how many moles of co2 will be produced from 72.0 g of ch4 assuming o2 is available in excess

Answer: 1. Vinegar, used in the kitchen, is a liquid containing 3-6% acetic acid. It is used in pickles and in many food preparations.

2. Lemon and orange juice contains citric acid. Citric acid is used in the preparation of effervescent salts and as a food preservative.

3. Acids have been put to many uses in industry. Nitric acid and sulphuric acid are used in the manufacture of fertilizers, dyes, paints, drugs and explosives.

4. Sulphuric acid is used in batteries, which are used in cars, etc. Tannic acid is used in the manufacture of ink and leather.

5. Hydrochloric acid is used to make aqua regia, which is used to dissolve noble metals such as gold and platinum.

6. Sulphuric acid is used in manufacturing fertilizers such as super phosphate, ammonium sulpahte etc.

Answer:

C3H7COOCH3 + H2O/H^+ --------> C3H7COOH + CH3OH

Explanation:

The acid hydrolysis of methyl butanoate is formed by the addition of water and thereby breaking Ester bond to form an alcohol and a carboxylic acid.

C3H7COOCH3 + H2O/H^+--------> C3H7COOH + CH3OH

The true statement about diffusion  is b. Molecules will move from high to low concentration until equilibrium is reached.

Molecules diffuse passively, moving from high-concentration regions to low-concentration regions without the requirement for external energy input.This motion continues until the system reaches equilibrium, at which point the concentration of molecules is uniform throughout. It's vital to remember that diffusion, which is caused by the random movement of particles, does not require a transport protein.

Option b, which highlights the movement of molecules from high to low concentration until a condition of equilibrium is reached, therefore appropriately captures a feature of diffusion.

complete question;

Which of the following is true of diffusion?

a. It requires energy.

b. Molecules will move from high to low concentration until equilibrium is reached.

c. It is a transport mechanism that requires a transport protein.

d. All of the above.

Answer:

Hg(NO₃)₂(aq) + Na₂SO₄(aq)   →   2NaNO₃(aq) + HgSO₄(s)

Moles of Hg(NO₃)₂ = 55.42 / 324.7 ==> 0.1707 moles

Moles of Na₂SO₄ = 16.642 / 142.04 ==> 0.1172 moles

Limiting reagent is Na₂SO₄ as it controls product formation

Moles of HgSO₄ formed = 0.1172 moles

                                        = 0.1172 x 296.65

                                        = 34.757g

Explanation:

Answer:

They expressed it as rate of change in concentration of reactants or products in a chemical reaction

The rate of a chemical reaction can be expressed in the terms of the increase in the concentration of product or decrease in the concentration of reactants with time.

The rate of reaction can be defined as the speed at which the products are formed from the reactants in the reaction. The rate of the chemical reaction offers information on how much the time reaction will be completed.

The rate of reaction can be defined as the speed of a reaction at which reactants are transformed into products. Some reactions are instantaneous, while some reactions take time to reach the final equilibrium.

A catalyst can be defined as a substance that enhances the rate of the reaction without going under any change in the reaction.  

Rates of reaction are expressed as the concentration of reactant used or the concentration of product produced per unit of time. The units of rates are mol per liter or mol/L.

Learn more about the rate of reaction, here:

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Answer:

1

Explanation:

Its periodic number is 1.

Answer:

There are 1 plus that is the periodic number

Answer:

or all desendants of a common ancestor

2. A period is a name given to the horizontal row of the periodic table.

3.

a.mg

b.k

c.Fe

d.cu

e.Al

4.

a.Carbon

b.Chlorine

c.Gold

d.strontium

5.

a.period 1

b.period 4

c.period 5

d.period 5

6.

a.group 6

b.group 2

c.group 7

d.group 8 belong ti 1st transitional elements.

7.

a.F

b.Na

c.Ar

d.V

e.I

This answer provides definitions for chemical families (groups) and periods, symbol and name identification for a number of elements, their period and group placements within the Periodic Table, and examples of atoms of different types.

1. In chemistry, a Family is a column of elements in the Periodic Table. They are also known as Groups and share similar chemical behavior.

2. A period in the Periodic Table is a horizontal row of elements. Each new row (or Period) signifies a new energy level in the atom's electrons.

3. The symbols for the elements are:
a. Magnesium - Mg
b. Potassium - K
c. Iron - Fe
d. Copper - Cu
e. Aluminum - Al

4. The names of the elements:
a. C - Carbon
b. Cl - Chlorine
c. Au - Gold
d. Sr - Strontium

5. The periods for the elements:
a. He (Helium) - Period 1
b. Ge (Germanium) - Period 4
c. Rb (Rubidium) - Period 5
d. I (Iodine) - Period 5

6. The groups for the elements:
a. Sulfur - Group 16
b. Ca (Calcium) - Group 2
c. Iodine - Group 17
d. Fe (Iron) - Group 8 (In the transition metals)

7. Examples of atoms based on characteristics:
a. Halogen - Fluorine(F)
b. Alkali metal - Sodium(Na)
c. Noble gas - Neon(Ne)
d. Transition metal - Iron(Fe)
e. Nonmetal - Oxygen(O)

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Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

There are two half lives in 20 years because 20 ÷ 10 = 2.

So, we divide the 100g sample in half 2 times.

100 ÷ 2 = 50

50 ÷ 2 = 25

There will be 25g of the radioactive sample remaining after two half lives.

Hope this helps!

C12H208 is the molecular formula of the alcohol.

Explanation:

The weight of carbon given is 26.05 grams

The weight of H20 = 6.630 grams

first let us find the number of moles of:

number of moles = weight given ÷ mass of 1 mole of the element

                              = 26.05 ÷ 12

                               =  2.170 moles of carbon

number of moles of hydrogen present in H2O

    =  6.630 ÷ 18

     = 0.368

1 mole of water contains 2 mole of hydrogen so, 2 × 0.368 grams

= 0.7366 moles

Number of moles of oxygen cannot be calculated as of now.

So from the data obtained,

50 gms C2H2Ox is combusted.

Lets, calculate the gms from moles using the same equation

For carbon, 2.170 × 12

             = 26.04 grams

For hydrogen, 0.368 × 1.01

              =  0.3716 grams

adding the carbon and hydrogen content, 26.04 grams

now the oxygen content can be obtained by

50 - 26.04

= 23.96 grams

Now moles of oxygen calculated as

n = 23.96 ÷ 16

  = 1.49 moles of oxygen

The emperical formula for the alcohol is C6H04

now the molar mass is divided by emperial formula mass.

molar mass = 189 amu

emperial formula mass = 137

the division would give= 1.37

it can be taken as 2

The subscript in the formula is multiplied by 2 to get molecular formula from emperial formula.

So, C12H208 is the molecular formula of the alcohol.

One mole of Ca equals approximately 6.022 x [tex]10^2^3[/tex] atoms, which is the value of Avogadro's number.

One mole of an element is defined as having the same number of atoms as there are in 12 grams of the 12C isotope of carbon. This number is known as Avogadro's number, and it is approximately 6.022 x [tex]10^2^3[/tex] particles. In the case of calcium (Ca), one mole of Ca would equal to roughly 6.022 x [tex]10^2^3[/tex] calcium atoms.

The concept of the mole is fundamental in chemistry for quantifying the amount of substance. Whenever we mention one mole of any element, we are referring to 6.022 x [tex]10^2^3[/tex] atoms of that element, whether it's carbon, calcium, or any other element.

339 grams of CLF3 is formed when F2 is in excess and 130 grams of CL2 reacts.

Explanation:

The balanced chemical reaction for the formation of ClF3 is given by:

[tex]Cl_{2}[/tex] + 3 [tex]F_{2}[/tex] ⇒ 2 Cl[tex]F_{3}[/tex]

the mass of Cl2 is given 130 grams

From the equation it is found that 2 moles of chloride reacts to form 2 moles of ClF3.

calculating the number of moles of chlorine by the formula:

Number of moles = mass of the substance ÷ atomic mass of one mole of the substance

n = 130 ÷ 35.45

   = 3.6671 moles

So, applying stoichiometry

2 moles of Cl2 formed 2 moles of ClF3

3.6671 moles of Cl2 will form x moles of ClF3

2 ÷ 2 = x ÷ 3.6671

x = 3.6671 moles of ClF3

now from the formula of number of moles

weight is calculated as n × mass of the gas

                                    3.6671 × 92.448

                                    =  339.01 grams of ClF3 is formed.

Answer:

This is a popular question because it is important. You have 2 Major kinds of substances, or compounds, ionic, and covalent. Covalent compounds usually do not “break apart” in solution, (in fact you have to try and find the right ones to do this), BUT, the IONIC compounds, like salts, held together by their opposite charges do tend to separate in solution.

Take NaCl, sodium chloride. Add waster, and you get Na+ and Cl-. Now if we add methanol, a poisonous alcohol, it simply remains together as it is diluted in water. It is a Covalent compound, where all of the atoms of CH3OH share their electrons, which is very different than being held together by opposite charges.

Explanation:

Final answer:

Ionic compounds create more solute particles in a solution compared to covalent compounds, as they dissociate into individual ions, resulting in a greater effect on colligative properties.

Explanation:

When comparing whether ionic compounds or covalent compounds create more solute particles in a solution, it is important to understand how each type of compound dissolves. Ionic compounds, when dissolved, dissociate into their constituent ions. For example, NaCl separates into Na+ ions and Cl- ions, doubling the number of particles in solution. On the other hand, covalent compounds, such as glucose, do not dissociate but rather separate into individual molecules in solution. Therefore, ionic compounds generally produce a larger number of dissolved particles and have a greater effect on colligative properties such as boiling point and freezing point of the solution.

Colligative properties are directly related to the number of solute particles in a solution. Since ionic compounds provide more solute particles due to dissociation, they significantly alter colligative properties compared to an equal amount of moles of a covalent compound. This is a crucial concept when analyzing the impact of different solutes on solutions.

Answer:

Increase the turns of the wire

Explanation:

By increasing the number of turns the wire has made, you are increase the inductive power of the coil in the generator, thereby giving rise to the output of the generator.

Answer:

C. 4.00 K

Explanation:

We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:

V1 / T1= V2 / T2

50ml / 20K = 10ml / T2

T2= 10ml/ 50ml * 20K

T2= 4K

Final answer:

The new temperature of the gas, when compressed from 50.0 mL to 10.0 mL under constant pressure, will be 4.00 K, following Charles's Law which relates temperature and volume of a gas under constant pressure.

Explanation:

The question involves the concept of how the volume of a gas changes with temperature, under constant pressure, following Charles's Law. This law states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is kept constant. Given that the volume of a gas is 50.0 mL at 20.0 K and the volume is compressed to 10.0 mL under constant pressure, we want to find the new temperature. Applying Charles's Law, we set up the proportion (V1/T1) = (V2/T2) where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

To solve for T2, we rearrange the formula to T2 = (V2/V1) * T1. Substituting the given values, T2 = (10.0 mL / 50.0 mL) * 20.0 K = 4.00 K. Therefore, the new temperature of the gas, when compressed to 10.0 mL under constant pressure, will be 4.00 K.

Answer:

thin

Explanation:

Answer:

very thin

Explanation:

the atmosphere is actually very thin compared to the size of the earth.

By stirring and increasing temperature, there is an increase in dissolving capacity of the solid solute.

Explanation:

If a solute is added to the solution, it doesn't get dissolve easily then we have to increase the temperature, which in turn increases the movement of the solvent (may be water) and the solute particles, thus increases the dissolving power of the solid solute. One more way is by constant stirring, that is by making more contact among the solvent as well as the solute particles there by increasing the solubility of solid solute.

Answer:Orbits

Explanation:All planets orbit around the sun at different speeds, directions, and time. Making it impossible to see all planets on any given time

Answer:

B) Orbits

Explanation:

got it right

Answer: meteorological phenomenon

Explanation: Hello, there! A rainbow is a meteorological phenomenon that is caused by reflection, refraction and dispersion of light in water droplets resulting in a spectrum of light appearing in the sky. It takes the form of a multicoloured circular arc. Rainbows caused by sunlight always appear in the section of sky directly opposite the sun.

I hoped i help and im here for any more questions you might have! thankyou!

Answer:

4. 273 K and 373K.

Explanation:

Conversion from Celsius to Kelvin ..

Kelvin = Celsius + 273

HCl Acid + Sodium Hydroxide ----> Sodium  Chloride + water.

Explanation:

                             HCl + NaOH → NaCl + H2O + Heat

Answer:

2000 years

Explanation:

A radioactive molecule will continuously decay and turn into another molecule. This nature of the radioactive molecule makes them can be used to estimate the age of an object. Half-life is the unit of time needed for radioactive molecules to decay to half of its mass. The formula for the mass remaining will be:

[tex]N(t)= N_{0} (\frac{1}{2})^{\frac{t}{t_{1/2} } }[/tex]

Where

N(t)= number of the molecule remains

N0= number of molecule initially

t= time elapsed

t1/2= half time

We have all variable besides the half time, the calculation will be:

[tex]N(t)= N_{0} (\frac{1}{2})^{\frac{t}{t_{1/2} } }[/tex]

[tex]0.125= 1 (\frac{1}{2})^{\frac{6000}{t_{1/2} } }[/tex]

[tex](\frac{1}{8})= (\frac{1}{2})^{\frac{6000}{t_{1/2} } }[/tex]

[tex](\frac{1}{2})^3= (\frac{1}{2})^{\frac{6000}{t_{1/2} } }[/tex]

3= 6000/ (t1/2)

t1/2= 6000/3= 2000

The half-life is 2000 years

The specific heat of the unknown metal is approximately 0.36 J/g°C.

First, let's identify the variables given in the problem:

- Mass of the unknown metal (m1) = 50g

- Initial temperature of the metal (T1) = 100.0°C

- Mass of water (m2) = 150g

- Initial temperature of water (T2) = 20.0°C

- Final temperature of the metal and water ([tex]T_f[/tex]) = 23.3°C

To find the specific heat of the metal, we can use the formula:

[tex]\[ q = m \times c \times ΔT \][/tex]

Where:

- ( q ) is the heat absorbed or released

- ( m ) is the mass of the substance (either the metal or water in this case)

- ( c ) is the specific heat capacity of the substance

- ( ΔT ) is the change in temperature

First, we'll find the heat absorbed by the metal using the above formula:

[tex]\[ q_{\text{metal}} = m_{\text{metal}} \times c_{\text{metal}} \times ΔT_{\text{metal}} \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (T_f - T_1) \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (23.3°C - 100.0°C) \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (-76.7°C) \][/tex]

Next, we'll find the heat released by the water as it cools down:

[tex]\[ q_{\text{water}} = m_{\text{water}} \times c_{\text{water}} \times ΔT_{\text{water}} \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times (T_f - T_2) \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times (23.3°C - 20.0°C) \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times 3.3°C \][/tex]

Since the heat lost by the metal equals the heat gained by the water (assuming no heat is lost to the surroundings):

[tex]\[ q_{\text{metal}} = q_{\text{water}} \]\[ 50g \times c_{\text{metal}} \times (-76.7°C) = 150g \times 4.18 J/g°C \times 3.3°C \][/tex]

Now, solve for [tex]\( c_{\text{metal}} \):[/tex]

[tex]\[ c_{\text{metal}} = \frac{150g \times 4.18 J/g°C \times 3.3°C}{50g \times (-76.7°C)} \]\[ c_{\text{metal}} = \frac{2085.3 J}{-3835 J} \]\[ c_{\text{metal}} ≈ 0.36 J/g°C \][/tex]

So, the specific heat of the unknown metal is approximately 0.36 J/g°C.

Complete Question:

50g of an unknown metal at 100.0 degrees celsius is placed into 150g of water at 20.0 degrees Celsius and the final temperature of the metal and water is 23.3 degrees Celsius. What is the specific heat of the metal?

The specific heat of the metal is approximately [tex]\( 0.527 \, \text{J/g}^\circ \text{C} \)[/tex].

For the metal:

[tex]\[ q_{\text{metal}} = m_{\text{metal}} \cdot c_{\text{metal}} \cdot \Delta T_{\text{metal}} \][/tex]

where[tex]\( q_{\text{metal}} \)[/tex] is the heat lost by the metal, \( m_{\text{metal}} \) is the mass of the metal, [tex]\( c_{\text{metal}} \)[/tex] is the specific heat capacity of the metal, and \( \Delta T_{\text{metal}} \) is the change in temperature of the metal.

 For the water:

[tex]\[ q_{\text{water}} = m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}} \][/tex]

where [tex]\( q_{\text{water}} \)[/tex] is the heat gained by the water, [tex]\( m_{\text{water}} \)[/tex] is the mass of the water, [tex]\( c_{\text{water}} \)[/tex] is the specific heat capacity of water (which is approximately [tex]\( 4.184 \, \text{J/g}^\circ \text{C} \))[/tex], and [tex]\( \Delta T_{\text{water}} \)[/tex] is the change in temperature of the water.

Since the heat lost by the metal is equal to the heat gained by the water, we have:

[tex]\[ q_{\text{metal}} = -q_{\text{water}} \][/tex]

Substituting the expressions for [tex]\( q_{\text{metal}} \)[/tex] and [tex]\( q_{\text{water}} \)[/tex] into this equation gives us:

[tex]\[ m_{\text{metal}} \cdot c_{\text{metal}} \cdot \Delta T_{\text{metal}} = -m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}} \][/tex]

Now we can plug in the known values:

[tex]\[ 50 \, \text{g} \cdot c_{\text{metal}} \cdot (23.3^\circ \text{C} - 100.0^\circ \text{C}) = -150 \, \text{g} \cdot 4.184 \, \text{J/g}^\circ \text{C} \cdot (23.3^\circ \text{C} - 20.0^\circ \text{C}) \][/tex]

Solving for [tex]\( c_{\text{metal}} \)[/tex]:

[tex]\[ 50 \cdot c_{\text{metal}} \cdot (-76.7) = -150 \cdot 4.184 \cdot 3.3 \] \[ c_{\text{metal}} = \frac{-150 \cdot 4.184 \cdot 3.3}{50 \cdot (-76.7)} \] \[ c_{\text{metal}} = \frac{-2020.2}{-3835} \] \[ c_{\text{metal}} \approx 0.527 \, \text{J/g}^\circ \text{C} \][/tex]

The answer is: 0.527 \,[tex]\text{J/g}^\circ \text{C}[/tex]"

Answer:

its lavered structure

Explanation:

Final answer:

The atmosphere acts as a system in how it manifests global wind patterns which are influenced by atmospheric pressure gradients, the rotation of the Earth, and thermal energy. The Coriolis effect and thermal activity generate geographically significant wind patterns like the trade winds. Global warming may induce alterations in these patterns.

Explanation:

Global Wind Patterns as an Atmospheric System

The earth's atmosphere behaves as a dynamic system, particularly evident through global wind patterns. These patterns are driven by complexities such as atmospheric pressure gradients, the rotation of the Earth, and thermal energy from the Sun. The resulting movement of air in response to these factors is what we call 'wind.'

For instance, in the northern hemisphere, air moves into a low-pressure region and is deflected to the right due to the Coriolis force, creating counterclockwise circulation. On the other hand, air moving away from high-pressure areas is deflected in a rightward motion as well, but this results in a clockwise circulation. The combination of rising and sinking air due to thermal activity and the Coriolis effect generates trade winds, which are essential in the global transfer of heat and moisture, impacting global climate and weather systems.

Additionally, global warming could significantly alter these atmospheric circulation patterns, potentially leading to changes in weather systems, like the distribution of precipitation and the intensity and frequency of storms.

Answer:

Ecosystem :

Any living organism interacting with its physical environment by any means is known as Ecosystem.

Ecology :

Ecology is the study of the ecosystem. In this field of biology, we study how an organism interact with its physical environment and how the environment respond.

Answer:

Atom are single neutral particles.Molecule are neutral particles made of two or more atom bonded together.

Answer:

For the first one it is C

Explanation:

Answer:

answer is: constant , direct solar radiation as the ocean influences weather and climate by storing solar radiation, distributing heat and moisture around the globe, and driving weather systems.

The Coriolis effect is the apparent curvature of global winds, ocean currents, and everything else that moves freely across the Earth's surface. The curvature is due to the rotation of the Earth on its axis. The effect was discovered by the nineteenth century French engineer Gaspard C.

Answer:

Explanation:

Potassium trioxonitrate(V) is KNO₃.

1. Find the molar mass of the solute

The molar mass of KNO₃ is 39.098g/mol + 14.007g/mol + 3×15.999g/mol = 101.102g/mol.

2. Convert the mass of solute, 20.02g, into number of moles

3. Assume that the volume of the solution is equal to the volume of water

This is a rough approximation, but it is necessary since you do not have the density of the solution:

Convert 100cm³ to dm³:

4. Calculate the solubility is mol/dm³

It is rounded to three significant digits to match the choices.

Final answer:

The solubility of potassium trioxonitrate(V) in water at room temperature is 2 mol/dm³, calculated by dividing the moles of the dissolved substance by the volume of the solvent in liters.

Explanation:

To calculate the solubility of potassium trioxonitrate(V), which is potassium nitrate (KNO3), we first need to find the molar mass of KNO3 to convert the given mass to moles. Potassium (K) has an atomic mass of approximately 39 g/mol, nitrogen (N) has an atomic mass of approximately 14 g/mol, and oxygen (O) has an atomic mass of approximately 16 g/mol. Therefore, the molar mass of KNO3 is 39 + 14 + (3 × 16) = 101 g/mol. Now, we take the mass of KNO3, 20.2 g, and divide it by its molar mass to find the number of moles:

Number of moles of KNO3 = 20.2 g / 101 g/mol = 0.2 mol

Since the solvent water has a mass of 100 g, and knowing that the density of water is approximately 1 g/cm³, we can assume that the volume of 100 g of water is approximately 100 mL or 0.1 L. Thus, the solubility of KNO3 in mol/dm³ can be calculated as:

Solubility = Number of moles / Volume in L = 0.2 mol / 0.1 L = 2 mol/dm³

Answer:

0.410

Explanation:

Rounding 0.41006 gram to three significant figures results in 0.410 g.

To express the measurement 0.41006 gram rounded to three significant figures. When rounding to significant figures, we look at the digits from the left and count the first non-zero digit and the following digits up to the desired number of figures.

Here, the first three significant figures are 4, 1, and 0 (since this zero comes after a non-zero digit and before another non-zero digit, it counts as significant). Therefore, rounding 0.41006 to three significant figures gives us 0.410 g.

Answer:

See below

Explanation:

Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters

=> Grams of solute = Molarity x Vol in Liters x formula wt

= (0.250M)(0.750L)(212.3g/mol)

= 39.8 grams

Final answer:

To find the mass of K3PO4 in a 0.250 M solution with a volume of 750.0 mL, calculate the number of moles and then multiply by the molar mass, resulting in 39.8 grams.

Explanation:

To calculate the mass of K3PO4 in a 0.250 M solution with a volume of 750.0 mL, we need to follow these steps:

Therefore, there are 39.8 grams of K3PO4 in 750.0 mL of a 0.250 M solution.

Answer:

The new pressure is 1,65 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.

(P1xV1)/T1= (P2xV2)/T2

(1,23atmx 8,46L)/267 K = (P2 x 6,98L)/ 295K

0,039 atmx L/K = (P2 x 6,98L)/ 295K

P2=(0,039 atmx L/K)x 295K/6,98L =1,65 atm