Answer:
30 electrons
Explanation:
Atoms are made of electrons, protons and neutrons.Protons and neutrons are in the nucleus and electrons are orbiting in energy shells around the nucleus. Atomic number is the number of protons and atomic number is characteristic for the element.
protons are positively charged and electrons are negatively charged. Neutral atoms are when the number of protons and electrons are equal.
Therefore this atoms atomic number is 30 where the number of protons is 30, and in the neutral atom since the number of protons is equal to the number of electrons, the number of electrons is 30
B. For the following questions, use the reaction NO2(g) N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS= 63.02 J/(mol·K).
i. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.
ii. Is the reaction endothermic or exothermic? Explain your answer. (2 points)
iii. What is the Gibbs free energy of the reaction at 25°C?
iv. Is the reaction spontaneous or nonspontaneous at 25°C? Explain your answer.
Answer:
I. Kindly, see the attached image.
II. The reaction is exothermic.
III. - 51.88 kJ/mol.
IV. The reaction is spontaneous.
Explanation:
I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.
Since the sign of ΔH is negative, the reaction is exothermic reaction.In an exothermic reaction, the energy of the reactants is higher than that of the products.
Kindly see the attached image to show you the potential energy diagram of the reaction.
II. Is the reaction endothermic or exothermic? Explain your answer.
The reaction is exothermic reaction.The sign of ΔH indicates wither the reaction is endothermic or exothermic one:If the sign is positive, the reaction is endothermic.
If the sign is negative, the reaction is exothermic.
Herein, ΔH = - 33.1 kJ/mol, so the reaction is exothermic.
III. What is the Gibbs free energy of the reaction at 25°C?
∵ ΔG = ΔH - TΔS.
Where, ΔG is the Gibbs free energy change (J/mol).
ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).
T is the temperature (T = 25°C + 273 = 298 K).
ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).
∴ ΔG = ΔH - TΔS = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = - 51.88 kJ/mol.
IV. Is the reaction spontaneous or nonspontaneous at 25°C?
The sign of ΔG indicates the spontaneity of the reaction:
If ΔG < 0, the reaction is spontaneous.
If ΔG = 0, the reaction is at equilibrium.
If ΔG > 0, the reaction is nonspontaneous.
Herein, ΔG = - 51.88 kJ/mol, so the reaction is spontaneous.
The reaction NO2(g) → N2(g) + O2(g) is exothermic as indicated by the negative ΔH. The Gibbs free energy (ΔG) at 25°C is calculated to be -51.9996 kJ/mol, which signifies that the reaction is spontaneous at this temperature.
Explanation:Understanding Chemical Reactions and ThermodynamicsFor the reaction NO2(g) → N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS = 63.02 J/(mol·K):
Potential energy diagram: Since this is a text-based response, we can describe the diagram. At the beginning we have the reactants at a higher potential energy level; then there's a peak representing the activation energy. Following this peak, the products are at a lower potential energy level by 33.1 kJ/mol, illustrating an exothermic reaction.Endothermic or exothermic: The reaction is exothermic since the enthalpy change (ΔH) is negative, indicating that energy is released.Gibbs free energy at 25°C: ΔG can be calculated using the equation ΔG = ΔH - TΔS. Plugging in the values we get ΔG = (-33.1 kJ/mol) - (298 K)(63.02 J/mol·K × 1 kJ/1000 J) = -33.1 kJ/mol - 18.8996 kJ/mol = -51.9996 kJ/mol.Spontaneity at 25°C: The reaction is spontaneous at 25°C since ΔG is negative, which implies that the reaction can occur without external energy input.Learn more about Exothermic Reactions here:https://brainly.com/question/10373907
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How many grams are in 2.06x10-4 moles of calcium phosphate
Answer:
63.86 mg
Explanation:
Molar mass is the mass of 1 mol of compound / atom.
molar mass of the compound is - 310 g/mol
mass of 1 mol is - 310 g
therefore mass of 2.06 x 10⁻⁴ mol is - 310 g/mol x 2.06 x 10⁻⁴ mol = 0.06386 g
mass of calcium phosphate is - 63.86 mg
Final answer:
To find the mass of 2.06 x 10⁻⁴ moles of calcium phosphate (Ca₃(PO₄)₂), calculate the formula mass using atomic masses of calcium, phosphorus, and oxygen. The formula mass of calcium phosphate is 310.18 g/mol. Multiplying this by the moles gives you 0.0639 grams of calcium phosphate.
Explanation:
To calculate the mass in grams of 2.06 x 10⁻⁴ moles of calcium phosphate (Ca₃(PO₄)₂), you must know the formula mass of calcium phosphate. The empirical formula indicates the compound contains three calcium ions (Ca⁺²) and two phosphate ions (PO₄⁻³). The formula mass is calculated by adding together the atomic masses of the constituent atoms: three calcium atoms, two phosphorus atoms, and eight oxygen atoms.
The atomic masses are approximately 40.08 g/mol for calcium, 30.97 g/mol for phosphorus, and 16.00 g/mol for oxygen. Calculating the formula mass, we have:
3(Calcium) + 2(Phosphorus) + 8(Oxygen) = 3(40.08 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 310.18 g/mol
Now, to find the mass of 2.06 x 10-4 moles of calcium phosphate:
2.06 x 10⁻⁴ moles x 310.18 g/mol = 0.0639 grams
Therefore, there are 0.0639 grams of calcium phosphate in 2.06 x 10⁻⁴ moles of the compound.
Determine the original amount of Ba-142 after 1.25 hours if 9.25 mg remains. The half-life of Ba-142 is 10.6 minutes.
Answer:
1246 mg = 1.246 g.
Explanation:
The decay of radioactive elements obeys first-order kinetics.For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).Where, k is the rate constant of the reaction.
t1/2 is the half-life time of the reaction (t1/2 = 10.6 minutes).
∴ k = ln2/(t1/2) = 0.693/10.6 = 6.54 x 10⁻² min⁻¹.
For first-order reaction: kt = lna/(a-x).
where, k is the rate constant of the reaction (k = 6.54 x 10⁻² min⁻¹.).
t is the time of the reaction (t = 1.25 hr x 60 = 75.0 min).
a is the initial concentration (original amount) (a = ??? mg).
(a-x) is the remaining concentration (a-x = 9.25 mg).
∴ kt = lna/(a-x)
(6.54 x 10⁻² min⁻¹)(75.0 min) = ln a/(9.25 mg)
4.903 = ln a/(9.25 mg)
Taking e for the both sides:
134.7 = a/(9.25 mg)
∴ a = (134.7)(9.25 mg) = 1246 mg = 1.246 g.
Before the reaction occurs, the concentration of A is 0.071M. If the concentration of A at equilibrium is 0.03195M, what is the equilibrium constant? A(g) = 2B(g) + C(g)
Answer:
Assume that the initial concentration of both B and C are zero.
Kc = 7.5 × 10⁻³.
Explanation:
What's the expression for the equilibrium constant of this reversible reaction? Note that the steps here apply only to equilibriums where all species are either gaseous (g) or in an aqueous solution (aq). Solids and liquids (water in particular) barely influence the equilibrium; in many cases they should not appear in the expression for the equilibrium constant.
Raise the concentration of each product to their coefficient's power.
The coefficient in front of B is 2. Raise the concentration of B to the second power, which will give [tex][\text{B}]^{2}[/tex]. The coefficient in front of C is 1. Raise the concentration of C to the first power, which is the same as [tex][\text{C}][/tex].The product of these terms will be the numerator in the expression of the equilibrium constant. For this reaction, the numerator shall be [tex][\text{B}]^{2} \cdot[\text{C}][/tex].
Repeat these steps for the reactants:
The coefficient in front of A is 1. Raise the concentration of A to the first power, which is the same as [tex][\text{A}][/tex].If there are more than one reactants, multiple each of those terms. The product shall be the denominator of the expression for the equilibrium constant. For this reaction, the denominator shall be [tex][\text{A}][/tex].
Hence the equilibrium constant:
[tex]\displaystyle K_c = \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}[/tex],
where [tex][\text{A}][/tex], [tex][\text{B}][/tex], and [tex][\text{C}][/tex] are concentrations when the reaction is at equilibrium.
Construct a RICE table to find the equilibrium concentration of each species. R stands for reaction, I for initial conditions, C for change in concentration, and E for equilibrium conditions. Assume that only A is initially present in the system. Let the decrease in the concentration of [tex]\text{A}[/tex] be [tex]x\;\text{M}[/tex].
[tex]\begin{array}{c|ccccc}\text{R}&\text{A}\;(g) &\rightleftharpoons &2\;\text{B}\;(g)& +& \text{C}\;(g)\\ \text{I}& 0.071 \;\text{M} & & 0\;\text{M} && 0 \;\text{M} \\ \text{C} &-x \;\text{M}&&+2x\;\text{M} & & +x\;\text{M}\\\text{E}&0.071 - x\;\text{M} && 2x\;\text{M} & &x\;\text{M} \end{array}[/tex].
The coefficient in front of B is twice that in front of A. In other words, for each unit of A consumed, two units of B are produced. Assume that volume stays the same. The decrease in the concentration of [tex]\text{A}\;(g)[/tex] is [tex]x\;\text{M}[/tex]. Accordingly, the increase in the concentration of [tex]\text{B}\;(g)[/tex] shall be [tex]2x\;\text{M}[/tex].
The question states that the equilibrium concentration of [tex]A\;(g)[/tex] is [tex]0.03195\;\text{M}[/tex].
[tex]0.071 - x = 0.03195[/tex],
[tex]x = 0.03905[/tex].
At equilibrium:
[tex][\text{A}\;(g)] = 0.03195\;\text{M}[/tex] according to the question;[tex][\text{B}\;(g)] = 2 x \;\text{M}= 0.0781\;\text{M}[/tex] as in the RICE table;[tex][\text{C}\;(g)] = x = 0.03905\;\text{M}[/tex] as in the RICE table.Hence the equilibrium constant.
[tex]\displaystyle \begin{aligned}K_c &= \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}\\&=\frac{{0.0781}^{2} \times 0.03905}{0.03195}\\&=7.5\times 10^{3}\;\text{M}\end{aligned}[/tex].
If the concentration of A at equilibrium is 0.03195M,the equilibrium constant is Kc ≈ 0.0072 (option a).
To begin solving for the equilibrium constant (Kc), we first need to determine the changes in concentrations for each species.
Step-by-Step Solution:
1. Initial and equilibrium concentrations:
Initial concentration of A ([A]i) = 0.071 MEquilibrium concentration of A ([A]eq) = 0.03195 M
2. Change in concentration for A:
Change in [A] = 0.071 M - 0.03195 M = 0.03905 M
Since the reaction stoichiometry is 1A → 2B + 1C, the change in concentration will also affect B and C:
Change in [B] = 2 × 0.03905 M = 0.0781 MChange in [C] = 0.03905 M
3. Equilibrium concentrations:
Equilibrium concentration of A, [A]eq = 0.03195 MEquilibrium concentration of B, [B]eq = 0.0781 MEquilibrium concentration of C, [C]eq = 0.03905 M
4. Equilibrium constant expression:
The equilibrium constant expression for the reaction A(g) = 2B(g) + C(g) is:
Kc = [B]² [C] / [A]
5. Substituting the equilibrium concentrations:
Kc = (0.0781)² × 0.03905 / 0.03195
6. Calculating Kc:
Kc ≈ 0.0072
Therefore, the equilibrium constant for the reaction is approximately 0.0072.
Complete Question - Before the reaction occurs, the concentration of A is 0.071 M. If the concentration of A at equilibrium is 0.03195 M, what is the equilibrium constant? A(g) = 2B(g) + C(g) Select the correct answer below:
a. Kc - 0.0072
b. Kc - 0.095
c. Kc - 14
d. Kc - 130
which of the following is an acid-base neutralization reaction
Sn+2HF->SnF2+H2
C2H4+3O2->2CO2+H2O
MgCl2+Ca(OH)2->Mg(OH)2+CaCl2
HNO3+KOH->KNO3+H2O
Answer:
The right choice is "HNO₃ + KOH → KNO₃ + H₂O"
Explanation:
acid-base neutralization reaction is a reaction in which acid react with base to form salt and water.
Sn + 2HF → SnF₂ + H₂This is a reaction between metal (Sn) and acid (HF)
2. C₂H₄ + 3 O₂ → 2 CO₂ + H₂O
This is a combustion reaction
3. MgCl₂ + Ca(OH)₂ → Mg(OH)₂ + CaCl₂
This is a simple displacement reaction between salt (MgCl₂) and base (Ca(OH)₂).
3. HNO₃ + KOH → KNO₃ + H₂O
This is a acid-base neutralization reaction in which acid (HNO₃) react with base (KOH) to form salt (KNO₃) and water (H₂O).
So, the right choice is "HNO₃ + KOH → KNO₃ + H₂O"
A chemical equation that is balanced will help you to determine the.......
Answer:
A chemical equation that is balanced will help you to determine how much product they will produce from their reactants.
Hope this helps :)
Have a great day !
5INGH
Explanation:
Which of the following is not equal to 0.1 centimeters?
0.000001 kilometers (km)
0.001 meters (m)
10 millimeters (mm)
1000 micrometers (µm)
Answer:
c) 10 millimeters (mm)
Explanation:
The unit conversions are as follows:
1 cm = 10 mm (millimeter)
1 cm = 0.01 m (meter)
1 cm = 0.00001 km (kilometer)
1 cm = 10000 μm (micrometer)
Based on the above conversions:
[tex]0.1 cm = \frac{10 mm*0.1 cm}{1 cm} = 0.1 mm[/tex]
[tex]0.1 cm = \frac{0.01 m*0.1 cm}{1 cm} = 0.001 m[/tex]
[tex]0.1 cm = \frac{0.00001 km * 0.1 cm}{1 cm} = 0.000001 km[/tex]
[tex]0.1 cm = \frac{10000 um*0.1cm}{1 cm} =1000 um[/tex]
Therefore, 0.1 cm = 10 mm is incorrect instead it is 0.1 mm
Answer:
Explanation:
the Americans maintained their control of Bunker Hill.
the British army sustained heavy casualties.
the Americans forced British soldiers to retreat to Boston.
the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because
the Americans maintained their control of Bunker Hill.
the British army sustained heavy casualties.
the Americans forced British soldiers to retreat to Boston.
the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because
what is the percentage of water in hydrated calcium chloride
Answer:
24.5%
Explanation:
You just add up the atomic masses.
Ca - 40.078
Cl2 - 35.4527 x 2 = 70.9054
------ 110.9834
H4 - 1.00794 x 4 = 4.03176
O2 - 31.9998
------ 36.03056
TOTAL - 147.01396
So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%
This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.
Answer: 24.5%
Explanation: Molar mass of CaCl2 * 2 H2O = 40.078 + ( 2 x 35.453) + ( 2 x 18.02)=147.024 g/mol
% H2O = 2 x 18.02 x 100/ 147.024 =24.5
How much energy is released when 0.40 mol C6H6(g) completely reacts with oxygen? 2C6H6(g) + 15O2(g) 12CO2(g) + 6H2O(g) kJ
Answer:
-1268 kJ
Explanation:
The molar enthalpy of combustion of C6H6 is -3170 kJ/mol
2C6H6(g) + 15O2(g) → 12CO2(g) + 6H2O(g)
Therefore;
when 1 mole of C6H6 undergoes combustion, an energy of -3170 kJ/mol is released.
Therefore; for 0.40 mole
= 0.4 × -3170 kJ
= -1268 kJ
Answer:
The guy above me is correct, but the next answers are -67.68 and exothermic
Explanation: edge
Which graph is an inverse graph?
Answer:
there are no graphs
Explanation:
Answer:
The graph has to switch into the values.
Explanation:
So if you're asked to graph a function and its inverse, all you have to do is graph the function and then switch all x and y values in each point to graph the inverse. Just look at all those values switching places from the f(x) function to its inverse g(x) (and back again), reflected over the line y = x.
Balance the following reaction. If a coefficient of "1" is required, choose "blank" for that box. C4H8 + Br2 → C4H8Br2
Please help fast
Answer:
C₄H₈ + Br₂ → C₄H₈Br₂
Explanation:
To balance a chemical equation, you need to ensure that the number of each element in the reactant side, matches the number of each element on the product side.
Reactants Product
C₄H₈ + Br₂ → C₄H₈Br₂
C = 4 C= 4
H = 8 H= 8
Br = 2 Br = 2
Since they match up on both sides, the chemical equation is balanced, so we keep it as is.
Answer:
blank for all
Explanation:
What is the molar mass of aluminum chlorate, Al(ClO3)3?
The molar mass of Aluminium Chlorate is 277.3351
The molar mass of Aluminium Chlorate is 277.3351.
What is meant by Molar Mass?The molar mass (symbol M, SI unit kg·mol−1) is defined as the mass per unit amount of substance of a given chemical entity. In keeping with the definition of the mole, the chemical entity in question should always be specified.The molar mass of Aluminium Chlorate is 277.3351.
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What type of equation is HgO=Hg+o2
Answer:
Thermal decomposition reaction.
Explanation:
Solid mercury(II) oxide is decomposed with heating into liquid mercury and oxygen gas. This reaction takes place at a 600-700°C.
The balanced chemical reaction is:
2HgO → 2Hg + O₂.
Considering the definition of decomposition reaction, the reaction HgO → Hg + O₂ is a thermal decomposition reaction.
Definition of decomposition reactionA single substance decomposes through a reaction called decomposition, producing two or more diferent compounds. That is, in this type of reaction two or more compounds are formed from a compound.
The atoms that make up a compound are separated to give the products according to the formula:
AB → A + B
This type of reaction can occur spontaneously or caused by certain external factors, such as heat. So, there are 3 types of decomposition reactions:
Catalysis is the term used when the decomposition results from the action of a catalyst.Thermal decomposition is the term used when decomposition is caused by the application of heat.Electrolytic decomposition or electrolysis is the term used to describe decomposition that is caused by the introduction of electric current.Type of reaction in this caseThe reaction HgO → Hg + O₂ is a thermal decomposition reaction where mercuric oxide (HgO) decomposes on heating to give mercury (Hg) and oxygen (O₂).
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when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced
Answer:
16.02 g
Explanation:
the balanced equation for the decomposition of CuCO₃ is as follows
CuCO₃ --> CuO + CO₂
molar ratio of CuCO₃ to CO₂ is 1:1
number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol
according to the molar ratio
1 mol of CuCO₃ decomposes to form 1 mol of CO₂
therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂
number of CO₂ moles produced - 0.364 mol
therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g
16.02 g of CO₂ produced
0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution
Answer:
= 10 M or 10 moles/liter
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
In this case;
The number of moles = 0.5 moles
Volume = 0.05 liters
Therefore;
Molarity = 0.5 moles/0.05 liters
= 10 M or 10 moles/liter
Thus the molarity is 10 M or 10 moles/liter
Final answer:
To calculate the molarity, divide the number of moles of sodium chloride (0.5 moles) by the volume of the solution in liters (0.05 liters), resulting in a molarity of 10 M for the NaCl solution.
Explanation:
The question relates to the concept of molarity, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution. The student's question involves calculating the molarity given a certain amount of solute (sodium chloride, NaCl) and the volume of the resulting solution. To calculate molarity, you would divide the number of moles by the volume in liters. In the case of the student's question, if 0.5 moles of NaCl are dissolved to make 0.05 liters of solution, the calculation would be:
Molarity = moles of solute / liters of solution
Molarity = 0.5 moles / 0.05 liters
Molarity = 10 M (molar)
This result indicates a 10 M NaCl solution, which signifies a highly concentrated solution.
Calculate the mole fraction of each component in a solution with 6.87 g of sodium chloride (NaCl) dissolved in 65.2 g of water. Work must be shown in order to earn credit.
Answer:
mole fraction of NaCl = 0.03145.
mole fraction of water = 0.9686.
Explanation:
Mole fraction is an expression of the concentration of a solution or mixture.It is equal to the moles of one component divided by the total moles in the solution or mixture. The summation of mole fraction of all mixture components = 1.mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).
no. of moles of NaCl = mass/molar mass = (6.87 g)/(58.44 g/mol) = 0.1176 mol.
no. of moles of water = mass/molar mass = (65.2 g)/(18.0 g/mol) = 3.622 mol.
∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.
∵ mole fraction of NaCl + mole fraction of water = 1.0.
∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.
Calculate the pH of a solution with [OH−]=1.3×10−2M. (Hint: Begin by using Kw to find [H3O+].)
Answer:
12.11.
Explanation:
∵ pOH = - log[OH⁻]
∴ pOH = - log(1.3 x 10⁻²) = 1.886.
∵ pH + pOH = 14.
∴ pH = 14 - pOH = 14 - 1.886 = 12.11.
Given the density of Au is 19.3 g/cm3. Determine the mass of gold in an ingot with the dimension of 10.0 cm x 4.00cm x 3.00cm.
Answer:
2.317 kg
Explanation:
Density = mass / vol
Vol = 10 x4 x 3 =120
Density=19.3 gm/cm3
Mass= density x vol =2316 gm or 2.317 kg
Answer: The mass of gold is 2316 grams.
Explanation:
To calculate the volume of cuboid, we use the equation:
[tex]V=lbh[/tex]
where,
V = volume of cuboid
l = length of cuboid = 10 cm
b = breadth of cuboid = 4 cm
h = height of cuboid = 3 cm
Putting values in above equation, we get:
[tex]V=10\times 4\times 3=120cm^3[/tex]
To calculate mass of a substance, we use the equation:
[tex]Density=\frac{Mass}{Volume}[/tex]
Putting values in above equation, we get:
[tex]19.3g/cm^3=\frac{\text{Mass of Gold}}{120cm^3}\\\\\text{Mass of osmium}=2316g[/tex]
Hence, the mass of gold is 2316 grams.
A substance has a high melting point and conducts electricity in the liquid phase The is substance is
Answer:
oxygen
Explanation:
?
why blood capillary walls differ from veins and arteries
Answer: Capillary walls main function is to exchange materials between the blood and tissue cells, While Arteries carry blood away from the heart to parts of your body like your lungs for instance, and your Veins carry blood back to your heart.
I hope this helps :)
Explanation:
What happens to the matter (bodies) of organisms after they die?
Answer:
they start to decompose
Explanation:
the easiest way to wxplain this is that all organic matter decomposees and turns into nutrients for other organisms, its a cycle. but after an organism dies then it starts to decompose and rot.
Answer:
they begin to rot
Explanation:
1.806*10^24 atoms of carbon is how many moles of carbon
The answer should be 3 moles of Carbon.
To convert the number of atoms of carbon to moles, divide the given number of atoms by Avogadro's number, which is 6.022 × 10^23 particles per mole. In this case, there are approximately 3 moles of carbon.
Explanation:To find the number of moles of carbon from the given number of atoms, we can use Avogadro's number. Avogadro's number is defined as 6.022 × 1023 particles per mole.
So, to convert the number of atoms of carbon to moles, we divide the given number of atoms by Avogadro's number:
Number of moles of carbon = (Number of atoms of carbon) / (Avogadro's number)
Plugging in the given values, we have:
Number of moles of carbon = (1.806 × 1024 atoms of carbon) / (6.022 × 1023 atoms/mol) ≈ 3 moles of carbon
Five grams of sugar is mixed with 300 mL of water. In the solution, water would be classified as the —
solute
solvent
base
saline
Answer:Five grams of sugar is mixed with 300 mL of water. In the solution, water would be classified as the —
solvent
Explanation:
It is the solvent because it can dissolve the sugar.
Solvent- able to dissolve other substances.
The sugar has been dissolved in the water, sugar has been considered as solute. The water has been dissolving sugar in itself so it has been considered as solvent.
The mixture of solute and solvent has been termed as the solution. The solute has been the molecule that has been dissolved. The solvent is the molecule that dissolves the solute.The base has been the solution in which the alkaline character has been more. More alkalinity has been contributed by the increased hydroxide ion concentration.The saline is the solution of NaCl in water. When NaCl has been dissolved in the water, the solution formed has been known as saline.Since sugar has been dissolved in the water, sugar has been considered as solute. The water has been dissolving sugar in itself so it has been considered as solvent.
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The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution
Answer:
16 Molarity
Step-by-step:
M= mols/L
M= 8mols/.5L
M= 16 Molarity
Answer:
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
Moles of NaOH = 8 moles
Volume of the solution = 0.5 L
[tex]Molarity=\frac{8 mol}{0.5 L}=16.0 M[/tex]
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral
Answer:
The solution is basic.
Explanation:
We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):
If no. of millimoles of acid > that of base; the solution is acidic.If no. of millimoles of acid = that of base; the solution is neutral.If no. of millimoles of acid < that of base; the solution is basic.We need to calculate the no. of millimoles of acid and base:no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.
no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.
∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).
So, the solution is: basic.
how long does the venus flytrap process take once it has its prey
After trapping its prey, the plant turns into a external stomach, sealing the trap so no air gets in or out. The digestion takes several days depending the size of the insect, and then the leaf re-opens.
How many milliliter of 2m NACL solution are required to make 1 liter of 0.4 M NACL solution
The volume (in mL) required to make 1 L of the solution is 200 mL
Data obtained from the questionMolarity of stock solution (M₁) = 2 MVolume of diluted solution (V₂) = 1 L = 1000 mL Molarity of diluted solution (M₂) = 0.4Volume of stock solution (V₁) = ?How to determine the volume of the stock solutionM₁V₁ = M₂V₂
2 × V₁ = 0.4 × 1000
2 × V₁ = 400
Divide both side by 2
V₁ = 400 / 2
V₁ = 200 mL
Learn more about dilution:
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Final answer:
To prepare 1 liter of a 0.400 M NaCl solution from a 2.00 M NaCl solution, you need 200 milliliters of the 2.00 M solution, calculated using the dilution formula M1V1 = M2V2.
Explanation:
To determine how many milliliters of a 2.00 M NaCl solution are required to make 1 liter of a 0.400 M NaCl solution, we can use the dilution formula M1V1 = M2V2, where M1 is the molarity of the initial solution, V1 is the volume of the initial solution, M2 is the molarity of the final solution, and V2 is the volume of the final solution
In this case, we have:
M1 = 2.00 M (initial molarity of NaCl)
M2 = 0.400 M (desired molarity of NaCl)
V2 = 1 liter = 1000 mL (desired volume of final solution)
To find V1, we rearrange the equation: V1 = (M2 × V2) / M1.
Substituting in the known values, we get: V1 = (0.400 M × 1000 mL) / 2.00 M = 200 mL.
So, you would need 200 milliliters of the 2.00 M NaCl solution to prepare 1 liter of a 0.400 M NaCl solution.
Nuclear decay is more likely to occur when?
Answer:
Radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold the nucleus together due to an excess of either protons or neutrons.
Hope this helps!
Answer:
It happens when a heavy nucleus is bombarded with neutrons, so it becomes unstable and decomposes into two nuclei.
Explanation:
This is known by the term nuclear fission, which is a reaction by which a heavy nucleus, when bombarded with neutrons, becomes unstable and divides into two nuclei, of sizes of the same order of magnitude, there is a high release of energy and emits two or three neutrons. These neutrons can lead to more fissions by interacting with other fissile nuclei.
1. In a compound, which type of bond is the sharing of electrons between adjacent atoms?
A. Nuclear bond
B. Electric bond
C. Chemical bond
D. Hydrogen bond
2. Two compounds are mixed and light is emitted, the color changes, and heat is liberated.
Which activity has occurred?
A. Chemical reaction
B. Chemical mixture
C. Chemical nucleus exchange
D. Chemical compromise
3. Which sodium reacts with chlorine to make sodium chloride (table salt), which term applies to sodium chloride?
A. Reactant
B. Mixture
C. Evaporate
D. Product
4. Which name is given to a reaction in which the number of each atom on one side of the equation is equal to the number of the same kind of atoms on the other side of the equation?
A. Complete
B. Atomic
C. Balanced
D. Electrical
5. In the reaction NA + CI - - - > NaCI, which statement indicates whether the equation is balanced?
A. Visual evidence is necessary to determine the balance of the reaction
B. Atoms of the same kind are of equal number on either side of the arrow
C. Atoms of the same kind are not of equal number on either side of the arrow
D. Evidence of the heat reaction is necessary to tell whether the equation is balanced.
Answer:
1. C. Chemical bond
2. A. Chemical reaction
3. Product
4. C. Balanced
5. B. Atoms of the same kind are of equal number on either side of the arrow
Explanation:
A chemical bond is a bond between two or more atoms. There are different types of chemical bonds, but the one that the question is pertaining to is called a covalen bond. A covalent bond occurs when the atoms are sharing electrons.
2. A chemical reaction is characterized by the production of light and/or heat, and a change in color in the product. By definition, it is the process where one or more substances react to produce one or more products.
3. When one or more reactants react with each other, it creates another substance or substances called products. In the case of your question, sodium reacts with chlorine (these are your reactants), which produces the product sodium chloride, which is a compound.
4. By definition, a balanced equation is an equation where the number of atoms of each element in the reactants are equal to the number of atoms of each element in the product.
ex.
Reactants Product
Na + Cl → NaCl
Na = 1 Na = 1
Cl = 1 Cl = 1
5. As explained above and shown, you can see that the number of atoms of each element in the reactants is equal to the number of each element in the product. So this means that the equation is balanced.
Answer:
1chemical bond 2chemical reaction 3 reaction 4 atomic 5atoms of the same kind ate not of equal number on either side of the arrow
what did earth look like before life began
Answer:
Like a jungle with trees everywhere
Hope This Helps! Have A Nice Day!!
I would suggest reading Genesis chapter 1 to 2. It'll explain it all.