Answer:
Your average would drop to 63.68%. Ask your grader if that is passing.
Step-by-step explanation:
If 10% of your grade is zero, the remaining amount is 90% of 70.76%, ...
0.90·70.76% = 63.684% ≈ 63.68%
The letter grade associated with this depends on class or school standards. Ask your grader what it is.
A school, hospital, and a supermarket are located at the vertices of a right triangle formed by three highways. The school and hospital are 14.7 miles apart. The distance between the school and the supermarket is 8.82 miles, and the distance between the hospital and the supermarket is 11.76 miles.
A service road will be constructed from the main entrance of the supermarket to the highway that connects the school and hospital. What is the shortest possible length for the service road? Round to the nearest tenth.
Answer:
7.1 miles
Step-by-step explanation:
Consider right triangle HospitalSchoolSupermarket. In this triangle:
HospitalSchool = 14.7 mi;HospitalSupermaket = 11.76 mi;School Supermarket = 8.82 mi.The shortest road from the main entrance of the supermarket to the highway that connects the school and hospital will be the height drawn from the point Supermarket to the hypotenuse HospitalSchool.
Let the length of this road be x mi and the distance from School to point A be y mi. Use twice the Pythagorean theorem for right triangles Supermarket SchoolA and SupermarketHospitalA:
[tex]\left\{\begin{array}{l}x^2+y^2=8.82^2\\ \\x^2+(14.7-y)^2=11.76^2\end{array}\right.[/tex]
Subtract from the second equation the first one:
[tex]x^2+(14.7-y)^2-x^2-y^2=11.76^2-8.82^2\\ \\14.7^2-2\cdot 14.7y+y^2-y^2=11.76^2-8.82^2\\ \\-29.4y=11.76^2-8.82^2-14.7^2\\ \\29.4y=155.5848\\ \\y\approx5.24\ mi[/tex]
Thus,
[tex]x^2=8.82^2-5.24^2=50.3348\\ \\x\approx 7.1\ mi.[/tex]
A loaf of bread is cut into slices of equal size. Some of the loaf is used in a recipe and 2/12 of the loaf is used to make a sandwich. The remaining 7/12 of the loaf is put into the refrigerator. Write and solve an equation to find the fraction of the loaf of bread that is used in the recipe.
The answer would be 3/12 was used on the recipe. If 3/12 was used on the recipe and we know 2/12 was used to make a sandwich, 3/12 + 2/12 =5/12 used and that holds true being as there is 7/12 of the loaf left. 12/12 - 5/12 = 7/12
Hope I helped. Please mark me brainliest! :)
Please, I need it ASAP!!!! I will give brainliest if correct!!!
Answer:
recursive: f(0) = 7; f(n) = f(n-1) -8
explicit: f(n) = 7 -8n
Step-by-step explanation:
The sequence is an arithmetic sequence with first term 7 and common difference -8. Since you're numbering the terms starting with n=0, the generic case will be ...
recursive: f(0) = first term; f(n) = f(n-1) + common difference
explicit: f(n) = first term + n·(common difference)
To get the answer above, fill in the first term and common difference values.
A square playing field has an area of 1255 square yards. About how long is each side of the field? Please explain how to do this problem
Answer:
about 35.4 yards
Step-by-step explanation:
Make use of the formula for the area of a square and solve for the side length. The area (A) of a square of side length s is given by ...
A = s²
You are given A and asked to find s. So you have
1255 yd² = s²
To find s, you take the square root of both sides of the equation.
√(1255 yd²) = √(s²)
35.426 yd ≈ s . . . . . the square root of 1255 is irrational, so we have shown an approximation rounded to 3 decimal places.
Each side of the field is about 35.4 yards long.
_____
Any scientific or graphing calculator can compute the square root for you, as can any spreadsheet program or any of a number of on-line calculators. A Google or Bing search box will also compute the square root for you. (see attachment)
Slove these one step equation for the variable listed: Show your work
1. 14-7= k
2. 21+ W = 36
3. -5= G+3
4. 2b = 12
5. 35 = 5R
6. Q/2 =6
1. 7=k
2. 21+w=36
-21 -21
----------------------
w=15
3. -5 =G+3
-3 -3
---------------------
-8=G
4. 2b/2=12/2
b=6
5. 35/5=5R/5
7= R
6. Q/2 (2) = 6 (2)
Q=12
Answer:
Step-by-step explanation:
1) 14-7 = 7 = k
2) 21 + W = 36 → W = 36 - 21 → W = 25
3) -5 = G + 3. Add 5 to both sides, obtaining G = 8.
4) 2b = 12. Div. both sides by 2: b = 6
5) 35 = 5R. Div. both sides by 5: 7 = R
6) Q/2 = 6; Mult both sides by 2: Q = 12
What is wrong with this “proof”? “Theorem” For every positive integer n, if x and y are positive integers with max(x, y) = n, then x = y. Basis Step: Suppose that n = 1. If max(x, y) = 1 and x and y are positive integers, we have x = 1 and y = 1. Inductive Step: Let k be a positive integer. Assume that whenever max(x, y) = k and x and y are positive integers, then x = y. Now let max(x, y) = k +1, where x and y are positive integers. Then max(x – 1, y – 1) = k, so by the inductive hypothesis, x – 1 = y – 1. It follows that x = y, completing the inductive step. Online Discussion Guidelines: Post your logical argument on the discussion forum. Read the logical argument of your peers. Reply the results posted by at least two of your peers.
The assumption of the inductive step is not correct. If [tex]\mathrm{max}(x,y)=2[/tex], for instance, it's entirely possible that [tex]x=1[/tex] and [tex]y=2[/tex].
what is the perimeter of the figure
Answer:
As we can see in the picture, we already knew 4 out of 6 sides of the figure so we need to find the other sides.
So the first missing side (the one near the 3 m one) should be:
7 - 4 = 3 (m)
The second missing side (the one near the 4m one) should be:
6 - 3 = 3 (m)
Now that we know all of the side lengths of the figure, the perimeter of the figure will be:
7 + 3 + 3 + 3 + 4 + 6 = 26 (m)
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y plus five squared divided by nine = 1
Answer:
The vertices are (3 , -5) , (-5 , -5)
The foci are (4 , -5) , (-6 , -5)
Step-by-step explanation:
* Lets study the equation of the hyperbola
- The standard form of the equation of a hyperbola with
center (h , k) and transverse axis parallel to the x-axis is
(x - h)²/a² - (y - k)²/b² = 1
- The length of the transverse axis is 2 a
- The coordinates of the vertices are (h ± a , k)
- The coordinates of the foci are (h ± c , k), where c² = a² + b²
- The distance between the foci is 2c
* Now lets solve the problem
- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1
* From the equation
# a² = 16 ⇒ a = ± 4
# b² = 9 ⇒ b = ± 3
# h = -1
# k = -5
∵ The vertices are (h + a , k) , (h - a , k)
∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)
* The vertices are (3 , -5) , (-5 , -5)
∵ c² = a² + b²
∴ c² = 16 + 9 = 25
∴ c = ± 5
∵ The foci are (h ± c , k)
∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)
* The foci are (4 , -5) , (-6 , -5)
Answer:
Vertices: (3,-5) (-5,-5)
Foci: (-6,-5) (4,-5)
Step-by-step explanation:
(x+1)^2/16-(y+5)^2/9 =1
formula: (x-h)^2/a^2 -(y-k)^2/b^2=1
in this case...
a^2=16 b^2=9
h=-1 k=-5
a=4 b=3
v=(h+/-a,k)
v1=(-1+4,-5)=
v1=(3,-5)
v2=(-1-4, -5) =
v2=(-5,-5)
Foci=(h+/-c,k)
F1=(h-c,k)
=(-1-5,-5)
f1=(-6,-5)
F2=(h+c,k)
=(-1+5, -5)
F2=(4,-5)
Hope this helps! :)
Simplify 2m - [n - (m - 2n)]. -3m - n 3m - n -3m - 3n 3m - 3n
Answer:
3m-3n
Step-by-step explanation:
We want to simplify the expression;
2m - [n - (m - 2n)].
We expand the parenthesis to obtain;
2m - (n - m + 2n)
2m - ( - m + 3n)
Expand further to get;
2m +m -3n
Combine the first two terms;
3m-3n
plz help. if u want part A. tell me if u know part A. help plzzz
Step-by-step explanation:
Did they define mechanical pencils using the variable m?
A box contains 3 cherry frozen treats and 2 grape frozen treats. Maggie takes a treat from the box without looking, gives it to her brother, and then selects another treat. What is the probability that Maggie and her brother gets a grape treat
Answer:
1/10
Step-by-step explanation:
When Maggie gives a grape treat to her brother, there are 2 grape treats out of 5 total treats.
When Maggie selects another treat, there is 1 grape treat out of 4 treats left.
So the probability that both happen is:
2/5 × 1/4
1/10
With a base salary of $250 and a commission of 4% of all sales, compute Cindy Nelson’s salary for the following weeks:
Week : 1 2 3 4
Base Salary. $250. $250 $250 $250
Sales. $890. $1,126 $975 $ 824
Commission ? ? ? ?
Total Salary ? ? ? ?
Answer:
Part 1) The commission is $35.6 and the total salary for week 1 is $285.6
Part 2) The commission is $45.04 and the total salary for week 2 is $295.04
Part 3) The commission is $39 and the total salary for week 3 is $289
Part 4) The commission is $32.96 and the total salary for week 4 is $282.96
Step-by-step explanation:
Let
x-----> the amount in sales
y----> Cindy Nelson’s salary
we know that
4%=4/100=0.04
so
The linear equation that represent this situation is
y=250+0.04x
case 1) week 1
Sales $890
For x=890
substitute in the linear equation
y=250+0.04(890)
y=250+35.6=$285.6
therefore
The commission is $35.6
The total salary for week 1 is $285.6
case 2) week 2
Sales $1,126
For x=1,126
substitute in the linear equation
y=250+0.04(1,126)
y=250+45.04=$295.04
therefore
The commission is $45.04
The total salary for week 1 is $295.04
case 3) week 3
Sales $975
For x=975
substitute in the linear equation
y=250+0.04(975)
y=250+39=$289
therefore
The commission is $39
The total salary for week 1 is $289
case 4) week 4
Sales $824
For x=824
substitute in the linear equation
y=250+0.04(824)
y=250+32.96=$282.96
therefore
The commission is $32.96
The total salary for week 1 is $282.96
Can someone explain to me how to do this
See the attached picture for the solution.
A 12-foot ladder is leaning up against a wall, as shown. how high does the ladder reach up the wall when x is 30°? 45°? 60°? round decimal answers to the nearest tenth, if necessary.
Answer:
6ft for 30°
8.5ft for 45°
10.4ft for 60°
Step-by-step explanation:
12(sin 30°)=x
x=6
12(sin 45°)=x
x=8.5
12(sin 60°)=x
x=10.4
By using right angle trigonometry and the cosine function (x = L cos θ), we find that a 12-ft ladder reaches 10.4 ft, 8.5 ft and 6 ft up a wall when it is leaned at 30°, 45° and 60° respectively.
Explanation:The problem described here involves the use of right angle trigonometry, specifically the use of the cosine function. In order to determine how high up the wall the ladder reaches at an angle of 30°, 45° and 60°, we can use the formula: x = L cos θ.
Firstly, let's calculate the height at 30 degrees (θ = 30°). We know that cos 30° = √3/2, so we substitute into the formula: x = 12ft * √3/2 which approximately equals 10.4 ft.
Next, for 45 degrees (θ = 45°), cos 45° = √2/2. Substituting into the formula: x = 12ft * √2/2 = 8.5 ft.
Finally, for 60 degrees (θ = 60°), cos 60° = 1/2. Therefore, x = 12ft * 1/2 = 6ft). So, the ladder reaches 10.4 ft up the wall when the angle is 30°, 8.5 ft when the angle is 45°, and 6 ft when the angle is 60°.
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200 tickets were sold to a concert. Floor seats cost $32 and stadium seats cost $20. Ticket sales totaled $5440. Find how many of each type we’re sold.
Answer:
120 floor seats, 80 stadium seats
Step-by-step explanation:
use extreme values
if all were floor seats, then cost would be 32*200, or 6400
6400-5440=960
32-20=12
960/12=80
200-80=120
120 floor seats and 80 stadium seats were sold.
Let's designate F as the number of floor seats and S as the number of stadium seats.
Given :
F + S = 200 (Equation for the total number of tickets)
32F + 20S = 5440 (Equation for the total sales amount)
We can use substitution or elimination to solve this system. If we multiply the first equation by 20 to get
20F + 20S = 4000
and subtract it from the second equation, we get:
12F = 1440
F = 120
We found the number of floor seats sold. We can then substitute F back into the first equation to find the number of stadium seats:
120 + S = 200
S = 80.
So, 120 floor seats and 80 stadium seats were sold.
If we assume that all possible poker hands (comprised of 5 cards from a standard 52 card deck) are equally likely, what is the probability of being dealt: a. a flush? (A hand is said to be a flush if all 5 cards are of the same suit. Note that this definition means that straight flushes (five cards of the same suit in numeric sequence) are also considered flushes.) b. one pair? (This occurs when the cards have numeric values a, a, b, c, d, where a, b, c, and d are all distinct.) c. two pairs? (This occurs when the cards have numeric values a, a, b, b, c, where a, b and c are all distinct.) d. three of a kind? (This occurs when the cards have numeric values a, a, a, b, c, where a, b and c are all distinct.) e. four of a kind? (This occurs when the cards have numeric values a, a, a, a, b.)
Answer:
See the attached photo for the calculations and answers
Step-by-step explanation:
The calculations and explanations are shown in the 3 attached photos below.
The answer to the given question will be a) P(flush) = 0.0019 b) P(one pair) = 0.4225 c) P( two pairs) = 0.475 d) P(three of a kind) = 0.211 e) P(four of a kind) = 0.00024
What is probability?
It's a field of mathematics that studies the probability of a random event occurring. From 0 to 1, the value is expressed.
The probability of being dealt a flush:
For a suit there are 4 choices and 13C₅ choices for a card in that suit
Probability of flush = 4.( 13C₅)/52C₅
Probability of flush = 0.0019
The probability of being dealt one pair:
There are 13 possible values of a, 4C₂ choice for suit of a, 12C₃ value for b, c, d and 4 choices each for choosing the suit of b, c, d.
P(one pair) = (13.4C₂.12C₃.4.4.4)/52C₅
P(one pair) = 0.4225
The probability of being dealt two pairs:
There are 13C₂ possibility for the value of a and b, 4C₂ choices for suits of both a and b and 44 possibilities for c from the remaining cards.
P(2 pairs) = (13C₂.4C₂.4C₂.44)/(52C₅) = 0.475
The probability of being dealt three of a kind:
There are 13 possibilities for the value of a and 4C₃ choices for the suits of a, 12C₂ possibilities for both b and c and 4 choices of suits for both b and c.
P( three of a kind) = (13.4C₃.12C₂.4.4)/52C₅ = 0.211
The probability of being dealt four of a kind:
There are 13 possibilities of a and 4C₄ values for the suit of a and 48 choices of b from the remaining cards.
P(four of a kind) = (13.4C₄.48)/52C₅ = 0.00024
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Factor each equation 64p^3 - 8q^3
Answer:
8(2p − q)(4p² + 2pq + q²)
Step-by-step explanation:
You would use the difference of cubes to factor this polynomial.
I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.
The perimeter of a rectangle is 32 feet. The length is 6 feet longer than the width. Find the dimensions.
To find the dimensions of the rectangle, express its length in terms of its width as 'width + 6'. Substitute this in the formula for perimeter and solve to get width = 5 feet and length = 11 feet.
Explanation:The problem stated relates to the geometric concept of perimeter and involves a bit of algebra. First, remember that the formula for the perimeter of a rectangle is 2(length + width). If the total perimeter is 32 feet, and the length is 6 feet longer than the width, we can describe the length as 'width + 6'.
Substitute these into the perimeter formula: 2((width + 6) + width) = 32. Simplify this to 2(width + width + 6) = 32, then simplify further to 2(2width + 6) = 32. Divide both sides by 2 to get 2width + 6 = 16. Solving for 'width', we get width = 5 feet. Therefore, the length (which is width + 6) would be 5 + 6 = 11 feet.
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Serena asked her parents if for their picnic they could have 20% more portions of coca-cola than they planned, and if each portion could be 20% bigger. Her parents agreed. By what percent more coca cola will they buy?
Answer:
44%
Step-by-step explanation:
If p represents the number of portions and q represents the quantity in each portion, then the original amount needed was p·q.
After p is increased by 20%, its number is ...
p + 0.20·p = 1.20·p
After q is increased by 20%, its amount is ...
q + 0.20 ·q = 1.20·q
Then the new amount the parents must buy is ...
(1.20p)(1.20q) = 1.20²·pq = 1.44pq
This amount is ...
(1 + 44/100)·pq = pq + 44%·pq
It is 44% more than the original planned purchase.
Answer:
44 percent
Step-by-step explanation:
20pts + brainliest PLEASE HELP
1. Find the 70th percentile for the values below:
26 37 18 45 20 36 22 25 50 41
2. Find the 40th percentile for the values below:
26 37 18 45 20 36 22 25 50 41
Answer:
1. 37
2. 25
Step-by-step explanation:
In order to find a percentile of a given number set, you must first put the values in ascending order:
18, 20, 22, 25, 26, 36, 37, 41, 45, 50
70% = 0.7
Since there are 10 numbers in the set, we'll multiply 10 by 0.7
10 × 0.7 = 7
So we are going to look at the seventh number in the set.
18, 20, 22, 25, 26, 36, 37, 41, 45, 50
1 2 3 4 5 6 7 8 9 10
The seventh number in the set is 37.
We're going to do the same for finding the 40th percentile:
40% = 0.4
10 × 0.4 = 4
Finding the fourth number in the set...
18, 20, 22, 25, 26, 36, 37, 41, 45, 50
1 2 3 4 5 6 7 8 9 10
... We get 25
And those are you answers, 37 and 25.
what is the following quotient? 5/ sqrt 11 - sqrt 3
[tex]\displaystyle\\\frac{5}{\sqrt{11}-\sqrt{3}}=?\\\\\\\text{We rationalize the denominator.}\\\\\frac{5}{\sqrt{11}-\sqrt{3}}=\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}=\frac{5(\sqrt{11}+\sqrt{3})}{(11-3)}=\boxed{\bf\frac{5\sqrt{11}+5\sqrt{3})}{8}}[/tex]
Answer:
The correct option is b) [tex]\frac{5\sqrt{11}+5\sqrt{3}}{8}[/tex]
Step-by-step explanation:
We need to find the quotient of [tex]\frac{5}{\sqrt{11}-\sqrt{3}}[/tex],
Rationalizing the above,
By multiply and divide by conjugate of its denominator,
[tex]\frac{5}{\sqrt{11}-\sqrt{3}} \times \frac{\sqrt{11}+\sqrt{3}}{\sqrt{11}+\sqrt{3}}[/tex]
[tex]\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}[/tex]
Since, [tex](a+b)(a-b)=a^{2}-b^{2}[/tex]
[tex]\frac{5\sqrt{11}+5\sqrt{3}}{(11-3)}[/tex]
simplify,
[tex]\frac{5\sqrt{11}+5\sqrt{3}}{8}[/tex]
Therefore, the correct option is b) [tex]\frac{5\sqrt{11}+5\sqrt{3}}{8}[/tex]
Simplify. Assume that no denominator is equal to zero. ([3^2]^3g^3h^4)^2
Answer:
531,441·g^6·h^8
Step-by-step explanation:
The operative rule of exponents is ...
(a^b)^c = a^(b·c)
Working from the inside out, according to the order of operations, we get ...
= (9^3·g^3·h^4)^2
= 729^2·g^(3·2)·h^(4·2)
= 531,441·g^6·h^8
A soccer ball is kicked off from the ground in an arc defined by the function, h(x)=-8x^2+64x. At what point does the ball hit the ground?
(0,4) , (0,8) , (4,0) , (8,0)
Answer:
(8,0)
Step-by-step explanation:
The equation that models the path traced by the ball is
[tex]h(x)=-8x^2+64x[/tex]
To find the point at which the ball hit the ground, we must equate the function to zero.
[tex]-8x^2+64x=0[/tex]
Factor;
[tex]-8x(x-8)=0[/tex]
[tex]-8x=0,(x-8)=0[/tex]
This implies that;
x=0,x=8,
At x=0, the ball was not yet kicked.
So we take x=8, to be the time the ball hit the ground.
We substitute x=8 into the function to get;
[tex]h(8)=-8(8)^2+64(8)=0[/tex]
Hence the point at which the ball hit the ground is (8,0)
Leah invested $950 in an account paying an interest rate of 1.5% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 6 years?
[tex]\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$950\\ r=rate\to 1.5\%\to \frac{1.5}{100}\dotfill &0.015\\ t=years\dotfill &6 \end{cases} \\\\\\ A=950e^{0.015\cdot 6}\implies A=950e^{0.09}\implies A\approx 1039.5\implies \stackrel{\textit{rounded up}}{A=1040}[/tex]
is 4j - 3 = j a equation?
Answer:
Yes , i thinks so because have letter and the result is perfect and have two statement.
Quick answer if you can help@
The domain is the input values, which are the X- values.
The domain would be -6, -1 , 0, 3
The first answer is the right one.
For this case, we have that by definition, the domain of a function is given by all the values of "x" for which the function is defined. The values of the domain are represented in the starting point.
Then, it is observed in the figure that the values of the domain are:
[tex]{x | x = -6, -1,0,3}[/tex]
ANswer:
Option A
Help me with ixl please
Answer:
$84.70
Step-by-step explanation:
Using the formula, B = 70(1+0.1)^2 = 70*1.21 = 84.7.
What is the x-intercept and the y-intercept of the line on the graph
Answer:
X-intercept: (0,4)
Y-intercept: (-4,0)
An athlete was having her blood pressure monitored during a workout. The doctor found that the periodic function, P= 20 sin (8pi/3 t) + 90 models her blood pressure as a function of time in seconds.
a. What is the systolic pressure (the maximum blood pressure)?
b. What is the diastolic pressure (the minimum blood pressure)?
c. What is the length in time, of her heartbeat cycle?
d. Sketch a wall labeled graph.
Answer:
(a) 110 mm Hg
(b) 70 mm Hg
(c) 3/4 second
(d) see the attachment
Step-by-step explanation:
(a) The sine function has a maximum value of +1, so the maximum value of p is ...
pmax = 20·(+1) +90 = 20+90 = 110 . . . . . mm Hg
__
(b) The sine function has a minimum value of -1, so the minimum value of p is ...
pmin = 20·(-1) +90 = -20+90 = 70 . . . . . mm Hg
__
(c) The period of the sine function is 2π, so the value of t that makes the argument be 2π will be the period.
8π/3·t = 2π
t = 2π·3/(8π) = 3/4 . . . . . . multiply by the inverse of the coefficient of t
The period of her heartbeat cycle is 3/4 seconds.
__
(d) a graph is attached.
MELVIN MOWS A LAWN. THE FRACTION OF THE AWN THAT MELVIN HA MOWED SO FAR IS REPRESENTED BY THE SHADED MODEL SHOWN. MELVIN WILL MOW 3/10 MORE OF THE LAWN BEFORE HE TAKES HIS FIRST BREAK. WHAT FRACTION OF THE LAWN WIK MELVIN HAVE MOWED WHEN HE TAKES HIS FIRST BREAK?
Final answer:
To find the total fraction of the lawn mowed by Melvin before his first break, one would add the additional 3/10 to the already mowed fraction represented by the shaded model.
Explanation:
The student's question is about calculating the fraction of the lawn that will be mowed by Melvin before he takes his first break. Initially, the question does not specify what fraction of the lawn is already mowed, but indicates that Melvin will mow an additional 3/10 of the lawn. Assuming that the shaded model represents the fraction already mowed (let's say x), the total fraction mowed before Melvin's first break would be x + 3/10. Without the specific value of the initially mowed fraction, we cannot provide the exact answer; however, generally, the operation would involve adding the given fraction to Melvin's progress before he mows the additional 3/10.