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Helppppppppppppppppp

Answers

Answer 1

Answer:

C

Step-by-step explanation:

Note that (f + g)(x) = f(x) + g(x)

f(x) + g(x)

= 4x + 1 + x² - 5 ← collect like terms

= x² + 4x - 4 → C


Related Questions

Solve for X (simple)

Answers

Answer:

156°

Step-by-step explanation:

This is simply angle on a straight and this angle is 180°

X + 24 = 180

Collect like terms

X = 180 — 24

X = 156°

a new stadium will seat 83,820. There will be 132 different sections. If each section seats same number of people, how many people will each section seat?

Answers

Answer:

635

Step-by-step explanation:

83,820 / 132 = 635

what is the a, b, and r for y=3.6(1.25)^x

Answers

Answer:

a=3.6, v=1.25 and r=25%

Step-by-step explanation:

The given exponential function is

[tex]y = 3.6 {(1.25)}^{x} [/tex]

We compare to the form:

[tex]y = a{(b)}^{x} [/tex]

We have a=3.6, b=1.25

The r is the percentage of increase or decrease.

We realized there is a 25% increase because

[tex]y = 3.6 {(1 + 25\%)}^{x} [/tex]

Hence

[tex]r = 25\%[/tex]

9+3x=6(3-x) what is the answer

Answers

Answer:

x = 1

Step-by-step explanation:

9 + 3x = 18 - 6x

3x + 6x = 18 - 9

9x = 9

X = 1

Answer:

Step-by-step explanation:

9+3x =6(3-x)

9+3x =6 ×3 - 6x

9+3x =18 -6x

Collect like terms

9-18= -6x-3x

-9 =-9x

Divide both sides by -9

-9/-9 =-9x/-9

Minus cancels minus and 9 divided by 9 is 1 on both sides

1 =x

x =1

A degree may seem like a very small unit but an error of one degree in measuring an angle may be very significant. For example, suppose a laser beam directed toward the visible center of the moon misses its assigned target by the amounts specified below. How far is it (in miles) from its assigned target in each case? (Use 234,000 miles as the distance from the surface of the earth to the surface of the moon.)
a: 1 degree
b: 30” (that’s 0 degree 0’ 30”)

Answers

To calculate the distance by which a laser beam misses its target on the moon due to an angular error, one can use the tangent function with the Earth-moon distance. For an error of 1 degree, it would miss by approximately 4,080 miles, and for an error of 30 arcseconds, by about 34 miles.

To find out how far a laser beam directed toward the center of the moon misses its target by 1 degree, we can use a simple trigonometric calculation. Since we are dealing with a right-angled triangle with the Earth-moon distance as one leg (the adjacent leg in this case), and we want to find the opposite leg which represents the distance on the moon's surface from the intended target, we can use the tangent function.

For an error of 1 degree:

Convert the degree to radians, because trigonometric functions in calculators usually use radians. There are π radians in 180 degrees, so 1 degree is (π/180) radians.

Use the formula distance = tangent of the angle in radians × Earth-moon distance. So distance = tan(1° × (π/180)) × 234,000 miles.

Calculate the tangent of 1° in radians (approximately 0.01745) and multiply by 234,000 miles.

The result is approximately 4,080 miles.

For an error of 30 arcseconds (30″):

There are 60 arcseconds in 1 arcminute and 60 arcminutes in 1 degree, hence 30 arcseconds is 30/60/60 degrees, which equals 1/120 degrees.

Convert 1/120 degrees to radians similarly as before.

Use the same tangent formula: distance = tan((1/120)° × (π/180)) × 234,000 miles.

Calculate the tangent of (1/120)° in radians (approximately 0.000145444) and multiply by 234,000 miles.

This results in approximately 34 miles from the assigned target.

two triangles are similar. The base of the first triangle is 10 cm and the height is 15 cm. The base of the second triangle is 12 cm. The height of the second triangle is?

Answers

Answer:

the height is 18cm

Explanation:

If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles shown are similar, compare their corresponding sides. Are these ratios equal?

given that

Triangle 1 (first triangle)

base = 10cm

height = 15cm

Triangle 2 (second triangle)

base = 12cm

height = unknown

base 1 / base 2 = height 1 / height 2

10cm / 12cm = 15cm / xcm

xcm = 18cm

height = 18cm

Given that S is the centroid of triangle MNO, find SQ.

Answers

Answer:

|SQ|=5

Step-by-step explanation:

If S is the median, then OP is a median of triangle OMN.

This implies that:

|MP|=|NP|

[tex]3x-4=x+4[/tex]

We group like terms and solve for x.

[tex]3x-x=4+4[/tex]

[tex]\implies 2x=8[/tex]

[tex]\implies x=4[/tex]

Now we know that: MN:SQ=2:1

But MN=2x+2

This implies that:

2x+2:SQ=2:1

Put x=4

2(4)+2:SQ=2:1

10:SQ=2:1

Therefore |SQ|=5

Solve write or draw to explain Saul and Luisa each scored 167 points on computer games How many points did they score together

Answers

Answer:167 + 167 = 334

Step-by-step explanation:

prove that sin^4x - cos^4x = 2sin^2x - 1

Answers

Step-by-step explanation:

Step 1: From the given equation, taking the Left Hand Side (LHS) of the equation

Step 2: Simplify the LHS to make it equal to the Right Hand Side (RHS)

LHS = sin^4x - cos^4x = (sin²x)² - (cos²x)²

       = (sin²x - cos²x)(sin²x + cos²x)

       = sin²x - (1 - sin²x)  since sin²x + cos²x = 1

       = 2 sin²x - 1

       = RHS

Hence proved.

About 50 percent of the math questions are multiple choice and 50 percent are grid-in.

True. False

Answers

The answer I think is false

Answer:

True

Step-by-step explanation:

For abc shown with vertices at A(-2,6),B(8,-2) and C(-8,-4), shown using coordinate geometry that the segment connecting the midpoint of sides Ac and BC is half the length of side AB.

Answers

Answer:

It is proved that AB = 2 × DE.

Step-by-step explanation:

The three vertices of triangle ABC are A(-2,6), B(8,-2) and C(-8,-4).

So, the mid point of AC (say D) has coordinates [tex](\frac{- 2 - 8}{2},\frac{6 - 4}{2}) = (-5,1)[/tex].

And the mid point of BC (say E) has coordinates [tex](\frac{8 - 8}{2}, \frac{- 2 - 4}{2}) = (0, - 3)[/tex].

Now, the length of DE will be [tex]\sqrt{(- 5 - 0)^{2} + (1 + 3)^{2}} = \sqrt{41}[/tex] units.

Again, the length of AB will be [tex]\sqrt{(- 2 - 8)^{2} + (6 + 2)^{2}} = 2\sqrt{41}[/tex] units.

So, it is proved that AB = 2 × DE. (Answer)

2 Points
Which equation represents the slope-intercept form of the line below?
y-intercept = (0,2)
slope =
O A. y= 2x-}
O B. y=-x-2
O C. y=-_x+2
O D. y= 2x+

Answers

Answer:

the answer is C

Step-by-step explanation:

In the y intercept formula which is y=Mx+b the b in the formula represents the y intercept

If x varies inversely as y, and x = 3 when y= 8, find y when x=4

Answers

The value of y is 6 when x is 4

Step-by-step explanation:

If x varies inversely as y, then

x = [tex]\frac{k}{y}[/tex] , where k is the constant of variationxy = k, you can find k by using the initial values of x and y[tex]\frac{x_{1}}{x_{2}}=\frac{y_{2}}{y_{1}}[/tex]

∵ x varies inversely as y

∴ x = [tex]\frac{k}{y}[/tex]

∵ When x = 3, y = 8

- Substitute these values in the equation to find k

∴ 3 = [tex]\frac{k}{8}[/tex]

- Multiply both sides by 8

24 = k

∴ The equation of variation is x = [tex]\frac{24}{y}[/tex]

x = 4

- Substitute the value of x in the equation to find y

∴ 4 = [tex]\frac{24}{y}[/tex]

- Multiply both sides by y

∴ 4y = 24

- Divide both sides by 4

y = 6

The value of y is 6 when x is 4

Learn more:

You can learn more about the direct and inverse variation in brainly.com/question/10708697

#LearnwithBrainy

Josie's dog weighs 122 pounds. This is about 7 times as much as Len's dog weighs. About how much does Len's dog weigh? Select the numbers that correctly complete the sentence. Len's dog weighs between pounds.

Answers

Divide the weight of Josies dog by 7:

122 / 7 = 17.43

It weighs between 17 and 18 pounds.

Final answer:

Len's dog weighs about 17 pounds, calculated by dividing Josie's dog's weight (122 pounds) by 7 since her dog is approximately 7 times heavier than Len's.

Explanation:

Josie's dog weighs 122 pounds, which is about 7 times as much as Len's dog weighs. To find the weight of Len's dog, we need to divide the weight of Josie's dog by 7. Here's the calculation:

122 pounds by 7 = approximately 17.43 pounds

Therefore, Len's dog weighs about 17 pounds. This is a unit of weight that makes sense for the size of a dog. We choose pounds because ounces would be too small and tons would be too large to represent the weight of a large dog accurately. Thus, using pounds is appropriate to express the weight of a dog, such as Len's dog in this case.

2×1 1/2 -1 1/2×1 1/2

Answers

Answer:

3/4

Step-by-step explanation:

Answer:

3/4

Step-by-step explanation:

7.8 dividend by 0.03

Answers

Answer:

its 26

Step-by-step explanation:

give me brainly

usually 1/1000 of the headphones cannot pass the tests . if they found 5 headphones failing, how many headphones did the workers test?

Answers

Answer: 5000

Step-by-step explanation: 5/5000

Final answer:

The workers tested 5000 headphones.

Explanation:

To find out how many headphones the workers tested,



We can set up a proportion to solve the problem:



1/1000 = 5/x



Cross multiplying, we get:



x = 5 * 1000



x = 5000



Therefore, the workers tested 5000 headphones.

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(1 point
4. A regression line has a correlation coefficient of r=-0.91. Which of the following statements
must be true?
The data are so varied that there is almost no discernible trend whatsoever.
O The data are very tightly clustered around the trend line.
The trend line has a very steep negative slope.
The trend line reliably represents only 91 percent of the data.

Answers

Answer:

A: The data are so varied that there is almost no discernible trend whatsoever.

Step-by-step explanation:

The other 3 don't make sense and are not true for the question

MAPS On a map, Wilmington Street, Beech Drive, and Ash Grove Lane appear to all be parallel. The on

ilmington to Ash Grove along Kendall is 820 feet and along Magnolia, 660 feet. If the distance between Beech and

ove along Magnolia is 280 feet, what is the distance between the two streets along Kendall?

Answers

The distance between the two streets along Kendall is 347.9 feet.

Solution:

The image of the problem is attached below.

Distance between Wilmington to Ash Grove along Kendall = 820 feet

Distance between Wilmington to Ash Grove along Magnolia = 660 feet

Distance between Beech and  Ash Grove along Magnolia = 280 feet

Distance between Wilmington to Beech along Magnolia

                                       = 660 feet – 280 feet

                                       = 380 feet

Let us x be the distance between Wilmington to Beech along Kendall and

820 – x be the distance between Beech and  Ash Grove along Kendall.

The given streets are parallel.

By proportionality theorem, parallel lines cut by a transversal are in proportion.

[tex]$\Rightarrow\frac{380}{280} =\frac{x}{820-x}[/tex]

Do cross multiplication.

[tex]$\Rightarrow{380}({820-x}) =280x[/tex]

[tex]$\Rightarrow 311600-380x =280x[/tex]

[tex]$\Rightarrow 311600 =280x+380x[/tex]

[tex]$\Rightarrow 311600 =660x[/tex]

[tex]$\Rightarrow x=472.1[/tex]

Distance between Beech and  Ash Grove along Kendall          

                                    = 820 – x  

                                    = 820 – 472.1

                                    = 347.9

Hence the distance between the two streets along Kendall is 347.9 feet.

Final answer:

By analyzing the given distances along two parallel paths and using proportional reasoning, it is determined that the distance between Beech Drive and Ash Grove Lane along Kendall is approximately 547.33 feet.

Explanation:

Since Wilmington Street, Beech Drive, and Ash Grove Lane are parallel, and given the distances along Kendall and Magnolia, we can deduce the relationships between these distances to find the desired measurement. Utilizing the ratio of distances along Magnolia, we can apply the same ratio to the distances along Kendall.

We know that the total distance along Magnolia (660 feet) minus the distance between Beech and Ash Grove (280 feet) gives the distance between Wilmington and Beech along Magnolia, which is 380 feet. Assuming the distance distribution is proportional along Kendall, the distance between Beech and Ash Grove along Kendall would be given by:

(280 feet / 660 feet) * 820 feet = (2/3) * 820 feet = 547.33 feet.

Therefore, the distance between Beech Drive and Ash Grove Lane along Kendall is approximately 547.33 feet.

12. What steps do you need to take to solve
the equation 2x + 6 - 187
A Add 6. Then multiply by 2.
B Subtract 6. Then divide by 2.
C Add 6. Then divide by 2.
D Subtract 6. Then multiply by 2.

Answers

Answer:

B is the right answer.

What does m equal?

3 3/4 m = 33 3/4

Answers

The believe the answer is m=9.

Find the distance (D) Round your answer the nearest tenth.PLEASE HELP!!

Answers

Using the distance formula
The answer is square root 29

Or 5.4
Final answer:

The distance (D) is 10 cm.

Explanation:

To find the distance (D), we can use the formula D = do + di, where do is the actual distance and di is the apparent image distance.

In the given information, it states that 2do must be less than 20 cm, so we can set do = 10 cm.

Therefore, the distance (D) is 10 cm.

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I WILL GIVE BRAINLIEST
Solve for r

-13 = r/9 + 8

r=

Answers

Answer:

r= -45

Step-by-step explanation:

trust on this one

Answer:

-189

Step-by-step explanation:

How do you evaluate 2x3x5

Answers

Answer:

Step-by-step explanation:

Answer:I think it's 30

Step-by-step explanation:

Because 2x3=6 and 6x5= 30

What is (8×^2+4×+6)(6×^2-5×+6)

Answers

Answer:

1

Step-by-step explanation:

I think it's 1 because I never did this question before.

A miners' cage of mass 420 kg contains 3 miners of total mass 280 kg. The cage
is lowered from rest by a cable. For the first 10 seconds the cage accelerates
uniformly and descends a distance of 75 m. What is the force in the cable during
the first 10 seconds?

Answers

Answer:

5817 Newtons.

Step-by-step explanation:

Total mass of the cage + the miners = 700 Kg which is a downward force of  700g N.

The net downward force = 700g - T where T is the tension (force) in the cable. The g = acceleration due to gravity = 9.81 m s-2.

We  calculate the  acceleration of the cage by using an equation of motion:

Distance = ut + 1/2 a t^2     where u = initial velocity , t = time and a = acceleration:

75 = 0(t) + 1/2 a (10^2)

50a =  75

a = 1.5 m s-2.

So using Newtons second law of motion

Force = mass * acceleration:

700*9.81 - T = 700 * 1.5

T = 700 * 9.81 - 700*1.5

= 5817 N.

Final answer:

The force in the cable during the first 10 seconds is 7930N. This was determined using the formulas s = ut + 1/2at² (to calculate acceleration) and F = ma + mg (to calculate the force).

Explanation:

The subject of this question is Physics, specifically dealing with forces and acceleration. The total weight of the miners and the cage equals the sum of the miners' weight and the cage's weight, giving a total of 700kg, using the formula weight = mass x gravity (assumed to be 9.8m/s²). Therefore, the total weight is 700kg x 9.8m/s² = 6860N.

Then, we'd calculate the acceleration. The formula used is s = ut + 1/2at², where s is distance, u is initial velocity, a is acceleration, and t is time. Given that initial velocity is 0, the formula is simplified to s = 1/2at². After rearranging, we get acceleration (a) = 2s/t² = 2*75/10² = 1.5m/s².

Finally, we can determine the force on the cable using the formula F = ma + mg (F = force, m = mass, a = acceleration, g = gravity). Substituting, we get F = 700kg x 1.5m/s² + 700kg x 9.8m/s² = 7930N. Therefore, the force in the cable during the first 10 seconds is 7930N.

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Whoever gives me the right answer gets extra points, please help me

Answers

Area of the carpet needed = 38 ft²

Solution:

The given image is splitted into two shapes.

One is trapezoid and the other is triangle.

Top base of the trapezoid = 8 ft

Bottom base of the trapezoid = 12 ft

Height of the trapezoid = 3 ft

Area of the trapezoid = [tex]\frac{1}{2} (a+b)\times h[/tex]

                                    [tex]$=\frac{1}{2}(8+12)\times3[/tex]

                                    [tex]$=10\times3[/tex]

                                    = 30

Area of the trapezoid = 30 ft²

Base of the triangle = 12 ft – 8 ft = 4 ft

Height of the triangle = 4 ft

Area of the triangle = [tex]\frac{1}{2} b h[/tex]

                                 [tex]$=\frac{1}{2} \times4\times4[/tex]

                                 = 8

Area of the triangle = 8 ft²

Area of the carpet = Area of the trapezoid + Area of the triangle

                               = 30 ft² + 8 ft²

                               = 38 ft²

Area of the carpet = 38 ft²

Hence 38 square feet of outdoor carpet will need for this hole.

In the order of operations, what is the first operation that you should take care of?

Answers

Answer: Remember PEMDAS. Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction. But when trying to solve a problem with a variable, remember to go backwards.

3x + 6y= 6
9x - 12y = 18 elimination with multiplication

Answers

Answer: x = 4y/3+2

   y = 0

Step-by-step explanation:

What is the solution 4x+6<18

Answers

Answer:

x < 3

Step-by-step explanation:

4x +6 < 18

add and subtract 6 from both sides

4x + 6 - 6 < 18 -6

4x < 12

x< 12/4

X < 3

Answer:

x < 3

Step-by-step explanation:

I took the test its, the right answer, trust me.

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