Answer:
4) J
5) D
Step-by-step explanation:
4) 416 = 2x² - 6x
2x² - 6x - 416 = 0
x² - 3x - 208 = 0
x² - 16x + 13x - 208 = 0
x(x - 16) + 13(x - 16) = 0
(x - 16)(x + 13) = 0
x = 16, -13(not possible)
So 16 rows
5) y = a(x - h)² + k
y = a(x - 3)² - 7
When x = 1, y = -10
-10 = a (1 - 3)² - 7
-10 = 4a - 7
4a = -3
a = -¾
y = -¾(x - 3)² - 7
12 with the exponer of -6 times 12 with the exponent of -5
Answer:
[tex] {12}^{ - 11} [/tex]
Step-by-step explanation:
The expression to be simplified is
[tex] {12}^{ - 6} \times {12}^{ - 5} [/tex]
We can see that the expression involves the idea of indices.Thus,we need to consider one of the laws of indices when dealing with the expression.
One of the laws of indices states that,
[tex] {a}^{m} \times{a}^{n} = {a}^{m + n} [/tex]
This means that when multiplying indices and the bases are equal, you repeat one of the bases and add the exponents.
This implies that
[tex] {12}^{ - 6} \times {12}^{ - 5} = {12}^{ (- 6 - 5)} [/tex]
Simplifying the exponent we obtain
[tex] = {12}^{ - 11} [/tex]
Can anyone help me solve this?
Answer:
a- 16/100
b- 1/6
c- not sure
Step-by-step explanation:
I need the slope intercept form please help and I need tho show the work
The slope-intercept form is [tex]y=\frac{1}{2} x+5[/tex].
Solution:
Given data:
Slope of the line, m = [tex]\frac{1}{2}[/tex].
Point on the line = (–2, 4)
Here [tex]x_1=-2, y_1=4[/tex]
Let us find the slope-intercept form of the line using point-slope formula.
Point-slope formula:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]$y-4=\frac{1}{2} (x-(-2))[/tex]
[tex]$y-4=\frac{1}{2} (x+2)[/tex]
[tex]$y-4=\frac{1}{2} x+1[/tex]
Add 4 on both sides of the equation.
[tex]$y=\frac{1}{2} x+5[/tex]
Hence the slope-intercept form is [tex]y=\frac{1}{2} x+5[/tex].
What is the radius of a sphere with the volume of 972pi mm
[tex]\large\text{Hey there!}[/tex]
[tex]\mathsf{The\ sphere\ formula\ is: \dfrac{4}{3}\pi\times r^3}[/tex]
[tex]\mathsf{Now, that\ we\ have\ our\ formula\ let's\ solve\ for\ the\ equation}[/tex]
[tex]\mathsf{So,\ first\ \bf{\underline{DIVIDE}}}\mathsf{\ both\ of\ your\ sides\ by\ \pi}[/tex]
[tex]\mathsf{\dfrac{4}{3}r^3=972}\\\\\rightarrow\ \mathsf{r^3=972\times\dfrac{3}{4}}\\\\\mathsf{972\times\dfrac{3}{4}=729}\\\\\mathsf{\rightarrow\ r^3=729}[/tex]
[tex]\mathsf{\sqrt[\mathsf{3}]{\mathsf{729}} = 81}\\\\\mathsf{\sqrt{81}=81\div9=9}\\\\\mathsf{\sqrt{81}=9}\\\\\mathsf{r=9}[/tex]
[tex]\boxed{\boxed{\mathsf{\bf{Answer: \boxed{\mathsf{radius = \bf{9}}}}}}}\checkmark[/tex]
[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\dfrac{\frak{LoveYourselfFirst}}{:)}[/tex]
The ________ states that if two values a and b are equal when you multiply each by the same value c, the products are equal
Answer:
The multiplication property of equality states that if two values a and b are equal when you multiply each by the same value c, the products are equal.
Step-by-step explanation:
Multiplication property of equality:
It states that multiplying both sides of the the equation with the same constant or number then the truth value of the equation does not change.That is the equality still holds true.So, if
[tex]a = b[/tex]
Then, we can write by multiplication property of equality
[tex]a=b\\\Rightarrow a\times c = b \times c\\\Rightarrow ac = bc[/tex]
Thus, the correct answer is
The multiplication property of equality states that if two values a and b are equal when you multiply each by the same value c, the products are equal.
Final answer:
The statement in question highlights the equality property of multiplication, which states that if two values are equal, their products with a same multiplier are also equal. This principle is fundamental in mathematics, particularly in algebra, where it underpins the manipulation and understanding of equations.
Explanation:
The statement "if two values a and b are equal when you multiply each by the same value c, the products are equal" refers to the basic principle of the equality property of multiplication in mathematics. This property underlines that if a = b, then a × c = b × c. This fundamental concept is crucial for understanding algebraic expressions and equations, where the manipulation of variables and constants is based on such properties.
For example, if we assert that 3 (number a) and 3 (number b) are equal and we choose to multiply both by 2 (number c), the resulting products, 6 and 6, are indeed equal. This example clearly illustrates how the equality of products remains consistent regardless of the multiplier, as long as the initial quantities are equal.
This principle is foundational in mathematics and serves as a cornerstone for solving equations, thereby reinforcing the understanding that equality is maintained through operations of multiplication by a constant.
From the 66 male and 88 female sales representatives for an insurance company, a team of 44 men and 33 women will be selected to attend a national conference on insurance fraud.In how many ways can the team of 7
be selected?
The answer should be about 36,491,112
Sorry for harassing you I've had a less the good day, also sorry if it's wrong I haven't done this type of stuff in a while
explain why an inverse variation function is not the best model for the data set
Answer: The products of corresponding x- and y- values of an inverse variation function are constant.
As x increases, y also increases.
The product of coordinate pairs are not equal: (165) (198) = 32,670 and (170) (204) = 34,680.
Step-by-step explanation:
| If f(x) = 7 + 4x and g(x)= 7, what is the value of (f/g)(5)
Answer:
27/7.
Step-by-step explanation:
(f/g)x = (7 + 4x) / 7
(f/g)(5) = (7 + 4(5)/ 7
= 27/7.
Yo sup??
f(x)=7+4x
g(x)=7
f/g(5)
=7+4*5/7
=27/7
Hope this helps
Factor the polynomial: 1–bx–x+b
The polynomial 1 - bx - x + b can be factored by rearranging the terms to (1 + b) - x(1 + b), allowing us to factor out 1 + b, resulting in the factored form (1 + b)(1 - x).
Explanation:The polynomial in question, 1 \\u2212 bx \\u2212 x + b, can be factored by rearranging and grouping terms. Indeed, the suggestion to factor out at least one x from all terms that contain it can be helpful in some cases, for example, ax^2+bx+c. However, for the polynomial given, we need to rearrange the terms to (1 + b) \\u2212 x(1 + b). Notice that 1 + b can be factored out, resulting in (1 + b)(1 \\u2212 x).
Therefore, the factored form of 1 \\u2212 bx \\u2212 x + b is (1 + b)(1 \\u2212 x).
In general, when factoring polynomials, being attentive to common factors and rearranging terms to identify them can lead to a simpler expression. For a quadratic equation like ax^2+bx+c=0, factoring is a powerful tool, often applied after identifying an integrating factor or using the quadratic formula.
G(F(x)) is always equal to F(G(x)).
O
A. True
OB. False
B. False
There are cases where this is not true, but if you want to prove that, you'll need to know what f and g are. For example, if f(x) = x - 3 and g(x) = x2, then f(g(x)) is not equal to g(f(x)) because
f(g(x)) = x2 - 3 and g(f(x)) = (x - 3)2. Those 2 functions are not the same because f(g(0)) = -3 ≠ 9 = g(f(0)).
What are the rules of functions?Function rules by equations | Algebra functions that match 1 variable to the other in a 2-variable equation. Functions are written using function notation. Create functions that match 1 variable to the another in a 2-variable equation.
What are some examples of mathematical functions?there are Some Examples of Functions
x2 (squaring) is the functionx3+1 is also a functionSine, Cosine or Tangent are functions used in trigonometryLearn more about functions here https://brainly.com/question/12431044
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a(n) = -1/16 (2) ^n-1 what is the 6th term
dan is building a circular swimming pool and wants the circumference to be no more than 95 feet what is the largest radius possible for the pool. Round to the nearest tenth of a foot.
The largest radius for the swimming pool is 15.1 feet
Step-by-step explanation:
Step 1:
Circumference of the circular swimming pool built by Dan = 95 feet
We need to determine the largest radius for the pool.
Step 2 :
Circle's circumference is given by 2πr
Where r represents the radius
This shows that the radius is in direct proportion to the circumference. Hence the radius corresponding to the maximum circumference will be the largest possible radius
So we have 2πr = 95
=> r = [tex]\frac{95}{2\pi }[/tex]
=> r = [tex]\frac{95}{2}[/tex] × [tex]\frac{7}{22 }[/tex] where [tex]\pi = \frac{22}{7}[/tex]
=> r = 15.1 feet (rounded off to tenth of a foot)
Step 3 :
The largest radius for the swimming pool is 15.1 feet
Final answer:
the largest radius possible for the pool, to ensure the circumference does not exceed 95 feet, is 15.1 feet.
Explanation:
Calculating the Largest Radius for a Swimming Pool
To find the largest possible radius for Dan's circular swimming pool with a circumference of no more than 95 feet, we will use the formula for the circumference of a circle, which is C = 2πr.
We need to solve for r (radius) when C ≤ 95 feet.
Setting up the equation:
95 ≥ 2πrr ≤ 95 / (2π)r ≤ 95 / (2 * 3.14) (Using π ≈ 3.14 for calculation)r ≤ 95 / 6.28r ≤ 15.1 feet (rounded to the nearest tenth)Therefore, the largest radius possible for the pool, to ensure the circumference does not exceed 95 feet, is 15.1 feet.
Hannah finds purple, blue, and silver space rocks while exploring.
2
3
of the rocks are purple and
3
4
of the remainder are blue. If there are 3 silver rocks, how many space rocks does Hannah have?
Answer:
There were 36 space rocks in total.
37.5% of what number is 6
To find the number that 37.5% of it equals 6, set up an equivalent fractions equation, cross-multiply, and solve for the unknown number. In this case, 37.5% of 16 is 6.
Explanation:The question pertains to finding a certain number when given a percentage of that number. Here, we're asked to find the number of which '37.5% is 6'. We can solve this through simple arithmetic and the use of equivalent fractions. An important rule to remember is that 'percentage' literally means 'per 100', so 37.5% can be written as the fraction 37.5/100.
To find the unknown number (let's call it X), you can set up the equation 37.5/100 = 6/x, where 'x' is the number we're trying to find. Then you cross-multiply to solve for 'x': 37.5 * X = 6 * 100. Simplifying this, X = (6 * 100) / 37.5. Calculating that out gives X = 16. Therefore, 37.5% of 16 is 6.
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The value of the unknown number whose 37.5 percent equals 6 is 16.
What number does its 37.5% gives 6?Given the parameter:
37.5% of what number is 6
The problem is asking for 37.5% of some unknown number which gives 6.
We can represent the unknown number as x.
Now, the equation to find the unknown number will be:
37.5% of x = 6
Replace 37.5% with 37.5/100:
37.5/100 of x = 6
37.5/100 × x = 6
Solve for x:
0.375 × x = 6
0.375x = 6
Divide both sides by 6:
x = 6/0.375
x = 16
Therefore, the value of the number is 16.
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A football field is 120 yards long by 53 yards wide if a player runs diagonally from one corner to the opposite corner. How far will they travel?
Answer: They will travel about 131.18 yards.
Step-by-step explanation:
Given : A football field is 120 yards long by 53 yards wide.
We know that a football field is rectangular in shape.
Each interior angle in a rectangle is a right angle.
Then, by Pythagoras theorem, we have
(Diagonal)² = (Length)² + (Width)²
If a player runs diagonally from one corner to the opposite corner, then the length of the diagonal is given by :-
[tex](\text{Diagonal})=\sqrt{(120)^2+(53)^2}\\\\\Rightarrow\ (\text{Diagonal})=\sqrt{14400+2809}\\\\\Rightarrow\ (\text{Diagonal})=\sqrt{17209}\\\\\Rightarrow\ (\text{Diagonal})=131.183078177\approx131.18\text{ yards}[/tex]
Hence, they will travel about 131.18 yards.
Final answer:
The distance a player would travel running diagonally across a football field that is 120 yards long and 53 yards wide is approximately 131.183 yards.
Explanation:
The student asked about the distance a player would travel if they ran diagonally from one corner to the opposite corner of a football field that is 120 yards long and 53 yards wide.
To solve this, we need to apply the Pythagorean theorem in which the length and width of the football field will be the legs of the right triangle and the diagonal the player runs will be the hypotenuse.
The formula for the Pythagorean theorem is a² + b² = c², where a and b are the lengths of the legs and c is the length of the hypotenuse.
Therefore, the calculation will be as follows:
(120 yd)² + (53 yd)² = c².
Simplifying,
14400 yd² + 2809 yd² = c².
Adding these together gives us 17209 yd², and taking the square root of that gives us the length of the diagonal, which is the distance the player will travel.
Thus, c = √17209 yd2 ≈ 131.183 yards.
Tyree is determining the distance of a segment whose endpoints are A(–4, –2) and B(–7, –7).
Step 1: d = StartRoot (negative 7 minus (negative 7)) squared + (negative 4 minus (negative 2)) squared EndRoot
Step 2: d = StartRoot (negative 7 + 7) squared + (negative 4 + 2) squared EndRoot
Step 3: d = StartRoot (0) squared + (negative 2) squared EndRoot
Step 4: d = StartRoot 0 + 4 EndRoot
Step 5: d = StartRoot 4 EndRoot
Therefore, d = 2.
Which best describes the accuracy of Tyree’s solution?
Tyree’s solution is accurate.
Tyree’s solution is inaccurate. In step 1, he substituted incorrectly.
Tyree’s solution is inaccurate. In step 2, he simplified incorrectly.
Tyree’s solution is inaccurate. In step 3, he added incorrectly.
Answer:
Tyree’s solution is inaccurate. In step 1, he substituted incorrectly.
Step-by-step explanation:
to find the distance between two point A(-4, -2) and B(-7, -7) we use the following distance formula
[tex]d=\sqrt{(x_{2} -x_{1})^2+(y_{2}-y_{1} )^2 \\\\[/tex]
x1=-4, x2=-7
y1=-2, y2=-7
so,
[tex]d=\sqrt{(-7-(-4))^2+(-7-(-2) )^2\\}\\\\d=\sqrt{(-7+4)^2+(-7+2)^2 }\\\\d=\sqrt{(-3)^2+(-5)^2 }\\\\\\\\d=\sqrt{9+25}\\ \\d=\sqrt{34}[/tex]
Answer:
Tyree’s solution is inaccurate. In step 1, he substituted incorrectly.
Explanation:
I got it right,
Hope this Helps!
select the quadratic equation that has roots x=8 and x=-5
Step-by-step explanation:
Since, x=8 and x=-5 are the roots.
Therefore, (x - 8) & (x - 5) will be factors.
Hence, required quadratic equation can be given as:
[tex](x - 8)(x - 5) =0 \\ \\ \therefore {x}^{2} + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\ \\ \therefore {x}^{2} + ( - 13) x+ 40= 0 \\ \\ \huge \red{ \boxed{ \therefore {x}^{2} - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.[/tex]
5 divided by 7 over 10
Answer:
1 over 14
Step-by-step explanation:
reduce the expression, if possible. by canceling the common factors.
Two times a number, x, plus 3 times a number, y, equals 50. Four times x minus 2 times y equals 4. What are the numbers?
A) x = 7, y = 12
B) x = 19, y = 4
C) x = 10, y= 18
D) x = -11, y = 24
Identify the property used in each step of solving the inequality 3x-2>-4.
Addition property of equality
Division property of equality
Solution:
Given inequality is:
3x - 2 > 4
[tex]\mathrm{Add\:}2\mathrm{\:to\:both\:sides}[/tex]
Here, Addition property of equality is used
When the same amount is added to both sides of an inequality, then the inequality is still true
3x - 2 + 2 > 4 + 2
3x > 6
[tex]\mathrm{Divide\:both\:sides\:by\:}3[/tex]
Here, Division property of equality is used
When we divide both sides of an equation by the same nonzero number, the sides remain equal.
[tex]\frac{3x}{3}>\frac{6}{3}\\\\x > 2[/tex]
Thus the property used in each step of solving the inequality is found
how do I solve system of equations elimination method
Step-by-step explanation:
To Solve a System of Equations by EliminationTo Solve a System of Equations by EliminationWrite both equations in standard form. ...To Solve a System of Equations by EliminationWrite both equations in standard form. ...Make the coefficients of one variable opposites. ...To Solve a System of Equations by EliminationWrite both equations in standard form. ...Make the coefficients of one variable opposites. ...Add the equations resulting from Step 2 to eliminate one variable.To Solve a System of Equations by EliminationWrite both equations in standard form. ...Make the coefficients of one variable opposites. ...Add the equations resulting from Step 2 to eliminate one variable.Solve for the remaining variable.To Solve a System of Equations by EliminationWrite both equations in standard form. ...Make the coefficients of one variable opposites. ...Add the equations resulting from Step 2 to eliminate one variable.Solve for the remaining variable.Substitute the solution from Step 4 into one of the original equations.To Solve a System of Equations by EliminationWrite both equations in standard form. ...Make the coefficients of one variable opposites. ...Add the equations resulting from Step 2 to eliminate one variable.Solve for the remaining variable.Substitute the solution from Step 4 into one of the original equations.More items...Identify any solutions to the system given below.
2x + y = 5
3y = 15 - 6x
(6.-7)
(2, 1)
o (-2,-9)
(-4, 13)
Answer:
(6,-7)
(2,1)
(-4,13)
Step-by-step explanation:
we have
[tex]2x+y=5[/tex] -----> equation A
[tex]3y=15-6x[/tex] ----> equation B
Multiply the equation A by 3 both sides
[tex]3(2x+y)=3(5)[/tex]
[tex]6x+3y=15[/tex]
isolate the variable 3y
[tex]3y=15-6x[/tex] -----> equation C
equation B and equation C are equal
That means -----> is the same line
so
The system has infinity solutions
Remember that
If a ordered pair is a solution of the line, then the ordered pair must satisfy the equation of the line
Verify each ordered pair
1) (6,-7)
substitute the value of x and the value of y in the linear equation
[tex]3(-7)=15-6(6)[/tex]
[tex]-21=-21[/tex] ---> is true
so
The ordered pair is a solution of the system of equations
2) (2,1)
substitute the value of x and the value of y in the linear equation
[tex]3(1)=15-6(2)[/tex]
[tex]3=3[/tex] ---> is true
so
The ordered pair is a solution of the system of equations
3) (-2,-9)
substitute the value of x and the value of y in the linear equation
[tex]3(-9)=15-6(-2)[/tex]
[tex]-27=27[/tex] ---> is not true
so
The ordered pair is not a solution of the system of equations
4) (-4,13)
substitute the value of x and the value of y in the linear equation
[tex]3(13)=15-6(-4)[/tex]
[tex]39=39[/tex] ---> is true
so
The ordered pair is a solution of the system of equations
Answer:
(6,-7)
(2,1)
(-4,13)
Step-by-step explanation:
got it right on edg2020 :)
What is the equation of a circle with center (-3,-5) and radius 4?
O A. (x+3)2 + (y + 5)2 = 4
O B. (x-3)2 + (y- 5)2 = 16
O C. (x-3)2 + (y- 5)2 = 4
O D. (x + 3)2 + (y + 5)2 = 16
Answer: D) (x + 3)² + (y + 5)² = 16
Step-by-step explanation:
The equation of a circle is: (x - h)² + (y - k)² = r²
where (h, k) = center and r = radius
Given: (h, k) = (-3, -5) r = 4
Equation: (x - (-3))² + (y - (-5))² = 4²
(x + 3)² + (y + 5)² = 16
Find the approximate side length of a square game board with an area of 136in^2
Answer:
68in
Step-by-step explanation:
Divide the area by 2 because a= l x w and squares sides are all the same.
PLEASE MARK BRAINLIEST! :]To find the approximate side length of a square game board with an area of 136in^2, you can use the formula for the area of a square and take the square root of the given area. The approximate side length is 11.66 inches.
Explanation:To find the approximate side length of a square game board with an area of 136in2, we can use the formula for the area of a square, which is length * length. In this case, we need to find the square root of 136 to get the side length. The square root of 136 is approximately 11.66 inches.
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Find the surface area, will give Brainliest
Answer:
96 units^2
Step-by-step explanation:
Base: 6 × 6 = 36
Faces: 5 × 6 = 30 (×2 = 60)
Add: 36 + 60 = 96
Answer:
96 units^2
Step-by-step explanation:
The Base: 6 × 6 = 36
The Faces: 5 × 6 = 30 (×2 = 60)
Then Add: 36 + 60 = 96
Hope to help.
What is the measure of minor arc BD?
Angle BCD is a circumscribed angle of circle A. Angle BCA
measures 40°
B
40°
© 50°
80°
100°
Answer:
[tex]minor\ arc\ BD=100^o[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
we know that
A circumscribed angle is the angle made by two intersecting tangent lines to a circle
so
In this problem
BC and CD are tangents to the circle
BC=CD ----> by the Two Tangent Theorem
That means
Triangle ABC and Triangle ADC are congruent
so
[tex]m\angle BAC=m\angle DAC[/tex]
Find the measure of angle BAC
In the right triangle ABC
[tex]m\angle BAC+m\angle BCA=90^o[/tex]
substitute given value
[tex]m\angle BAC+40^o=90^o[/tex]
[tex]m\angle BAC=90^o-40^o=50^o[/tex]
Find the measure of angle BAD
[tex]m\angle BAD=2m\angle BAC[/tex]
[tex]m\angle BAD=2(50^o)=100^o[/tex]
Find the measure of minor arc BD
we know that
[tex]minor\ arc\ BD=m\angle BAD[/tex] -----> by central angle
therefore
[tex]minor\ arc\ BD=100^o[/tex]
Final answer:
The measure of the minor arc BD is d. 80°, because it is twice the measure of the inscribed angle BCA, which is 40°.
Explanation:
When we are looking for the measure of a minor arc in a circle, and we know the measure of the inscribed angle that subtends that arc, we can find the measure of the arc by understanding that the inscribed angle is half the measure of the arc it cuts from the circle. Given that angle BCA measures 40°, and assuming BCD is an inscribed angle that subtends the arc BD, we can deduce that the minor arc BD is actually twice the measure of the inscribed angle BCA.
Therefore, to find the measure of minor arc BD, we double the measure of angle BCA:
Measure of minor arc BD = 2 × measure of angle BCA
Measure of minor arc BD = 2 × 40°
Measure of minor arc BD = 80° (d.)
At the park there is a pool shaped like a circle with diameter 22 yd. A ring-shaped path goes around the pool. Its width is 6 yd.
We are going to give a new layer of coating to the path. If one gallon of coating can cover 5 yd", how many gallons of coating do we need? Note that coating
comes only by the gallon, so the number of gallons must be a whole number. (Use the value 3.14 for n).
Answer:
106 gal
Step-by-step explanation:
step 1
Find the area of the path
we know that
The area of the path is given by the formula
[tex]A=\pi r_2^{2} -\pi r_1^{2}[/tex]
[tex]A=\pi [r_2^{2} -r_1^{2}][/tex]
where
r_2 is the radius of the pool plus the width of the path
r_1 is the radius of the pool
we have
[tex]r_1=22/2=11\ yd[/tex] ---> the radius is half the diameter
[tex]r_2=11+6=17\ yd[/tex]
substitute
[tex]A=\pi [17^{2}-11^{2}][/tex]
[tex]A=168\pi\ yd^2[/tex]
assume
[tex]\pi =3.14[/tex]
[tex]A=168(3.14)=527.52\ yd^2[/tex]
step 2
Find the gallons of coating needed
Divide the area of the path by 5
so
[tex]527.52/5=105.5\ gal[/tex]
Round up
therefore
106 gal
To calculate how many gallons of coating are needed, we find the area of the path by subtracting the area of the pool from the total area covered. This equals to 527.52 yd². As each gallon of coating covers 5 yd², we need 105.504 gallons. However, since the paint is sold in whole gallons, we round it up to 106 gallons.
Explanation:To determine how many gallons of coating are needed, we first need to calculate the area of the ring-shaped path around the pool.
The pool is a circle with a diameter of 22 yd, so its radius is 11 yd. The path is around this pool and has a width of 6 yd. Therefore, the outer radius of the path is 11yd (radius of pool) + 6yd (width of path)=17 yd. The area of a circle is given by the formula πr² where r is the radius and π is a constant, approximately equal to 3.14.
So, the area of the outer circle is 3.14 × (17 yd)² = 907.46 square yards, and the area of the inner circle (pool) is 3.14× (11 yd)² = 379.94 square yards. The area of the path is the difference of those two areas, 907.46 yd² - 379.94 yd² = 527.52 yd².
Since one gallon of the coating can cover 5 sq yd, the number of gallons required is the total area divided by the area that one gallon can cover, which is 527.52 yd² / 5 yd²/gallon = 105.504 gallons. Since paint comes in whole gallons, you'll need to round up to the next whole number, which is 106 gallons.
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I Need help Asap no decimal please just plot the point!
Step-by-step explanation:
if you see the number the line is divided into 6 or to get from 0 to 1 or 2 to 3 it takes 6 space that means the fraction should n/6.
n= a number
2 5/6 that means that there is 2 wholes or 2 6/6
6/6= 1
it is easy to plot 2 5/6 because it is already 5/6, you plot it right on the line that is before 3 or 5 spaces after 2.
1 2/3 is the same as 1 4/6
there is 1 whole or one 6/6. now it is easy you plot it on the line that is 4 spaces away from 1.
Plotted the points on the line. Please see attached.
2 5/6 = 17/6 = 2.83
1 2/3 = 5/3 = 1.67
About 53.6% of the students in class got an A. If 15 students got an A, how many students were in the class?
Answer:
Step-by-step explanation:
56.3% of the student got A
15 students got A
Then,
Let the total number of students be x
56.3% of x= got A
56.3/100 × x =15
0.563x=15
Then x=15/0.563
x=26.6
The number of students can't or be 26.6 so let approximate it
Then, x=27
Therefore 27students are in the class
isolate the variables of 110=m+95
Answer:
15
Step-by-step explanation:
To isolate the variable, subtract 95 on both sides.
110=m + 95
m=15
Hope this helped! :)
Answer:
m=15
Step-by-step explanation:
110=m+95
Just subtract 95 from each side to isolate m and get your answer
110=m+95
-95 -95
15=m