Answers
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ -3}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -1 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-3)=-1(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+3=-x+5\implies y=-x+2[/tex]
6)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 2}}\quad ,&{{ 1}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 3 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=3(x-2) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-1=3x-6\implies y=3x-5[/tex]
7)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ 2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 0 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=0(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-2=0\implies y=2[/tex]
8)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]
9)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]
10)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{-2}}\quad ,&{{ -2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-2)=\cfrac{3}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x+1[/tex]
Related Questions
Battery was charged. when the charging began it was 23% full after 30 minutes of charging the battery was 89% full. how fast was the battery charged? How long did it take the battery to be funny charged?
Answers
Answer:
The battery was charged at a rate of 2.2 % per minute.
It took 35 minutes to fully charge the battery
Step-by-step explanation:
Initial amount of charge = 23%
Charge after 30 minutes = 89%
Percentage of charge gained in 30 minutes = 89-23
= 66 %
Charging speed of battery = [tex]\frac{percentage\hspace{3}of\hspace{3}charge\hspace{3}gained}{time\hspace{3}taken\hspace{3}in\hspace{3}minutes}[/tex]
= [tex]\frac{66}{30}[/tex]
= 2.2 % per minute
2.2% charge takes 1 minutes
1% charge takes [tex]\frac{1}{2.2}[/tex] minutes
Initially it was 23% charged so it needs 77% more charge to be fully charged.
So, 77% charge takes [tex]\frac{1}{2.2}*77[/tex] minutes
= [tex]\frac{100}{2.2}[/tex] minutes
= 35 minutes
If the polynomial x5 − 105 can be split as the product of the polynomials
x − 10 and a, what is a?
Answers
The mathematical expression that can be used in order to properly express the given scenario is,
x⁵ - 10⁵ = (x - 10)(a)
The value of a, as stated above, can be calculated by the equation,
a = (x⁵ -10⁵) / (x - 10)
There are two ways to solve the problem: synthetic division and the long way. Each of which will yield the same answer. Simplifying the value of a will give us a final answer of,
a = x⁴ + 10x³ + 100x² + 1000x
the value of a is
[tex]\( a = \frac{9845}{x - 10} \)[/tex].
To find a, we can use polynomial long division or synthetic division to divide [tex]\( x^5 - 105 \)[/tex] by [tex]\( x - 10 \)[/tex]. The remainder should be zero if [tex]\( x - 10 \)[/tex] is a factor of [tex]\( x^5 - 105 \)[/tex].
Let's perform polynomial long division:
____________________________
x - 10 | x^5 + 0x^4 + 0x^3 + 0x^2 + 0x - 105
- (x^5 - 10x^4)
____________________________
10x^4 + 0x^3 + 0x^2 + 0x - 105
- (10x^4 - 100x^3)
____________________________
100x^3 + 0x^2 + 0x - 105
- (100x^3 - 1000x^2)
___________________________
1000x^2 + 0x - 105
- (1000x^2 - 10000x)
___________________________
995x - 105
- (995x - 9950)
___________________________
9845
```
Since the remainder is a constant term, it's clear that [tex]\( x - 10 \)[/tex] is a factor of [tex]\( x^5 - 105 \)[/tex]. So, [tex]\( a = \frac{9845}{x - 10} \)[/tex].
Therefore, [tex]\( a = \frac{9845}{x - 10} \)[/tex].
Adam has $450. he spends $210 on food. later he divides all the money into four parts out of which three parts were distributed and one part he keeps for himself. then he found $50 on the road. write the final expression and find the money he has left?
Answers
First, subtract $210 from it (spent by Adam on food)
$450 - $210 = $240
Then, divide the remaining amount of money by 4
$240 / 4 = $60
Since, it was only one part that he kept to himself, the amount of money left with him, x, is
x = $60
Then, the total amount of money he has including that which he only picked from the road is,
T = $60 + $50 = $110
In the end, Adam had $110.
last one help. Use formulas to find the lateral area and surface area of the given prism. Round your answer to the nearest whole number.
A. 645 m2; 812 m2
B. 668 m2 ; 704m2
C. 645 m2; 740 m2
D. 668 m2; 740 m2
Answers
[tex] A_{L} = (a + b + c )h[/tex]
So put in the values and you get
[tex] A_{L} = (12.04 + 9 + 8 )23[/tex]
[tex] A_{L} = 668[/tex]
The formula for finding the surface area of a triangular prism is
SA = bh + (s1 + s2 + s3)H
So put in all the values and you get
SA = 9(8) + (9 + 8 + 12.04)23
SA = 740
Hope this helps! :)
Find the area
A. 54 in
B. 36 in
C. 18 in
D. 324 in
(In pie)
Answers
area of a circle = pi r^2
radius = 18
so R62 = 18^2 = 324
since you want the answer in pi it would be 324PI
so the answer is 324
So the Answer you want would be D. 324in
Prove that if one solution for a quadratic equation of the form x 2 + bx + c = 0 is rational (where b and c are rational), then the other solution is also rational. (use the fact that if the solutions of the equation are r and s, then x 2 + bx + c = (x − r)(x − s).)
Answers
Say r is rational. Suppose for a second, that s is not. Then, r+s is irrational. But this contradicts the fact that b is rational.
So, if one root is rational, then the other root is also rational
Final answer:
If one root of a quadratic equation with rational coefficients is rational, the other root must be rational too because the sum and product of the roots are related to the coefficients, which are also rational.
Explanation:
To prove that if one solution for a quadratic equation of the form x^2 + bx + c = 0 is rational, then the other solution is also rational, we can use the quadratic formula and properties of rational numbers. If the quadratic equation has rational coefficients and one rational solution, then the sum and product of the roots must also be rational. This is because a quadratic equation with roots r and s can be factored as (x - r)(x - s) = 0, which expands to x^2 - (r + s)x + rs = 0. Matching coefficients, we see that - (r + s) = b and rs = c. Since b and c are rational, r + s and rs must be rational as well.
Given that we have one rational root, let's say r, the sum of the roots r + s is rational, so s must also be rational because the difference of two rational numbers is rational. Hence, if one root of a quadratic equation with rational coefficients is rational, the other root must be rational as well.
3. Elizabeth opened a library with 19,000 books in the year 1998. The number of books increases at a rate of 6.49% each year. Use a graph to predict the number of books in 2020.
A) ≈ 71,160
B) ≈ 75,779
C) ≈ 80,697
D) ≈ 66,824
Answers
V (t)=V0 (1+r)^t
V (t) number of books in 2020 ?
V0 books in the year 1998 19000
R rate of growth 0.0649
T time 2,020−1,998=22 years
V (22)=19,000×(1+0.0649)^(22)
V (22)=75,778.81 Round your answer to get 75779
Answer: ≈ 75,779
Step-by-step explanation:
What is the probability that when a fair coin is flipped 25 times, there will be exactly five heads
Answers
A trapezoid has two right angles and bases that measure 16m and 8m. The right triangle formed by an altitude has a hypotenuse of 4 square root 5m. Sketch the trapezoid. What are its perimeter and area?
Answers
length of the rectangle = 8 m
base of triangle = 16 - 8 = 8 m
hypotenuse = 4√5 m
width of the rectangle = √(4√5 - 8) = 4 m
Perimeter = 8 + 16 + 4√5 + 4 = 28 + 4√5 m
Area = area of triangle + area of rectangle
Area = 8(4) / 2 + 8(4) = 48 m^2
Final answer:
The trapezoid forms a right-angled triangle with one additional rectangle. Its area is found to be 48m^2, and its approximate perimeter is 36.944m, by adding the lengths of all its sides together.
Explanation:
To find the perimeter and area of a trapezoid with two right angles and bases of 16m and 8m, we must first visualize the trapezoid. This trapezoid appears like a right-angled triangle with an additional rectangle attached to its hypotenuse.
We are given the hypotenuse of the altitude's right triangle is 4√5m, thanks to Pythagoras' theorem, we can find the two legs (which are the altitude h and the difference in bases). Let's call the altitude h and the difference in bases 'd'. Now, we know that the length of the longer leg of the right triangle is 16m - 8m = 8m.
Using the Pythagorean theorem where hypotenuse2 = altitude2 + difference in bases2, we have (4√5)2 = h2 + 82. Solving for 'h', we have h = √(80 - 64) = √16 = 4m. The area of a trapezoid is given by the formula A = (1/2) × (sum of the bases) × (height), which in this case is A = (1/2) × (16m + 8m) × 4m = 48m2.
For the perimeter, it can be calculated by adding the lengths of all sides. So, perimeter = 16m + 8m + 4m + 4√5m = 28m + 4√5m. To find the approximate value of 4√5m, we can calculate 4 × 2.236 (since √5 = 2.236), which gives us approximately 8.944m. Adding this to 28m gives us a perimeter of approximately 36.944m.
Last year, there were n pies baked for the bake sale. This year, there were 156 pies baked. Using n, write an expression for the total number of pies baked in the two years
Answers
Number of pies this year: 156
n + 156 = total number of pies baked in 2 years.
The midpoint of a segment is (4,3) and one endpoint is (10,8) Find the coordinates of the other endpoint.
Answers
Answer:
[tex](-2,-2)[/tex].
Step-by-step explanation:
Let us assume that coordinates of other endpoint are [tex](x_1,y_1)[/tex]
We have been given that the midpoint of a segment is (4,3) and one endpoint is (10,8). We are asked to find the coordinates of the other endpoint.
We will use midpoint formula to solve our given problem.
[tex]x\text{-coordinate of midpoint}=\frac{x_1+x_2}{2}[/tex]
[tex]y\text{-coordinate of midpoint}=\frac{y_1+y_2}{2}[/tex]
Upon using our given information, we will get:
[tex]4=\frac{x_1+10}{2}[/tex]
[tex]4\cdot 2=\frac{x_1+10}{2}\cdot 2[/tex]
[tex]8=x_1+10[/tex]
[tex]8-10=x_1+10-10[/tex]
[tex]x_1=-2[/tex]
Similarly, we will find y-coordinate.
[tex]3=\frac{y_1+8}{2}[/tex]
[tex]3\cdot 2=\frac{y_1+8}{2}\cdot 2[/tex]
[tex]6=y_1+8[/tex]
[tex]6-8=y_1+8-8[/tex]
[tex]y_1=-2[/tex]
Therefore, the coordinates of other endpoint would be [tex](-2,-2)[/tex].
Which of the following equations represents a line that is parallel to the line below?
A.
y=1/3x-2
B.
y =-1/3x-2
C.
y=3x-2
y=-3x-2
Answers
so slope = (2-1) / (0-3) = 1/-3 = -1/3
parallel has same slope = -1/3
b = 2
equation
y = -1/3x + 2
answer
equation is y = -1/3x +2. I don't see any of those above matched
Find the arc length of a central angle of pi/4 in a circle whose radius is 8 inches
Answers
C=Θ/360πd
where:
Θ=45
d=8*2=16 in
hence;
C=45/360*π*16
=6.3 inches
A cube is packed with decorative pebbles. If the cube has a side length of 6 inches, and each pebble weighs on average 0.5 lb per cubic inch, what is the total weight of the pebbles in the cube?
Answers
V = l³ , where l = 6 in
V = 6³ = 216 in³
Each pebble weights on average is 0.5 lb per cubic inch.
Weight = 216 in³ · 0.5 lb/in = 108 lb
Answer:
The total weight of the pebbles in the cube is 108 lb.
what is the solution to -1 -7 ?
Answers
When you see a negative minus a negative, pretend both negatives are positive and just add them.
Show me how to make 33 in four different ways
Answers
11*3
10*3+3
60-30+3
(sorry if these didn't help i'm a beginner and i'm in 7th grade)
The law of cosines is a^2+b^2-2abcos(C). Find the value of 2abcos(C).
A. 37
B. -40
C. 40
D. 20
Answers
and surely you know how much that is.
Hello!
Can I get some help with that question please. I don't think I did it right, sadly.
Thank you!
Don't forget to show your work and give as much details possible.
Answers
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
The bear population increases at a rate of 2% each year. There are 1573 bears this year. Which function models the bear population?
Answers
The solution is, the growth factor b is, 1.02
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
Using the formula:
P = P0(1+r)^t
where
P0 is the initial population
r is the rate in decimal
b = 1+r is the growth factor
t is the time in years.
As per the statement:
the bear population increases at a rate of 2% each year there are 1573 bears this year,
⇒P0 = 1573,
r = 2% = 0.02
then;
solving using the formula,
we get,
⇒ b = 1.02
Therefore, the growth factor b is, 1.02.
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What is the number 212three in base-two form?
Answers
The correct answer is: B. 10111
To convert the number [tex]\(212_{\text{three}}\)[/tex] to base-two (binary) form, we need to first convert it to base-ten and then convert the base-ten number to base-two.
[tex]\(212_{\text{three}}\)[/tex] in base-ten:
[tex]\[ 212_{\text{three}} = 2 \cdot 3^2 + 1 \cdot 3^1 + 2 \cdot 3^0 = 18 + 3 + 2 = 23_{10} \][/tex]
Now, we convert [tex]\(23_{10}\)[/tex] to base-two:
[tex]\[ 23_{10} = 16 + 4 + 2 + 1 = 2^4 + 2^2 + 2^1 + 2^0 = 10111_{2} \][/tex]
Final answer:
The number 212 in base three (212three) converts to 17 in decimal, which is represented as 10001 in binary notation (base-two).
Explanation:
The number 212 in base three (2123) needs to be converted into base-two form (binary). Converting from base three to base two requires understanding each digit's place value in base three and then converting that to binary. Starting from the rightmost digit to the left, we have:
The units place (30), with a value of 2The threes place (31), also with a value of 2The nines place (32), with a value of 1So, we have:
2123 = (1 × 32) + (2 × 31) + (2 × 30)
2123 = (1 × 9) + (2 × 3) + (2 × 1)
2123 = 9 + 6 + 2 = 17 in decimal.
Now we need to find the binary representation of 17:
17 divided by 2 is 8 with remainder 1 (20)8 divided by 2 is 4 with remainder 0 (21)4 divided by 2 is 2 with remainder 0 (22)2 divided by 2 is 1 with remainder 0 (23)1 divided by 2 is 0 with remainder 1 (24)So, the binary equivalent is 1(24)0(23)0(22)0(21)1(20), which is 100012.
Find the indicated probability. round to three decimal places. a test consists of 10
a. True
b. False questions. to pass the test a student must answer at least 6 questions correctly. if a student guesses on each question, what is the probability that the student will pass the test?
Answers
To answer this problem, we use the binomial distribution formula for probability:
P (x) = [n! / (n-x)! x!] p^x q^(n-x)
Where,
n = the total number of test questions = 10
x = the total number of test questions to pass = >6
p = probability of success = 0.5
q = probability of failure = 0.5
Given the formula, let us calculate for the probabilities that the student will get at least 6 correct questions by guessing.
P (6) = [10! / (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10! / (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10! / (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10! / (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10! / (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total Probability = 0.376953 = 0.38 = 38%
There is a 38% chance the student will pass.
PLEASE HELP ON THESE ILL GIVE 20 POINTS AND A BRAINLIEST IF YOUR CORRECT!!
Variation is a term that is used to describe __________.
A.
how repetitive a data set is
B.
how large or small a data set is
C.
how spread out or scattered a data set is
D.
how different a data set is from other data sets
Answers
A test consists of 10 problems and students are told to answer any 4 of these questions. In how many different ways can they choose the 4 questions?
Answers
nCr = n! / (r!)(n - r)!
This is read as "combination of n taken r". In this item, n = 10 and r = 4. Substituting the known vaues to the equation,
10C4 = (10!) / (4!)(10 - 4)!
10C4 = 210
Therefore, the number of which is which the questions can be answered is 210.
43% of adults say cashews are their favorite kind of nut. you randomly select 12 adults and ask each to name his or her favorite nut. find the probability that the number who say cashews are their favorite nut is (a) exactly three, (b) at least four, and (c) at most two. if convenient, use technology to find the probabilities.
Answers
This question involves the concept of binomial probability in statistics. The scenarios involve calculating the probability of a certain number of successes (cashew preference) among a set number of trials (12 adults). It's recommended to use a calculator or software tool to perform the calculations.
Explanation:The subject of the query is known as binomial probability which is part of statistics in mathematics. Here, we need to find the probability of 'success' (in this case, the preference of cashews) exactly a set number of times when conducting a set number of trials (12 adults).
(a) Exactly 3: In this scenario, you want exactly 3 out of 12 adults to prefer cashews. Using binomial probability formula, it would be [tex]12C3\times (0.43)^3 \times (0.57)^9.[/tex](b) At least 4: Here, you want 4 or more adults to prefer cashews. You can either calculate separate probabilities for exactly 4, 5, 6, and so on up to 12, and then add them together. Or, you can use the complement rule: 1 - (P(0) + P(1) + P(2) + P(3)).(c) At most 2: In this case, you want 2 or fewer adults to prefer cashews. Similar to (b), you take the probability of 0, 1, and 2 'successes' and add them together.
It's also important to note, the results in these examples would be more accurate if you use a calculator or software like Excel to handle the computations.
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The probability of exactly 3 cashews in a random sample of 12 adults is approximately 19.4%.
The probability of at least 4 cashews is approximately 15.0%.
The probability of at most 2 cashews is approximately 72.0%.
These probabilities were calculated using the binomial probability formula and considering the complementary event for cases with "at least" or "at most" conditions. Technology like calculators or statistical software can be helpful in performing these calculations efficiently.
Determining the Probability of Nut Preference in a Random Sample
In this scenario, we're analyzing the probability of specific outcomes when randomly selecting 12 adults and inquiring about their favorite nut, knowing that 43% prefer cashews. Here's a breakdown of the requested probabilities:
(a) Exactly Three Cashew Preferences:
Imagine having 12 slots to fill with "cashew" or "other." We need 3 "cashew" slots and 9 "other" slots. Using the binomial probability formula, the probability of this specific arrangement is:
P(3 cashews in 12 trials) = (12 choose 3) * (0.43)^3 * (0.57)^9 ≈ 0.194
(b) At Least Four Cashew Preferences:
This includes scenarios with 4, 5, 6, 7, 8, 9, 10, 11, or all 12 adults preferring cashews. We can calculate the probability for each case and sum them up, but a simpler approach is to find the probability of the opposite event (fewer than 4 cashews) and subtract it from 1:
P(at least 4 cashews) = 1 - P(fewer than 4 cashews)
P(at least 4 cashews) ≈ 1 - (0.194 + 0.237 + 0.184 + 0.115 + 0.063 + 0.034 + 0.015 + 0.006 + 0.002) ≈ 0.150
(c) At Most Two Cashew Preferences:
This includes scenarios with 0, 1, or 2 adults preferring cashews. Similar to (b), we can calculate the probability for each case and sum them up:
P(at most 2 cashews) = P(0 cashews) + P(1 cashew) + P(2 cashews)
P(at most 2 cashews) ≈ 0.237 + 0.299 + 0.184 ≈ 0.720
Is #7 correct? Please explain.
Answers
Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16).
What is the y-value of P'?
Answers
translated according to the rule (x, y) → (x – 2, y – 16)
P' will be:
P'(–4, -10)
So y value will be - 10
hope it helps
the fraction 1/9 produces a repeating decimal 0.1 ? true or false
Answers
[tex]1.9 = 0.11111111[/tex]
So yes, 1/9 produces a repeating decimal 0.1...
What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of ab and . bc
Answers
AC = 3
AB = 4
BC = 5
The coordinates of the vertices of the triangle are A ( 2 , 2 ) , B ( 6 , 2 ) and C ( 2 , -1 )
What is a Triangle?A triangle is a plane figure or polygon with three sides and three angles.
A Triangle has three vertices and the sum of the interior angles add up to 180°
Let the Triangle be ΔABC , such that
∠A + ∠B + ∠C = 180°
The area of the triangle = ( 1/2 ) x Length x Base
For a right angle triangle
From the Pythagoras Theorem , The hypotenuse² = base² + height²
if a² + b² = c² , it is a right triangle
if a² + b² < c² , it is an obtuse triangle
if a² + b² > c² , it is an acute triangle
Given data ,
Let the triangle be represented as ΔABC
Now , the coordinates of the triangle are
A ( 2 , 2 ) , B ( 6 , 2 ) and C ( 2 , -1 )
And , length of AB is given by the distance formula .
Distance D = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²
AB = √ ( 16 + 0 ) = 4 units
BC = √ ( 16 + 9 ) = 5 units
Hence , the lengths of AB and BC are 4 and 5 units respectively
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Find the value of n in the equation 6.2n – 3.7n = 85 + 45. A. 16 B. 52 C. 13.13 D. 325
Answers
2.5n=130
N=130/2.5
N=52
The answer is B. Hope this helps!
How many of each position fantasy football?
Answers
In standard fantasy football, each team incorporates a variety of positions including a Quarterback, Running Backs, Wide Receivers, a Tight End, a Flex, Defense/Special Teams, a Kicker and bench spots.
Explanation:In standard fantasy football, each team is composed of a variety of positions: 1 Quarterback (QB), 2 Running Backs (RB), 2 Wide Receivers (WR), 1 Tight End (TE), 1 Flex (which can be a RB, WR, or TE), 1 Defense/Special Teams (DST), and 1 Kicker (K). In most cases, you also have bench spots for subs or injured players, usually 6-7. These numbers can vary depending on the rules of your fantasy league.
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