In a glide reflection, what comes first and what comes second?

Answers

Answer 1

Answer:

A glide reflection is a composition of transformations.In a glide reflection, a translation is first performed on the figure, then it is reflected over a line. Therefore, the only required information is the translation rule and a line to reflect over. ... The first one is a translation rule.

Answer 2

Final answer:

In a glide reflection, the translation occurs first, moving the figure along a straight line, followed by a reflection over a line parallel to the translation vector, resulting in a figure that has been moved and potentially reoriented.

Explanation:

In a glide reflection, a transformation that combines a translation with a reflection, the proper sequence is important. The translation part comes first, where the figure is slid along a straight line called the translation vector. After the figure has been moved, the second step is the reflection over a line parallel to the vector of the translation. This two-step process results in a final image that has the same size and shape as the original figure but is in a different position and may have a different orientation.

Imagine a point undergoing a glide reflection. Initially, it is translated along a vector, and then it is reflected across a line that is parallel to the direction of translation. The end result is that the point has 'glided' to a new location, as if it had slid across a mirror placed at an angle to its original path.


Related Questions

What should be the next letter in the following series? A z e b i y o _ ?_

Answers

Answer:  c

Step-by-step explanation:

Notice the pattern (vowel, consonant, vowel, consonant):

A: first vowel            z: last consonant

e: second vowel                                        b: first consonant      

i: third vowel             y: second to the last consonant

o: fourth vowel                                           c: second consonant

The quoient of two rational numbers is positive. What can you conclude about signs of the dividend and the divisor?

Answers

Answer:

  the two signs are the same

Step-by-step explanation:

Whenever the quotient or product of two operands is positive, the signs of the operands are both the same, both negative or both positive.

__

Comment on the general case

Whenever the product of any number of operands is positive, the number of negative signs among the factors is even.

A quotient is the product of one operand and the reciprocal of another (the denominator). A number and its reciprocal have the same sign.

Two bags contain blue and red marbles. The first bag contains 3 blue and 5 red marbles. The second bag contains
2 blue and 4 red marbles. A marble is drawn from each bag. What is the probability that both marbles are blue?​

Answers

Answer: 1/8

Step-by-step explanation:

First Bag   and      Second Bag

[tex]\dfrac{3\ blue}{8\ total}[/tex]        x            [tex]\dfrac{2\ blue}{6\ total}[/tex]        =  [tex]\dfrac{6}{48}[/tex]

which reduces to [tex]\boxed{\dfrac{1}{8}}[/tex]


15. Find the area of a triangle with a base of 10 in. and an altitude of 14 in. (The formula for the area of a triangle is A = bh ÷ 2.)

A. 280 sq in.
B. 24 sq in.
C. 70 sq in.
D. 140 sq in.

Answers

Hello There!

We know that the formula of a triangle is "Base Multiplied By Height And Then Divide It By 2"

First, let's plug in our numbers. Our base is going to be 10 inches so we have 10 multiplied by our height which is 14 inches and we get a product of 140.

Next, we divide 140 by 2 to get a quotient of 70.

Finally, our answer is 70in squared

Base = 10 inches
Height = 14 inches

(Base x Height) ÷ 2 = Area
(10 x 14) ÷ 2 = Area
(140) ÷ 2 = Area
70 = Area

Area = 70 square inches

Need help with a math question

Answers

Answer:

[tex]z =3\sqrt{13}[/tex]

Step-by-step explanation:

In the figure you can identify up to 3 straight triangles.

To solve the problem, write the Pythagorean theorem for each triangle.

Triangle 1

[tex]13^2 = z^2 + x^2[/tex]

Triangle 2

[tex]z^2 = y^2 + 9^2[/tex]

Triangle 3

[tex]x^2 = y^2 + 4^2[/tex]

Now substitute equation 2 and equation 3 in equation 1 and solve for y.

[tex]13^2 = y^2 + 9^2 + y^2 + 4^2[/tex]

[tex]13^2 = 2y^2 + 9^2 + 4^2[/tex]

[tex]169 = 2y^2 + 81 + 16[/tex]

[tex]2y^2 =72[/tex]

[tex]y^2 =36[/tex]

[tex]y =6[/tex]

substitute the value of y in the second equation and solve for z

[tex]z^2 = 6^2 + 9^2[/tex]

[tex]z^2 = 36 + 81[/tex]

[tex]z^2 = 117[/tex]

[tex]z = \sqrt{117}[/tex]

[tex]z =3\sqrt{13}[/tex]

Given: △ABC is equilateral. The radius of each circle is r. Find: AB

Answers

Answer:

2r (1 + √3)

Step-by-step explanation:

Circle O₁ is tangent to AB.  Let's call the point of intersection point D.  If we draw a radius from the center O₁ to D, we know this forms a right angle.

△ABC is an equilateral triangle, so we know m∠A = 60°.  If we draw a line from A to O₁, we know that bisects the angle, so m∠DAO₁ = 30°.

So △DAO₁ is a 30-60-90 triangle.  We can find the length AD:

AD = r √3

Now on the other side, circle O₃ is tangent to AB.  Let's call the point of intersection point E.  We know it's the same triangle we found earlier, so:

EB = r √3

And finally, we can draw a rectangle connecting O₁, O₃, E, and D.  The distance between O₁ and O₃ is 2r, so:

DE = 2r.

Therefore:

AB = r√3 + 2r + r√3

AB = 2r√3 + 2r

AB = 2r (1 + √3)

Here's a graph showing the steps.  Hopefully this helps, let me know if you have questions!

desmos.com/calculator/hgaonfzxsm

what is the measure of DEF

Answers

Answer:

The measure of arc DEF is 204° ⇒ answer C

Step-by-step explanation:

* Lets talk about some facts in the circle

- If the vertex of an angle on the circle and the two sides of the

 angle are chords in the circle, then this angle is called  

 an inscribed angle

- Each inscribed angle subtended by the opposite arc, the arc name

 is the starting point and the ending point of the angle

- The measure of any circle is 360°

# Ex: ∠CAB is inscribed angle subtended by arc CB

- There is a relation between the inscribed angle and its  

  subtended arc, the measure of the inscribed angle equals half

  the measure of its subtended arc

* Now lets solve the problem

- ∠DEF is an inscribed angle subtended by arc DF

∴ m∠DEF = (1/2) measure of arc DF

∵ The measure of ∠DEF = 78°

∴ 78° = (1/2) measure of arc DF ⇒ multiply both sides by 2

∴ The measure of arc DF = 78° × 2 = 156°

∵ The measure of arc DF + The measure of arc DEF = The measure of

   the circle

∵ The measure of the circle = 360°

∵ The measure of the arc DF = 156°

∴ 156° + measure of arc DEF = 360° ⇒ subtract 156 from both sides

∴ The measure of arc DEF = 360° - 156° = 204°

* The measure of arc DEF is 204°

Answer: OPTION C.

Step-by-step explanation:

By definition:

[tex]Inscribed\ Angle = \frac{1}{2} Intercepted\ Arc[/tex]

Then we can calculate the measure of DF. This is:

[tex]78\°=\frac{1}{2}DF\\\\DF=(2)(78\°)\\\\DF=156\°[/tex]

We know that there are 360 degrees in a circle, therefore, in order to find the measure of DEF, we need to make the following subtraction:

[tex]DE[/tex][tex]F[/tex][tex]=360\°-156\°[/tex]

[tex]DE[/tex][tex]F[/tex][tex]=204\°[/tex]

 You can observe that this matches with the option C.


A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude of 41,000 feet. Model the most fuel-efficient altitudes using a compound inequality.

x ≥ 29,000 and x ≤ 41,000
x ≤ 29,000 and x ≥ 41,000
x ≥ 41,000 and x ≥ 29,000
x ≤ 41,000 and x ≤ 29,000

Answers

Answer:

[tex]x\geq 29,000[/tex]  and  [tex]x\leq 41,000[/tex]

Step-by-step explanation:

Let

x -----> the altitude of a commercial aircraft

we know that

The expression " A minimum altitude of 29,000 feet" is equal to

[tex]x\geq 29,000[/tex]

All real numbers greater than or equal to 29,000 ft

The expression " A maximum altitude of 41,000 feet" is equal to

[tex]x\leq 41,000[/tex]

All real numbers less than or equal to 41,000 ft

therefore

The compound inequality is equal to

[tex]x\geq 29,000[/tex]  and  [tex]x\leq 41,000[/tex]

All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft

The solution is the interval ------> [29,000,41,000]

option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using compound inequality.

We need to identify the correct compound inequality describing the altitude at which the aircraft operates most efficiently. The best fuel efficiency altitudes range from 29,000 ft to 41,000 ft, meaning the altitude must be at least 29,000 ft and at most 41,000 ft.

So, to represent that the altitude must be at least 29000 ft we use the mathematical expression:

[tex]x\geq 29,000[/tex]

To represent that the altitude must be 41000 ft at most we use the mathematical expression:

[tex]x\leq 41,000[/tex]

These two expression can be represented as a compound inequality as follows:

[tex]x\geq 29,000\[/tex] and [tex]x\leq 41,000[/tex]

Therefore, option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using a compound inequality.

If the given sequence is a geometric sequence, find the common ratio.

3/3, 3/12, 3/48, 3/192, 3/768

a. 4

b. 1/30

c. 30

d. 1/4

Answers

Answer:

  d.  1/4

Step-by-step explanation:

The ratio of adjacent terms is the common ratio:

  (3/12)/(3/3) = 3/12 = 1/4

Please answer this question correctly for 30 points and brainliest!!

Answers

Answer:

  22 quarters

Step-by-step explanation:

Let q represent the number of quarters in the bank. Then 60-q is the number of nickels, and the total value of the coins is ...

  0.25q + 0.05(60 -q) = 7.40

  0.20q + 3.00 = 7.40 . . . . . . . . simplify

  0.20q = 4.40 . . . . . . . . . . . . . . subtract 3.00

  q = 4.40/0.20 = 22 . . . . . . . . . divide by the coefficient of q

There are 22 quarters in the piggy bank.

_____

Check

The other 60-22 = 38 coins are nickels, so the total value is ...

  0.25×22 + 0.05×38 = 5.50 + 1.90 = 7.40 . . . . . . the required amount

Step-by-step answer:

Here's a different way to solve the problem, mentally.

Mixture of 60 coins composed of nickels (5 cents) and quarters (25 cents).

Total value = 7.40.

IF all coins were quarters, value would be 60*0.25 = $15

That makes too many quarters.

To conform to the value of $7.40, we need to reduce the mix by $15-7.40 = 7.60.

Each exchange of quarters and nickels reduces the value by $0.25-0.05=0.20.

It takes 7.60 / 0.20 = 38 exchanges.

So there are 38 nickels and 22 quarters.

Please explain how you got this answer.

-Aparri

Answers

Answer:

She got a 87 on her chemistry test

Step-by-step explanation:

(72 + 85 + 92 + x)/4 = 84

249 + x = 336

x = 87

A salesperson obtained a systematic sample of size 20 from a list of 500 clients. to do​ so, he randomly selected a number from 1 to 25​, obtaining the number 18. he included in the sample the 18th client on the list and every 25th client thereafter. list the numbers that correspond to the 20 clients selected

Answers

Final answer:

The salesperson selected clients 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493 through systematic sampling from a list of 500 clients.

Explanation:

This is a question related to systematic sampling, which is a statistical method where elements are selected from an ordered sampling frame. In this case, the 20 clients were selected beginning with the 18th client and then continuing every 25th client.

To find the specific client numbers selected, we would follow the pattern by adding 25 to the prior number starting from 18. Keep adding until you reach 20 numbers. Let me list them for you:

18 (Starting client) 43 (18 + 25) 68 (43 + 25) 93 (68 + 25) 118 (93 + 25) 143 (118 + 25) 168 (143 + 25) 193 (168 + 25) 218 (193 + 25) 243 (218 + 25) 268 (243 + 25) 293 (268 + 25) 318 (293 + 25) 343 (318 + 25) 368 (343 + 25) 393 (368 + 25) 418 (393 + 25) 443 (418 + 25) 468 (443 + 25) 493 (468 + 25)

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Final answer:

The salesperson used systematic sampling to select clients from the list. Starting with the 18th client, the salesperson then selected every 25th client thereafter. The client numbers selected were 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493.

Explanation:

In this scenario, the salesperson obtained a systematic sample by first selecting the 18th client and then every 25th client thereafter from a list of 500 clients. This method of sampling is called systematic sampling. It's a type of sampling where we select items from an ordered population using a fixed, periodic interval after a random start. So, the numbers of the clients selected would be: 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493.

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Rebecca buys a table that was priced $650. There is a 8% sales tax in her state. Fortunately, it was 25% off! So she only
paid $:

Answers

Answer:

$526.50

amount×discount=?

650×.25= 162.5

total-discount=?

650-162.5= 487.5

new amount×sales tax=?

487.5×.08= 39

new amount+tax=total

487.5+39= 526.5

Total=$526.50

Divide the binomial by the monomial to find the quotient.

48x^4y-72x^6y^2
-------------------------
-12x^2y

Answers

Answer:

  -4x² +6x⁴y

Step-by-step explanation:

Deal with it term by term, factor by factor.

[tex]\dfrac{48x^4y-72x^6y^2}{-12x^2y}=\dfrac{48x^4y}{-12x^2y}+\dfrac{-72x^6y^2}{-12x^2y}\\\\=\dfrac{48}{-12}\cdot\dfrac{x^4}{x^2}\cdot\dfrac{y}{y}+\dfrac{-72}{-12}\cdot\dfrac{x^6}{x^2}\cdot\dfrac{y^2}{y}=-4x^2+6x^4y[/tex]

Final answer:

To divide the binomial by the monomial, divide each term's coefficients and subtract their exponents, resulting in the quotient [tex]-4x^2 + 6x^4y[/tex].

Explanation:

To divide the given binomial by the monomial, we divide each term in the numerator by the term in the denominator. In this case, we need to divide both terms of the binomial [tex]48x^4y - 72x^6y^2[/tex] by the monomial[tex]-12x^2y[/tex]. This involves dividing the coefficients (the numbers in front of the variables) and subtracting the exponents for like bases according to the rules of division of exponentials.

Starting with the first term:

[tex]\frac{48x^4y}{ -12x^2y} = -4x^{(4-2)}y^{(1-1)} = -4x^2y^0 = -4x^2[/tex]

Now the second term:

[tex]\frac{-72x^6y^2}{-12x^2y } = 6x^{(6-2)}y^{(2-1)} = 6x^4y[/tex]

The final quotient of dividing the binomial by the monomial is:

[tex]-4x^2 + 6x^4y[/tex]

If an object is dropped from a height of 144 feet, the function h(t) = -16t2 + 144 gives the height of the object after t seconds. When will the object hit the ground?

Answers

Answer:

3 seconds is correct.

Step-by-step explanation:

The object hit the ground at 3 seconds

What are equations?

An equation is a mathematical statement which equate two algebraic expressions. An equation has an equal to (=) sign in between the expression.

How to find when will the object hit the ground?

According to the problem,

An object is dropped from a height of 144 feet

The given function is h(t) = -16t2 + 144.

When the object reaches the ground h(t) becomes 0

So, the equation will be 0 =  -16t2 + 144.

Solving the equation we get t = 3 seconds

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What is the length of the missing side? What is the area of the figure?
Show ALL work.​

Answers

Answer:

Missing side=25 units.

Area of the figure= 470 sq units.

Step-by-step explanation:

The figure is made up of a rectangle and a triangle.

To get the base of the triangle, we find the difference between the two parallel sides, that is, 16ft and 31 ft.

31ft-16ft=15ft  

The height of the triangle is 20 since it is parallel and equal to the length of the rectangle.

We therefore use pythagoras theorem to find ?

a²+b²=c²

15²+20²=c²

625=c²

c=25

ii. The figure is a trapezium therefore we use the following formula to find the area.

A= 1/2(a+b)h, where a and b are the two parallel sides. and h the distance between them.

=(1/2)(31+16)×20

=470 sq units

Below is the beginning of the construction of a line parallel to the y-axis through point P. What is the next step of this construction?


A. Measure the distance from the intersection of the transversal to point P.

B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis.

C. Draw another transversal.

D. Connect the arc intersections using a straight edge.

Thanks!

Answers

Answer:

  B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis

Step-by-step explanation:

Creating a parallel line through a point involves copying the angle a transversal makes with the given line. The copied angle has the given point as its vertex, and the transversal as one side.

Copying an angle uses the steps of ...

draw an arc through the sides of the given angledraw an arc with the same radius centered at the new vertex...

The step this question is referring to is the first bullet above. The given angle is the angle between the transversal and the y-axis.

NEED HELP FAST PULEASEE

Please help fast asap

What is the probability of drawing three black cards, one at a time with replacement, from a standard deck of 52 cards?


A.'3/52

Its not b

C.1/8

d.75/676


Need help fasttt

GIve p(6,6) and q=(-5,-3) find the magnitude of 2p+3q



A.2 sqr3


B. 3 sqr2


its not C


D.14



According to NFL statistics, the Cincinnati Bengals will lose 13 out of 16 games, regardless of opponent. What are the odds of Cincinnati losing a game?



A.3;13


its not b


C.13;3


D16;13



Determine which trigonometric function to use to solve for the hypotenuse. Then,


solve for the length of the hypotneuse.

b=9

A=55.8


A.cosin, .062

B.sin,10.8

C.sin,16.0

its not D

Answers

Answer:

6

Step-by-step explanation:

Combine Radicals/Fractional Exponents

Image Below, Will Give Brainliest~

What is the product of a b and c

Answers

[tex]\mathsf{Given :\;\;\dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{64x^3y^3}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{4^3x^3y^3}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{(4xy)^3}}}[/tex]

[tex]\bigstar\;\;\textsf{We know that : \boxed{\mathsf{\sqrt[n]{a} = a^{\dfrac{1}{n}}}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{(4xy)^{\dfrac{3}{3}}}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{4xy}}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) \left(\dfrac{x^{\dfrac{-3}{2}}}{{x}}\right)\left(\dfrac{y^{-2}}{y}\right)}[/tex]

[tex]\bigstar\;\;\textsf{We know that : \boxed{\dfrac{a^m}{a^n} = a^{m - n}}}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3}{2} - 1\right)}}y^{(-2 - 1)}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3 - 2}{2}\right)}}y^{-3}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-5}{2}\right)}}y^{-3}}[/tex]

[tex]\textsf{Comparing the above with $\mathbf{ax^by^c}$, We can notice that :}[/tex]

[tex]\bigstar\;\;\mathsf{a = \dfrac{5}{4}}[/tex]

[tex]\bigstar\;\;\mathsf{b = \dfrac{-5}{2}}[/tex]

[tex]\bigstar\;\;\mathsf{c = -3}[/tex]

[tex]\implies \mathsf{Product\;of\;a,\;b\;and\;c = \left(\dfrac{5}{4}\times \dfrac{-5}{2} \times -3\right)}[/tex]

[tex]\implies \mathsf{Product\;of\;a,\;b\;and\;c = \dfrac{75}{8}}[/tex]

The cost of a long-distance phone call is $0.45 for the first minute and $0.36 for each additional minute. If the
total charge for a long-distance call is $6.93, how many minutes was the call?
The call was for
minutes.

Answers

Answer:

19 minutes

Step-by-step explanation:

cost = .45+.36m

If we take 6.93 minus .45 for the minute, we get 6.48. We take 6.48 and divide it by .36 for each additional minute, which is 18. We take the 18 and add one more minute to it since .45 was covered for the first minute.

Final answer:

The long-distance phone call that cost $6.93 was 19 minutes long. This was calculated by first deducting the cost of the first minute from the total cost, then dividing the remaining cost by the cost of each additional minute, and finally adding back the first minute.

Explanation:

The subject of this question is mathematics, and it involves understanding the cost structure of a long-distance phone call. So here's how we solve the problem:

Subtract the first minute's cost from the total cost. So, $6.93 - $0.45 = $6.48.Then divide the remaining total by the cost of each additional minute. So, $6.48 / $0.36 = 18 additional minutes.Last, add back in the first minute that we subtracted at the start. So, 18 minutes + 1 minute = 19 minutes total.

Therefore, the duration of the long-distance phone call that cost $6.93 was 19 minutes.

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If tuvw is an an isoaceles trapezoid with tu parallel to wv, name a pair of similar traingles. Explain

Answers

Answer:

  TUW ~ UTV, TWV ~ UVW

Step-by-step explanation:

An isosceles trapezoid is symmetrical about the perpendicular bisector of its bases. A triangle formed by deleting a vertex on one side of that line of symmetry will be similar to the corresponding triangle formed by deleting the symmetrically opposite vertex on the other side. The two pairs listed above are the possibilities.

How does the graph of y= sec(x-2)+2 comparé to the graph of y= sec(x) ?

Answers

Answer:

The function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards., compared to y=sex(x).

Step-by-step explanation:

To solve this problem we need to know the rules for translation of graphs:

Given the function y = f(x):

y=f(x-a) is the same graph shifted 'a' units to the right. If 'a' is negative, then, the graph is shifted to the left. y = f(x) - a is the same graph, but shifted 'a' units downwards. If 'a' is negative, then the graph will be shifted upwards.

In this case, our main function is y=sec(x). And the function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards.

Answer:

D. it is shifted two units up and two units right

Step-by-step explanation:

this is the correct answer on ed-genuity, hope this helps! :)

Daniel is packing his bags for his vacation. He has 5 unique socks, but only 4 fit in his bag How many different groups of 4 socks can he take

Answers

Answer:

5

Step-by-step explanation:

Someone please help me with this...

Answers

Answer:

The total number of points you score is dependent variable Because it change when x is change.

The number of question you answer correctly is independent variable Because it can change itself when you got more correct answers.

The top put a dot for dependent variable,
The bottom put independent variable.

Hope this helps!

In △ M N O , points R and T are the midpoints of their respective sides. MT and OR intersect at point C.

1. 14 units

2. None of the listed answers are correct

3. 15 units

4. 16.5 units

5. 12.5 units

Answers

Answer:

  3.  15 units

Step-by-step explanation:

When medians intersect, the point of intersection divides the median into parts in the ratio 2:1. That is ...

  OC : CR = 2 : 1 = 4 units : 2 units . . . . . . OR = (4+2) units = 6 units

  MC : CT = 2 : 1 = 6 units : 3 units . . . . . . MT = (6+3) units = 9 units

The sum of lengths OR + MT is ...

  6 units + 9 units = 15 units

Final answer:

The given question is incomplete. Without information about dimensions or additional information of the triangle or the lines, we cannot solve for lengths.

Explanation:

Unfortunately, the question is incomplete, so it is impossible to answer it accurately. In the given situation, we have a triangle △MNO and points R and T are the midpoints of their respective sides. The lines MT and OR intersect at a point C. However, without explicit dimensions or additional information about the triangle or the lines, we cannot determine the length of any line segment. In geometry problems like this, it's crucial to have a complete set of given information before proceeding with the solution.

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Match each function formula with the corresponding transformation of the parent function y = (x - 1)2 1. y = - (x - 1)2 Reflected over the y-axis 2. y = (x - 1)2 + 1 Reflected over the x-axis 3. y = (x + 1)2 Translated right by 1 unit 4. y = (x - 2)2 Translated down by 3 units 5. y = (x - 1)2 - 3 Translated up by 1 unit 6. y = (x + 3)2 Translated left by 4 units

Answers

Answer:

y = -(x-1)² . . . . reflected over the x-axisy = (x-1)² +1 . . . . translated up by 1 unity = (x+1)² . . . . reflected over the y-axisy = (x-2)² . . . . translated right by 1 unity = (x-1)² -3 . . . . translated down by 3 unitsy = (x+3)² . . . . translated left by 4 units

Step-by-step explanation:

Since you have studied transformations, you are familiar with the effect of different modifications of the parent function:

f(x-a) . . . translates right by "a" unitsf(x) +a . . . translates up by "a" unitsa·f(x) . . . vertically scales by a factor of "a". When a < 0, reflects across the x-axisf(ax) . . . horizontally compresses by a factor of "a". When a < 0, reflects across the y-axis.

Note that in the given list of transformed functions, there is one that is (x+1)². This is equivalent to both f(x+2) and to f(-x). The latter is a little harder to see, until we realize that (-x-1)² = (x+1)². That is, this transformed function can be considered to be either a translation of (x-1)² left by 2 units, or a reflection over the y-axis.

What is the opposite of squaring a number

Answers

The opposite of squaring a number is taking the square root. They are inverse operations.

The opposite of squaring a number is taking the square root of the number. They are inverse operations.

What is a perfect square?

A perfect square is a number system that can be expressed as the

square of a given number from the same system.

Perfect squares are those integers whose square root is an integer.

Let x-a be the closest perfect square less than x,

Let x-a be the closest perfect square less than x, and let x+b be the closest perfect square more than x, then we get x-a < x < x+b (no perfect square in between x-a and x+b, except possibly x itself).

Then, we get:

[tex]\sqrt{x-a} < \sqrt{x} < \sqrt{x+b}[/tex]

Thus, these are the closest integers, less than and more than the value of[tex]\sqrt{x}[/tex]. (assuming x is a non-negative value).

The opposite of squaring a number is taking the square root of the number. They are inverse operations.

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Solve: e^2x+5= 4 (for those who want the answer to this!)

Answers

Answer:

Step-by-step explanation:

With the way it is written, there are no values of x that make the equation true.

Ben drew 3 two-dimensional shapes that had II angles in all. Draw shapes Ben could have drawn.

Answers

The figure is attached to show the shapes Ben could have drawn

He could have drawn  2 four angled polygon , 1 triangle and  1 pentagon , 2 triangles .

What are Two Dimensional Shapes ?

The shapes which lie on two coordinate axis and has length ,and breadth are called Two dimensional shapes.

A polygon is included in two dimensional shapes.

It is given in the question that

Ben drew 3 two-dimensional shapes that had 11 angles in all.

11 angles mean

2 four angled polygon , 1 triangle

2 quadrilaterals ( rectangle , square , rhombus etc.) and a triangle

1 pentagon , 2 triangles

A figure is attached  for the above stated answer .

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Complete a two-column proof for each problem.






In a difficult position right now all help is welcomed tyty

Answers

Answer:

D is the midpoint of AC                          Given

∠BDC ≅ ∠BDA                                        Given

BD ≅ BD                                                   Reflexive Property

AD ≅ DC                                                   Definition of line segment bisector

ΔADB ≅ ΔCBD                                         CPCTC (Congruent Parts of                   Congruent Triangles are Congruent)

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