For a reaction at equilibrium, which of the following is the best way to think about it?

a. forward rate = reverse rate
b. The concentration of intermediates becomes negligible.
c. The concentration of reactants becomes negligible.
d. The concentration of reactants = concentration of products.
e. The concentration of reactants and products are not related.

Answer:

Total 20 mL of solution is needed in which 2.5 m L will be of Albuterol solution and 17.5 mL will be of normal saline solution.

Explanation:

Amount of Albuterol in 1 vial = 2.5 mg/0.5 mL

Volume of dose in which 12.5 mg of Albuterol is present be x.

So,

[tex]\frac{2.5 mg}{0.5 mL}=\frac{12.5 mg}{x}[/tex]

x = 2.5 mL

Volume of  Albuterol solution is 2.5 mL.

If the output flow of your continuous nebulizer is 10 mL per hour.Then in 2 hours total volume of solution delivered = T

T = 10 × 2 mL = 20 mL

Volume of normal saline solution needed = y

T = x + y

y = T - x = 20 mL - 2.5 mL = 17.5 mL

Total 20 mL of solution is needed in which 2.5 mL will be of Albuterol solution and 17.5 mL will be of normal saline solution.

Answer:

Moles of [tex]ScCl_3[/tex] = 6 moles

Explanation:

The reaction of [tex]Sc[/tex] and [tex]Cl_2[/tex] to make [tex]ScCl_3[/tex] is:

[tex]2Sc+3Cl_2[/tex]⇒[tex]2ScCl_3[/tex]

The above reaction shows that 2 moles of Sc  can react with 3 moles of [tex]Cl_2[/tex] to form [tex]ScCl_3.[/tex]

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of [tex]Cl_2[/tex] = [tex]Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}[/tex]

Moles of [tex]Cl_2[/tex] = [tex]10 *\frac{3 moles of Cl_2}{2 Moles of Sc}[/tex]

Moles of [tex]Cl_2[/tex] =15 moles

So 15 moles of [tex]Cl_2[/tex] are required to react with 10 moles of [tex]Sc[/tex] but we have 9 moles of [tex]Cl_2[/tex] , it means [tex]Cl_2[/tex] is limiting reactant.

[tex]Moles of ScCl_3=Given\ Moles\ of\ Cl_2 *\frac{2\ Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}[/tex]

[tex]Moles\ of\ ScCl_3=9 *\frac{2\ Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}[/tex]

Moles of ScCl_3= 6 moles

Answer:

6.00 moles of ScCl3 will be produced.

Explanation:

Step 1: Data given

Moles of Sc = 10.00 moles

Moles of Cl2 = 9.00 moles

Molar mass of Sc = 44.96 g/mol

Molar mass of Cl2 = 70.9 g/mol

Step 2: The balanced equation

2Sc + 3Cl2 → 2ScCl3

Step 3: Calculate the limiting reactant

For 2 moles Sc we need 3 moles Cl2 to produce 2 moles ScCl3

Cl2 is the limiting reactant. It will completely be consumed (9.00 moles)

Sc is the limiting reactant. There will react 2/3 * 9.00 = 6.00 moles

There will remain 10.00 - 6.00 =4.00 moles Sc

Step 4: Calculate moles ScCl3

For 3 moles Cl2 we'll have 2 moles ScCl3

For 9.00 moles we'll have 6.00 moles of ScCl3

6.00 moles of ScCl3 will be produced.

Answer: The final pressure of carbon dioxide is 15.4 atm

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of carbonic acid = 78.2 g

Molar mass of carbonic acid = 62 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of carbonic acid}=\frac{78.2g}{62g/mol}=1.26mol[/tex]

For the given chemical reaction:

[tex]H_2CO_3(aq.)\rightarrow H_2O(l)+CO_2(g)[/tex]

By Stoichiometry of the reaction:

1 mole of carbonic acid produces 1 mole of carbon dioxide

So, 1.26 moles of carbonic acid will produce = [tex]\frac{1}{1}\times 1.26=1.26mol[/tex] of carbon dioxide

To calculate the pressure, we use the equation given by ideal gas, which follows:

[tex]PV=nRT[/tex]

where,

P = pressure of the carbon dioxide = ?

V = Volume of the container = 2.00 L

T = Temperature of the container = 298 K

R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]

n = number of moles of carbon dioxide = 1.26 moles

Putting values in above equation, we get:

[tex]P\times 2.00L=1.26mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\P=\frac{1.26\times 0.0821\times 298}{2.00}=15.4atm[/tex]

Hence, the final pressure of carbon dioxide is 15.4 atm

Answer:

hydrogen Flouride, hydrogen Tennesside

Explanation:

The strongest bond among hydrogen halides is found in hydrogen fluoride, while the longest bond is found in hydrogen iodide. This is due to the decreasing bond strength and increasing bond length with increasing size of the halide ion.

Among the hydrogen halides, the strongest bond is found in hydrogen fluoride (HF) and the longest bond is found in hydrogen iodide (HI). The bond strength in hydrogen halides typically decreases as the size of the halide ion increases, with fluorine being the smallest and therefore, the strongest. Conversely, the bond length increases with the size of the halide ion, hence why iodine, the largest halide, forms the longest bond with hydrogen.

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Answer:

5.426 x 10⁹ g

5.55 mol

Explanation:

This type of problems involve the use of proportions , and the use of conversion of units to solve them.

In the first part we have to determine the mass in grams of a mole of virus, so we have to convert the mass to grams and  multiply by avogadro´s number.

9.010x 10⁻¹² mg x  ( 1 g / 1000 mg ) = 9.010 x 10⁻¹⁵ g

mass of 1 mol viruses:

9.010 x 10⁻¹⁵ g/ virus x ( 6.022 x 10²³ virus/mol ) = 5.426 x 10⁹ g /mol

(Note we rounded to 4 significant figures since 9.010 has 4 significant figures.)

For the second part convert the mass of the oil tanker to grams, and make use of the previous result to determine the # of moles of viruses which have the same mass.

mass oil tanker = 3.01 x 10⁷ Kg x ( 1000 g /Kg ) = 3.01 x 10¹⁰ g

3.01 x 10¹⁰ g x ( 1 mol virus / 5.426 x 10⁹ g ) = 5.55 mol

( Note here we rounded to three significant figures since in the multiplication we have 3.01 with three significant figures. )

The result is amazing and it is due to the very small mass of the virus. Imagine only 5.55 mol of virus in the same mass as that of an oil tanker !!!

Final answer:

The mass of one mole of viruses is 5.42 grams, calculated by converting the mass of a single virus to grams and then multiplying by Avogadro's number. To equate to the mass of an oil tanker, there would be 5.54 × 10^9 moles of viruses.

Explanation:

To calculate the mass of one mole of viruses, we use the given mass of a single virus and Avogadro's number. Since we have the mass of one virus as 9.0 × 10-12 mg, we first convert this mass to grams by dividing by 1,000,000 (since there are 1,000,000 micrograms in a gram), giving us 9.0 × 10-18 g. Then, we multiply this mass by Avogadro's number (6.022 × 1023 particles/mole) to get the mass of one mole of viruses: 5.42 g.

To find out how many moles of viruses have a mass equal to that of the oil tanker, we first convert the mass of the oil tanker to grams (3.0 × 107 kg is equal to 3.0 × 1010 g because there are 1,000 kg in a tonne and 1,000 g in a kg). Now, we divide this mass by the mass of one mole of viruses (5.42 g/mole), giving us: 5.54 × 109 moles.

Final answer:

The factors to consider when choosing the ideal solvent for crystallization include solubility properties, intermolecular forces, polarity, and solvent properties such as reactivity, cost, toxicity, and boiling point.

Explanation:

When choosing the ideal solvent for the crystallization of a particular compound, several factors should be taken into consideration:

Answer:

The initial velocity as a percentage of Vmax is 1100%

Explanation:

From Michaelis Menten equation,

Vo = Vmax[S]/Km+[S]

Vo/Vmax = [S]/Km+[S]

Expressing the initial velocity as a percentage of Vmax is

Vmax/Vo = Km+[S]/[S] × 100

[S] = Km/10

Km = 10[S]

Vmax/Vo = 10[S]+[S]/[S] × 100 = 11[S]/[S] ×100 = 11×100 = 1100%

The initial velocity of an enzyme, as a percentage of Vmax, is 10% when the substrate concentration is equal to Km/10.

The initial velocity of an enzyme, as a percentage of Vmax, can be calculated using the Michaelis-Menten equation. Let's assume that the substrate concentration [S] is equal to Km/10. The Michaelis constant (Km) represents the substrate concentration at which the velocity is half of Vmax.

Therefore, if [S] = Km/10, the velocity would be 10% of Vmax. This means that the initial reaction rate is only 10% of the maximum rate that can be achieved when all enzyme active sites are saturated.

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Answer:

2-methoxybutane

Explanation:

This reaction is an example of Nucleophilic substitution reaction. Also, the reaction of (S)-2-bromobutane with sodium methoxide in acetone, is bimolecular nucleophilic substitution (SN2). The reaction equation is given below.

(S)-2-bromobutane + sodium methoxide (in acetone) → 2-methoxybutane

Answer:

102 L

Explanation:

Data of the solution

The moles of HCl in the solution are:

1.25 L × 3.20 mol/L = 4.00 mol

The gas must contain 4.00 moles of HCl

Data of the gas

745 torr × (1 atm/760 torr) = 0.980 atm

We can the volume (V) of HCl gas using the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 4.00 mol × (0.08206 atm.L/mol.K) × 303.2 K/ 0.980 atm

V = 102 L

Answer:

The empirical formula is C3H4O

Explanation:

Step 1: Data given

Mass of the compound = 1.000 grams

The compound contains:

- Carbon

- hydrogen

- oxygen

The combustion of this compound gives:

2.360 grams of CO2

0.640 grams of H2O

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 2.360 grams / 44.01 g/mol

Moles CO2 = 0.05362 moles

In CO2 we have 1 mol

This means for 1 mol CO2 we have 1 mol C

For 0.05362 moles CO2 we have 0.05362 moles C

We have 0.05362 moles of C in the compound  

Step 3: Calculate mass of C

Mass C = moles C * molar mass C

Mass C = 0.05362 moles * 12.0 g/mol

Mass C = 0.643 grams  

Step 4: Calculate moles of H2O  

Moles H2O = 0.640 grams / 18.02 g/mol

Moles H2O =  0.0355 moles H2O

For 1 mol H2O we have 2 moles of H

For 0.0355 moles H2O we have 2*0.0355 =  0.071 moles H  

Step 5: Calculate mass of H

Mass H = moles H * molar mass H

Mass H = 0.071 moles * 1.01 g/mol

Mass H = 0.072 grams

Step 6: Calculate mass of O

Mass of O = Mass of compound - mass of C - mass of H

Mass of O = 1.000 g - 0.643 - 0.072 = 0.285 grams

Step 7: Calculate moles of O

Moles O = 0.285 grams / 16.0 g/mol

Moles O = 0.0178 moles

Step 8: Calculate mol ratio

We divide by the smallest amount of moles

C:  0.05362 / 0.0178 = 3

H: 0.071 / 0.0178 = 4

O: 0.0178/0.0178 = 1

The empirical formula is C3H4O

The study of chemicals and bonds is called chemistry.

The correct answer is C3H4O

All the data is given in the question, these data is as follows:-

The compound contains:

The combustion of this compound gives:

The formula to calculate the moles is as follows:-

[tex]Moles CO2 = \frac{mass}{molar mass}[/tex]

[tex]Moles \ CO2 = \frac{2.360} {44.01} Moles\ CO2 = 0.05362 moles [/tex]

In CO2 we have 1 mole, Which means for 1 mole CO2 we have 1 mole Carbon. For 0.05362 moles CO2, we have 0.05362 moles Carbon, We have 0.05362 moles of C in the compound  

lets calculate the mass of C

Mass C = moles C * molar mass C

Mass C = [tex]0.05362 moles * 12.0 g/mol[/tex]

Mass C = 0.643 grams  

The moles of H2O is as follows

Moles H2O = [tex]\frac{0.640}{18.02} [/tex]

Moles H2O = 0.0355 moles H2O

For 1 mole H2O, we have 2 moles of H. For 0.0355 moles H2O we have 2*0.0355 =  0.071 moles H  

let's Calculate the mass of H

Mass H = moles H * molar mass H

Mass H = 0.071 moles * 1.01 g/mol

Mass H = 0.072 grams

let's Calculate mass of O

Mass of O = Mass of compound - mass of C - mass of H

Mass of O = 1.000 g - 0.643 - 0.072 = 0.285 grams

let's Calculate moles of O

Moles O = 0.285 grams / 16.0 g/mol

Moles O = 0.0178 moles

The mole ratio is as follows:-

We divide by the smallest amount of moles

C:  0.05362 / 0.0178 = 3

H: 0.071 / 0.0178 = 4

O: 0.0178/0.0178 = 1

Hence, The empirical formula is C3H4O

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Final answer:

Option A is the correct answer .The crystalline solid described is a network covalent solid, which is characterized by a three-dimensional network of covalent bonds, leading to features like exceptional hardness and high melting points.

Explanation:

A crystalline solid with a high melting point and held together with covalent bonds is an example of a network covalent solid. These solids are formed by atoms that are covalently bonded in a large, continuous three-dimensional network. Network covalent solids, which include materials like diamond and silicon dioxide, are known for their hardness, strength, and very high melting points, often requiring the breaking of strong covalent bonds to melt or to break the solid.

Unlike ionic and metallic solids, network covalent solids are poor conductors of electricity, as they are made up of neutral atoms instead of charged ions. These properties make network covalent solids distinct from other types of crystalline solids, which include ionic, molecular, and metallic solids, each characterized by their own unique bonding and structural features.

An appropriate alkyne starting material A could be 2-butyne (C4H6). An intermediate product B could be but-2-en-1-yne (C4H4). Both the starting material and the intermediate product have the same number of carbon atoms.

An appropriate alkyne starting material A could be 2-butyne (C4H6).

An intermediate product B could be but-2-en-1-yne (C4H4).

Both the starting material and the intermediate product have the same number of carbon atoms.

Alumina, corundum, and bauxite contain significant amounts of aluminum oxide. Alumina is a form of aluminum oxide, corundum is a crystalline form that usually contains traces of other elements, and bauxite is the principal ore of aluminum.

The substances which contain significant amounts of aluminum oxide are alumina, corundum, and bauxite.

Alumina, by its nature, is a form of aluminum oxide. Corundum is a crystalline form of aluminum oxide and typically contains traces of iron, titanium, vanadium, and chromium. Bauxite is the principal ore of aluminum and it primarily consists of one or more aluminum hydroxide minerals, which are often structurally composed of aluminum oxide.

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Option A states that 0.1 moles of HCl remain unreacted. This proves that option A is incorrect. The volume of hydrogen gas produced is 0.22 L. Thus option D is correct.

From the given reaction, 1 mole of Fe and 2 moles of HCl reacts to form 1 mole ferric chloride and 1-mole hydrogen gas.

The number of moles of HCl in 30 ml 1 M solution are:

Moles = molarity [tex]\times[/tex] volume (L)

Moles of HCl = 1 [tex]\times[/tex] 0.03

Moles of HCl = 0.030 moles.

The moles of 0.56 grams Fe powder are :

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of Fe = [tex]\rm \dfrac{0.56}{56}[/tex] moles

Moles of Fe = 0.01 moles

For the reaction of 0.01 moles of Fe, moles of HCl required = 0.01 [tex]\times[/tex] 2

Moles of HCL reacted = 0.02 moles

Total moles of HCL = 0.03 moles

Moles of HCl unreacted = 0.03 - 0.02

Moles of HCl unreacted = 0.01 moles

Option A states that 0.1 moles of HCl remain unreacted. This proves that option A is incorrect.

0.01 moles of Fe form, 0.01 mole of Hydrogen gas.

From the ideal gas equation:

PV = nRT

1 [tex]\times[/tex] Volume = 0.01 [tex]\times[/tex] 0.0821 [tex]\times[/tex] 273

Volume of Hydrogen gas = 0.22 L.

The volume of hydrogen gas produced is 0.22 L. Thus option D is correct.

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Option D is correct since exactly 0.22 L of H₂ is produced, which matches the stoichiometric calculations for the reaction.

To determine why A is incorrect, we need to perform stoichiometric calculations based on the reaction: Fe(s) + 2HCl(aq) --> FeCl₂(aq) + H₂(g). First, calculate the moles of Fe and HCl:

The balanced equation shows that 1 mole of Fe reacts with 2 moles of HCl. Therefore, 0.0100 mol of Fe will react with 0.0200 mol of HCl, leaving an excess of 0.0100 mol of HCl (0.0300 mol - 0.0200 mol). However, this contradicts option A which states 0.100 mol HCl remains unreacted.

Now, for option D: 0.0100 mol of Fe will produce 0.0100 mol of H₂. Using the ideal gas law at standard conditions (273 K and 1.0 atm), the volume of H₂ produced is:

This confirms that D is correct.

The complete question is:

Fe(s) + 2HCl(aq) --> FeCl₂(aq) + H₂(g)

When a student adds 30.0 mL of 1.00 M HCl to 0.56 g of powdered Fe, a reaction occurs according to the equation above. When the reaction is complete at 273 K and 1.0 atm, which of the following is true?

A) HCl is in excess, and 0.100 mol of HCl remains unreacted.

D) 0.22 L of H₂ has been produced.

The correct question is:

To the reaction mixture having reaction as 25 Fe(s) + 2 HCI(aq) -> FeCl₂(aq) + H₂(g), When a student adds 30.0 mL of 1.00 M HCI to 0.56 g of powdered Fe, a reaction occurs according to the equation above. When the reaction is complete at 273 K and 1.0 atm, which of the following is true?

(A) HCI is in excess, and 0.100 mol of HCI remains unreacted.

(B) HCI is in excess, and 0.020 mol of HCI remains unreacted.

(C) 0.015 mol of FeCl₂ has been produced.

(D) 0.22 L of H₂ has been produced.

Answer:

B. only one copy of the field in memory

Explanation:

A static method is sort of a description of a class but is not part of the objects that it generates. Crucial: A program may perform a static method without constructing an object first! All other functions (those not static) only occur when they're member of an object. Thus it is necessary to build an object before they could be executed.

Therefore, when an static field is declared static, there will be:

B. only one copy of the field in memory

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

The question is incomplete, here is the complete question:

An aqueous solution at 25°C has a [tex]H_3O^+[/tex] concentration of [tex]8.8\times 10^{-12}M[/tex] . Calculate the [tex]OH^-[/tex] concentration. Be sure your answer has the correct number of significant digits.

Answer: The hydroxide ion concentration of the solution is [tex]0.1\times 10^{-2}M[/tex]

Explanation:

To calculate the pH of the solution, we use the equation:

[tex]pH=-\log[H_3O^+][/tex]

We are given:

[tex][H_3O^+]=8.8\times 10^{-12}M[/tex]

Putting values in above equation, we get:

[tex]pH=-\log (8.8\times 10^{-12})\\\\pH=11.05[/tex]

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

[tex]pOH=14-11.05=2.95[/tex]

To calculate hydroxide ion concentration of the solution, we use the equation:

[tex]pOH=-\log[OH^-][/tex]

We are given:

pOH = 2.95

Putting values in above equation, we get:

[tex]2.95=-\log[OH^-][/tex]

[tex][OH^-]=10^{-2.95}[/tex]

[tex][OH^-]=1.12\times 10^{-3}M=0.1\times 10^{-2}M[/tex]

Hence, the hydroxide ion concentration of the solution is [tex]0.1\times 10^{-2}M[/tex]

Answer: Use of Etherificarion followed by fractional distinction.

Explanation:

It is done by reacting a mixture of tetrahydrofurfuryl alcohol and up to about one equivalent of at least one low work function element, Reacting the said mixture with a halide; fractionally distilling said reacted mixture to yield the first distillate; reacting said first distillate with an excess amount of at least one low work function element; and, fractionally distilling said reacted first distillate to obtain the purified ether wherein said at least one low work function element is an elemental metal or a metal hydride which has a φ of less than about 3.0 eV.

Answer:

The neutral organic product of the reaction is the 2-methoxy-2-methylpropane, shown in the attached figure.

Explanation:

By reacting an alkene (2-methylprop-1-ene) with an alcohol (methanol) in the presence of an acid it forms an ester (2-methoxy-2-methylpropane) through Markovnikov’s rule. First, a protonation of the alkene occurs where a tertiary carbocation is formed, then the nucleophile (methanol) attacks the previously formed carbocation, and finally ocurr the deprotonation of the hydrogen bound to the oxygen, thus forming the ester, in our case the neutral organic product 2-methoxy-2-methylpropane.

Without information about the reactants and reaction conditions, it is impossible to predict the neutral organic product of a reaction.

The question refers to a reaction and asks for the prediction of the neutral organic product. However, the reaction and reactants are not provided, so it is impossible to provide a specific answer. In organic chemistry, reactions can involve different reactants and conditions, leading to various possible products.

To predict the neutral organic product of a reaction, it is necessary to know the reactants and the specific reaction conditions.

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Answer:

[Cl₂] in equilibrium is 1.26 M

Explanation:

This is the equilibrium:

PCl₃(g) + Cl₂(g) ⇋ PCl₅(g)

Kc = 91

So let's analyse, all the process:

                PCl₃(g)        +        Cl₂(g)     ⇋        PCl₅(g)

Initially     0.24 M                 1.50M                 0.12 M

React           x                           x                         x

Some amount of compound has reacted during the process.

In equilibrium we have

              0.24 - x                  1.50 - x                  0.12 + x

As initially we have moles of product, in equilibrium we have to sum them.

Let's make the expression for Kc

Kc = [PCl₅] / [Cl₂] . [PCl₃]

91 = (0.12 + x) / (0.24 - x) ( 1.50 - x)

91 = (0.12 + x) / (0.36 - 0.24x - 1.5x + x²)          

91 (0.36 - 0.24x - 1.5x + x²) = (0.12 + x)

32.76 - 158.34x + 91x² = 0.12 +x

32.64 - 159.34x + 91x² = 0

This a quadratic function:

a = 91; b= -159.34; c = 32.64

(-b +- √(b² - 4ac)) / 2a

Solution 1 = 1.5

Solution 2 = 0.23 (This is our value)

So [Cl₂] in equilibrium is 1.50 - 0.23 = 1.26 M

Answer: c. oxygen-17

Explanation:

The isotopic representation of an atom is: [tex]_Z^A\textrm{X}[/tex]

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given nuclear reaction:

[tex]^{14}_{7}\textrm{N}+^4_2\textrm{He}\rightarrow ^A_Z\textrm{X}+^{1}_{1}\textrm{H}[/tex]

To calculate A:

Total mass on reactant side = total mass on product side

14 + 4= A + 1

A = 17

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

7+ 2 = Z + 1

Z = 8

The isotopic symbol of element is [tex]_{17}^{8}\textrm{O}[/tex]

Thus a proton is produced along with oxygen-17.

A proton is produced along with:

c. oxygen-17

[tex]^AX_Z[/tex]

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given nuclear reaction:

[tex]^{14}N_7+^4He_2----- > ^AX_Z+^1H_1[/tex]

To calculate A:

Total mass on reactant side = total mass on product side

14 + 4= A + 1

A = 17

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

7+ 2 = Z + 1

Z = 8

The isotopic symbol of element is: [tex]^8O_{17}[/tex]

Thus, A proton is produced along with oxygen-17

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Answer: 5.8

Explanation:

the formula:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2\,}d=

(x

2

​

−x

1

​

)

2

+(y

2

​

−y

1

​

)

2

​

The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

Answer: The volume of solution is 5.2 L

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]

We are given:

Molarity of solution = 0.13 M

Given mass of potassium dichromate = 200. g

Molar mass of potassium dichromate = 294.15 g/mol

Putting values in above equation, we get:

[tex]0.13M=\frac{200}{294.15\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{200}{294.15\times 0.13}=5.23L[/tex]

Hence, the volume of solution is 5.2 L

The volume of a potassium dichromate solution containing 1.8 moles cannot be calculated without the molarity of the solution. Once molarity is known, use V = n / M and convert to liters, considering significant figures for accuracy.

To calculate the volume of a potassium dichromate solution that contains 1.8 moles of potassium dichromate, we must first determine the molarity (M) of the solution, which is not provided in the question. Assuming we have this information, the formula to find the volume (V) when the number of moles (n) and molarity (M) are known is:V = n / M

Without a given molarity, we cannot proceed with this calculation. If molarity is provided, we'd convert it to liters. Since the molarity and actual number of grams of potassium dichromate were not provided in your question, we cannot complete this calculation precisely. However, the reference provided for preparing a different solution with KBrO3 and the details about significant figures indicate that calculations should be made using suitable glassware for precision and rounding off to the correct number of significant digits.

Answer:

500 years

Explanation:

The original carbon-14 was 100%, and after 100 years, it decays 1.202%. So after 100 years it goes to 98.798%, after more 100 years (200 years), it will be 97.596% (98.798 - 1.202), thus, after n 100 years "package", the percenatge will be:

100% - actual% = n*1.202

n = (100% - actual%)/1.202

n = (100% - 94%)/1.202

n = 4.992

So, the number of years is n*100 = 4.992*100 = 499.2 ≅ 500 years.

This problem is about the Photoelectric Effect in quantum physics, calculating the maximum kinetic energy of emitted electrons and the maximum number of freed electrons due to light exposure.

The questions are related to the Photoelectric Effect, a fundamental concept in quantum physics.

a.) The relationship between the frequency of light and the maximum kinetic energy of emitted electrons is given by the formula: E = hf – W, where E is the maximum kinetic energy, h is Planck’s constant, f is the frequency of light, and W is the work function of the material. The frequency can be found from the speed of light divided by the given wavelength (439 nm).

b.) The maximum number of electrons freed by light depends on the energy of the photons and the material's work function. You can find this by dividing the total energy of the burst of light (1.00μJ) by the energy required to remove one electron.

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Answer : The correct option is, (C) 10-mL volumeric pipet.

Explanation :

Graduated cylinder : It is a measuring cylinder that is used to measure the volume of a liquid. It has a narrow cylindrical shape. The marked line drawn on the graduated cylinder shows the amount of liquid that has been measured.

Pipet : It is a type of laboratory equipment that is used to measure the volume of a liquid. It is small glass tube and the marked line drawn on the pipet. It is used to accurately measure and transfer of volume of liquid from one container to another.

Volumetric flask : It is a type of laboratory tool that is also used for measuring the volume of liquid. It is used to make up a solution to a known volume. It measure volumes much more precisely than beakers.

Beaker : It is a type of laboratory equipment that has cylindrical shape and it is used for the mixing, stirring, and heating of chemicals.

As per question, we conclude that the pipet is most precise than other devices because in pipet the marking lines are more accurate. Thus, it can be used to measure volume to precision.

Hence, the correct option is, (C) 10-mL volumeric pipet.

Explanation:

Most reagent forms are going to absorb water from the air; they're called "hygroscopic".  Water presence can have a drastic impact on the experiment being performed  For fact, it increases the reagent's molecular weight, meaning that anything involving a very specific molarity (the amount of molecules in the final solution) will not function properly.

Heating will help to eliminate water, although some chemicals don't react well to heat, so it shouldn't be used for all.  A dessicated environment is simply a means to  "dry."  That allows the reagent with little water in the air to attach with.

Answer:Iodide has weaker ion-dipole interactions with water than bromide.

Explanation:

The electronegativity difference between sodium and iodine in sodium iodide is about 1.73. This shows that the compound is not composed of purely ionic bonds. Electro negativity decreases down the group hence iodine is far less electronegative than bromine and is thus ineffective in forming strong dipole interactions with water hence the higher entropy due to much less association of ions in solution.

The entropy change for NaI is greater than that for NaBr because iodide ions have weaker ion-dipole interactions with water, leading to a more disordered system and higher entropy upon dissolution.

The entropy change is greater for the dissolution of NaI compared to NaBr because Iodide has weaker ion-dipole interactions with water than bromide. This is attributable to the larger size and more diffuse electron cloud of the iodide ion, which makes its interactions with water molecules less specific and weaker compared to the smaller bromide ion. Due to these weaker interactions, when NaI dissolves, there is a greater increase in disorder or entropy within the system as the iodide ions are less constrained by water molecules relative to bromide ions. Since entropy is a measure of disorder or the number of available microstates for a system, the dissolution of NaI leads to a higher increase in entropy.

Complete Question:

A chemist prepares a solution of iron chloride by measuring out 0.10 g of FeCl2 into a 50. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution.

Answer:

[Fe+] = 0.0156 M

[Cl-] = 0.0316 M

Explanation:

The molar mass of iron chloride is 126.75 g/mol, thus, the number of moles presented in 0.10 g of it is:

n = mass/molar mass

n = 0.10/126.75

n = 7.89x10⁻⁴ mol

In a solution, it will dissociate to form:

FeCl2 -> Fe+  + 2Cl-

So, the stoichiometry is 1:1:2, and the number of moles of the ions formed are:

nFe+ = 7.89x10⁻⁴ mol

nCl- = 2*7.89x10⁻⁴  = 1.58x10⁻³ mol

The molarity is the number of moles divided by the solution volume, in L (50.0 mL = 0.05 L):

[Fe+] = 7.89x10⁻⁴/0.05 = 0.0156 M

[Cl-] = 1.58x10⁻³/0.05 = 0.0316 M

Answer:

(a) Atomic Mass = 35.24

(b) 2.95x10²¹ Cl₂ molecules

Explanation:

In the attached picture you may read your question, written in a different format.

(a) We calculate the atomic weight of the enriched Cl using the abundances and masses of the isotopes:

(b) We use the previously calculated atomic mass and use it as molar mass (35.24 g/mol), alongside Avogadro's number: