how to do this question

Answer:

The kinetic energy gained is 40[J]

Explanation:

This is a problem that applies the work and energy conservation. We must analyze the initial and final positions as well as the forces that act on the couch during displacement.

The working and energy conservation theorem says:

[tex]E_{k1} + W_{1-2}= E_{k2}[/tex]

The above equation tells us that kinetic energy plus the work done to move an object from one position to another will be equal to kinetic energy in the last position.

The kinetic energy in the initial position is zero since the couch is at rest, Ek1=0

The work will be given by the force that drives the couch multiplied by the distance, and the friction force that acts in the opposite direction to the displacement.

[tex]0+(200-180)*2= Ek2\\Ek2=20*2= 40 [J][/tex]

Answer:

37.1

Explanation:

mass of 2 atoms of chlorine-35 = 2× 35 = 70

mass of 5 atoms of chlorine-38 = 5 × 38 =  190

average mass = total mass / total number of atoms

                        = (70 +190) / (2 +5)

                        =  260 / 7

                        = 37.143

                        = 37.1

Final answer:

The average mass of chlorine-35 and chlorine-38 can be calculated using their respective atomic masses and percent abundances. The average mass of chlorine is 35.46 amu.

Explanation:

The average mass of chlorine can be calculated using the information provided. Chlorine-35 has an atomic mass of 34.969 amu and a percent abundance of 75.77%. Chlorine-38 has an atomic mass of 36.966 amu and a percent abundance of 24.23%. To calculate the average mass, we multiply the fraction of chlorine-35 (0.7577) by its mass, and add it to the fraction of chlorine-38 (0.2423) multiplied by its mass.

Therefore, the average mass of chlorine is: (0.7577 * 34.969) + (0.2423 * 36.966) = 35.46 amu.

Answer:

It would be A.

Explanation:

The scale goes from 0 to 14, With 0 being acidic and 14 being basic.

So if 7 is neutral, then anything less than 7 is moving more towards being more acidic.  Anything higher than 7 is moving towards being more basic.

Answer:

100, 50, 40, 30, 20, 10 butter

Explanation:

Answer:

longitudinal waves have those properties

Answer:

[tex]\displaystyle y_m=3.65m[/tex]

Explanation:

Motion in The Plane

When an object is launched in free air with some angle respect to the horizontal, it describes a known parabolic path, comes to a maximum height and finally drops back to the ground level at a certain distance from the launching place.

The movement is split into two components: the horizontal component with constant speed and the vertical component with variable speed, modified by the acceleration of gravity. If we are given the values of [tex]v_o[/tex] and [tex]\theta\\[/tex] as the initial speed and angle, then we have

[tex]\displaystyle v_x=v_o\ cos\theta[/tex]

[tex]\displaystyle v_y=v_o\ sin\theta-gt[/tex]

[tex]\displaystyle x=v_o\ cos\theta\ t[/tex]

[tex]\displaystyle y=v_o\ sin\theta\ t -\frac{gt^2}{2}[/tex]

If we want to know the maximum height reached by the object, we find the value of t when [tex]v_y[/tex] becomes zero, because the object stops going up and starts going down

[tex]\displaystyle v_y=o\Rightarrow v_o\ sin\theta =gt[/tex]

Solving for t

[tex]\displaystyle t=\frac{v_o\ sin\theta }{g}[/tex]

Then we replace that value into y, to find the maximum height

[tex]\displaystyle y_m=v_o\ sin\theta \ \frac{v_o\ sin\theta }{g}-\frac{g}{2}\left (\frac{v_o\ sin\theta }{g}\right )^2[/tex]

Operating and simplifying

[tex]\displaystyle y_m=\frac{v_o^2\ sin^2\theta }{2g}[/tex]

We have

[tex]\displaystyle v_o=20\ m/s,\ \theta=25^o[/tex]

The maximum height is

[tex]\displaystyle y_m=\frac{(20)^2(sin25^o)^2}{2(9.8)}=\frac{71.44}{19.6}[/tex]

[tex]\displaystyle y_m=3.65m[/tex]

Answer:

562.5 m

Explanation:

Displacement is area under the graph of velocity.

d = 10*25 + 25^2/2 = 562.5 m

The displacement of the object is 550 meters.

The velocity graph shows that the object is moving in a positive direction for the first 25 seconds.

The velocity is constant at 10 m/s for the first 10 seconds, and then it increases to 20 m/s for the next 15 seconds.

The area under the velocity graph is equal to the displacement of the object. The area of a triangle is equal to (1/2) * base * height. In this case, the base of the triangle is 25 seconds and the height is 20 m/s.

Therefore, the area of the triangle is (1/2) * 25 * 20 = 250 m^2.

The object is also moving in a positive direction for the next 10 seconds, but the velocity is constant at 20 m/s. Therefore, the area under the velocity graph for these 10 seconds is a rectangle with a base of 10 seconds and a height of 20 m/s.

The area of the rectangle is 10 * 20 = 200 m^2.

The total area under the velocity graph is 250 m^2 + 200 m^2 = 550 m^2. Therefore, the displacement of the object is 550 meters.

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Answer:  " 1.03 " .

____________________________________

Explanation:

_____________________________________

When we add "measured" or "obtained values" ; the rules for "signficant digits" (also known as "significant figures" ; or "sig figs")  are different from the rules we use when we multiply "measured or obtained values".

We are given 2 (two) "measured or obtained values" ; and we are asked to add these values together using the "significant digit rules.

In this case, we add up the "sum total value" of all the values—Not taking into account the number of significant figures.  Then, we take that "sum value" ; and we round that value to the number of "decimal places" that corresponds to the the number of decimals places in the "measured/obtained valued" that occurs in the value using to calculate the sum —the one that also happens to have the least number of significant digits among all the values used to calculate the "sum total".

As such:

_____________________________________

              1.0090 cm

+            0.02      cm          

      ________________    

           1.0290  cm.                                    

 →  Now, there were two (2) values used to calculate the "sum total" ;

1)  1.0090 cm ; which has 5 (five) significant digits.

2)  0.02 cm ;  which as 1 (one)  significant digits.

_____________________________________

 So, " 1" is less than "5" ;  so:  " 0.02" is the value within the calculations used to find the sum total — that has the "least" number of significant digits.    

  →  " 0.02 " ;  happens to have 2 (two) decimal spaces.

_____________________________________

So, we take the "sum total" :

      →   "  1.0290 cm " ;

      →  And round this number to:  " 2 (two) decimal places:

            → 1.029... ;  

      →  If the number after the second decimal place is from "1 to 4" ; we round down.  If the number after the second decimal place is

from "5 and 9" ; to round up.  Since the third decimal place is:  "9" ;

  [Note:  " 1.029.." ;  is between "5 to 9" } ; we round up:

→  The answer is:  " 1.03 " .

_____________________________________

Hope this is helpful to you!

     Wishing you the best!

_____________________________________

The apparent shift in measurement is called Parallax.

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.

Parallax is the apparent shift of an object's position relative to more distant background objects caused by a change in the observer's position.

In other words, parallax is a perspective effect of geometry.

The apparent shift of an observed object's position resulting from a change of perspective is called "parallax." With the previous demonstration, we've established an inverse relationship.

The closer the object, the greater the parallax angle. We can apply the same principle to the stars.

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The time needed is 25 s

Explanation:

Assuming that the sprinter is moving by uniform motion, then we can use the following equation that relates distance, time and speed:

[tex]v=\frac{d}{t}[/tex]

where

v is the speed of the sprinter

d is the distance covered

t is the time elapsed

In this problem, we know that

v = 4 m/s is the speed of the sprinter

d = 100 m is the distance that must be covered

Solving for t, we find the minimum time needed:

[tex]t=\frac{d}{v}=\frac{100}{4}=25 s[/tex]

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Answer:

1 ) density = 1200[kg/m^3]

2)

a) wide = 0.35[m]

long = 1,1 [m]

thick  = 0.015 [m]

b)

Volume = 0.005775[m^3]

mass = 15.6 [kg]

Explanation:

1)

This problem can be solved by knowing the definition of density which is expressed as the relation between mass and volume, so that the following equation can give us the density value.

[tex]density=\frac{m}{V}\\ where:\\m= mass [kg]\\V= volume [m^3]\\replacing\\density=\frac{90}{0.075} \\density=1200 [kg/m^3][/tex]

2)

The following data is equal to:

a)

wide = 35 [cm] = 0.35[m]

long = 11 [dm] = 11 [decimeters] = 1,1 [m]

thick = 15 [mm] = 0.015 [m]

b)

We know that density is the relationship between mass and volume of a body.

So the volume will be:

volume = wide * long * thick = (0.35*1.1*0.0015) = 0.005775[m^3]

[tex]the mass will be:\\m=density*volume\\m=2700[kg/m^3]*0.005775[m^3]\\m=15.6[kg][/tex]

Answer :

(1) The density of asphalt is, [tex]1200kg/m^3[/tex]

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

Part 1 :

As we are given:

Mass of block = 90 kg

Volume of block = [tex]0.075m^3[/tex]

Formula used :

[tex]\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}[/tex]

Now put all the given values in this formula, we get:

[tex]\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3[/tex]

Thus, the density of asphalt is, [tex]1200kg/m^3[/tex]

Part 2(a) :

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

Part 2(b) :

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

[tex]\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}[/tex]

[tex]2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}[/tex]

[tex]\text{Mass of aluminium}=15.59kg[/tex]

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

7000 Joules

We are given;

But, Force = mass × g (taking g as 10 N/kg)

Assuming we are given the distance moved by the object as 7 m

We can calculate the work done by the force

We need to know that;

Work done = Force × distance

Therefore;

Work done = 1000 N × 7 m

                   = 7000 Joules

Therefore, the work done by the force is 7000 Joules

Answer: D

Explanation:

A -amount of work

F-force

s-distance

If you keep same Force(F) and increase distance(s), amount of work will increase, according to:

A=F*s

Answer:

D) The amount of work will increase

Explanation:

Took test

Answer:

The different values are in the located in the word document

Explanation:

In the attached document in  word, we can find each of the conversion for each one of the quantities.

Answer: A (Incident ray).

Explanation:

Answer:

b. 40V , 40V

Explanation:

Connections are as per the figure.

As total current through source is 4A , current through each lamp is 1A.

As total resistance of the circuit is 10Ω ,resistance of each bulb is 40Ω because in case of a parallel circuit in which identical objects are connected , [tex]R_{eff} = \frac{R}{n}[/tex] where R is the resistance of each bulb and n is the number of bulbs.

As per Ohm's law , voltage of the source =IR = 4×10 =40V.

We can see from the figure that if the voltage across the source is 40V , the voltage across each bulb is also 40V.

Answer:

Explanation:

a )

mass m = 275 kg , final velocity v = 41 m/s

distance,  s = 49.3 m

acceleration a = ?

v² = u² + 2as

41² = 2 a x 49.3

a = 17.05 m/s²

time t = v - u / a

t = 41 / 17.05

= 2.4 s

b )

force = mass x acceleration

= 275 x 17.05

= 4688.75 N

c ) maximum range = v² / g

= 41²/9.8

= 171.5 m

height ( maximum )

v² sin²45 / 2g ( at angle of projectile of 45 , range and height is maximum.)

= 41²/ 2 x 9.8

= 85.76 m

d )

Let the angle be θ

height h = v² sin²θ / 2g

50 = 41² sin²θ /2g

sin²θ  = .58

sinθ = .76

50°.

Answer:

Horizontal acceleration=0

Explanation:

Horizontal Launching

When an object is launched horizontally at a certain speed [tex]v_o[/tex], only one force will be acting throughout the whole duration of the motion: the force of gravity. If no effect of the wind is to be considered, then the horizontal speed will not change over time. It means the horizontal acceleration is zero. Please note the vertical acceleration is not zero, it is in fact, the acceleration of gravity (0.8 m/sec^2)

Answer: 5.17 m

Explanation:

The football reaches its maximum height when the vertical component of the velocity is zero:

[tex]V_{y}=0 m/s[/tex]

This is exactly at the point where the football stops and then begins to fall thanks to the acceleration due gravity.

So, we can use the following equation:

[tex](V_{y})^{2}=(V_{oy})^{2}-2gy_{max}[/tex]

Where:

[tex]V_{y}=0[/tex] is the final velocity

[tex]V_{oy}=V_{o} sin(32\°)[/tex] is the vertical component of the initial velocity

[tex]V_{o}=19 m/s[/tex] is the initial velocity

[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

[tex]y_{max}[/tex] is the football's maximum height

Isolating [tex]y_{max}[/tex]:

[tex]y_{max}=\frac{(V_{o} sin(32\°))^{2}}{2g}[/tex]

[tex]y_{max}=\frac{(19 m/s sin(32\°))^{2}}{2(9.8 m/s^{2})}[/tex]

Finally:

[tex]y_{max}=5.17 m[/tex] This is the football's maximum height

Answer:

The acceleration of Mildred is, 1.33 m/s²  

Explanation:

Given data,

The initial velocity of Mildred, u = 12 m/s

The final velocity of Mildred, v = 8 m/s

The time period of travel, t = 3 s

The acceleration of Mildred,

                                   a = (v-u)/t

                                    a = (8 - 12) /3

                                       =  -4/3

                                       =  -1.33 m/s²

The negative sign indicates that the Mildred is decelerating.

Hence, the acceleration of Mildred is, 1.33 m/s²    

The law of inertia states that an object:

e. Will do all of the above.

Why?

Newton's First Law or the Law of inertia, states that an object at rest will always remain at rest if a force does not act on/upon it. Also, when an object is moving describing a straight line, if a force does not act upon it, it will keep the motion forever.

According to the Law, if an object is moving at constant velocity (same speed and same direction) it will keep the motion unless an outside force acts on it.

So, the correct option will be:

e. The object will do all of the above options.

Have a nice day!

The law of inertia states that an object at rest will remain at rest unless acted on by an outside force, while an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force.

The law of inertia, also known as Newton's first law of motion, states that an object at rest will remain at rest unless acted on by an outside force. Similarly, an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force. This law applies to all objects and is a fundamental principle in physics.

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Answer:

20N

Explanation:

10×2

Answer:

Answer:

20N

Explanation:

10×2

Answer:

E11. 0.6 N

E12. 1.61×10⁻⁴ N

E13. 1.12 N

E14. 45 lb

Explanation:

The force due to gravity between two objects is:

F = Gm₁m₂ / r²

where G is the gravitational constant,

m₁ and m₂ are the masses of the objects,

and r is the distance between them.

E11. At a distance r, the force is 9.6 N.

9.6 = Gm₁m₂ / r²

At quadruple the distance (4r), the force is:

F = Gm₁m₂ / (4r)²

F = Gm₁m₂ / (16r²)

F = 9.6 / 16

F = 0.6

E12. Given m₁ = m₂ = 700 kg, and r = 0.45 m:

F = Gm₁m₂ / r²

F = (6.67×10⁻¹¹ m³/kg/s²) (700 kg) (700 kg) / (0.45 m)²

F = 1.61×10⁻⁴ N

E13. At a distance r, the force is 0.28 N.

0.28 = Gm₁m₂ / r²

At half the distance (r/2), the force is:

F = Gm₁m₂ / (r/2)²

F = 4 Gm₁m₂ / r²

F = 4 (0.28)

F = 1.12

E14. The acceleration due to gravity on the Moon is 1/6 that of Earth's.  So an astronaut weighs 1/6 as much on the Moon.

W = 270 lb / 6

W = 45 lb

Answer:

20N option C

Explanation:

10× 2

Answer:

3 m/s

Explanation:

average  speed = distance traveled / total time taken

                           = 6m/ 2s

                           = 3 m/s

Answer:a??

Explanation:

Transition (A) from n=4 to n=1 by an electron will release the greatest amount of energy.

The fixed distances from an atom's nucleus where electrons may be found are referred to as energy levels (also known as electron shells). In an atom, the small, positively charged nucleus is surrounded by smaller, negatively charged electrons.

Energy levels resemble the rungs of a ladder in several ways. You cannot stand between the steps, only on one or the other. In the same way, electrons. They are able to occupy energy levels, but not the area between them.

In the given question there have four transitions of electron:

As for transition A; Δn = 4 -1 = 3 is the highest among the four  transitions of electron, transition from n=4 to n=1  by an electron will release the greatest amount of energy.

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Explanation:

V=40m/s

Vy=V.sina=40.sin20=40 . 0.342=13.68m/s

Vx=V.cosa=40.cos20=40 . 0.766=30.64m/s

Projectile travels during 5 seconds and the ramge becomes:

x=V.t=30.64 . 5=153.2m

The frequency of light changes when it is emitted from a moving source. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. In this case, the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz. Option a is correct.

The frequency of light changes when it is emitted from a moving source. This change in frequency is known as the Doppler effect. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. To calculate the new frequency, we can use the formula f' = f/(1+v/c), where f' is the observed frequency, f is the emitted frequency, v is the speed of the galaxy, and c is the speed of light.

In this case, the galaxy is moving away from Earth with a speed of 3325 km/s. The emitted frequency is 5.00 * 10^14 Hz. Plugging these values into the formula, we get f' = 5.00 * 10^14 Hz / (1 + 3325 km/s / 3 * 10^5 km/s). Simplifying this expression, we find that the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz.

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A) 4.945 x [tex]10^{14}[/tex] Hz is correct option. Using the Doppler effect formula, we calculate the observed frequency of the light from a galaxy receding at 3325 km/s.

To determine the frequency of light from a receding galaxy as observed on Earth, we use the Doppler effect formula for light:

[tex]f_{obs}[/tex] = [tex]f_{em}[/tex] x (1 - v/c)

Where:

Let’s substitute the values into the formula:

[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 3325000 m/s / 3.00 x [tex]10^{8}[/tex] m/s)

[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 0.01108333)

[tex]f_{obs}[/tex] ≈ 4.945 x [tex]10^{14}[/tex] Hz

Therefore, the frequency of the light observed on Earth is 4.945 x [tex]10^{14}[/tex] Hz.

Answer:

Distance-           The length along a path between two points .

Velocity-            The rate and direction at which an object moves .

Displacement-  The net change in position of an object .

Vector-               A measurement that has both magnitude and direction .

Speed-               Measure of the rate at which an object changes position .

Momentum-      The mass of an object multiplied by its velocity.

Explanation:

Vector: A physical quantity having both magnitude and direction is called Vector quantity. Example: Displacement, Velocity, Acceleration, Force etc.

On the other hand , quantity having only magnitude is called Scalar. Example: Distance, Speed, Time, Current etc.

Distance: The totle length of path traversed by a body in certain time is called distance. It is scalar quantity as it has only magnitude. SI unit of distance is meter.

Displacement: It is defined as change in position of a body in given period of time. Actually it is the distance between initial and final position along with given direction. So it is vector quantity. SI unit is meter.

Speed: The rate at which distance is traveled with respect to time is called speed.It is scalar quantity. SI unit is meter/second.

                                    [tex]Speed=\frac{Distance}{Time}[/tex]

Velocity: It can be defined as rate of change in position or displacement with respect to time.It is vector quantity. SI unit is meter/second.

                                    [tex]Velocity=\frac{Displacement}{Time}[/tex]

Momentum: The amount of motion contain in a body is the momentum. It is defined as product of mass and velocity. It is vector quantity. SI unit is kg.meter/second

                                    Momentum=Mass×Velocity

Answer: The answer above is correct! I got 100% :))

Explanation: