The molarity of the NaOH solution is calculated by determining the moles of KHP, which is 0.002693 mol, and then using the volume of the NaOH solution that reacted with KHP. The molarity comes out to be 0.1068 M.
To determine the molarity of the NaOH solution, we need to know the stoichiometry of the reaction between NaOH and KHP (potassium hydrogen phthalate). The equation for the reaction is:
KHP + NaOH -> KNaP + H2O
Each mole of KHP reacts with one mole of NaOH. First, we determine the moles of KHP:
Molar mass of KHP (C8H5KO4) = 204.22 g/mol
Moles of KHP = mass of KHP / molar mass of KHP
Moles of KHP = 0.550 g / 204.22 g/mol = 0.002693 mol KHP
Since the mole ratio between KHP and NaOH is 1:1, the moles of NaOH will also be 0.002693 mol. We can now determine the molarity (M) of the NaOH solution.
Molarity (M) = moles of solute / liters of solution
Molarity of NaOH = 0.002693 mol / 0.02521 L = 0.1068 M
Therefore, the molarity of the NaOH solution is 0.1068 M.
The molarity of the NaOH solution is [tex]{0.107 \text{ M}[/tex]
To find the molarity of the NaOH solution, follow these steps:
1. Write the balanced chemical equation for the reaction between NaOH and KHP (potassium hydrogen phthalate). The reaction is as follows:
[tex]\[ \text{NaOH} + \text{KHC}_8\text{H}_4\text{O}_4 \rightarrow \text{KNaC}_8\text{H}_4\text{O}_4 + \text{H}_2\text{O} \][/tex]
2. Calculate the moles of KHP that reacted with the NaOH solution. The molar mass of KHP [tex](KHC$_8$H$_4$O$_4$)[/tex] is 204.22 g/mol. Using the given mass of KHP (0.550 g), we can find the moles of KHP:
[tex]\[ \text{moles of KHP} = \frac{\text{mass of KHP}}{\text{molar mass of KHP}} = \frac{0.550 \text{ g}}{204.22 \text{ g/mol}} \][/tex]
3. Perform the calculation for the moles of KHP:
[tex]\[ \text{moles of KHP} = \frac{0.550}{204.22} \approx 0.002693 \text{ mol} \][/tex]
4. Since the reaction between NaOH and KHP occurs in a 1:1 molar ratio, the moles of NaOH that reacted with KHP are equal to the moles of KHP:
[tex]\[ \text{moles of NaOH} = \text{moles of KHP} = 0.002693 \text{ mol} \][/tex]
5. Calculate the molarity of the NaOH solution. The volume of the NaOH solution used is 25.21 ml, which is equivalent to 0.02521 L (since 1 L = 1000 ml):
[tex]\[ \text{Molarity of NaOH} = \frac{\text{moles of NaOH}}{\text{volume of NaOH in liters}} = \frac{0.002693 \text{ mol}}{0.02521 \text{ L}} \][/tex]
6. Perform the calculation for the molarity of NaOH:
[tex]\[ \text{Molarity of NaOH} = \frac{0.002693}{0.02521} \approx 0.1068 \text{ M} \][/tex]
7. To express the molarity with the correct number of significant figures, consider the given data. The volume of NaOH has four significant figures (25.21 ml), and the mass of KHP has three significant figures (0.550 g). Therefore, the molarity should be expressed with three significant figures:
[tex]\[ \text{Molarity of NaOH} = 0.107 \text{ M} \][/tex]
Which three temperature readings all mean the same thing?
A. 373 Kelvin, 100 degrees Celsius, 273 degrees Fahrenheit.
B. 273 Kelvin, 100 degrees Celsius, 212 degrees Fahrenheit.
C. 100 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
Explanation:
Conversion of degree Celsius to Kelvin :
K=^oC+273
Conversion of degree Celsius to degrees Fahrenheit :
^oF=(\frac{9}{5}\times ^oC)+32
By using these two conversion factors, we get the three temperature readings all mean the same thing.
For option A :
K=^oC+273=100+273=373K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF
For option B :
K=^oC+273=100+273=373K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF
For option C :
K=^oC+273=0+273=273K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF
For option D :
K=^oC+273=0+273=273K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF
From the given options, only option (D) is correct.
Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
Hope this helps!
Temperature is a degree of measure of heat and coldness. Temperature readings that are the same are 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
What are the units of the temperature?Temperature tells about the hotness and the cold degree measure of any substance or object. It can be measured by Kelvin, Celsius or Fahrenheit scale.
Convert degree Celsius to kelvin as:
[tex]\begin{aligned}\rm K &= \rm ^{\circ} C+273\\\\&= 0 + 273 \\\\&= 273 \;\rm kelvin\end{aligned}[/tex]
Convert degree Celsius to Fahrenheit as:
[tex]\begin{aligned}^{\circ} \rm F & = \rm (\dfrac{9}{5}\times ^{\circ} C)+32\\\\&= 0 + 32\\\\&= 32 \;\rm Fahrenheit \end{aligned}[/tex]
Therefore, option D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit is the temperature reading that means the same.
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What is peroxide (H2O2) oxidized to during redox reactions?
Answer:
H2O2 - - - - - -> H2O + O2
+1 +2 0
Oxidation O. S.
state of of Oxygen
Oxygen
[tex]2H_{2}O_{2}[/tex]---------> [tex]2H_{2}O+O_{2}[/tex] is the equation given for the oxidation of peroxide during a redox reaction.
What is a redox reaction?The reaction in which both oxidation and reduction can simultaneously occur to give raise to product is called as redox reaction.
The term redox is from 2 different words namely reduction and oxidation.Oxidation means the loss of electrons or increase in the oxidation state, reduction means the gain of electrons and decrease in the oxidation state.Redox reactions generally involve the transfer of electrons.To learn more about redox reactions, refer:
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Refer to the example about diatomic gases A and B in the text to do problems 19 - 27. How many grams in 3 moles of A2?
a.) 1.5
b.) 3
c.) 6
Final answer:
To find the number of grams in 3 moles of A2, we can use the formula: grams = moles * molar mass. In this case, the number of grams would be 6X grams.
Explanation:
To determine the number of grams in 3 moles of A2, we need to know the molar mass of A2. Assuming A is a diatomic gas, its molar mass would be the sum of the atomic masses of the two atoms in its formula. Let's say the atomic mass of A is X and the atomic mass of B is Y. Since A2 has two atoms of A, the molar mass of A2 would be 2X. Therefore, to find the number of grams in 3 moles of A2, we can use the formula: grams = moles * molar mass. In this case, the number of grams would be 3 * 2X = 6X grams. Hence, the correct option is c.) 6.
The correct answer is c.) 6. in 3 moles of A2 (with an assumed atomic mass of 3 units for element A), there are 18 grams.
Explanation:To determine the number of grams in 3 moles of A2, we first need to find the molar mass of A2. The molar mass of a substance is the mass in grams of one mole of that substance. Since A2 represents a diatomic molecule (two atoms of A), we'll calculate the molar mass by adding the atomic masses of two atoms of element A.
Looking at the periodic table, suppose the atomic mass of element A is X units. As A2 consists of two atoms of A, the molar mass of A2 is 2 * X units.
Without specific atomic masses provided, let's assume a hypothetical atomic mass of 3 units for element A. Therefore, the molar mass of A2 would be 2 * 3 = 6 units.
Now, to find the grams in 3 moles of A2, we use the formula:
[tex]\[ \text{Grams} = \text{Number of Moles} \times \text{Molar Mass} \][/tex]
Plugging in the values, we get:
[tex]\[ \text{Grams} = 3 \, \text{moles} \times 6 \, \text{units/mol} = 18 \, \text{units} \][/tex]
Thus, in 3 moles of A2 (with an assumed atomic mass of 3 units for element A), there are 18 grams.
This calculation relies on the assumed atomic mass for element A. However, the specific atomic masses for the elements A and B in the diatomic gases are essential for accurate calculations. The given question lacks this information, so the assumption of the atomic mass was necessary for computation.
A man weighing 48 newtons climbs a 2.0-meter ladder. How much work is done? 0.0 J 24 J 96 J 124 J
Answer:C) 96 j
explanation:48 N * 2.0 m = 96. Your answer should be C, 96 joules.
Answer: Work done by the man will be 96 J.
Explanation:
Work is defined as the amount of energy that is transferred in order to move an object by an external force. It is expressed in joules.
Mathematically,
[tex]W=F\times d[/tex]
Where,
W = Work done = ? J
F = Force applied = 48 N
d = Displacement of the body = 2 m
Putting values in above equation, we get:
[tex]W=48\times 2=96J[/tex]
Hence, work done by the man will be 96 J.
The table below gives the data that is needed to calculate the average atomic mass of element B. Isotope Atomic mass (amu) Relative abundance (%) B-10 10.01 19.91 B-11 11.01 80.09 Based on these data, what is the average atomic mass of element B? 10.01 10.51 10.81 11.01
Answer:
[tex]\boxed{\text{10.81 u}}[/tex]
Explanation:
The atomic mass of B is the weighted average of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent of the total).
Set up a table for easy calculation:
[tex]\begin{array}{ccccr}\textbf{Atom} & \textbf{Mass/u} &\textbf{Percent} & \textbf{Calculation}& \textbf{Result}\\^{10}\text{B}& 10.01 & 19.91 & 10.01 \times 0.1991 & 1.99\\^{11}\text{B}& 11.01 & 80.09 & 11.01 \times 0.8009 & 8.82 \\& & & \text{TOTAL} = &\textbf{10.81}\\\end{array}[/tex]
The average atomic mass of B is [tex]\boxed{\textbf{10.81 u}}[/tex].
Answer:
10.81u
Explanation:
I just did the test
Which type of functional group is located on a monosaccharide?
Halogen
Alcohol
Amine
Alkane
Answer:
Alcohol
Explanation:
Monosaccharides are the building block of carbohydrates, they include examples such as glucose, fructose, and galactose among others.Two monosaccharides join to form a disaccharide such as maltose and sucrose while many monosaccharides join to form polysaccharides such as starch and cellulose.Monosaccharides are made up of functional groups; carbonyl group,-COO and hydroxyl group also known as alcohol, OH.The type of functional group found on a monosaccharide is an alcohol group. Monosaccharides, like glucose, contain multiple alcohol (-OH) groups.
Explanation:The type of functional group located on a monosaccharide is an alcohol group. Monosaccharides are the simplest form of sugars and are characterized by the presence of multiple hydroxyl (-OH) groups, which are alcohol groups. An example of a monosaccharide is glucose, which has five alcohol groups. Other functional groups like halogen, amine, and alkane are not typically associated with monosaccharides in their common forms.
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THERE ARE FOUR SOLUTIONS: A, B, C, D. SOLUTION A YIELDS 3 PROTONS UPON IONIZATION, SOLUTION B IS AN ELECTRON PAIR DONOR, SOLUTION C IS AN OH- PRODUCER, AND SOLUTION D IS AN ELECTRON PAIR ACCEPTOR. WHICH OF THE FOLLOWING STATEMENTS IS TRUE.
A)C IS AN ACID
B)D IS A BASE
C)B IS A BASE
D)A IS A TRIPROTIC BASE
Answer:
The correct answer is C) B is a base. I just did it.
Explanation:
What will be the cell potential for a cu−zn galvanic cell with [zn2+]=0.1 m and the [cu2+]=0.01 m? view available hint(s)?
Answer: 1.07 V
Explanation: [tex]E^0_{[Zn^{2+}/Zn}=-0.76V[/tex]
[tex]E^0_{[Cu^{2+}/Cu]}=+0.34V[/tex]
The metal with negative reduction potential will easily lose electrons and thus is oxidized and the one with positive reduction potential will easily gain electrons and thus is reduced.
[tex]Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu[/tex]
[tex]E^o_{cell}[/tex] = standard electrode potential =[tex]E^0_{cathode}- E^0_{anode}=0.34-(-0.76)=1.1V[/tex]
Using Nernst equation:
[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}[/tex]
where,
n = number of electrons in oxidation-reduction reaction = 2
[tex]E_{cell}=1.10-\frac{0.0592}{2}\log \frac{[0.1]}{[0.01]}[/tex]
[tex]E_{cell}=1.07V[/tex]
Select the correct answer. Which statement describes the acid found in vinegar (acetic acid)? A. It tastes bitter. B. It feels slippery. C. It changes red litmus paper to blue. D. It reacts with Mg to produce H2. E. It releases OH- in a solution.
Answer:
D. It reacts with Mg to produce H2.
Answer: Option (D) is the correct answer.
Explanation:
The acetic acid, [tex](CH_{3}COOH)[/tex] present in vinegar reacts wit magnesium and therefore, it releases hydrogen gas and magnesium acetate.
The chemical reaction will be as follows.
[tex]2CH_{3}COOH + 2Mg \rightarrow 2Mg(CH_{3}COO) + H_{2}[/tex]
An acid is a substance which has pH less than 7 and changes blue litmus red. Acids taste sour as they are acidic in nature and releases hydrogen ions.
Whereas bases have pH greater than 7 and changes red litmus into blue.Bases taste bitter and releases hydroxide ions.
Thus, we can conclude that the statement it reacts with Mg to produce [tex]H_{2}[/tex] best describes the acid found in vinegar (acetic acid).
What quantity of energy is released when 540 g of cyclopentane are burned amswer?
Final answer:
When 540 g of cyclopentane are burned, approximately 8434.2 kJ of energy is released.
Explanation:
In order to determine the quantity of energy released when 540 g of cyclopentane is burned, we can use the information given in the examples. For example, when 3.12 g of glucose is burned, it releases 48.7 kJ of heat. We can use this information to calculate the heat released per gram of glucose, and then apply it to cyclopentane.
First, we calculate the heat released per gram of glucose:
Heat released per gram of glucose = 48.7 kJ / 3.12 g = 15.63 kJ/g
Now, we can use this value to calculate the heat released when 540 g of cyclopentane is burned:
Heat released = 15.63 kJ/g × 540 g = 8434.2 kJ
Therefore, when 540 g of cyclopentane is burned, approximately 8434.2 kJ of energy is released.
CHEMISTRY QUESTION WILL MARK YOU BRAINLIEST!
Based on Boyle's law, which of the following statements is true for an ideal gas at a constant temperature and mole amount?
A. Pressure is directly proportional to volume.
B. Pressure is inversely proportional to volume.
C. The number of collisions is independent of pressure.
D. The number of collisions decreases with increase in pressure.
Answer:
Based on Boyle's law, which of the following statements is true for an ideal gas at a constant temperature and mole amount?
A) Pressure is directly proportional to volume.
B) Pressure is inversely proportional to volume. CORRECT ANSWER!!!
C) The number of collisions is independent of pressure.
D) The number of collisions decreases with increase in pressure.
B is the CORRECT answer!!!
Based on Boyle's law, pressure is inversely proportional to volume is true for an ideal gas at a constant temperature and mole amount.
What is Boyle's law?Boyle’s law is a gas law which states that the pressure exerted by a gas (of a given mass, kept at a constant temperature) is inversely proportional to the volume occupied by it. In other words, the pressure and volume of a gas are inversely proportional to each other as long as the temperature and the quantity of gas are kept constant.
Boyle’s law is a connection between pressure and volume. It asserts that under constant temperature, the pressure of a specific quantity of gas is inversely proportional to its volume. It is possible to prove the law empirically. The paper discusses a syringe-based experimental approach for verifying the law.
The mathematical equation for Boyle's law is, where P denotes the pressure of the system, V denotes the volume of the gas, k is a constant value representative of the temperature and volume of the system.
The correct answer is option B.
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For the reaction ag2s(s) ⇌ 2 ag+ (aq) + s2- (aq), keq = 2.4 × 10-4 and the equilibrium concentration of silver ion is [ag+] = 2.5 × 10-1 m. what is [s2-] at equilibrium?
Answer : The concentration of silver ion is, [tex]3.8\times 10^{-3}M[/tex]
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,
[tex]Ag_2S(s)\rightleftharpoons 2Ag^+(aq)+S^{2-}(aq)[/tex]
The expression of [tex]K[/tex] will be,
[tex]K_{eq}=[Ag^+]^2[S^{2-}][/tex]
[tex]2.4\times 10^{-4}=(2.5\times 110^{-1})^2[S^{2-}][/tex]
[tex][S^{2-}]=3.8\times 10^{-3}M[/tex]
Therefore, the concentration of silver ion is, [tex]3.8\times 10^{-3}M[/tex]
3.84 x 10⁻³ M
Further explanationGiven:
[tex]\boxed{K_{eq} = 2.4 \times 10^{-4}}[/tex]The equilibrium concentration of silver ion is [tex]\boxed{ \ [Ag^+] = 2.5 \times 10^{-1} \ M \ }[/tex].Question:
What is [S²⁻] at equilibrium?
The Process:
For the reaction [tex]\boxed{ \ Ag_2S_{(s)} \rightleftharpoons 2Ag^+_{(aq)} + S^{2-}_{(aq)} \ }[/tex], we can observe that the substances on the right-hand side have a solution phase (aq) that is allowed into the equilibrium constant K.
Remember, pure solids (s) and liquids (l) are disregarded and kept at 1.
Therefore, from the initial formula [tex]\boxed{ \ K = \frac{ [Ag^+]^2.[S^{2-}] }{[Ag_2S]} \ }[/tex] we get the final result [tex]\boxed{ \ K = [Ag^+]^2.[S^{2-}] \ }[/tex].
Let us find out [S²⁻] at equilibrium.
[tex]\boxed{ \ K_{eq} = [Ag^+]^2.[S^{2-}] \ }[/tex]
[tex]\boxed{ \ 2.4 \times 10^{-4} = [2.5 \times 10^{-1}]^2.[S^{2-}] \ }[/tex]
[tex]\boxed{ \ 2.4 \times 10^{-4} = 6.25 \times 10^{-2} \cdot [S^{2-}] \ }[/tex]
[tex]\boxed{ \ [S^{2-}] = \frac{2.4 \times 10^{-4}}{6.25 \times 10^{-2}} \ }[/tex]
Thus we get [S²⁻] at equilibrium equal to [tex]\boxed{ \ [S^{2-}] = 3.84 \times 10^{-3} \ M \ }[/tex]
- - - - - - - - - -
Notes:
[tex]\boxed{ \ K_c \ or \ K_{eq} \ }[/tex], denotes that the equilibrium constant is expressed using molar concentrations, i.e., [tex]\boxed{ \ mol.dm^{-3} \ or \ mol.L^{-1} \ \ }[/tex]. For this question, [tex]\boxed{ \ K_c \ }[/tex] means the same thing as [tex]\boxed{ \ K_{eq} \ }[/tex].The rIght-hand side of the equation on top, left-hand side of the equation on the bottom.The square brackets show concentrations in [tex]\boxed{ \ mol.dm^{-3} \ or \ mol.L^{-1} \ or \ M \ }[/tex].The indices are the numbers in front of each substance (or the coefficients) in the chemical equation.A heterogeneous balance consists of more than one phase. Typical examples include reactions involving solids and gases, or solids and liquids. Substances that can be included in formula K are substances with a gas phase (g) or aqueous phase (aq). Pure solids and liquids are unincluded in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, so they are disregarded and kept at 1.Learn moreWrite the equilibrium constant for the reaction https://brainly.com/question/10608589 Write the equilibrium constant for the reaction a heterogeneous balance https://brainly.com/question/13026406What is the Ksp of the salt at 22°C? https://brainly.com/question/8985555which type of covalent bond is the shortest and the strongest
a. single bond
b. double bond
c. triple bond
d. ionic bond
Answer:
c. triple bond
Explanation:
Triple bonds are shortest and strongest covalent bond occur when six electrons are shared between two atoms.Bond strength is directly proportional to the amount of energy required to break the bond between the two atoms. The more energy required, the strongest the bond is . Bond length is the distance between two bonded atoms nuclei.Triple bonds are shorter and stronger than double bonds. While double bonds have shorter distances than single bonds.The shortest and strongest covalent bond is the triple bond. It involves the sharing of three pairs of electrons between two atoms, making it stronger and shorter than single and double bonds. An ionic bond is a different kind of bonding involving the transfer of electrons.
Explanation:In terms of covalent bonds, the triple bond is both the shortest and the strongest. Covalent bonds are a category of chemical bonding where two atoms share one or more electron pairs. Single bonds are longer and weaker since they involve the sharing of only one pair of electrons. Double bonds involve two pairs and are shorter and stronger. Triple bonds, such as those found in a nitrogen molecule (N2), are the shortest and strongest since they involve the sharing of three pairs of electrons. The ionic bond is not a type of covalent bond, it's a completely different kind of bonding which involves the transfer of electrons from one atom to another, not sharing.
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4.8 kg of sulfur dioxide contains how many molecules?
4.5 x 10^25 molecules of SO2
NH+4 is known as a _____________.
A. Polyatomic ion
B. Polycompound ion
C. Multi-atomic ion
D. None of these
A. Polyatomic Ion
Why? Nitrogen and Hydrogen are covalently bonded, and there are 4 Nitrogen atoms (fitting the prefix “poly”, meaning “many”).
[tex]NH^{+ 4}[/tex] is a A. Polyatomic ion
Explanation:When two atoms combine with each other through a covalent bond it leads to the formation of charged species called as polyatomic ions.
The ammonium cation is a decidedly accused polyatomic particle of the synthetic recipe [tex]NH^{+ 4}[/tex]. It is shaped by the protonation of ammonia. Ammonium is additionally a general name for decidedly charged or protonated substituted amines and quaternary ammonium cations [tex](NH^{+ 4})[/tex], where at least one hydrogen molecules are supplanted by natural gatherings.
The key requirement for a chain reaction is that...
More neutrons are produced than are absorbed
If you have 10 grams of a substance that decays with a half-life of 14 days, then how much will you have after 70 days?
a.0.31 g
b.0.10 g
c.2.50 g
d.1.25 g
Answer:
a. 0.31 g
Explanation:
It is known that the decay of a radioactive isotope isotope obeys first order kinetics.Also, it is clear that in first order decay the half-life time is independent of the initial concentration.Half-life time is the time needed for the reactants to be in its half concentration.If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).The half-life time of the substance = 14 days.So, 70 days represent (70 days/ 14 days = 5.0 half-lives).
So, the substance will decay:
10 g → (first half-life = 14 days) 5 g → (second half-life = 28 days) 1.5 g → (third half-life = 42 days) 1.25 g → (fourth half-life = 56 days) 0.625 g → (fifth half-life = 70 days) 0.3125 g.
So, the right choice is: a. 0.31 g.
Answer:
0.31 g
Explanation:
proved the answer right below
I need help. Please help me on the question
Th answer is A. Hormones are chemical receptors and the x structure is taking it to the nucleus
Draw the structure of the alkyl bromide from which the alkyl acetate shown below was made by SN2 reaction.
Show all stereochemistry.
Hi there nice to meet u thank you
A negative change in entropy indicates that...
A. the products have a greater number of available energy microstates than the reactants.
B. the products have a smaller number of available energy microstates than the reactants.
Answer: Option (B) is the correct answer.
Explanation:
Entropy is the measure of randomness present within the molecules of a substance.
When entropy of a reaction has a positive sign then it means there is an increase in the entropy. On the other hand, when entropy of a reaction has a negative sign then it means there is a decrease in entropy.
As, entropy change = entropy of products - entropy of reactants
And, larger is the value of entropy more will be the number of microstates.
When entropy is negative then entropy of products is less than the entropy of reactants.
This also means that products have small number of available energy microstates than reactants.
Thus, we can conclude that a negative change in entropy indicates that the products have a smaller number of available energy microstates than the reactants.
Answer:
A negative charge of entropy indicates that the product has a smaller number of available energy microstates than the reactants.
Explanation:
Entropy can be defined as the thermodynamic property of the system associated with the randomness of the molecules. The energy of entropy is represented as the mathematical flow for the availability of the reactants and products.
When the entropy has a negative charge, this indicates that there is a decrease in the entropy of the system.
A positive charge of entropy indicates the increase in the energy of the system. This indicates that there is a greater number of available microstates for the product.
With a negative charge, there is a decrease i.e. the available energy microstates are smaller for the product stating the product has lesser energy as compared to the reactants.
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Which statement correctly compares chemical reactions with nuclear reactions? In chemical reactions, new isotopes are formed. In nuclear reactions, new compounds are formed. Chemical reactions can be represented by balanced equations. Nuclear reactions cannot be represented by balanced equations. In chemical reactions, small amounts of energy can be absorbed or released. In nuclear reactions, changes in energy are much larger. In chemical reactions, only protons and neutrons are affected. In nuclear reactions, only electrons are affected.
Answer:
In chemical reactions, small amounts of energy can be absorbed or released. In nuclear reactions, changes in energy are much larger.
Explanation:
Chemical reactions involves the release or absorption of energy from the environment. When energy is released into the environment the chemical reaction is called exothermic reaction, while the one that takes energy from the environment is called endothermic reaction.Nuclear reactions on the other hand involves the release of large amounts of energy. Nuclear reactions are classified as either nuclear fission or nuclear fusion. Energy generated during nuclear reactions is large enough to produce electricity in nuclear power plants.Answer:
the answer is c
Explanation:
People can become a part of a When a person becomes part of an electrical that person can be shocked
Do you mean people become part of a 'circut' when a person becomes part of an electrical current?
Answer:
Circuit
Explanation:
People become part of the circuit
The freezing point and the boiling point of water can be altered by a variety of
techniques.
Which of the following has little or no effect on the boiling point of water?
a. Increasing the air pressure above the liquid
b. Adding alcohol to the water
c. Adding sodium chloride to the water
d. Increasing the amount of water
Answer:
Option d. increasing the amount of water has no effect of the boiling point of water.Explanation:
The boiling point is defined as the tempearature at which the vapor pressure of a substance equals the atmospheric pressure.
The vapor pressure is the pressure exerted by the vapor particles above the liquid in a sealed container.
In order to a liquid boil, the particles must have enough kinetic energy to escape from the tliquid to the gas (vapor) phase. With that we can approach the choices:
a. Increasing the air pressure above the lquid.
Incorrect choice.
If the air pressure above the liquids is increased, then the liquid particles will need more energy to escape, which means that this change has a considerable effect on increasing the boiling point.
b. Adding alcohol to the water.
Incorrect choice.
The alcohol added to the water is a solute. Some of the particles of the alcohol added will ocuppy part of the surface of liquid, reducing the number of particles of water that can escape from the liquid phase to the gas state. This reduces the vapor pressure and cause that the boiling point increase. Then, adding alcohol to the water does has an effect on the boiling point (the boiling point will increase).
c. Adding sodium chloride to the water.
Incorrect choice.
As in the case of adding alcohol, sodium chloride is a solute. Thus, the same analysis drives the condlusion that adding sodium chloride to the water does has an effect on the boiling point (the boiling point will increase).
d. Increasing the amount of water.
Correct choice.
The boiling point is a specific property of the substance: it does not depend on the amount of substance. Then, increasing the amount of water will not affect the boiling point.
The Tyndall effect is used to distinguish between
a. solutions and colloidsb. solvents and solutesc. liquids and gasesd. electrolytes and nonelectrolytes
A. solutions and colloids
The removal of silver tarnish from silverware using aluminum foil and a solution of electrolyte is an example of 1. oxidation of aluminum metal. 2. an example of an electrochemical cell. 3. all of these 4. reduction of silver ions.
Answer:
[tex]\boxed{\text{3. All of these}}[/tex]
Explanation:
The tarnish on silverware is silver sulfide.
You can remove the tarnish by resting the silverware on a piece of aluminium foil in a pot of boiling water with a small amount of salt.
The reaction is an example of an electrochemical cell.
The half-cell reactions are
3×[Ag₂S(s) + 2e⁻ ⟶ 2Ag(s) + S²⁻(aq)]
2×[Al(s) ⟶ Al³⁺(aq) + 3e⁻]
2Al³⁺(aq) + 3S²⁻(aq) ⟶ Al₂S₃(s)
3Ag₂S(s) + 2Al(s) ⟶ 6Ag(s) + Al₂S₃(s)
The aluminium ions react with the sulfide ions to form aluminium sulfide.
The aluminum atoms lose three electrons each, so they are oxidized.
The silver atoms gain one electron each, so they are reduced.
Thus, the answer is [tex]\boxed{\textbf{3. All of these}}[/tex].
What do you understand by the following terms used in a chemical equation :
a. Reactants
b. Products
c. Balanced chemical equation
Answer:
The 'reactants' react to form 'products'. Your turn this into a symbol equation and it is unbalanced so you must make it a 'balanced chemical equation'.
Hope this helps :)
Have a great day !
5INGH
Explanation:
The human body is made up of cells. The cells are like building blocks that are put together in just the right way to create a human. The cells of a human body can best be compared to a atoms in matter b thermal energy c oxygen in plants d conduction in heat transfer
Answer: i would personly say it would be atomos in matter because that mostly how human cells work
calculate the concentration in parts per million (ppm) of DDT if a sample size of 2000 g contained 0.050 g DDT
Answer:
= 25 ppm
Explanation:
PPM also refers to parts per million, it represents a low concentration of a solution. It represents 0.001 gram or a milligram in a 1000 mL, which equivalent to 1 mg per liter.Given; a sample size of 2000 g contained 0.050 g DDT
It means, 2000 mL sample contained 50 mg DDT
Therefore in ppm we get;
= 50 mg/ 2 L
= 25 mg/L
= 25 ppm
The concentration of DDT in your sample is calculated by dividing the mass of DDT by the total mass and multiplying by 1,000,000. Using your provided values, the DDT concentration is 25 parts per million (PPM).
Explanation:In the context of your question, you want to know the concentration of DDT in a sample size of 2000 g which contains 0.050 g of DDT in terms of parts per million (PPM). PPM is a unit typically used to express concentrations of pollutants and other trace contaminants in similar low concentration scenarios.
To calculate the concentration in PPM, the formula is quite straightforward. You divide the mass of the contaminant by the total mass of the sample, then multiply the result by 1,000,000.
Using your values:
(mass of DDT / total mass) * 1,000,000 = (0.050g / 2000g) * 1,000,000 = 25 ppm.
This means that there are 25 parts of DDT per every 1,000,000 parts of the sample.
Learn more about parts per million here:https://brainly.com/question/25104378
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What type of bond joins glycerol to fatty acids?
Ester linkages
Amine linkages
Carbohydrate linkages
Phosphate linkages
Answer:
Ester Linkages
Explanation:
In a fat molecule, the fatty acids are attached to each of the three carbons of the glycerol molecule with an ester bond through the oxygen atom.
You're welcome
The bond that joins glycerol to fatty acids in lipids like triglycerides and phospholipids is the ester linkage.
Explanation:The type of bond that joins glycerol to fatty acids in fat molecules and phospholipids is the ester linkage. Glycerol, which is a triol, bonds with three fatty acids, each through an ester bond, during a dehydration synthesis reaction. This reaction forms a triglyceride, which is a type of lipid essential for storing energy and providing insulation. In triglycerides, the fatty acids are attached to glycerol's three carbons through an oxygen atom, forming a strong ester bond. In the case of phospholipids, which are the major constituents of cell membranes, two fatty acid chains and a phosphate group form ester linkages with the glycerol backbone.
Which of the following is the major regulator of oxygen consumption during oxidative phosphorylation?
a.NADH
b.NAD+
c.NADPH
d.NADP+
e.ATP
f.ADP
g.O2
h.H20
i.CO2
Answer:
f.ADP
Explanation:
Oxidative phosphorylation occurs during the electron transport chain which is the final phase of cellular respiration. It depends on the hydrogen ion concentration gradient generated and is maintained by the electron transport chain. The oxidative phosphorylation acquires energy of high-energy electrons to synthesize ATP. During this process ADP is the major regulator of oxygen consumption.The regulation by ADP is referred to as the acceptor or respiratory control.Answer: F. ADP
Explanation:
The level of ADP is the most important factor in the determination of the rate of Oxidative Phosphorylation.
The rate of oxygen utilization by the Mitochondria is increased when ADP is added and usually returns to its initial level when the added ADP has being converted to ATP.