[tex]\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]
[tex]\bf \stackrel{\textit{"x" varies with "y"}}{x=ky}\qquad \textit{we also know that } \begin{cases} x=7.5\\ y=10 \end{cases}\implies 7.5=k(10) \\\\\\ \cfrac{7.5}{10}\implies \cfrac{~~\frac{15}{2}~~}{10}=k\implies \cfrac{3}{4}=k~\hfill \boxed{x=\cfrac{3}{4}y} \\\\\\ \textit{when y = 4, what is \underline{x}?}\qquad x=\cfrac{3}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}(~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~)\implies x=3[/tex]
Nancy sold cosmetics products on a commission if her total sale for the month were 2000 and her rate of commission was 7.5% what was the amount of her commission
Answer:
The amount of her commission= 150
Step-by-step explanation:
Sale price = 2000
Rate of commission = 7.5%
Amount of commission =?
Formula:
Commission_amount = sale price * commission_percentage / 100
Now put the values in the formula.
Commission_amount=2000*7.5/100
Commission_amount=150.
Thus the amount of her commission is 150....
The sum of the numerator and the denominator of
a fraction is 4 more than twice the numerator. If 3
is added to each of the numerator and denominator,
their ratio becomes 2 : 3. Find the fraction.
Step-by-step explanation:
(1)
Let the numerator be x and denominator be y. A/Q x + y = 4 + 2x → - x + y = 4
(2)
multiplying each term by 2, 2x-2y= -8
(3)
Also, (x+3) / (y+3) = 2 / 3 → 3x - 2y = -3
Subtracting (2) from (3) → x = 5 and by putting this in (1) we can get y=9. Hence, the fraction is 5 / 9
Answer:
[tex]\frac{5}{9}[/tex]
Step-by-step explanation:
let the fraction be [tex]\frac{x}{y}[/tex], then
x + y = 2x + 4 ( subtract x from both sides )
y = x + 4 → (1)
If 3 is added to numerator and denominator, then
[tex]\frac{x+3}{y+3}[/tex] = [tex]\frac{2}{3}[/tex] ( cross- multiply )
3(x + 3) = 2(y + 3) ← distribute both sides
3x + 9 = 2y + 6 ← substitute y = x + 4
3x + 9 = 2(x + 4) + 6
3x + 9 = 2x + 8 + 6 = 2x + 14 ( subtract 2x from both sides )
x + 9 = 14 ( subtract 9 from both sides )
x = 5
Substitute x = 5 into (1)
y = 5 + 4 = 9
Hence the original fraction is [tex]\frac{5}{9}[/tex]
which function is odd check all that apply
a. y=sin x
b. y=csc x
c. y=cot x
d. y=sec x
Answer:
a) y = sin x
b) y = csc x
c) y = cot x
Step-by-step explanation:
only d is even
whats the difference of 2 times d minus 3
a.2
b.1 c.4
d.3
e.0
Answer:
2(d - 3) is the equation. You cannot solve for d. You can only simplify it
What is the simplest form of 3square root 27a3b7
Answer:
= [tex]3ab^{\frac{2}{3} }[/tex]
Step-by-step explanation:
∛(27 a³ [tex]b^{7}[/tex])
= ∛27 · ∛a³ · ∛b³ · ∛b³ · ∛b
= 3 · a · b · b ∛b
= 3ab² [tex]b^{\frac{1}{3} }[/tex]
or
= [tex]3ab^{\frac{2}{3} }[/tex]
Problem
At full speed, Hal travels 600 miles in 2 hours
with the wind. The same distance against
the wind takes 3 hours.
What's the maximum speed of Hal's airplane
in still air? What's the speed of the wind?
Answer:
The maximum speed of Hal's airplane in still air is:
[tex]v= 250\ miles/h[/tex]
The speed of the wind
[tex]c = 50\ miles/h[/tex]
Step-by-step explanation:
Remember that the velocity v equals the distance d between time t.
[tex]v=\frac{d}{t}[/tex] and [tex]t*v=d[/tex]
The distance that Hal travels when traveling with the wind is:
[tex](2\ hours)(v + c) = 600[/tex] miles
Where v is the speed of Hal and c is the wind speed.
The distance when traveling against the wind is:
[tex](3\ hours)(v-c) = 600[/tex] miles
Now we solve the first equation for v
[tex](2)(v + c) = 600[/tex]
[tex]2v + 2c = 600[/tex]
[tex]2v= 600-2c[/tex]
[tex]v= 300-c[/tex]
Now we substitute the value of v in the second equation and solve for c
[tex]3((300-c)-c) = 600[/tex]
[tex]3(300-2c) = 600[/tex]
[tex]900-6c = 600[/tex]
[tex]-6c = 600-900[/tex]
[tex]-6c = -300[/tex]
[tex]6c = 300[/tex]
[tex]c = 50\ miles/h[/tex]
Then:
[tex]v= 300-(50)[/tex]
[tex]v= 250\ miles/h[/tex]
The maximum speed of Hal's airplane in still air is:
[tex]v= 250\ miles/h[/tex]
The speed of the wind
[tex]c = 50\ miles/h[/tex]
Find the value of the function sin
7pi/2
Answer:
The answer is D: -1.00
Step-by-step explanation:
I just took the test on edg 2020 and got it correct
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The required value of the given trigonometric ratio is - 1.
Hence option D is correct.
Use the concept of trigonometric ratio defined as:
Trigonometric ratios are based on the value of the ratio of sides of a right-angled triangle and contain all trigonometric functions' values.
The trigonometric ratios of an acute angle supplied are the ratios of the sides of a right-angled triangle with respect to that angle.
The given trigonometric ratio is,
[tex]\text{sin}(\dfrac{7\pi}{2})[/tex]
Since we can write the expression of radian as,
[tex]\dfrac{7\pi}{2} = 3\pi + \dfrac{\pi}{2}[/tex]
Then,
[tex]\text{sin}(\dfrac{7\pi}{2}) = \text{sin}(3\pi + \dfrac{\pi}{2})[/tex]
Since we know that,
sin(3π + θ) = -sinθ
Therefore,
[tex]\text{sin}(3\pi + \dfrac{\pi}{2}) = -\text{sin}(\dfrac{\pi}{2})[/tex]
Ans we also know sin(π/2) = 1
So,
[tex]\text{sin}(\dfrac{7\pi}{2}) = -1.00[/tex]
Hence, the required value of the given trigonometric ratio is - 1 which is option D.
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How do you answer a, b and c, answers and also how you worked it out
We can either convert to standard form first or convert to a common multiplier, kinda like a common denominator. The latter makes more sense if they wanted the result in scientific notation, but let's do it that way anyway.
a)
4.5 × 10⁴ + 3.8 × 10³ = 45 × 10³ + 3.8 × 10³ = 48.8× 10³ = 48,800
Answer: 48,800
b)
4.5 × 10⁴ - 3.8 × 10³ = 45 × 10³ - 3.8 × 10³ = 41.2× 10³ = 41,200
Answer: 41,200
c)
7.2 × 10⁻³ + 6.3 × 10⁻² = 7.2 × 10⁻³ + 63 × 10⁻³ = 70.2 × 10⁻³
= 7.02 × 10⁻² = 0.0702
Answer: 0.0702
20 POINTS
WILL MARK BRAINLIEST
The last two pictures are to question two.
Answer:
The total surface area of the solid is 702 cm² ⇒ answer B
The true statements are m∠WYX = 46° and m∠YWX = 63° ⇒ 1st and 2nd answers
Step-by-step explanation:
* Lets explain the solid figure
- It has one rectangular base of dimensions 10 cm and 14 cm
- It has 4 rectangular side faces , two of dimensions 6 cm and 10 cm
and another two of dimensions 6 cm and 14 cm
- It has 4 triangular faces , two of base 10 cm and height 12 cm and
another two of base 14 cm and height 11 cm
- The total surface area of the solid is the sum of the area of the 9 faces
* Lets find the area of all the faces
# Area of the base
∵ The base is a rectangle
∵ Area of the rectangle = length × width
∵ Length = 14 cm and width = 10 cm
∴ Area of the base = 14 × 10 = 140 cm²
# Area of the four rectangular faces
∵ Length = 10 cm and width = 6 cm
∴ The area of the face with dimensions 10 , 6 = 10 × 6 = 60 cm²
∵ Length = 14 cm and width = 6 cm
∴ The area of the face with dimensions 14 , 6 = 14 × 6 = 84 cm²
# Area of the four triangular faces
∵ Area of a triangle = 1/2 × base × height
∵ The base = 10 cm and the height = 12 cm
∴ The area of the face = 1/2 × 10 × 12 = 60 cm²
∵ The base = 14 cm and the height = 11 cm
∴ The area of the face = 1/2 × 14 × 11 = 77 cm²
∵ The total surface area of the solid = the sum of the areas of 9 faces
∴ TSA = 140 + 2 × 60 + 2 × 84 + 2 × 60 + 2 × 77
∴ TSA = 140 + 120 + 168 + 120 + 154 = 702 cm²
* The total surface area of the solid is 702 cm²
* Lets solve the 2nd part
- WXY is a scalene triangle
- m∠WXY is 71°
- The two sides of the triangle WY and XY exceeded
- The ray WY and the ray XY intersect each other at point Y and
formed vertically opposite angles with measure 46°
∵ Ray WY intersect ray XY at point Y
∴ m∠WYX = 46°
- In Δ WYX
∵ m∠WXY = 71° ⇒ given
∵ m∠WYX = 46° ⇒ proved
∵ The sum of the measures of the interior angles of a triangle is 180°
∴ m∠YWX + m∠WXY + m∠WYX = 180°
∴ m∠YWX + 71° + 46° = 180
∴ m∠YWX + 117° = 180° ⇒ subtract 117 from both sides
∴ m∠YWX = 63°
Lets check the true statements
# m∠WYX = 46° ⇒ true
# m∠YWX = 63° ⇒ true
# m∠WXY = 46° ⇒ not true
# m∠YWX = 46° ⇒ not true
# m∠WYX = 134° ⇒ not true
* The true statements are m∠WYX = 46° and m∠YWX = 63°
y=3x^2 + 7 + m have two intercepts ?
Answer:
In general, quadratic equations have two x-intercepts. But sometimes it happens that a quadratic eqution has one x-intercept or no interepts. That's why we should fully analyze this equation:
Given the following equation: y=3x^2 + 7 + m
If y=0, then:
3x^2 + 7 + m = 0 ⇒ x^2 = (-m-7)/3
Then [tex]x =[/tex]± [tex]\sqrt{\frac{-m-7}{3}}[/tex]
Given that we can take the square root of a negative number, the only way this equation has two x-intercepts is if m<-7.
Summarizing:
The equation: y=3x^2 + 7 + m has two x-intercepts only if m is less than -7. If m equals -7, the equation has only one x-intercept, and finally, if m is greater than -7, the equation has NO x-intercepts.
which function has the same y-intercept as the function. y=2/3x-3
A. 2/3x +3y=-3
B.-2/3x+3y=6
C. 6x-7y=21
D. x+4y=12
Answer:
C. 6x - 7y = 21
Step-by-step explanation:
y=2/3 x - 3, y-intercept = -3
A. 2/3 x + 3y = -3
3y = -2/3 x - 3
y = -2x - 1; y-intercept = -1
B.-2/3 x + 3y = 6
3y = 2/3 x + 6
y = 2x + 2; y-intercept = 2
C. 6x-7y=21
7y = 6x - 21
y = 6/7 x - 3; y-intercept = -3
D. x+4y = 12
4y = -x +12
y = -1/4 + 3; y-intercept = 3
Answer is C. 6x - 7y = 21
Find the area of the hexagon to the nearest tenth.
One of the solutions to x2 - 2x – 15 = 0 is x = -3. What is the other solution?
Ox=-5
Ox= -1
0 x=1
x = 5
Answer:
x=5
Step-by-step explanation:
Factoring x2 - 2x – 15 we get
(x+3)(x-5) so x+3=0 and x-5=0 or x=-3 and x=5
Answer:
x=5
Step-by-step explanation:
x^2 - 2x – 15 = 0
Factor
What 2 numbers multiply to -15 and add to -2
-5*3 = -15
-5+3 = -2
(x-5) (x+3) = 0
Using the zero product property
(x-5) =0 x+3 =0
x-5+5 =0+5 x+3-3 = 0-3
x=5 x=-3
In The Diagram △ ABC≅ △ECD. Which statement is true?
A.) Angle BCA ≅ Angle ECD
B.)Angle CAB ≅ Angle ECD
C.)BC≅ED
D.)AB≅CE
Answer:
The correct option is D.
Step-by-step explanation:
Given information: △ABC≅△ECD.
The corresponding parts of congruent triangles are congruent.
The congruent angles are :
[tex]\angle A\cong \angle E[/tex]
[tex]\angle B\cong \angle C[/tex]
[tex]\angle C\cong \angle D[/tex]
[tex]\triangle BCA\cong \triangle CDE[/tex]
Option A is incorrect.
[tex]\triangle CAB\cong \triangle DEC[/tex]
Option B is incorrect.
The congruent sides are :
[tex]BC\cong CD[/tex]
Option C is incorrect.
[tex]AC\cong ED[/tex]
[tex]AB\cong EC[/tex]
It can also written as
[tex]AB\cong CE[/tex] [tex][\because EC=CE,\text{Reflective Property}][/tex]
Therefore the correct option is D.
The correct statement is BC ≅ ED.
Explanation:The correct statement is BC ≅ ED.
Since △ABC ≅ △ECD, the corresponding sides and angles of the triangles are congruent.
Therefore, we can conclude that BC ≅ ED.
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Which relation is a function?
Can Sb help please
A relation is a function if you associate exactly one output for every input. This means that, when you choose a value for x, there must be only one correspondent value for y. This only happens in the top-right parabola.
If f(x)=2x^2+1, what is f(x) when x=3?
Answer:
19
Step-by-step explanation:
Plug in x = 3 into the function
f(x)=2x^2+1
f(x)=2(3)^2+1
f(x)=18+1
f(x)=19
The answer is:
f(3) = 19
Work/explanation:
To evaluate this function, plug in 3 for x:
[tex]\sf{f(x)=2x^2+1}[/tex]
[tex]\sf{f(3)=2(3)^2+1}[/tex]
[tex]\sf{f(3)=2\times9+1}[/tex]
Then, according to PEMDAS, we multiply:
[tex]\sf{f(3)=18+1}[/tex]
[tex]\sf{f(3)=19}[/tex]
Therefore, when x = 3, the function evaluates to 19.
How many vertical asymptotes does the graph of this function have f(x)=3/(x-11)(x+4)
Answer:
2
Step-by-step explanation:
The function is given as [tex]f(x)=\frac{3}{(x-11)(x+4)}[/tex]
Vertical asymptotes occur when the denominator is set to 0.
Thus,
(x-11)(x+4) = 0
x = 11 or x = -4
Hence, there are 2 vertical asymptotes
Answer: 2
Step-by-step explanation:
A P E X
pLeAsE HeLp
What is the domain of y=logx?
All real numbers less than 0
All real numbers greater than 0
All real numbers not equal to 0
All real numbers
Answer:all real number greater than 0
Step-by-step explanation:
Firstly if you input any number equal to 0 or less than 0 you will not find the defined range...
You cant use o or any negetive number as domain in the term of log or ln type math..
But if u put any value more than 0 you can find all real number as range
Such as, log(0.001)=-3
log(1)=0
log(120)=2.07
So the domain is all real number above o...but the range is all real number including 0 and negetive number..
The domain of y=logx is all real numbers greater than 0.
So, firstly we input any number equal to 0 or less than 0 then we will not find the defined range.We can't use 0 or any negative number as the domain in the term of log or in type mths.But if we put any value more than 0 then we will find that all are real numbers as a range such example given below[tex]log(0.001)=-3[/tex][tex]log1=0[/tex][tex]log120=2.07[/tex]So, the domain is all real numbers above 0But the range is all real numbers including 0 and negative numbers.Hence, option b is the correct answer.
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Which is the graph of x-y=1?
Answer:
In graph
Step-by-step explanation:
First put it in Slope -Intercept form.
then graph the y- intercept first.
After that it's rise over run so think 1/1
up 1 over one.
Answer:
CCCCCCCCCCCCC
Step-by-step explanation:
Write the slope-intercept form of the line that passes through the point (1, 0) and is parallel to x - y = 7. T
Answer:
y = x -1
Step-by-step explanation:
x - y = 7
We need to put this in slope intercept form to find the slope.
Add y to each side
x-y+y =7+y
x = y+7
Subtract 7 from each side
x-7 = y+7-7
x-7 = y
The slope is 1 since it is in the form y = mx+b
We have a slope 1 and an point (1,0)
We can use point slope form to make an equation
y-y1 = m(x-x1)
y-0 = 1(x-1)
y = x -1
This is in slope intercept form
the line passing through point (0, 0) and parallel to the line whose equation is 3x + 2y - 6 = 0
Answer: y= -3/2x
Explanation:
3x+ 2y- 6
→ 2y= -3x+ 6
→ y= -3/2x+ 3
Parallel to y= ax+ b is to have the same slope (ax) and have a different y- intercept.
For this equation, y= -3/2x + 3, it is y= -3/2x because the line has to pass through point (0,0).
Which of the following is not a solution to the system of linear equations below?
5y = 3x+15
6x = 10y– 30
A. (5,6)
B. (–15, 12)
C. (0,3)
D. (-10,-3)
Answer:
B. (-15, 12)Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}5y=3x+15&\text{subtract 3x from both sides}\\6x=10y-30&\text{subtract 10y from both sides}\end{array}\right\\\left\{\begin{array}{ccc}-3x+5y=15\\6x-10y=-30&\text{divide both sides by 2}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-3x+5y=15\\3x-5y=-15\end{array}\right}\\.\qquad0=0\qquad\bold{TRUE}\\\\\bold{Infinitely\ many\ solutions}\\\\5y=3x+15\qquad\text{divide both sides by 5}\\\\y=\dfrac{3}{5}x+3\qquad(*)\\\\\text{Put the coordinates of the points to the equation (*)}[/tex]
[tex]A.\ (5,\ 6)\\\\6=\dfrac{3}{5}(5)+3\\\\6=3+3\\\\6=6\qquad\bold{CORRECT}\\\\B.\ (-15,\ 12)\\\\12=\dfrac{3}{5}(-15)+3\\\\12=(3)(-3)+3\\\\12=-9+3\\\\12=-6\qquad\bold{FALSE}\\\\C.\ (0,\ 3)\\\\3=\dfrac{3}{5}(0)+3\\\\3=0+3\\\\3=3\qquad\bold{CORRECT}\\\\D.\ (-10,\ -3)\\\\-3=\dfrac{3}{5}(-10)+3\\\\-3=(3)(-2)+3\\\\-3=-6+3\\\\-3=-3\qquad\bold{CORRECT}[/tex]
Polygon A is 4 times smaller than polygon B. If one side of polygon B measures 20 inches, what does the matching side of polygon A measure?
A matching side of Polygon A measures 5 inches if it is 4 times smaller than a side of Polygon B that measures 20 inches.
Explanation:If Polygon A is 4 times smaller than Polygon B, and a side of Polygon B measures 20 inches, then the matching side of Polygon A measures 5 inches. This is because when an object is said to be 'x times smaller' than another, you divide the original size by 'x' to find the new size. Therefore, the matching side length of Polygon A would be 20 inches ÷ 4 = 5 inches.
Example related to area comparison between two squares: Marta has a square with a side length of 4 inches. She has another square with side lengths that are twice as long. The side length of the larger square would be 4 inches x 2 = 8 inches. Since the area of a square is the side length squared, the area of the larger square would be 8 inches x 8 inches = 64 square inches, which is 4 times the area of the smaller square (16 square inches).
Which of the following is an even function?
f(x) = |x|
f(x) = x3 – 1
f(x) = –3x
Answer:
f(x) = |x|
Step-by-step explanation:
Only f(x) = |x| is an even function. If you evaluate this function at x = 3, for example, the result is 3; if at x = -3, the result is still 3. That's a hallmark of even functions.
Answer:
f(x) = |x|
Step-by-step explanation:
If we keep -x in place of x and it does not effect the given function, then it is even function. i.e. f(-x) = f(x).
and, If we put -x in place of x then the resultant function will get negative of the first function, then it is odd function. i.e. f(-x) = -f(x).
1. f(x) = |x|
Put x = -x ,then
f(-x) = |-x| = |x| = f(x)
Hence, f(x) is even function.
2.f(x) = x³ - 1
Put x = -x, then
f(-x) = (-x)³ - 1
= -x³ - 1 = -f(x)
Hence, this function is odd.
3. f(x) = -3x
Put x = -x
then, f(-x) = -3(-x)
= 3x = -f(x)
Hence, the given function is odd function.
Thus, only f(x) = |x| is even function.
40 points?With explanation
Answer:
46°
Step-by-step explanation:
Alternate angles from 46° and alternate angles are equal
What are the solutions of this system of equations?
The first three steps in determining the solution set of the
system of equations algebraically are shown.
y = x2 - x-3
y=-3x + 5
(-2, -1) and (4, 17)
(-2, 11) and (4, -7)
(2, -1) and (-4, 17)
(2, 11) and (-4,-7)
Step
1
2
Equation
x– X-3 = -3x +5
0 = x² + 2x - 8
0 = (x-2)(x+4)
3
Answer:
Option C is correct.
Step-by-step explanation:
y = x^2-x-3 eq(1)
y = -3x + 5 eq(2)
We can solve by substituting the value of y in eq(2) in the eq(1)
-3x+5 = x^2-x-3
x^2-x+3x-3-5=0
x^2+2x-8=0
Now factorizing the above equation
x^2+4x-2x-8=0
x(x+4)-2(x+4)=0
(x-2)(x+4)=0
(x-2)=0 and (x+4)=0
x=2 and x=-4
Now finding the value of y by placing value of x in the above eq(2)
put x =2
y = -3x + 5
y = -3(2) + 5
y = -6+5
y = -1
Now, put x = -4
y = -3x + 5
y = -3(-4) + 5
y = 12+5
y =17
so, when x=2, y =-1 and x=-4 y=17
(2,-1) and (-4,17) is the solution.
So, Option C is correct.
Answer: Third Option
(2, -1) and (-4, 17)
Step-by-step explanation:
We have the following system of equations:
[tex]y = x^2 - x-3[/tex]
[tex]y=-3x + 5[/tex]
We have the first three steps to solve the system.
[tex]x^2- x-3 = -3x +5[/tex] equal both equations
[tex]0 = x^2 + 2x - 8[/tex] Simplify and equalize to zero
[tex]0 = (x-2)(x+4)[/tex] Factorize
Then note that the equation is equal to zero when [tex]x = 2[/tex] or [tex]x = -4[/tex]
Now substitute the values of x in either of the two situations to obtain the value of the variable y.
[tex]y=-3(2) + 5[/tex]
[tex]y=-6 + 5[/tex]
[tex]y=-1[/tex]
First solution: (2, -1)
[tex]y=-3(-4) + 5[/tex]
[tex]y=12 + 5[/tex]
[tex]y=17[/tex]
Second solution: (-4, 17)
The answer is the third option
which is the graph of the inequality? 3y - 9x ≥ 9
The inequality 3y - 9x ≥ 9, you can start by rearranging it into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. Now, you can graph the line y = 3x + 3. When graphing the inequality, you will shade the region above the line, which represents the solutions to the inequality 3y - 9x ≥ 9.
To graph the inequality 3y - 9x ≥ 9, you can start by rearranging it into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
3y - 9x ≥ 9
3y ≥ 9x + 9
y ≥ 3x + 3
Now, you can graph the line y = 3x + 3.
When graphing the inequality, you will shade the region above the line. The shading represents the solutions to the inequality 3y - 9x ≥ 9.
Here's how you can graph it:
Plot the y-intercept at y = 3 on the y-axis.Use the slope m = 3 to find another point. For example, move up 3 units and to the right 1 unit from the y-intercept, and plot another point.Draw a solid line through these two points.WHAT IS ANOTHER WAY TO WRITE 6%
Answer:
3/50 or 0.06
Step-by-step explanation:
6/100=3/50
6/100=0.06
Answer:
0.06
Step-by-step explanation:
Which two- way table contains the same information as the venn diagram?
Answer: C
Step-by-step explanation:
20 people have a dog: 8 are yes dog/yes cat & 12 are yes dog/no cat
17 people have no dog: 10 are no dog/yes cat & 7 are no dog/no cat
[tex]\begin{array}{c|c|c|c}\underline{\qquad \qquad}&\underline{Cat}&\underline{No\ Cat}&\underline{TOTAL}\\Dog&8&12&20\\\underline{\ No\ Dog\ }&\underline{\ 10\ }&\underline{\quad 7\quad }&\underline{\quad 17\quad }\\TOTAL&18&19&37\end{array}[/tex]
Which of the following is a classified as a binomial? A. 3x^3 -6x^2-x B. 6x^3-6x^2+x-1 C. 3x^3-6x D. 6x^3
Answer: C
Step-by-step explanation:
Binomial have only two terms.
A) 3x²-6x²-+x has three terms
B) 6x³-6x²+x-1 has four terms
C) 3x³-6x has two terms
D) 6x³ has only one term