Final answer:
To find the weight of an object on another planet with 1/10th of Earth's gravity, multiply the mass by the reduced gravitational force (0.98 m/s²) giving a weight of 0.98 N for a 1.0-kg object.
Explanation:
The weight of an object on another planet where gravitational attraction is reduced to 1/10 of Earth's can be calculated by adjusting the gravitational force. On Earth, the acceleration due to gravity, g, is 9.80 m/s², and the weight w of a 1.0-kg object is thus 9.8 N calculated by w = m * g. If the gravitational pull is 1/10th that of Earth's, the acceleration due to gravity on this new planet would be 0.98 m/s². Therefore, the weight of a 1.0-kg object on this planet would be:
w = m * g
= (1.0 kg) * (0.98 m/s²)
= 0.98 N.
So, an object that weighs 9.8 N on Earth would weigh just 0.98 N on a planet where gravity is 1/10 as strong.
John has a boat that will travel at the rate of 15 kph in still water. he can go upstream for 35 km in the same time it takes to go 140 km downstream. how fast is his boat traveling when he goes downstream? 22 kph 24 kph 26 kph
Answer:
24kph
Explanation:
John has a boat that will travel at the rate of 15 kph in still water. he can go upstream for 35 km in the same time it takes to go 140 km downstream, then it would go 24 kph downstream, therefore the correct answer is option B.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter / second.
As given in the problem John has a boat that will travel at the rate of 15 kph in still water. he can go upstream for 35 km in the same time it takes to go 140 km downstream.
Let us take the speed of the stream would be x kph.
35 / 15 -x = 140 / 15 + x
x = 9
The speed of the boat downstream = 15 + 9
= 24 kph
Thus, it would go 24 kph downstream, therefore the correct answer is option B.
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A valley of rolling hills is an example of _____.
monoclines
anticlines and synclines
horsts and grabens
fault-block mountains
I believe it's
A valley of rolling hills is an example of anticlines and synclines.
A 2 kg bar of metal weighs about 4.4 pounds. Approximately how much does it weigh in newtons?
A) 1 N
B) 44 N
C) 2.2 N
D) 20 N
Answer:
Answer is D) 20 N
Explanation:
A 2 kg bar of metal weighs approximately 19.58 newtons. This gives us an approximate weight of 19.58 newtons, which is closest to option D) 20 N.
Explanation:To convert the weight of a metal bar from pounds to newtons, you can use the conversion factor: 1 pound is approximately equal to 4.44822 newtons.
To convert the weight of the metal bar from pounds to newtons, we can use the conversion factor 1 pound = 4.45 newtons. Therefore, to find the weight in newtons, multiply 4.4 pounds by 4.45 newtons/pound. This gives us an approximate weight of 19.58 newtons, which is closest to option D) 20 N.
To convert the weight of a metal bar from pounds to newtons, you would multiply the weight in pounds by the conversion factor of 4.44822, since 1 pound is approximately equal to 4.44822 newtons.
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TRUE OR FALSE!? HELP!!!!!
a) During deposition, particles of molecular nitrogen become farther apart.
b) When a piece of copper melts, its particles remain the same.
(Please, explain your answer!!!!)
Answer:
False
True
Explanation:
False: The reason is because theyare bonded by molecules
True: This is because a physical change does not change the chemical composition
Explain why nuclear fusion takes place only in the center of stars
In a bumper car arena, two cars of equal mass are heading straight toward each other. The orange one is traveling at a speed of 5 meters per second. The green one is traveling at a speed of 2 meters per second. Which of the forces most affects the motion of the bumper cars after they collide?
Answer: D.
Explanation: Orange, at 3 meters per second if you calculate the net force being applied to the system.
hope this helps! ✌
What does the law of conservation of energy state?
The total amount of energy remains constant in an isolated system. It implies that energy can neither be created nor destroyed, but can be change from one form to another.
Often what one expects to see influences what is perceived in the surrounding environment. Please select the best answer from the choices provided T F
This statement is in-doubtingly true
It is true that Often what one expects to see influences what is perceived in the surrounding environment.
What is person's surrounding environment?The environment can be defined as the sum of all living and non-living elements and their effects on human life.
Non-living or abiotic elements include water, land, sunlight, rocks, and air, while all living or biotic elements are animals, plants, forests, fisheries, and birds.
The noun surroundings can refer to the immediate environment, including all nearby objects, as well as the location itself and the circumstances or conditions in which you find yourself.
When someone constructs a house, the surroundings influence which direction it faces and how many windows it has.
What one expects to see frequently influences what one perceives in the surrounding environment.
Thus, the given statement is true.
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Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?
Protons
Neutrons
Which statement is accurate for these two sub-atomic particles.
A) They both have a neutral charge.
B) They both have a positive charge.
C) They are both located in the nucleus.
Eliminate
D) They are both located outside the nucleus.
Answer:
c
Explanation:
Birds sitting on a single power line don't get shocked because there is no path for the current to flow to the __________.
Answer:
Ground.Explanation:
Basically, the reason why birds don't get electrically shocked, it's because they only reach a single path of the current. However, if they are able to toch something connected to the groun while they are on a cable, they will be shocked, becuase they are completeling the electrical cicle needed to flow the electricity.
Having said that, even a person can do that. Someone can grab a single power line without touching the ground or other cable, and that person will be fine, there can be thousands of volts and amperes, but that person will be totally fine.
Therefore, the word missing here is ground.
Birds sitting on a single power line don't get shocked because there is no path for the current to flow to the ground.
A tennis ball bounces on the floor three times, and each time it loses 23.0% of its energy due to heating. how high does it bounce after the third time, if we released it 4.0 m from the floor?
The tennis ball will bounce to a height of approximately 1.828 meters after the third bounce when it loses 23.0% of its energy with each bounce starting from a height of 4 meters.
If a tennis ball is released from a height of 4 meters and bounces on the floor three times, each time losing 23.0% of its energy due to heating, we can calculate its height after the third bounce. The initial potential energy (PE) of the ball when released is converted into kinetic energy as it falls and then back into potential energy as it bounces upward. After each bounce, the ball retains only 77% (100% - 23%) of its energy because of the energy lost to heat. Therefore, after the third bounce, the ball has
(0.77)³ or about 45.7% of its original energy.
Here is the calculation to find the height (h) after the third bounce:
[tex]PE{initial }[/tex]= mg[tex]h_{initial}[/tex] = mg[tex]h_{final}[/tex]
[tex]h_{final}[/tex] = (0.77)³ h_initial
[tex]h_{final}[/tex] = (0.77)³
(4.0 m) = 0.457
(4.0 m) = 1.828 m.
The tennis ball will bounce to a height of approximately 1.828 meters after the third bounce.
Momentum Monster does 600,000 joules of work in 10 seconds. How much power is that in watts?
I think it's 60,000, but I need someone who knows for sure whether this is correct or not.
When a system of measurement is based on units of ten, it is called a ____system.
Answer:
It is called a metric system!
Explanation:
A car travels at uniform acceleration over a distance of 440.0 m. Its final velocity after 20.0 s is 33.0 m/s. What is its initial velocity?
Since it is a uniform accelerated motion, we can use the following SUVAT equation that relates initial velocity, final velocity, time and distance covered:
[tex]S=\frac{1}{2}(v_i +v_f)t[/tex]
where
S=440.0 m is the distance covered
vi is the initial velocity
vf=33.0 m/s is the final velocity
t=20.0 s is the time
Re-arranging the formula and substituting the data, we can find the initial velocity:
[tex]v_i = \frac{2S}{t}-v_f=\frac{2(440.0 m)}{20.0 s}-33.0 m/s=11.0 m/s[/tex]
What is the mass of a shopping cart that is pushed with a net force of 10 N to accelerate at the rate of 0.5 m/s2?
Actualy the correct answer is going to be 20kg. And this how i got it. All i did was 10 divided by .5 and i got the answer.
Please mark brainiest please.
Force is the product of mass and acceleration. The force acting on the shopping cart is 10 N with an acceleration of 0.5 m/s². Then, mass of the cart is 20 Kg.
What is force?Force is an external agent acting on an object to change its state of rest or motion or to deform it. There are various kinds of forces, such as frictional force, magnetic force, gravitational force etc.
Newton's second law of motion states that, force of an objecting with a speed is the product of its mass and acceleration. Thus force increases with increase in mass or acceleration or with an increase in both together.
Given that, net force acting on the cart = 10 N
acceleration = 0.5 m/s².
Force = m a
mass m = F/a
= 10 N/ 0. 5 m/s²
= 20 Kg
Therefore, mass of the shopping cart is 20 Kg.
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A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. the scale reads 849 n. as the elevator moves up, the scale reading increases to 934 n, then decreases back to 849 n. the acceleration of gravity is 9.8 m/s 2 . find the acceleration of the elevator. answer in units of m/s 2 .
Actual weight W = mg = 849
N
mass m = 849 / g = 86.54
kg
apparent weight m ( a+ g ) = 934 N
(a + g) = 934 / m = 10.79
from this acceleration a = 10.79 - g
= 10.79-9.8
= 0.9827 m / s^ 2
Your car and the trailer it is towing are initially at rest. you apply an acceleration of 1.75 m/s2 to get the vehicles moving. the mass of your car is 1200 kg and the mass of the trailer is 540 kg. (a) determine the net force acting on the car.
Final answer:
The net force acting on the car, which is towing a trailer, is calculated using Newton's second law of motion and is found to be 3045 newtons.
Explanation:
To determine the net force acting on the car, we use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). Since the car and trailer are initially at rest and they start to accelerate together, the net force on the car can be calculated by adding the masses of the car and the trailer and then multiplying the total mass by the given acceleration.
First, we find the total mass of the car and the trailer combined: total mass = mass of car + mass of trailer = 1200 kg + 540 kg = 1740 kg. Then, we multiply this total mass by the given acceleration to find the net force:
Net force = total mass × acceleration = 1740 kg × 1.75 m/s² = 3045 N.
Therefore, the net force acting on the car is 3045 newtons.
Helium is considered a noble gas because it has a _blank___ valence electron shell
Answer:
Helium has a full valency electron shell
Explanation:
Noble gases are gases at in general they don't react with any other element easily. They are a group of elements that make up Group 18 on the periodic table. They are referred to as inert gases because of their unreactive nature because they have a full valency electron shell. They have the following general properties: colourless, odourless, tasteless, and are nonflammable gases.
In a crash test, a 2,500 kg car hits a concrete barrier at 1.3 m/s2. If the car strikes the barrier with a force of 3,250 N, how much resistance force does the barrier provide? N This pair of forces is an example of Newton’s law of motion.
The concrete barrier provides a resistance force equal to the car's impact force of 3,250 N, illustrating Newton's Third Law of Motion, wherein every action has an equal and opposite reaction.
Explanation:In the scenario where a 2,500 kg car hits a concrete barrier with a force of 3,250 N, it is important to understand Newton's laws of motion to determine the resistance force provided by the barrier. Newton's Third Law states that for every action, there is an equal and opposite reaction. Hence, the barrier would provide an equal resistance force of 3,250 N back on the car, as it is the action-reaction pair described by this law.
Newton's Third Law of Motion :
This situation exemplifies Newton's Third Law of Motion, which is often paraphrased as, 'To every action, there is always an opposed and equal reaction.' In crash tests and automobile mechanics, this law helps us understand and predict the forces involved during a collision. When the car exerts a force on the barrier, the barrier exerts an equal and opposite resisting force on the car, confirming that the car's impact force and the barrier's resistance force are indeed equal.
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A graduated cylinder has a mass of 80 g when empty. when 20 ml of water is added, the graduated cylinder has a mass of 100 g. if a stone is added to the graduated cylinder, the water level rises to 45 ml and the total mass is now 156 g. what is the density of the stone
Answer:
[tex]\rho_{stone} = \frac{56 g}{25 mL} = 2.24 g/mL[/tex]
Explanation:
Mass of the cylinder = 80 g
water added in the cylinder = 20 mL
mass of water + cylinder = 100 g
mass of water added = 100 g - 80 g = 20 g
density of water = [tex]\frac{mass}{volume}[/tex]
[tex]\rho = \frac{20 g}{20 mL} = 1 gm/mL[/tex]
now when stone is put into the cylinder then the volume reached to 45 mL
so volume displaced by the stone = 45 mL - 20 mL
V = 25 mL
mass of stone = 156 g - 100 g = 56 g
now density of stone is
[tex]\rho_{stone} = \frac{mass}{volume}[/tex]
[tex]\rho_{stone} = \frac{56 g}{25 mL} = 2.24 g/mL[/tex]
A ball is at rest on the floor of a car moving at a constant velocity. What will happen to the ball if the car swerves suddenly to the left, and why will this happen?
The ball would move to the right under a thrust force.
What would happen to the ball?We know that in physics that an object would continue in its state of uniform motion or at a state of rest unless it has been acted upon by external forces that are acting on the object.
In this case, we have a ball that is at rest and then we have a car that is moving uniformly but is suddenly swerved to the left hand side. We know that the thrust that is produced by the car would act on the ball in the opposite direction.
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A van slows down as it travels up a steep hill. Its speed goes from 20m/s at the bottom of the hill to 12m/s when it reaches the top 8 seconds later. How far has the van travelled between the bottom and the top of the hill?
Answer
13.06 m
Explanation
The height reach ca be calculated using the one of the linear equation.
v² = u² - 2gs
where u ⇒ is the initial speed,
v ⇒ is the final speed
g ⇒ is the acceleration due to gravity and
s ⇒ the height reached.
v² = u² - 2gs
12² = 20² - (2×9.8×s)
144 = 400 - 19.6s
19.6s = 400 - 144
= 256
s = 256/19.6
= 13.06 m
Answer:
d = 128 m
Explanation:
Here given that van slows down as it travels up a inclined steep hill
So here we can assume that through out the motion its acceleration will remain constant.
Now we can use kinematics to find out the distance traveled by it
As we know that acceleration is defined as
[tex]a = \frac{v_f - v_i}{t}[/tex]
here we know that
[tex]v_f = 12 m/s[/tex]
[tex]v_i = 20 m/s[/tex]
time = 8 s
now we have
[tex]a = \frac{12 - 20}{8} = -1 m/s^2[/tex]
Now in order to find out the distance it moved we can use
[tex]v_f^2 - v_i^2 = 2 ad [/tex]
now we will plug in all above data
[tex]12^2 - 20^2 = (2)(-1)d[/tex]
[tex]144 - 400 = -2d[/tex]
[tex]d = \frac{-256}{-2} = 128 m[/tex]
so it will cover total distance of 128 m
How many times does the kinetic energy of a car increase when traveling 60mph as opposed to traveling 30mph?
3x/y=6g/b solve for x
When experimenting, you purposely change the temperature, temperature is the ___ variable?
What is direct evidence? Another name? An example?
Direct evidences are obtained rom the investigation area itself or directly from a sample under study and not from previous records or surveys.
What is direct evidence?Direct evidence is a type of proof that frequently utilizes the form of witness testimony or eyewitness narratives. When a witness states that they witnessed an accused person conduct a crime, overheard someone else say a certain word or words, or saw a certain act occur, these are examples of direct evidence.
The truth of an assertion is supported directly by direct evidence, i.e., without an intermediary inference. A witness describes what they personally saw or heard, but they may also use any other sense, such as scent, touch, or pain.
Other evidences collected from surveys, or from previous records, hearing from indirect witness etc. are not take as direct evidences.
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A 1.50-liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25°C. Without changing the temperature, a piston is moved in the cylinder until the pressure in the cylinder is reduced to 1.00 atmospheres. The volume of the gas is _____.
The volume of the gas after the change of pressure will be 4.5 litres.
What is Boyle's law?Boyle's law, also known as the Boyle-Mariotte law or Mariotte's law, is an experimental gas law that states that as a container's volume grows, a gas's pressure tends to drop. The temperature remains constant.
Given that a 1.50-litre sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25°C. Without changing the temperature, a piston is moved in the cylinder until the pressure in the cylinder is reduced to 1.00 atmospheres.
Use Boyle's law:-
P₁V₁ = P₂V₂
Put the values of initial pressure, volume and final pressure then calculate the value of final volume as the temperature of the process is constant.
1.50 x 3.00 = V x 1.00 atm
V₂ = 1.50 x 3.00 / 1.00
V₂ = 4.50 L
Therefore, the volume of the gas will be 4.5 litres.
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True or false the amount of solar radiation an area receives is dependent on the angle of the energy and whether it is filtered through the atmosphere
A satellite of mass 6000 kg orbits the earth and has a period of 5700 s. determine the radius of its circular orbit.
The radius of the satellite's circular orbit is approximately 11,350,000 meters or 11,350 kilometers.
Given,
Mass of satellite = 6000 kg
Revolution time = 5700s
To determine the radius of the circular orbit of a satellite orbiting the Earth, the following equation based on the laws of circular motion can be used:
[tex]r = (\frac{G \times M \times T^2}{4\pi^2})^{(1/3)}[/tex]
Where:
r is the radius of the orbit
G is the gravitational constant (approximately 6.67430 × 10⁻¹¹m³ kg⁻¹ s⁻²)
M is the mass of the Earth (approximately 5.972 × 10²⁴ kg)
T is the period of the orbit
Substituting these values into the equation:
[tex]r = (\frac{G \times M \times T^2}{4\pi^2})^{(1/3)}[/tex]
[tex]r = \frac{6.67430 \times 10^{-11} \times 5.972 \times 10^{24} \times (5700)^2}{(4\pi^2)^{(1/3)}}[/tex]
r = 1.135 × 10⁷ meters
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