Chemistry High School

How much HCl is produced from the reaction of an excess of HSbCl4 with 3 moles H2S in the following reaction? HSbCl4 + H2S → Sb2S3 + HCl (Remember to balance the equation.)

Answers

Answer 1

Answer:

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Explanation:

Step 1: Data given

Number moles of H2S = 3.0 moles

Step 2: The balanced equation

2HSbCl4 + 3H2S → Sb2S3 + 8HCl

Step 3: Calculate moles HCl

For 2 moles HSbCl4 we need 3 moles H2S to produce 1mol Sb2S3 and 8 moles HCl

For 3.0 moles H2S we'll have 8.0 moles HCl

Step 4: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 8.0 moles * 36.46 g/mol

Mass HCl = 291.7 grams

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Answer 2
Final answer:

From the balanced equation, it is determined that 2 moles of HCl are produced from 1 mole of HSbCl4. Therefore, 6 moles of HCl will be produced from the reaction of an excess of HSbCl4 with 3 moles of H2S.

Explanation:

The balanced equation for the reaction is:

HSbCl4 + H2S → Sb2S3 + 2HCl

The mole ratio between HSbCl4 and HCl is 1:2, which means that for every 1 mole of HSbCl4, 2 moles of HCl are produced.

Since there is an excess of HSbCl4, we can assume that all 3 moles of H2S will react.

Therefore, the number of moles of HCl produced will be:

(3 moles H2S) x (2 moles HCl/1 mole HSbCl4) = 6 moles HCl

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