Answer:
When the car crashes there is no balanced force acting on the person so they continue forward in the car
Explanation:
Calculate the force of Earth's gravity on 1350kg spacecraft that is 1.28 * 10 ^ 6 * m above Earth surface ( Earth's mass is 6*10^ 24 kgg) .
Answer:
The force of Earth's gravity is 327954 N
Explanation:
Given:
Mass of the space craft = 1350 kg
Mass of the earth = 6*10^ 24
Distance = 1.28 * 10 ^ 6
To Find:
The force of Earth's gravity = ?
Solution:
The force of attraction between a planet and an object kept in space is given by the expression
[tex]F =\frac{GMm}{R^2}[/tex]
where
M is the mass of the earth
m is the mass of the space craft
R is the distance between the earth and the space craft and
G is the gravitational constant
On substituting the values
[tex]F =\frac{(6.67 \times 10^{-11})(6\times10^ {24})(1350)}{(1.28\times 10^6)^2}[/tex]
[tex]F =\frac{(54027\times 10^{13})}{(1.28\times 10^6)^2}[/tex]
[tex]F =\frac{(54027\times 10^{13})}{(1.6384\times 10^{12})}[/tex]
F = 327954 N
A block of wood is found to have the dimensions of 6.21 cm x 4.63 cm x 5.34 cm. Calculate the volume of the block.
*Apparently its not 153.54 cm^3, so I need the right answer.*
The volume is [tex]153.54 cm^3[/tex]
Explanation:
The volume of the block, assuming it is a parallelepided, is given by
[tex]V=L\cdot W \cdot H[/tex]
where
L is the length
W is the width
H is the height
For the block in this problem, we have
L = 6.21 cm
W = 4.63 cm
H = 5.34 cm
Therefore, the volume is
[tex]V=(6.21)(4.63)(5.34)=153.54 cm^3[/tex]
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Identify and define the four major forms of matter, explain how melting, freezing, boiling,
evaporation, condensation, sublimation and deposition affect them.
There are four forms of matter: Solid, Liquid, gas and Plasma and matter undergoes various state changes termed as melting, freezing, boiling, evaporation, condensation, sublimation and deposition.
Explanation:
Solids
A matter that have a definite shape because of its closely packed molecular structure; are known as Solids. It can be identified as they have a definite shape and cannot flow or float without external forces are applied.
Liquids
These have a an internal molecular structure with comparatively more spaces with one another. Liquids have a property to flow and change shape according to the container it is taken.
Gases
The internal molecular structure of gases has the widest range of space among one another and thus they have a floating property because of least density.
Plasma
A complete ionized gas which has equal amount of positively and negatively charged ions. The best example of plasma is a plasma-ball.
Phase transformation among the four forms of matter
Melting
A matter changing from a solid phase to liquid phase is known as melting. Ex: Ice into water
Freezing
A matter changing from liquid to solid is known as freezing.
Boiling
When the liquid is heated to its boiling point, this gets transformed into the state of gas where liquid's pressure equals to the external pressure.
Evaporation
Once the liquid reached the temperature range above the boiling point ad starts converting into vapours or gaseous state.
Condensation
When the gases changes from the gaseous phase to liquid phase, this is called condensation.
Sublimation
The change of solid into gas is called as sublimation.
Deposition
Deposition refers the thermodynamic process where phase transition takes place as the gas solidifies without passing through the liquid phase. An example: the process of converting water vapour from frozen air directly into ice without initially becoming a liquid.
As a bike accelerates from rest, it gains
Answer:
kenetic energy
When you arent moving something its called potential enegy when its moving it changes into kinetic energy
Answer:
momentum, speed, velocity, and kinetic energy
Explanation:
The sun’s___and the planet’s___keeps planets moving is___orbits.
The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.
Explanation:
The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:
1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is
[tex]F=G\frac{Mm}{r^2}[/tex]
where
G is the gravitational constant
M is the mass of the Sun
m is the mass of the planet
r is the distance between the Sun and the planet
This force acts as centripetal force, continuously "pulling" the planet towards the centre of its circular orbit.
2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.
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John and Daniel are playing tug-of-war together. John is exerting 10 N of force. Daniel is exerting 12 N of force. What is their net force?
Answer: 2 N in Daniel's direction.
Answer: 2N in Daniel's direction.
Explanation:
Since, both of them are playing a game of tug and war, the resultant(net) force consists of opposing forces.
Net force= 12N-10N = 2N
And the net force is in Daniel's direction because Daniel exerted greater force.
In the tug-of-war scenario between John and Daniel, the net force is 2 N in Daniel's direction, as his force is 12 N compared to John's 10 N. The forces are unbalanced with the larger force determining the direction of the net force.
When John and Daniel play tug-of-war, John exerts a force of 10 N while Daniel exerts a slightly higher force of 12 N. To find the net force, we consider the direction of the forces as well. Since they are exerting forces in opposite directions, the net force is the difference between the two forces. Therefore, the net force is 12 N (Daniel's force) - 10 N (John's force) = 2 N in the direction of the larger force, which is Daniel's direction.
Understanding tug-of-war forces is an interesting way to conceptualize the principles of balanced and unbalanced forces. In this case, the forces are unbalanced because one player is exerting more force than the other, causing the net force to shift in one direction.
1. A ball is thrown straight up into the air with an initial speed of 8.0 m/s.
a. How long does it take for the rocket to reach its highest point?
b. What is the maximum height the ball reaches above the ground?
Explanation:
When an object falls freely, it falls due to the influence of gravity and this free falling object is called as acceleration of gravity. The free falling object has an acceleration value of about 9.8 m / s^2 downward on Earth.
The Acceleration of Gravity is denoted by a symbol g.
Solution:
Initial speed = 8.0 m / s.
a. To calculate the time taken, (initial velocity is 8.0 m/s and the final velocity is 0)
T = Velocity / gravity
Time taken to reach highest point t = 8 / 9.8 = 0.816 s.
b. To calculate the height, (initial velocity is 8.0 m/s and the final velocity is 0)
h = square of velocity / (2 * g)
The maximum height the ball reaches h = (8 * 8) / (2 * 9.8)
= 64 / 19.6 = 3.26 m.
What is the kinetic energy of the ball just before it hits the ground?
Answer:
[tex]0.5mv^{2}[/tex]
Explanation:
Kinetic energy, [tex]KE= 0.5mv^{2}[/tex]
while potential energy, PE= mgh where m is the mass, v is the velocity of the ball, g is acceleration due to gravity and h is the height.
The question requires kinetic energy hence we use the [tex]KE= 0.5mv^{2}[/tex]
Since the figures are not given, we maintain that [tex]KE= 0.5mv^{2}[/tex]
The kinetic energy of a ball just before it hits the ground is its motion energy due to gravitational potential energy conversion. It can be computed using the kinetic energy formula and the ball's mass and velocity. The energy dissipates and converts during the bounce, depending on the coefficient of restitution.
Kinetic Energy Before Colliding with the Ground
The kinetic energy of a ball just before it hits the ground is the energy it has due to its motion. This energy is obtained from the conversion of gravitational potential energy into kinetic energy as the ball falls. Assuming no non-conservative forces are acting on the ball, such as air resistance, the kinetic energy can be calculated using the equation KE = 1/2 mv₂, where m is the mass of the ball and v is its velocity just before impact. The velocity can be found using kinematic equations or the conservation of energy principle. Since its initial potential energy is converted entirely into kinetic energy at the moment before collision, if the height from which the ball was dropped is known and the mass of the ball is given, one can accurately calculate its velocity and consequently its kinetic energy just before the impact.
Conversion and Dissipation of Energy During Bounce
Once the ball collides with the ground, its kinetic energy is temporarily transferred into other forms, including elastic potential energy and thermal energy due to deformation. The coefficient of restitution, represented as e, determines what fraction of the kinetic energy is retained after the collision. Hence, the kinetic energy of the ball just after it bounces up will be a fraction e2 of its initial kinetic energy before the collision. As the ball ascends, this kinetic energy is once again converted back into potential energy.
Which list gives the proper sequence of energy changes that occur in a hydroelectric plant? The mechanical energy of the turbine rotates the generator parts The turbine blades capture the kinetic energy of the water Electrical energy is transferred via power lines The generator produces electrical energy Electrical energy is transferred via power lines The turbine blades capture the kinetic energy of the water The generator produces electrical energy The mechanical energy of the turbine rotates the generator parts The generator produces electrical energy The mechanical energy of the turbine rotates the generator parts The turbine blades capture the kinetic energy of the water Electrical energy is transferred via power lines The turbine blades capture the kinetic energy of the water The mechanical energy of the turbine rotates the generator parts The generator produces electrical energy Electrical energy is transferred via power lines
Answer:
The turbine blades capture the kinetic energy of the water The mechanical energy of the turbine rotates the generator parts. The generator produces the electrical energy that is then transferred via power lines
Explanation:
Hydroelectric Plant
It's widely used to transform potential gravitational energy of the water located at a higher height into electrical energy. A dam is constructed in the potential location of the power plant, so all the water is directed to the turbines at a lower level from the face of the water. This water enters a set of pipes that send the stream to the turbines, whose blades are moved by the water, capturing its kinetic energy. The turbine now has enough mechanical energy to have the generation system moving and transform mechanical into electrical energy. That electric energy is finally sent to the consuming centers through power lines.
Thus, the correct sequence is:
The turbine blades capture the kinetic energy of the water The mechanical energy of the turbine rotates the generator parts. The generator produces the electrical energy that is then transferred via power lines
Answer:The turbine blades capture the kinetic energy of the water
The mechanical energy of the turbine rotates the generator parts
The generator produces electrical energy
Electrical energy is transferred via power lines
Explanation:
bc I just took the k12 test
BRAINLIEST:
How do forecasters predict hurricanes?
Weather forecaster can predict hurricanes through two methods:
by calculating the seasonal probabilitiesby estimating the recent hurricane scenarios.Explanation:
Prediction of Hurricanes
With the help of elementary statistics, meteorologists can predict the intensity of hurricanes coming in specific regions with the approximate wind speeds. The possible trajectory of hurricanes can be drawn as a cone which is updated by estimating the error in the prediction.
Based on the past events of hurricanes and the current climate conditions, a statistical regression equation is formed. There are many many models such as NHC90 and BAM that help meteorologists to predict the intensity of waves and eventually the probability of hurricanes coming in specific regions.
A metal rod is 25.000 cm long at 25.0 degrees Celsius. When heated to 102.0
degrees Celsius, it is 25.054 cm long. What is the coefficient of linear expansion
for this metal?
The coefficient of linear expansion for the metal rod is calculated using the formula α = ΔL / (L₀ × ΔT) and is found to be approximately 2.8 x 10⁻⁵ per degree Celsius.
The question you've asked pertains to finding the coefficient of linear expansion for a metal rod that has expanded due to an increase in temperature. The formula to calculate the coefficient of linear expansion (α) is given by:
α = ΔL / (L₀ × ΔT)
Where:
ΔL is the change in length of the rod
L₀ is the original length of the rod
ΔT is the change in temperature
Let's plug in the values we have:
ΔL = 25.054 cm - 25.000 cm = 0.054 cm
L₀ = 25.000 cm (initial length)
ΔT = 102.0°C - 25.0°C = 77.0°C
Before substitution, convert the length in cm to meters (1 cm = 0.01 m):
ΔL = 0.054 cm × 0.01 m/cm = 0.00054 m
L₀ = 25.000 cm × 0.01 m/cm = 0.25 m
Now, calculate α:
α = 0.00054 m / (0.25 m × 77.0°C)
α = 0.00054 m / (19.25 m°C)
α ≈ 2.8 x 10⁻⁵ per degree Celsius
The coefficient of linear expansion for this metal is approximately 2.8 x 10⁻⁵ per degree Celsius.
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In Newton’s third law, the action and reaction forces _____.
A.)cancel each other out
B.)act on the same object
C.)add together to double the force
D.)act on different objects
In Newton's third law, the action and reaction forces D.)act on different objects
Explanation:
Newton's third law of motion states that:
"When an object A exerts a force on object B (action force), then action B exerts an equal and opposite force (reaction force) on object A"
It is important to note from the statement above that the action force and the reaction force always act on different objects. Let's take an example: a man pushing a box. We have:
Action force: the force applied by the man on the box, forwardReaction force: the force applied by the box on the man, backwardAs we can see from this example, the action force is applied on the box, while the reaction force is applied on the man: this means that the two forces do not act on the same object. This implies that whenever we draw the free-body diagram of the forces acting on an object, the action and reaction forces never appear in the same diagram, since they act on different objects.
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Answer:Act on different objects
Explanation:
I NEED HELP ASAP!!!!!!
Spiral, elliptical, irregular, and barred spiral are descriptions of different shapes of ________. A. stars B. galaxies C. solar systems D. orbits
Answer:
B. galaxies
Explanation:
Galaxies are clusters of stars, gas and dark matter. They are classified based on the shape they form. There are three main categories: Spiral, elliptical, and irregular. As their named suggests, that is what they look like.
Barred spiral galaxies are a subcategory of spiral galaxies. The nucleus of the galaxy (Center) a bar material is formed and arms branch out from the ends of it.
Some galaxies on the other hand, do not fit the main categories.
Attached is a picture of the common and uncommon categories of galaxies.
The motion of roller coasters depends upon the conversion of potential and kinetic energy. A 100-kg car starts from rest at the top of a hill with a height of 50 m. Which of the following is this car's kinetic energy at the bottom of the hill?
Answer:
K=49,000 Joule
Explanation:
Kinetic and Gravitational Potential Energy
The principle of conservation of the mechanical energy states that the mechanical energy of a system of particles remains unaltered unless some external non-conservative forces acting on the system.
The total mechanical energy present in the roller coasters is the sum of their kinetic and gravitational potential energies:
[tex]\displaystyle ME=\frac{m.v^2}{2}+m.g.h[/tex]
If the roller coaster decreases its height, the speed will increase and compensates for the loss of potential energy. If the roller coaster increases its height, it will go slower and eventually stop until running out of kinetic energy.
We know the car starts from rest at the top of the hill of 50 m. This implies that the mechanical energy is
[tex]\displaystyle ME=\frac{100.0^2}{2}+100.(9.8).(50)=49,000\ J[/tex]
When it reaches the bottom of the hill, the potential energy is zero, thus the car has only kinetic energy.
Kinetic energy at the bottom = 49,000 Joule
The roller coaster's potential energy at the top of the hill is converted to kinetic energy at the bottom. Assuming no energy losses, the car's kinetic energy at the bottom is 49050 J, equal to the potential energy it had at the top.
Explanation:Understanding Energy Conservation in a Roller Coaster
The question addresses the principle of energy conservation in physics, particularly as it pertains to a roller coaster's movement. When the roller coaster is at the top of a hill, it possesses a maximum amount of gravitational potential energy due to its position. As it descends, this potential energy is converted into kinetic energy, which is dependent on the mass and velocity of the coaster car. To find the kinetic energy at the bottom of the hill, we can use the equation KE = ½mv², where m is mass and v is velocity.
To determine the kinetic energy at the bottom, we first need to calculate the potential energy at the top. The potential energy (PE) can be found using the formula PE = mgh, where g is the acceleration due to gravity (approximately 9.81 m/s² on Earth) and h is the height. For a roller coaster car with a mass of 100 kg at a height of 50 m, the potential energy is PE = 100 kg × 9.81 m/s² × 50 m, which equates to 49050 J (joules). Assuming no energy is lost to friction or air resistance, this potential energy will be entirely converted into kinetic energy at the bottom of the hill.
Thus, the car's kinetic energy at the bottom equals the potential energy at the top, which is 49050 J.
If sodium has one valence electron and sulfur has six, how many sodium atoms are needed to form an ionic bond with sulfur?
ITS TWO
Answer: two
Explanation:
Answer:
Its 2
Explanation:
This compound has a central Sulfur atom surrounded by 4 Oxygens in a covalent bonds, with an overall charge of negative 2 and 2 Sodium atoms with a charge of positive one. Thus making the answer 2.
How many coulombs of positive charge are there in 47.0 gm of plutonium, given its atomic mass is 244 and that each plutonium atom has 96 protons?
(enter answer to three significant figures and in the exponent form: Example,
1.38e5)
Answer:
1.78×10⁶ CExplanation:
Using the atomic mass of pluonium atoms (244 g/mol), you can calculate the number of atoms in 47.0 g. Then, knowing that each plutonium atom has 96 protons, you calculate the number of protons in the 47.0 g sample. Finally, using the positive charge of one proton, you calculate the total positive charge in the 47.0 g of plutonium.
1. Number of atoms of plutonium in 47.0 g
Number of moles = mass / atomic mass = 47.0 g / 244 = 0.1926 molesNumber of atoms = number of moles × 6.022 × 10²³ atoms/mol Number of atoms = 0.1926 mol × 6.022 × 10²³ atoms/mol = 1.15998×10²³ atoms2. Number of protons
Number of protons = 1.15998×10²³ atoms × 96 protons/atom = 1.11385×10²⁵ protons3. Charge
Charge = charge of one proton × number of protonsCharge = 1.602×10⁻¹⁹ C/proton × 1.11385×10²⁵ protons = 1.78×10⁶C1. A container has a mass of 36 kg. How much does the container weigh?
Answer:
Explanation:The container weighs 352.8
I still walk four blocks north three blocks east for black stuff and then two blocks west where is the students distance and what is the students displacement
1) Distance: 9 blocks
2) Displacement: 4.12 blocks at [tex]76^{\circ}[/tex] north of east
Explanation:
1)
Distance is a scalar quantity that represents the total length of the path covered by a body during its motion, regardless of its direction. It can be calculated by simply adding the length of each part of the path.
In this problem, the motion of the person is:
4 blocks north
3 blocks east
2 blocks west
Therefore, the distance covered is just the sum of the length of each path:
distance = 4 + 3 + 2 = 9 blocks
2)
Displacement is a vector quantity connecting the initial position to the final position of the motion of a body. Since it is a vector, it has both a magnitude and a direction.
The magnitude can be computed by calculating the distance in a straight line between the initial and final position of motion.
In this problem, we have:
- The final position along the north-south direction is 4 blocks north
- The final position along the east-west direction is
(3 east) + (2 west) = 1 block east
Therefore, the magnitude of the displacement is given by Pythagorean's theorem:
[tex]displacement = \sqrt{4^2 + 1^2}=4.12[/tex] blocks
and the direction is given by
[tex]\theta=tan^{-1}(\frac{4}{1})=76^{\circ}[/tex] north of east.
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Energy of motion is also known as
a. work
b. potential energy
c. kinetic energy
d. total mechanical energy
Answer:
kinetic energy
Explanation:
before energy is put in motion its being stored as potential energy then becomes kinetic once its released
Kinetic energy is the energy of motion possessed by an object.
Explanation:The energy of motion is known as kinetic energy. It is the energy possessed by an object due to its motion. Kinetic energy can be calculated using the formula:
Kinetic Energy = 1/2 * mass * velocity2
For example, a moving car has kinetic energy because it is in motion.
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A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)
The work done against gravity is 100 J
Explanation:
The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:
[tex]W=mg\Delta h[/tex]
where
m is the mass of the object
g is the acceleration of gravity
[tex]\Delta h[/tex] is the change in height of the object
For the object in this problem, we have:
m = 5 kg
[tex]g=10 m/s^2[/tex]
[tex]\Delta h = 2 m[/tex]
Substituting into the equation,
[tex]W=(5)(10)(2)=100 J[/tex]
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BRAINLIST | Why are there some areas of the country where solar power is not the best option?
The reasons for solar power not being best option for some areas of country are mentioned below.
Explanation:
1. The semiconductors used are expensive and need clean environment.
2. Hard to build, install and maintain.
3. Not all areas recieve enough sunlight to make use of solar panels efficiently.
4. Not all areas have sufficient space for installation.
5. Some areas may use cheaper alterantives to generate power.
6. Not helpful on a rainy or foggy day so weather conditions of the area are a major factor.
A piece of metal is 4 cm by 10 cm
by 2 cm. Find its mass if it has a
density of 2 g/cm'.
Answer:
m=ρV
V=LxWxD
V=4x10x2=80
m=2*80=160 grams
Explanation:
Mass is equal to density multiply by volume of object. Volume of rectangle pice can be calculated by multiplying all sides.
Final answer:
The mass of the metal piece is calculated by first obtaining the volume, which is 80 cm³, and then using the density to find the mass, resulting in a mass of 160 g.
Explanation:
Metals are components or with brilliant, hard, moldable, blending, pliable properties. Name of metal (material) types are - Gold, Silver, Aluminum, Copper, Iron, and so on. They are utilized to create devices as they might be strong and effectively formed.
To find the mass of a piece of metal with given dimensions and density, first calculate its volume and then apply the formula for mass. The volume of a rectangular piece of metal is found by multiplying its length, width, and height.
Volume = Length x Width x Height = 4 cm x 10 cm x 2 cm = 80 cm³.
Once the volume is known, the mass can be calculated using the given density:
Mass = Density x Volume = 2 g/cm³ x 80 cm³ = 160 g.
Therefore, the mass of the metal piece is 160 grams.
A 1165 kg car traveling at 55 km/h is brought to a stop while skidding 38 m. Calculate the work done on the car by the friction forces.
The work done is [tex]-1.36\cdot 10^5 J[/tex]
Explanation:
According to the work-energy theorem, the work done by external forces on the car is equal to the change in kinetic energy of the car. Therefore, we have:
[tex]W=\Delta K\\W = \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
where
W is the work done by the external forces
m is the mass of the car
v is its final velocity
u is its initial velocity
In this problem, we have:
m = 1165 kg
[tex]u=55 km/h =15.3 m/s[/tex]
v = 0 (the car comes to a stop)
Solving for W, we find the work done by the frictional forces:
[tex]W=\frac{m(v^2-u^2)}{2}=\frac{(1165)(0-15.3^2)}{2}=-1.36\cdot 10^5 J[/tex]
Where the negative sign indicates that the direction of the force is opposite to the direction of motion of the car.
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A 59 kg physics student is riding her 220 kg Harley at 12 m/s when she has a head-on collision with a 2.1 kg pigeon flying the opposite direction at 44m/s. The bird is still on the motorcycle after the collision. How fast is the motorcycle going after the collision?
Answer:
Explanation:
Using conservation of momentum
[tex]m_1=59+220=279kg[/tex]
[tex]m_2=2.1kg[/tex]
[tex]U_1=12m/s[/tex]
[tex]U_2=-44m/s[/tex]
[tex]m_1U_1+m_2U_2=(m_1+m_2)V\\\\\frac{278\times 12-2.1\times 44}{279+2.1}=V\\\\V=11.58m/s[/tex]
The velocity of the motorcycle after collision is 11.6 m/s.
Conservation of linear momentumUsing the principle of conservation of momentum, the total momentum of the system remains constant. Hence, momentum after collision must be equal to momentum before collision.
Thus;
[(55 + 220) Kg * 12 m/s] + 2.1 kg * (-44m/s) = (55 + 220 + 2.1) v
3300 - 92.4 = 277.1v
v = 3300 - 92.4/277.1
v = 11.6 m/s
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If an airplane undergoes a displace-
ment of 500. km northwest in 1.2 hr,
what is its average velocity?
Final answer:
The average velocity of the airplane is calculated using the formula: velocity equals displacement divided by time. For a displacement of 500 km northwest over 1.2 hours, the average velocity is 416.67 km/h northwest.
Explanation:
Calculating Average Velocity
To calculate the average velocity of an airplane that has a displacement of 500 km northwest in 1.2 hours, we need to use the formula for average velocity, which is the displacement divided by the time taken. Since the displacement is given as a northwest direction, we are dealing with vector quantities, meaning that both magnitude and direction are important. However, for average velocity, we are concerned with the magnitude of this vector quantity.
The formula to calculate average velocity, v, is:
v =[tex]rac{d}{t}[/tex]
In this problem:
Displacement (d) = 500 km northwest
Time (t) = 1.2 hours
To find the average velocity, we divide the displacement by the time:
v = rac{500}{1.2} = 416.67 km/h northwest
The airplane's average velocity is 416.67 km/h in the northwest direction.
Your roommate drops your wallet down to you from the third floor window of your apartment, which is 11.5m from the ground. what is the velocity of the wallet when you catch it. ( Assume you catch the wallet right before it hits the ground)
Answer:
15.0 m/s
Explanation:
Take the down direction to be positive.
Given:
Δy = 11.5 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (11.5 m)
v = 15.0 m/s
A charge of 5.67 x 10-18 C is placed 3.5 x 10 m away from another charge of - 3.79 x 10 "C
What is the force of attraction between them?
Answer:
1. 579 x 10 ^-22N
Explanation:
F = kq1q2/r^2
= 9.0 x 10^9 x 5.67 x 10^-18 x 3.79 x 10^-18/ (3.5 x 10^-2)^2
= 1. 579 x 10 ^-22N
The attraction force between two charges is [tex]1.55 \times 10^{-22} \;\rm N[/tex].
Force Between Two ChargesCoulomb's law is used to find out the force of attraction between two charges placed at a certain distance. This law states that, when two point charges are placed at a distance, the force of attraction between them is proportional to the product of both charges and inversely proportional to the square of the distance between them.
[tex]F \propto q_1q_2[/tex] and [tex]F \propto \dfrac{1}{r^2}[/tex]
[tex]F =K \dfrac {q_1q_2}{r^2}[/tex]
Where K is the coulombs constant whose value is 8.988×109 N⋅m2⋅C−2.
Given that charges q1 and q2 are 5.67 x 10-18 C and 3.79 x 10 "C. The distance r is 3.5 x 10 m. The force of attraction is given below.
[tex]F = 8.98\times 10^9 \dfrac {5.67 \times 10^{-18}\times 3.79 \times 10^{-18}}{(3.5\times 10^{-2})^2}[/tex]
[tex]F = 1.55\times 10^{-22} \;\rm N[/tex]
Hence we can conclude that the attraction force between two charges is [tex]1.55 \times 10^{-22} \;\rm N[/tex].
To know more about the coulombs law, follow the link given below.
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objects with three very different sizes and weights are dropped off a tower on the moon. which factor of the objects will determine which hits the ground first?
1) size
2) weight
3) shape
4) none of these matter. with no air resistance, they all hit the ground at the same time.
4) none of these matter. with no air resistance, they all hit the ground at the same time.
Explanation:
The motion of the objects is a free fall motion, since the only force acting on them is gravity. Therefore, it is a uniformly accelerated motion with constant acceleration [tex]g[/tex] (acceleration of gravity) towards the ground, and so we can find the time of flight by using the suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
s is the vertical displacement (equal to height of the tower)
u = 0 is the initial velocity
t is the time
[tex]a=g[/tex] is the acceleration
Re-arranging the equation.
[tex]t=\sqrt{\frac{2s}{g}}[/tex]
As we can see, the time of flight depends only on the height of the tower (s) and the acceleration due to gravity (g): therefore, the three objects reach the ground at the same time.
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The density of mercury is 1X36X10'4 kg/m'3 at 0c. What is it density at 25 c? The coefficient of volume expansion of mercury is 2.8C10'-4
The density at 25 degrees is [tex]1.35\cdot 10^4 kg/m^3[/tex]
Explanation:
The density of a material is given by
[tex]d=\frac{m}{V}[/tex]
where
m is its mass
V is its volume
The volume of a material changes as a function of the temperature, according to
[tex]V(T)=V_0(1+\alpha (T-T_0))[/tex]
where
[tex]V_0[/tex] is the volume at temperature [tex]T_0[/tex]
[tex]\alpha[/tex] is the coefficient of volume expansion
In this problem, let's take a sample of mercury of mass
m = 1 kg
The density at 0 degrees is
[tex]d_0 = 1.36\cdot 10^4 kg/m^3[/tex]
So the corresponding volume is
[tex]V_0 = \frac{m}{d_0}=\frac{1}{1.36\cdot 10^4}=7.35\cdot 10^{-5} m^3[/tex]
For mercury,
[tex]\alpha = 2.8\cdot 10^{-4} ^{\circ}C^{-1}[/tex]
So the volume when [tex]T=25^{\circ}C[/tex] is
[tex]V(25)=(7.35\cdot 10^{-5})(1+2.8\cdot 10^{-4}(25-0))=7.4\cdot 10^{-5} m^3[/tex]
And since the mass has not changed, we can now calculate the density at 25 degrees:
[tex]d_{25}=\frac{m}{V_{25}}=\frac{1}{7.4\cdot 10^{-5} m^3}=1.35\cdot 10^4 kg/m^3[/tex]
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