How Do You Round In Molar Mass ​

Using Charles's Law, the volume of argon gas at standard temperature (0°C) after initial conditions of 22.8 mL at 48°C is calculated to be approximately 19.5 mL.

The student is asking for help with the concept of how gas volume changes with temperature at constant pressure, a principle known as Charles's Law. Since the question involves argon gas, a noble gas, and relates to changes in temperature and volume, this is a Chemistry subject, typically studied in high school.

According to Charles's Law, the volume of a gas is directly proportional to its temperature when pressure is held constant. The formula relating initial and final volumes and temperatures is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature. Here, T must be in Kelvin.

The standard temperature (STP) is defined as 0 degrees Celsius or 273.15 K. To find the volume at STP (V2) for the argon gas, we first convert the initial temperature from degrees Celsius to Kelvin:

Now, we apply Charles's Law:

V1/T1 = V2/T2 -> (22.8 mL / 321.15 K) = V2 / 273.15 K

Multiplying both sides by 273.15 K to solve for V2 gives:

V2 = (22.8 mL * 273.15 K) / 321.15 K

V2 ≈ 19.5 mL

So, at standard temperature, this sample of argon would occupy approximately 19.5 mL.

All living beings are made up of cells. or Cell is the most basic unit of life. or All cells must come from pre-existing cells.

I hoped I helped a little

a) Answer:

= 225 mL

Explanation:

Using Boyle's law of gases;

The volume of a fixed mass of a gas is inversely proportional to its pressure at constant temperature.

Therefore;

P1V1 = P2V2

in this case; let the initial pressure be P;

Therefore; V1 = 450 mL, P1 = P, V2 = ? and P2 = 2P

Thus;

V2 = P1V1/P2

     = (P×450)/ (2P)

     = 225 mL

Therefore, the new volume will be 225 mL

b) Answer;

=1800 mL

Explanation;

Let the initial pressure be P;

Therefore; V1 = 450 mL, P1 = P, V2 = ? and P2 = 1/4P

Thus;

V2 = P1V1/P2

     = (P×450)/(0.25P)

      = 1800 mL

Thus, when the pressure is reduced to one-fourth of its original, the new volume will be 1800 mL.

Given that the initial volume of the gas is 450 mL, the new volume of the gas obtained based on the given data are:

A. The new volume of the gas when the pressure is doubled is 225 mL

B. The new volume of the gas when the pressure is reduced to one-fourth of its original value is 1800 mL

P₁V₁ / T₁ = P₂V₂ / T₂

Since the temperature is constant, we have:

P₁V₁ = P₂V₂

P × 450 = 2P × V₂

Divide both side by 2P

V₂ = (P × 450) / 2P

V₂ = 450 / 2

V₂ = 225 mL

P₁V₁ / T₁ = P₂V₂ / T₂

Since the temperature is constant, we have:

P₁V₁ = P₂V₂

P × 450 = ¼P × V₂

450P = PV₂ / 4

Cross multiply

450P × 4 = PV₂

Divide both side by P

V₂ = (450P × 4) / P

V₂ = 450 × 4

V₂ = 1800 mL

Learn more about gas laws:

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Answer: 0.548J/g°C

Explanation:

Q = s × m × DeltaT

Q = Heat (J)

S = Specific Heat Capacity

M = mass (g)

DeltaT = Change in temperature (°C)

0.158Kg x 1000 = 158g

2.510J = s x 158g x (61°C-32°C)

2.510J/(158g x 29°C) = s

S = 0.54779.... J/g°C

S = 0.548 J/g°C

The answer is:

The approximate volume is 9.84 L.

[tex]V=9.84L[/tex]

Since we are given the numer of moles, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

[tex]PV=nRT[/tex]

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant, which is equal to:

[tex]R=0.082\frac{atm.L}{mol.K}[/tex]

So, we are given the information:

[tex]n=1.5mol\\Temperature=300K\\Pressure=3.75atm[/tex]

Now, substituting the given information and isolating the Volume from The Ideal Gas Law equation, we have:

[tex]PV=nRT[/tex]

[tex]V=\frac{nRT}{P}[/tex]

[tex]3.75atm*V=1.5mol*0.082*\frac{atm.L}{mol.K}*300K[/tex]

[tex]V=\frac{ 1.5mol*0.082*\frac{atm.L}{mol.K}*300K}{3.75atm}\\\\V=\frac{36.9atm.L}{3.75atm}=9.84L[/tex]

So, the approximate volume is 9.84 L.

[tex]V=9.84L[/tex]

Have a nice day!

False100% sure of it

I believe the answer is A

Answer:

The bottom is troposhere the next is sratoshere,mesosphere,thermosphere then exoshere

Explanation:

The study of the atmosphere is called metrology. There are different types of components present in the atmosphere and these are gases and impure particles.

According to the question, the layers name is as follows:-

Hence, the answer is mentioned above.

For more information about the layers, refer to the link:-

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Answer:

= 3,702.816 Joules

Explanation:

Heat absorbed by water is equivalent to heat released by copper.

Heat absorbed is given by:

Q = mcΔT

where m is the mass, c is the specific capacity and ΔT is the change in temperature.

Mass = 1248 g

ΔT = 45°C - 22°C = 23°C

c = 0.129j/g°c

Heat = 1248 g × 23°C × 0.129j/g°C

        = 3,702.816 Joules

The heat required can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.

The amount of heat required to raise the temperature of a substance can be calculated using the formula:

Q = mcΔT

Where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the temperature change. In this case, the mass of the gold is 1.248 kg, the specific heat capacity is 0.129 J/g°C, and the temperature change is from 22.0°C to 45.0°C. Converting the mass to grams (1.248 kg = 1248 g), we can calculate the heat energy:

Q = (1248 g)(0.129 J/g°C)(45.0°C - 22.0°C) = 19230.72 J

Therefore, the total amount of heat required to raise the temperature of 1.248 kg of gold from 22.0°C to 45.0°C is 19230.72 Joules.

Answer:

612 g

Explanation:

concentration or molarity is the number of moles of solute in 1 L of solution

the molarity of the solution is 12.5 M

therefore there are 12.5 mol in 1 L of solution

in 1 L of solution there are 12.5 mol

therefore in 3.5 L there are - 12.5 mol/L x 3.5 L = 3.6 mol

molar mass of AgNO₃ is 170 g/mol

mass of 3.6 mol of AgNO₃ is - 170 g/mol x 3.6 mol = 612 g

612 g of AgNO₃ is needed to make a 12.5 M solution

Answer:

An acid would be soemthing that starts with H (hydrogen)

That is just the way it is written chemically.

Hope this helped!

Explanation:

Answer:

7.5 mol of hydrogen would be needed to consume the available nitrogen.

Explanation:

3H₂ + N₂ → 2NH₃

it is clear that 3mol of hydrogen react with 1 mol of Nitrogen to give 2 mol of ammonia.

for H₂:

number of moles = mass / molar mass = (7.00 g) /  (2.00 g/mol) = 3.5 mol.

for N₂:

number of moles = mass / molar mass = (70.00 g) /  (28.00 g/mol) = 2.5 mol.

using cross multiplication

1 mol of  N₂ needs → 3 mol of H₂

2.5 mol of  N₂ needs → ??? mol of H₂

∴ the number of mol of H₂ needed = (3*2.5) / 1 = 7.5 mol

So, the right choice is:

7.5 mol of hydrogen would be needed to consume the available nitrogen.

Answer:

Its A

Explanation:

Answer:

A. by lowering the activation energy

Explanation:

Answer:

A. By Lowering the activation energy

Explanation

edmentum/plato family!

give me likes plz!

Lunar eclipse

A solar eclipse is when the Moon is between the Earth and the Sun, and a lunar eclipse is when the Earth is between the Moon and the Sun.

Answer: 4 mol

C + 2S = CS2

1 mol of CS2 contains 2 mol of sulfur

So 2 mol of cs2 contains 2*2 mol of S

2mol CS2 x 2 mol S/ 1 mol CS2 =

4 mol S

Final answer:

In 2.00 moles of carbon disulfide (CS2), there are 4.00 moles of sulfur atoms because each molecule of CS2 contains two sulfur atoms.

Explanation:

The question asks how many moles of sulfur atoms are present in 2.00 moles of carbon disulfide (CS2). Carbon disulfide is a chemical compound made up of one carbon atom and two sulfur atoms per molecule (CS2).

To determine the moles of sulfur atoms, we use the mole ratio from the molecular formula, which is 1 mole of CS2 contains 2 moles of sulfur (S). Accordingly, for 2.00 moles of CS2, we would have:

2.00 moles CS2 × (2 moles S / 1 mole CS2) = 4.00 moles of sulfur atoms.

Answer:

Solution X might be a solution of carbonate ions [tex]\text{CO}_3^{2-}\;(aq)[/tex].

The question doesn't tell much about the positive ion in solution X. The ion itself shall not react with carbonate ions [tex]\text{CO}_3^{2-}\;(aq)[/tex] to form a precipitate. For that, cations from group 1 metals will work. For example, X can be a solution of sodium carbonate, which contain a large number of sodium ions [tex]\text{Na}^{+}\;(aq)[/tex].

Explanation:

Start with the first observation:

"Solution X mixed with magnesium chloride solution to form a white precipitate."

A solution of magnesium chloride [tex]\text{MgCl}_2\;(aq)[/tex] contains both

Both may react to form a white precipitate.

[tex]\text{Mg}^{2+}\;(aq)[/tex] ions:

[tex]\text{Cl}^{-}\;(aq)[/tex] ions:

Second observation:

"The white precipitate obtained and reacted with [dilute] HCl to give [colorless] gas bubbles."

The carbon dioxide gas from the reaction between [tex]\text{MgCO}_3\;(s)[/tex] and dilute HCl reacts with lime water (saturated calcium hydroxide [tex]\text{Ca}(\text{OH})_2\;(aq)[/tex] solution in water) to form the white-colored, insoluble salt calcium carbonate [tex]\text{CaCO}_3\;(s)[/tex]. The [tex]\text{CaCO}_3\;(s)[/tex] precipitate will turn the lime water milky.

In summary,

[tex]\rm \underbrace{\text{Na}_2\text{CO}_3\;(\rm aq)}_{\text{White Precipitate}} + \text{MgCl}_2 \;(aq) \to 2\;\text{NaCl}\;(aq) + \underbrace{\text{MgCO}_3\;(\rm s)}_{\text{White Precipitate}[/tex].

[tex]\rm \underbrace{\text{MgCO}_3\;(\rm s)}_{\text{From Solution X}} + \text{HCl} \;(aq) \to \text{MgCl}_2\;(aq) + \rm H_2O\;( aq) + \underbrace{{\rm CO_2}\;(g)}_{\rm Colorless\;Gas}[/tex].

[tex]\rm Ca(OH)_2\;(aq)+CO_2\;(g)\to \underbrace{\rm CaCO_3\;(s)}_{\begin{aligned}&\small\text{Turns Lime}&\\[-0.5em]&\small\text{Water Milky}&\end{aligned}} + H_2O\;(l)[/tex].

Answer:

12 moles of cesium xenon heptafluoride

Explanation:

The reaction of cesium fluoride with xenon hexafluoride is CeF + XeF6 -> CeXeF7 and the reaction is balanced as written. So the mole ratio is 1:1:1. We are given 12 moles of CeF and 14 moles of XeF6 are reacting, but after the 12 moles of CeF react completely, the reaction will stop as we have run out of one of our reactants. So only 12 moles of CeXeF7 will be produced.

Final answer:

12 moles of cesium xenon heptafluoride can be produced from the reaction of 12 mol cesium fluoride with 14 mol xenon hexafluoride, assuming a 1:1 molar ratio in the reaction and complete consumption of reactants.

Explanation:

To determine how many moles of cesium xenon heptafluoride (CsXeF₇) can be produced from 12 mol cesium fluoride (CsF) with 14 mol xenon hexafluoride (XeF₆), we first need to know the balanced chemical reaction. This reaction can be expressed as:

CsF + XeF₆ → CsXeF₇

If we assume 100% efficiency and that all reactants are used up completely, we would expect 12 moles of CsF to fully react with 12 moles of XeF6 since the reaction is in a 1:1 molar ratio. Therefore, the amount of product formed, CsXeF₇, would be 12 moles. The remaining 2 moles of XeF₆ will not react as there is no additional CsF to react with.

Answer:

Absolute zero is the lowest possible temperature of a gas.

Explanation:

Absolute zero is the lowest possible temperature, at which all molecular motion theoretically stops. Its actual implications, especially concerning the volume of a gas, don't fully comply with classical interpretations and delve into the realm of quantum physics.

Absolute zero is the lowest possible temperature at which all molecular motion ceases. It is defined as 0 on the Kelvin scale and equivalent to -273.15 degrees Celsius. This temperature is theoretically the point at which a gas would have no kinetic energy.

It's important to understand that while at temperatures near absolute zero, the behavior of real gases deviates from that predicted by ideal gas laws like Charles's Law or Amonton's Law. These deviations occur because the volume of the gas molecules themselves becomes appreciable relative to the total volume occupied by the gas and the collisions between the molecules can no longer be ignored.

However, these assumptions become less valid as temperatures approach absolute zero. The volume of a gas at absolute zero is a matter of quantum physics, and doesn't strictly comply with classical interpretations of gas behavior.

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Answer:

Precipitate.

Explanation:

The reaction between AgNO₃ and NaCl:

AgNO₃ + NaCl → AgCl↓ + NaNO₃

It will produce insoluble substance (AgCl) which is considered as a precipitate.

Answer:

Newton 3rd Law of Motion or the Law of Force Pairs

(An applied force)

Force is a phenomenon that creates a push or pull that has both magnitude and direction. No push or pull exists in isolation, and multiple forces interacting can have cumulative effects. The force can vary in magnitude and can manifest both as a contact force and a field force.

A force is a push or pull that acts upon an object as a result of its interaction with another object. It has both magnitude and direction, therefore it's a vector quantity. Objects and systems are moved by forces. This area comes under the study of dynamics.

Examples of a force can include a person pushing a table (a contact force), or the gravitational pull of the Earth on a falling object (a field force). Forces have been categorized into many types such as push, pull, thrust, lift, weight, friction, and tension.

Keep in mind that no push or pull occurs in isolation (Newton's third law). For instance, when you are pushing a wall, the wall exerts an equal and opposite force on you.

When multiple forces act on an object, they add up like vectors. If two forces push in different directions on an object, the total force will be in the direction of the resultant force.

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Answer:

The cube will contain 8000 mL of the fluid.

Explanation:

where, L is the edge length.

∴ V of the cube = L³ = (20.0 cm)³ = 8000 cm³.

Knowing that 1.0 cm³ = 1.0 mL.

∴ The cube will contain 8000 mL of the fluid.

Answer:

97.54

Explanation:

Molar mas of cu (oh) 2

Cu = 63.54

O x 2  = 16 x 2 = 32

H x 2 = 1 x 2 = 2

TOTAL = 97.54

A) If volume increases, temperature increases

The law is V/T, meaning the two values are directly proportional, as one increases, the other increases too.

The statement which best describes Charles law is: A) If volume increases, temperature increases.

Charles law states that when the pressure of an ideal gas is kept constant, the volume of a gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles law is given by this formula;

[tex]V\;\alpha \;T\\\\V=kT[/tex]

This ultimately implies that, as the volume of an ideal gas increases, its temperature also increases in accordance with Charles law.

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Answer:

Explanation:molar mass of N2=28

Volume occpied at stp=22.4 so 28/22.4=1.25 so mass nitrogen will be 56 multiply 1.25 =70g

The answer is B.

Each of the points or vertex represent a carbon atom. Answer choice B is the only choice that has 8.

Answer:

1.8 L.

Explanation:

2H₂(g) + O₂(g) → 2H₂O(g),

It is clear that 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.

It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.

using cross multiplication:

1.0 mol of H₂ represents → 22.4 L.

??? mol of H₂ represents → 3.6 L.

∴ 3.6 L of H₂ represents = (1.0 mol)(3.6 L)/(22.4 L) = 0.1607 mol.

Using cross multiplication:

2.0 mol of H₂ react completely with → 1.0 mol of O₂, from stichiometry.

0.1607 mol of H₂ react completely with → ??? mol of O₂.

∴ The no. of moles of O₂ = (1.0 mol)(0.1607 mol)/(2.0 mol) = 0.08036 mol.

1.0 mol of O₂ represents → 22.4 L, at STP.

0.08036 mol of O₂ represents → ??? L.

∴ The no. of liters of O₂ will be produced = (0.08036 mol)(22.4 L)/(1.0 mol) = 1.8 L.

Answer:

The answer is 1.8 L

Answer: A, B, D

Explanation:

all of these examples show matter moving from a high volume of matter, to low volume of matter. When the molecules of the paint, toast, and chemicals were released, they will try to disperse away from the high concentration

Examples of diffusion include the spread of marker odor in a classroom, the smell of burnt toast in a kitchen, and the detection of toxic fumes in a town miles from a chemical factory. Diffusion is the movement of particles from an area of higher concentration to an area of lower concentration.

Examples of diffusion in the list provided include:

Option C) is not an example of diffusion; it is an example of the gas contracting due to lower kinetic energy when cooled. Option E) concerns the expansion of a container with gas when heated due to increased pressure, not diffusion.

The answer is:

The new volume is 2.84 L.

[tex]V_{2}=2.84L[/tex]

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law,  and Boyle's Law.

The law is defined by the following equation:

[tex]\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}[/tex]

Where,

[tex]P_{1}[/tex] is the first pressure.

[tex]V_{1}[/tex] is the first volume.

[tex]T_{1}[/tex] is the first temperature.

[tex]P_{2}[/tex] is the second pressure.

[tex]V_{2}[/tex] is the second volume.

[tex]T_{2}[/tex] is the second temperature.

So, we are given the following information:

[tex]V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K[/tex]

Then, isolating the new volume, and substituting, we have:

[tex]\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L[/tex]

Hence, the new volume is 2.84 L.

[tex]V_{2}=2.84L[/tex]

Have a nice day!

Answer:

45) the answer is C.

46) The calculation of quantities in chemical reaction is called Stoichiometry .

47) The phase changed from solid to gas so I think the answer is A.

48) The phase changed from solid to gas as well so I think that the answer is A again.

49) Applying the formula n = m/M, we have n = 1.5 moles, therefore the answer is D.

50) C2H4 + 3O2 -> 2H2O + 2CO2

The answer is C.

51) The answer is C.

52) 2NaHCO3 + CaCl2 -> CaCO3 + H2O + 2NaCl + CO2

Hopefully I got all of them correct.