How does the image help convey the message of this poster?

The image of a large clock next to a lazy worker stresses the importance of being on time, particularly for work in the factories.
The image of a large clock next to an unproductive worker emphasizes the importance of utilizing every minute of production time.
The image of a large clock next to a tired worker supports the idea of maintaining fair working hours, even during the war.
The image of a large clock next to a slow worker suggests that faster production is the central key to winning the war.

Answer:

The person with locked legs will experience greater impact force.

Explanation:

Let the two persons be of nearly equal mass (say m)

The final velocity of an object (person) dropped from a height H (here 2 meters) is given by,

[tex]v=\sqrt{2gH}[/tex]

([tex]g[/tex] = acceleration due to gravity)

which can be derived from Newton's equation of motion,

[tex]v^2=u^2+2aS[/tex]

Now, the time taken (say [tex]t[/tex] ) for the momentum ( [tex]mv[/tex] ) to change to zero will be more in the case of the person who bends his legs on impact than who keeps his legs locked.

We know that,

[tex]Force=\frac{\Delta(mv)}{t}[/tex]

Naturally, the person who bends his legs will experience lesser force since [tex]t[/tex] is larger.

Answer: 4.74 mm

Explanation:

We can solve this problem with the following equation:

[tex]Y=\frac{stress}{strain}[/tex] (1)

Where:

[tex]Y=1.8(10)^{10} Pa[/tex] is the Young modulus for femur

[tex]stress=\frac{F}{A}=1.58(10)^{8} Pa[/tex] is the stress (force [tex]F[/tex] applied per unit of transversal area [tex]A[/tex]) on the femur

[tex]strain=\frac{\Delta l}{l_{o}}[/tex]

Being:

[tex]\Delta l[/tex] the compression the femur can withstand before breaking

[tex]l_{o}=0.54 m[/tex] is the length of the femur without compression

Writing the data in equation (1):

[tex]Y=\frac{\frac{F}{A}}{\frac{\Delta l}{l_{o}}}[/tex] (2)

[tex]1.8(10)^{10} Pa=\frac{1.58(10)^{8} Pa}{\frac{\Delta l}{0.54 m}}[/tex] (3)

Isolating [tex]\Delta l[/tex]:

[tex]\Delta l=\frac{(1.58(10)^{8} Pa)(0.54 m)}{1.8(10)^{10} Pa}[/tex] (4)

[tex]\Delta l=0.00474 m[/tex] (5) This is the compression in meters

Converting this result to millimeters:

[tex]\Delta l=0.00474 m \frac{1000 mm}{1 m}=4.74 mm[/tex]

- Decreasing one of the masses to 1/2 of its original value

- Increasing the distance by a factor of [tex]\sqrt{2}[/tex]

Explanation:

There are no options provided, however we can still answer the question.

In fact, the magnitude of the gravitational force between two objects is given by  the equation:

[tex]F=G\frac{m_1 m_2}{r^2}[/tex]

where

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

We notice that:

Therefore, in order to reduce the gravitational attraction by one half, we can do one of the following changes:

- Decreasing one of the masses to 1/2 of its original value: for example, if [tex]m_1'=\frac{1}{2}m_1[/tex], the gravitational force becomes

[tex]F'=G\frac{m_1' m_2}{r^2}=G\frac{\frac{1}{2}m_1m_2}{r^2}=\frac{1}{2}(G\frac{m_1m_2}{r^2})=\frac{1}{2}F[/tex]

- Increasing the distance by a factor of [tex]\sqrt{2}[/tex]: in fact, if [tex]r'=\sqrt{2}r[/tex], the gravitational force becomes

[tex]F'=G\frac{m_1 m_2}{r'^2}=G\frac{m_1m_2}{(\sqrt{2}r)^2}=\frac{1}{2}(G\frac{m_1m_2}{r^2})=\frac{1}{2}F[/tex]

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Her resultant displacement is (45 Meters East.)

She originally walks 45 meters east, then she goes south 45 meters, then north 45 meters.  The south and north placements  just make her go back to where her previous placements were before them. Making her 45 meters east.

Answer:

the Mass of 1 kg object is same in Earth & Moon.

Explanation:

Weight, on the otherhand does change with location depends on the gravity. so the answer is : Weight of one kilo on the surface of moon is 1.622 N. A body is taken from the center of the Earth to the Moon.

The weight on moon will be 166.66 grams.

We have a object on earth.

We have to identify its weight on moon.

Weight is a force acting on the body directed towards the center of earth and is the product of mass and acceleration due to gravity.

W = mg

According to the question -

Mass on earth = 1 Kg = 1000 grams

Now, the weight on moon is 1/6 of that of weight on earth. Therefore -

W(M) = [tex]$\frac{1}{6}[/tex] W(E)

Therefore -

W(M) =  [tex]\frac{1}{6}[/tex] x 1000 = 166.66 grams

Hence, the weight on moon will be 166.66 grams.

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Answer:

-6, [tex]-5\frac{2}{5}[/tex], [tex]-4\frac{1}{5}[/tex]

Explanation:

The solution of answer is in the picture attached

Answer:

Due to the generation of carbon dioxide

Explanation:

Climate change occurs due to global warming generated by greenhouse gases. Carbon dioxide is the gas that does not leave or allow solar radiation from the sun to rise from the Earth's surface, increasing the average temperature of the planet.

Burning fossil fuels for energy generation such as coal is another source of carbon dioxide generation. The generation of energy should be directed towards the production of renewable energies, using sources such as solar and wind energy.

The given statement "When the net force of an object decreases, the object's acceleration decreases" is true about Newton's second law.

Answer: Option B

Explanation:

Newton’s second law of motion states that the object’s acceleration depends on two variable:

The equation can be given as below,

             Force = mass × acceleration

Hence, from the above, it is concluded that force is directly proportionate to mass and acceleration of the objects. So, when force increases both mass and acceleration increases. Similarly, if force decreases, both mass and acceleration get decreased. Therefore, the given statement in option B would be correct answer.

Answer:

Space

Explanation:

Hope this helped

Answer:

VOLUME AND MASS IF U ;LOOK AT THE OTHERGUIYS ANSWER IS SPACE WHICH IS CORRECT BUT MY ANSSIGNMENT DOES NOT HAVE THAT ANSWER SO ITS VOLUME AND MASS

Explanation:

Answer:

Explanation:

The total energy at all times is equal to the sum of kinetic and potential energy.

Eu = Ep + Ek

If an object has reached a finite height point and is stationary, then the potential energy is maximum (100 J) and the kinetic energy is equals to zero.

If the same object started to fall before the impact on the ground itself, the kinetic energy is maximum (100 J) and the potential energy is minimum ie zero.

God is with you!!!

Answer:

R2=10ohm

Explanation:

In this combination

R2 and R3 are in series combination where R1 is in parallel combination with them hence

R2+R3=R`

And

1/R`+1/R1=1/Req

1/R`=1/Req-1/R1

1/R`=1/4-1/6

=1/12

R`=12ohm

Also

R2+R3=R`

R2=R`-R3

R2=12-2

R2=10ohm

Answer:

Orange juice has a lower viscosity than chocolate syrup.

Explanation:

Viscosity is the measure we use to determine essentially how thick a fluid is. So, a liquid that has a high viscosity, is thicker than a liquid that has a lower viscosity. Viscosity is also benchmarked against that of water since water is considered to he the least viscous fluid. Therefore, the more "watery" the substance, the less viscous it is.

Its easy to imagine how orange juice would have a lower viscosity. When we imagine, we think about how quickly both orange juice and chocolate syrup would flow if they both were to be spilled. Basically, we would be looking at their "flow rate" where orange juice would wash away quickly while chocolate syrup would tend to stick to the surface and be slower. But lets also look why this happens. This happens because of the size of the particles. Orange juice is diluted and has a lot of water molecules which are small and can move very quickly. Chocolate syrup on the other hand is comprised of molecules that are larger and heavier and therefore take a longer time to move. So a liquid with lower viscosity is "less resistant to flow".

Paul the penguin's velocity is 3.33[tex]ms^{-1}[/tex].

Explanation:

Paul glided (displaced) 40 meters towards north.

The time he taken to displace is 12 seconds.

∴displacement d= 40m.

time t= 12s.

The speed of a body in a certain direction is the measure of Velocity.

The velocity of the an moving object is given by ratio of the rate of change in the distance by the time taken.

⇒Velocity v= [tex]\frac{displacement}{time}[/tex].

=[tex]\frac{40}{12}[/tex].

=3.33 [tex]ms{-1}[/tex].

Thus the velocity of the Paul the penguin glided on ice is 3.33 [tex]ms{-1}[/tex].

a) 6.4 m/s

b) 2.1 m

c) [tex]61.6^{\circ}[/tex]

d) 14.0 N

e) 4.6 m/s

f) 37.9 N

Explanation:

a)

Since the system is isolated (no external forces on it), the total momentum of the system is conserved, so we can write:

[tex]p_i = p_f\\m_1 u_1 = m_1 v_1 + m_2 v_2[/tex]

where:

[tex]m_1 = 2 kg[/tex] is the mass of the 1st sphere

[tex]m_2 = 3kg[/tex] is the mass of the 2nd sphere

[tex]u_1 = 8 m/s[/tex] is the initial velocity of the 1st sphere

[tex]v_1[/tex] is the final velocity of the 1st sphere

[tex]v_2[/tex] is the final velocity of the 2nd sphere

Since the collision is elastic, the total kinetic energy is also conserved:

[tex]E_i=E_k\\\frac{1}{2}m_1 u_1^2 = \frac{1}{2}m_1 v_1^2 + \frac{1}{2}m_2 v_2^2[/tex]

Combining the two equations together, we can find the final velocity of the 2nd sphere:

[tex]v_2=\frac{2m_1}{m_1+m_2}u_1=\frac{2(2)}{2+3}(8)=6.4 m/s[/tex]

b)

Now we analyze the 2nd sphere from the moment it starts its motion till the moment it reaches the maximum height.

Since its total mechanical energy is conserved, its initial kinetic energy is entirely converted into gravitational potential energy at the highest point.

So we can write:

[tex]KE_i = PE_f[/tex]

[tex]\frac{1}{2}mv^2 = mgh[/tex]

where

m = 3 kg is the mass of the sphere

v = 6.4 m/s is the initial speed of the sphere

[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity

h is the maximum height reached

Solving for h, we find

[tex]h=\frac{v^2}{2g}=\frac{(6.4)^2}{2(9.8)}=2.1 m[/tex]

c)

Here the 2nd sphere is tied to a rope of length

L = 4 m

We know that the maximum height reached by the sphere in its motion is

h = 2.1 m

Calling [tex]\theta[/tex] the angle that the rope makes with the vertical, we can write

[tex]h = L-Lcos \theta[/tex]

Which can be rewritten as

[tex]h=L(1-cos \theta)[/tex]

Solving for [tex]\theta[/tex], we can find the angle between the rope and the vertical:

[tex]cos \theta = 1-\frac{h}{L}=1-\frac{2.1}{4}=0.475\\\theta=cos^{-1}(0.475)=61.6^{\circ}[/tex]

d)

The motion of the sphere is part of a circular motion. The forces acting along the centripetal direction are:

- The tension in the rope, T, inward

- The component of the weight along the radial direction, [tex]mg cos \theta[/tex], outward

Their resultant must be equal to the centripetal force, so we can write:

[tex]T-mg cos \theta = m\frac{v^2}{r}[/tex]

where r = L (the radius of the circle is the length of the rope).

However, when the sphere is at the highest point, it is at rest, so

v = 0

Therefore we have

[tex]T-mg cos \theta=0[/tex]

So we can find the tension:

[tex]T=mg cos \theta=(3)(9.8)(cos 61.6^{\circ})=14.0 N[/tex]

e)

We can solve this part by applying again the law of conservation of energy.

In fact, when the sphere is at a height of h = 1 m, it has both kinetic and potential energy. So we can write:

[tex]KE_i = KE_f + PE_f\\\frac{1}{2}mv^2 = \frac{1}{2}mv'^2 + mgh'[/tex]

where:

[tex]KE_i[/tex] is the initial kinetic energy

[tex]KE_f[/tex] is the kinetic energy at 1 m

[tex]PE_f[/tex] is the final potential energy

v = 6.4 m/s is the speed at the bottom

v' is the speed at a height of 1 m

h' = 1 m is the height

m = 3 kg is the mass of the sphere

And solving for v', we find:

[tex]v'=\sqrt{v^2-2gh'}=\sqrt{6.4^2-2(9.8)(1)}=4.6 m/s[/tex]

f)

Again, since the sphere is in circular motion, the equation of the forces along the radial direction is

[tex]T-mg cos \theta = m\frac{v^2}{r}[/tex]

where

T is the tension in the string

[tex]mg cos \theta[/tex] is the component of the weight in the radial direction

[tex]m\frac{v^2}{r}[/tex] is the centripetal force

In this situation we have

v = 4.6 m/s is the speed of the sphere

[tex]cos \theta[/tex] can be rewritten as (see part c)

[tex]cos \theta = 1-\frac{h'}{L}[/tex]

where in this case,

h' = 1 m

L = 4 m

And [tex]r=L=4 m[/tex] is the radius of the circle

Substituting and solving for T, we find:

[tex]T=mg cos \theta + m\frac{v^2}{r}=mg(1-\frac{h'}{L})+m\frac{v^2}{L}=\\=(3)(9.8)(1-\frac{1}{4})+(3)\frac{4.6^2}{4}=37.9 N[/tex]

Answer:

4.4 m

Explanation:

Given:

v = 0 m/s

a = -9.8 m/s²

t = 2.0 s

Find: Δy

Δy = vt − ½ at²

Δy = 0 − ½ (-9.8) (2.0)²

Δy = 4.4 m

Answer:

The force  a person applies to a simple machine

Explanation:

An input force is that variable that enters a simple machine to perform a particular job by multiplying the value of that input force.

As a typical example we can find a lever where a person introduces an input force, this force multiplies according to the mechanical advantage of the lever resulting in the work of a simple machine with more work.

Answer:

The force a simple machine applies to an system

Explanation:

Answer:

Ultraviolet radiation.

Answer:

T=2π[tex]\sqrt{l/g}[/tex]  (simple pendulum)

length of the string  and gravity mainly effect the pendulum period

Explanation:

Answer:

A is right in my opinion

Answer:

B-400 mL

Explanation:

Volume = Mass divided by density

360 / 0.9 = 400

Answer:

i think the answer is 12 ohms

plz mark me as brainliest :)

Answer:

12 ohms

Explanation:

The five 60 Ohms resistance can be represented as follows:

R1 = 60 Ohms

R2 = 60 Ohms

R3= 60 Ohms

R4 = 60 Ohms

R5 = 60 Ohms

Rt =?

Since they are in parallel connections, the equivalent resistance (Rt) can be calculated as follows :

1/Rt = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5

1/Rt = 1/60 + 1/60 + 1/60 + 1/60 + 1/60

1/Rt = ( 1+1+1+1+1)/60

1/Rt = 5/60

1/Rt = 1/12

Cross multiply to express in linear form

Rt = 12 ohms

Therefore the equivalent resistance is 12ohms

Answer:

Correct answer: Kinetic energy of rotation, kinetic energy of translation and potential energy

Explanation:

Before it began to rotate it possessed potential energy. After being released from the rest it starts to roll on the roof and get kinetic energy of rotation, kinetic energy of translation along with potential energy.

God is with you!!!

Answer:

Force

Explanation:

W= F * d

Work is defined in physics as the product of force and an object's displacement. It is expressed mathematically as Work = Force x Distance. The direction of the force and displacement also affect whether the work done is considered positive or negative.

In physics, work is defined as the product of force and an object's displacement. It is represented mathematically as Work = Force x Distance. In this equation, Force is the amount of effort exerted on an object, and Distance or displacement is the amount of space over which the force is applied. If the force and the displacement are in the same direction, the work done is positive.

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Answer:

Explanation:

Folic acid is the form of folate found in vitamin supplements and fortified foods. Fortified foods, also called enriched foods, are foods that have specific nutrients added to them.

Neural tube defect happen when the tissues and bone around the brain and spine do not grow well. Neural tube can happen in the third and fourth week after conception (the first or second week after your first missed period). This could be before you know that you are pregnant.

Folic acid lowers the risk of your unborn baby having a neural tube defect . Neural tube are a group of serious birth defects that affect a baby’s spinal cord, brain and skull. Some babies with severe Neural tube defect birth are stillborn or do not survive long after birth. Spina Bifida is the most common Neural tube defect.

Answer:

42000N

Explanation:

F=mass *acceleration

F= 1200*35

F=42000N

Yo sup??

To solve this question we must learn that

pH=-log([H+])

in the question its given that

[H+]=10^(-8)

therefore

pH=-log(10^(-8))

=-(-8)log10

=8

Since pH>7 therefore its basic

Hence the correct answer is option A ie

A.8, basic

Hope this helps.

Answer: 8 basic

Explanation:

Answer:

Explanation:

It's Newton's first law of motion, and object in motion continues to stay in motion unless acted upon by an unbalanced force. In this case, your body is the force that's moving on the bus. When you jump(the unbalanced force) your body is still used to being in motion, which makes you fall and not land on your feet.  

In this area the convection is taking place inside the water which is inside the utensils.

Explanation:

To calculate the speed of the 0.300 kg mass when it is 0.0600 m from equilibrium on a 26.6 N/m spring, use the conservation of energy principle to find the kinetic energy at that point and then solve for velocity.

The problem involves a 0.300 kg mass attached to a spring with a force constant of 26.6 N/m. The mass is pulled 0.120 m from equilibrium and released. To find the speed of the mass when it is 0.0600 m from equilibrium, we can use the principle of conservation of energy. The total mechanical energy is conserved because we are ignoring any external forces like friction or air resistance.

Initially, when the mass is released from 0.120 m, the spring has some potential energy (due to being stretched) and the kinetic energy is zero since it's released from rest. When the mass is at 0.0600 m from equilibrium, there is a combination of potential energy (due to being displaced from equilibrium) and kinetic energy (since the mass is moving).

The initial potential energy (PEi) stored in the spring can be calculated using the formula PEi = 1/2 * k * x2, where k is the spring constant and x is the initial displacement. The final potential energy (PEf) is calculated similarly, with x being the final displacement of 0.0600 m.

The difference between the initial and final potential energy will give us the kinetic energy at 0.0600 m from equilibrium, since energy is conserved and the difference must have been converted to kinetic energy. The kinetic energy (KE) can be expressed as KE = 1/2 * m * v2, where m is the mass and v is the velocity we want to find.

Here's how you would set up the equations:

The speed of a 0.300 kg mass attached to a 26.6 N/m spring, when it is 0.0600 m from equilibrium, is approximately 0.978 m/s. This was determined using principles of energy conservation. Initial potential energy was converted to kinetic energy to find the speed.

Given a 0.300 kg mass attached to a spring with a force constant (k) of 26.6 N/m, we can determine the speed when the mass is 0.0600 m from equilibrium using energy conservation principles. Initially, the mass is pulled 0.120 m from equilibrium and released.

We start by calculating the total mechanical energy of the system at the maximum displacement (0.120 m):

Potential Energy (PEmax) = 1/2 k xmax²

PEmax = 1/2 x 26.6 N/m x (0.120 m)²

PEmax = 1/2 x 26.6 x 0.0144

PEmax = 0.19152 J

At the position where the mass is 0.0600 m from equilibrium, the potential energy is:

PE = 1/2 k x²

PE = 1/2 x 26.6 N/m x (0.0600 m)²

PE = 1/2 x 26.6 x 0.0036

PE = 0.04788 J

The difference in energy will be converted into kinetic energy (KE):

KE = PEmax - PE

KE = 0.19152 J - 0.04788 J

KE = 0.14364 J

Using the kinetic energy formula (KE = 1/2 mv²), we solve for the speed:

0.14364 J = 1/2 x 0.300 kg * v²

0.14364 = 0.150 x v²

v² = 0.14364 / 0.150

v² = 0.9576

v = √0.9576

v ≈ 0.978 m/s

Thus, the speed of the mass when it is 0.0600 m from equilibrium is approximately 0.978 m/s.

Answer:

V=21V

Explanation:

In series combination current is same

I=2.6A

R2=8ohm

V2=2.6×8

V2=20.8

V2=21V

Answer:

Explanation:

21 v