If you horizontally stretch the quadratic parent function f(x)=x^2 by a factor of 3. What is the equation

Answer:

B

Step-by-step explanation:

Answer:

Length: 13 feet,

Width: 4 feet.

Step-by-step explanation:

Let w represent width of bulletin board.

We have been given that the length is 3 feet less than 4 times the width. So the length of the bulletin board would be [tex]4w-3[/tex].

We have been given the area of a bulletin board is 52 square feet. We know that a bulletin board is in form of rectangle, so its area would be length times width.

We can represent this information in an equation as:

[tex]w(4w-3)=52[/tex]

Let us solve for w.

[tex]w(4w-3)=52[/tex]

[tex]4w^2-3w=52[/tex]  

Use quadratic formula:

[tex]w=\frac{-(-3)\pm\sqrt{(-3)^3-4\cdot 4\cdot (-52)}}{2\cdot 4}[/tex]

[tex]w=\frac{3\pm\sqrt{9+832}}{8}[/tex]

[tex]w=\frac{3\pm\sqrt{841}}{8}[/tex]

[tex]w=\frac{3\pm29}{8}[/tex]

[tex]w=\frac{3-29}{8}\text{ (or) }w=\frac{3+29}{8}[/tex]

[tex]w=\frac{-26}{8}\text{ (or) }w=\frac{32}{8}[/tex]

[tex]w=\frac{-13}{4}\text{ (or) }w=4[/tex]

Since width cannot be negative, therefore, width of the bulletin board is 4 feet.

Substitute [tex]w=4[/tex] in expression [tex]4w-3[/tex] to find length of bulletin board.

[tex]4w-3\Rightarrow 4(4)-3=16-3=13[/tex]

Therefore, length of the bulletin board is 13 feet.

Answer:

2x+15=75

Step-by-step explanation:

Let the temperature of  chicago be x

75-15=2x

Reversing the equation

2x+15=75

An equation to determine the temperature in Chicago will be 2x + 15 = 75. so option A is correct.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let the temperature of Chicago be represented x.

75 - 15 = 2x

Reversing the equation;

2x + 15 = 75

An equation to determine the temperature in Chicago will be 2x + 15 = 75. so option A is correct.

Learn more about equations here;

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Answer:

  168/(x² +7x)

Step-by-step explanation:

The height of each window is 14/(x+7), and the width of each window is 12/x. The area of each window is the product of its height ans width:

  area = (14/(x+7))(12/x) = 168/(x(x +7))

  area = 168/(x² +7x)

_____

Comment on the problem

There is not enough information given to determine suitable values for x. If x is 42, each window is a square 3 3/7 inches on a side.

Answer:

  1.25 gallons of alcohol

Step-by-step explanation:

Let x represent the amount of alcohol to add to the mix. Then the total amount of alcohol in the mix is ...

  0.15×20 + x = 0.20×(20 +x)

  3 +x = 4 + 0.2x . . . . simplify

  0.8x = 1 . . . . . . . . . . add -3-0.2x

  x = 1/0.8 = 1.25 . . . . divide by 0.8

1.25 gallons of alcohol should be added to make 21.25 gallons of 20% alcohol.

Answer:

Step-by-step explanation:

Let x represent the shorter dimension in feet. Then the longer one is x+7 and the Pythagorean theorem tells us the relation of these to the diagonal is ...

  x² + (x+7)² = 13²

  2x² +14x + 49 = 169 . . . . eliminate parentheses

  x² +7x -60 = 0 . . . . . subtract 169 and divide by 2

  (x +12)(x -5) = 0 . . . . factor the equation

  x = -12 or +5 . . . . . . . only the positive value of x is useful here.

The short dimension is 5 ft, so the long dimension is 12 ft. The area is their product, 60 ft².

_____

Comment on finding the area

The quadratic equation above can be rearranged and factored as ...

  x(x +7) = 60

Since the dimensions of the garden are x and (x+7), this product is the garden's area. This equation tells us the area is 60. We don't actually have to find the dimensions.

Answer:

The answer would be [tex]7(\sqrt[5]{x^{2}y } )[/tex]

Step-by-step explanation: I got it right on Edge 2020

If we want to find when the population of species A will be equal to the population of species B, we need to see when the two equations for the population of each species are equal, ie. equate them and solve for t. Thus:

2000e^(0.05t) = 5000e^(0.02t)

(2/5)e^(0.05t) = e^(0.02t) (Divide each side by 5000)

2/5 = e^(0.02t) / e^(0.05t) (Divide each side by e^(0.05t))

2/5 = e^(-0.03t) (use: e^a / e^b = e^(a - b))

ln(2/5) = -0.03t (use: if b = a^c, then loga(b) = c )

t = ln(2/5) / -0.03 (Divide each side by -0.03)

= 30.54 (to two decimal places)

Therefor, the population of species A will be equal to the population of species B after 30.54 years.

I wasn't entirely sure about the rounding requirements so I've left it rounded to two decimal places.

[tex]\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{\Delta y}{ y_2- y_1}}{\stackrel{\Delta x}{ x_2- x_1}}\implies \cfrac{10-(-5)}{0-(-3)}\implies \cfrac{10+5}{0+3}\implies \cfrac{\stackrel{\stackrel{\Delta y}{\downarrow }}{\boxed{15}}}{3}[/tex]

1. "Create your own circle on a complex plane."

The equation of a circle in the complex plane can be written a number of ways. For center c (a complex number) and radius r (a positive real number), one formula is ...

  |z-c| = r

If we let c = 2+i and r = 5, the equation becomes ...

  |z -(2+i)| = 5

For z = x + yi and |z| = √(x² +y²), this equation is equivalent to the Cartesian coordinate equation ...

  (x -2)² +(y -1)² = 5²

__

2. "Choose two end points of a diameter to prove the diameter and radius of the circle."

We don't know what "prove the diameter and radius" means. We can show that the chosen end points z₁ and z₂ are 10 units apart, and their midpoint is the center of the circle c.

For the end points of a diameter, we choose ...

The distance between these is ...

  |z₂ -z₁| = |(-1-5) +(-3-5)i| = |-6 -8i|

  = √((-6)² +(-8)²) = √100

  |z₂ -z₁| = 10 . . . . . . the diameter of a circle of radius 5

The midpoint of these two point should be the center of the circle.

  (z₁ +z₂)/2 = ((5 -1) +(5 -3)i)/2 = (4 +2i)/2 = 2 +i

  (z₁ +z₂)/2 = c . . . . . the center of the circle is the midpoint of the diameter

__₁₂₃₄

3. "Show how to determine the center of the circle."

As with any circle, the center is the midpoint of any diameter (demonstrated in question 2). It is also the point of intersection of the perpendicular bisectors of any chords, and it is equidistant from any points on the circle.

Any of these relations can be used to find the circle center, depending on the information you start with.

As an example. we can choose another point we know to be on the circle:

  z₄ = 6-2i

Using this point and the z₁ and z₂ above, we can write three equations in the "unknown" circle center (a +bi):

Using the formula for the square of the magnitude of a complex number, this becomes ...

  (5-a)² +(5-b)² = r² = 25 -10a +a² +25 -10b +b²

  (-1-a)² +(-3-b)² = r² = 1 +2a +a² +9 +6b +b²

  (6-a)² +(-2-b)² = r² = 36 -12a +a² +4 +4b +b²

Subtracting the first two equations from the third gives two linear equations in a and b:

  11 -2a -21 +14b = 0

  35 -14a -5 -2b = 0

Rearranging these to standard form, we get

  a -7b = -5

  7a +b = 15

Solving these by your favorite method gives ...

  a +bi = 2 +i = c . . . . the center of the circle

__

4. "Choose two points, one on the circle and the other not on the circle. Show, mathematically, how to determine whether or not the point is on the circle."

The points we choose are ...

We can show whether or not these are on the circle by seeing if they satisfy the equation of the circle.

  |z -c| = 5

For z₃: |(3 -2i) -(2 +i)| = √((3-2)² +(-2-i)²) = √(1+9) = √10 ≠ 5 . . . NOT on circle

For z₄: |(6 -2i) -(2 +i)| = √((6 -2)² +(2 -i)²) = √(16 +9) = √25 = 5 . . . IS on circle

Answer:

At t = 1s, The instantaneous velocity will be -9

Step-by-step explanation:

The position is given by

s(t) = -8 - 9t

If we find the derivative, we get the expression for the velocity

d(s(t))/dt = v(t) = -9

The velocity of the object is constant.

At t = 1s, it will be -9

Answer:

3/4

Step-by-step explanation:

a1 = (-1/3)^0 = 1

r = -1/3

Hence S = 1/(1+1/3) = 1/(4/3) = 3/4

Answer:

0.75.

Step-by-step explanation:

The common ratio = -1/3 and the first term = (-1/3)^0 = 1.

Sum to infinity =  1 / (1 - (-1/3))

= 1 / 4/3

= 3/4

= 0.75.

Answer:

5.25 miles - 3 miles = 2.25 miles

2.25 miles is the extra miles.

2.25 miles x $1.20 = $2.7

Total:

$2.7 + ($1.5 x 3 miles)

=$2.7 + $4.5

=$7.2

5.5 miles will cost $2.7.

Answer:

You need to have some idea where you want to start if you're going to derive equations for these. You can start with a definition based on focus and directrix, or you can start with a definition based on the geometry of planes and cones. (The second focus is replaced by a directrix in the parabola.)  In general, these "conics" represent the intersection between a plane and a cone. Perpendicular to the axis of symmetry, you have a circle. At an angle to the axis of symmetry, but less than parallel to the side of the cone, you have an ellipse. Parallel to the side of the cone, you have a parabola. At an angle between the side of the cone and the axis of the cone, you have a hyperbola. (See source link.)  

You can also start with the general form of the quadratic equation.  

.. ±((x-h)/a)^2 ± ((y-k)/b)^2 = 1  

By selecting signs and values of "a" and "b", you can get any of the equations. (For the parabola, you probably need to take the limit as both k and b approach infinity.)

Answer:

[tex]d =\sqrt{(b-0)^2 +(c-a)^2}[/tex]

Step-by-step explanation:

We know that the distance between two points is calculated using the following formula

[tex]d =\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}[/tex]

In this case we look for the RS distance

Then

The starting point is: (0, a)

The final point is (b, c)

So

[tex]x_2 = b\\x_1 = 0\\y_2 = c\\y_1=a[/tex]

The distance is:

[tex]d =\sqrt{(b-0)^2 +(c-a)^2}[/tex]

Answer:

Revenue , Cost and Profit Function

Step-by-step explanation:

Here we are given the Price/Demand Function as

P(x) = 253-2x

which means when the demand of Cat food is x units , the price will be fixed as 253-2x per unit.

Now let us revenue generated from this demand i.e. x units

Revenue = Demand * Price per unit

R(x) = x * (253-2x)

      = [tex]253x-2x^2[/tex]

Now let us Evaluate the Cost Function

Cost = Variable cost + Fixed Cost

Variable cost = cost per unit * number of units

                      = 3*x

                      = 3x

Fixed Cost = 6972 as given in the problem.

Hence

Cost Function C(x) = 3x+6972

Let us now find the Profit Function

Profit = Revenue - Cost

P(x) = R(x) - C(x)

= [tex]253x-2x^2 - (3x + 6972)[/tex]

= [tex]253x-3x-2x^2-6972\\= 250x-2x^2-6972\\=-2x^2+250x-6972\\[/tex]

Now we have to find the quantity at which we attain break even point.

We know that at break even point

Profit = 0

Hence P(x) = 0

[tex]-2x^2+250x-6972=0\\[/tex]

now we have to solve the above equation for x

Dividing both sides by -2 we get

[tex]x^2-125x+3486=0[/tex]

Now we have to find the factors of 3486 whose sum is 125. Which comes out to be 42 and 83

Hence we now solve the above quadratic equation using splitting the middle term method .

Hence

[tex]x^2-42x-83x+3486=0\\x(x-42)-83(x-42)=0\\(x-42)(x-83)=0\\[/tex]

Either (x-42) = 0 or (x-83) = 0 therefore

if x-42= 0 ; x=42

if x-83=0 ; x=83

Smallest of which is 42. Hence the number of units at which it attains the break even point is 42.

The cost function is C(x) = 3x + 6972, the revenue function is R(x) = 253x - 2x², and the profit function is P(x) = 250x - 2x²- 6972. The smallest break-even point occurs at 16 bins.

To solve the given problem, let's break it down step-by-step:

      The cost function includes both the fixed cost and the variable cost.            The fixed cost is $6972, and the unit cost to produce one bin of cat food is $3. Therefore, the cost function C(x) where x is the number of bins is:

C(x) = 3x + 6972

The price-demand function is given by p(x) = 253 - 2x. Revenue R(x) is the product of the price per bin and the number of bins sold, so:

R(x) = x * (253 - 2x) = 253x - 2x²

The profit function is the revenue function minus the cost function. So, the profit function P(x) is:

P(x) = R(x) - C(x) = (253x - 2x²) - (3x + 6972) = 250x - 2x² - 6972

To find the smallest break-even point, we need to solve the equation where profit equals zero:

0 = 250x - 2x² - 6972

Rewriting the equation, we get:

2x² - 250x + 6972 = 0

Solving this quadratic equation using the quadratic formula x = [-b ± sqrt(b² - 4ac)] / 2a, where a = 2, b = -250, and c = 6972:

x = [250 ± sqrt(62500 - 4*2*6972)] / 4

x = [250 ± sqrt(62500 - 27888)] / 4

x = [250 ± sqrt(34612)] / 4

x = [250 ± 186.01] / 4

So, the two solutions for x are approximately:

x = (250 + 186.01) / 4 = 109

x = (250 - 186.01) / 4 = 15.997 ≈ 16

The smallest break-even point is at a quantity of 16 bins.

The cost function is C(x) = 3x + 6972, the revenue function is R(x) = 253x - 2x², and the profit function is P(x) = 250x - 2x² - 6972. The smallest break-even point occurs at 16 bins.

[tex]P(A)=0.995\\P(A')=0.005[/tex]

So [tex]P(A')[/tex] is pretty much unlikely.

Answer:

2

Step-by-step explanation:

f(x) = 3х^2 + 5x

Let x = -2

f(-2) = 3(-2)^2 + 5(-2)

      = 3*4 -10

      = 12-10

       =2

Answer:

Z = 27°

Step-by-step explanation:

The sum of the internal angles of a triangle is always equal to 180 °. Note that the triangle shown whose angles are z and 63 ° is a right triangle. Therefore it has an angle of 90 °. Then we can write the following equation:

[tex]z + 63\° +90\°= 180\°\\\\z = 180\° - 63\°-90\°\\\\z = 27\°[/tex]

Finally z = 27°

ANSWER

[tex]z = 27 \degree[/tex]

EXPLANATION

The diagonals of a rhombus bisect each other at right angles.

Hence each of the four angles at the center by are 90° each.

This means that:

[tex]z + 63 + 90 = 180[/tex]

Sum of interior angles of a triangle.

[tex]z + 153= 180[/tex]

[tex]z = 180 - 153[/tex]

This simplifies to.

[tex]z = 27 \degree[/tex]

Answer:

Jamie spent $39.36 in total.

Step-by-step explanation:

First, add the money spent for the sandwich, beverage, and fruit together.

4.75 + 1.25 + .56 = 6.56

Then, multiply the amount spent for one friend by six to find the total.

6.56 x 6 =39.36

I hope this helped you!

Answer:

Step-by-step explanation:

The general form of an exponential equation for growth is

[tex]y=(1+r)^x[/tex]

and for decay is

[tex]y=(1-r)^x[/tex]

In general, if the number inside the parenthesis (the growth or decay rate) is greater than 1, it's a growth problem.  If the number inside the parenthesis is greater than 0 but less than 1 (in other words a positive fraction), it's a decay problem.

Final answer:

To determine if an exponential equation represents growth or decay, examine the base of the expression: a growth model has a base greater than 1, while a decay model has a base between 0 and 1. Exponential growth is illustrated by a J-shaped curve, whereas logistic growth follows an S-shaped curve.

Explanation:

The general form of an exponential function is f(t) = a*b^t, where a is the initial amount, b is the base, and t is the time.

Growth is modeled when the base b is greater than 1. This signifies that the quantity is increasing over time. For example, with a base of 2, the sequence would be 2, 4, 8, 16, and so forth, representing that the population doubles at each time interval.

In contrast, decay is modeled when the base b is between 0 and 1. This indicates that the quantity is decreasing over time, such as in the case of radioactive decay or depreciation of assets.

Exponential growth is often represented by a 'J-shaped' curve, which depicts how a population may grow faster as the population becomes larger. On the other hand, logistic growth, which is more realistic in natural populations due to factors like limited resources, follows an 'S-shaped' curve where growth levels off at carrying capacity.

Answer:

it's definitely a positive nonlinear graph

Step-by-step explanation:

The Set Up:

x² = (Side1)² + (Side2)² - 2[(Side1)(Side2)]

Solution:

cos(Toby's Angle) • x² = 55² + 65² - 2[(55)(65)] cos(110°)

x² = 3025 + 4225 -7150[cos(110°)]

x² = 7250 - 2445.44x =

√4804.56x = 69.31m

The distance, x, between two landmarks is 69.31m.

Note: The answer choices given are incorrect.

Answer:

98.5 m

Step-by-step explanation:

Refer the attached figure

AB = 55

AD = 65

∠ABC=40°

∠ADC = 30°

We are supposed to find the distance between the two landmarks i.e. BD = BC+CD

In ΔABC

[tex]Cos \theta = \frac{Base}{Hypotenuse}[/tex]

[tex]Cos 40^{\circ} = \frac{BC}{AB}[/tex]

[tex]0.76604444= \frac{BC}{55}[/tex]

[tex]0.76604444 \times 55 =BC[/tex]

[tex]42.132442 =BC[/tex]

In ΔADC

[tex]Cos \theta = \frac{Base}{Hypotenuse}[/tex]

[tex]Cos 30^{\circ} = \frac{CD}{AD}[/tex]

[tex]0.8660254= \frac{CD}{65}[/tex]

[tex]0.8660254 \times 65 =CD[/tex]

[tex]56.291651 =CD[/tex]

So, BD = BC+CD=42.132442+56.291651=98.424≈ 98.5

Hence the distance between the two landmarks is 98.5 m.

Answer:

t = 2489 years

Step-by-step explanation:

The equation you need for this is

[tex]N=N_{0}e^{kt}[/tex]

where N is the amount AFTER the decomposition, N-sub-0 is the initial amount, k is the decomposition constant and t is time in years.

If we are told that the tusk LOST 26% of its carbon-14, that means 74% of it remains from the initial 100% it had.

Filling in:

[tex]74=100e^{-.00012097t}[/tex]

Begin by dividing both sides by 100 to get a decimal of .74:

[tex].74=e^{-.00012097t}[/tex]

The goal is to get that t out of the exponential position in which it is currently sitting.  Do this by "undoing" the e.  Do THAT by taking the natural log of both sides because a natural log "undoes" an e.  This is due to the fact that the base of a natural log is e.  

[tex]ln(.74)=ln(e^{-.00012097t})[/tex]

The ln and the e disappear on the right side, leaving

ln(.74) = -.00012097t

Plug ln(.74) into your calculator to get

-.3011050928 = -.00012097t

t = 2489

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

Answer:

120*pi in^3

Step-by-step explanation:

We are given

Radius of cone=r=6 in

Height of cone=h=10 in

We know that the formula for finding the volume of cone is:

[tex]V=\frac{1}{3}\pi *(r)^{2}*h[/tex]

Putting the values of radius and height:

[tex]V=\frac{1}{3}\pi *(6)^{2}*10\\=\frac{1}{3}\pi *36*10\\=\frac{360}{3}\pi\\=120\pi[/tex]

So, the volume of cone in terms of pi is 120pi cubic in^3 ..

Answer:

The volume of cone = 120π cubic inches

Step-by-step explanation:

Points to remember

Volume of cone = (πr²h)/3

Where r - Radius of cone and

h - Height of cone

To find the volume of cone

Here r = 6 in and h = 10 in

Volume = (πr²h)/3

 = (π * 6² * 10)/3

 = (π * 36 * 10)/3

 = 360π/3

 = 120π cubic inches

Therefore volume of cone = 120π cubic inches

The three-dimensional figure that is formed by the rotation is (a) an hemisphere

From the figure, we can see that the line is rotated along the y-axis.

And the length of rotation reduces as the rotation moves downward

This rotation would create an hemisphere

The option (a) represents an hemisphere

Hence, the three-dimensional figure that is formed by the rotation is (a) an hemisphere

Read more about rotation at:

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Answer:

To better understand the data you're working with

Step-by-step explanation:

Note that, the sample is a subset of your whole population (population here is a general definition, it could be a population of cars for example), which means that if you want to understand your population your best "bet" would be using a sample to try to estimate some unknown characteristics of your population. Let's suppose you want to estimate the true mean of your population, then you would need a sample, and if this sample is big enough you could approximate the estimative to the true mean.

It's hard to say exactly what this survey could mean, but the general idea is to understand your data a little more, see if there is any pattern, if a certain value occurs more than others, to calculate the sample mean, median and standard deviation, and so on...

Hope it helped!

Answer:

For b, the answer is that your trying to find out what the type of funtion may be. It could be either exponential, linear, or quadratic.

Step-by-step explanation:

That's what the lesson in edg is all about.