Given the following statistics for women over the age of 50 entering our medical clinic: 1% actually have breast cancer 90% of the women who have breast cancer are going to get a positive test result (affirming that they have the disease) 8% of those that actually don’t have the disease are going to be told that they do have breast cancer (a “false positive”) What’s the actual probability, if a woman gets a positive test result, that she actually does have breast cancer?

Answers

Answer 1

Answer: 91.2%

Step-by-step explanation:

Of the 1% of women that have breast cancer, 90% of those are tested positive with 8% of those being false positive. 8% of 90% is 8.8% so 91.2% chance.


Related Questions

Find S for the given geometric series. Round answers to the nearest hundredth, if necessary.

a1=0.2, a5=259.2, r=6

a) 311
b)51
c)222.2
d)624.96

Answers

Answer:

A

Step-by-step explanation:

Sum of the first n terms of a geometric series is:

S = a₁ (1 - r^n) / (1 - r)

Here, a₁ = 0.2, r = 6, and n = 5.

S = 0.2 (1 - 6^5) / (1 - 6)

S = 311

Answer:

Option A

Step-by-step explanation:

For the given geometric series  

a₁ = 0.2

a₅ = 259.2

r = 6

Then we have to find the sum of initial 5 terms of this series

[tex]S_{n} =\frac{a_1(r^4-1)}{(r-1)}=\frac{0.2(6^3-1)}{(6-1)}[/tex]

[tex]=\frac{0.2(7776-1)}{5}[/tex]

[tex]\frac{0.2\times 7775}{5}[/tex]

= 311

Option A is the answer.

A refrigerator contains 6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11 plums, and 2 mangos. Imagine you stick your hand into the refrigerator and pull out a piece of fruit at random. What is the sample space for your action? ????={6, 5, 10, 3, 7, 11, 2}S={6, 5, 10, 3, 7, 11, 2} ????={apple, orange, banana, pear, peach, plum, mango}S={apple, orange, banana, pear, peach, plum, mango} ????={6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11 plums, 2 mangos}

Answers

Answer:

4th Option is correct.

Step-by-step explanation:

Given:

Number of apples in refrigerator = 6

Number of oranges in refrigerator = 5

Number of bananas in refrigerator = 10

Number of pears in refrigerator = 3

Number of peaches in refrigerator = 7

Number of plums in refrigerator = 11

Number of mangoes in refrigerator = 2

A piece is randomly taken out from refrigerator.

To find: Sample Space of the experiment

Sample Space : It is a set which contain all the possible outcome / results of the experiment.

So, here Sample Space = { 6 apples , 5 oranges , 10 bananas , 3 pears , 7 peaches , 11 plums , 2 mangoes }

Therefore, 4th Option is correct.

You want to have $600,000 when you retire in 10 years. If you can earn 8% interest compounded monthly, how much would you need to deposit now into the account to reach your retirement goal?

Answers

Answer:

  $270,314.08

Step-by-step explanation:

The multiplier each month is 1+0.08/12 ≈ 1.0066667, so after 120 months, the amount is multiplied by (1.0066667)^120 ≈ 2.2196402. The amount needed is ...

  $600,000/2.2196402 ≈ $270,314.08

Final answer:

To reach a retirement goal of $600,000 in 10 years with an 8% interest rate compounded monthly, you would need to deposit approximately $277,002.66 now.

Explanation:

In this case, we're using a formula to determine the amount needed to deposit today (P) for a future goal ($600,000) using an interest rate (r) of 8% compounded monthly for ten years. The formula to use is P = F / (1 + r/n)^(nt), where:

F is the future value of the investment ($600,000) r is the annual interest rate (8% or 0.08 as a decimal) n is the number of times that interest is compounded per unit t (12 times a year for our case) t is the time the money is invested for in years (10 years).

So, you need to plug these figures into the equation: P = 600,000 / (1 + 0.08/12)^(12*10). After doing the math, you would need to deposit around $277,002.66 now to reach your retirement goal of $600,000 in ten years given an 8% annual interest rate compounded monthly.

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The lengths of plate glass parts are measured to the nearest tenth of a millimeter. The lengths are uniformly distributed with values at every tenth of a millimeter starting at 590.2, and continuing through 590.8. Determine the mean and variance of the lengths. (a) mean (in tenths of millimeters) Round your answer to two decimal places (e.g. 98.76). (b) variance (in tenths of millimeters2) Round your answer to three decimal places (e.g. 98.765).

Answers

Answer:     [tex]\text{Mean length}=590.5\ mm\\\\\text{Variance of the lengths}=0.03\ mm[/tex]

Step-by-step explanation:

The mean and variance of a continuous uniform distribution function with parameters m and n is given by :-

[tex]\text{Mean=}\dfrac{m+n}{2}\\\\\text{Variance}=\dfrac{(n-m)^2}{12}[/tex]

Given : [tex] m=590.2\ \ \ n=590.80[/tex]

[tex]\text{Then, Mean=}\dfrac{590.2+590.8}{2}=590.5\ mm\\\\\text{Variance}=\dfrac{(590.8-590.2)^2}{12}=0.03\ mm[/tex]

Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a​ cat; 70 had neither a cat nor a​ dog, and in addition did not have a​ parakeet; 4 had a​ cat, a​ dog, and a parakeet. How many had a parakeet​ only?

Answers

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

 parakeet

- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

 of 67 and 520

* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

 D represented the dog

 P represented the parakeet

- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

 dog only had 22 - 4 = 18 families

- The common part between the circle of the dog and the circle of the

 parakeet only had a families

- The common part between the circle of the cat and the circle of the

 parakeet only had b families

- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

A clothing store has just advertised at a bargain price, that a customer tries on a t-shirt is 0.40. a new range of t-shirts. The probability If a customer tries a t-shirt, the probability that they will buy it is 0.70 while if a customer does not try on a t-shirt, the probability that they will buy it is 0.15. A customer has just bought a t-shirt. Find the probability that the customer did not try on the t- shirt.

Answers

Answer:

The probability that the customer did not try on the t- shirt is:

                             0.2432

Step-by-step explanation:

It is given that the probability that a customer tries a t-shirt is: 0.40

After he will try

The probability that he will buy the t-shirt is: 0.70

The probability that he will not try t-shirt is: 1-0.40=0.60

If he will not try

then the probability of buying a t-shirt is: 0.15

This means that the total probability of Buying a t-shirt is:

  0.40×0.70+0.60×0.15

= 0.37

It is given that the customer bought a t-shirt, we need to find the probability that he did not try the  t-shirt:

The probability is given by:

[tex]\dfrac{0.60\times 0.15}{0.37}\\\\\\=\dfrac{0.09}{0.37}\\\\\\=0.2432[/tex]

Final answer:

The question asks for the conditional probability that a customer did not try on a t-shirt given that they bought it. This probability value can be calculated using the total probability theorem and Bayes' theorem. It is found to be approximately 0.159.

Explanation:

This question falls under the topic of probability, specifically conditional probability and Bayes' theorem. The probability values are given in the problem statement but it seeks the probability that a customer did not try on a t-shirt given that they bought it.

Let A represent the event that a customer buys a t-shirt and B1 represent the event that a customer tries on a t-shirt whereas B2 represent the event that the customer did not try on a t-shirt.

We are given that P(B1) = 0.40, P(A|B1) = 0.70 and P(A|B2) = 0.15. We are asked to find P(B2|A).

To find P(B2|A), we use Bayes' theorem:

P(B2|A) = (P(B2) * P(A|B2)) / P(A)

We know that P(B1) + P(B2) = 1, so P(B2) = 1 - P(B1) = 1 - 0.40 = 0.60.

The probability that a customer tried a t-shirt is 0.40 and bought it is 0.70, that yields the joint probability P(A, B1) = P(B1) * P(A|B1) = 0.40 * 0.70 = 0.28. Similarly the joint probability P(A, B2) = P(B2) * P(A|B2) = 0.60 * 0.15 = 0.09.

P(A) is the probability that a customer buys a t-shirt and is calculated using the total probability theorem as P(A) = P(A, B1) + P(A, B2) = 0.28 + 0.09 = 0.37.

Substituting the values we calculated into Bayes' theorem, we find:

P(B2|A) = (0.60 * 0.15) / 0.37 ≈ 0.24.

So, the probability that a customer did not try the t-shirt given that they bought it is approximately 0.24.

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It is known that for all tests administered last​ year, the distribution of scores was approximately normal with mean 74 and standard deviation 7.1. a. A particular employer requires job candidates to score at least 80 on the dexterity test. Approximately what percentage of the test scores during the past year exceeded 80​?

Answers

Answer: 19.77%

Step-by-step explanation:

Given: Mean : [tex]\mu=74[/tex]

Standard deviation : [tex]\sigma = 7.1[/tex]

The formula to calculate z-score is given by :_

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x= 80, we have

[tex]z=\dfrac{80-74}{7.1}\approx0.85[/tex]

The P-value = [tex]P(z>0.85)=1-P(z<0.85)=1-0.8023374=0.1976626[/tex]

In percent , [tex]0.1976626\times100=19.76626\%\approx19.77\%[/tex]

Hence, the approximate percentage of the test scores during the past year exceeded 80 =19.77%

Consider the equation of the line, c(c2 + 2)y = c − x where c > 0 is a constant. (a) Find the coordinates of the x-intercept and the y-intercept. x-intercept ( , ) y-intercept ( , ) (b) Find a formula for the area of the triangle enclosed between the line, the x-axis, and the y-axis. A(c) =

Answers

The equation of the line indicates that the x and y-intercept and the formula for the area of the triangle are;

x-intercept (c, 0)

y-intercept (0, 1/(c² + 7))

A(c) = c/(2·(c² + 7))

The steps used to find the x-intercept and the y-intercept are presented as follows;

The equation of the line c·(c² + 7)·y = c - x, can be expressed in the slope intercept form to find the coordinates of the x-intercept and the coordinates of the y-intercept as follows;

c·(c² + 7)·y = c - x

y = (c - x)/(c·(c² + 7))

y = c/(c·(c² + 7)) - x/(c·(c² + 7))

y = 1/((c² + 7)) - x/(c·(c² + 7))

The above equation is in the slope-intercept form, y = m·x + c

Where c is the y-coordinate of the y-intercept, and (0, c) ids the coordinate of the y-intercept; Therefore, the coordinates of the y-intercept is; (0,  1/((c² + 7)))

The coordinate of the x-intercept can be found by plugging in y = 0, in the above equation to get;

0 = 1/((c² + 7)) - x/(c·(c² + 7))

x/(c·(c² + 7)) = 1/((c² + 7))

x = (c·(c² + 7))/((c² + 7))

(c·(c² + 7))/((c² + 7)) = c

x = c

Therefore coordinates of the x-intercept is; (c, 0)

The triangle enclosed by the line and the x-axis and y-axis is a right triangle, therefore;

The positive x and y-values of the x-intercept and y-intercept indicates that the area of the triangle is the product half the distance from the origin to the y-intercept and the distance from the origin to the x-intercept

Area = (1/2) × (1/((c² + 7)) - 0) × (c - 0)

(1/2) × (1/((c² + 7))) × (c) = c/(2·(c² + 7)

Area of the triangle, A(c) = c/(2·(c² + 7)

The complete question found through search can be presented as follows;

Consider the equation of the line c·(c² + 7)·y = c - x where c > 0 is a constant

(a) Find the coordinates of the x-intercept and the y-intercept

x-intercept (  ,  )

y-intercept (  ,  )

(b) Find a formula for the area of the triangle enclosed between the line, the x-axis and the y-axis

In a survey of 520 likely voters in a certain city, 307 said that they planned to vote to reelect the incumbent mayor. What is the probability that a surveyed voter plans to vote to reelect the mayor? Write only a number as your answer. Round to two decimal places (for example: 0.43).

Answers

Answer: 0.59

Step-by-step explanation:

Probability is a measure that quantifies the likelihood that events will occur.

Probabilities can be numerically described by the number of desired outcomes divided by the total number of all outcomes .

In this case, the number of desired outcomes is 307 (surveyed voters who plan to vote to reelect the mayor), and the total number of all outcomes is 520 (total of surveyed voters) .

Then, the probability that a surveyed voter plans to vote to reelect the mayor is calculated as:

[tex]\frac{307}{520}=0.59[/tex]

Final answer:

The probability that a surveyed voter plans to vote to reelect the mayor is 0.59.

Explanation:

To find the probability that a surveyed voter plans to vote to reelect the mayor, we divide the number of surveyed voters who plan to reelect the mayor by the total number of surveyed voters.


Given that 307 out of 520 likely voters plan to reelect the incumbent mayor, the probability is:


Probability = Number of surveyed voters who plan to reelect the mayor / Total number of surveyed voters


Probability = 307 / 520 = 0.59 (rounded to two decimal places)

If f(x)=3x^2-2 and g(x)=4x+2, what is the value of (f+g)(2)

Answers

[tex](f+g)(x)=3x^2-2+4x+2=3x^2+4x\\\\(f+g)(2)=3\cdot2^2+4\cdot2=12+8=20[/tex]

Given the stem and leaf plot, which of the following statements is true?

STEM LEAF

2 9

3 2 6 7

4 1 2

5 0

6

7 5

a) There are no outliers on the stem and leaf plot; b) the numbers 29 and 75 are the outliers on the stem and leaf plot; c) the number 75 is an outlier on the stem and leaf plot; d) the number 60 is the outlier on the stem and leaf plot.

Answers

Answer: c) The number 75 is an outlier on the stem and leaf plot.

Step-by-step explanation:

An outlier is a value in data which is extremely large or small from all the values. It appears detached from the other values in data.

When we look in the given stem-leaf plot, there is no leaf attached to the stem with value 6.

It mean there is no value between 50 and 75.

It shows that the value of 75 is detached from the other values in the data.

The number 75 is an outlier on the stem and leaf plot.

Answer:

The answer is C

Step-by-step explanation:

Problem Page
The Bailey family and the Harris family each used their sprinklers last summer. The water output rate for the Bailey family's sprinkler was 15 L per hour. The water output rate for the Harris family's sprinkler was 40 L per hour. The families used their sprinklers for a combined total of 55 hours, resulting in a total water output of 1325
. How long was each sprinkler used?

Answers

Answer:

Bailey family's sprinkler was used for 35 hours and Harris family's sprinkler was used for 20 hours.

Step-by-step explanation:

 Set up a system of equations.

Let be "b" the time Bailey family's sprinkler was used and "h" the time Harris family's sprinkler was used.

Then:

[tex]\left \{ {{b+h=55} \atop {15b+40h= 1,325}} \right.[/tex]

You can use the Elimination method. Multiply the first equation by -15, then add both equations and solve for "h":

[tex]\left \{ {{-15b-15h=-825} \atop {15b+40h= 1,325}} \right.\\.............................\\25h=500\\\\h=\frac{500}{25}\\\\h=20[/tex]

Substitute [tex]h=20[/tex] into an original equation and solve for "b":

[tex]b+20=55\\\\b=55-20\\\\b=35[/tex]

trains A and B are 240 miles apart. Both start at the same time and travel toward each other. They meet 3 hours later. The speed of train A is 20 miles faster than train B. Find the speed of each train.

Answers

Final answer:

Train B travels at a speed of 30 miles per hour and train A travels at a speed of 50 miles per hour.

Explanation:

Let's say the speed of train B is x miles per hour. Since train A is 20 miles per hour faster, the speed of train A is x + 20 miles per hour.

Distance = Speed x Time

For train A, Distance = (x +20) * 3

For train B, Distance = x * 3

Since they meet 240 miles apart, the sum of their distances is 240:

(x + 20) * 3 + x * 3 = 240

3x + 60 + 3x = 240

6x = 180

x = 30

Hence, train B travels at a speed of 30 miles per hour and train A travels at a speed of 50 miles per hour.

if the probability of an event happening is 65% then the probability this event does not occur?

Answers

You must know that percent are ALWAYS taken out of 100. This means that 100 subtracted by 65 will give the percent that this event won't happen:

100 - 65 = 35

This event has 65% probability of happening and a 35% of NOT happening

Hope this helped!

~Just a girl in love with Shawn Mendes

You pick 7 digits (0-9) at random without replacement, and write them in the order picked. What is the probability that you have written the first 7 digits of your phone number

Answers

Final answer:

The probability of writing the first 7 digits of your phone number is 1/60480.

Explanation:

To determine the probability of choosing the first 7 digits of your phone number in the given scenario, we need to calculate the probability of choosing each digit correctly and in order. Since there are 10 digits to choose from, the probability of choosing the first digit correctly is 1/10. The probability of choosing the second digit correctly is 1/9, since one digit has already been chosen. Continuing this pattern, the probability of choosing all 7 digits correctly and in order is:



P(choosing all seven numbers correctly) = P(choosing 1st number correctly) * P(choosing 2nd number correctly) * ... * P(choosing 7th number correctly)



So, the probability is:



1/10 * 1/9 * 1/8 * 1/7 * 1/6 * 1/5 * 1/4 = 1/60480

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Final answer:

The probability of writing the first 7 digits of your phone number is 1/604,800.

Explanation:

The probability of writing the first 7 digits of your phone number depends on the specific digits in your phone number. However, assuming that all digits are equally likely to be chosen, the probability can be calculated by multiplying the probabilities of choosing each digit correctly. Since there are 10 digits to choose from and you are picking 7, the probability would be:

Probability of choosing the first digit correctly: 1/10Probability of choosing the second digit correctly: 1/9 (since you are picking without replacement)Probability of choosing the third digit correctly: 1/8Probability of choosing the fourth digit correctly: 1/7Probability of choosing the fifth digit correctly: 1/6Probability of choosing the sixth digit correctly: 1/5Probability of choosing the seventh digit correctly: 1/4

To calculate the overall probability, you multiply these individual probabilities together:

1/10 * 1/9 * 1/8 * 1/7 * 1/6 * 1/5 * 1/4= 1/(10*9*8*7*6*5*4)= 1/604,800

So, the probability of writing the first 7 digits of your phone number is 1/604,800.

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Suppose that we have a sample space S = {E 1, E 2, E 3, E 4, E 5, E 6, E 7}, where E 1, E 2, ..., E 7 denote the sample points. The following probability assignments apply: P(E 1) = 0.1, P(E 2) = 0.15, P(E 3) = 0.15, P(E 4) = 0.2, P(E 5) = 0.1, P(E 6) = 0.05, and P(E 7) = 0.25.
A= {E1, E4, E6}
B= {E2, E4, E7}
C= {E2, E3, E5, E7}
(a) Find P(A), P(B), and P(C). (b) What is P(A ∩ B)? (c) What is P(A ∪ B)? (d) Are events A and C mutually exclusive?

Answers

Answer:

(a) The probability of P(A), P(B), and P(C) are 0.35, 0.6 and 0.65 respectively.

(b) The probability of P(A ∩ B) is 0.2.

(c) The probability of P(A ∪ B) is 0.75.

(d) Events A and C mutually exclusive because the intersection of set A and C is null set or ∅.

Step-by-step explanation:

The given sample space is

[tex]S=\{E_1,E_2,E_3,E_4,E_5,E_6,E_7\}[/tex]

[tex]P(E_1)=0.1, P(E_2)=0.15,P(E_3)=0.15,P(E_4)=0.2,P(E_5)=0.1,P(E_6)=0.05, P(E_7)=0.25[/tex]

It is given that

[tex]A=\{E_1,E_4,E_6\}[/tex]

[tex]B=\{E_2,E_4,E_7\}[/tex]

[tex]C=\{E_2,E_3,E_5,E_7\}[/tex]

(a)

[tex]P(A)=P(E_1)+P(E_4)+P(E_6)=0.1+0.2+0.05=0.35[/tex]

[tex]P(B)=P(E_2)+P(E_4)+P(E_7)=0.15+0.2+0.25=0.6[/tex]

[tex]P(C)=P(E_2)+P(E_3)+P(E_5)+P(E_7)=0.15+0.15+0.1+0.25=0.65[/tex]

Therefore the probability of P(A), P(B), and P(C) are 0.35, 0.6 and 0.65 respectively.

(b)

A ∩ B represent the common elements of set A and set B.

[tex]A\cap B=\{E_4\}[/tex]

[tex]P(A\cap B)=P(E_4)=0.2[/tex]

The probability of P(A ∩ B) is 0.2.

(c)

A ∪ B represent all the elements of set A and set B.

[tex]A\cup B=\{E_1,E_2,E_4,E_6,E_7\}[/tex]

[tex]P(A\cup B)=P(E_1)+P(E_2)+P(E_4)+P(E_6)+P(E_7)[/tex]

[tex]P(A\cup B)=0.1+0.15+0.2+0.05+0.25=0.75[/tex]

The probability of P(A ∪ B) is 0.75.

(d)

Set A and C has no common element. So, the intersection of set A and C is empty set.

Yes, events A and C mutually exclusive because the intersection of set A and C is null set or ∅.

Final answer:

The probability of events A, B, and C are calculated by summing the individual probabilities of their constituent sample points. The probability of the intersection of events A and B is equal to the probability of the common sample point. The probability of the union of events A and B is obtained by subtracting the probability of the intersection from the sum of their individual probabilities. Events A and C are not mutually exclusive because they have common sample points.

Explanation:

(a) Probability of events A, B, and C:

P(A) = P(E1) + P(E4) + P(E6) = 0.1 + 0.2 + 0.05 = 0.35P(B) = P(E2) + P(E4) + P(E7) = 0.15 + 0.2 + 0.25 = 0.6P(C) = P(E2) + P(E3) + P(E5) + P(E7) = 0.15 + 0.15 + 0.1 + 0.25 = 0.65

(b) Probability of intersection of events A and B:

P(A ∩ B) = P(E4) = 0.2

(c) Probability of union of events A and B:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 0.35 + 0.6 - 0.2 = 0.75

(d) Mutually exclusive events A and C:

No, events A and C are not mutually exclusive because they have common sample points in E2 and E7.

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Problem Page
A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 80 pounds. The truck is transporting 55 large boxes and
70 small boxes. If the truck is carrying a total of 4850 pounds in boxes, how much does each type of box weigh?

Answers

For this case we propose a system of equations:

x: Variable representing the weight of large boxes

y: Variable that represents the weight of the small boxes

So

[tex]x + y = 80\\55x + 70y = 4850[/tex]

We clear x from the first equation:

[tex]x = 80-y[/tex]

We substitute in the second equation:

[tex]55 (80-y) + 70y = 4850\\4400-55y + 70y = 4850\\15y = 450\\y = 30[/tex]

We look for the value of x:

[tex]x = 80-30\\x = 50[/tex]

Large boxes weigh 50 pounds and small boxes weigh 30 pounds

Answer:

Large boxes weigh 50 pounds and small boxes weigh 30 pounds

Answer: A large box weighs 50 pounds and a small box weighs 30 pounds.

Step-by-step explanation:

Set up a system of equations.

Let be "l" the weight of a large box and "s" the weight of a small box.

Then:

[tex]\left \{ {{l+s=80} \atop {55l+70s=4,850}} \right.[/tex]

You can use the Elimination method. Multiply the first equation by -55, then add both equations and solve for "s":

[tex]\left \{ {{-55l-55s=-4,400} \atop {55l+70s=4,850}} \right.\\.............................\\15s=450\\\\s=\frac{450}{15}\\\\s=30[/tex]

Substitute [tex]s=30[/tex] into an original equation and solve for "l":

[tex]l+(30)=80\\\\l=80-30\\\\l=50[/tex]

An old picture frame has dimensions 33 inches by 24 inches. What one length must be cut from each dimension so that the ratio of the shorter side to the longer side is 2/3?

Answers

Final answer:

To achieve a 2:3 ratio for the picture frame's dimensions, 6 inches must be cut from both the length and width.

Explanation:

To resize the picture frame while maintaining a specific ratio between its sides, we need to establish a proportion based on the desired ratio of 2:3 (shorter side to the longer side). Let's denote the amount that needs to be cut from the shorter side as x inches, and the amount to be cut from the longer side as y inches. After cutting, the dimensions of the frame will be (33 - y) inches by (24 - x) inches.

We want to set up a proportion to reflect the desired ratio: (24 - x)/(33 - y) = 2/3. To solve for x and y, we can use the property that cross-multiplying the terms in a proportion gives us an equality: 3(24 - x) = 2(33 - y). This simplifies to 72 - 3x = 66 - 2y. We also know that the amount cut off from both dimensions should be the same, thus x = y. Substituting y for x gives us 72 - 3x = 66 - 2x. Solving this equation, we get x = 6 inches. So, 6 inches must be cut from both the length and the width to achieve the 2:3 ratio.

The probability that a student graduating from Suburban State University has student loans to pay off after graduation is .60. If two students are randomly selected from this university, what is the probability that neither of them has student loans to pay off after graduation?

Answers

Answer: 0.16

Step-by-step explanation:

Given: The probability that a student graduating from Suburban State University has student loans to pay off after graduation is =0.60

Then the probability that a student graduating from Suburban State University does not have student loans to pay off after graduation is =[tex]1-0.6=0.4[/tex]

Since all the given event is independent for all students.

Then , the probability that neither of them has student loans to pay off after graduation is given by :-

[tex](0.4)\times(0.4)=0.16[/tex]

Hence, the probability that neither of them has student loans to pay off after graduation =0.16

Expand the logarithm log 7(3x − 2)^2

Answers

[tex]\textbf{Transform}\\ \textrm{log} (7(3x -2)^2) \textbf{ into} \textrm{ log}(7) + \textrm{log}(3x-2)^2\\\\ \textbf{Expand} \\ \text{log}(3x-2)^2\\\\ \text{You can move 2 outside of }\text{log}(3x-2)^2\\\\ \textbf{Answer}\\ \text{log }7 + 2\text{ log}(3x-2)[/tex]

In a sample of 8 high school students, they spent an average of 28.8 hours each week doing sports with a sample standard deviation of 3.2 hours. Find the 95% confidence interval, assuming the times are normally distributed.

Answers

Answer:

[tex]26.12\:<\:\mu\:<\:31.48[/tex]

Step-by-step explanation:

Since the population standard deviation [tex]\sigma[/tex] is unknown, and the sample standard deviation [tex]s[/tex], must replace it, the [tex]t[/tex] distribution  must be used for the confidence interval.

The sample size is n=8.

The degree of freedom is [tex]df=n-1[/tex], [tex]\implies df=8-1=7[/tex].

With 95% confidence level, the [tex]\alpha-level[/tex](significance level) is 5%.

Hence with 7 degrees of freedom, [tex]t_{\frac{\alpha}{2} }=2.365[/tex]. (Read from the t-distribution table see attachment)

The 95% confidence interval can be found by using the formula:

[tex]\bar X-t_{\frac{\alpha}{2}}(\frac{s}{\sqrt{n} } )\:<\:\mu\:<\:\bar X+t_{\frac{\alpha}{2}}(\frac{s}{\sqrt{n} } )[/tex].

The sample mean is [tex]\bar X=28.8[/tex] hours.

The sample sample standard deviation is [tex]s=3.2[/tex] hours.

We now substitute all these values into the formula to obtain:

[tex]28.8-2.365(\frac{3.2}{\sqrt{8} } )\:<\:\mu\:<\:28.8+2.365(\frac{3.2}{\sqrt{8} } )[/tex].

[tex]26.12\:<\:\mu\:<\:31.48[/tex]

We are 95% confident that the population mean is between 26.12 and 31.48  hours.

The features of a Coverdell Education Savings Account include all of the following EXCEPT: (A) The contributions are deductible. (B) $2,000 is the maximum contribution in any one year. (C) Withdrawals are tax free. (D) Contributions are phased out for certain taxpayers who have adjusted gross income above a certain level.

Answers

Answer:

c

Step-by-step explanation:

. Geometry The area of a triangular sign is 33 square meters. The base of the triangle is 1 meter less than double the altitude. Find the altitude and the base of the sign.

Answers

Answer: The altitude and the base of the sign are 6 meters and 11 meters respectively.

Step-by-step explanation:

Since we have given that

Area of triangular sign = 33 sq. meters

Let the altitude of the triangle be 'x'.

Let the base of the triangle be ' 2x-1'.

As we know the formula for "Area of triangle ":

[tex]Area=\dfrac{1}{2}\times base\times height\\\\33=\dfrac{1}{2}\times x(2x-1)\\\\33\times 2=2x^2-x\\\\66=2x^2-x\\\\2x^2-x-66=0\\\\2x^2-12x+11x-66=0\\\\2x(x-6)+11(x-6)=0\\\\(2x+11)(x-6)=0\\\\x=-\dfrac{11}{2},6\\\\x=-5.5,6[/tex]

Discarded the negative value of x for dimensions:

So, altitude of triangle becomes 6 meters

Base of triangle would be [tex]2(6)-1=12-1=11\ meters[/tex]

Define a function sinc(x) (pronounced "sink of x") by: sinc(x)= {sin(x)/x if x is not 0 {1 if x = 0 Use this list of Basic Taylor Series to find the Taylor Series for f(x) = (sinc(x)) based at 0. a.Give your answer using summation notation. b.Give the interval on which the series converges.

Answers

You probably know that

[tex]\sin x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)!}[/tex]

Then

[tex]\mathrm{sinc}\,x=\displaystyle\frac1x\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)!}=\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}[/tex]

when [tex]x\neq0[/tex], and 1 when [tex]x=0[/tex].

By the ratio test, the series converges if the following limit is less than 1:

[tex]\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+2}}{(2n+3)!}}{\frac{(-1)^nx^{2n}}{(2n+1)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)!}{(2n+3)!}[/tex]

The limit is 0, so the series converges for all [tex]x[/tex].

Two friends went to get ice cream sundaes. They each chose a flavor of ice cream from a list of vanilla and chocolate and toppings from a list of hot fudge, strawberries, sprinkles, peanuts, and whipped cream. Use the sets below describing their choices and find B'.
Let A = {vanilla, chocolate, hot fudge, strawberries, sprinkles, peanuts, whipped cream}
Let B = {vanilla, hot fudge, sprinkles, whipped cream}
Let C = {chocolate, hot fudge, peanuts, whipped cream}
{vanilla, hot fudge, sprinkles, whipped cream}
{chocolate, strawberries, peanuts}
{chocolate, strawberries}
{vanilla, strawberries, peanuts}

Answers

Answer:

{chocolate, strawberries, peanuts}

Step-by-step explanation:

Given that three sets are

Let A = {vanilla, chocolate, hot fudge, strawberries, sprinkles, peanuts, whipped cream}

Let B = {vanilla, hot fudge, sprinkles, whipped cream}  

Let C = {chocolate, hot fudge, peanuts, whipped cream}

Then Universal set U = AUBUC

= {vanilla, chocolate, hot fudge, strawberries, sprinkles, peanuts, whipped cream}

B'=elements in U but not in B

={chocolate, strawberries, peanuts}

The resulting set is B' = {chocolate, strawberries, peanuts}.

To solve for B', we first need to understand that B' (B complement) consists of elements that are in set A but not in set B.

Given the sets:

A = {vanilla, chocolate, hot fudge, strawberries, sprinkles, peanuts, whipped cream}B = {vanilla, hot fudge, sprinkles, whipped cream}C = {chocolate, hot fudge, peanuts, whipped cream}

Set B includes: vanilla, hot fudge, sprinkles, and whipped cream. Therefore, B' will be the elements of set A excluding those in B.

Thus, B' is:

chocolatestrawberriespeanuts

Therefore, the set B' = {chocolate, strawberries, peanuts}.

This method can help you understand combinations without repetition effectively.

If (-3, y) lles on the graph of y = 3*, then y =

Answers

The line y = 3 means that x = 0.

The point (-3, y) tells me that x = -3 when y is 3.

So, y = 3 completes the point (-3, 3).

a(12) = 50- 1.25x

how do I solve it​

Answers

Answer:

a(12) = 35

Step-by-step explanation:

Given

a(12) = 50- 1.25x

Value of x is 12

50 - 1.25(12)

Simplify

50 - 15

Solve

a(12) = 50 - 15

a(12) = 35

The Royal Fruit Company produces two types of fruit drinks. The first type is 55% pure fruit juice, and the second type is 100% pure fruit juice. The company is attempting to produce a fruit drink that contains 70% pure fruit juice. How many pints of each of the two existing types of drink must be used to make 240 pints of a mixture that is 70%
pure fruit juice?

Answers

Answer:

First type of fruit drinks: 160 pints

Second type of fruit drinks: 80 pints

Step-by-step explanation:

Let's call A the amount of first type of fruit drinks. 5.5% pure fruit juice

Let's call B the amount of second type of fruit drinks. 100% pure fruit juice

The resulting mixture should have 70% pure fruit juice and 240 pints.

Then we know that the total amount of mixture will be:

[tex]A + B = 240[/tex]

Then the total amount of pure fruit juice in the mixture will be:

[tex]0.55A + B = 0.7 * 240[/tex]

[tex]0.55A + B = 168[/tex]

Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -1 and add it to the second equation:

[tex]-A -B = -240[/tex]

[tex]-A -B = -240[/tex]

                  +

[tex]0.55A + B = 168[/tex]

--------------------------------------

[tex]-0.45A = -72[/tex]

[tex]A = \frac{-72}{-0.45}[/tex]

[tex]A = 160\ pints[/tex]

We substitute the value of A into one of the two equations and solve for B.

[tex]160 + B = 240[/tex]

[tex]B = 80\ pints[/tex]

Final answer:

To make 240 pints of a mixture that is 70% pure fruit juice, you will need 160 pints of the first type of fruit drink (55% pure fruit juice) and 80 pints of the second type of fruit drink (100% pure fruit juice).

Explanation:

To solve this problem, we can set up a system of equations. Let's say x represents the number of pints of the first type of fruit drink (55% pure fruit juice) and y represents the number of pints of the second type of fruit drink (100% pure fruit juice). We know that the total number of pints of the mixture is 240, so we can write the equation x + y = 240. We also know that the desired percentage of pure fruit juice in the mixture is 70%, so we can write the equation (55% * x + 100% * y) / 240 = 70%. To solve this system of equations, we can use substitution or elimination method. Let's use substitution:

From the first equation, we can solve for x in terms of y: x = 240 - y. Substituting this into the second equation, we get ((55% * (240 - y)) + 100% * y) / 240 = 70%. Simplifying the equation, we have (0.55(240 - y) + y) / 240 = 0.70. Distributing and combining like terms, we get (132 - 0.55y + y) / 240 = 0.70. Simplifying further, we have (132 + 0.45y) / 240 = 0.70. Cross multiplying, we get 132 + 0.45y = 0.70 * 240. Simplifying, we have 132 + 0.45y = 168. Multiplying 0.45 with y, we get 0.45y = 168 - 132. Subtracting 132 from 168, we get 0.45y = 36. Dividing both sides of the equation by 0.45, we get y = 36 / 0.45. Evaluating this expression, we get y = 80. So, the number of pints of the second type of fruit drink (100% pure fruit juice) needed is 80. Substituting this value back into the first equation, we can solve for x: x + 80 = 240. Subtracting 80 from both sides of the equation, we get x = 240 - 80. Evaluating this expression, we get x = 160. Therefore, the number of pints of the first type of fruit drink (55% pure fruit juice) needed is 160.

Learn more about Solving Systems of Equations here:

https://brainly.com/question/29050831

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Walgreens sells both Kleenex and NyQuil. In a random sample of 5000 purchases, it was found that 1200 contained Kleenex and 540 contained NyQuil. These are not independent because sick people are more likely to buy both and healthy people more likely to buy neither. In looking into that, it was found that 360 purchases contained both.
a. Make a two-way table to display this information. Fill in the table with the missing entries, and be sure your table has row and column totals.

b. If we randomly select a purchase that contained Kleenex, what is the probability it also contained NyQuil?

c. What percent of all purchases didn’t contain either product?

Answers

I’m just doing this for the thing

​Thirty-five math​ majors, 23 music majors and 65 history majors are randomly selected from 586 math​ majors, 224 music majors and 254 history majors at the state university. What sampling technique is​ used?

Answers

Answer: Simple random sampling

Step-by-step explanation:

Simple random sampling is a technique of sampling in which an experimenter selects the group of samples or subjects randomly from a large group of population. Each sample is chosen randomly by chance and each entity of a population has equal possibility of being selected as sample.

According to the given situation, simple random sampling is the technique that should be used for sampling.

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