Answer:
Step 2
Step-by-step explanation:
The quadratic formula is given by [tex]x=-b+-\frac{\sqrt{b^{2}-4ac } }{2a}[/tex]
Our equation is y = 2x²-x-6
So here our a = 2, b = -1, and c = -6
We can now plug these numbers into our formula
[tex]x= -(-1) +-\frac{\sqrt{(-1)^{2}-4(2)(-6) } }{2(2)} = 1 +-\frac{\sqrt{1+24} }{4} = 1+-\frac{\sqrt{25} }{4}[/tex]
Step 2 is incorrect because it states that "x equals the negative of negative 1 plus or minus the square root of negative one plus forty-eight all over two times 2."
The correct statement would be "x equals the negative of negative 1 plus or minus the square root of positive one plus forty-eight all over two times 2.", because the square of a negative is positive, resulting in a positive one.
Since this step is incorrect, the steps after are also incorrect, but Harry went wrong at Step 2
Answer:
The above answer is correct.
Step-by-step explanation:
I got it right on the test
The right rectangular prism below is made up of 8 cubes. Each cube has an edge length of 12inch.
What is the volume of this prism?
Answer:
13824 cubic inches
Step-by-step explanation:
So all we need to do is:
1) Find the volume of 1 cube of the 8
2) Multiply that by 8, because 8 of them make the prism.
SO 1)
the volume of cube = side * side * side = 12*12*12 = 1728
SO 2)
the volume of prism = vol(cube) * 8 = 1728 * 8 = 13824
ANSWER: 13824 cubic inches ;)
A rectangular sheet of paper is folded diagonally. What is the length of XY?
15 in
8 in
OA) 23 in.
OB) 19 in.
OC) 15 in.
OD) 17 in.
Answer:
17 inches
Step-by-step explanation:
Pablo runs 7 miles in 80 minutes. At the same rate, how many miles would he run in 64 minutes?
Type the expressions as radicals.
[tex] \sqrt{ {q}^{3} } [/tex]
Step-by-step explanation:
[tex] {q}^{ \frac{3}{2} } = ( {q}^{3} )^{ \frac{1}{2} } = \sqrt{ {q}^{3} } \\ [/tex]
The volume of a cube is 343 cubic inches. What is the length of each edge of the cube?
Answer:7 inches
Step-by-step explanation:
Volume of cube=343
volume of cube=length x length x length
length =L
Volume of cube=LxLxL
343=L^3
L^3=343
Taking the cube root of both sides we get
L=cube root of 343
L=7
Length =7 inches
Steph runs a vehicle body repair shop with one mechanic in Cleveland. Repair time for vehicles is exponentially distributed, with a mean of 2.8 minutes per vehicle. Customers arrive at an average rate of 15 per hour following a Poisson distribution. NOTE: calculate the measures per hour. Calculate system utilization. (Round your answer to the nearest whole percent without the percent sign.) System Utilization =
Answer:
System utilization = 0.7 or 70%
Step-by-step explanation:
Given arrival rate of customer = 15 customer/Hour
Servie rate = [tex] \dfrac{60}{2.8} customer/Hour [/tex]
Now, use the below formula to find the system utilization.
System utilization = [tex] \dfrac{\text{ Arrival rate of customer }}{\text{ Servie rate}}[/tex]
System utilization = [tex] \dfrac{15}{ \dfrac{60}{2.8}}[/tex]
System utilization = [tex] \dfrac{15}{ \dfrac{60}{2.8}}[/tex]
System utilization = 0.7 or 70%
Box measure 4 units by 2.5 by 1.5 units what is the greatest number of cubes side length o 1/2 unit can be pack inside the box
Show details
Answer:120
Step-by-step explanation:
Volume=length x width x height
volume of box=4x2.5x1.5
Volume of box=15
Length of side of cube=1/2=0.5
Volume of cube=0.5x0.5x0.5
Volume of cube=0.125
Number of cube that can pack inside there box=15 ➗ 0.125=120
A restaurant sells four combo meals. Jolly Meal, which cost $7, consists of 2 yogurt cups and 1 sandwich. The Special Meal, which is made up of 2 sandwiches and 1 yogurt cup, cost $12.50. Calculate the cost of the following combo meals if the charge for sandwiches and yogurt cups are the same for all combo meals.
Answer:
Yogurt: $0.50 Sandwich: $6
Step-by-step explanation:
Because if you make the combos equations it would be Y+Y+X=7 and X+X+Y=12.5 so you would solve with those and for it to work with both, 0.50 for yogurt, and 6 for sand which would work.
12 more than 8.2 times a number n is
Answer:
12+ 8.2n
Step-by-step explanation:
12 more than 8.2 times a number n is:
First, 12 more indicates that whatever we get has to add 12 on since it is 12 more.
Second, 8.2 times a number is multiplication and that number is filled in by a variable (n).
Therefore, the equation is 8.2n + 12
The volume of a cone is 565.2 cubic inches. The height of the cone is 15 inches. What is the radius of the cone, rounded to the nearest inch? (Use π = 3.14.) (1 point)
Group of answer choices
3
6
18
36
Answer:
Radius, r = 6 inches
Step-by-step explanation:
We have,
Volume of a cone is 565.2 cubic inches
Height of the cone is 15 inches
It is required to find the radius of the cone. Volume of a cone is given by :
[tex]V=\dfrac{1}{3}\pi r^2 h[/tex]
r is radius of cone
[tex]r=\sqrt{\dfrac{3V}{\pi h}} \\\\r=\sqrt{\dfrac{3\times 565.2}{3.14\times 15}} \\\\r=6\ \text{inch}[/tex]
So, the radius of the cone is 6 inches. The correct option is (b).
Hundreds, tens, and ones
hat number represents the same amount as 3 hundreds + 4 tens +16 ones?
Answer:
356
Step-by-step explanation:
3 hundreds = 3 * 100 = 300
4 tens = 4 * 10 = 40
16 ones = 16 * 1 = 16
Combine the terms: 300 + 40 + 16 = 356
356 is your answer.
~
The operations manager of a manufacturer of television remote controls wants to determine which batteries last the longest in his product. He took a random sample of his remote controls and tested two brands of batteries. Here are the number of minutes of continuous use before the batteries failed for each brand. Is there statistical evidence of a difference in longevity between the two batteries?
Answer:
There is not enough evidence to support the claim that the longevity of the two brand of batteries differs.
Step-by-step explanation:
The question is incomplete:
The sample data for each battery is:
Battery 1: 106 111 109 105
Battery 2: 125 103 121 118
The mean and STD for the sample of battery 1 are:
[tex]M_1=\dfrac{1}{4}\sum_{i=1}^{4}(106+111+109+105)\\\\\\ M_1=\dfrac{431}{4}=107.75[/tex]
[tex]s_1=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{4}(x_i-M)^2}\\\\\\s_1=\sqrt{\dfrac{1}{3}\cdot [(106-(107.75))^2+(111-(107.75))^2+(109-(107.75))^2+(105-(107.75))^2]}\\\\\\ s_1=\sqrt{\dfrac{1}{3}\cdot [(3.06)+(10.56)+(1.56)+(7.56)]}\\\\\\ s_1=\sqrt{\dfrac{22.75}{3}}=\sqrt{7.58333333333333}\\\\\\s_1=2.754[/tex]
The mean and STD for the sample of battery 2 are:
[tex]M_2=\dfrac{1}{4}\sum_{i=1}^{4}(125+103+121+118)\\\\\\ M_2=\dfrac{467}{4}=116.75[/tex]
[tex]s_2=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{4}(x_i-M)^2}\\\\\\s_2=\sqrt{\dfrac{1}{3}\cdot [(125-(116.75))^2+(103-(116.75))^2+(121-(116.75))^2+(118-(116.75))^2]}\\\\\\ s_2=\sqrt{\dfrac{1}{3}\cdot [(68.06)+(189.06)+(18.06)+(1.56)]}\\\\\\ s_2=\sqrt{\dfrac{276.75}{3}}=\sqrt{92.25}\\\\\\s_2=9.605[/tex]
This is a hypothesis test for the difference between populations means.
The claim is that the longevity of the two brand of batteries differs.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0[/tex]
The significance level is α=0.05.
The sample 1, of size n1=4 has a mean of 107.75 and a standard deviation of 2.754.
The sample 2, of size n2=4 has a mean of 116.75 and a standard deviation of 9.605.
The difference between sample means is Md=-9.
[tex]M_d=M_1-M_2=107.75-116.75=-9[/tex]
The estimated standard error of the difference between means is computed using the formula:
[tex]s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{2.754^2+9.605^2}{4}}\\\\\\s_{M_d}=\sqrt{\dfrac{99.841}{4}}=\sqrt{24.96}=4.996[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-9-0}{4.996}=\dfrac{-9}{4.996}=-1.8014[/tex]
The degrees of freedom for this test are:
[tex]df=n_1+n_2-1=4+4-2=6[/tex]
This test is a two-tailed test, with 6 degrees of freedom and t=-1.8014, so the P-value for this test is calculated as (using a t-table):
[tex]P-value=2\cdot P(t<-1.8014)=0.122[/tex]
As the P-value (0.122) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the longevity of the two brand of batteries differs.
Anna has 7 pairs of yellow socks, 8 pairs of red socks, and 2 pairs of blue socks mixed together in a drawer. All pairs of socks are identical except for their colors. What is the smallest number of socks she has to take out without looking to make sure she has 2 matching pairs of socks
To ensure Anna has two matching pairs of socks, she will need to draw out five socks. This illustrates a principle in probability known as the Pigeonhole Principle.
Explanation:In this mathematics question, we are dealing with an example of the Pigeonhole Principle. Anna has 3 different types of socks: yellow, red, and blue. In the worst-case scenario, she picks one of each color for the first three socks- this doesn't give her a pair. To ensure she gets a pair, she would need to take out a fourth sock. Since we only have three different types, this fourth sock will have to be either a yellow, red or blue one, thus ensuring at least one pair. However, the question asks for two pairs. This would involve picking out a fifth sock, in the worst-case scenario this fifth sock could match with the second pair. Hence, to guarantee that there are two matching pairs, she would need to draw out a total of five socks.
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Given two dependent random samples with the following results: Population 1 76 77 66 71 55 63 83 58 Population 2 78 71 71 65 61 71 77 62 Can it be concluded, from this data, that there is a significant difference between the two population means? Let d=(Population 1 entry)−(Population 2 entry). Use a significance level of α=0.1 for the test. Assume that both populations are normally distributed. Step 2 of 5: Find the value of the standard deviation of the paired differences. Round your answer to one decimal place.
Answer: Std = 6.0
Step-by-step explanation:
Let us take a step by step process to solve this problem.
We have from the question that;
Population 1: 76 77 66 71 55 63 83 58
Population 2: 78 71 71 65 61 71 77 62
where n is no of occurrence = 8
taking the difference of P1 - P2 we have;
Difference (d) : -2 6 -5 6 -6 -8 6 -4
Total value of difference = -7
Difference squared (d₁ -d)² = 4 36 25 36 36 64 36 16
Total value of difference squared (d₁ -d)² = 253
The mean Σ = sum of values (d)/total value = -7/8 = -0.875
⇒ We are asked to find the value of the standard deviation of the paired difference.
Standard deviation is given as;
Std = √(Σ (Δd)² / n-1
Std = √[(253) / 8-1]
Std = √(253/7) = 6.0
Std = 6.0
cheers i hope this helped!!!!!!
Match the expressions given in words with their values when m = 6. 42 3 21 15 2 the difference of the product of 3 and m minus the quotient of m divided by 2 arrowRight the sum of 3 times m and 4 times m arrowRight the quotient of 6 divided by the difference of m minus 3 arrowRight the sum of m and 3 divided by the difference of m minus 3 arrowRight
Answer:
154223Step-by-step explanation:
When m=6
(1) The difference of the product of 3 and m minus the quotient of m divided by 2
[tex]3m-\dfrac{m}{2}\\=3(6)- \dfrac{6}{2}\\=18-3\\=15[/tex]
(2)The sum of 3 times m and 4 times m
3m+4m
=3(6)+4(6)
=18+24
=42
(3)The quotient of 6 divided by the difference of m minus 3
[tex]\dfrac{6}{m-3} =\dfrac{6}{6-3} =\dfrac{6}{3} =2[/tex]
(4)The sum of m and 3 divided by the difference of m minus 3
[tex]\dfrac{m+3}{m-3}= \dfrac{6+3}{6-3}=\dfrac{9}{3}=3[/tex]
Mr. Hobbs has 10 blue markers, 6 black markers, and 8 red markers
on his desk. What fraction of black markers can be found on Mr.
Hobbs' desk?
Select one:
1.3/9
2.5/12
3.1/4
4.1/3
Answer:
4
Step-by-step explanation:
Im not completely sure
the quesiton is in the picture
Answer:
The three equivalent options are: [tex]\frac{1}{6}x+47[/tex], [tex]\frac{5}{3}x+35-\frac{3}{2}x+12[/tex], and [tex]5(\frac{1}{3} x+(5)(7)-(3)(\frac{1}{2}x)+(3)(4)[/tex]
Step-by-step explanation:
Expand [tex]5(\frac{1}{3}x+7)-3(\frac{1}{2}x-4)[/tex] to get [tex]\frac{5}{3}x+35-\frac{3}{2}x+12[/tex].
Simplifying this gets you [tex]\frac{1}{6}x+47[/tex].
Which choice are equivalent to the fraction below? Check all that apply 6^7/6^5
Answer:36
Step-by-step explanation:u
6^7/6^5
6^(7-5)
6^2
6x6=36
corse hereo Joe has two drawers containing socks. The first contains three pairs of red socks, two pairs of black socks, and one pair of white socks. The second drawer contains two pairs of red socks, one pair of black socks, and two pairs of white socks. Each morning Joe flips a fair coin and picks two socks at random from the first drawer if heads is flipped; if tails is flipped he instead picks two socks at random from the second drawer. Joe is observed leaving his house this morning wearing one red and one black sock. What is the probability he flipped heads today?
Answer:
P(H/A) = 0.6716
Step-by-step explanation:
Let's call H the event that Joe flipped heads, T the event that Joe flipped tails and A the event that Joe wear one read and one black sock.
So, the probability that he flipped heads given that Joe wears one read and one black sock is calculated as:
P(H/A) = P(H∩A)/P(A)
Where P(A) = P(H∩A) + P(T∩A)
On the other hand, nCx gives the number of combinations in which we can select x elements from a group of n elements. nCx is calculated as:
[tex]nCx=\frac{n!}{x!(n-x)!}[/tex]
So, the probability that Joe wear one red and one black sock given that he picks the socks from the first drawer is:
[tex]\frac{6C1*4C1*2C0}{12C2}=0.3636[/tex]
Because he need to choose one red sock from the 6 that are in the first drawer, one black sock from the 4 that are in the first drawer and 0 white socks. Additionally there are 12C2 ways to choose a pair of socks.
Therefore the probability P(H∩A) that that Joe flipped heads and Joe wear one read and one black sock is:
P(H∩A) = 0.5*0.3636 = 0.1818
Because there is a probability of 0.5 to flipped heads and the probability that Joe wear one red and one black sock given that he flipped heads is 0.3636.
At the same way, the probability that Joe wear one red and one black sock given that he picks the socks from the second drawer is:
[tex]\frac{4C1*2C1*4C0}{10C2}=0.1778[/tex]
Therefore the probability P(T∩A) that that Joe flipped tails and Joe wear one read and one black sock is:
P(T∩A) = 0.5 * 0.1778 = 0.0889
Finally, P(A) and P(H/A) is equal to:
P(A) = 0.1818 + 0.0889 = 0.2707
P(H/A) = 0.1818/0.2707 = 0.6716
−15x + 60 ≤ 105 AND 14x + 11 ≤ −31
Answer:
X=-3
Step-by-step explanation:
help. If 20 men can survive for 24 days on 15 cans of rations, how many cans will be needed for 16 men to survive for 36 days?
Answer: 29 cans.
Step-by-step explanation:
20 can survive 24 days with 15 cans.
If X is the number of days that a man can survive with one can of rations.
so X is in the units can/day
then we have that:
24/15*X = 20
X = 20*15/24 = 12.5
This means that a man can live 12.5 days with a can of food.
then, for 16 men and 36 days we have:
(36/C)*12.5 = 16
C = (36/16)*12.5 = 28.1215
And we can not have a 0.1215 of a can, so we should round it up to 29 cans.
If 15 bahs are equal to 24 rahs, and 9 rahs are equal in value to 15 yahs, how many bahs are equal in value to 1000 yahs?
Answer:
375
Step-by-step explanation:
b : r = 15 : 24
r : y = 9 : 15 = 3 : 5 = 24 : 40
Then ...
b : r : y = 15 : 24 : 40
The number of bahs equivalent to 1000 yahs is ...
bahs = (15/40)(1000) = 375
375 bahs are equal in value to 1000 yahs.
tina has a doll which she can dress with a hat, a scarf and a jacket.
she has 3 different colour hat, 4 different colour scarves and 5 different colour jackets
Tina chose a hat a scarf and a jacket for her doll
how many combinations of hat scarf and jacket can she choose
Answer:
60 combinations
Step-by-step explanation:
3 × 4 × 5 = 60
Hope i helped!
Tina can choose from 60 different combinations of hat, scarf, and jacket for her doll.
To find the total number of combinations Tina can choose for her doll's outfit, you can use the multiplication principle.
Tina has 3 choices for the hat, 4 choices for the scarf, and 5 choices for the jacket.
To find the total number of combinations, multiply the number of choices for each item together:
3 (choices for the hat) × 4 (choices for the scarf) × 5 (choices for the jacket) = 60
Tina can choose from 60 different combinations of hat, scarf, and jacket for her doll.
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Jenny is 12 years older than Nancy. Five years ago Jenny was three times as old as Nancy. How old is each now?
Answer:
Jenny = 23 | Nancy = 11
Step-by-step explanation:
The cost, not including tax, of paper and pens
at the card store is $21.79. The tax is 9% of
the selling price. What is the total cost of the
pens and pencils including tax?
A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 125 people living in Gastown and finds that 25 have an annual income that is below the poverty line.
Part i) The proportion of the 125 people who are living below the poverty line, 25/125, is which of the following:________.
A. variable of interest.
B. parameter.
C. statistic.
Part ii) Use the sample data to compute a 95% confidence interval for the true proportion of Gastown residents living below the poverty line.
(Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places).
95% confidence interval = ( ___ , ___ )
Answer:
Part I: C. statistic
Part II: 95% confidence interval = (0.130, 0.270)
Step-by-step explanation:
Part I: The proportion of the 125 people who are living below the poverty line, 25/125, is which of the following: statistic, as it is a measure taken from the sample.
Part II:
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.2.
[tex]p=X/n=25/125=0.2[/tex]
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{125}}\\\\\\ \sigma_p=\sqrt{0.00128}=0.035777[/tex]
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:
[tex]MOE=z\cdot \sigma_p=1.96 \cdot 0.035777=0.070122[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=p-z \cdot \sisgma_p = 0.2-0.070122=0.129878\\\\UL=p+z \cdot \sisgma_p = 0.2+0.070122=0.270122[/tex]
The 95% confidence interval for the population proportion is (0.130, 0.270).
Multiply and simplify: (6x + 3y)(6x − 3y)
Answer:
36x² - 9y²
Step-by-step explanation:
We see that the given expression (6x + 3y)(6x - 3y) looks just like the expression (a + b)(a - b). When multiplied out, this is a difference of squares identity that I highly recommend you memorise:
(a + b)(a - b) = a² - b²
Here, a = 6x and b = 3y, so plug these in:
(6x + 3y)(6x - 3y) = (6x)² - (3y)² = 36x² - 9y²
Answer:
36x² - 9y²
Step-by-step explanation:
(6x + 3y)(6x − 3y)
(6x)² - (3y)²
36x² - 9y²
Suppose the true proportion of students at a college who study abroad is 0.25. I select a random sample of 40 students from the college and record if they have studied abroad. What is the probability that the proportion of students in my sample who have studied abroad is less than 0.2
Answer:
[tex]\mu_{\hat p} = 0.25[/tex]
[tex]\sigma_{\hat p}= \sqrt{\frac{0.25*(1-0.25)}{40}}= 0.0685[/tex]
[tex] z = \frac{0.2-0.25}{0.0685}= -0.730[/tex]
And we can use the normal standard distribution or excel to find this probability and we got:
[tex] P(\hat p <0.2) = P(z<-0.730)= 0.233[/tex]
Step-by-step explanation:
We define the parameter as the proportion of students at a college who study abroad and this value is known [tex]p =0.25[/tex], we select a sample size of n =40 and we are interested in the probability associated to the sample proportion, but we know that the distirbution for the sample proportion is given by:
[tex]\hat p \sim N(p , \sqrt{\frac{p(1-p)}{n}}[/tex]
And the paramters for this case are:
[tex]\mu_{\hat p} = 0.25[/tex]
[tex]\sigma_{\hat p}= \sqrt{\frac{0.25*(1-0.25)}{40}}= 0.0685[/tex]
We want to find the following probability:
[tex]P(\hat p< 0.2)[/tex]
For this case since we know the distribution for the sample proportion we can use the z score formula given by:
[tex] z = \frac{\hat p -\mu_{\hat p}}{\sigma_{\hat p}}[/tex]
Replacing the info given we got:
[tex] z = \frac{0.2-0.25}{0.0685}= -0.730[/tex]
And we can use the normal standard distribution or excel to find this probability and we got:
[tex] P(\hat p <0.2) = P(z<-0.730)= 0.233[/tex]
To find the probability that the proportion of students in your sample who have studied abroad is less than 0.2, you can use the normal distribution approximation for sampling proportions.
Explanation:To find the probability that the proportion of students in your sample who have studied abroad is less than 0.2, you can use the normal distribution approximation for sampling proportions. First, find the mean of the sampling distribution, which is equal to the true proportion (0.25) multiplied by the sample size (40), giving a mean of 10.
Next, find the standard deviation of the sampling distribution, which is calculated as the square root of (p(1-p)/n), where p is the true proportion (0.25) and n is the sample size (40). The standard deviation is approximately 0.071.
Finally, use the normal distribution to find the probability that the proportion is less than 0.2. Using the z-score formula, calculate the z-score as (sample proportion - mean)/(standard deviation). In this case, the z-score is approximately -1.41. Use a standard normal distribution table or calculator to find the corresponding probability, which is approximately 0.079.
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A car that normally sells for $20,000 is on sale for $16,000. What percent of the original price of the car is the final price?
Answer:
80%
Step-by-step explanation:
20000. take out 3 zeros from both numbers and you get 20 and 16. 20 is 4 times 5 and 16 is 4 times 4 if 20 is 100% then 4 over 5 is 80%
Poornima is a stay-at-home parent who lives in San Francisco and teaches tennis lessons for extra cash. At a wage of $30 per hour, she is willing to teach 3 hours per week. At $50 per hour, she is willing to teach 7 hours per week. Using the midpoint method, the elasticity of Poornima's labor supply between the wages of $30 and $50 per hour is approximately(1.6,0.13,0.63,25) , which means that Poornima's supply of labor over this wage range is (elastic, inelastic)
Answer:
We can deduce that the elasticity of the labor supply is greater than 1 the labor supply is considered elastic
Step-by-step explanation:
The formula to use is the following:
Elasticity = (Change in working hours / Average working hours) / (Change in wage rate / Average wage rate)
we replace the data
Elasticity = [(7 - 3) / (7 + 3) / 2] / [(50 - 30) / (50 + 30) / 2]
Elasticity = [4 / (10/2)] / [20 / (80/2)]
Elasticity = (4/5) / (20/40)
Elasticity = 0.8 / 0.5
OUTCOME
Elasticity = 1.6
We can deduce that the elasticity of the labor supply is greater than 1 the labor supply is considered elastic
The elasticity of Poornima's labor supply between the wages of $30 and $50 per hour is approximately 1.5. This shows that Poornima's supply of labor in this wage range is elastic, indicating responsiveness to wage changes.
Explanation:The elasticity of labor supply can be calculated using the midpoint method. This method measures elasticity as the percent change in quantity supplied divided by the percent change in wage. The percent change in quantity supplied is calculated as (Q2-Q1)/[(Q1+Q2)/2], where Q1 = 3 and Q2 = 7. That gives us (7-3)/[(3+7)/2] = 1. The percent change in wage is calculated similarly as (P2-P1)/[(P1+P2)/2], where P1 = $30 and P2 = $50, giving us (50-30)/[(30+50)/2] = 0.67. By dividing the percent change in quantity supplied by the percent change in wage, we get the elasticity of labor supply: 1/0.67 = 1.5 (rounded).
Therefore, the elasticity of Poornima's labor supply between wages of $30 and $50 per hour is approximately 1.5. Because the elasticity is greater than 1, Poornima's supply of labor over this wage range is elastic, meaning she is responsive to wage changes.
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