Answer:
59.09%
Step-by-step explanation:
We can calculate it with a direct rule of 3. If 22 chapters are the 100% of the book, what percent is 13 chapters?
[tex]\text{22 chapters} -\!\!\!-\!\!\!- 100\%\\ \\\text{13 chapters} -\!\!\!-\!\!\!- x\%[/tex]
We use the formula of the direct rule of 3:
[tex]x = \frac {13* 100}{22} \\ \\ x = \frac {1300}{22}[/tex]
x = 59.09
She has read the 59.09% of the book.
What is the value of the range of the function f(x)=x^2+2 for the domain value 1/4?
19+X=17 What is X pls tell me!
Betsy and 3 of her friends are splitting a whole watermelon. There are 6 circular slices of watermelon. How many slices of watermelon will each person get?
The slices of watermelon each person will get is 1.5 slices.
If the watermelon is divided equally, the number of slices each person would get can be determined by dividing the total slices of watermelon by the total number of friends.
Slice each person would get = total slices / total number of friends
6 / 4 = 1.5 slices
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Suppose r contains a reference to a new rectangle(5, 10, 20, 30). which of the following assignments is legal? (look inside the api documentation to check which interfaces the rectangle class implements.)
a. rectangle a = r;
e. measurable e = r;
b. shape b = r; f. serializable f = r;
c. string c = r; g. object g = r;
d. actionlistener d = r;
The Java Rectangle class implements both the Shape and Serializable interfaces. Therefore, Rectangle r can be legally assigned to Rectangle, Shape, Serializable, and Object data types. It can't be assigned to a String, Measurable, and ActionListener as Rectangle doesn't implement these.
Explanation:In Java, the Rectangle class implements the Shape and Serializable interfaces. Therefore, the legal assignments would be:
Rectangle a = r; because r is a Rectangle, you can assign r to another Rectangle object.Shape b = r; because Rectangle implements the Shape interface, you can assign r to a Shape object.Serializable f = r; because Rectangle implements the Serializable interface, you can assign r to a Serializable object.Object g = r; because all classes in Java extend the Object class implicitly, you can assign r to an Object.The rest assignments are not legal because the Rectangle class doesn't implement Measurable, ActionListener interfaces and it cannot be assigned to a String.
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A recipe calls for 4 2/3 cups of stock. If 4 1/2 times the recipe needs to be made, how much stock will be needed?
To find out how much stock is needed to make 4 1/2 times a recipe that calls for 4 2/3 cups, multiply 4.67 by 4.5 to get 21.015 cups of stock.
To determine how much stock will be needed if 4 1/2 times the recipe is made, we first need to multiply the amount of stock in the original recipe by 4 1/2. The original recipe calls for 4 2/3 cups of stock. To calculate the total amount required, we convert 2/3 to a decimal to make multiplication easier. Thus, 2/3 is equivalent to approximately 0.67.
Next, we multiply 4.67 (4 + 0.67 for the 2/3 cup) by 4.5 (4 1/2).
4.67 x 4.5 = 21.015 cups. Therefore, 21.015 cups of stock will be needed to make 4 1/2 times the recipe.
Stephanie has $152 in her bank account. She withdraws $20. Then, she deposits $84. Write an addition expression to represent this situation. Then, find the sum and explain it's meaning.
What is 31/2 times 3 1/2
Which of the following is the best example of a characteristic of an experiment?
Participants should be selected into the treatment group randomly.
Participants are rarely aware that they are part of an experiment.
Participants are observed without researchers making changes to their behaviors.
The results of an experiment are based on a questionnaire given to a random sample of the population.
Prove that f(x) = x^3 – 1000x^2 + x – 1 is ω(x^3) and o(x^3).
To prove that [tex]f(x) = x^3 - 1000x^2 + x - 1[/tex] is [tex]\omega(x^3)[/tex] and [tex]o(x^3)[/tex], we must show how the function grows in comparison to x^3 asymptotically.
To prove that [tex]f(x) = x^3 - 1000x^2 + x - 1[/tex] is [tex]\omega(x^3)[/tex] and [tex]o(x^3)[/tex], we need to show two things:
1. Proving that [tex]f(x) = x^3 - 1000x^2 + x - 1[/tex] is [tex]\omega(x^3)[/tex]
For a function to be [tex]\omega(x^3)[/tex], it needs to grow faster than [tex]x^3[/tex] asymptotically. This requires that the ratio of the function to [tex]x^3[/tex] tends towards infinity as x approaches infinity.
Consider:
[tex]\lim_{x \to \infty}[\frac{f(x)}{x^3} ] = \lim_{x \to \infty}[ \frac{x^3-1000x^2+x-1}{x^3} ][/tex]
Simplify the expression:
[tex]\lim_{x \to \infty}[ 1-\frac{1000}{x}+\frac{1}{x^2}-\frac{1}{x^3} ] =1[/tex]
Since the limit does not tend to infinity but instead tends to 1, f(x) is not ω(x^3). We made a mistake in our earlier assumption; let's correct this in the next point.
2. Proving that [tex]f(x) = x^3 - 1000x^2 + x - 1[/tex] is [tex]o(x^3)[/tex]
To show that f(x) is [tex]o(x^3)[/tex], the ratio of f(x) to [tex]x^3[/tex] should tend to zero as x tends to infinity.
Consider:
[tex]\lim_{x \to \infty} [\frac{f(x)}{x^3}] = \lim_{x \to \infty}[\frac{x^3-1000x^2+x-1}{x^3}][/tex]
Simplify the expression:
[tex]\lim_{x \to \infty}[ 1-\frac{1000}{x}+\frac{1}{x^2}-\frac{1}{x^3} ] =1[/tex]
This indicates that the limit tends to 1 and not 0, hence f(x) is not [tex]o(x^3)[/tex] either. We can see in both cases that the limits did not meet the required criteria for [tex]\omega(x^3)[/tex] or [tex]o(x^3)[/tex], implying a misunderstanding in the problem setup.
write 784 miles per 40 gallons as a rate in simplest form?
I believe it would be
784 miles/40 gallons = 19.6 miles per gallon
Describe t-test and explain how to interpret its results?
Use polar coordinates to find the limit. [if (r, θ) are polar coordinates of the point (x, y) with r ⥠0, note that r â 0+ as (x, y) â (0, 0).] (if an answer does not exist, enter dne.) lim (x, y)â(0, 0) 7eâx2 â y2 â 7 x2 + y2
Jim worked 40 regular hours last week, plus 8 overtime houts at the time and a half rate. His gross pay was $1,248.
a.) What was his hourly rate?
b.) What was his hourly overtime rate?
40 hours regular pay
8 hours at 1.5 = 8*1.5 = 12
40+12 = 52
1248/52 = 24
A) $24 per hour
B) 14*1.5 = $36 per hour for overtime
a)
His hourly rate= $ 24
b)
His hourly overtime rate= $ 36
Step-by-step explanation:Jim worked 40 regular hours last week, plus 8 overtime hours at the time and a half rate.
This means if he is paid $ x per hour working in regular hours.
Then he will be paid $ (1.5x) per hour working overtime.
( Since it is given that: he is paid time and a half rate for overtime)
Now, his gross pay is: $ 1248
i.e.
Amount working at regular hours for 40 hours+ Amount obtained for working 8 hours overtime= $ 1248
i.e.
40x+8(1.5x)=1248
i.e.
40x+12x=1248
i.e.
52x=1248
i.e.
x=24
a)
Hence, his hourly rate is:$ 24
b)
His hourly overtime rate is: $ (24×1.5)
i.e.
His hourly overtime rate is: $ 36
Enter the value, as a mixed number in simplest form, in the box. |2 1/3| = ?
Let P=(x,y) be a point on the graph of y=x2−9. (a) Express the distance d from P to the origin as a function of x.
Explanation on finding distance from a point to the origin as a function of x and showing invariance under rotations.
Distance from point P to the origin as a function of x:
Given point P(x, y) on y = x² – 9.
The distance d from P to the origin is d = √(x² + y²).
Substitute y = x² - 9 into the distance formula to express d as a function of x: d = √(x² + (x² - 9)²).
Invariance of distance under rotations:
The distance from P to the origin remains constant regardless of the rotation, as it depends only on the coordinates of the point and not the orientation of the coordinate system.
A study of king penguins looked for a relationship between how deep the penguins dive to seek food and how long they stay under water. for all but the shallowest dives, there is a linear relationship between depth of dive and length of time under water. the study report gives a scatterplot for a random sample of penguins. the dive duration is measured in minutes and depth (x value) is in meters. the depths are all positive numbers. the dives varied from 40 meters to 300 meters in depth. the report then says, "the regression equation for this bird is y|x = 2.85 + 0.0149x.
Derrick's garden is 18 1/2 feet long. He plants 3/8 of a foot apart. How many bulbs can Derrick plant in one row?
Hector is competing in a 42 mile bicycle race, he has already completed 18 miles of the race ad is traveling at a constant speed of 12 miles per hour when Wanda starts the race. Wanda is traveling at a constant speed of 16 miles per hour
Find the equation when Wanda will catch up to hector
solve sin4xcos2x-cos4xsin2x=square root of 2 sinx over the interval [0,2pi)
Final answer:
The trigonometric equation is solved using the sine difference identity, simplifying to sin(2x) = √2 sin(x). The solution involves finding values of x that satisfy the equation over the interval [0,2π). Trigonometric identities such as double angle formulas are essential in the process.
Explanation:
The student has presented a trigonometric equation involving sine and cosine functions to solve: sin(4x)cos(2x) - cos(4x)sin(2x) = √2 sin(x) over the interval [0,2π). This can be addressed by recognizing the left-hand side as the expansion of the sine difference identity: sin(A - B) = sin(A)cos(B) - cos(A)sin(B), where A = 4x and B = 2x. Therefore, the equation simplifies to sin(2x) = √2 sin(x). We solve this equation over the specified interval by looking for values of x that satisfy the condition.
However, none of the reference equations or principles provided directly align with solving the original question. Hence, we must rely solely on our knowledge of trigonometric identities, such as the double angle formulas which are relevant to this problem. The double angle identities state that sin(2θ) = 2sin(θ)cos(θ) and cos(2θ) = cos^2(θ) - sin^2(θ) or equivalently cos(2θ) = 2cos^2(θ) - 1 and cos(2θ) = 1 - 2sin^2(θ).
The number of terms in a binomial expansion
is one less than the power
is equal to the power
is one more than the power
Answer:
(C) is one more than the power
Step-by-step explanation:
Let us consider a binomial expansion:
[tex](x+y)^2=x^2+2xy+y^2[/tex]
The power of the above expansion is [tex]2[/tex] and the number of the terms in the above binomial expansion are [tex]3[/tex], thus the total number of terms in the binomial expansion is one more than the power.
Hence, Option C is correct.
the larger of two numbers is nine more than four times the smaller number the sum of the two numbers is 59 find the two numbers
Which one of the following is an arithmetic sequence?
A. .35, .5, .85, 1.1, 1.22, . . .
B. 5, 0, −1, −3, −7, . . .
C. 2, 3, 5, 7, 11, 13, 17, . . .
D. −2, 1, 4, 7, 10, . . .
Find the area lying above the x-axis and below the parabolic curve y = 4x -x2 A. 8 B. 16 C. 10 2/3 D. 8 1/3
Jayne has a home-based business putting on children’s parties. She charges $60 to design the party and then $10.00 per child. Write a function rule that relates the total cost of the party to the number of children n.
A f(n) = 10 – 55n
B f(n) = 60 + 10n
C f(n) = 10 + 60n
D f(n) = 10n – 55
The answer is f(n) = 60 + 10n.
What's the characteristic of the rule also called?The composite function rule (also called the chain rule) Has taken a look at the characteristic f(x)=(x2 + 1)17. we will think about this function as being. the end result of mixing features. If g(x) = x2 + 1 and h(t) = t17 then the result of.
What is an example of a characteristic rule?A function rule along with value = p + zero.08p is an equation that describes a useful relationship. If p is the charge you pay for an object and 0.08 is the income tax, the feature rule above is the value of the item. in case you are given a desk, usually, you need to cautiously study the desk to peer what the function rule is.
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What is the nth term for 1 7 15 25 37
Answer:
51 hope this helps!!!!!!!!!!
Step-by-step explanation:
Final answer:
The nth term for the given sequence 1, 7, 15, 25, 37 is derived to be n² + n - 1, which fits the pattern of the sequence accurately.
Explanation:
The sequence given is 1, 7, 15, 25, 37. To find the nth term of this sequence, let's first identify the pattern of differences between the terms. Observing the differences, we see they are 6, 8, 10, and 12, which suggests an arithmetic sequence in the differences. This indicates the original sequence is quadratic.
Using the general formula for the nth term of a quadratic sequence, An² + Bn + C, we can substitute the first few terms to solve for A, B, and C. However, there's a quicker method given the pattern of differences seen in the second layer (6, 8, 10, 12, ...) that increases by 2 each time, suggesting that 2n is involved.
Through analysis, the nth-term formula can be derived as n² + n - 1.
Here's why:
considering n=1 for the first term, we get 1+1-1=1;
for n=2, the formula yields 2^2+2-1=7; and so forth, matching the given sequence precisely.
almonds cost 3.49$ per pound. a bag of almonds cost 6.95$. to the nearest whole pound, about how many pounds of almonds are in the bag?
Find the area of the shaded figure. To do so, subtract the area of the smaller square from the area of the larger square.
Large square side length: (x squared plus 10)
Small square side length: x
Image included.
What is the area of the shaded region?
The area of the shaded figure is (x⁴ + 19x² + 100) square meters after subtracting the area of the smaller square from the area of the larger square.
What is a square?It is defined as a two-dimensional geometry that has four sides and four vertices. The sides of the square are equal in length. It is a regular quadrilateral.
It is given that:
Large square side length: (x squared plus 10)
Small square side length: x
The area of the large square = (x² + 10)(x² + 10)
The area of the large square = (x² + 10)²
The area of the small square = (x)(x)
The area of the small square = x²
The area of the shaded figure = (x² + 10)² - x²
The area of the shaded figure = (x⁴ + 19x² + 100) square meters
Thus, the area of the shaded figure is (x⁴ + 19x² + 100) square meters after subtracting the area of the smaller square from the area of the larger square.
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Determine the missing information in the paragraph proof. Given: Lines a and c intersect at point S, creating 4 angles. Prove: Corresponding angles are congruent. We are given that lines a and c intersect at point S. Translate line a down line c until point S reaches point Q. Call the new line through Q line b. Because translations preserve orientation, lines a and b are ________. Because translations preserve angle measure, ∠RSU ≅ ∠RQU'. For the same reason, ∠RST ≅ ∠RQT', ∠PSU ≅ ∠PQU', and ∠PST ≅ ∠PQT'. Each of the angle pairs are corresponding angles. Therefore, corresponding angles are congruent. parallel perpendicular congruent reflected
Answer: Parallel.
Step-by-step explanation:
Given: Lines a and c intersect at point S, creating 4 angles.
To Prove: Corresponding angles are congruent.
We are given that lines a and c intersect at point S.
Translate line a down line c until point S reaches point Q.
Call the new line through Q line b.
We know that translations preserve orientation then every point on line b is equidistant from every points on line a.
Therefore, lines a and b are parallel by the definition of parallel lines.
Hence, the complete statement is Because translations preserve orientation, lines a and b are parallel.
Mae sold raffle tickets to Steven and to Theo. Each ticket costs k dollars. Steven bought 10 raffle tickets. Theo bought 15 raffle tickets. Which expression must be equal to the difference between how many dollars Theo spent and how many dollars Steven spent
How many terms are in the arithmetic sequence 7, 0, −7, . . . , −175?
Hint: an = a1 + d(n − 1), where a1 is the first term and d is the common difference