According to Hooke's Law, the distance when a spring is stretched by a hanging object varies directly as the weight of the object. We can use this information to find the distance when the weight is 7 kg. We get 84 cm.
Explanation:Hooke's Law states that the distance d when a spring is stretched by a hanging object varies directly as the weight w of the object.
This means that if you double the weight, the distance will also double.
Mathematically, we can express this relationship as d = kw, where k is the constant of variation.
To find the value of k, we can use the given information: when the weight is 3 kg, the distance is 38 cm.
Plugging these values into the equation, we get 38 = 3k.
Solving for k, we divide both sides by 3 to get k = 12.
Now, we can find the distance when the weight is 7 kg by plugging this value into the equation: d = 12 * 7 = 84 cm.
An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. What is the radius of the circle ? helpppppp me
materiel in which the relative location of the atom is fixed are
How did anchient greeks spend there free time??
From Wien's law, at what wavelength does Jupiter's thermal emission peak?
µm In what part of the electromagnetic spectrum does this wavelength lie?
a man drops a ball downside from the roof of a tower of height 400 meters.At the same time another ball is thrown upside with a velocity 50 m/s from the surface of the tower,find when and at which height from the surface of the tower the two balls meet together.
The two balls meet at approximately 272.5 meters above the surface of the tower after around 5.1 seconds.
To determine when and at what height the two balls meet, we'll analyze their motions individually and then together.
Step 1: Motion of the dropped ball
For the ball dropped from the roof at a height of 400 meters, the equation of motion under gravity is:
h₁ = 400 - 0.5 * g * t²
where:
h₁ is the distance traveled by the dropped ball in meters.
g is the acceleration due to gravity (9.8 m/s²).
t is the time in seconds.
Putting in the values, h₁ = 400 - 4.9 t²
Step 2: Motion of the thrown ball
For the ball thrown upwards with an initial velocity of 50 m/s, the equation of motion is:
h₂ = 50t - 0.5 * g * t²
where:
h is the distance traveled by the thrown ball in meters.
Putting in the values, h₂ = 50t - 4.9 t²
Step 3: Equating the distances
The balls meet when their total distance is 400 meters, so:
h₁ + h₂ = 400
Substituting the equations for h₁ and h₂, 400 - 4.9 t² + 50t - 4.9 t² = 400
Simplifying, -9.8 t² + 50t = 0
Factoring out t, t(50 - 9.8t) = 0
Thus, t = 0 (initial point, not useful) or t = 50 / 9.8 ≈ 5.1 seconds.
Step 4: Calculating the height
Using t ≈ 5.1 seconds in any height equation:
h₁ = 400 - 4.9 * (5.1)²
h₁ = 400 - 127.5
h₁ ≈ 272.5 meters
Therefore, the two balls meet approximately 272.5 meters above the surface of the tower after about 5.1 seconds.
What causes the electric charges to flow from one end of the battery to the other?
a balance in electric potential
a balance in resistance
a difference in electric potential
a difference in resistance
Answer:
c. a difference in electric potential
Explanation:
A 521-kg meteor is subject to a force of 2520 N. What is its acceleration?
Answer:
Acceleration, [tex]a=4.83\ m/s^2[/tex]
Explanation:
It is given that,
Mass of the meteor, m = 521 kg
Force acting on the meteor, F = 2520 N
Let a is the acceleration of the meteor. It can be calculated using the Newton's second law of motion. According to this law the force acting on an object is equal to the product of mass and acceleration with which it is moving. Mathematically, it is given by :
[tex]F=m\times a[/tex]
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{2520\ N}{521\ kg}[/tex]
[tex]a=4.83\ m/s^2[/tex]
So, the acceleration of the meteor is [tex]4.83\ m/s^2[/tex]. Hence, this is the required solution.
The density of liquid oxygen at its boiling point is 1.14 \rm{kg/L} , and its heat of vaporization is 213 \rm{kJ/kg} .
How much energy in joules would be absorbed by 3.0 L of liquid oxygen as it vaporized?
To vaporize 3.0 L of liquid oxygen with a density of 1.14 kg/L and a heat of vaporization of 213 kJ/kg, 728460 joules of energy would be absorbed.
The student is asking about the amount of energy required to vaporize a certain volume of liquid oxygen. Given that the density of liquid oxygen at its boiling point is 1.14 kg/L, and its heat of vaporization is 213 kJ/kg, we can calculate the energy needed for vaporization using these two properties.
First, calculate the mass of 3.0 L of liquid oxygen:
Mass = Density times Volume = 1.14 kg/L times 3.0 L = 3.42 kg
Then, calculate the energy required for vaporization:
Energy = Mass times Heat of Vaporization = 3.42 kg times 213 kJ/kg = 728.46 kJ
Since 1 kJ = 1000 J, we can convert the energy to joules:
Energy in joules = 728.46 kJ times 1000 J/kJ = 728460 J
Therefore, 728460 joules of energy would be absorbed by 3.0 L of liquid oxygen as it vaporizes.
anyone know any of these please???
The Enlightenment period supported reason over religious beliefs.
Please select the best answer from the choices provided
T F
Having some conceptual trouble with this problem: "A falling object travels one-fourth of its total distance in the last second of its fall. What height was it dropped from?" Would someone please help me set this one up?
Answer:
[tex]H = 273.4 m[/tex]
Explanation:
Let the falling object took "n" seconds to reach the ground and it travels H height
So we will have
[tex]H = \frac{1}{2}gn^2[/tex]
now we know that it covers one fourth of total height in last second
So we can say that it will cover 3H/4 distance in (n-1) seconds
so we will have
[tex]\frac{3H}{4} = \frac{1}{2}g(n-1)^2[/tex]
now from above two equations
[tex]\frac{4}{3} = (\frac{n}{n-1})^2[/tex]
[tex]1.155(n-1) = n[/tex]
[tex]n = 7.46 s[/tex]
Now we have
[tex]H = \frac{1}{2}(9.81)(7.46^2)[/tex]
[tex]H = 273.4 m[/tex]
Where could convection currents form? Check all that apply.
in a sand dune
in a freshwater lake
in the atmosphere
in outer space
in Earth’s mantle
Answer:
In The Atmosphere
Explanation:
edg2021
What is a measurement of the earth's history divided into time periods?
Forces contribute to the net force on a car rolling down a ramp.
a. Which force supports the car’s weight?
b. Which force accelerates the car down the ramp?
c. Which force acts against the motion of the car?
Which of the following does not contribute to eutrophication ?
A. Sediment
B. Decaying organisms
C. Fertilizer
D. Pollution
The correct answer is A. Sediment
Answer: A. Sediment
Eutrophication is a phenomena in which a water body gets enriched with minerals and nutrients frequently entered into water body due to run-off from the land, which facilitates dense growth of plants especially on the superficial layers of water body. Decaying organisms, fertilizers and pollution all add nutrients and minerals necessary for plant growth specifically remain floating on the superficial layers of water where plant growth takes place but sediments gets settled at the bottom of the water body, the minerals present in it remain settle at the bottom and hence, does not contribute to eutrophication.
Which of the following determine an object's velocity?
A.
speed and direction
B.
direction and acceleration
C.
speed and mass
D.
speed, direction, and acceleration
Speed and direction are the factors that affect an object's velocity.
What do your mean by velocity?The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. A vector quantity, that is. The change in an object's displacement with respect to time is known as velocity.
Displacement / Time = Velocity
The information is ,
Let V be the symbol for an object's velocity.
The measurement of V is now determined as
The concept of speed describes how quickly an object is traveling across a specific distance.
An object's speed just indicates how swiftly or slowly it is moving. It doesn't say which way the object is moving. Speed and direction are both referred to by the word velocity. A vector is an amount of velocity.
Now that the displacement is a vector quantity with direction, the equation for velocity is displacement / time.
As a result, an object's velocity is determined using its speed and direction.
Click here to learn more about velocity.
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In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.18 m. The mug slides off the counter and strikes the floor 1.20 m from the base of the counter. With what velocity did the mug leave the counter? What was the direction of the mug's velocity just before it hit the floor?
Physics Help Please:
Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.130kg apple toward astronaut 2 with a speed of vi,1 = 1.07m/s . The 0.160kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.19m/s . Unfortunately, the fruits collide, sending the orange off with a speed of 0.998m/s in the negative y direction.
What are the final speed and direction of the apple in this case?
I already found the speed (1.29m/s) but I cannot find the direction.
Picture is in the reply box.
Thank You
The problem involves applying conservation of momentum principles to a two-dimensional collision between an apple and an orange tossed by astronauts. The final direction of the apple after the collision can be determined using the velocity components and trigonometry, specifically the arctan function. To provide the direction, additional details like initial direction are needed.
Explanation:The student is seeking help with a physics problem involving the concepts of momentum conservation and two-dimensional collisions. In this problem, two astronauts (in a hypothetical scenario) are tossing an apple and an orange to each other when the fruits collide in space. The provided information lets us analyze the collision using the principles of momentum to find the final direction of the apple after the collision.
To solve for the direction of the apple after the collision, we must apply the law of conservation of momentum in two dimensions because the collision sends the objects off in different directions. Since there are no external forces, the total momentum in each direction (x and y) should remain constant. We use the before-collision and after-collision momenta to form equations and solve for the final velocity components of the apple, allowing us to calculate the final direction using trigonometry.
However, to provide the exact direction, a diagram or more information indicating the initial directions of the fruits would be required. Assuming the initial throw was along the x-axis and the final velocity of the orange is given in the y-axis, you can apply the arctan function to the velocity components of the apple to find the direction in terms of angle from the x-axis.
Dalton was one of the first scientists to experimentally prove that
a. the nucleus and the electron have different electrical charges.
b. most of the atom is made of "empty space".
c. the chemical and physical properties of an element correlate with its mass and size.
d. the atom is composed of smaller pieces.
when a bullet is fired, does gunpowder only travels back towards the shooter
Answer:
false
Explanation:
Jamal plugged his radio into the wall. The radio's plug had copper wires surrounded by rubber. The rubber protects Jamal from______?
me answer be ye Conduction
You move a 75-kg box 35 m. This requires a force of 90 N. How much work is done while moving the box?
Answer: 3150 J
Explanation:
Work is the result when a force acts on an object and moves it by some distance and it is calculated in Joules.
So,
Distance covered by the box = 35m
Force applied on the box = 90N
Formula:
The force and the distance covered was in the same direction, so the angle between them is 0°. The work can be found using the formula:
W = Fd cosθ
W = Fd cos0
W = Fd(1)
W= (90) * (35)
W = 3150 J
Would you be doing any more work by going up the stairs twice as fast?
Two identical small cars (car A & car B) have a head-on collision. Which scenario is true?
A. Car A exerts a greater force on car B than car B exerts on car A.
B. Car B exerts a greater force on car A than car A exerts on car B.
C. The force that car A exerts on car B and the force that car B exerts on car A are the same magnitude.
Answer:
The force that car A exerts on car B and the force that car B exerts on car A are the same magnitude.
Explanation:
There can be two types of collision i.e. elastic and inelastic collision. Elastic collision is also known as head-on collision. In this type of collision, the momentum and kinetic energy before and after the collision remains the same.
If two identical small cars (car A & car B) have a head-on collision, then the force that car A exerts on car B and the force that car B exerts on car A are the same magnitude. It is due to Newton's third law of motion which states that there is an equal and opposite reaction when one object applies a force on another object. So, the correct option is (c).
Consider the observation the andromeda galaxy, a member of our local group, is moving toward us. why doesn’t this observation contradict the idea that the universe is expanding?
In a scene in an action movie, a stuntman jumps from the top of one
building to the top of another building 4.0 m away. After a running start,
he leaps at a velocity of 5.0 m/s at an angle of 15° with respect to the flat
roof. Will he make it to the other roof, which is 2.5 m lower than the
building he jumps from? ...?
Yes, the stuntman can jump from one building to the other building.
Further explanation:
The stuntman jump from one building inclined at some angle to the other traversing a parabolic path.
Given:
The velocity of stuntman is 5m/s.
The distance between the buildings is 4m.
The difference in the height of the buildings is 2.5m.
The angle of inclination is [tex]{15^ \circ }[/tex].
Concept used:
When stuntman jumps from the top of one building to the top of other building he start running first then he jump at a velocity of 5m/s inclined at an angle of [tex]{15^ \circ }[/tex] from the horizontal of first building.
The velocity of stuntman has two components [tex]{v_x}[/tex] and [tex]{v_y}[/tex], respectively in the X-direction and in the Y-direction.
The expression for the distance in horizontal direction is given as.
[tex]x = \left( {v\cos \theta } \right)t[/tex]
Rearrange the above expression for time.
[tex]t = \dfrac{x}{{\left( {v\cos \theta } \right)}}[/tex] …… (1)
Here, t is the time of flight, v is the velocity of object and [tex]\theta[/tex] is the angle of inclination.
The expression for the distance in Y-direction is given by the second equation of motion.
[tex]y = ut + \frac{1}{2}\left( { - g} \right){t^2}[/tex]
Here, u is the velocity in Y-direction and (–g) is the acceleration due to gravity directed in the downward direction.
The expression for the component of velocity in Y-direction is given as.
[tex]u = v\sin \theta[/tex]
Substitute [tex]v\sin\theta[/tex] for u in the above expression.
[tex]y = \left( {v\sin \theta } \right)t + \frac{1}{2}\left( { - g} \right){t^2}[/tex] …… (2)
Substitute 5m/s for v, 4m for x and [tex]{15^ \circ }[/tex] for in equation (1).
[tex]\begin{aligned}t&=\frac{{4\,{\text{m}}}}{{\left({\left( {5\,{\text{m/s}}}\right)\left( {\cos {{15}^ \circ }}\right)}\right)}}\\&=0.828\,{\text{s}}\\\end{aligned}[/tex]
Substitute [tex]0.828\,{\text{s}}[/tex] for t, 5m/s for v, [tex]9.8\,{\text{m/}}{{\text{s}}^{\text{2}}}[/tex] for g and [tex]{15^ \circ }[/tex] for [tex]\theta[/tex] in equation (2).
[tex]\begin{aligned}y&=\left( {\left( {5\,{\text{m/s}}} \right)\sin \left( {{{15}^ \circ }} \right)} \right)\left( {0.828\,{\text{s}}} \right) + \frac{1}{2}\left( { - 9.8\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right){\left( {0.828\,{\text{s}}} \right)^2}\\&=1.071 - 3.36 \\&=- 2.29\,{\text{m}}\\\end{aligned}[/tex]
Thus, the stuntman can jump from one building to another because its vertical distance is less than the difference in height of buildings.
Learn more:
1. Motion under force https://brainly.com/question/6125929.
2. Projection of ball https://brainly.com/question/11023695.
3. Conservation of momentum https://brainly.com/question/9484203.
Answer Details:
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords:
Force, motion, parabolic path, acceleration due to gravity, time of flight, angle of inclination, inclined plane, buildings, height difference, cliff, horizontal direction, vertical direction, 2.29 m, 2.3m, 0.828sec.
The question involves calculating whether a stuntman can jump from one rooftop to another using principles of projectile motion. By calculating the horizontal and vertical components of the stuntman's velocity, and the time and distance he will travel, we determine he will fall approximately 2.9 meters. Since the other roof is only 2.5 meters lower, the stuntman will successfully make the jump.
Explanation:The student's question involves determining whether a stuntman can safely jump from one building to another, given his initial velocity, the angle of his jump, and the distance and height difference between the buildings. This is a classic physics problem involving projectile motion, where we consider the horizontal and vertical components of the motion separately. We can ignore air resistance and use the kinematic equations to solve this problem.
Firstly, we need to find the horizontal and vertical components of the initial velocity. The horizontal component, vx, is v × cos(θ), and the vertical component, vy, is v × sin(θ), where v is the initial velocity and θ is the angle of launch. For a jump of 5.0 m/s at 15°:
vx = 5.0 m/s × cos(15°) ≈ 4.83 m/svy = 5.0 m/s × sin(15°) ≈ 1.29 m/sThe time, t, it takes to travel horizontally across the 4.0 m gap is found using t = d / vx, where d is the horizontal distance:
t = 4.0 m / 4.83 m/s ≈ 0.83 s
Now, let's determine if he will drop less than 2.5 m in this time frame. We use the equation of motion for vertical displacement, Δy = vyt + ½gt², with g being the acceleration due to gravity (9.81 m/s²) to find the vertical drop:
Δy = (1.29 m/s × 0.83 s) + (0.5 × -9.81 m/s² × (0.83 s)²) ≈ -2.9 m
The stuntman will fall approximately 2.9 m, thus he will make it to the other roof, which is 2.5 m lower than his initial jump point.
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A 20,000 kg truck traveling at 25 m/s has a head-on inelastic collision with a 1500 kg car traveling at -30 m/s. calculate the initial momentum of the truck.
The distance traveled by an object divided by the time it takes to travel that distance is called
A. Average velocity
B. Average speed
C. Average acceleration
D. Negative acceleration
How do you best determine whether j/m2 and m*s2/N are equivalent units?
Compare the written form of the units to see if they look the same.
Notice that one unit contains joules and other newtons.
Determine if the formula that each unit came from are the same.
Express them both in terms of SI base units.
The units can be best determined by expressing them both in terms of SI base units.
What is SI Unit?The Système International (SI) unit is named after the French word for it. The International System of Units (ISO) is the name of the metric system that is used as the industrial standard for measurements (SI). SI units are crucial for the growth of science and technology.
It is composed of 7 base units, from which 22 derivative units are generated. Either a standard multiple or a fractional quantity can be used to express SI units. Prefix multipliers with powers of 10 in the range from [tex]10^{-24}[/tex] To [tex]10^{24}[/tex] Are used to define these numbers.
Now, according to the question :
J=kg×m²/s²
J/m²=kg/s²
and, N=kg×m/s²
⇒m×s²/(kg×m/s²)
=[tex]s^{4}[/tex]/kg
Hence, after comparing both of them, we can say that they are not equivalent.
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The density (mass/volume) of aluminum is 2.70 mc016-1.jpg 103 kilograms per cubic meter (kg/m3). What is the mass of an aluminum cylinder that has a volume of 1.50 m3?
The mass of the aluminum cylinder is 4,050 kg, obtained by multiplying the given density of aluminum with the given volume of the cylinder.
Explanation:The mass (m) of the aluminum cylinder can be calculated using the formula for density (ρ), which is Density = Mass/Volume. In this case, since the density of the aluminum (ϱ) is 2.70 * 103 kilograms per cubic meter (kg/m3) and the volume (V) of the cylinder is 1.50 m3, we can rearrange the formula to find mass such that Mass = Density * Volume. Substituting the given values, we get m = 2.70 * 103 kg/m3 * 1.50 m3 = 4,050 kg. Therefore, the mass of the aluminum cylinder is 4,050 kg.
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