Answer:
It remains zero
Explanation:
The work done on an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force applied
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, the object is the wall, which is stationary. Therefore, the displacement of the wall is zero:
d = 0
And so, the work done is always zero, even if the force applied is twice as stronger.
Which of the following is considered to be a vector?
A. Temperature B. Velocity C. Time D. Mass
Answer: B) Velocity
Explanation:
Velocity is a vector quantity. Velocities have both magnitude and direction.
Answer:B. Velocity
Explanation:
How is heat transferred by conduction?
Answer:
solid form
Explanation:
Heat is transferred by conduction in a solid form.
Which could result from untreated diabetes check all that apply A .Asthma B. Numbness in hands and feet C.Exhaustion D.Weight loss E.Blurred vision
With the exception of Asthma, all of those things, and a lot more that you don't want, could result from untreated diabetes.
Answer:
B. Numbness In Hands and Feet
C. Exhaustion
D. Weight Loss
E. Blurred Vision
Nuclear fusion within the sun takes place within the
Answer:
Within the core
Explanation:
The core of the sun (and of every star) is the central part of the star, the hottest one.
Its temperature is about 10 million Kelvin degrees and more - and this temperature is enough to allow the nuclei of hydrogen to overcome the electrostatic repulsion between each other and come close enough to initiate the nuclear fusion.
The nuclear fusion is the process that produces energy in a star: in a nuclear fusion reaction, the nuclei of hydrogen fuse together to form nuclei of helium, and since the mass of the final products is less than the mass of the initial products, part of the mass is converted into energy, according to Einstein's famous equation
[tex]E=mc^2[/tex]
What percentage of water vapor is found in the air
Answer:
. The percentage water vapor in surface air varies from 0.01% at -42 °C (-44 °F) to 4.24% when the dew point is 30 °C (86 °F).
hope this helps :)
Explanation:
Answer:
0 to 4 percent
Explanation:
Water vapor varies by volume in the atmosphere from a trace to about 4%. Therefore, on average, only about 2 to 3% of the molecules in the air are water vapor molecules. The amount of water vapor in the air is small in extremely arid areas and in location where the temperatures are very low (i.e. polar regions, very cold weather). The volume of water vapor is about 4% in very warm and humid tropical air.
So, why can't the amount of water vapor in the air be greater than 4%? The answer is because temperature sets a limit to how much water vapor can be in the air. Even in tropical air, once the volume of water vapor in the atmosphere approaches 4% it will begin to condense out of the air (rain). The condensing of water vapor prevents the percentage of water vapor in the air from increasing. If temperatures were much warmer, there would be a potential to have more than 4% water vapor in the atmosphere. Think about the steam trapped in a tea kettle. The very warm temperatures and higher pressures allow for a large amount of water vapor to exist in the air within the tea kettle. Just from watching the steam leave the tea kettle, one can get an idea of the water vapor density within that kettle. The amount of water vapor within the air in the kettle is greater than 4%.
If the earth's oceans were placed on the planet Venus, the ocean water would boil into the atmosphere and produce a very dense steam (current surface temperatures on Venus are 900 degrees Fahrenheit with an average sea level pressure of 92,000 millibars, or 92 times that of Earth). Under this amount of enormous heat and pressure (hot enough to melt lead), water vapor would well exceed 4% of the atmosphere by volume. As a note, Venus does not have any significant amounts of water vapor; the atmosphere of Venus is 96% carbon dioxide and 3.5% nitrogen.
SO! Temperature determines the maximum amount of water vapor that can exist in the air. The higher the temperature, the greater the potential percentages of water vapor in the air, up to a maximum of approximately 4%.
Why are objects that fall near earth’s surface rarely in free fall?
Answer:
Because of the presence of air resistance
Explanation:
When an object is in free fall, ideally there is only one force acting on it:
- The force of gravity, W = mg, that pushes the object downward (m= mass of the object, g = acceleration of gravity)
However, this is true only in absence of air (so, in a vacuum). When air is present, it exerts a frictional force on the object (called air resistance) with upward direction (opposite to the motion of free fall) and whose magnitude is proportional to the speed of the object.
Therefore, it turns out that as the object falls, its speed increases, and therefore the air resistance acting against it increases too; as a result, the at some point the air resistance becomes equal (in magnitude) to the force of gravity: when this happens, the net acceleration of the object becomes zero, and so the speed of the object does not increase anymore. This speed reached by the object is called terminal velocity.
Answer: Gravity does not act on objects near Earth’s surface.
Explanation:
A man pushes on a trunk with a force of 250 newtons. The trunk does not move. How much positive work is done on the trunk?
0.0 J
-250 J
250 J
125 J
Answer:
F is 250 N
d is 0 m
F x d
=250 x 0
=0
The answer is 0.0 J.
Answer:
0.0 J
Explanation:
Are materials that dissolve in water hydrophobic or hydrophilic
Answer:
hydrophilic
Explanation:
hydrophobic means it hates water so a hydrophobic material would separate from the water and just sit there (an example of this is oil)
The mass of an electron is 9.11×10−31 kg. If the de Broglie wavelength for an electron in a hydrogen atom is 3.31×10−10 m, how fast is the electron moving relative to the speed of light? The speed of light is 3.00×108 m/s.
Answer: The electron moves slower than the speed of light
Explanation:
The de Broglie wavelength [tex]\lambda[/tex] is given by the following formula:
[tex]\lambda=\frac{h}{p}[/tex] (1)
Where:
[tex]h=6.626(10)^{-34}\frac{m^{2}kg}{s}[/tex] is the Planck constant
[tex]p[/tex] is the momentum of the atom, which is given by:
[tex]p=m_{e}v[/tex] (2)
Where:
[tex]m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg[/tex] is the mass of the electron
[tex]v[/tex] is the velocity of the electron (the value we want to find)
Substituting (2) in (1):
[tex]\lambda=\frac{h}{m_{e}v}[/tex] (3)
Finding [tex]v[/tex] :
[tex]v=\frac{h}{m_{e}\lambda}[/tex] (4)
[tex]v=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(3.31(10)^{-10}m/s)}[/tex] (5)
Finally:
[tex]v=2.197(10)^{6} m/s[/tex]>>> This is the velocity of the electron, which compared to the [tex]v=3(10)^{8} m/s[/tex] of the light is quite slower.
The electron's speed relative to the speed of light is calculated using the de Broglie wavelength formula, which determines the velocity of the electron. The formula is rearranged to solve for velocity and the given details are inserted into the formula to obtain the answer.
Explanation:The electron's speed can be determined in relation to the speed of light using the de Broglie wavelength formula, which states that an electron's wavelength equals Planck's constant (6.63 x 10^-34 m^2 kg/s) divided by the electron's momentum. Momentum is the product of mass and velocity. The speed of the electron is then calculated by rearranging the formula to solve for velocity.
Given:
de Broglie wavelength, λ = 3.31×10−10 m
Mass of electron, m = 9.11x10^-31 kg
Planck's constant, h = 6.63 x 10^-34 m^2 kg/s
Speed of light, c = 3.00×10^8 m/s
Calculation:
Velocity of the electron, v = h / (m * λ)
The velocity of the electron relative to the speed of light is therefore v/c.
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The focal length of a lens is determined by the curve of the lens and the material that the lens is made from. (5 points) is this true or false??
Answer:
true
Explanation:
if the lens is curved differently or the material is changed then it would affect where the image is which is calculated using the focal point.
sorry I know I'm late but please let me know if I'm right, mark brainliest, and have a great day :)
Which of the following represents an image that is located behind a mirror?
A. +di
B. -do
C. +do
D. -di
Explanation:
There are some conventions while solving the problems based on mirrors. All parameters are taken like x-y coordinate system.
All the measurements are done from the optical centre of the mirror.
[tex]d_i[/tex] is the image distance
[tex]d_o[/tex] is the object distance
[tex]-d_i[/tex] is the image distance which is formed behind the mirror.
[tex]-d_o[/tex] is the object distance when an object is placed behind the mirror.
So, [tex]-d_i[/tex] shows the image that is located behind the mirror. Hence, this is the required solution.
What divides the northern hemisphere from the southern hemisphere
what is the electric force acting between two charges of -0.0045 C and -0.0025 C that are 0.0060 m apart? Use Fe=kq1q2/r^2 and k = 9.00 x 10^9 N*m^2/C^2
A. 1.7 x 10^7 N
B. -1.7 x 10^7 N
C. -2.8 x 10^9 N
D. 2.8 x 10^9 N
Answer:
D. 2.8 × 10⁹ N
Explanation:
The force between two charges is directly proportional to the amount of charges at the two points and inversely proportional to the square of distance between the two points.
Fe= k Q₁Q₂/r²
Q₁= -0.0045 C
Q₂= -0.0025 C
r= 0.0060 m
k= 9.00 × 10 ⁹ Nm²/C²
Fe= (9.00 × 10 ⁹ Nm²/C²×-0.0045 C×-0.0025 C)/0.0060²
=2.8 × 10⁹ N
Answer:
D. 2.8 x 10^9 N
Explanation:
A P E X
What was anton van leeuwenhoek famous for
Answer:
He is known as the first microbiologist and also “the Father of Microbiology” because he was the first to observe bacteria underneath a microscope. He made many other significant discoveries in the field of biology and also made important changes to the microscope.
Explanation:
hope this helps. and if it did pls mark brainliest :)
How much smaller is an atom than a speck of dust
Answer:
an atom is about a trillion times smaller then a speck of dust.
Explanation:
hope this helps :)
An atom is 4 times smaller than a speck of dust when both are compared.
The average radius of an atoms is about 0.1 nm ( 0.1 x 10⁻⁹ m).
The average radius of a speck of dust is about 0.1 x 10⁻⁵ m.
The ratio of these particles can be compared as follows;
[tex]ratio = \frac{0.1 \times 10^{-4}}{0.1 \times 10^{-9}} = 10^4[/tex]
Thus, we can conclude that when a speck of dust is compared to an atom, an atom will be 4 times smaller than a speck of dust.
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The energy equivalent of the rest mass of an electron is
Answer:energy times mass
Explanation: yeh
One model for a certain planet has a core of radius R and mass M surrounded by an outer shell of inner radius R, outer radius 2R, and mass 4M. If M = 6.24 × 10^24 kg and R = 4.11 × 10^6 m, what is the gravitational acceleration of a particle at points (a) R and (b) 3R from the center of the planet?
(a) [tex]24.6 m/s^2[/tex]
At a distance r=R from the centre of the planet, there is no effect due to the outer shell: so, the gravitational field strength at r=R is only determined by the gravity produced by the core of the planet.
So, the strength of the gravitational field is given by
[tex]g= \frac{GM}{R^2}[/tex]
where
G is the gravitational constant
M = 6.24 × 10^24 kg is the mass of the core of the planet
R = 4.11 × 10^6 m is the radius of the core
Substituting into the equation, we find
[tex]g= \frac{(6.67\cdot 10^{-11})(6.24\cdot 10^{24} kg)}{(4.11\cdot 10^6 m)^2}=24.6 m/s^2[/tex]
(b) [tex]13.7 m/s^2[/tex]
at distance r=3R from the centre, the particle feels the effect of gravity due to both the core of the planet and the outer shell between R and 2R.
So, we have to consider the total mass that exerts the gravitational attraction at r=3R, which is the sum of the mass of the core (M) and the mass of the shell (4M):
M' = M + 4M = 5M
Therefore, the gravitational acceleration at r=3R will be
[tex]g'= \frac{G(5M)}{(3R)^2}=\frac{5}{9}\frac{GM}{R^2} = \frac{5}{9}g[/tex]
And susbstituting
g = 24.6 m/s^2
found in the previous part, we find
[tex]g' = \frac{5}{9} (24.6 m/s^2)=13.7 m/s^2[/tex]
The gravitational acceleration at point R is approximately 9.85 m/s². the gravitational acceleration at point 3R is approximately 1.09 m/s².
The formula for gravitational acceleration:
g = (G × M) / r²
where:
g is the gravitational acceleration,
G is the gravitational constant,
M is the mass of the planet,
and r is the distance from the center of the planet.
Given:
M = 6.24 × 10²⁴ kg
R = 4.11 × 10⁶ m
(a) At point R:
g = (G × M) / R²
g = (6.674 × 10⁻¹¹ × 6.24 × 10²⁴) / (4.11 × 10⁶)²
g = 9.85 m/s²
Therefore, the gravitational acceleration at point R is approximately 9.85 m/s².
(b) At point 3R:
g = (G × M) / (3R)²
g = (6.674 × 10⁻¹¹ × 6.24 × 10²⁴) / (3 × 4.11 × 10⁶)²
g = 1.09 m/s²
Therefore, the gravitational acceleration at point 3R is approximately 1.09 m/s².
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WHOEVER ANSWERS CORRECTLY GETS BRAINLIEST
Which of the following happens when the swing moves from Position B to Position A?
[ ] Both potential energy and kinetic energy of the student increase.
[ ] Both potential energy and kinetic energy of the student decrease.
[ ] Potential energy of the student decreases and kinetic energy of the student increases.
[ ] Kinetic energy of the student decreases and potential energy of the student
Answer: its c
Explanation:
Total energy is conserved.
Energy = potential energy + kinetic energy as other forms of energy are neglected.
Clearly , position A is at a higher position from the ground , so it has more potential energy.
As the energy is conserved , the kinetic energy at A must have decreased making the total energy the same as that during B.
So,to sum it up
potential energy of the student increases and the kinetic energy decreases as he moves from B to A
When the swing goes from Position B to Position A, potential energy increases due to height gain, while kinetic energy decreases as the swing slows down.
Explanation:When a swing moves from Position B (the lowest point) to Position A (a higher point), the potential energy of the student increases while the kinetic energy decreases. This is because as the swing rises, it slows down due to gravity working against the motion, converting kinetic energy into potential energy. At the highest point of the swing (Position A), the swing has its maximum potential energy and minimum kinetic energy. Conversely, as the swing descends back toward Position B, the potential energy is converted back into kinetic energy, increasing the speed of the swing.
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What type of energy conversion occurs at the moment fireworks explode?
chemical energy converts into light, heat and sound energy
Answer: Rapid Oxidation
Explanation:
In fireworks, the energy source is the rapid oxidation (burning or exploding) of gunpowder and other flammable chemicals. This burning causes the formation of gases that are heated and expand.
This rapid expansion involves three forms of energy : 1) The motive force to carry aerial fireworks into the sky, and to separate parts of them, 2) The heated molecules that give off radiance (visible light) in various forms of displays, and 3) The energetic vibration of air molecules that creates the sound of explosions.
Positrons are spontaneously emitted from the nuclei of
Answer:
Positrons are spontaneously emitted from the nuclei of potassium -37
Explanation:
Answer: potassium 37
Explanation:
If an electromagnetic wave has a frequency of 8 ⋅ 10^14 H z , what is its wavelength? Use λ=V/F. The speed of light is 3 ⋅ 10^8 m/s.
The wavelength of an electromagnetic wave with a frequency of 8 ⋅ 10^14 Hz and speed of 3 ⋅ 10^8 m/s, calculated using the formula λ = V / F, is approximately 3.75 ⋅ 10^-7 meters.
Explanation:To find the wavelength of an electromagnetic wave with a known frequency and speed, you can use the formula λ = V / F, where λ is the wavelength, V the speed of light, and F the frequency of the wave
Given that V (the speed of light) = 3 ⋅ 10^8 m/s and the frequency (F) = 8 ⋅ 10^14 Hz, substituting these values into the formula gives: λ = (3 ⋅ 10^8 m/s) / (8 ⋅ 10^14 Hz) .
Solving this equation, we find that the wavelength (λ) of the electromagnetic wave is approximately 3.75 ⋅ 10^-7 meters.
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A frequency generator sends a 550 Hz sound wave through both water and ice.
What is the difference in wavelength between the wave produced in ice and the wave produced in water?
Δλ = 3.103 m.
To solve this problem we have to know the speed of sound in both elements water and ice.
Element Speed of sound
Water (25°C) 1493 m/s
Ice 3200 m/s
The velocity of a wave is given by the equation v = λf, where λ is the wavelength, and f is the frecuency of the wave.
In order to calculate the wavelength we have to clear λ in the equation v = λf, resulting:
λ = v/f
Calculating the wavelength in both elements:
λ(water) = 1493 m/s / 550 Hz = 2.715 m
λ(ice) = 3200 m/s / 550 Hz = 5.818 m
So, the difference in wavelength between the wave produced in ice and the wave produced in water is:
Δλ = λ(water) - λ(ice) = 5.818 m - 2.715 m
Δλ = 3.103 m
Answer:
3.1 m
Explanation:
If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, ________ is being done.
Explanation:
A force that leads to movement of an object is known as work.
The energy present in an object due to its position in a gravitational field is known as gravitational potential energy.
Kinetic energy is the energy obtained by an object due to its motion.
For example, when Jerome is swinging on a rope then there occurs movement in the swing due to which the swing has kinetic energy.
Since, a force has been applied on the swing to make it move. Hence, a work is also done.
Therefore, we can conclude that if Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, work is being done.
Answer:
the answer is B ( work )
Explanation:
A.) compression
B.) work
C.) radiation
D.) energy creation
The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-15 is 2 × 10-7 seconds. The half-life of is times greater than the half-life of .
Explanation:
The half-life [tex]h[/tex] of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13: [tex]h_{B-13}=5(10)^{-10}s=0.0000000005s[/tex]
beryllium-15: [tex]h_{B-15}=2(10)^{-7}s=0.0000002s[/tex]
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:
[tex]h_{B-15}=X.h_{B-13}[/tex]
Where [tex]X[/tex] is the amount we want to find:
[tex]X=\frac{h_{B-15}}{h_{B-13}}[/tex]
[tex]X=\frac{2(10)^{-7}s}{5(10)^{-10}s}[/tex]
Finally:
[tex]X=400[/tex]
Therefore:
The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.
Two pans of water are on different burners of a stove. One pan of water is boiling vigorously, while the other is boiling gently. What can be said about the temperature of the water in the two pans? Two pans of water are on different burners of a stove. One pan of water is boiling vigorously, while the other is boiling gently. a. The pan which is boiling vigorously has greater temperature. b. The pan which is boiling vigorously has less temperature. c. The temperature of water in both the pans is the same.
Answer:
The correct answer is C.
Explanation:
Answer:
It's C
Explanation:
Light is described as having a dual wave-particle nature. Which piece of evidence provides support for the model of light as a particle?
Young’s double slit experiment showed that light waves show interference.
Light reflects when it hits a surface.
Light refracts when it moves from one medium to another.
Light does not need a medium to travel.
Explanation:
It is now clear that light behaves as a wave and as a particle. It should be noted that the first to propose the corpuscular theory of light was Issac Newton, while the wave theory was initially proposed by Christian Huygens, who was contemporaneous with Newton.
Now, focusing on the corpuscular theory, Newton proposed that light is composed of tiny massless particles, traveling in a straight line and at high speed. In addition, he used the reflection phenomenon of the of light to show that it behaved like particles that when hitting a mirror were reflected by a perfectly elastic collision.
Answer:
Light does not need a medium to travel.
Explanation:
Which best describes what forms in nuclear fission?A. two smaller, more stable nucleiB. two larger, less stable nucleiC. one smaller, less stable nucleusD. one larger, more stable nucleus
In nuclear fission, a heavy nucleus splits into two smaller, more stable nuclei, releasing a large amount of energy. These smaller nuclei are more stable because they are closer to the most stable nuclear configuration found in nickel and iron-sized nuclei.
Nuclear fission is the process in which a heavy nucleus splits into two smaller, more stable nuclei, accompanied by the release of energy. This occurs particularly with nuclei that have a mass number higher than 92. During fission, the original nucleus divides into two fragments that are not necessarily equal in size, but are usually closer to the size of iron-56, which is the most stable size for a nucleus. A notable example is the fission of uranium-235, where the nucleus splits into two smaller fragments and releases additional free neutrons and energy in the form of gamma rays.
The larger nucleus undergoing fission must rearrange its nucleons towards a configuration that is closer to that of the most stable nuclei, which are around the size of nickel and iron. This implies that during fission, the resulting nuclei are generally smaller and more stable compared to the original one. Therefore, the correct description of what forms in nuclear fission is two smaller, more stable nuclei (Option A).
Ocean waves with 15 meters between wave crests travel with a velocity of 3 meters per second. With what frequency will these ocean waves pass under an anchored boat?(v = f λ)Ocean waves with 15 meters between wave crests travel with a velocity of 3 meters per second. With what frequency will these ocean waves pass under an anchored boat?(v = f λ)Ocean waves with 15 meters between wave crests travel with a velocity of 3 meters per second. With what frequency will these ocean waves pass under an anchored boat?(v = f λ)Ocean waves with 15 meters between wave crests travel with a velocity of 3 meters per second. With what frequency will these ocean waves pass under an anchored boat?(v = f λ)
Answer:
0.2 Hz
Explanation:
The frequency of a wave is given by
[tex]f=\frac{v}{\lambda}[/tex]
where
f is the frequency
v is the speed of the wave
[tex]\lambda[/tex] is the wavelength
For the ocean waves in this problem,
[tex]\lambda=15 m[/tex] is the wavelength
v = 3 m/s is the speed
So their frequency is
[tex]f=\frac{3 m/s}{15 m}=0.2 Hz[/tex]
The frequency of ocean waves passing under an anchored boat can be calculated using the wave equation v = f λ. In this case, the velocity of the waves is given as 3 meters per second and the distance between wave crests (wavelength) is given as 15 meters. The frequency at which these ocean waves pass under an anchored boat is 0.2 Hz.
Explanation:The frequency of ocean waves passing under an anchored boat can be calculated using the wave equation v = f λ, where v is the velocity of the waves, f is the frequency, and λ is the wavelength.
In this case, the velocity of the waves is given as 3 meters per second and the distance between wave crests (wavelength) is given as 15 meters. We need to find the frequency.
Using the wave equation, we can rearrange it to solve for frequency as f = v / λ. Substituting the given values, we get f = 3 m/s / 15 m = 0.2 Hz.
Therefore, the frequency at which these ocean waves pass under an anchored boat is 0.2 Hz.
a body covers a semicircle of radius 7cm in 5s .find its linear speed
Ok so we are given the radius of 7cm and time of 5 seconds.
From the data we got we can calculate speed, frequency, perimeter and area of the semicircle.
Let's start with perimeter.
We know that perimeter of circle is [tex]2\pi r[/tex] so the perimeter of semicircle is [tex]\dfrac{2\pi r}{2}[/tex] or simply [tex]\pi r[/tex]
So the perimeter is equal to:
[tex]\pi r=\pi\cdot7\approx\boxed{22cm}[/tex]
So this is the length of a curve or let's say the distance.
Now let's look at the linear speed [tex]s=\dfrac{d}{t}[/tex] where d is distance and t time.
We know the distance and we know the time.
So let's calculate it.
[tex]s=\dfrac{d}{t}=\dfrac{22}{5}=\boxed{4.4\dfrac{cm}{s}}[/tex]
Hope this helps.
r3t40
What is the work done by the electric force to move a 1 c charge from a to b?
The work done by the electric force to move a 1 c charge between two points is calculated by multiplying the charge by the electric potential difference between those points.
Explanation:The work done by the electric force to move a 1 c charge from point a to point b depends on the electric potential difference, or voltage, between points a and b. The work done is calculated by the equation: Work = Charge * Electric Potential Difference. If we know the electric potential difference between points a and b, we can substitute it into the equation to find the work done. For example, if the potential difference between a and b is 5 volts, the work done to move a 1 c charge would be 1 c * 5 V = 5 Joules.
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