers

I hope this helps you





487/100×10^12




487×10^-2×10^12



487×10^10

What is 2840 divided by 6 in long division

Answers

473.333333333 is the answer.

Hello. Im having problems in Geometry programming and I was wondering if there is anyway for someone to help me

Answers

There are loads of ways people can help. Just put the pic or (type the) question and voila! many people will help hopefully.. well those on your grade lvl! 

Good Luck!

the length of a rectangle is given by 2t+1 and its height is t^(1/2), where t is time in sec. Find the rate of change of the area with respect to time

Answers

A=(2t+1)t^1/2 differentiate both sides w.r.t t to get the solution

use the remainder theorem to divide 3x2+10x-8 by x-2 what is the remainder

Answers

The remainder is 24/x-2

Answer:

Remainder is 24.

Step-by-step explanation:

Given dividend = 3x² + 10x - 8

and divisor = x - 2

To find: Remainder using Remainder theorem.

Remainder Theorem states that let p(x) be any polynomial of degree greater than or equal to one and let a be any real number. If p(x) is divided by the linear polynomial x - a, then the remainder is p(a).

Let p(x) = 3x² + 10x - 8

using remainder theorem,

Remainder = p(2) = 3 × 2² + 10 × 2 - 8

                  = 3 × 4 + 20 - 8

                  = 12 + 12

                  = 24

Therefore, Remainder is 24.

if Jane has 5 pairs of pants and 7 shirts, how many different combinations of pants and shirts are possible?

Answers

Jane has 5 pants and 7 shirts.

In order to find how many different combinations of pants and shirts we must multiply.

7 x 5 = 35

The answer is 35 combinations.

This method works when finding out the combinations of anything. Just multiply all the items together.

Number 7. I need to write a ladder diagram

Answers

Since, "27" isn't a 'prime number'.. you'll have to do: 3 × 3 × 3

27
/ \
/ \ \
3. 3 3

PLLEEAASSEE HELP ME!!!!! 20 POINTS AND BRAINLIEST ANSWER

Holly made fruit punch for an office party a few months ago; she used 1 gallon of strawberry juice and 3 gallons of watermelon juice, which cost her a total of $8. For today’s party, she used 3 gallons of strawberry juice and 2 gallons of watermelon juice, spending a total of $10. How much does a gallon of each type of juice cost? Write a system of equations to describe the situation and solve using elimination. (use x for strawberry juice and y for watermelon juice)

Answers

1x+3y=8
3x+2y=10

solve

multiply first equation by -3 and add to 2nd equation

-3x-9y=-24
3x+2y=10 +
0x-7y=-14

-7y=-14
divide by -7 both sides
y=2

sub back
x+3y=8
x+3(2)=8
x+6=8
minus 6
x=2

wow

both juices cost $2 per gallon

543,982 rounded to the nearest thousand

Answers

it would be 544,000

hope this helps you
544,000 hope this helps

Sally went into the local dollar store because they have so many deals .the following deal that she was debating is 4 bars of soap that cost $5 .what would 8 bars cost her

Answers

8 is twice 4, so ten dollars because that is $5 twice


A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in! Her father immediately jumped on his scooter to try and track her down and tell her the good news. Riding at a breezy 15 miles per hour, at what time will her father catch up to her?

Answers

The first step is:
- determine how far from the house is young equestrian at noon. 
2 x 10 = 20 miles
15 t = 20 + 10 t
15 t - 10 t = 20
5 t = 20
t = 20 : 5
t = 4 hours
Answer: at 4:00 PM
Final answer:

The equestrian's father will catch up to her at 2:00 pm by using the concept of relative speed and calculating the time it will take for him to close the gap between them.

Explanation:

The student's father will catch up to the equestrian at 2:00 pm. To solve this problem, we can use the concept of relative speed. The equestrian starts riding away from the house at 10 miles per hour (mph) at 10:00 am. By noon, when the father starts chasing her on his scooter at 15 mph, the equestrian is already 20 miles away (2 hours × 10 mph).

Since the father's speed is 15 mph and the equestrian's speed is 10 mph, the father is closing the gap at a speed of 15 mph - 10 mph = 5 mph. To cover the 20 miles gap, the father will need 20 miles / 5 mph = 4 hours. Therefore, if the father starts at noon, he will catch up to her at 4 hours later, which is 2:00 pm.

Factor 25x2 – 16.

A. (5x – 4)2
B. (5x + 1)(5x – 1)
C. (5x + 4)2
D. (5x + 4)(5x – 4)

Answers

The answer is D. (5x+4) (5x-4)

What I did was multiply. So the first step I did was take 5x and mutiplied it by 5x which gave me 25x2. Then after that I took 5x and muliplied it by -4 which gave me -20x. 

The second step was taking 4 and multiplied it by 5x which would be +20x and then 4 x -4 would be -16 so when you write it down your problem is gonna be like this: 25x2 - 20x +20x -16

Last step! is to cross out both 20x's cause it's going to be 0 but the thing is you do not put the 0 in just leave it blank so your answer is 25x2 - 16. Hope this helps! :)

~Shadow

Answer:

D. (5x + 4)(5x – 4)

Step-by-step explanation:

This is the difference of two squares

[tex]a^{2} - b^{2}  = (a-b)(a+b)\\[/tex]

Following from above,

25[tex]25x^{2} -16[/tex]

Taking the elements of the expression

[tex]25x^{2} = 5^{2}x^{2}[/tex]

Using the law of indices,

[tex]a^{2} b^{2} = (ab)^{2}[/tex]

[tex]25x^{2} = (5x)^{2}[/tex]

[tex]16 = 4^{2}[/tex]

Therefore,

[tex]25x^{2} -16[/tex] =  [tex](5x)^{2}  - 4^{2}[/tex]

=[tex](5x-4)(5x+4)[/tex]

Hence the correct answer is Option D.

The total fare for two adults and three children on an excursion boat is $14. If each childs fare is one half of each adults fare, what is the adult fare ...?

Answers

Make each adult x and each kid 5x
 and
set equal to 14.
 so it would be
 3.5x=14.
 14/3.5 = 4
so
x  = 4.
 adult tickets are 4$ while kids are 2$

Answer:

$4

Step-by-step explanation:

In order to solve this problem you just have to create an equation, and it´s very simple, each kid ticket will be represented by the letter "x", and as we know a kid´s ticket is worth half what is worth an adult ticket, so the adult ticket = 2 kids tickets=2x

So we know that there are 2 adults and three kids, and the totla was $14, we create our equation:

[tex]2 adults+3kids=14\\2(2x)+3x=14\\4x+3x=14\\7x=14\\x=\frac{14}{7}\\ x=2[/tex]

Now we know that the kids ticket is $2, so the adult ticket would be twice that, $4 is the price of the adult ticket.

What is the volume of a rectangular prism that has a length, width, and height of 1/2 m, 1/4 m, and 2/3 m, respectively?

Answers

V = L * W * H
V = (1/2)(1/4)(2/3) 
V = (1 * 1 * 2) / (2 * 4 * 3)
V = 2/24 reduces to 1/12 m <===

What is the maximum number of intersection points a hyperbola and a circle could have?

A. 4
B. 3
C. 1
D. 2 ...?

Answers

The right option is 4.

Answer: A. 4


Step-by-step explanation:

The characteristic equation of a circle is

[tex]x^2+y^2=r^2[/tex]

The characteristic equation of a hyperbola is

[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]

The intersection points will be obtained as the solution of the both characteristic equations.

[tex]x^2+y^2=r^2[/tex].......(1)

[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex].............(2)

⇒[tex]y^2=r^2-x^2[/tex].....(from 1)

put this in (2)

[tex]\frac{x^2}{a^2}-\frac{r^2-x^2}{b^2}=1[/tex]

⇒[tex]y^2=r^2-x^2\\\frac{x^2}{a^2}+\frac{-x^2}{b^2}=1+\frac{r^2}{b^2}[/tex]

⇒[tex]y^2=r^2-x^2\\x^2(\frac{1}{a^2}+\frac{1}{b^2})=1+\frac{r^2}{b^2}[/tex]

⇒[tex]y^2=r^2-x^2\\x^2(\frac{a^2+b^2}{a^2b^2})=\frac{b^2+r^2}{b^2}[/tex]

[tex]\Rightarrow\ x^2=\frac{a^2(b^2+r^2)}{a^2+b^2}\\y^2=\frac{b^2(r^2-a^2)}{a^2+b^2}[/tex]

So there are 2 different values of x and two different values of y, thus the maximum number of intersection points  is 4.

AB is tangent to the circle at B m< A = 14 and mBC = 112 (The figure is not drawn to scale.

a.Find x

b.Find y.

Answers

a. The value of x ≈ 60°

b. The value of y ≈ 93°

The relevant relations are ...

external angle A is half the difference of intercepted arcs BC and BD

inscribed angle y° is half the measure of intercepted arc CD

the sum of arcs of a circle is 360°

Using these relations, we have ...

(a) A = (BC -x°)/2

x° = BC -2A = 112° -2(27°)

x° = 58°

(b) y° = CD/2 = (360° -BC -BD)/2 = (360° -112° -60°)/2

y° = 91°

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Mary and tom were buying a present for their mother on mothers day. mary spent $12 and tom spent $28 if they wanted to share the cost equally, how much money does mary owe tom?

Answers

16 dollars is how much mary owes tom

12 + 28 = 40...so they spent $40. To make it even, they would have to spend (40/2) = 20 bucks a piece.

Tom spent 28 ......Mary spent 12...if Tom lends Mary 8 bucks, they will have both spent 20. So Mary owes Tom 8 bucks

Convert 11-4x=(3x-2)^2 1 to standard form?

Answers

9x² - 8x - 6 is the answer

Gina invests $1,677 in an account paying 8.61% simple interest annually. How much interest has Gina gained after six years? a. $668.65 b. $240.65 c. $866.34 d. $2,543.34

Answers

Answer:

Option (c) is correct.

The interest gained by Gini in 6 years is $ 866.34

Step-by-step explanation:

Given: Gina invests $1,677 in an account paying 8.61% simple interest annually for 6 years.

We have to calculate the interest gained by Gina in 6 years.

Using formula for simple interest

[tex]S.I.=\frac{P\times I\times T}{100}[/tex]

Where,

S.I = simple interest

P is principal

R is interest rate

T is time  

Given : P = $ 1677

R = 8.61%

T = 6 years

Substitute, we get,

[tex]S.I.=\frac{1677\times 8.61\times 6}{100}[/tex]

Simplify, we get,

S.I. = $ 866.3382

Rounding off to nearest hundred  we get, Interest is $866.34

Thus, the interest gained by Gini in 6 years is $ 866.34

Gina has gained $866.34 in interest after six years.

To find the interest gained, we can use the formula: Interest = Principal * Rate * Time. In this case, the principal is $1,677, the rate is 8.61%, and the time is 6 years. Plugging these values into the formula, we get: Interest = $1,677 * 0.0861 * 6 = $866.34. Therefore, Gina has gained $866.34 in interest after six years.

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2. A bowling alley charges $3.00 to rent shoes and $1.50 per game bowled.

Answers

3+1.50n would be an expression for this

Which expressions are equivalent to the one below? Check all that apply.

10x
A. 50x/5x
B. 10 • 10x - 1
C. 10 • 10x + 1
D. 50x/5
E. (50/5)x
F. x5

Answers

A ) is not correct because x/x = 1 so you get 10 and not 10x
B) is not correct because 10*10x - 1 = 100x - 1 which is not 10x
C) simillar as B. Not correct
D) is correct. 50x/5 is same as 50/5*x = 10x
E) correct. Straight forward. 50/5 = 10 and when multiplied by x gets 10x
F) x5 or 5x however it is meant to be written is not 10x

The answer is A, B, and  E.

Just plot write the equation in a graphing calculator which shows they are the same.

Mark and John were sharing the $10 cost to rent some video games with another friend. Mark paid $3, John paid of the total, and their friend paid the rest. Who paid the most towards the rental?

Answers

Final answer:

John paid the most towards the rental.

Explanation:

To determine who paid the most towards the rental, we need to find out how much each person paid. Mark paid $3 and John paid <percentage> of the total. Their friend paid the remaining amount. Since the total cost to rent the video games was $10, we can calculate how much John paid by subtracting what Mark paid from $10 and finding the percentage of that remaining amount.

Subtracting $3 from $10 gives us $7. Since John paid the majority, we can say that he paid 70% of the total. Therefore, John paid the most towards the rental.

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A-Team Corporation issued 1,000 shares of $5 par value stock for land. The stock is actively traded at $9 per share. The land was advertised for sale at $10,500. The land should be recorded at:
A.$4,000.
B.$5,000.
C.$9,000.
D.$10,500.

Answers

The land was advertised for sale at $10,500. The land should be recorded at $ 9,000. Below is the solution:

USD 9,000 = 1000 x USD 9

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The price of a coat is $114 before sales tax . The sales tax is 7%. Find the total cost of the coat

Answers

121.98 114 + 7%= 121.98
that is your answer

Final answer:

To calculate the total cost of the coat with a 7% sales tax, multiply the cost of the coat by 0.07 to get the sales tax amount of $7.98, then add it to the original cost for a total of $121.98.

Explanation:

To find the total cost of a coat that costs $114 with a 7% sales tax, you first need to calculate the amount of sales tax by converting the percentage to a decimal. Then multiply the decimail by the price of the coat to get the sales tax amount.

Here is the calculation for sales tax:

$114 × 0.07 = $7.98

Next, add the sales tax to the original price to find the total cost:

$114 + $7.98 = $121.98

So, the total cost of the coat, including sales tax, is $121.98.

A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment
70 ML of the 50% solution and 35 ML of the 80% solution
35 ML of the 50% solution and 70 ML of the 80% solution
70 ML of the 50% solution and 70 ML of the 80% solution
35 ML of the 50% solution and 35 ML of the 80% solution

Answers

How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment?

1. Look at how 60% is closer to the solution of lower concentration (50%). You can deduce that you will be mixing a higher volume of the 50% solution.

2. All 4 answers add up to 105ml.

3. The intuitive answer is the first option:
70 ML of the 50% solution and 35 ML of the 80% solution

4. Let's check whether point 3 is true.
70ml/105ml X 0.5 + 35ml/105ml X 0.8 = (35 + 28)/105= 63/105= 60% / 105 ml = 105ml of 60% sugar solution

solve the seperable equation:
dy/dx= (sec^2)y/1+x^2

Answers

cos^2(y)dy=(1/1+x^2)dxy/2+sin(2y)/4=aractan(x)+C2y+sin(2y)=arctan(x)+C
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