Answer:
A. 0.52
Step-by-step explanation:
Let D be the event that person used Debit card and C b the event that person used coupon.
We have to find the probability of customer does not use coupons given that a customer does not pay with a debit card,
P(C'/D')=P(C')P(D'/C')/[P(C')P(D'/C')+P(D')P(D'/C')]
We are given that P(D)=0.35, P(C)=0.30 and P(D/C)=0.5.
P(D')=1-0.35=0.65
P(C')=1-0.3=0.7
P(D'/C')=0.5.
P(C'/D')=0.7(0.5)/[0.7(0.5)+0.65(0.5)]
P(C'/D')=0.35/[0.35+0.325]
P(C'/D')=0.35/[0.35+0.325]
P(C'/D')=0.35/0.675
P(C'/D')=0.5185=0.52
Thus, the probability of customer does not use coupons given that a customer does not pay with a debit card is 0.52.
We roll two fair 6-sided dice, A and B. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Find the probability that dice A is larger than dice B. 2) Given that the roll resulted in a sum of 5 or less, find the conditional probability that the two dice were equal. 3) Given that the two dice land on different numbers, find the conditional probability that the two dice differed by 2.
Answer:
1) 41.67% probability that dice A is larger than dice B.
2) Given hat the roll resulted in a sum of 5 or less, there is a 20% conditional probability that the two dice were equal.
3) Given that the two dice land on different numbers there is a 26.67% conditional probability that the two dice differed by 2.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have these possible outcomes:
Format(Dice A, Dice B)
(1,1), (1,2), (1,3), (1,4), (1,5),(1,6)
(2,1), (2,2), (2,3), (2,4), (2,5),(2,6)
(3,1), (3,2), (3,3), (3,4), (3,5),(3,6)
(4,1), (4,2), (4,3), (4,4), (4,5),(4,6)
(5,1), (5,2), (5,3), (5,4), (5,5),(5,6)
(6,1), (6,2), (6,3), (6,4), (6,5),(6,6)
There are 36 possible outcomes.
1) Find the probability that dice A is larger than dice B.
Desired outcomes:
(2,1)
(3,1), (3,2)
(4,1), (4,2), (4,3)
(5,1), (5,2), (5,3), (5,4)
(6,1), (6,2), (6,3), (6,4), (6,5)
There are 15 outcomes in which dice A is larger than dice B.
There are 36 total outcomes.
So there is a 15/36 = 0.4167 = 41.67% probability that dice A is larger than dice B.
2) Given that the roll resulted in a sum of 5 or less, find the conditional probability that the two dice were equal.
Desired outcomes:
Sum of 5 or less and equal
(1,1), (2,2)
There are 2 desired outcomes
Total outcomes:
Sum of 5 or less
(1,1), (1,2), (1,3), (1,4)
(2,1), (2,2), (2,3)
(3,1), (3,2)
(4,1)
There are 10 total outcomes.
So given hat the roll resulted in a sum of 5 or less, there is a 2/10 = 20% conditional probability that the two dice were equal.
3) Given that the two dice land on different numbers, find the conditional probability that the two dice differed by 2.
Desired outcomes
Differed by 2
(1,3), (2,4), (3,1), (3,5),(4,2),(4,6), (5,3), (6,4).
There are 8 total outcomes in which the dices differ by 2.
Total outcomes:
There are 30 outcomes in which the two dice land of different numbers.
So given that the two dice land on different numbers there is a 8/30 = 0.2667 = 26.67% conditional probability that the two dice differed by 2.
what is the solution to the equation below? round your answer to two decimal places. 4 • 8^x=11.48
Answer:
x = 0.51
Step-by-step explanation:
[tex]4\cdot 8^x = 11.48\\8^x = \frac{11.48}{4}\\ 8^x = 2.87\\\log_8 8^x = \log_8 2.87\\x=\log_8 2.87\\x=0.51[/tex]
Answer:
x=0.51
Step-by-step explanation:
Consider the viscosity versus shear rate data provided below. Fit these data using a power law model η = K ( ∂vx / ∂y) n‐1 , where K and n are constants. What values of K and n correspond to your fitting (provide the appropriate units)?
Answer:
The value of K is 90461 Pa·s^(0.456) and the value of n is 0.456 (with no units).
Compleated data:
η ∂vx / ∂y
0,02 750000
0,05 450000
0,1 350000
0,2 200000
0,5 130000
1 100000
2 60000
5 35000
10 28000
20 17000
50 10000
100 8000
Step-by-step explanation:
To solve this problem we can use a Least Squares Approximation with a power function to approximate the data sample.
In this case, we have to do some mathematical work to linearize the function.
For the function selected:
[tex]\eta=K(\partial v_x/\partial y)^{n-1}\\ln(\eta)=ln(K(X)^{m})=ln(K)+ln((\partial v_x/\partial y)^{n-1})\\ln(\eta)=ln(K)+(n-1)ln((\partial v_x/\partial y))[/tex]
Now we can do the next change of variables:
[tex]ln(\eta)=Y\\ln(K)=C\\(n-1)=m\\ln((\partial v_x/\partial y))=X\\[/tex]
Therefore:
[tex]Y=C+mX[/tex]
the matrix resultant of Least Squares Approximation with the data above is:
[tex]Y=\left[\begin{array}{c}-3.91&-3&-2.3\\-1.61&-0.69&0\\0.69&1.61&2.3\\3&3.91&4.61\end{array}\right][/tex] and [tex]\left[\begin{array}{cc}1&13.53\\1&13.02\\1&12.77\\1&12.21\\1&11.78\\1&11.51\\1&11\\1&10.46\\1&10.24\\1&9.74\\1&9.21\\1&8.99\end{array}\right] \cdot \left[\begin{array}{c}C&M\end{array}\right]=A\cdot x[/tex]
We then solve the equation:
[tex]A\cdot x=Y\\A^tA\cdot x=A^tY=b[/tex]
Solving this system of 2x2, we obtain:
C=11.4126741 and m=-0.544
Therefore
[tex]C=11.4126741=ln(K)\rightarrow K=90461\\m=-0.544=(n-1)\rightarrow n=0.456[/tex]
Knowing that the viscosity has as units Pa·s and the shear rate s⁻¹, the units of the constant k is:
[tex]K=90461 Pa\cdot s^{0.456}\\[/tex]
The constant n has no units.
Answer and Step-by-step explanation
η = K ((∂Vx / ∂y)^(n-1))
-Take the natural logarithm of both sides
In η = In {K ((∂Vx / ∂y)^(n-1))}
In η = In K + In ((∂Vx / ∂y)^(n-1))
In η = In K + (n-1) In (∂Vx / ∂y)
In η = (n-1) In (∂Vx / ∂y) + In K
-Compare this relation to the equation of a straight line, y = mx + C
y = In η
m = (n-1)
x = In (∂Vx / ∂y)
C = In K
So, the data missing must be for the Viscosity, η and the shear rate, ∂Vx / ∂y
- First step in the data treatment is to take the natural logarithm of these data sets.
- This leads to a new table of data with In η and In (∂Vx / ∂y).
- Plot this new set of data on a graph with In η on the y-axis and In (∂Vx / ∂y) on the x-axis.
- The slope of this graph, m = (n-1) from the power law relation. Therefore, n = slope + 1
- And the intercept on the y-axis, c = In K, that is, K = (e^c)
So, there goes the answers to the questions, n and K.
n has no units and K has varying units depending on the value of n.
Suppose we have a tank containing 1/2 lb of salt mixed in 1 gal of water. You pour salt into the tank at a rate of 2 lbs/min, and the well-stirred mixture leaves the tank at a rate in gal/min equal to the square of the current volume of water in the tank. How much salt is in the tank after 1 minute? Set up the initial value problem, and indicate what you are solving for.
Answer:
1.45lb of salt is present after 1 minute
Step-by-step explanation:
The detailed steps and derivation from integration is as shown in the attachment.
Samantha owns a food truck that sells tacos and burritos. She sells each taco for $3.75 and each burrito for $7.50. Yesterday Samantha made a total of $750 in revenue from all burrito and taco sales and there were twice as many burritos sold as there were tacos sold. Write a system of equations that could be used to determine the number of tacos sold and the number of burritos sold. Define the variables that you use to write the system.
Equation 1: 3.75t + 7.50b = 750
Equation 2: b = 2t
We can set up a system of equations to determine the number of tacos and burritos sold by Samantha.
Let's define the variables as follows:
Let "t" represent the number of tacos sold.
Let "b" represent the number of burritos sold.
According to the given information, we know:
1. Each taco is sold for $3.75, and each burrito is sold for $7.50.
2. Samantha made a total of $750 in revenue from all taco and burrito sales.
3. There were twice as many burritos sold as there were tacos sold.
To represent the total revenue, we can set up the equation:
3.75t + 7.50b = 750
To represent the relationship between the number of burritos and tacos sold, we can set up the equation:
b = 2t
Now we have a system of equations:
Equation 1: 3.75t + 7.50b = 750
Equation 2: b = 2t
By solving this system of equations, we can find the values of "t" and "b" which represent the number of tacos and burritos sold by Samantha.
Risk taking is an important part of investing. In order to make suitable investment decisions on behalf of their customers, portfolio managers give a questionnaire to new customers to measure their desire to take financial risks. The scores on the questionnaire are approximately normally distributed with a mean of 49.5 and a standard deviation of 15. The customers with scores in the bottom 10% are described as "risk averse." What is the questionnaire score that separates customers who are considered risk averse from those who are not? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
Final answer:
To identify the score separating risk-averse customers from others in a normally distributed set of questionnaire scores, we find the 10th percentile, which corresponds to a z-score of -1.2816. Using the mean of 49.5 and a standard deviation of 15, we calculate the cutoff score as 30.3.
Explanation:
To find the score that separates the customers who are considered risk averse from those who are not, we must look for the score at the 10th percentile in the normal distribution. Since the scores are approximately normally distributed, we can use the standard z-score table or a statistical calculator to find this value.
The mean (μ) of the distribution is 49.5, and the standard deviation (σ) is 15. We want to find the z-score that corresponds to the cumulative probability of 0.10. Looking at the z-score table or using a calculator, we find that the z-score associated with the bottom 10% of the distribution is approximately -1.2816.
Now we can use the z-score formula:
z = (X - μ) / σ
Where X is the score we are looking for. Substituting the values we have, we get:
-1.2816 = (X - 49.5) / 15
Solving for X:
X = -1.2816 * 15 + 49.5
X ≈ -19.224 + 49.5
X ≈ 30.276
When rounded to one decimal place, we get X = 30.3. Therefore, a score of 30.3 on the questionnaire separates those who are considered risk averse from those who are not.
Your company manufactures two models of speakers, the Ultra Mini and the Big Stack. Demand for each depends partly on the price of the other. If one is expensive, then more people will buy the other. If p1 is the price of the Ultra Mini, and p2 is the price of the Big Stack, demand (quantity sold) for the Ultra Mini is given by q1(p1, p2) = 100,000 ? 800p1 + p2 where q1 represents the number of Ultra Minis that will be sold in a year. The demand for the Big Stack is given by: q2(p1, p2) = 150,000 + p1 ? 800p2
Find the prices for the Ultra Mini and the Big Stack that will maximize your total revenue.
Answer:
1. At p1 = (100,000 - p2)/1,600 for Ultra Minis
2. At p2 = (150,000 - p1)/1,600 for Big Stack
Step-by-step explanation:
Since we are dealing with demand functions in which there is a negative relationship between price and quantity demanded, the question marks marks in the two demand functions can be assumed to be negative signs. As a result, the equations can be re-stated as follows:
q1(p1, p2) = 100,000 - 800p1 + p2 ................................ (1)
q2(p1, p2) = 150,000 + p1 - 800p2 ............................... (2)
In economics, total revenue (TC) is quantity demanded/sold multiply by price, the TCs for Ultra Mini (TCq1), and the Big Stack (TCq2) can be obtained by multiplying equations (1) and (2) with p1 and p2 as follows:
For q1:
TCq1 = p1*q1(p1, p2) = p1(100,000 - 800p1 + p2)
TCq1 = 100,000p1 - 800p1^2 + p1p2 .............................. (3)
For q2:
TCq2 = p2*q2(p1, p2) = p2(150,000 + p1 - 800p2)
TCq2 = p2150,000 + p1p2 - 800p2^2 .......................... (4)
We will take partial derivatives of each of equations (3) and (4) to obtain the marginal revenue (MR) as follows:
Partial derivative of equation (3) with respect to p1 and equate to zero:
MR = dTCq1/dp1 = 100,000 - 2(800p1) + p2 = 0
= 100,000 - 1,600p1 + p2 = 0
By rearranging and solving for p1, we have:
1,600p1 = 100,000 - p2
p1 = (100,000 - p2)/1,600 ....................................... (5)
The p1 in equation (5) is the price that will maximize the total revenue of Ultra Mini.
Partial derivative of equation (4) with respect to p2 and equate to zero:
MR = dTCq2/dp2 = 150,000 + p1 - 2(800p2) = 0
= 150,000 - 1,600p2 + p1 = 0
By rearranging and solving for p2, we have:
1,600p2 = 150,000 - p1
p2 = (150,000 - p1)/1,600 ....................................... (6)
The p2 in equation (6) is the price that will maximize the total revenue of Big Stack.
Therefore the prices at which total revenue of the company will be maximized are at p1 = (100,000 - p2)/1,600 for Ultra Minis and at p2 = (150,000 - p1)/1,600 for Big Stack.
To maximize total revenue, we need to find the prices for the Ultra Mini and the Big Stack that will maximize the quantity sold for each speaker model.
Explanation:To maximize total revenue, we need to find the prices for the Ultra Mini and the Big Stack that will maximize the quantity sold for each speaker model. To do this, we need to find the demand functions for the Ultra Mini and the Big Stack and set their derivatives equal to zero to find the critical points.
For the Ultra Mini, the demand function is q1(p1, p2) = 100,000 – 800p1 + p2, where q1 represents the number of Ultra Minis sold in a year. Taking the derivative of q1 with respect to p1, we get q1'(p1, p2) = -800. Setting q1' equal to zero, we find -800 = 0, which has no solution. Therefore, there are no critical points for the Ultra Mini.For the Big Stack, the demand function is q2(p1, p2) = 150,000 + p1 – 800p2, where q2 represents the number of Big Stacks sold in a year. Taking the derivative of q2 with respect to p2, we get q2'(p1, p2) = -800. Setting q2' equal to zero, we find -800 = 0, which has no solution. Therefore, there are no critical points for the Big Stack.Since there are no critical points for either speaker model, we cannot find the prices that will maximize total revenue. The company should consider other factors, such as production costs and market competition, to determine the optimal pricing strategy.
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The probability that a certain kind of component will survive a shock test is 3/4. Find the probability that exactly 2 of the next 4 components tested survive test, assuming tests are independent.
Answer:
Therefore the required probability is [tex]=\frac{27}{128}[/tex]
Step-by-step explanation:
The probability of success is [tex]\frac{3}{4}[/tex]
The number of trial = 4
X= the items survive out of 4
[tex]P(x=r)=^nC_rq^{n-r}p^r[/tex] p =the probability of success and q = the probability failure.
p=[tex]\frac{3}{4}[/tex] and [tex]q=(1-\frac{3}{4})=\frac{1}{4}[/tex]
[tex]\therefore P(X=2)=^4C_2(\frac{1}{4} )^2(\frac{3}{4} )^2[/tex]
[tex]=\frac{4!}{2!2!} (\frac{1}{16} )(\frac{9}{16} )[/tex]
[tex]=\frac{27}{128}[/tex]
Therefore the required probability is [tex]=\frac{27}{128}[/tex]
Final answer:
The probability that exactly 2 out of 4 components survive a shock test is calculated using the binomial probability formula, which results in approximately 0.2109 when rounded to four decimal places.
Explanation:
The question is asking for the probability that exactly 2 out of 4 components will survive a shock test given that the probability of a single component surviving is 3/4. To solve this, we use the binomial probability formula which is P(X = k) = (n choose k) p^k (1-p)^(n-k), where 'n' is the total number of trials, 'k' is the number of successful trials, and 'p' is the probability of success on a single trial.
Plugging in the given values, we have:
n = 4 (the number of components tested)
k = 2 (the desired number of components to survive)
p = 3/4 (the probability of a component surviving)
Using the formula:
P(X = 2) = (4 choose 2) * (3/4)^2 * (1/4)^(4-2)
P(X = 2) = 6 * (9/16) * (1/16)
P(X = 2) = 6 * (9/256)
P(X = 2) = 54/256
P(X = 2) = 0.2109 when rounded to four decimal places.
Therefore, the probability that exactly 2 of the next 4 components tested survive the shock test is approximately 0.2109.
Solve the initial value problem. x squared StartFraction dy Over dx EndFraction equalsStartFraction 4 x squared minus x minus 3 Over (x plus 1 )(y plus 1 )EndFraction , y (1 )equals 2 The solution is nothing. (Type an implicit solution. Type an equation using x and y as the variables.)
Answer:
C = 2*Ln (2) - 1
Step-by-step explanation:
Given
x²(dy/dx) = (4x²-x-3)/(x+1)(y+1)
y(1) = 2
We apply separation of variables as follows
(y+1) dy = ((4x²-x-3)/(x+1)(x²)) dx
⇒ ∫(y+1) dy = ∫((4x²-x-3)/(x+1)(x²)) dx
(y²/2) + y + C₁ = 2 ∫(1/(x+1)) dx + ∫((2x-3)/x²) dx
⇒ (y²/2) + y + C₁ = 2 Ln (x+1) 2 Ln (x) + (3/x) + C₂
⇒ C₁ - C₂= Ln (x+1)² + Ln (x)² + (3/x) - (y²/2) - y
⇒ C = Ln ((x+1)²(x)²) + (3/x) - (y²/2) - y
⇒ C = Ln ((x²+x)²) + (3/x) - (y²/2) - y
if y(1) = 2
we get
C = Ln ((1²+1)²) + (3/1) - (2²/2) - 2
⇒ C = 2*Ln (2) + 3 - 4 = 2*Ln (2) - 1
A company wants to determine if its employees have any preference among 5 different health plans which it offers to them. A sample of 200 employees provided the data below. Find the critical value chi Subscript alpha Superscript 2χ2α to test the claim that the probabilities show no preference. Use alphaαequals=0.01. Round to three decimal places.col1 Plan 1 2 3 4 5col2 Employees 32 30 55 65 18
A) 13.277B) 11.143C) 9.488D) 14.860
Answer:
a) 13.277
Step-by-step explanation:
The chi-square critical value can be assessed using chi-square area table and for this table need value of alpha and degree of freedom.
The value of alpha is given which is 0.01 and degree of freedom can be calculated as
df=k-1
Where k represent the categories which are 5 in the given case.
df=5-1=4.
For alpha=0.01 and df=4, we get the chi-square critical value 13.277.
Suppose the demand for a certain item is given by:
D(p) = - 5p^2-6p+400, where p represents the price of the item in dollars.
a. Find the rate of change of demand with respect to price.
b. Find and interpret the rate of change of demand when the price is $9.
Answer:
a. D'(p) = -10p - 6
b. There is a decrease of 96 units of demand for each dollar increase
Step-by-step explanation:
The demand function is:
[tex]D(p) = - 5p^2-6p+400[/tex]
(a) The derivate of the demand function with respect to price gives us the rate of change of demand:
[tex]\frac{dD(p)}{dp}=D'(p) = -10p-6[/tex]
(b) When p = $9, the rate of change of demand is:
[tex]D'(9) = -10*9-6\\D'(9) = -96\ \frac{units}{\$}[/tex]
This means that, when p = $9, there is a decrease of 96 units of demand for each dollar increase.
Final answer:
The rate of change of demand with respect to price is given by the derivative D'(p) = -10p - 6. When the price is $9, the rate of change of demand is -96, indicating that for each dollar increase in price, demand decreases by 96 items.
Explanation:
To address the demand model problem, we first need to calculate the rate of change of demand with respect to price. This involves taking the derivative of the demand function D(p) = -5p^2 - 6p + 400 with respect to price p. The derivative, D'(p), is calculated as follows:
Differentiate each term with respect to p:
The derivative of -5p^2 is -10p.
The derivative of -6p is -6.
The derivative of a constant (400) is 0.
Combine these to get the rate of change formula D'(p) = -10p - 6.
To find the rate of change of demand when the price is $9, we substitute p with 9 into the rate of change formula:
D'(9) = -10(9) - 6 = -90 - 6 = -96
The rate of change of demand at a price of $9 is -96 items per dollar. This means that for each one dollar increase in price, the quantity demanded decreases by 96 items.
A car is being towed at constant velocity on a horizontal road using a horizontal chain.
The tension in the chain must be equal to the weight of the car in order to maintain constant velocity.
a. true b. false
Answer:
b. false
Step-by-step explanation:
As the car is being towed using a horizontal chain, the tension's direction is horizontal and in opposite with the friction force's direction. The weight of the car, on the other hand, has a vertical direction and downward. Therefore, tension and weight are not related. In order to maintain constant velocity tension needs to be equal to friction force, which may be equal or less than the car weight.
A sales representative must visit nine cities. There are direct air connections between each of the cities. Use the multiplication rule of counting to determine the number of different choices the sales representative has for the order in which to visit the cities.
Answer:
362880
Step-by-step explanation:
Given that a sales representative must visit nine cities. There are direct air connections between each of the cities
Since there are direct connections between any two pairs the sales rep can visit in any order as he wishes.
He has 9 ways to select first city, now remaining cities are 8. He can visit any one in 8 ways.
i.e. No of ways of visiting 9 cities in any order = 9P9
= 9!
= 362880
So no of ways he visits the cities since there are direct connections between any two cities is
362880
This is a permutation problem. The sales representative has 9 factorial (9*8*7*6*5*4*3*2*1 = 362,880) different choices for the order to visit the cities.
Explanation:The subject of this question is a part of combinatorics, specifically Permutations. In this scenario, the sales representative has 9 different cities to visit and the order in which the cities are visited is important.
Using the multiplication rule of counting, the number of ways he can visit these cities is 9 factorial (9!). In general, the abbreviation 'n!' denotes the product of all positive integers less than or equal to n.
So for 9 cities this would be: 9*8*7*6*5*4*3*2*1 = 362,880 different choices for order to visit the cities.
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An experimenter is randomly sampling 4 objects in order from among 43 objects. What is the total number of samples in the sample space?
Final answer:
The total number of samples in the sample space can be found by using the concept of permutations and the rule of product.Therefore total number of samples in the sample space is 352,560.
Explanation:
The total number of samples in the sample space can be found by using the concept of permutations and the rule of product. Since there are 43 objects and we are sampling 4 objects in order, we can use the formula:
nPr = n! / (n - r)!
where n is the total number of objects and r is the number of objects being sampled. Plugging in the values, we get:
43P4 = 43! / (43 - 4)!
Simplifying, we have:
43P4 = 43! / 39!
which can be further simplified to:
43P4 = (43 * 42 * 41 * 40 * 39!) / 39!
The 39! terms cancel out, leaving us with:
43P4 = 43 * 42 * 41 * 40
Evaluating this expression, we find that the total number of samples in the sample space is 352,560.
The total number of samples in the sample space when randomly sampling 4 objects from 43 is calculated using permutations, resulting in 2,906,880 possible samples.
The student has asked about finding the total number of samples in the sample space when randomly sampling 4 objects in order from among 43 objects. This can be calculated using the formula for permutations, given that the order of selection matters and repeats are not allowed. The formula for permutations of n objects taken r at a time is nPr = n! / (n - r)!, where n! denotes the factorial of n, and (n-r)! denotes the factorial of (n-r).
In this case, n = 43 (the total number of objects) and r = 4 (the number of objects being selected). Thus, the calculation will be 43P4 = 43! / (43 - 4)! = 43! / 39!. Carrying out the calculation, 43P4 equals 43 × 42 × 41 × 40, which results in 2,906,880 possible samples.
The probability is 0.271 that the gestation period of a woman will exceed 9 months. In 3000 human gestation periods, roughly how many will exceed 9 months?
Answer:
813 will exceed 9 months.
Step-by-step explanation:
For each women, there are only two possible outcomes. Either they will exceed the gestation period, or they will not. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
In this problem, we have that:
[tex]n = 3000, p = 0.271[/tex]
In 3000 human gestation periods, roughly how many will exceed 9 months?
[tex]E(X) = np = 3000*0.271 = 813[/tex]
813 will exceed 9 months.
The gestation period should be exceed 9 month is 813.
Given that,
The probability is 0.271 that the gestation period of a woman will exceed 9 months. And, there is 3000 human gestation periodsBased on the above information, the calculation is as follows:
[tex]= 0.271 \times 3,000[/tex]
= 813
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What is the difference between the population and sample regression functions? Is this a distinction without difference?
Answer:
See explanation below.
Step-by-step explanation:
When we want to fit a linear model given by:
[tex] y = \beta_0 + \beta_1 x[/tex]
Where y is a vector with the observations of the dependent variable, [tex]\beta_0 , \beta_1 [/tex] the parameters of the model and x the vector with the observations of the independent variable.
For this case this population regression function represent the conditional mean of the variable Y with values of X constant. And since is a population regression the parameters are not known, for this reason we use the sample data to obtain the sample regression in order to estimate the parameters of interest [tex] \beta_0, \beta_1[/tex]
We can use any method in order to estimate the parameters for example least squares minimizing the difference between the fitted and the real observations for the dependenet variable. After we find the estimators for the regression model then we have a model with the estimated parameters like this one:
[tex] \hat y = \hat b_0 +\hat b_1 x[/tex]
With [tex] \hat \beta_0 = b_o , \hat \beta_1 = b_1[/tex]
And this model represent the sample regression function, and this equation shows to use the estimated relation between the dependent and the independent variable.
In five-card poker, a straight consists of five cards with adjacent denominations (e.g., 9 of clubs, 10 of hearts, jack of hearts, queen of spades, and king of clubs). Assuming that aces can be high or low, if you are dealt a five-card hand, what is the probability that it will be a straight with high card 9? (Round your answer to six decimal places.)
Answer:
[tex]0.000394[/tex]
Step-by-step explanation:
First we will find the probability of selecting five cards out of pack of cards
Probability of selecting five cards is equal to
[tex]^{52}C_5[/tex]
On expanding we get
[tex]\frac{52!}{47! * 5!} \\[/tex]
[tex]\frac{52 * 51 * 50 * 49 * 48 * 47!}{47 ! * 5*4*3*2*1} \\= 2598960[/tex]
straight high card [tex]9[/tex] means five cards with values lesser than [tex]9[/tex] but adjacent to it are
[tex]9, 8, 7, 6, 5[/tex]
there are four card for each number
Hence, probability of choosing five cards is equal to
[tex]4*4*4*4*4\\= 1024[/tex]
Probability of getting a straight with high card 9 is equal to
[tex]\frac{1024}{2598960}[/tex]
[tex]0.000394[/tex]
An experimenter is studying the effects of temperature, pressure, and different type of catalysts.
If there are 3 different temperatures, 4 different pressures, and 5 different catalysts, how many experimental runs are available?
Answer: 60
Step-by-step explanation:
Given : The number of choices for different temperatures = 3
The number of choices for different pressures = 4
The number of choices for different catalyst = 5
Since , the experimenter is studying the effects of temperature, pressure, and different type of catalysts.
Then by using the Fundamental principle of counting , we have
The number of experimental runs are available = (number of choices for temperatures ) x (number of choices for pressures) x( number of choices for catalyst)
= 3 x 4 x 5 = 60
Hence, the number of experimental runs are available = 60
An business development executive travels extensively for business. Her company offers two options to offset her driving expenses. Option 1 provides a car allowance of 510 dollars per month and a mileage reimbursement of $0.38/mile for fuel, insurance, and maintenance costs. Option 2 provides a mileage reimbursement of $0.65/mile to cover all expenses associated with owning a car.How many miles would she have to drive each YEAR for the two options to be of equal value. Express your answer in miles to the nearest whole mile.
Answer: 26667 miles
Step-by-step explanation:
According to the statement,
In option 1 we have 510 dollars per month plus $0.38/mile.
In option 2 we have $0.65/mile
Let x be the number of miles.
For a whole year, the option 1 is 510*12+ 0.38 x
For a whole year, the option 2 is 0.65 x
Equating both, we get
6120 + 0.38 x = 0.65 x
Solving, we get
x= 6120/ 0.27
x= 22666.67
x= 26667 miles
Someone trips on the sidewalk, droppingan urn containing 3 blue and 3 yellow marbles. themarbles roll away, but come to a stop (all in a row)on a crack in the cement. What is the probabilityof the three blue marbles ending up next to one an-other (i.e., without any yellow marbles in betweenthem)
Answer:
The probability of the three blue marbles ending up next to one another (i.e., without any yellow marbles in between them is 1/5 or 0.2.
Step-by-step explanation:
The 6 marbles can be arranged in 6! ways, But, there are 3 identical marbles of similar colour in two separate cases,
So, 6 marbles, consisting of 3 blue and 3 yellow marbles can be arranged in 6!/(3!3!) ways = 20 ways.
But, to arrange the six marbles in such a way that the 3 blue marbles end up next to one another without any yellow marble between them. This can be done by viewing the 3 blue marbles as one. Therefore, there are 4 marbles; 3 identical, blue marbles and 1 special marble.
To arrange that, it is, 4!/(3!1!) = 4
The probability of the three blue marbles ending up next to one another (i.e., without any yellow marbles in between them will be 4/20 = 1/5 or 0.2.
Final answer:
The probability that the three blue marbles will end up next to each other is 1/120. This is calculated by considering the blue marbles as one unit and arranging them with the yellow marbles, leading to 24 total arrangements, but since the blue marbles are indistinguishable, the number of favorable outcomes is the same as the arrangement of the yellow marbles, which is 6. The total number of possible outcomes is 720, calculated by 6 factorial.
Explanation:
The question asks for the probability that three blue marbles will end up next to each other after being dropped and rolling into a crack. To solve this, consider the three blue marbles as a single unit. Since there are also three yellow marbles, we can arrange four units (three blue marbles together as one unit and the three individual yellow marbles) in 4! (4 factorial) ways, which is equal to 24. However, the three blue marbles as a single unit can also be arranged among themselves in 3! (3 factorial) ways, but since they are indistinguishable, we don't consider these arrangements separate. So, there is only one way to arrange the blue block. Therefore the total number of favorable outcomes is the same as the number of ways to arrange the yellow marbles, which is also 3! or 6. To find the probability, we divide the favorable outcomes by the total possible outcomes without restrictions.
The total possible outcomes without any restrictions can be calculated assuming all 6 marbles are distinct, which gives us 6! (6 factorial) arrangements, equal to 720. Applying the probability formula, we have-
Probability = Favorable outcomes / Total outcomes = 6 (the number of ways to arrange the yellow marbles) / 720 possible arrangements = 6/720 = 1/120.
Therefore, the probability that the three blue marbles will end up next to each other is 1/120.
A painter is placing a ladder to reach the third story window, which is 19 feet above the ground and makes an angle with the ground of 80. How far out from the building does the base of the latter need to be positioned? Round your answer to the nearest 10th. The base of the latter needs to be positioned__ feet out from the building
Answer:
The answer to your question is 3.35 ft
Step-by-step explanation:
Data
height = 19 ft
angle = 80°
Process
1.- It is formed a right triangle so use a trigonometric function that relates the opposite side and the adjacent side. This trigonometric function is tangent.
tan Ф = Opposite side/adjacent side
adjacent side = Opposite side / tan Ф
adjacent side = 19 / tan 80
adjacent side = 19 / 5.67
adjacent side = 3.35 ft
Answer: The base of the latter needs to be positioned 3.6 feet out from the building.
Step-by-step explanation:
The ladder forms a right angle triangle with the building and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height from the where the top of the ladder touches the window to the base of the building represents the opposite side of the right angle triangle.
The distance from the bottom of the ladder to the base of the building represents the adjacent side of the right angle triangle.
To determine distance,h from the bottom of the ladder to the base of the building, we would apply
the tangent trigonometric ratio.
Tan θ = opposite side/adjacent.
Tan 80 = 19/h
h = 19/Tan 80 = 19/5.6713
h = 3.6 feet
A marijuana survey included 1610 responses from a list of approximately 241,500,000 adults 10) in the U.S. from which every 150.000 name was surveyed. Identify which of these types of sampling is used: A) Stratified B) Cluster C) ConvenienceD) Systematic E) Simple random
Answer:
the Fact that 1610 responses where gotten from the original population of
241 500 000 makes this a convenience sampling.
Step-by-step explanation:
convenience Sampling : this is a type of non-probability sampling that involves the sample being drawn from that part of the population that is close to hand.
A bacteria culture is initially 10 grams at t=0 hours and grows at a rate proportional to its size. After an hour the bacteria culture weighs 11 grams. At what time will the bacteria have tripled in size?
Answer: It will take 11.56 hours .
Step-by-step explanation:
Exponential growth in population or size formula :
[tex]P(t)=P_0e^{rt}[/tex]
, where [tex]P_0[/tex] = initial size
r= rate of growth
t= time period
As per given , we have
[tex]P_0=10[/tex] grams
At t= 1 , P(t)= 11 grams
Then,
[tex]11=10e^{r(1)}\\\\ 1.1= e^r\\\\\text{Taking natural log on both sides , we get} \\\\\ln (1.1)=r\ln (e)\\\\ r=\ln (1.1)\\\\ r=0.0953101798043\approx0.095[/tex]
When, the bacteria have tripled in size , P(t) = 3 x10 = 30
Then,
[tex]30=10e^{0.095t}\\\\ 3=e^{0.095t}[/tex]
[tex]\text{Taking natural log on both sides , we get}\\\\ \ln 3=0.095t\\\\ t=\dfrac{\ln3}{0.095}\\\\ t=\dfrac{1.09861228867}{0.095}\approx11.56[/tex]
Hence, it will take 11.56 hours .
A bacteria culture is initially 10 grams at t=0 hours & grows at a rate proportional to its size , After an hour the bacteria culture weighs 11 grams , The bacteria takes 11.56 hours to have tripled in size.
To find the time of bacteria when increasing the growth to tripled.
Given : when time=0 hours , weight=10 grams.
when time=1 hours , weight=11 grams.
To find: when time= ? hours , weight=30grams.
Here according to question, initial size = 10 grams we have asked for tripled in size i.e. 30 grams.
Now we knows that,
The formula for exponential growth in population or size is
[tex]\rm (P)=P_0e^{rt}[/tex] where,
[tex]\rm P_0=initial\;size\\\\r= rate\;of\;growth\\\\t= time \;period[/tex]
Now, we put the value in formula we get,
[tex]\rm P_0=10\;grams \\\\when ,\\\;\;t=1\;hour P(t)=11 grams\\Then,\\11=10e^{r(1)\\1.1 =e^r\\\\\rm Taking \;log(natural)\;both\;the\; side \;on \;solving\;we\;get,\\ln(1.1)=r\;ln(e)\\r=ln(1.1)\\r=0.953101798043\approx0.095[/tex]
Now when the bacteria increase its size to triple
[tex]\rm P(t) = 3 \times 10 = 30[/tex]
Then, according to the formula we substitute values in the formula,
[tex]\rm 30=10e^{0.095t}\\\\3=e^{0.095t}\\\\Again \;we \;take\;natural\;log\;on \;both\;the\;sides, we\;get\\ln\;3=0.095t\\\\t=\dfrac{\rm ln\;3}{0.095}\\\\\\\\\rm t= \dfrac{1.09861228867}{0.095} \\\\\ t=approx \; 11.56[/tex]
Therefore, The bacteria takes 11.56 hours to have tripled in size.
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A wallet contains five $10 bills, three $5 bills, six $1 bills, and no larger denominations. If bills are randomly selected one-by-one from the wallet, what is the probability that at least two bills must be selected to obtain the first $10 bill?
Final answer:
The probability that at least two bills must be selected to obtain the first $10 bill is approximately 24.7%.
Explanation:
To find the probability that at least two bills must be selected to obtain the first $10 bill, we need to calculate the probability of not drawing a $10 bill on the first draw and then drawing a $10 bill on the second draw. In total, there are 5 + 3 + 6 = 14 bills in the wallet.
On the first draw, the probability of not getting a $10 bill is the number of non-$10 bills over the total number of bills, which is (3 $5 bills + 6 $1 bills) / 14 total bills = 9/14.
Assuming a non-$10 bill was drawn first, there are now 13 bills left in the wallet. The probability of drawing a $10 bill on the second draw is now the number of $10 bills remaining over the total number of bills left, which is 5/13.
The combined probability of these two events happening in sequence (not drawing a $10 bill first and then drawing a $10 bill) is the product of their probabilities: (9/14) * (5/13).
Thus, the total probability is (9/14) * (5/13) = 45/182, which simplifies to approximately 0.247 or 24.7%.
Given the following sequence, what is the 10th term of the sequence? Assume that the sequences start with an index of 1. Sequence: The nth term is 3.
Answer:
the 10th term of the sequence is 3
Step-by-step explanation:
A sequence is a list of numbers or objects in a specific order
The nth term given in the question is not a function of n
i.e aₙ= 3
Since the sequence starts with an index of 1
a₁=3
All other terms in the sequence will also be 3. Meaning that it is an arithmetic progression with a common difference of 0.
The 10th term is given by
a₁₀= 3
The formula d = 6 t − 11 d=6t-11 expresses a car's distance (in feet) from a stop sign, d d, in terms of the number of seconds t t since it started moving. Determine the car's average speed over each of the following intervals of time.a. From t=3 to t=6 seconds...
b. From t=6 to t=6.5 seconds...
c. From t=6.5 to t=7 seconds...
Answer:
a) 6feet/secs
b) 6feet/secs
c) 6feet/secs
Step-by-step explanation:
The detailed steps are as shown in the attachment
The average speed of the car in each time interval is calculated by first evaluating the distance formula at the endpoints of the interval, subtracting to find the distance travelled, and then dividing by the time taken to travel that distance.
Explanation:The given formula is
d = 6t - 11
, where 'd' is the distance in feet, and 't' is the time in seconds since the car started moving. Firstly, to find the average speed, which is the distance travelled divided by time taken, we need to calculate the distance travelled in each interval. For instance, for the interval from 't=3' to 't=6', we first calculate the distances 'd' at t=3 and t=6 by substituting them into the equation, then subtracting the two to get the distance travelled over this time interval. Similarly, the distances travelled in the intervals from t=6 to t=6.5 seconds and t=6.5 to t=7 seconds were calculated. Finally, the
average speed
in each time interval is obtained by dividing that interval's travelled distance by the time taken.
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A normal deck of cards has 52 cards, consisting of 13 each of four suits: spades, hearts, diamonds, and clubs. Hearts and diamonds are red, while spades and clubs are black. Each suit has an ace, nine cards numbered 2 through 10, and three "face cards." The face cards are a jack, a queen, and a king. Answer the following questions for a single card drawn at random from a well-shuffled deck of cards. a. What is the probability of drawing a king of any suit? b. What is the probability of drawing a face card that is also a spade? c. What is the probability of drawing a card without a number on it? d. What is the probability of drawing a red card? What is the probability of drawing an ace? What is the probability of drawing a red ace? Arc these events ("ace" and "red") mutually exclusive? Are they independent? List two events that are mutually exclusive
Final answer:
a. The probability of drawing a king of any suit is 1/13. b. The probability of drawing a face card that is also a spade is 3/26. c. The probability of drawing a card without a number is 4/13. d. The probability of drawing a red card is 1/2. The probability of drawing an ace is 1/13. The probability of drawing a red ace is 1/26.
Explanation:
a. There are 4 kings in a deck of cards, one for each suit. So, the probability of drawing a king of any suit is the number of king cards divided by the total number of cards in the deck: 4/52 = 1/13 = 0.077 or 7.7%.
b. There are 3 face cards in each suit, and there are 2 black suits (spades and clubs). So, the probability of drawing a face card that is also a spade is the number of face cards (3) multiplied by the number of black suits (2), divided by the total number of cards in the deck: (3 * 2)/52 = 6/52 = 3/26 = 0.115 or 11.5%.
c. A card without a number refers to a face card (jack, queen, or king) or an ace. There are 12 face cards and 4 aces in a deck. So, the probability of drawing a card without a number is the number of face cards plus the number of aces divided by the total number of cards in the deck: (12 + 4)/52 = 16/52 = 4/13 = 0.308 or 30.8%.
d. There are 26 red cards in a deck (hearts and diamonds) and 52 total cards. So, the probability of drawing a red card is the number of red cards divided by the total number of cards: 26/52 = 1/2 = 0.5 or 50%. The probability of drawing an ace is 4/52 = 1/13 = 0.077 or 7.7%. The probability of drawing a red ace is the number of red aces divided by the total number of cards: 2/52 = 1/26 = 0.038 or 3.8%.
These events are mutually exclusive because a card cannot be an ace and also be a non-ace card at the same time. However, they are not independent because the probability of drawing a red ace would change if an ace had already been drawn.
Two events that are mutually exclusive are drawing a spade and drawing a heart. You cannot draw a card that is both a spade and a heart at the same time.
A 40% antifreeze solution is to be mixed with a 70% antifreeze
solution to get 240 liters of a 50% solution. How many liters of the
40% solution and how many liters of the 70% solution will be used?
Answer: 160 liters of the
40% solution and 80 liters of the 70% solution will be used.
Step-by-step explanation:
Let x represent the number of liters of 40% antifreeze solution that should be used.
Let y represent the number of liters of 70% antifreeze solution that should be used.
The volume of the mixture to be mixed is 240 liters. It means that
x + y = 240
The 40% antifreeze solution is to be mixed with a 70% antifreeze
solution to get 240 liters of a 50% solution. This means that
0.4x + 0.7y = 0.5(240)
0.4x + 0.7y = 120 - - - - - - - - - - - -1
Substituting x = 240 - y into equation 1, it becomes
0.4(240 - y) + 0.7y = 120
96 - 0.4y + 0.7y = 120
- 0.4y + 0.7y = 120 - 96
0.3y = 24
y = 24/0.3
y = 80
x = 240 - y = 240 - 80
x = 160
[tex]160 \ litres[/tex] of [tex]40 \%[/tex] antifreeze solution and [tex]80 \ litres[/tex] of [tex]70 \%[/tex] antifreeze solutions will be used.
Given, two solutions namely [tex]40 \%[/tex] antifreeze and [tex]70 \%[/tex] antifreeze solutions.
Let [tex]x[/tex] litres of the [tex]40 \%[/tex] antifreeze solution and [tex]y[/tex] litres of the [tex]70 \%[/tex] antifreeze solutions will be used.
Total volume of the solution,
[tex]x+y=240..........(1)[/tex]
Now, [tex]40\%[/tex] of antifreeze solution is to be mixed with a [tex]70 \%[/tex] of antifreeze
solution to get 240 liters of a [tex]50 \%[/tex] solution,
[tex]0.4x+0.7y=240\times 0.5[/tex]
[tex]0.4x+0.7y=120........(2)[/tex]
From Equation (1) [tex]y=240-x[/tex], substitute the value of [tex]y[/tex] in Equation (2),we get
[tex]0.4x+0.7(240-x)=120\\0.4x+168-0.7x=120\\-0.3x=120-168\\-0.3x=-48\\x=160[/tex]
Putting the value of [tex]x=160[/tex], we get
[tex]y=240-160[/tex]
[tex]y=80[/tex].
Hence [tex]160 \ litres[/tex] of [tex]40 \%[/tex] antifreeze solution and [tex]80 \ litres[/tex] of [tex]70 \%[/tex] antifreeze solutions will be used.
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A manufacturer of jeans has plants in California, Arizona, and Texas. A group of 25 pairs of jeans is randomly selected from the computerized database, and the state in which each is produced is recorded.
CA AZ AZ TX CA
CA CA TX TX TX
AZ AZ CA AZ TX
CA AZ TX TX TX
CA AZ AZ CA CA
a. What is the experimental unit?
b. What is the variable being measured? Is it qualitative or quantitative?
c. Construct a pie chart to describe the data.
d. Construct a bar chart to describe the data.
e. What proportion of the jeans are made in Texas?
f. What state produced the most jeans in the group?
g. If you want to find out whether the three plants produced equal number of jeans, or whether one produced more jeans that the others, how can you use the charts from parts c and d to help you? What conclusions can you draw from these data?
Answer and Step-by-step explanation:
a) In statistics, an experimental unit is one member of a set of entities being studied. Experimental units are the individuals on whom an experiment is being performed on.
25 pairs of jeans are randomly selected, hence, a single experimental unit is a pair of jeans.
b) Variables are the qualities/topics being investigated. Qualitative variables puts the variables in categories while quantitative variables involve numerical variables.
This question focuses on which state each pair of jeans is being produced, therefore this quality categorizes the jeans according to which state they were produced in. Hence, the variable being measured is a qualitative one.
c) For the pie chart, we need the frequency of the pair's of the jeans according to which state they were produced in.
California, CA, frequency = 9
Arizona, AZ, frequency = 8
Texas, TX, frequency = 8
Total = 25
A pie chart is based on 360°
CA will occupy (9/25) × 360° = 129.6°
AZ will occupy (8/25) × 360° = 115.2°
TX will occupy (8/25) × 360° = 115.2°
The pie chart is drawn with Microsoft Excel and presented in the image attached to this answer.
d) The bar chart is drawn with Microsoft Excel and presented in the image attached to this question. Each bar has equal width, but the height of each bar corresponds to its frequency.
e) The proportion of jeans produced in Texas = 8/25 = 0.32
f) The state that produces the highest number of jeans is the one with the highest frequency. That is California with frequency of 9 out of 25.
(g) The plant that produced more jeans than the others is the state in the
pie chart of part (c) with the largest angle (129.6°) or slice (California) and is the state in the bar graph of part (d) that has the highest bar.
From the data, it is evident that the three states make almost the same number of jeans, but California slightly edges the other two by being the state that produces the most number of jeans. Arizona and Texas produce the similar amounts of Jeans.
Although, this is just a sample out of a whole large quantity of Jeans, the laws of statistics and probability makes this random selection a representative of the whole set of jeans produced.
Hope this helps!
In this case, the experimental unit is the pair of jeans, the variable measured is the production state which is qualitative. The proportional production and most productive state can be determined by counting entries, and pie and bar charts can illustrate production distribution.
Explanation:a. The experimental unit is the individual pair of jeans.
b. The variable being measured is the state in which the jeans are produced, which is a qualitative variable.
c. and d. To construct the pie and bar charts, you simply need to count the total number of jeans produced in each state and represent this on the charts. This can be useful for visualizing the distribution of production across the states.
e. The proportion of jeans made in Texas can be found by counting the number of 'TX' entries and dividing by the total number of jeans (25).
f. The state that produced the most jeans is the one with the highest count in your data set. You would need to tally the appearances of each state to determine this.
g. The charts from parts c and d can assist you in determining whether there is a noticeable difference in production between the states. If one section of the pie chart or one bar on the bar graph is significantly larger than the others, it would suggest that state produces significantly more jeans. Similarly, if all sections/bars are similar in size, it suggests equal production across the states.
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Consider the two different numbers 327b (327 is base b) and 327b 1 (327 in base b 1), where b is a positive integer 8 or greater. If the difference between these two numbers is 89, what is the value of b
Answer:
Value of b = 14
Step-by-step explanation:
The detailed calculations with steps is shown in the attachment.