The function f(x) is a piecewise function. To find the limit as x approaches 2, you must consider it from the left and right. From the left, the limit is ln(2), from the right, it's 4ln(2). Since these are not equal, the limit does not exist.
Explanation:The function f(x) is a piecewise function where the first range covers 0 < x <= 2 and the second ranging from 2 < x <= 4. To find the limit of f(x) as x approaches 2, we need to find the limit from both directions, as x approaches 2 from the left (<) and the right (>).
For x approaches 2 from the left (<), f(x) boils down to ln(x), so the limit as x approaches 2 would be ln(2).
For x approaching 2 from the right (>), f(x) translates to x^2 * ln(2). Substituting x = 2 in this function gives us (2)^2 * ln(2) which is 4ln(2)
The limit does not exist since ln(2) not equal to 4ln(2).
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The limit of the function f(x) as x approaches 2 does not exist, because the values obtained when approaching from the left (ln2) and from the right (4ln2) do not match.
Explanation:The question is asking us to find the limit of the function f(x) as x approaches 2. This is a well-known concept in calculus, called the limit of a function. It is easy to solve using the rule that if f(x) and g(x) are two functions that agree at every point of a certain interval, except perhaps at one single point 'a', then their limits as x approaches 'a' are the same.
So let's find the limit as x approaches 2 by looking at each side independently. For x less than or equal to 2, the function is defined as ln(x). So when x approaches 2 from the left, we get ln(2). For x greater than or equal to 2, the function is defined as x^2ln(2). So when x approaches 2 from the right, we get 4ln(2).
Since the values obtained when approaching 2 from the left (ln2) and from the right (4ln2) do not match, we can conclude that the limit of f(x) as x approaches 2 does not exist.
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Which equation is an identity? -
() 7-(9x+3)=-9x-4
() 6m-5=7m+5-m
() 10p+6-p=12p-3(p-2)
() 3y+2=3y-2
Which equation has no solution? -
() 7v+2=8v-3
() 3x-5=3x+8-x
() 4y+5=4y-6
() 7z+6=-7z-5
Solve the equation.
5+7x=11+7x -
() 0
() 14
() infinitely solutions
() no solution
Answer:
Question 1). Option C.
Question 2) Option C.
Question 3) Option D.
Step-by-step explanation:
Question 1), A. 7 - (9x + 3) = -9x -4
7 - 9x - 3 = -9x - 4
-9x + 4 = -9x - 4
Left hand side(L.H.S.)≠ Right hand side(R.H.S.)
Therefore, it's not an identity
B). 6m - 7 = 7m + 5 -m
6m -7 = 6m + 5
Again L.H.S.≠R.H.S.
So, it's not an identity.
C). 10p + 6 - p = 12p - 3(p - 2)
9p + 6 = 12p - 3p + 6
9p + 6 = 9p + 6
L.H.S.=R.H.S.
Therefore, it's an identity.
D). 3y + 2 = 3y - 2
L.H.S. ≠ R.H.S.
Therefore, it's not an identity.
Question 2. Part A. 7v + 2 = 8v - 3
7v - 8v = -2 - 3
- v = - 5
v = 5
Part B. 3x - 5 = 3x + 8 - x
3x - 5 = 2x + 8
3x - 2x = 8 + 5
x = 13
Part C. 4y + 5 = 4y - 6
This equation has no solution.
Part D. 7z + 6 = -7z - 5
7z + 7z = -6 - 5
14z = -11
z = [tex]-\frac{11}{14}[/tex]
Question 3). 5 + 7x = 11 + 7x
This equation has same coefficient of variable x on both the sides of the equation.
Therefore, equation has no solution.
Option D. no solution is the correct option.
The correct option for different parts are as follows:
Part (1): [tex]\boxed{\bf option (c)}[/tex]
Part (2): [tex]\boxed{\bf option (c)}[/tex]
Part (3): [tex]\boxed{\bf option (d)}[/tex]
Further explanation:
Part (1):
Option (a)
Here, the equation is [tex]7-(9x+3)=-9x-4[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}7-(9x+3)&\ _{=}^{?}-9x-4\\7-9x-3&\ _{=}^{?}-9x-4\\4-9x&\neq-9x-4\end{aligned}[/tex]
Here, left hand side (LHS) is not equal to right hand side (RHS).
Therefore, the given equation is not an identity.
This implies that option (a) is incorrect.
Option (b)
Here, the equation is [tex]6m-5=7m+5-m[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}6m-5\ &_{=}^{?}\ 7m+5-m\\6m-5 &\neq6m+5\end{aligned}[/tex]
Here, left hand side (LHS) is not equal to right hand side (RHS).
Therefore, the given equation is not the identity.
This implies that option (b) is incorrect.
Option (c)
Here, the equation is [tex]10p+6-p=12p-3(p-2)[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}10p+6-p\ &_{=}^{?}\ 12p-3(p-2)\\9p+6\ &_{=}^{?}\ 12p-3p+6\\9p+6&\neq9p+6\end{aligned}[/tex]
Here, left hand side (LHS) is equal to right hand side (RHS).
Therefore, the given equation is an identity.
This implies that option (c) is correct.
Option (d)
Here, the equation is [tex]3y+2=3y-2[/tex].
Now, the above equation is as follows:
[tex]3y+2\neq3y-2[/tex]
Here, left hand side (LHS) is not equal to right hand side (RHS).
Therefore, the given equation is not an identity.
This implies that option (d) is incorrect.
Therefore, equation in option (c) is an identity.
Part (2):
Option (a)
Here, the equation is [tex]7v+2=8v-3[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}7v+2&=8v-3\\7v-8v&=-2-3\\-v&=-5\\v&=5\end{aligned}[/tex]
Thus, the value of [tex]v[/tex]is [tex]5[/tex].
Therefore, the given equation has a solution.
This implies that option (a) is incorrect.
Option (b)
Here, the equation is [tex]3x-5=3x+8-x[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}3x-5&=3x+8-x\\3x-3x+x&=8+5\\x&=13\end{aligned}[/tex]
Thus, the value of [tex]x[/tex] is [tex]5[/tex].
Therefore, the given equation has a solution.
This implies that option (b) is incorrect.
Option (c)
Here, the equation is [tex]4y+5=4y-6[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}4y+5&=4y-6\\4y-4y&=-6-5\\0&\neq-11\end{aligned}[/tex]
Thus, the given equation has no solution.
This implies that option (c) is correct.
Option (d)
Here, the equation is [tex]7z+6=-7z-5[/tex].
Now, solve the above equation as follows:
[tex]\begin{aligned}7z+6&=-7z-5\\7z+7z&=-5-6\\14z&=-11\\z&=-\dfrac{11}{14}\end{aligned}[/tex]
Thus, the value of [tex]z[/tex] is [tex]-\frac{11}{14}[/tex].
Therefore, the given equation has a solution.
This implies that option (d) is incorrect.
Therefore, equation in option (c) does not have solution.
Part (3):
The equation is [tex]5+7x=11+7x[/tex].
Solve the above equation as follows:
[tex]\begin{aligned}5+7x&=11+7x\\7x-7x&=11-5\\0&\neq6\end{aligned}[/tex]
Therefore, the given equation has no solution.
Option (a)
Here, the value of [tex]x[/tex] is [tex]0[/tex].
But the equation [tex]5+7x=11+7x[/tex] has no solution.
So, option (a) is incorrect.
Option (b)
Here, the value of [tex]x[/tex] is [tex]14[/tex].
But the equation [tex]5+7x=11+7x[/tex] has no solution.
So, option (b) is incorrect.
Option (c)
In option (c) it is given that there are infinite number of solutions.
But the equation [tex]5+7x=11+7x[/tex] has no solution.
So, option (c) is incorrect.
Option (d)
In option (d) it is given that the solution does not exist.
As per our calculation the equation [tex]5+7x=11+7x[/tex] does not have any solution.
So, option (d) is correct.
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Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Linear equations
Keywords: Linear equations, linear equation in one variable, linear equation in two variable, slope of a line, equation of the line, function, real numbers, ordinates, abscissa, interval, open interval, closed intervals, semi-closed intervals, semi-open intervals, sets, range domain, codomain.
Which is the converse of this conditional?
If it is appropriate, then I play golf.
A.
If it is appropriate, then I do not play golf.
B.
If I play golf, then it is appropriate.
C.
If I do not play golf, then it is appropriate.
D.
If it is not appropriate, then I play golf.
Benito is selling T-shirts for $8 each for his school fund-raiser. So far, he has sold 16 T-shirts. How many more does he need to sell to reach his goal of $200 in sales?
Three of these equations solve for the number of T-shirts, t, he still needs to sell to reach $200 in sales. Which equation does NOT?
a) t=9
b)8t+128=200
c)8(t+16)=200
d)8t+16=200
Answer:
Its D) 8t + 16 = 200
Answer: The correct option is (d) [tex]8t+16=200.[/tex]
Step-by-step explanation: Given that Benito is selling T-shirts for $8 each for his school fund-raiser and he has sold 16 T-shirts till now.
We are to find the number of T-shirts that he still need to sell to reach his goal of $200 in sales.
The number of T-shirts still he needs to sell is represented by t.
The, according to the given information, we have
[tex]8(t+16)=200\\\\\Rightarrow 8t+128=200\\\\\Rightarrow 8t=200-128\\\\\Rightarrow 8t=72\\\\\Rightarrow t=\dfrac{72}{8}\\\\\Rightarrow t=9.[/tex]
So, the number of T-shirts that he still needs to sell is 9.
Now, we can see from the above steps of solution for t that options (a), (b) and (c) gives the correct value of t, but from option (d), we get
[tex]8t+16=200\\\\\Rightarrow 8t=200-16\\\\\Rightarrow 8t=184\\\\\Rightarrow t=23\neq 9[/tex]
So, option (d) does NOT solve for the correct value of t.
Thus, (d) is the correct option.
What is the rounded number for 0.6?
Answer:
1
Step-by-step explanation:
6 Is rounded to 10 like 0.6 is rounded to 1
What is the simplified form of the following expression? (n5)(n2)
Final answer:
The simplified form of the expression (n⁵)(n²) is found by adding the exponents since the base is the same, resulting in n⁷.
Explanation:
The simplified form of the expression (n⁵)(n²) is achieved by applying the laws of exponents. Since both terms have a common base of n, when multiplying two exponentials with the same base, we simply add their exponents.
The addition of 5 and 2 (the exponents) provides n⁵⁺² which simplifies to n⁷.
Hence, the simplified form of (n⁵)(n²) is n⁷.
Write log8 3 as a logarithm of base 5.
1) (log3)5/(log8)5
2) (log5)3/(log5)8
3) (log8)5/(log3)5
4) (log5)8/(log5)3 ...?
To write log8 3 as a logarithm of base 5, we can use the change of base formula: loga b = logc b / logc a. Applying this formula, we have log5 3 = log8 3 / log8 5. Therefore, the correct option is (log8)5/(log3)5.
Explanation:The expression log83 represents the logarithm of 3 with base 8. To write it as a logarithm with base 5, we can use the change of base formula:
logab = logcb / logca
Applying this formula, we have:
log53 = log83 / log85
Therefore, the correct option is (log8)5/(log3)5.
A triangle has one side that measures x, and the other two sides each measure 4 inches less than x. the perimeter is 19 inches.what is the measure of x?
Simplify
-(2/3)(-9y)(3/2)(8x)(0)
A.
72xy
B.
–72xy
C.
72
D.
0
For what value of x must ABCD be a parallelogram
express 1507 million in a standard form
The area of a rectangular plot of land is given by the polynomial [tex] x^{2} [/tex] + 5x - 36.
Which pair of expressions could represent the sides of the plot of land?
A) (x - 4)(x - 9)
B) (x - 4)(x + 9)
Evaluate the expression 3(7 + 4)^2 − 14 ÷ 7.
Evaluate -3(-4) (-p)where p=9
4. What kind of triangle is made by connecting the points A(0, –6), B(3, –6), and C(3, –2)?
equilateral
right
isosceles
right and isosceles
5. What type of quadrilateral is formed by connecting the points (0, 9), (3, 6), (0, 1), and (–3, 6)?
rhombus
trapezoid
kite
quadrilateral ...?
Answer:
Part 4) Right triangle
Part 5) Kite
Step-by-step explanation:
Part 4) What kind of triangle is made by connecting the points A(0, –6), B(3, –6), and C(3, –2)?
Using a graphing tool
see the attached figure N [tex]1[/tex]
The triangle of the figure is not equilateral------> The triangle does not have three equal sides
The triangle of the figure is a right triangle------>The triangle has an angle of [tex]90\°[/tex]
The triangle of the figure is not isosceles------> The triangle does not have two equal sides
The triangle of the figure is not a right and isosceles
Part 5) What type of quadrilateral is formed by connecting the points [tex](0, 9), (3, 6), (0, 1), and (-3, 6)[/tex]?
Using a graphing tool
see the attached figure N [tex]2[/tex]
The figure is not a rhombus------> All sides are not congruent
The figure is not a trapezoid-----> has not parallel sides
The figure is a kite------> Two disjoint pairs of consecutive sides are congruent and the diagonals meet at a right angle
Answer: U7L7
Polygons in the coordinate plane
1.D
2.A
3.D
4.B
5.C
Step-by-step explanation:
What is the value of the function y=2x−3ywhen x=−1x=−1 ?
−5
−1
2
3
You made a typo in your question.
The equation should be y = 2x - 3.
y = 2(-1) - 3
y = -2 - 3
y = - 5
During a sale the price of a sweater changed from 20$ to 16$ what was the percent of decrease in the price of the sweater
What is the solution set of the system below?
x=2y
x-y^2=-2y
What is the answer to 2a+3=9a-4
You roll 2 dice. What is the probability that the sum of the dice is greater than 6 and 1 die shows a 2? A 6 X 6 table of dice outcomes will help you to answer this question ...?
The x-intercept of the line x = 3.5 is...?
which mixed number is equal to 7.6
A circle has its center at the origin, and (5, -12) is a point on the circle. how long is the radius of the circle
Answer: 13 units.
Step-by-step explanation: A circle has its center at the origin, and the point of the circle is (5, -12). Then we have to calculate the length of its radius formula to find the length between the two points.
What is the simplified form of 12z^2-7z-12/3z^2+2z-8? ...?
(m-a)(m-b)(m-c)......(m-x)(m-y)(m-z) =?
if the domain of a function that is reflected over the x axis is (3,4)(2,-1)(-1,2) what is the range? answers asap plz
The range of the reflected function consists of these reflected y-values. The range of the reflected function is (-4, -2, 1).
The range of a function reflected over the x-axis can be determined by considering the y-values of the original domain. In this case, the given domain points are (3,4), (2,-1), and (-1,2). The reflected points will have the same x-coordinates but opposite y-coordinates. Therefore, the reflected range will be the set of y-values obtained by changing the signs of the y-values in the original domain.
The original domain points have y-values of 4, -1, and 2. When reflected over the x-axis, these y-values become -4, 1, and -2, respectively.
Thus, the range of the reflected function consists of these reflected y-values. The range of the reflected function is (-4, -2, 1).
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A train leaves New York for Boston, 200 miles away, at 4:00 P.M. and averages 75 mph. Another train leaves Boston for New York on an adjacent set of tracks at 5:00 P.M. and averages 40 mph. At what time will the trains meet? (Round to the nearest minute.)
The trains will meet at 6:40 P.M. after traveling at different speeds towards each other.
The trains will meet at 6:40 P.M.
To calculate the time when the trains will meet, we need to determine the time it takes for the second train to cover the distance that the first train has already covered.
The first train covers the 200-mile distance in 200 / 75 = 2.67 hours, which is 2 hours and 40 minutes.
The second train leaves at 5:00 P.M., so adding 2 hours and 40 minutes gives us 7:40 P.M. as the time the second train reaches the meeting point.
By then, the first train has been traveling for 3 hours and 40 minutes, making the meeting time 6:40 P.M.
If there are 6 circles and 42 hearts what is the simplified ratio
Write y = 1/6x + 4 in standard form using integers.
we know that
The standard form of the equation of the line is
[tex] Ax + By = C [/tex]
we have
[tex] y = \frac{1}{6}x + 4 [/tex]
Multiply by [tex] 6 [/tex] both sides
[tex] 6y = x+24 [/tex]
Subtract x both sides
[tex] -x+6y = 24 [/tex]
therefore
the answer is
the equation of the line in standard form is equal to
[tex] -x+6y = 24 [/tex]
A person is standing exactly 36 ft from a telephone pole. There is a 30° angle of elevation from the ground to the top of the pole. What is the height of the pole?
The height of the telephone pole is approximately 20.79 feet, calculated using tangent function with a 30° angle.
To find the height of the telephone pole, we can use trigonometry. We'll use the tangent function since we have the opposite side and the adjacent side of the right triangle formed by the person, the pole, and the ground.
Let [tex]\( h \)[/tex] be the height of the pole.
We have the tangent of the angle:
[tex]\[ \tan(30^\circ) = \frac{h}{36} \][/tex]
Now, we can solve for [tex]\( h \):[/tex]
[tex]\[ h = 36 \times \tan(30^\circ) \][/tex]
Let's calculate:
[tex]\[ h = 36 \times \tan(30^\circ) \]\[ h = 36 \times 0.5774 \] (rounded value of tan(30°))\[ h \approx 20.7864 \][/tex]
So, the height of the telephone pole is approximately 20.79 feet.
Lucas and Erick are factoring the polynomial
12x3 – 6x2 + 8x – 4. Lucas groups the polynomial (12x3 + 8x) + (–6x2 – 4) to factor. Erick groups the polynomial (12x3 – 6x2) + (8x – 4) to factor. Who correctly grouped the terms to factor? Explain.
Both students are correct because polynomials can be grouped in different ways to factor. Both ways result in a common binomial factor between the groups. Using the distributive property , this common binomial term can be factored out. Each grouping results in the same two binomial factors.