Answer:
Yo, you just kind of answered it yourself. The Electron Cloud Model is the informal way of describing an atomic orbital.
Explanation:
The analogy of the cloud of electrons is really describing the groups of electrons orbiting around said atom. Depending on the atom, there will be many or few electrons orbiting around it on all sides which can resemble an all-encompassing cloud.
The electron-cloud model is used in atomic physics to describe the behavior and location of electrons. It suggests that electrons exist in a cloud or probability distribution surrounding the nucleus. This model is based on the Heisenberg uncertainty principle.
Explanation:The electron-cloud model is a model used in atomic physics to describe the behavior and location of electrons within an atom. It suggests that electrons do not move around the nucleus in fixed, predictable orbits, but rather exist in a cloud or probability distribution surrounding the nucleus.
The model is based on the Heisenberg uncertainty principle, which states that it is impossible to precisely know both the position and momentum of a subatomic particle like an electron. Instead, the electron-cloud model describes the probability of finding an electron within a certain region of space, represented as an electron cloud or cloud of probability.
This model provides a more accurate representation of electron behavior compared to the earlier Rutherford model, which depicted electrons as orbiting the nucleus in fixed paths. The electron-cloud model helps explain phenomena such as atomic bonding, electron energy levels, and electron configurations.
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What do we mean when we say that the sun is in gravitational equilibrium?
D)
It has played a role throughout the Sun's history, but it was most important right after nuclear fusion began in the Sun's core. What do we mean when we say that the Sun is in gravitational equilibrium? ... There is a balance within the Sun between the outward push of pressure and the inward pull of gravity.
When we say that the sun is in gravitational equilibrium, it simply means that there's a balance within the sun between the outward push of pressure and the inward pull of gravity.
The sun is important as it holds the solar system together. The sun is the most important body to the Earth. It. helps in the provision of heat and energy to the Earth. Without the sun, the Earth will be lifeless.It should be noted that the sun is stable. In this case, it's neither contracting nor expanding. In this case, the sun is in equilibrium and the forces within it are balanced.Gravitational Equilibrium ensures that the core of the sun is at the right level of nuclear fusion. When the sun is in gravitational equilibrium, there is a balance within the sun between the outward push of pressure and the inward pull of gravity.In conclusion, the amount of energy that's released by fusion in the core of the sun will then be equal to the amount of energy that radiated from the surface of the sun into space.
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to permit a large water flow , the pipe must have, A.enough strength,B.a large cross sectional area, C.enough length to conduct the flow or ,D. a sufficient drop
Answer:
B. A large cross sectional area,
Explanation:
To permit a large flow of water in a pipe, the cross sectional area of the pipe must be significantly large. According to the flow rate equation:
V = [tex]\frac{Q}{A}[/tex]
Where:
Q is the Volume flow rate and it is the volume of fluid that flows through the pipe
V is the velocity of the fluid in the pipe
A is the cross sectional area of the pipe.
From the equation, we see that for a larger amount of water to flow in a pipe, the cross-sectional area must be very large. In short, Q varies directly as A.
Answer:
a large cross-sectional area
Explanation:
Object A has a length of 3 cm, a width of 2 cm, and a height of 4 cm. Object B is dropped into a graduated cylinder. It displaces 19 mL of water. The volume of object A is:
A: greater than the volume of object B
B: less than the volume of object B
C: equal to the volume of object B
Answer:
A: greater than the volume of object B
Explanation:
Based on the dimensions, the volume of object A is ...
(3 cm)(2 cm)(4 cm) = 24 cm³ = 24 mL
If object B displaces 19 mL of water, we presume that is its volume. Since 24 mL is more than 19 mL, we conclude ...
The volume of object A is greater than the volume of object B.
_____
Comment on density
We have presumed that object B is completely submerged. If it is not, then the relative volumes will depend on the densities. If the density of object B is less than about (19/24) g/mL, its volume may very well be larger than that of object A.
Answer:
A: greater than the volume of object B
Explanation:
Based on the dimensions, the volume of object A is ...
(3 cm)(2 cm)(4 cm) = 24 cm³ = 24 mL
If object B displaces 19 mL of water, we presume that is its volume. Since 24 mL is more than 19 mL, we conclude ...
The volume of object A is greater than the volume of object B.
_____
Comment on density
We have presumed that object B is completely submerged. If it is not, then the relative volumes will depend on the densities. If the density of object B is less than about (19/24) g/mL, its volume may very well be larger than that of object A.
You are driving on an Interstate highway in bad weather, and you do not feel safe at the speed limit. You should A: Follow closely behind a large truck. It will shield you from the weather. B: Slow down to the speed that allows you to have complete control of your vehicle. C: Always drive the same speed as other vehicles, even if it feels unsafe.
Answer:
B. Slow down to the speed that allows you to have complete control of your vehicle.
Explanation:
Your life is very important, and driving at the same speed as others or even closely behind could endanger your life. Being directly behind someone else, if they stop immediately you will hit them because you can't stop fast enough. If something feels unsafe never continue doing it.
Answer:
B. slow down to the speed that allows you to h ave complete control of your vehicle.
Explanation:
You can also reduce the risk of external factors by slowing down and keeping a safe distance from the vehicle in front of you.
The mass of the sun is 1.99×1030kg and its distance to the earth is 1.50×1011m. What is the gravitational force of the sun on the earth?
Answer: [tex]3.524(10)^{22}N[/tex]
Explanation:
According to Newton's law of Gravitation, the force [tex]F[/tex] exerted between two bodies of masses [tex]m1[/tex] and [tex]m2[/tex] and separated by a distance [tex]r[/tex] is equal to the product of their masses and inversely proportional to the square of the distance:
[tex]F=G\frac{(m1)(m2)}{r^2}[/tex] (1)
Where:
[tex]G[/tex] is the Gravitational Constant and its value is [tex]6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex]
[tex]m1=1.99(10)^{30}kg[/tex] is the mass of the Sun
[tex]m2=5.972(10)^{24}kg[/tex] is the mass of the Earth
[tex]r=1.50(10)^{11}m[/tex] is the distance between the Sun and the Earth
Substituting the values in (1):
[tex]F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.99(10)^{30}kg)(5.972(10)^{24}kg)}{(1.50(10)^{11}m)^2}[/tex] (2)
Finally:
[tex]F=3.524(10)^{22}N[/tex] This is the gravitational force of the Sun on the Earth.
Final answer:
The resulting force is approximately 3.54 times [tex]10^{22}[/tex] N.
Explanation:
The question pertains to calculating the gravitational force exerted by the Sun on Earth which can be found using Newton's law of universal gravitation. The formula for the gravitational force F between two masses m1 and m2 separated by a distance r is given by F = G * (m1 * m2) / [tex]r^2[/tex], where G is the gravitational constant (6.67430 times [tex]10^{-11}[/tex]N times[tex](m/kg)^2[/tex]).
Given the mass of the Sun (m1) is 1.99 times [tex]10^{30}[/tex]kg, the mass of the Earth (m2) is 5.972 times [tex]10^{24}[/tex] kg (approximately, for ease of calculation), and the average distance (r) between the Earth and Sun is 1.50 times [tex]10^{11}[/tex] m, we can substitute these values into the gravitational force formula to generate accurate answer.
Therefore, the gravitational force of the Sun on the Earth is calculated to be approximately 3.54 times [tex]10^{22}[/tex]N.
What is the entropy of isolated system?
Answer: Entropy is the measure of the disorder of a system
Explanation:
Entropy is a thermodynamic quantity defined as a criterion to predict the evolution or transformation of thermodynamic systems. In addition, it is used to measure the degree of organization of a system.
In other words: Entropy is the measure of the disorder of a system and is a function of state. That is, it depends only on the state of the system.
However, in the case of an isolated system in an irreversible process, the value of entropy increases in the course of a process that occurs naturally. While in a reversible process the entropy of the isolated system remains constant.
The toy on a spring illustrated energy conversion among what different forms?
a.Gravitational potential energy, kinetic energy, and elastic potential energy
b.Gravitational potential energy, kinetic energy, and thermal energy
c.Kinetic energy, elastic potential energy, and thermal energy
d.Kinetic energy and elastic potential energy
e.Gravitational potential energy and thermal energy
Final answer:
The toy on a spring converts energy between elastic potential energy, kinetic energy, and gravitational potential energy, demonstrating the principles of the Law of Conservation of Mechanical Energy. So the correct option is a.
Explanation:
The toy on a spring illustrates energy conversion among different forms of energy. The correct answer is a. Gravitational potential energy, kinetic energy, and elastic potential energy. Initially, the toy has elastic potential energy due to the compression of the spring. When the spring is released, this energy is converted into kinetic energy as the toy begins to move. As the toy moves up a slope, kinetic energy is gradually converted into gravitational potential energy. The toy's energy transitions between these forms without any loss if we assume negligible friction and air resistance, consistent with the Law of Conservation of Mechanical Energy.
Mariner 10 was the first to visit this planet in 1974. what is this planet?
The Mariner 10 probe was launched by NASA on November 3rd, 1973, with the purpose of exploring the characteristics of two planets in the solar system that were closest to the Sun, Mercury and Venus.
In addition, it was launched to explore the atmosphere and surface of both planets and prove that it was possible to use gravitational assistance (also called slingshot effect, a special orbital maneuver in order to use the gravitational field energy of a planet or massive body to accelerate or slow the probe and change the direction of its trajectory) in long interplanetary trips to save fuel.
In this case, Mariner 10 first arrived at Venus and succeded in using its gravitational field to accelerate its trajectory towards Mercury.
The planet visited by Mariner 10 in 1974 was Mercury.
In 1974, Mariner 10 passed within 9500 kilometers of Mercury's surface and transmitted more than 2000 photographs back to Earth. These images provided unprecedented details of Mercury's surface.How far did lewis and clark travel round trip
Answer:
8,000 miles and for 2 years
Explanation:
from May 14, 1804, to September 23, 1806, from St. Louis, Missouri, to the Pacific Ocean and back Lewis and Clark traveled. They traveled nearly 8,000 miles (13,000 km). There expedition was called Corps of Discovery.
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What is the mass of a student that weighs 3000N stands on one foot, balancing on a step stool.
Weight = (mass) x (gravity)
so
Mass = (weight) / (gravity)
Mass = (3000N) / (9.8 m/s^2)
Mass = 306.1 kg
But he could never stand on one foot balanced on a step stool. The poor kid weighs 675 pounds ! !
The mass of a student can be calculated using the formula F = m*g. Hence the mass is approximately 305.81 kg.
To find the mass of the student, we need to convert the weight to force using the formula, F = m * g where F is the force or weight, m is the mass, and g is the acceleration due to gravity (g = 9.8 m/s² on Earth) or Using the relationship between weight and mass, which is expressed by the formula W = m*g, where W is weight.
To calculate the mass (m), we rearrange the formula to m = W/g.
m = 3000 N / 9.81 m/s^2 = 305.81 kg
Therefore, the mass of the student who exerts a force of 3000N due to gravity on the step stool while balancing on one foot is 305.81 kilograms.
Suppose that as an object falls from the top of a cliff, its position in feet above the ground after t seconds is given by s(t) = 160-16t^2. Find the average velocity from t=1to t=1+h seconds, where h not= 0.
a.32+16h
b.-32-16h
c.32-16h
d.-32+16h
The average velocity of the object can be found by calculating the change in position divided by the change in time.
Explanation:The average velocity of the object from t=1 to t=1+h seconds can be found by calculating the change in position divided by the change in time.
To find the change in position, subtract s(1) from s(1+h):
s(1+h) - s(1) = (160-16(1+h)^2) - (160-16(1)^2)
simplifying gives: -16h - 16h^2
To find the change in time, subtract 1 from 1+h: 1+h - 1 = h
So, the average velocity is:
-16h - 16h^2 / h = -16 - 16h
Therefore, the correct answer is d. -32 + 16h.
Ionic compounds have high melting points.
This can best be explained by the fact that the bonds in ionic compounds
A. involve the sharing of electrons.
B. require a great deal of energy to break.
C. occur between metals and nonmetals.
D. form between a positively charged atom and a negatively charged atom.
Ionic compounds have high melting points due to the strong electrostatic forces of attraction between ions, which require a great deal of energy to break.
Explanation:The high melting points of ionic compounds are best explained by the B option: ionic bonds require a great deal of energy to break. This is because ionic compounds are formed by the strong electrostatic forces of attraction between positively charged cations and negatively charged anions. This strong inter-ionic bonding makes ionic compounds hard, requiring substantial energy to overcome and result in a high melting point.
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The law of conservation of energy states that (4 points)
energy is always created and destroyed
energy cannot be created or destroyed
energy is unable to change forms
energy should be saved as often as possible
Answer:
energy cannot be created or destroyed
Explanation:
Energy can't be created nor destroyed; rather, it transforms from one form to another.
Answer:
The law of conservation of energy states that energy cannot be created or destroyed.
Wind and solar energy are examples of scarce resources. Renewable resources. Capital resources. Nonrenewable resources.
Answer:
Renewable Resources
Explanation:
This is because wind is almost infinite and doesn't pollute.
Answer: Renewable resources
Explanation:
The largest of 2 integers is one more than three times the smaller. If the sum of the two integers is 37
Answer:
The two integers are 28 and 9
Explanation:
Let's call the two integers x and y.
We have:
- The largest of the 2 integers is one more than three times the smaller: this means
x = 3y + 1 (1)
- The sum of the two integers is 37:
x + y = 37 (2)
It's a system of two equations that we can solve. Substituting directly (1) into (2),
3y + 1 + y = 37
4y + 1 = 37
4y = 36
y = 9
And so,
x = 3y + 1 = 3(9) + 1 = 27 +1 = 28
So the two integers are 28 and 9.
Someone please help me
Answer:
D or 49.7°
Explanation:
You are given the equation and all the information you need, so you simply need to understand what the question asks for and answer appropriately. Notice that the light wave travels from the water to air. This means that water should be labelled with a "1" as it comes prior to air, which should be labeled "2". Thus, all you need to do, is plug and chug:
[tex]\theta_2 = sin^{-1}(\frac{n_1sin(\theta_1)}{n_2}) = sin^{-1}(\frac{(1.33)sin(35)}{1})[/tex]
[tex]\theta_2 = sin^{-1}(0.763) = 49.7^o[/tex]
And, therefore, your answer is D, 49.7°.
What is the maximum eccentricity an ellipse can have
Answer: 1
Explanation: The highest eccentricity an ellipse can have is '1', a straight line.
The maximum eccentricity an ellipse can have is 1.0, which makes the ellipse appear 'flat' or extremely elongated. Eccentricity is the ratio of the distance between the foci and the length of the major axis.
Explanation:In the world of Mathematics, specifically within the context of Geometry, an Ellipse is a particular shape that can be modified by altering its eccentricity. The eccentricity of an ellipse is determined by the ratio of the distance between the two foci and the length of the major axis.
The eccentricity thus dictates the roundness of the ellipse. For instance, if the eccentricity is zero, the ellipse is indeed a circle. As the eccentricity increases, the ellipse becomes more elongated. The maximum eccentricity an ellipse can have is 1, beyond which the ellipse would be considered a line. When the eccentricity is exactly 1, the ellipse is at its most elongated state, appearing almost 'flat'.
To make it more precise, eccentricity is calculated as e = f/a where 'f' is the distance from the center of the ellipse to one of the foci, and 'a' is half the long axis.
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3. Which equation shows the relationship between the Kelvin and Celsius temperature scales? K = 273 – °C K = °C + 273 K = °F + 273 K = °C + °F
Answer: [tex]K=\°C+273.15[/tex]
Explanation:
The Kelvin ([tex]K[/tex]), is the unit of temperature of the scale created by the British physicist William Thomson (Lord Kelvin) in 1848, taking as a base the Celsius scale, establishing the zero point for this scale in the absolute zero which is in [tex]-273.15\°C[/tex].
This was achieved by observing that when a gas cools, its volume decreases proportionally to its temperature. That is, for each degree of temperature that the gas decreases, its volume also decreases by a certain percentage.
After which, Kelvin made the calculations and it turned out that at a temperature of [tex]-273.15\°C[/tex] the volume of the gas would be zero (theoretically).
It should be noted that the Kelvin is the unit of temperature of the International System of Units and that although the scale starts at absolute zero (theoretical), in which no molecule should move, in reality it is not so, because according to quantum physics, at this temperature the molecules retain a residual movement.
On a trip to the Colorado Rockies, you notice that when the freeway goes steeply down a hill, there are emergency exits every few miles. These emergency exits are straight ramps which leave the freeway and are sloped uphill. They are designed to stop runaway trucks and cars that lose their brakes on downhill stretches of the freeway even if the road is covered with ice. You are curious, so you stop at the next emergency exit to take some measurements. You determine that the exit rises at an angle of 10o from the horizontal and is 100m long. What is the maximum speed of a truck that you are sure will be stopped by this road, even if the frictional force of the road surface is negligible?
Answer:
The maximum speed that the truck can have and still be stopped by the 100m road is the speed that it can go and be stopped at exactly 100m. Since there is no friction, this problem is similar to a projectile problem. You can think of the problem as being a ball tossed into the air except here you know the highest point and you are looking for the initial velocity needed to reach that point. Also, in this problem, because there is an incline, the value of the acceleration due to gravity is not simply g; it is the component of gravity acting parallel to the incline. Since we are working parallel to the plane, also keep in mind that the highest point is given in the problem as 100m. Solving for the initial velocity needed to have the truck stop after 100m, you should find that the maximum velocity the truck can have and be stopped by the road is 18.5 m/s.
Explanation:
Using principles from physics, specifically the energy conservation principle and trigonometry, you can determine that the maximum speed a truck could be going and still be stopped by the emergency exit—even with negligible friction—is roughly 18.56m/s or 66.81km/h.
Explanation:In physics, when a vehicle goes up a slope, two main forces tend to stop the vehicle: gravity and friction. In this problem, we are asked to ignore friction, so that only gravity will slow down the vehicle. Given that that the velocity of the truck at the end of the emergency exit has to be zero, we should use the energy conservation principle because work done by gravity equals the initial kinetic energy of the truck. Since work done by gravitational force equals mass (m) * gravitational acceleration (g) * height (h), and initial kinetic energy equals 0.5 * mass (m) * velocity^2 (v^2), we have m * g * h = 0.5 * m * v^2 (with v being the maximum velocity). Then, we can calculate the height using trigonometry because we know the angle and the length of the slope. So, h = 100m * sin(10) = 17.36m. Plug h into the equation above and solve for v gives v = sqrt(2 * g * h). With g = 9.8m/s^2, v = sqrt(2 * 9.8m/s^2 * 17.36m) = 18.56m/s or 66.81km/h.
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Which describes an object in projectile motion? Check all that apply.A.Gravity acts to pull the object downB.The object moves in a straight path.C.The forward velocity of the object is 0 m/s.D.The object’s inertia carries it forward.E.The path of the object is curved.
Projectile motion refers to an object in motion in the air, affected only by gravity. Attributes of such motion include gravity pulling the object down, inertia propelling it forward, and a parabolic trajectory resulting from these forces.
Projectile motion describes the movement of an object thrown or projected into the air and is influenced solely by gravity, which is the only force acting upon it accelerating the object downwards. The aspects that describe this motion include the following: Gravity acts to pull the object down, the object's inertia carries it forward in the direction it was thrown, and the path of the object is indeed curved due to the gravity acting on it. Option A and D
An object in projectile motion does not move in a straight path (therefore, option B is incorrect), and the forward velocity of the object is not 0 m/s as it has initial velocity in the horizontal direction (thus, option C is also incorrect). The combination of the forward motion and the acceleration due to gravity results in a parabolic trajectory, which signifies a two-dimensional motion.
Resistivity of a material is the resistance of a cm long sample of the material of 1 cm2 cross-sectional area.
Yes the formula of resistivity is:
[tex]R=\dfrac{\rho l}{A}[/tex]
Where [tex]\rho[/tex] is relativistic resistance with units [tex]\dfrac{\Omega}{m}[/tex], each metal has different relativistic resistance you must find the relativistic resistance of your material using the table of relativistic resistances.
[tex]l[/tex] stands for the length of a wire.
[tex]A[/tex] stands for the area of the wire. Usually it is equal to [tex]\pi r^2[/tex] because.
So now we have data [tex]A=1cm^2[/tex] but nothing else was specified so we are unable to calculate anything.
Hope this helps.
r3t40
Answer:
Your answer is going to be 1 cm.
Explanation:
Calculate the kinetic energy in joules of an automobile weighing 4345 lb and traveling at 75 mph. (1 mile
Answer:
1.11×10⁶ J
Explanation:
75 mi/hr × (1609.34 m / mi) × (1 hr / 3600 s) = 33.5 m/s
4345 lbf × (1 lbm / lbf) × (1 kg / 2.2 lbm) = 1975 kg
KE = 1/2 mv²
KE = 1/2 (1975 kg) (33.5 m/s)²
KE = 1.11×10⁶ J
The kinetic energy of the automobile weighing 4345lb and with a speed of 75mph is 1.1077 × 10⁶J
Given the data in the question;
Mass of the automobile [tex]m = 4345lb = 1970.859 kg[/tex][we convert from pound to kilogram]
Velocity of the automobile; [tex]v = 75mph = 33.528m/s[/tex][ we convert from miles per hour to meter per second]
Kinetic energy; [tex]K.E = ?[/tex]
We know that, Kinetic Energy ( K.E ) is a form of energy that a matter possesses by reason of its motion.
It is directly proportional to the mass of the matter and to the square of its velocity.
That is; [tex]K.E = \frac{1}{2} mv^2[/tex]
To find the Kinetic Energy, we simply substitute our given values into the equation
[tex]K.E = \frac{1}{2}\ * 1970.859kg\ *\ ( 33.528m/s)^2\\\\K.E = 1107747.69 kg.m^2/s^2\\\\K.E = 1.1077 * 10^6 J[/tex]
Therefore, the kinetic energy of the automobile weighing 4345lb and with a speed of 75 mph is 1.1077 × 10⁶J
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The mean free path of a helium atom in helium gas at standard temperature and pressure is 0.2 um.What is the radius of the helium atom in nanometers?
Answer:
r = 0.1217 nm
Explanation:
r^2 = (RT) / ( 4 * pi *P * A* L)
r^2 = 8.314 * 273 / ( 4 * pi * (1.01*10^5) * (6.022*10^23) * (0.2*10^-6))
r = 1.217*10^-10
r = 0.1217 nm
The radius of the helium atom in helium gas can be determined using the mean free path and the concept of cross-sectional area.
Explanation:The radius of a helium atom can be determined using the mean free path and the concept of cross-sectional area. The mean free path is the average distance a molecule travels between collisions. In this case, the mean free path of a helium atom in helium gas at standard temperature and pressure is given as 0.2 um.
To find the radius of the helium atom, we can relate the cross-sectional area, which is 4r², to the mean free path using the formula (N/V)(4r²)(λ) = 1. Rearranging this formula, we have r = sqrt(1 / (4 * N / V * λ)), where N/V is the molar density of helium gas at standard temperature and pressure.
Since we are given the mean free path as 0.2 um, we can substitute this value into the formula. The molar density of helium gas at standard temperature and pressure is approximately 1.78 x 10^25 atoms/m³. Plugging in these values, we can calculate the radius of the helium atom in nanometers.
Using the formula, r = sqrt( 1 / (4 * 1.78 x 10^25 * 0.2 x 10^-6)), we can simplify and convert to nanometers to get r ≈ 0.109 nm. Therefore, the radius of the helium atom is approximately 0.109 nanometers.
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An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis. Calculate the possible values of vx.
Answer:
2 m/s and -2 m/s
Explanation:
The object travels with an angle of
60.0°
with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).
If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:
[tex]v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s[/tex]
If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:
[tex]v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s[/tex]
The center of the Milky Way most likely contains
A.
empty space.
B.
a red giant star.
C.
a globular cluster.
D.
a supermassive black hole.
Answer:
The center of the Milky Way most likely contains a supermassive black hole.
Explanation:
Because it is an eleptical galaxy, it has a little rotation to it but not enough to flatten out so the center will contain a supermassive black hole.
All life on earth exists in a region known as
Hello There!
All life on Earth exists in a region called the biosphere.
The biosphere is known as the global sum of all ecosystems. It's called the "zone of life"
Answer:the bioshpere
Explanation:
Use ohms law to determine the battery voltage you would need to send 2.5 A of current through a light bulb with 3.6 Ω of resistance.
According to Ohm's law, the voltage drop V across a resistor when a current flows through it is V = IR. To determine the battery voltage needed to send 2.5 A of current through a light bulb with 3.6 Ω of resistance, we rearrange Ohm's law and substitute the known values.
Explanation:According to Ohm's law, the voltage drop V across a resistor when a current flows through it is calculated using the equation V = IR, where I equals the current in amps (A) and R is the resistance in ohms. To determine the battery voltage needed to send 2.5 A of current through a light bulb with 3.6 Ω of resistance, we rearrange Ohm's law as V = IR. Substituting the known values, we have V = (2.5 A)(3.6 Ω), which gives us a battery voltage of 9 V.
A 10-cm-long spring is attached to the ceiling. When a 2.0 kg mass is hung from it, the spring stretches to a length of 15 cm. How long when a 3.0 kg mass is suspended from it?
Final answer:
Using Hooke's Law and the spring constant calculated from the initial scenario, the length of the spring when a 3.0 kg mass is suspended from it will be 17.5 cm.
Explanation:
The question involves calculating how much a spring will stretch under a certain weight, which can be addressed using Hooke's Law and the concept of spring constants in physics. We are given a scenario in which a spring stretches an additional 5 cm (from 10 cm to 15 cm) when a 2.0 kg mass is hung from it. To determine how long the spring will be when a 3.0 kg mass is suspended from it, we first need to calculate the effective spring constant (k) using the initial provided information.
We can use the formula for Hooke's Law: F = k × Δx, where F is the force applied to the spring (which is the weight of the mass), k is the spring constant, and Δx is the change in length of the spring from its equilibrium position. Because the weight force due to gravity is F = m × g (where m is the mass and g is the acceleration due to gravity, 9.8 m/s²), we can find k as follows:
For a 2.0 kg mass, F = 2.0 kg × 9.8 m/s² = 19.6 N. The change in length Δx is 5 cm or 0.05 m. Therefore, k = F / Δx = 19.6 N / 0.05 m = 392 N/m.
Now we can find the new change in length for a 3.0 kg mass. Let Δx' be the new change in length. We have F' = 3.0 kg × 9.8 m/s² = 29.4 N. Since k is constant for the spring: 29.4 N = 392 N/m × Δx'. Solving for Δx' gives Δx' = 29.4 N / 392 N/m = 0.075 m or 7.5 cm. Therefore, the total length of the spring when a 3.0 kg mass is hung will be 10 cm + 7.5 cm = 17.5 cm.
A force of 45 newtons is applied on an object, moving it 12 meters away in the same direction as the force. What is the magnitude of work done on the object by this force? Part A: Enter the variable symbol for the quantity you need to find. Use your keyboard and the keypad to enter your answer. Then click Done.
Explanation:
The Work [tex]W[/tex] done by a Force [tex]F[/tex] refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.
Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
[tex]W=(F)(d)[/tex] (1)
In this case both (the force and the distance in the path) are parallel (this means they are in the same direction), so the work [tex]W[/tex] performed is the product of the force exerted to push the box [tex]F=45N[/tex] by the distance traveled [tex]d=12m[/tex].
Hence:
[tex]W=(45N)(12m)[/tex] (2)
[tex]W=540Nm=540J[/tex]
Answer: W
Explanation:
For Edmentum the answer is simply W
Which is not true of the Intertropical Convergence Zone?A) It features heavy precipitation B) It's where the trade winds collideC) It's a high-pressure zone with sinking air D) It is also known as the doldrums
Explanation:
The intertropical convergence zone is the region of the terrestrial globe where the trade winds of the northern hemisphere converge with those of the southern hemisphere.
It is characterized by being a belt of low pressure and inconsistent location around the equator constituted by ascending air currents, where large masses of warm and humid air converge from the north and south of the intertropical zone.
The reason of its inconsistent location is due to the movements of the Earth with the seasons, having as a consequence the amount variation of heat energy from the sun in this region.