If you have a bank account that is modeled bybthe following equation, how much money would you have after 10 years. A=5000e 0.10t. Using the problem solving Temple with rational functions.

The population of the town increased by 7,882 people and the rate of increase is approximately 16.69%.

Finding the rate of increase in a town's population involves two steps: calculating the amount of change and expressing it as a percentage. Here's how:

1. Calculate the amount of change:

Imagine this change like climbing stairs. The initial population (47,230) is one step, and the final population (55,112) is another step higher. To find how many steps you climbed (the amount of change), simply subtract the starting step from the ending step:

Amount of change = Final population - Initial population

Amount of change = 55,112 people - 47,230 people

Amount of change = 7,882 people

2. Express the change as a rate of increase:

Now, imagine you want to tell someone how much faster you climbed compared to your starting position. To do that, you calculate the percentage increase, which is like expressing the number of steps climbed relative to your starting point (one step).

Rate of increase = (Amount of change / Initial population) * 100%

Rate of increase = (7,882 people / 47,230 people) * 100%

Rate of increase ≈ 16.69%

Therefore, the population of the town increased by 7,882 people and the rate of increase is approximately 16.69%. This means the population grew by roughly 16.69% compared to its original size.

Step-by-step explanation:

average rate of change of function is given by :

[tex]f= (f(a+h)-f(a))/h[/tex]

where

[tex]f(x)=3x[/tex]

and a= 7

so inserting values is formula for h=1

[tex]f=(f(7+1)-f(7))/1[/tex]

[tex]f= f(8)-f(7)= 3(8)-3(7)=24-21=3[/tex]

now for h= 0.1

[tex]f=(f(7+0.1)-f(7))/0.1=(f(7.1)-f(7))/0.1=(3(7.1)-3(7))/0.1[/tex]

[tex]f=3[/tex]

similarly average rate of change of given function is same for all given step sizes.

Final answer:

The question involved calculating the average rate of change of the function f(x) = 3x over various intervals, showing that the rate of change is constant and equals 3 for all given values of h.

Explanation:

The question asks to calculate the average rate of change of the function f(x) = 3x over the intervals [a, a + h] for values of h = 1, 0.1, 0.01, 0.001, and 0.0001, where a = 7.

The average rate of change is calculated using the formula [tex]\frac{f(a+h) - f(a)}{h}[/tex]

For each value of h, we substitute a and h into the function and use the formula to find the average rate of change.

For h = 1, the average rate of change is 3.

For h = 0.1, the average rate of change is also 3.

For h = 0.01, the average rate of change remains 3.

For h = 0.001, the average rate is again 3.

Similarly, for h = 0.0001, the average rate of change is 3.

Using technology for values of h smaller than 0.1 is recommended due to the precision required in calculations. However, for this particular function, the rate of change is constant across these intervals, simplifying the process.

Answer:

[tex]x=\frac{1+5i} {2}[/tex]   and  [tex]x=\frac{1-5i} {2}[/tex]

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

[tex]ax^{2} +bx+c=0[/tex]

is equal to

[tex]x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]f(x)=2x^{2} -2x+13[/tex]  

Equate the function to zero

[tex]2x^{2} -2x+13=0[/tex]  

so

[tex]a=2\\b=-2\\c=13[/tex]

substitute in the formula

[tex]x=\frac{-(-2)\pm\sqrt{-2^{2}-4(2)(13)}} {2(2)}[/tex]

[tex]x=\frac{2\pm\sqrt{-100}} {4}[/tex]

Remember that

[tex]i=\sqrt{-1}[/tex]

so

[tex]x=\frac{2\pm10i} {4}[/tex]

Simplify

[tex]x=\frac{1\pm5i} {2}[/tex]

therefore

[tex]x=\frac{1+5i} {2}[/tex]   and  [tex]x=\frac{1-5i} {2}[/tex]

Answer:

Step-by-step explanation:

1) since the sixth term is 3 and the fifth term 24, the common ratio would be 3/24 = 1/8

The formula for finding the nth term of a geometric sequence is

Tn = ar^(n - 1)

If t6 = 3,r = 1/8, then

3 = a × 1/8^(6 - 1) = a × (1/8)^5

a = 3/(0.125)^5 = 98304

The first term is 98304.

Second term is 98304 × 1/8 = 12288

Third term is 12288 × 1/8 = 1536

Third term is 1536 × 1/8 = 192

2) t1 = 4

t2 = - 3t(2- 1) = - 3t1 = - 3 × 4 = - 12

t3 = - 3t(3- 1) = - 3t2 = - 3 × - 12 = 36

t4 = - 3t(4- 1) = - 3t3 = - 3 × 36 = - 108

3) let the numbers be t2,t3 and t4

The sequence becomes

1/2, t2,t3, t4,8

The formula for finding the nth term of a geometric sequence is

Tn = ar^(n - 1)

8 = 1/2 × r^(5 - 1)

8 = 1/2 × r^4

16 = r^4

2^4 = r^4

r = 2

t2 = 1/2 × 2 = 1

t3 = 1 × 2 = 2

t4 = 2 × 2 = 4

Answer:

Option (2) is correct graph.

Step-by-step explanation:

Given:

The function to graph is given as:

[tex]f(x)=4(\frac{1}{2})^x[/tex]

Now, the above function is an exponential function of the form [tex]f(x)=ka^x[/tex]

Where, 'k' and 'a' are constants.

The range of an exponential function is always greater than 0.

The domain is all real numbers.

Now, for graphing it, we need to find some points on it and its end behaviour.

Now, for x = 0, the function value is given as:

[tex]f(0)=4(\frac{1}{2})^0=4[/tex]

So, (0, 4) is a point on the graph.

Now, for x = 1, the function value is given as:

[tex]f(1)=4(\frac{1}{2})^1=4\times\frac{1}{2}=2[/tex]

So, (1, 2) is another point on the graph.

Now, for x = 2, the function value is given as:

[tex]f(2)=4(\frac{1}{2})^2=4\times\frac{1}{4}=1[/tex]

So, (2, 1) is another point on the graph.

Now, as 'x' tends to ∞, the function value tends to:

[tex]f(x\to\infty)=4\cdot\frac{1}{2}^{\infty}=\frac{4}{\infty}=0[/tex]

So, as

[tex]x\to\infty,f(x)\to0\\\\x\to-\infty,f(x)\to\infty[/tex]

Now, from among all the options, only option (2) fulfills all the conditions given above.

So, option (2) is correct graph.

Answer:

option 2

Step-by-step explanation:

The range of the body temperature is [tex]2\leq x\leq 35[/tex]

Explanation:

Let x denote the body temperature of the bees.

The maximum body temperature of the bee is 35° Celsius.

When they sleep, the body temperature can drop by up to 2° Celsius.

Thus, the minimum body temperature of the bee is 2° Celsius.

Thus, the range of the body temperature is from 35° Celsius to 2° Celsius.

The range of body temperature is given by:

[tex]2\leq x\leq 35[/tex]

Thus, the range in body temperature of the bees is [tex]2\leq x\leq 35[/tex]

Step-by-step explanation:

a) √ 8/10

= to get the bench mark we have to look for perfect square that are closer to the numbers 8 and 10

= for 8, it is 9 ; for 10 it is also 9

Therefore, √ 8/10 is about√ 9/9

= 3/3 = 1

b) √17/5

= to get the bench mark we have to look for perfect square that are closer to the numbers 17 and 5

= for 17, it is 16; for 5 it is 4

Therefore, √ 17/5 is about √ 16/4

= 4/2= 2

c) √7/13

= to get the bench mark we have to look for perfect square that are closer to the numbers 7 and 13

= for 7, it is 9; for 13 it is 16

Therefore, √ 7/13 is about √ 9/16

= 3/4

d) √29/6

= to get the bench mark we have to look for perfect square that are closer to the numbers 29 and 6

= for 29, it is 25; for 6 it is 4

Therefore, √ 29/6 is about √ 25/4

= 5/4

Answer:

Y=2000x+175,000

Step-by-step explanation:

y=mx+b so your M will be your 2000 and your x is gonna be years, and your b is gonna be 175,000

Final answer:

It will take Daniel approximately 0.26 hours, or 15.6 minutes, to catch up with Frank.

Explanation:

To find how long it will take Daniel to catch up with Frank, we can use the formula time = distance / speed. Since Frank started out first, we can calculate his distance using the formula distance = speed * time. Let's assume it takes Daniel t hours to catch up with Frank. The time it takes Frank to travel 13 miles is 13 miles / 45 mph = 0.289 hours. Therefore, when Daniel starts, Frank has already traveled a distance of 0.289 hours * 45 mph = 13 miles. To catch up with Frank, Daniel needs to travel the same distance in t hours at a speed of 50 mph. So, 13 miles = 50 mph * t hours. Dividing both sides by 50 mph gives us t = 13 miles / 50 mph = 0.26 hours. Therefore, it will take Daniel approximately 0.26 hours, or 15.6 minutes, to catch up with Frank.

Answer:

There were 180 votes for blue.

Step-by-step explanation:

Given:

Riverside elementary school is holding a schoolwide election to choose a color. 5/8 of the votes were for blue. 5/9 of the remaining votes were for green and the remaining 48 votes were for red.

Now, to find the votes for blue.

Let the total votes be [tex]x.[/tex]

The votes for blue:

[tex]\frac{5}{8} \ of\ x[/tex]

[tex]=\frac{5}{8} \times x[/tex]

[tex]=\frac{5x}{8}[/tex]

Remaining votes are:

[tex]x-\frac{5x}{8} \\\\=\frac{8x-5x}{8} \\\\=\frac{3x}{8}[/tex]

The votes for green:

[tex]\frac{5}{9} \ of\ \frac{3x}{8} \\\\=\frac{5}{9} \times \frac{3x}{8} \\\\=\frac{15x}{72}[/tex]

The remaining votes for red = 48.

Now, the total votes are:

[tex]\frac{5x}{8} +\frac{15x}{72} +48=x\\\\\frac{45x+15x+3456}{72}=x\\\\\frac{60x+3456}{72}=x[/tex]

Multiplying both sides by 72 we get:

[tex]60x+3456=72x[/tex]

Subtracting both sides by 60[tex]x[/tex] we get:

[tex]3456=12x[/tex]

Dividing both sides by 12 we get:

[tex]288=x\\\\x=288.[/tex]

Thus, the total votes = 288.

Now, to get the votes for blue:

[tex]\frac{5}{8} \ of\ 288\\\\=\frac{5}{8}\times 288\\\\=0.625\times 288\\\\=180.[/tex]

Therefore, there were 180 votes for blue.

Answer: it will take 0.23 hours for the first car to catch the second one.

Step-by-step explanation:

Let t represent the time it will take for the first car to catch the second one.

The initial distance between the cars was 30 miles. This means that by the time both cars meet, they would have covered a total distance of 30 miles.

Distance = speed × time

The first car was going 70 miles per hour.

Distance covered by the first car after t hours is

70 × t = 70t

The second was going 60 miles per hour. Distance covered by the second car after t hours is

60 × t = 60t

Since the total distance covered is 30 miles, then

70t + 60t = 30

130t = 30

t = 30/130 = 0.23 hours

Answer:

[D] 11.25

Step-by-step explanation:

Broker/dealers must trade with customers based on the current bid and ask.

10.50 Bid for customers selling

11.25 Ask for customers buying

Answer:

Correct answer choices are [tex]27x^{2}[/tex] and [tex]657 cm^{2}[/tex]

Step-by-step explanation:

We are able to arrive at these answers through basic equation used to calculate area of an triangle and monomial laws

Answer:

The zeros of the given function are not real. The zeros of the function is at :

[tex]x=\frac{1}{2}+\frac{5i}{2}[/tex]    and  [tex]x=\frac{1}{2}-\frac{5i}{2}[/tex]

Step-by-step explanation:

Given quadratic function:

[tex]f(x)=2x^2-2x+13[/tex]

To  find the zeros of the function using quadratic formula.

Solution:

Applying quadratic formula:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

For the given function:

[tex]a=2, b=-2\ and\ c=13[/tex]

Thus, we have:

[tex]x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(13)}}{2(2)}[/tex]

[tex]x=\frac{2\pm\sqrt{4-104}}{4}[/tex]

[tex]x=\frac{2\pm\sqrt{-100}}{4}[/tex]

[tex]x=\frac{2\pm\sqrt{100}i}{4}[/tex]

[tex]x=\frac{2\pm10i}{4}[/tex]

[tex]x=\frac{2+10i}{4}[/tex]      and  [tex]x=\frac{2-10i}{4}[/tex]

[tex]x=\frac{2}{4}+\frac{10i}{4}[/tex]   and  [tex]x=\frac{2}{4}-\frac{10i}{4}[/tex]

[tex]x=\frac{1}{2}+\frac{5i}{2}[/tex]    and  [tex]x=\frac{1}{2}-\frac{5i}{2}[/tex]

Thus, the zeros of the given function are not real. The zeros of the function is at :

[tex]x=\frac{1}{2}+\frac{5i}{2}[/tex]    and  [tex]x=\frac{1}{2}-\frac{5i}{2}[/tex]

Area of the window [tex]=49\frac{5}{6}\ \text{ft}^2[/tex]

Solution:

Width of the window = [tex]8\frac{2}{3}[/tex] feet

Height of the window = [tex]5\frac{3}{4}[/tex] feet

To find the area of the window:

The window is in rectangular shape.

Formula for the area of the rectangle = base × height

Substitute the given values in the formula.

Area of the window = [tex]8\frac{2}{3}\times 5\frac{3}{4}[/tex]

Convert mixed fraction into improper fraction.

                                [tex]$=\frac{26}{3}\times \frac{23}{4}[/tex]

Multiply the numerators and denominators separately.

                               [tex]$=\frac{598}{12}[/tex]

Divide the numerator and denominator by the common factor 2.

                               [tex]$=\frac{598\div2}{12\div2}[/tex]

                               [tex]$=\frac{299}{6}[/tex]

Now convert improper fraction into mixed fraction.

                              [tex]$=49\frac{5}{6}\ \text{ft}^2[/tex]

Area of the window [tex]=49\frac{5}{6}\ \text{ft}^2[/tex].

Answer:

49 5/6 will be your answer

Step-by-step explanation:

Answer:

25.15 ponds is the weight of two year old baby corresponds to 10th percentile.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 29 pounds

Standard Deviation, σ = 3 pounds

We are given that the distribution of weight of two year old babies is a bell shaped distribution that is a normal distribution.

Formula:

[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]

We have to find the value of x such that the probability is 0.10

P(X < x)  

[tex]P( X < x) = P( z < \displaystyle\frac{x - 29}{3})=0.10[/tex]  

Calculation the value from standard normal z table, we have,  

[tex]P(z < -1.282) = 0.10[/tex]

[tex]\displaystyle\dfrac{x - 29}{3} = -1.282\\x = 25.154 \approx 25.15[/tex]

Thus, 25.15 ponds is the weight of two year old baby corresponds to 10th percentile.

Answer:

[tex]11b+9c+7v\leq 1256[/tex]

Step-by-step explanation:

Let 'b' plates of beef, 'c' plates of chicken, and 'v' plates of vegetarian dishes are purchased for the party.

Given:

Cost of 1 plate of beef dish = $11

Cost of 1 plate of chicken dish = $9

Cost of 1 plate of vegetarian dish = $7

Total money available to spend = $1256

So, as per question:

Total money spent on purchasing the dishes must be less than or equal to the total money available by the Math club.

Total cost of all the dishes is equal to the sum of the costs of 'b' plates of beef, 'c' plates of chicken, and 'v' plates of vegetarian dishes.

Therefore, total cost of all the dishes is given as:

Total cost = [tex]11b+9c+7v[/tex]

Now, the inequality for the given situation is:

Total cost on dishes ≤ Total money available to spend

⇒ [tex]11b+9c+7v\leq 1256[/tex]

Hence, the inequality is [tex]11b+9c+7v\leq 1256[/tex]

Answer: B.  [tex]\dfrac{28}{55}[/tex] .

Step-by-step explanation:

Given : Number of blue disks =4

Number of green disks = 8

Total disks = 12

Total number of combinations of drawing any 3 disks from 12 = [tex]^{12}C_3[/tex]

Number of combinations of drawing 1 blue and 2 green disks = [tex]^{4}C_1\times^{8}C_2[/tex]

Now , the probability that 1 of the disks selected is blue, and 2 of the disks selected are green will be :

[tex]\dfrac{^{4}C_1\times^{8}C_2}{^{12}C_3}\\\\=\dfrac{4\times\dfrac{8!}{2!6!}}{\dfrac{12!}{3!9!}}\\\\=\dfrac{4\times28}{220}\\\\=\dfrac{28}{55}[/tex]

Hence, the correct answer is B.  [tex]\dfrac{28}{55}[/tex] .

Answer:

The answer to your question is below

Step-by-step explanation:

a) The intervals in which the graph is decreasing are the right section of the first parabola, the left section of the second parabola and also the right section of the third parabola.

               (9, 11) U (14.5, 17) U (21, 27)

b) There are only two intervals in which the graph is increasing

                (1, 9) U (17, 21)

c) During the time the graph is increasing, Andre is getting away from his origin.

Answer:

Step-by-step explanation:

18 + x ≤ 28

x ≤ 28 - 18

x ≤ 10

1 ≤ x ≤ 10

The possible number of additional miles Chau can run ranges from 0 to 10 miles, which is expressed by the inequality t ≤ 10, where t represents the additional miles.

To find the possible number of additional miles Chau will run, we use the inequality that represents the situation:
Chau has run 18 miles and will run at most 28 miles in total. Thus, we have:

18 miles + t additional miles ≤ 28 miles

By isolating t, we subtract 18 from both sides of the inequality:

t ≤ 28 miles - 18 miles

t ≤ 10 miles

This inequality means that Chau can run at most 10 additional miles this week.

Therefore, the possible numbers of additional miles t that Chau can run range from 0 to 10 miles.

Option A: -24 is the coefficient of i

Explanation:

The expression is [tex](6-2 i)^{2}[/tex]

To determine the coefficient of i, first we shall find the square of the binomial for the expression [tex](6-2 i)^{2}[/tex]

The formula to find the square of the binomial for this expression is given by

[tex](a-b)^{2}=a^{2}-2 a b+b^{2}[/tex]

where [tex]a=6[/tex] and [tex]b=2i[/tex]

Substituting this value and expanding, we get,

[tex](6-2 i)^{2}=6^{2} -2(6)(2i)+(2i)^{2}[/tex]

Simplifying the terms, we have,

[tex](6-2 i)^{2}=36-24i-4[/tex]

Thus, from the above expression the coefficient of i is determined as -24.

Hence, Option A is the correct answer.

Answer: V = 8x^3-80x^3 +200x

Domain 0<x<5

Step-by-step explanation:

Dimension of cardboard = 10 by 10

Let the length of box = 10-2x

Let the width of box = 10 - 2x

Let the height of box be =x

Volume = l×w×h

V = (10-2x)×(10-2x)×x

V= 100 - 40x +42 × x

V= 8x^3 -80x^2 +200x

The volume of the box as a function of x is 8x³ - 80x² + 200x

The formula to calculate volume will be:

= Length × Width × Height

The dimensions of the cardboard will be:

Length = 10 - 2x

Width = 10 - 2x

Height = x

Therefore, the volume will be:

= (10 - 2x) × (10 - 2x) × x

= 8x³ - 80x² + 200x

Therefore, the volume of the box as a function of x is 8x³ - 80x² + 200x.

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Answer:

Zeke will catch up with Niko at 16 yards from the start line, y = 16 yards.

Zeke will catch up Niko after 8 seconds, x = 8 seconds.

Step-by-step explanation:

i) distance to be run = 30 yards

ii) Niko has a head start of 12 yards.

iii) speed of Zeke = 2 yards / second

iv) speed of Niko = 1 yard every 2 seconds  = 0.5 yard / second

v) x represents the number of seconds they have been racing.

vi) y represents the distance from the start line.

vii) the time at which Zeke catches up with Niko will be given by

     [tex]x = \frac{y - 12}{0.5} = \frac{y}{2}[/tex]

    Therefore 2y - 24 = 0.5y     [tex]\Rightarrow[/tex]  1.5 y = 24    [tex]\therefore[/tex] y = 24 / 1.5  = 16 yards

Therefore x  = 16 /2  = 8 seconds

The equations that represent Niko's and Zeke's distance from the start line are [tex]y = 12 + \frac 12 x[/tex] and [tex]y = 2 x[/tex], respectively.

The given parameters are:

[tex]Total = 30[/tex] --- the total distance

Niko is 12 yards ahead, and runs at 1 yard per 2 seconds. So, Niko's equation is

[tex]N i k o = 12 + \frac 12 x[/tex]

Zeke runs 2 yards per seconds. So, Zeke's equation is

[tex]Zeke = 2 x[/tex]

Hence, Niko's and Zeke's distance from the start line are [tex]y = 12 + \frac 12 x[/tex] and [tex]y = 2 x[/tex], respectively.

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Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

[tex]f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)[/tex]

We need to equalize f' to 0

Thus, the value of x that gives the maximum transmission is 1/√e.

The rate of transmission in a telegraph cable is given by the equation: rate of transmission = x^2 ln(1/x), where x is the ratio of the radius of the core to the thickness of the insulation.

The rate of transmission in a telegraph cable is given by the equation: rate of transmission = x2 ln(1/x), where x is the ratio of the radius of the core to the thickness of the insulation.

This equation shows that the rate of transmission is directly proportional to the square of x and logarithmically inversely proportional to x.

For example, if x is 0.5, the rate of transmission is (0.5)2 ln(1/0.5) = 0.25 ln(2).

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Final answer:

The question is a mathematical problem where we find that Devon has 70 points after setting up and solving an algebraic equation based on the conditions given.

Explanation:

The student's question revolves around a Mathematical problem concerning the points scored by two players, Erin and Devon, in a game. Erin has 42 points, and the question provides a condition that if Devon had 14 more points, he would have double the points Erin has. This scenario can be translated into an algebraic equation to solve for the number of points Devon currently has.

Let's denote the current number of points Devon has as D. According to the problem, if Devon had 14 more points, his total would be D + 14. We are also told that this hypothetical total would be double the points Erin has, which is 42. Therefore, we can write the equation as:

D + 14 = 2 × 42

By solving this equation, we can find out how many points Devon has:

Devon currently has 70 points.

Erin has 42 points. Devon has 70 points. If he had 14 more, he'd have double Erin's points.

let's break it down step by step:

Given:

- Erin has 42 points.

- If Devon had 14 more points, he'd have double the points Erin has.

Let's denote Devon's points as [tex]\( D \).[/tex]

According to the given information, if Devon had 14 more points, he'd have double the points Erin has. So, mathematically, we can represent Devon's points as [tex]\( 2 \times 42 \)[/tex] when we add those 14 points.

So, we can write the equation:

[tex]\[ D + 14 = 2 \times 42 \][/tex]

Now, let's solve for [tex]\( D \):[/tex]

[tex]\[ D + 14 = 84 \][/tex]

Subtract 14 from both sides of the equation:

[tex]\[ D = 84 - 14 \]\[ D = 70 \][/tex]

So, Devon currently has 70 points.

Answer:

255 sequence

Step-by-step explanation:

Since

Head replaced by 1

Tail replaced by 0

For each toss, there are two possible outcomes: heads 1, or tails 0.

For 9 toss the possible outcome sequence range from

000000000 to 111111111

000000000 in binary = 0 in decimal

111111111 in binary = 511 in decimal

Since we are asked to find decimal corresponding to the observed set of heads and tails that exceed 256?

That is sequence that exceed 256 (100000000)

Which is 257 (100000001) to n

So the outcome sequence will range from 257 to the last possible outcome sequence for 9 tosses which is 511

Therefore between 257 to 511.

Number of outcome sequence is 255

Question is Incomplete,Complete question is given below;

At a college, the cost of tuition increased by 10%. Let b be the former cost of tuition. Use the expression b + 0.10b for the new cost of tuition.

a)  Write an equivalent expression by combining like terms.

b)  What does your equivalent expression tell you about how to find the new cost of tuition?

Answer:

a. The equivalent expression is [tex]1.1b[/tex].

b. The new cost of tuition is 1.1 times the former cost of tuition.

Step-by-step explanation:

Given:

Former cost of tuition = [tex]b[/tex]

the cost of tuition increased by 10%.

New cost of tuition = [tex]b+0.10b[/tex]

Solving for part a.

we need to find the equivalent expression by combining the like terms we get;

Now Combining the like terms we get;

new cost of tuition = [tex]b(1+0.1) = 1.1b[/tex]

Hence The equivalent expression is [tex]1.1b[/tex].

Solving for part b.

we need to to say about equivalent expression about how to find the new cost of tuition.

Solution:

new cost of tuition = [tex]1.1b[/tex]

So we can say that.

The new cost of tuition is 1.1 times the former cost of tuition.

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let A = a part is supplied by supplier A, B = a part is supplied by supplier B and D = a part is defective.

Given:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event A and B is:

[tex]P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20[/tex]

Compute the probability of selecting a defective product:

[tex]P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058[/tex]

The probability of selecting a non-defective part provided by supplier A is:

[tex]P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807[/tex]

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

The required probability of selecting a non-defective part provided by supplier A is 0.807.

Let,

A part is supplied by supplier A,

B part is supplied by supplier B,

And D = a part is defective.

Given:

P ([tex]\frac{D}{A}[/tex]) =5% = 0.05,

P([tex]\frac{D}{B}[/tex]) = 9% =  0.09

A supplies four times as many parts as B, .

Then, n (A) = 4 and n (B) = 1.

The probability of event A and B is:

Probability of event P(A) = [tex]\frac{n (A)}{n (A) + n(B)}[/tex] = [tex]\frac{4}{4+1}[/tex]

                                 P(A) = [tex]\frac{4}{5}[/tex]

And Probability of Event P(B) = [tex]\frac{n (B )}{n (A) + n(B)} = \frac{1}{4+1}[/tex]

                                        P(B) = [tex]\frac{1}{5}[/tex]

Then , the probability of selecting a defective product:

P(D) = [tex]P(\frac{D}{A}) P(A) + P(\frac{D}{B}) P(B)[/tex]

P(D) = 0.50×0.80 + 0.09×0.20

P(D) = 0.058

The probability of selecting a non-defective part provided by supplier A is

[tex]P(\frac{A}{D'} )= \frac{P(D'(A)) . P(A)}{P(D')} \\\\[/tex]

          = [tex]\frac{1- P(D(A)). P(A)}{1-P(A)} \\\\\frac{(1-0.05) . 0.80}{1- 0.05} \\\\[/tex]

          = 0.807

Hence, the probability of selecting a non-defective part provided by supplier A is 0.807.

For more information about Probability click the live given below.

https://brainly.com/question/23044118

Answer:

61.12 units²

Step-by-step explanation:

(½ × pi × r²) + (½ × b × h)

½ [(3.14 × 4²) + (8 ×9)]

½(122.24)

61.12 units²

Answer:

61.13 units squared

Step-by-step explanation:

This figure is composed of a semicircle and a triangle. Let's find these areas separately:

1) SEMICIRCLE:

The area of a semicircle is: [tex]A=\frac{\pi r^2}{2}[/tex] , where r is the radius (which is the distance from the center to a point on the circle). In this case, the radius of the circle is 4. So, we have:

[tex]A=\frac{\pi *4^2}{2} =\frac{16\pi }{2} =8\pi[/tex] ≈ 25.13 units squared

2) TRIANGLE:

The area of a triangle is: [tex]A=\frac{bh}{2}[/tex] , where b is the base and h is the height. Here, the base is 8 (b = 8) and the height is 9 (h = 9). So, we have:

[tex]A=\frac{8*9}{2} =\frac{72}{2} =36[/tex] units squared

Finally, we add these two areas together:

25.13 + 36 = 61.13 units squared.

Hope this helps!

Answer:

Home away should record the contribution to a Net assets with donor restriction

Step-by-step explanation

A Net asset with donor restriction is the part of net assets of a not- for - profit making organisation  that is subject to donor-imposed restrictions.  

The stipulation that the fund of $15,000 should be used to buy beds automatically makes it to be classified as a Net assets with donor restriction  item.