if a sample of gas is intially at 1.8 atm,22.0 l, and 26.4 c, what will be the volume if the pressure is reduced by 0.8 atm and the temperature is lowered to 20.3 c?

The equation that represents the action of diethylamine (C2H5)2NH as a Brønsted-Lowry base in water is (C2H5)2NH + H2O -> (C2H5)2NH2+ + OH-. Diethylamine acts as the Brønsted-Lowry base, while water acts as the Brønsted-Lowry acid.

The equation that represents the action of diethylamine (C2H5)2NH as a Brønsted-Lowry base in water is:

(C2H5)2NH + H2O → (C2H5)2NH2+ + OH-

In this reaction, diethylamine accepts a proton from water, forming a diethylammonium ion (C2H5)2NH2+ and a hydroxide ion (OH-). Diethylamine acts as the Brønsted-Lowry base in this reaction, while water acts as the Brønsted-Lowry acid.

Final answer:

The octet rule states that atoms are most stable with eight electrons in their valence shell, guiding their chemical behaviors such as forming covalent or ionic bonds. However, there are exceptions to the rule, including hydrogen and transition metals.

Explanation:

The concept of the octet rule is fundamental in chemistry. It refers to the tendency of atoms to achieve a valence shell with eight electrons, which is the most stable arrangement for most main group elements. This principle guides the formation of chemical compounds and helps predict the behavior of atoms during chemical reactions. Atoms can reach an octet by gaining, losing, or sharing electrons through ionic or covalent bonding. For example, oxygen needs two additional electrons to complete its valence shell and can achieve this by forming covalent bonds in water (H₂O).

However, there are exceptions, such as hydrogen, which is stable with two valence electrons, and transition metals that do not typically follow the octet rule. Cations are positive ions formed when an atom loses valence electrons to reveal a lower, full octet shell. Understanding the octet rule is vital for comprehending how elements form stable molecules and compounds.

Answer:

table salt (NaCl) - I

TNT (C7H5N3O9) - O

glucose (C6H12O6) - O

2, 4-D (C3H6O3Cl2) - O

limestone (CaCO₃) - I

water (H₂O) - I

hope it helps :)

Answer: The stoichiometric coefficient of [tex]O_2[/tex] is 3.

Explanation:

Every balanced chemical equation follows Law of conservation of mass.

This law states that mass can neither be created nor be destroyed, but it can only be transformed from one form to another form.

This also means that the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side.

For the balanced chemical equation:

[tex]C_2H_6O(l)+3O_2(g)\rightarrow 2CO2(g)+3H_2O(l)[/tex]

On reactant side:

Number of Carbon atoms = 2

Number of Hydrogen atoms = 6

Number of Oxygen atoms = 7

On product side:

Number of Carbon atoms = 2

Number of Hydrogen atoms = 6

Number of Oxygen atoms = 7

Hence, the coefficient of [tex]O_2[/tex] in the balanced chemical equation is 3.

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal. Here the stoichiometric coefficient for oxygen is 7.

A balanced chemical equation, in which the masses of the reactants and products are equal, contains the same amount of atoms of each element on both sides of the equation. In other words, both sides of the reaction have an equal balance of mass and charge.

The number in front of the formula is the coefficient in chemistry. The coefficient reveals the number of molecules in a specific formula.

Here the balanced equation is:

2C₂H₆ +7O₂ → 4CO₂+ 6H₂O

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According to the Kinetic Molecular Theory, the absolute temperature of a gas is directly related to average molecular kinetic energy. Therefore, option B is correct.

The energy that an object has as a result of motion is known as kinetic energy. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilograms-meters squared per second squared if the mass is measured in kilograms and the velocity is measured in meters per second.

The idea of kinetic energy was first proposed in 1849 by William Thompson, who subsequently rose to the position of Lord Kelvin.

Thus, option B is correct.

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The molecular formula C8H8 might represent a cyclic compound where carbon atoms are linked in an 8-membered ring, with each carbon atom being bonded to two other carbon atoms and a hydrogen atom, maintaining the tetravalency of carbon.

The compound you mentioned, C8H8, does not fit with the typical hydrocarbon pattern which typically results in hydrocarbons like alkanes having a general formula of CnH2n+2. However, since the question stated clearly that there are no double or triple bonds and all carbon atoms are identical, there's a possibility that the compound is a cyclic structure. Let's consider a structure where carbon atoms are linked in a cyclic form, forming an 8-membered ring. Each carbon atom in this ring will form two bonds with two other carbon atoms and the remaining two bonds will be with hydrogen atoms. In this way, each carbon atom will maintain its tetravalency (4 bonds per carbon atom), and there will be 8 hydrogen atoms, exactly fitting the given formula C8H8. To draw the Lewis structure, arrange 8 carbon atoms in a ring and attach a hydrogen atom to each carbon atom. Remember, each line represents a single bond between atoms.

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The request for a Lewis structure of C8H8 without double or triple bonds and with all carbon and hydrogen atoms being chemically identical suggests an unusual compound that contradicts common organic chemistry principles, hence a conventional structure cannot be provided.

The student is asking for a Lewis structure of a compound with the formula C8H8 that does not contain any double or triple bonds. Given that all carbon and hydrogen atoms in this compound are chemically identical, this suggests a cyclic structure where each carbon atom is bound to two other carbons and a single hydrogen atom, forming a ring. The best structure fitting this description would be cyclooctatetraene, although it has alternating single and double bonds, which contradicts the no double or triple bonds condition.

However, considering the compound has no double or triple bonds, the compound would be highly unusual and not in line with standard organic chemistry principles. All carbon atoms making four bonds is a fundamental concept in organic chemistry, which leads to the conclusion that either the information given in the question is incorrect or it is a highly unconventional compound not typically covered in standard chemistry curricula. Therefore, without double or triple bonds, the compound's structure cannot be satisfactorily drawn while adhering to typical valency rules.

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Answer:

The given alkene is in the Z configuration. The bromination will result in the formation of 2,3 Dibromo 3 methyl pentane.

Explanation:

E and Z forms of the isomers are the configuration in which the polarity of groups on different sides of the double bond is different.

When the polar groups are on the opposite side of the double bond, it results in a Z isomer. When the polar groups are on the same side of the double it results in an E isomer.

The given figure is of [tex]\rm CH_3-CH=CH-CH_2-CH_2[/tex]

There is the presence of polar groups on the opposite side of the isomer. The molecule posses Z isomer.

The bromination of the molecule will result in the formation of 2,3 dibromo-3 methyl pentane.

The image for the bromination is attached below.

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The solvent in the developing tank is only 1/2 cm high and the samples are spotted at 3 cm.

The spots should always be above the level of solvent. If the spots are below the level of solvent, then the sample spot will dissolve or wash off in the solvent much before traveling in the Thin layer chromatography plate. So the sample will not separate out and the purpose of Thin layer chromatography will not be fulfilled.

Hence separation of components of sample mixture will not happen.

The spots should always be above the solvent, so that when the solvent move up through capillary action, the solvent comes in contact with the sample mixture and carries it up. As different component travel with different speed , so separation takes place.

We start with

1KClO3→KCl+O2

Balance K :

We have 1 K on the left, so we need 1 K on the right. We put a 1 in front of the KCl .

1KClO3→1KCl+O2

Balance Cl :

Cl is already balanced, with 1 Cl on each side.

Balance O :

We have 3 O atoms on the left and only 2 on the right. We need 1½ O2 molecules on the right. Uh, oh! Fractions!

We start over with a 2 as the coefficient.

2KClO3→2KCl+O2

Now we have 6 O atoms on the left. To get 6 O atoms on the right, we put a 3 in front of the O2 .

2KClO3→2KCl+3O2

Every formula now has a fixed coefficient. We now should have a balanced equation.

The balance chemical equation for the equation: KClO₃ -> KCl + O₂ is

2KClO₃ -> 2KCl + 3O₂

The balanced chemical equation for the equation KClO₃ -> KCl + O₂ can be obtained as illustrated below:

KClO₃ -> KCl + O₂

There are 2 atoms of O on the right side and 3 atoms on the left. It can be balanced by writing 2 before KClO₃ and 3 before O₂ as shown below:

2KClO₃ -> KCl + 3O₂

There are 2 atoms of K on the left side and 1 atom on the right. It can be balanced by writing 2 before KCl as shown below:

2KClO₃ -> 2KCl + 3O₂

Now, we can see that the equation is balanced as the number of atoms of each elements are equal on both sides of the equation.

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First let us compute for the molar mass of Mg(OH)2.

molar mass = 24.3 + 2 (16) + 2(1.0)

molar mass = 58.3 g/mol

So the mass is then:

mass = 3.2 mol * (58.3 g/mol)

mass = 186.56 grams

Final answer:

Mixing solutions of barium chloride and sodium sulfate results in a precipitation reaction, forming insoluble barium sulfate and soluble sodium chloride. The balanced chemical equation for this reaction is BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaCl(aq). The net ionic equation simplifies to Ba2+(aq) + SO42−(aq) → BaSO4(s).

Explanation:

Barium Chloride and Sodium Sulfate Reaction

When aqueous solutions of barium chloride (BaCl2(aq)) and sodium sulfate (Na2SO4(aq)) are mixed, a precipitation reaction occurs producing barium sulfate and sodium chloride.

The word equation for this reaction is:

Barium chloride + Sodium sulfate → Barium sulfate + Sodium chloride

The balanced chemical equation is:

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)

In the chemical equation, solid barium sulfate (BaSO4) is the precipitate, indicating a chemical change has occurred. Understanding solubility rules is key to predicting that barium sulfate is insoluble in water and will precipitate from the mixture.

The complete ionic equation for this reaction would show all the ions that are present in solution separately. Since BaSO4 is insoluble, it will not dissociate into ions:

Ba2+(aq) + 2Cl−(aq) + 2Na+(aq) + SO42−(aq) → BaSO4(s) + 2Na+(aq) + 2Cl−(aq)

The net ionic equation omits the spectator ions (in this case, Na+ and Cl−) and includes only the ions involved in the formation of the precipitate:

Ba2+(aq) + SO42−(aq) → BaSO4(s)

Final answer:

Approximately 6.808 moles of dipyrithione contain 8.2 x 10²⁴ atoms of nitrogen, given that dipyrithione contains 2 nitrogen atoms per molecule.

Explanation:

To find out how many moles of dipyrithione contain 8.2 x 10²⁴ atoms of Nitrogen (N), we first need to know the chemical formula of dipyrithione. But for the purpose of this exercise, let's assume it's a compound containing 2 N atoms per molecule (as with the common structure many pyrithione based compounds have). We'll use Avogadro's number (NA = 6.022 x 1023 mol-1) to calculate the moles of N in dipyrithione.

Since 1 mole of a substance contains Avogadro's number of particles (atoms in this case), 8.2 x 10²⁴atoms of N will be:

Number of moles (n) = Number of particles (N) / Avogadro's number (NA)

n = (8.2 x 10²⁴ atoms of N) / (6.022 x 10²³mol⁻¹)

n ≈ 13.616 moles of N

However, each molecule of dipyrithione has 2 N atoms, so we need to halve the amount of moles of N to find the moles of dipyrithione:

n(Dipyrithione) = n(N) / 2

n(Dipyrithione) ≈ 13.616 moles of N / 2

n(Dipyrithione) ≈ 6.808 moles of dipyrithione

Therefore, approximately 6.808 moles of dipyrithione contain 8.2 x 10²⁴ atoms of N.

Its iron melting i made an 100% on the test

Geologists primarily use seismic wave studies to gain indirect knowledge about Earth’s interior. Signals from these waves, recorded by seismographs, draw an image of the planet's internal structure, including its composition, temperature, and the nature of different layers.

Geologists obtain indirect evidence about Earth’s interior by d. recording and studying seismic waves. Similar to how sound waves travel through a struck bell, seismic waves move through a planet, providing valuable insight into its composition and structure. Depending on the materials seismic waves travel through, their paths bend (or refract), just as light waves do in telescope lenses. By monitoring and analyzing these wave patterns in a network of seismographs, scientists can construct a model of Earth's interior.

One significant observation is that shear or transverse waves, which cannot travel through liquid, aren’t transmitted through the Earth's core. Yet, longitudinal compression waves can pass through liquid and are therefore detectable throughout the Earth’s core. This information helps to estimate the temperature and state of matter within the Earth’s interior. Hence, seismic studies become a crucial tool for unlocking the secrets of our planet's interior.

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Answer:

As acebutolol is made into its hydrochloride and in that particular case,saturated liquid is no soluble in unsaturated solution,therefore its solubility is increase in the water.

This is an acid – base reaction and this always result a salt and water in a neutralization reaction. 

The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2) 

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O

balancing the elements: 

2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)

The product that is formed when hydrobromic acid and calcium hydroxide are combined is calcium bromide and water.

Chemical compounds combine chemically to produce new products. In the chemical reaction, the bonds of the reactants are broken and new substances called products are produced.

According to this question, hydrobromic acid and calcium hydroxide combine as follows:

Ca(OH)₂ + 2HBr → CaBr₂ + 2H₂O

The products from this combination are calcium bromide and water.

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The statement is true as a 1s electron in a Be atom has a greater effective nuclear charge (Zeff) than a 2s electron due to less shielding and being closer to the nucleus.

The statement that in a Be atom a 1s electron has a greater Zeff than a 2s electron is true. The concept of effective nuclear charge (Zeff) describes the net positive charge experienced by an electron in an atom. Since the 1s electron is closer to the nucleus than the 2s electron, it experiences less shielding and therefore feels a greater Zeff. Electrons in the 1s orbital effectively shield the 2s electrons from the nuclear charge, leading to a higher Zeff for the 1s electron. The greater penetration of the 1s electron (due to its proximity to the nucleus) results in a stronger attraction to the nucleus and a higher Zeff.

After the pizza comes out of the oven, it continues to cool down mainly through convection, as warmer air rises and cooler air takes its place. Conduction also occurs when it makes contact with cooler surfaces. Minor radiation in the form of infrared also contributes to the heat transfer.

After a pizza comes out of the oven, heat transfer continues to occur. This happens as the pizza releases heat into the cooler surrounding air. The primary mode of this heat transfer is convection, where warmer air rises from the hot surface of the pizza and cooler air moves in to take its place, creating a current that facilitates the transfer of heat. Additionally, conduction occurs when the pizza is placed on a cooler surface, like a cutting board or plate, causing heat to transfer from the hot pizza to the cooler object through direct physical contact.

There's also minor heat transfer by radiation, wherein heat is emitted from the hot pizza in the form of infrared radiation. However, compared to air-drying processes, the convective heat transfer coefficient is much higher during this process because of the large difference in temperatures between the pizza and the surrounding air. Over time, the temperature of the pizza will equalize with the room temperature, assuming no other heat sources are involved. Natural convection plays a role as well since the heat transfer within the air around the pizza doesn't require an external force like a fan, just the temperature difference caused by the hot pizza itself.

Answer : The mass of calcium sulfate precipitate will be, 6.12 grams

Solution :

First we have to calculate the moles of [tex]Ca^{2+}[/tex] and [tex]SO_4^{2-}[/tex].

[tex]\text{Moles of }Ca^{2+}=\text{Molarity of }Ca^{2+}\times \text{Volume of }Ca^{2+}=0.10mole/L\times 0.5L=0.05\text{ moles}[/tex]

[tex]\text{Moles of }SO_4^{2-}=\text{Molarity of }SO_4^{2-}\times \text{Volume of }SO_4^{2-}=0.10mole/L\times 0.5L=0.05\text{ moles}[/tex]

As, 0.05 moles of [tex]Ca^{2+}[/tex] is mixed with 0.05 moles of  [tex]SO_4^{2-}[/tex], it gives 0.05 moles of calcium sulfate.

Now we have to calculate the solubility of calcium sulfate.

The balanced equilibrium reaction will be,

[tex]CaSO_4\rightleftharpoons Ca^{2+}+SO_4^{2-}[/tex]

The expression for solubility constant for this reaction will be,

[tex]K_{sp}=(s)\times (s)[/tex]

[tex]K_{sp}=(s)^2[/tex]

Now put the value of [tex]K_{sp}[/tex] in this expression, we get the solubility of calcium sulfate.

[tex]2.40\times 10^{-5}=(s)^2[/tex]

[tex]s=4.89\times 10^{-3}M[/tex]

Now we have to calculate the moles of dissolved calcium sulfate in one liter solution.

[tex]\text{Moles of }CaSO_4=\text{Molarity of }CaSO_4\times \text{Volume of }CaSO_4=4.89\times 10^{-3}mole/L\times 1L=4.89\times 10^{-3}\text{ moles}[/tex]

Now we have to calculate the moles of calcium sulfate that precipitated.

[tex]\text{Moles of }CaSO_4\text{ precipitated}=\text{Moles of }CaSO_4\text{ present}-\text{Moles of }CaSO_4\text{ dissolved}[/tex]

[tex]\text{Moles of }CaSO_4\text{ precipitated}=0.05-4.89\times 10^{-3}=0.045\text{ moles}[/tex]

Now we have to calculate the mass of calcium sulfate that precipitated.

[tex]\text{Mass of }CaSO_4\text{ precipitated}=\text{Moles of }CaSO_4\text{ precipitated}\times \text{Molar mass of }CaSO_4[/tex]

[tex]\text{Mass of }CaSO_4\text{ precipitated}=0.045moles\times 136g/mole=6.12g[/tex]

Therefore, the mass of calcium sulfate precipitate will be, 6.12 grams

6.13 grams

Given:

Question:

What mass of calcium sulfate will precipitate?

The Process:

Step-1

The balanced equilibrium reaction:

[tex]\boxed{ \ CaSO_4_{(s)} \rightleftharpoons Ca^{2+}_{(aq)} + SO_{4}^{2-}_{(aq)} \ }[/tex] [tex]\boxed{ \ K_{sp} = 2.40 \times 10^{-5} \ }[/tex]

Let us prepare moles for both ions.

[tex]\boxed{ \ M = \frac{n}{V} \ }[/tex] [tex]\rightarrow \boxed{ \ n = MV \ }[/tex]

[tex]\boxed{ \ Moles \ of \ Ca^{2+} = 0.10 \ \frac{mole}{L} \times 0.5 \ L = 0.05 \ moles \ }[/tex]

[tex]\boxed{ \ Moles \ of \ SO_4^{2+} = 0.10 \ \frac{mole}{L} \times 0.5 \ L = 0.05 \ moles \ }[/tex]

Then prepare the concentration of each ion after mixing. Remember, after mixing we get a total volume of 500 mL + 500 mL = 1,000 mL or 1 L.

[tex]\boxed{ \ [Ca^{2+}] = \frac{0.05 \ moles}{1 \ L} = 0.05 \ M \ }[/tex]

[tex]\boxed{ \ [SO_4^{2-}] = \frac{0.05 \ moles}{1 \ L} = 0.05 \ M \ }[/tex]

Step-2

Let us calculate the ion product (Q) and compare it to Ksp.

[tex]\boxed{ \ Q = [Ca^{2+}][SO_{4}^{2-}] \ }[/tex] [tex]\rightarrow \boxed{ \ Q = [0.05][0.05] = 2.50 \times 10^{-3} \ M^2 \ }[/tex]

Compare with [tex]\boxed{ \ K_{sp} = 2.40 \times 10^{-5} \ }[/tex].

Because Q > Ksp, the solution is supersaturated and CaSO₄ will precipitate from solution.

Step-3

Let us calculate the solubility of CaSO₄ (s).

CaSO₄ ⇄ Ca²⁺ + SO₄²⁻

   s            s           s

[tex]\boxed{ \ K_{sp} = [Ca^{2+}][SO_{4}^{2-}] \ }[/tex]

[tex]\boxed{ \ K_{sp} = s \times s \ }[/tex]

[tex]\boxed{ \ K_{sp} = s^2 \ } \rightarrow \boxed{ \ s = \sqrt{K_{sp}} \ }[/tex]

[tex]\boxed{ \ s = \sqrt{2.40 \times 10^{-5}} \ }[/tex]

Hence, the solubility of CaSO₄ is [tex]\boxed{ \ 4.90 \times 10^{-3} \ M \ }[/tex].

After that, we can find out the mole of CaSO₄ which is dissolved.

[tex]\boxed{ \ Moles \ of \ CaSO_4 = 4.90 \times 10^{-3} \ \frac{mole}{L} \times (0.5 + 0.5) \ L = 4.90 \times 10^{-3} \ moles \ }[/tex]

Step-4

Thus we know that in this reaction:

[tex]\boxed{ \ CaSO_4_{(s)} \rightleftharpoons Ca^{2+}_{(aq)} + SO_{4}^{2-}_{(aq)} \ }[/tex] 0.05 moles of Ca²⁺ mixed with 0.05 moles of SO₄²⁻, will produce 0.05 moles of CaSO₄.

To calculate the precipitated mole of CaSO₄, we must subtract the resulting CaSO₄ mole with the dissolved CaSO₄ mole.

Moles of CaSO₄ precipitated = [tex]\boxed{ \ 0.05 \ moles - 4.90 \times 10^{-3} \ moles = 0.0451 \ moles \ }[/tex]

Final Step

Let us calculate the mass of CaSO₄ that will precipitate.

[tex]\boxed{ \ n = \frac{mass}{Mr} \ }[/tex] [tex]\rightarrow \boxed{ \ mass = n \times Mr \ }[/tex]

The molar mass of CaSO₄ is 136 g/mole.

[tex]\boxed{ \ mass = 0.0451 \ moles \times 136 \ \frac{g}{mole} \ }[/tex]

Thus, the mass of calcium sulfate which will precipitate by 6.13 grams.

_ _ _ _ _ _ _ _ _ _

Notes

We use the formula for root-mean-square speed and the given stratospheric temperature to calculate the average speeds of N2, O2, and O3 molecules.

The root-mean-square (rms) speed of a gas molecule can be calculated using the formula: rms speed = sqrt(3kT/m), where k is Boltzmann's constant (1.38 x 10^-23 J/K), T is the absolute temperature in Kelvin, and m is the molar mass of the gas in kilograms per mole.

Firstly, we convert the temperature from °C to K: -24°C = 249.15K.

Then, calculate the rms speed for each molecule, given the molar masses of N2=28.01 g/mol, O2=32 g/mol, and O3=48 g/mol, but convert these molar masses to kg/mol: N2=28.01 x 10^-3 kg/mol, O2=32 x 10^-3 kg/mol, O3=48 x 10^-3 kg/mol.

By inserting these values into formula, we can determine the rms speed for N2, O2, and O3 molecules at a temperature of -24°C in the stratosphere. This will give us the average speed of these molecules under these atmospheric conditions.

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Answer:

Explanation:

When there's a 'k' before an unit, it means "kilo". For instance, "2 kJ" is read as "two kilojoules". This prefix means 1000, so 2 kJ are equal to 2000 J.

With the above information in mind, we can rewrite the energy values of the problem into J:

So now it's just a matter of organizing the values:

The number of moles is simply calculated by taking the ratio of mass over the molar mass. The molar mass of silver nitrate AgNO3 is 169.87 g/mol. Therefore:

number of moles AgNO3 = 100 g / (169.87 g/mol)

number of moles AgNO3 = 0.59 moles

This question asks for a balanced equation for the reaction between hydrobromic acid and sodium bicarbonate. The balanced equation is HBr(aq) + NaHCO3(aq) → NaBr(aq) + H2O(l) + CO2(g) with respective phases of the substances noted.

The reaction between HBr(aq) and NaHCO3(aq) can be represented as a chemical equation as follows:

HBr(aq) + NaHCO3(aq) → NaBr(aq) + H2O(l) + CO2(g)

Here, the phases are expressed in parentheses. '(aq)' represents an aqueous solution, '(l)' represents a liquid, and '(g)' signifies a gas. In this reaction, hydrobromic acid (HBr) reacts with sodium bicarbonate (NaHCO3) to produce sodium bromide (NaBr), water (H2O), and carbon dioxide (CO2). In the balanced equation, the number of each type of atom on the reactant side (left) is equal to the number of each atom type on the product side (right), and this showcases the Law of Conservation of Mass.

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Answer: A

Explanation:

Larger gases like Neon produce more color bands (line spectra) than smaller gases like Hydrogen because they have more energy levels and therefore more possible electronic transitions. The number of color bands in a line spectrum is determined by the number of possible electronic transitions.

When a gas is heated, it emits light in the form of a line spectrum. The line spectrum consists of discrete, colored lines that correspond to specific wavelengths of light. Larger gases like Neon produce more color bands (line spectra) than smaller gases like Hydrogen because larger atoms have more energy levels and therefore more possible electronic transitions.

For example, Neon has ten electrons and its line spectrum consists of several distinct lines in the visible range, including red, orange, and blue. In contrast, Hydrogen has only one electron and its line spectrum consists of four distinct lines, called the Balmer series, with wavelengths in the red, green, blue, and violet regions of the spectrum.

Therefore, the number of color bands in a line spectrum is determined by the number of possible electronic transitions, which is higher for larger gases due to their larger number of energy levels.