how does the movement of electrons create an electric charge?

The gravity is described by an attractive force, non-contact force and vertical force. Thus, options (a), (c) and (f) are correct.

The gravity is an attractive force that acts between the objects or particles kept on the of Earth and the Earth itself. The force is proportional to the product of masses of particles/objects and Earth. Since, the earth carry more mass, therefore, all objects are attracted towards the centre of Earth.

Thus, we can conclude that gravity is described by an attractive force, non-contact force and vertical force.

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Answer:

(a) Attractive Force.

(c) Non-contact force.

(f) A vertical force.

The equation that is applicable to this problem is expressed as 

p = γmu 

where p is the relativistic momentum, m is equal to the proton mass and u is the speed of proton. γ is equal to 1/√(1 - u²/c²) where c is the speed of light. 

Another equation to determine p fully is to use this relativistic equation:
E = γmc² 

where E is the total kinetic energy including the gamma energy.

We are given with E = 2.7 × 10^(-10) J and from a proton’s data, mc^2 = 938.27201 MeV. Using the conversion from MeV to J which is 1 eV = 1.60218 * 10^(-19) J, we compute for γ

γ=E/mc^2 =2.7 × 10^(-10) J / 938.27201x10^6 eV *(1.60218 * 10^(-19) J/eV) = 1.80

we use this number to determine u from the second equation γ = 1/√(1 - u²/c²)

we square both sides and cross multiply, resulting to
γ² (1 - u²/c²) = 1 

u²/c² = (γ² -1)/γ² 

u = c/y sq rt of (γ² -1)

u = 0.83

Substituting eventually to the first equation, we get

p = γmu 

p = 1.80 * 1.67262 * 10^(-27) kg * 0.83 * 2.99792 * 10^8 m/s 

p = 7.481 * 10^(-19) kg.m/s

To calculate time it takes the car to travel 45 miles at a speed of 60 mph, you use the formula time = distance/speed. When you plug in the values, you get 0.75 hours or 45 min.

To calculate the time it takes for a car to travel a certain distance at a specific speed, we use the formula time = distance/speed. Here, the distance is 45 miles and the speed is 60 mph. So it's time = distance/speed = 45 miles / 60 mph = 0.75 hours. Therefore, the car takes 0.75 hours or 45 min to travel 45 miles at a speed of 60 mph.

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Answer:

Explanation:

In the image attached you can observe where is the parallax angle placed.

Now, this parallax angle is inversely proportional to the distance measured in parsecs. That means, the greater the distance, the smaller the parallax angle.

Mathematically, it's defined as

[tex]D=\frac{1}{p}[/tex]

Where [tex]D=12.5 pc[/tex], replacing this value, we have

[tex]D=\frac{1}{p}\\p=\frac{1}{D}=\frac{1}{12.5 pc} =0.08''[/tex]

Therefore, the parallax angle is 0.08 seconds of arc.

Answer:

Speed with which it strike the water = 36.66 m/s

Explanation:

Horizontal component of velocity = 18 m/s

We need to find vertical component of velocity.

Considering vertical motion of stone

Initial velocity, u =  0 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 52 m

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    v² = 0² + 2 x 9.81 x 52

    v = 31.94 m/s

Vertical component of velocity = 31.94 m/s

[tex]\texttt{Total velocity = }\\\\\sqrt{\texttt{Horizontal component of velocity}^2+\texttt{Vertical component of velocity}^2}\\\\\texttt{Total velocity = }\sqrt{18^2+31.94^2}=36.66m/s[/tex]

Speed with which it strike the water = 36.66 m/s

If a person standing at the edge of a seaside cliff kicks a stone over the edge, the speed with which the stone strike the water is 36.65 m/s.

Given the following data:

We know that acceleration due to gravity (a) is equal to 9.8 meter per seconds square.

First of all, we would determine the vertical component of the velocity by using the third equation of motion;

[tex]V^2 = U^2 + 2aS[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]V^2 = 0^2 + 2(9.8)(52)\\\\V^2 = 0 + 1038.2\\\\V = \sqrt{1019.2}[/tex]

Vertical component of velocity = 31.92 m/s

To find the speed with which the stone strike the water, we would calculate the resultant speed by doing a vector addition of the horizontal component of the velocity and the vertical component of the velocity;

[tex]Speed = \sqrt{H^2 + V^2} \\\\Speed = \sqrt{18^2 + 31.92^2}\\\\Speed = \sqrt{324 + 1019.2}\\\\Speed = \sqrt{1343.2}[/tex]

Speed = 36.65 m/s

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Answer:

If the speed would be doubled, the distance traveled by the vehicle will be FOUR times. It can be proved by 3rd equation of motion.

Explanation:

When the brakes are applied, frictional force acts on the tires which decreases the speed. Eventually the car will stop. This frictional force is nearly independent of the speed hence by applying 3rd equation of motion, we can find the distance traveled.

2aS = Vf²-Vi²

[tex]S=\frac{Vf^{2}-Vi^{2}}{2a}[/tex]

For Vf=0

S=-Vi²/2a

Vi-new = 2*Vi

S-new = -(Vi-new)²/2a

S-new = -(2*Vi)²/2a

S-new = -4Vi²/2a

S-new = 4.S

Here

Vf= Final Velocity i.e. 0m/s²

Vi= Initial Velocity

a= Deceleration (Negative Acceleration)

S= Distance covered by vehicle

Explanation:

Capacitance of a capacitor is defined as the amount of charge stored per unit voltage. Capacitor is a device that is used to store electric charge. Its mathematical term is given by :

[tex]C=\dfrac{Q}{V}[/tex]

Q is the amount of charge

V is the voltage or potential difference

Its SI unit is farad. It consist of two conducting plates that are separated by an insulating material. If A is the cross sectional area of each of the plates that are separated by a distance d. Then capacitance is given by :

[tex]C=\dfrac{A\epsilon_o}{d}[/tex]

[tex]\epsilon_o[/tex] is the permittivity of the free space

Answer:

500 Yards or 457.2 Meters

Explanation:

The waves created behind a boat because of its movement in the water is called as "Wake". More the speed of the vessel, more severe is the wake.The speed at which the boat will be able to move and navigate but will not be creating wake is known as  "Slow - No Wake"  speed. As per Homeland Security restrictions, any vessel must slow down to "slow-no wake" within 500 yards of any US Naval Vessel.

The time it took for the car to stop, given an acceleration of -5.00 m/s^2 and a distance of 15.0 m, is approximately 2.45 seconds.

The subject of this question is physics, more specifically the concept of acceleration. Given the car's acceleration is -5.00 m/s^2 (negative because it is slowing down) and it traveled a distance of 15.0 m, we can use the equation of motion to find the time it took for the car to stop. The equation that suits this situation best is d = ut + 0.5at^2. In this case, the initial velocity (u) is what we need to find first.

Assuming that the acceleration was constant, we can apply the third equation of motion:  

v^2 = u^2 + 2as  

We have v (final velocity) = 0 m/s (since the car stops), a = -5.00 m/s^2, and s = 15.0 m. Solving this equation for u (initial velocity) gives u = sqrt(v^2 - 2as) = sqrt(0 - 2 * -5 * 15) = sqrt(150) = ~12.25 m/s. Using this initial velocity value, we can now find the time it took for the car to stop using the first equation of motion (v = u + at). We know v = 0, u = ~12.25 m/s, and a = -5.00 m/s^2. Solving this for time (t), we have t = (v - u) / a = (0 - 12.25) / -5 = ~2.45 seconds.

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Answer:

A

Explanation:

Because its the answer I got on a certain learning site

Answer:

D). Newton's First Law of Motion

Explanation:

This is the explanation of Newton's First law or Law of inertia.

As per this law if there is no unbalanced force on a system then they system will always maintain its state of motion.

Or in other words we can say that if there is no force then the object will always maintain its state of motion i.e. if object is in motion then it will continue in motion and if object is in rest then it will continue at rest

So here when bike immediately stops then due to this law our body will continue its state and move off from the bike and fly away on the ground at some distance away.

So here correct answer will be

D).  Newton's First Law of Motion

Answer:

Grounded

Explanation:

Three wires are use while wiring and even in appliances. They are live, neutral and earthing wire.

Grounding or earthing is the process through which we safeguard us from electric shock.

The earthing wire is directly connected to a box buried in ground at certain level So any kind of leakage current that can cause shock will directly pass to the ground making equipment and humans safe.

Slow-moving vehicles should not travel on expressways or roads with a speed limit greater than 45 mph and they should utilize the rightmost lane on divided highways.

Slow-moving vehicles are generally prohibited from traveling on expressways or on roadways with a minimum posted speed limit greater than 45 miles per hour. This ensures safety as slow-moving vehicles can create dangerous situations if the flow of traffic is substantially faster. On divided highways, there is typically more than one lane for each direction of travel. Slow-moving vehicles are advised to use the rightmost lane, often referred to as the slow lane. This is because the left lane is usually reserved for faster vehicles and passing. Drivers in right lanes at slower speeds have an easier time allowing faster vehicles, which generally use left lanes, to pass safely.

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To answer this problem, we have to define the two energies, Potential and Kinetic Energy.

Initially when the child is at rest at 52.1 cm, the potential energy PE is at its highest.

PE = m g h

Where,

m = total mass = 14.8 kg + 1.30 kg = 16.10 kg

g = gravitational acceleration = 9.8 m /s^2

 h = height = 52.1 cm = 0.521 m

Computing for PE:

PE = 16.10 * 9.8 * 0.521

PE = 82.29 N

As the swing moves past its lowest point h = 0, then all PE is converted to Kinetic Energy KE. Therefore, at lowest point

KE = 82.29

KE = 0.5 m v^2

0.5 (16.10) v^2 = 82.29

v = 3.20 m/s

Final answer:

When an object is cut in half, its mass and volume are divided by two, but its density remains constant because both mass and volume change proportionately.

Explanation:

When Connelly cuts a solid object in half, both the mass and volume are divided by two. However, density, which is defined as the mass of an object divided by its volume, remains unchanged. This is because both the mass and volume change proportionately, which means the ratio of mass to volume (density) does not alter.

Therefore, the correct answer to what happens to the mass, volume, and density of the object that Connelly cuts is: D) The mass and volume are both divided by two, but the density remains the same.

The speed limit most typically enforced at uncontrolled railroad crossings in the U.S when visibility of 400 feet in both directions isn't available is 15 mph. This may change according to specific state regulations so drivers must be aware of local laws regarding this.

The subject of this question lies within traffic law, more specifically related to railway crossing safety. Traffic regulations often mandate certain behaviors in the interest of maintaining safety, particularly around railway crossings. Although the question does not provide a specific speed limit, given context, I can tell you most states in the U.S stipulate that when motorists are unable to see 400 feet in both directions at an uncontrolled railroad crossing, they should reduce their speed to 15 mph.

However, these laws may vary by region, it is crucial that drivers familiarize themselves with local traffic regulations, always obey posted limits, and show prudence while approaching a railroad crossing.

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Imagining that the forces form a right triangle (since the 3rd force is acting perpendicularly) then the resultant force can simply be calculated using the hypotenuse formula:

c^2 = a^2 + b^2

Where a and b is equivalent to:

a = 15 N + 25 N = 40 N

b = 30 N

Therefore the resultant force is then calculated:

c^2 = (40 N)^2 + (30 N)^2

c^2 = 1,600 + 900

c^2 = 2,500

c = 50 N

Answer:

To find the magnitude of the resultant force, we can use the Pythagorean theorem and the trigonometric ratios.

First, we need to find the horizontal and vertical components of the two forces acting in the same direction:

Horizontal component = 15 N + 25 N = 40 N

Vertical component = 0 N (since the forces are in the same direction)

Next, we need to find the horizontal and vertical components of the third force acting perpendicular to the first two:

Horizontal component = 0 N (since the force is perpendicular to the other forces)

Vertical component = 30 N

Now, we can find the horizontal and vertical components of the resultant force:

Horizontal component = 40 N + 0 N = 40 N

Vertical component = 0 N + 30 N = 30 N

Using the Pythagorean theorem, we can find the magnitude of the resultant force:

Resultant force = sqrt((40 N)^2 + (30 N)^2)

Resultant force = sqrt(1600 N^2 + 900 N^2)

Resultant force = sqrt(2500 N^2)

Resultant force = 50 N

Therefore, the magnitude of the resultant force is 50 newtons.

The average force on the glove during the catch of a baseball with an initial velocity of 17.1 m/s and a mass of 0.5 kg, brought to rest in 0.1 seconds, can be calculated using the impulse-momentum theorem, resulting in an average force of 85.5 newtons.

The question involves the concept of impulse and the physics of motion. In physics, impulse is equal to the change in momentum of an object when a force is applied over a duration of time. The formula to calculate the impulse J is J = Ft, where F is the average force and t is the time period the force is applied. The change in momentum can also be written as m[tex](v_f - v_i)[/tex], where m is the mass, [tex]v_f[/tex] is the final velocity, and [tex]v_i[/tex]is the initial velocity. In this scenario, the baseball's initial velocity is 17.1 m/s, the mass of the baseball is 0.5 kg, and it is brought to rest (final velocity 0 m/s) in 0.1 seconds, resulting in a change in velocity of -17.1 m/s.

Using the impulse-momentum theorem, we can calculate the average force on the glove during the catch by rearranging the impulse formula to solve for the average force F. The calculation would thus be:

F = m * ([tex]v_f - v_i[/tex]) / t

F = 0.5 kg * (-17.1 m/s - 0 m/s) / 0.1 s

F = -85.5 N (The negative sign indicates that the force is in the opposite direction of the ball's initial motion, i.e., it is a decelerating force.)

Therefore, the average force on the glove is 85.5 newtons.