HELPPP! true or false and explain pls!!

22. All kites are quadrilaterals.
24.A kite can have congruent diagonals.

Answer:

Its D) 8t + 16 = 200

Answer:  The correct option is (d) [tex]8t+16=200.[/tex]

Step-by-step explanation:  Given that Benito is selling T-shirts for $8 each for his school fund-raiser and he has sold 16 T-shirts till now.

We are to find the number of T-shirts that he still need to sell to reach his goal of $200 in sales.

The number of T-shirts still he needs to sell is represented by t.

The, according to the given information, we have

[tex]8(t+16)=200\\\\\Rightarrow 8t+128=200\\\\\Rightarrow 8t=200-128\\\\\Rightarrow 8t=72\\\\\Rightarrow t=\dfrac{72}{8}\\\\\Rightarrow t=9.[/tex]

So, the number of T-shirts that he still needs to sell is 9.

Now, we can see from the above steps of solution for t that options (a), (b) and (c) gives the correct value of t, but from option (d), we get

[tex]8t+16=200\\\\\Rightarrow 8t=200-16\\\\\Rightarrow 8t=184\\\\\Rightarrow t=23\neq 9[/tex]

So, option (d) does NOT solve for the correct value of t.

Thus, (d) is the correct option.

The range of the reflected function consists of these reflected y-values. The range of the reflected function is (-4, -2, 1).

The range of a function reflected over the x-axis can be determined by considering the y-values of the original domain. In this case, the given domain points are (3,4), (2,-1), and (-1,2). The reflected points will have the same x-coordinates but opposite y-coordinates. Therefore, the reflected range will be the set of y-values obtained by changing the signs of the y-values in the original domain.

The original domain points have y-values of 4, -1, and 2. When reflected over the x-axis, these y-values become -4, 1, and -2, respectively.

Thus, the range of the reflected function consists of these reflected y-values. The range of the reflected function is (-4, -2, 1).

Learn more about range and reflection in functions here:

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Answer:

The prefixes in the metric system are used to modify the basic units. The prefixes either make the unit a larger measurement, as in the case of meter to kilometer, or they make the unit a smaller measurement, as in the case of meter to millimeter.

Step-by-step explanation:

Answer:

Question 1). Option C.

Question 2) Option C.

Question 3) Option D.

Step-by-step explanation:

Question 1), A. 7 - (9x + 3) = -9x -4

7 - 9x - 3 = -9x - 4

-9x + 4 = -9x - 4

Left hand side(L.H.S.)≠ Right hand side(R.H.S.)

Therefore, it's not an identity

B). 6m - 7 = 7m + 5 -m

6m -7 = 6m + 5

Again L.H.S.≠R.H.S.

So, it's not an identity.

C). 10p + 6 - p = 12p - 3(p - 2)

9p + 6 = 12p - 3p + 6

9p + 6 = 9p + 6

L.H.S.=R.H.S.

Therefore, it's an identity.

D). 3y + 2 = 3y - 2

L.H.S. ≠ R.H.S.

Therefore, it's not an identity.

Question 2. Part A. 7v + 2 = 8v - 3

7v - 8v = -2 - 3

- v = - 5

v = 5

Part B. 3x - 5 = 3x + 8 - x

3x - 5 = 2x + 8

3x - 2x = 8 + 5

x = 13

Part C. 4y + 5 = 4y - 6

This equation has no solution.

Part D. 7z + 6 = -7z - 5

7z + 7z = -6 - 5

14z = -11

z = [tex]-\frac{11}{14}[/tex]

Question 3). 5 + 7x = 11 + 7x

This equation has same coefficient of variable x on both the sides of the equation.

Therefore, equation has no solution.

Option D. no solution is the correct option.

The correct option for different parts are as follows:

Part (1): [tex]\boxed{\bf option (c)}[/tex]

Part (2): [tex]\boxed{\bf option (c)}[/tex]

Part (3): [tex]\boxed{\bf option (d)}[/tex]

Further explanation:

Part (1):

Option (a)

Here, the equation is [tex]7-(9x+3)=-9x-4[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}7-(9x+3)&\ _{=}^{?}-9x-4\\7-9x-3&\ _{=}^{?}-9x-4\\4-9x&\neq-9x-4\end{aligned}[/tex]  

Here, left hand side (LHS) is not equal to right hand side (RHS).

Therefore, the given equation is not an identity.

This implies that option (a) is incorrect.

Option (b)

Here, the equation is [tex]6m-5=7m+5-m[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}6m-5\ &_{=}^{?}\ 7m+5-m\\6m-5 &\neq6m+5\end{aligned}[/tex]  

Here, left hand side (LHS) is not equal to right hand side (RHS).

Therefore, the given equation is not the identity.

This implies that option (b) is incorrect.

Option (c)

Here, the equation is [tex]10p+6-p=12p-3(p-2)[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}10p+6-p\ &_{=}^{?}\ 12p-3(p-2)\\9p+6\ &_{=}^{?}\ 12p-3p+6\\9p+6&\neq9p+6\end{aligned}[/tex]  

Here, left hand side (LHS) is equal to right hand side (RHS).

Therefore, the given equation is an identity.

This implies that option (c) is correct.

Option (d)

Here, the equation is [tex]3y+2=3y-2[/tex].

Now, the above equation is as follows:

[tex]3y+2\neq3y-2[/tex]  

Here, left hand side (LHS) is not equal to right hand side (RHS).

Therefore, the given equation is not an identity.

This implies that option (d) is incorrect.

Therefore, equation in option (c) is an identity.  

Part (2):

Option (a)

Here, the equation is [tex]7v+2=8v-3[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}7v+2&=8v-3\\7v-8v&=-2-3\\-v&=-5\\v&=5\end{aligned}[/tex]  

Thus, the value of [tex]v[/tex]is [tex]5[/tex].

Therefore, the given equation has a solution.

This implies that option (a) is incorrect.

Option (b)

Here, the equation is [tex]3x-5=3x+8-x[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}3x-5&=3x+8-x\\3x-3x+x&=8+5\\x&=13\end{aligned}[/tex]  

Thus, the value of [tex]x[/tex] is [tex]5[/tex].

Therefore, the given equation has a solution.

This implies that option (b) is incorrect.

Option (c)

Here, the equation is [tex]4y+5=4y-6[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}4y+5&=4y-6\\4y-4y&=-6-5\\0&\neq-11\end{aligned}[/tex]

Thus, the given equation has no solution.

This implies that option (c) is correct.

Option (d)

Here, the equation is [tex]7z+6=-7z-5[/tex].

Now, solve the above equation as follows:

[tex]\begin{aligned}7z+6&=-7z-5\\7z+7z&=-5-6\\14z&=-11\\z&=-\dfrac{11}{14}\end{aligned}[/tex]

Thus, the value of [tex]z[/tex] is [tex]-\frac{11}{14}[/tex].

Therefore, the given equation has a solution.

This implies that option (d) is incorrect.

Therefore, equation in option (c) does not have solution.

Part (3):

The equation is [tex]5+7x=11+7x[/tex].

Solve the above equation as follows:

[tex]\begin{aligned}5+7x&=11+7x\\7x-7x&=11-5\\0&\neq6\end{aligned}[/tex]

Therefore, the given equation has no solution.

Option (a)

Here, the value of [tex]x[/tex] is [tex]0[/tex].

But the equation [tex]5+7x=11+7x[/tex] has no solution.

So, option (a) is incorrect.

Option (b)

Here, the value of [tex]x[/tex] is [tex]14[/tex].

But the equation [tex]5+7x=11+7x[/tex] has no solution.

So, option (b) is incorrect.

Option (c)

In option (c) it is given that there are infinite number of solutions.

But the equation [tex]5+7x=11+7x[/tex] has no solution.

So, option (c) is incorrect.

Option (d)

In option (d) it is given that the solution does not exist.

As per our calculation the equation [tex]5+7x=11+7x[/tex] does not have any solution.

So, option (d) is correct.

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Linear equations

Keywords: Linear equations, linear equation in one variable, linear equation in two variable, slope of a line, equation of the line, function, real numbers, ordinates, abscissa, interval, open interval, closed intervals, semi-closed intervals, semi-open intervals, sets, range domain, codomain.

Answer: 13 units.

Step-by-step explanation: A circle has its center at the origin, and the point of the circle is (5, -12).  Then we have to calculate the length of its radius formula to find the length between the two points.

Both students are correct because polynomials can be grouped in different ways to factor. Both ways result in a common binomial factor between the groups. Using the distributive property , this common binomial term can be factored out. Each grouping results in the same two binomial factors.

Answer:

Option A is correct that is the slope of f(x) is the same as the slope of g(x).

Step-by-step explanation:

We have been given a function g(x)= -2x -5

And slope of f(x) can be shown from the given graph

And a line (0,3) and (1,1) is f(x)

Slope we can find in f(x) by the formula

[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

Here, in f(x) [tex]x_1=0,x_2=1,y_1=3,y_2=1[/tex]

On substituting the values we get slope of f(x) as:

[tex]slope=\frac{1-3}{1-0}=-2[/tex]

hence, slope of f(x) is -2

And slope of g(x) can be find by the formula

y= mx +c; where m is the slope on comparing the given equation with the above equation

We have slope of g(x) is -2

Hence,  the slope of f(x) is the same as the slope of g(x).

Therefore, option A is correct.

Answer:

first option

Step-by-step explanation:

To know this, let's begin with discarting options.

The expression is 3x + 4

This expression means that you have 3 times a number and then you add 4 to that number.

According to this, the second option states that to the number 4 you add the 3, in other words 4 + 3 and then a number. This cannot be the correct option.

The third option states a division, but we don't have in the expression any division, so, this is not the option.

The fourth option is the same as the second option with the difference that instead of adding you do a substract, which is not the case.

So with this we can conclude that the correct option is the first one, sum 3 times a number with 4.

the answer is (A) the sum of 3 times a number and 4

Final answer:

The lengths of the three sides of the triangular plot are 600 feet for the shortest side, 800 feet for the middle side, and 1000 feet for the longest side.

Explanation:

To find the lengths of the three sides of the triangular plot, let's define the shortest side as x. Therefore, according to the problem statement, the longest side would be 2x - 200 feet and the middle side would be (2x - 200) - 200 = 2x - 400 feet. The perimeter of the triangle is the sum of all its sides, which is given as 2400 feet.

The equation representing the perimeter of the triangle is:
x + (2x - 200) + (2x - 400) = 2400

Simplifying the equation, we get:
5x - 600 = 2400
Adding 600 to both sides:
5x = 3000

Dividing by 5 gives us:
x = 600

Thus, the shortest side is 600 feet, the longest side is 2(600) - 200 = 1000 feet, and the middle side is 1000 - 200 = 800 feet.

The lengths of the three sides of the triangular plot are 600 feet, 800 feet, and 1000 feet respectively.

To write log8 3 as a logarithm of base 5, we can use the change of base formula: loga b = logc b / logc a. Applying this formula, we have log5 3 = log8 3 / log8 5. Therefore, the correct option is (log8)5/(log3)5.

The expression log83 represents the logarithm of 3 with base 8. To write it as a logarithm with base 5, we can use the change of base formula:

logab = logcb / logca

Applying this formula, we have:

log53 = log83 / log85

Therefore, the correct option is (log8)5/(log3)5.

Final answer:

The simplified form of the expression (n⁵)(n²) is found by adding the exponents since the base is the same, resulting in n⁷.

Explanation:

The simplified form of the expression (n⁵)(n²) is achieved by applying the laws of exponents. Since both terms have a common base of n, when multiplying two exponentials with the same base, we simply add their exponents.

The addition of 5 and 2 (the exponents) provides n⁵⁺² which simplifies to n⁷.

Hence, the simplified form of (n⁵)(n²) is n⁷.

The height of the telephone pole is approximately 20.79 feet, calculated using tangent function with a 30° angle.

To find the height of the telephone pole, we can use trigonometry. We'll use the tangent function since we have the opposite side and the adjacent side of the right triangle formed by the person, the pole, and the ground.

Let [tex]\( h \)[/tex] be the height of the pole.

We have the tangent of the angle:

[tex]\[ \tan(30^\circ) = \frac{h}{36} \][/tex]

Now, we can solve for [tex]\( h \):[/tex]

[tex]\[ h = 36 \times \tan(30^\circ) \][/tex]

Let's calculate:

[tex]\[ h = 36 \times \tan(30^\circ) \]\[ h = 36 \times 0.5774 \] (rounded value of tan(30°))\[ h \approx 20.7864 \][/tex]

So, the height of the telephone pole is approximately 20.79 feet.

By setting up an equation using the measures of adjacent angles AOB, BOC, and AOC, we find that the sum of AOB and BOC equals AOC. Simplifying and solving for x gives us the value of x as 3.

To solve for the value of x given the measures of angles AOB, BOC, and AOC, we have to use the fact that the sum of the angles AOB and BOC is equal to the angle AOC since the angles are adjacent to each other.

By setting up an equation where m + m equals m, we have:

(4x - 1) + (2x + 15) = (8x + 8).

Upon simplifying, we combine like terms to get:

4x + 2x - 1 + 15 = 8x + 8,

which simplifies to 6x + 14 = 8x + 8. To solve for x, we need to move the terms involving x to one side and the constant terms to the other side. Subtracting 6x from both sides of the equation yields:

14 = 2x + 8,

and then subtracting 8 from both sides gives us:

6 = 2x,

Divide both sides by 2, and we find that:

x = 3.