Find the volume of the following cone. Use 3.14 for π.

A. 9847.04 cubic meters


B. 39388.16 cubic meters


C. 10257.33 cubic meters


D. 41029.33 cubic meters

Find The Volume Of The Following Cone. Use 3.14 For .A. 9847.04 Cubic MetersB. 39388.16 Cubic MetersC.

Answers

Answer 1

Answer:

Step-by-step explanation:

Radius

= 28 ÷ 2

= 14 m

Volume

= 1/3 (3.14) (14)²(48)

= 1/3 (3.14) (196)(48)

= 9847.04 m³

Answer 2

Answer:  A. 9847.04 cubic meters

Step-by-step explanation:

From the given picture, we have

The diameter of the cone = 28 m

Then the radius of the cone = [tex]\dfrac{28}{2}=14\text{ m}[/tex]

Height of the cone = 48 inches

The volume of cone is given by :-

[tex]V=\dfrac{1}{3}\pi r^2h\\\\\Rightarrow V=\dfrac{1}{3}(3.14)(14)^2(48)\\\\\Rightarrow V=9847.04\text{ m}^3[/tex]

Hence, the volume of the cone = [tex]9847.04\text{ m}^3[/tex]


Related Questions

will mark brainliest pleassse help someone
Pyramid A is a square pyramid with a base side length of 9 inches and a height of 10 inches. what is the volume

Answers

Check the picture below.

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=&area~of\\ &its~base\\ h=&height\\ \cline{1-2} B=&\stackrel{9\times 9}{81}\\ h=&10 \end{cases}\implies V=\cfrac{1}{3}(81)(10)\implies V=270[/tex]

Kevin sold a house for $57,000 his fee or sales commission for selling the house was $2,679. What percent of the price of the price of the house was Kevin's commission

Answers

Answer:

4.7%

Step-by-step explanation:

Kevin's commission was 4.7% of the price of the house.

Calculate the percentage by dividing Kevin's commission by the selling price: $2,679 / $57,000 = 0.047.Multiply the result by 100 to get the percentage: 0.047 * 100 = 4.7%.

A function is created to represent the amount of money you save or spend each day of the week. What restrictions would be made to the range?

A) The range would only include integers.
B) The range would only include positive integers.
C) The range would only include negative integers.
D) The range would include all real numbers.

Answers

The range would only include positive integers.

Answer B

In 1990 the enrollment at Trenton East High School was 840. From 1990 through 1996 the enrollment increased at an average rate of 24 students per year. Write a linear model for the enrollment at Trenton East High School. Let x represent the number of years since 1990. Trenton East was built to hold 900 students. Write a linear inequality that represents the possible number of years since 1990 when the school's enrollment was less than the maximum capacity for which the school was built. Solve the inequality.​

Answers

Answer:

X x 26= 26x +840

Step-by-step explanation:

Answer:

See below in bold.

Step-by-step explanation:

Linear model:

E = 24x + 840   where E is the  enrolment .

If there are 900 students then

900 = 24x + 840

24x = 900-840 = 60

For  E < 900 we have the inequality

24x < 60

x < 2.5

As we are dealing in years our answer is

x <  3 years .

What is the area of a circle with a diameter of 12.6 in.?

Use 3.14 for pi and round your final answer to the nearest hundredth.


Enter your answer in the box.

Answers

Hey there! I'm happy to help!

To find the area of a circle, you square the radius and then multiply by pi (3.14 in our case).

The radius is half of the diameter.

12.6/2=6.3

We square this.

6.3²=39.69

We multiply by 3.14

39.69×3.14=124.6266

We round to the nearest hundredth, giving us an area of 124.63 in².

Now you can find the area of a circle! Have a wonderful day! :D

You can use formula for area of circle which simply is pi times square of radius. The radius is half of diameter.

The area of the given circle is 124.63 sq inches

Given that:A circle has diameter of 12.6 inches.To find:

Area of circle using pi = 3.14 and approximated to nearest hundredth.

Formula for Area of circle with radius r units:

[tex]\text{Area} = \pi \times r^2[/tex]

Finding radius:

[tex]\text{Radius} = \dfrac{\text{diameter}}{2}\\ r = \dfrac{12.6}{2} = 6.3 \: \rm inch[/tex]

Finding the area:

[tex]Area = \pi \times r^2 \approx 3.14 \times 6.3^2 \approx 124.626 \approx 124.63 \: \rm inch^2[/tex]

Thus, the area of the given circle is 124.63 sq inches

Learn more about area of circle here:

https://brainly.com/question/266951

(I've been trying to figure this out for 3 days and I really need help)

1. You are opening a snow cone stand. Your cups, which are shaped like a cone, are 4" tall and have a 6" diameter. How much room is there in the cone without a top on the snow cone? (filled to the brim only)

2. The top of your snow cone is a perfect semicircle. It goes all the way across the cone. How many cubic inches of ice in the top of the snow cone?

3. How many cubic inches of snow cone will you be serving?

4.You want to start selling 2 different sizes of cones. You want your new cone to be twice as big as your current cone (top included). You found a cone that has a 6" diameter and is 8" tall. How many cubic inches of snow cone will you have with the new cone?

Answers

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7[/tex]

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55[/tex]

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

[tex]\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^[/tex]

A company makes concrete bricks shaped like rectangular prisms. Each brick is 15 inches long, 10 inches wide, and 5 inches tall. If they used 15000 in cubed of concrete, how many bricks did they make?

Answers

Answer:

20 bricks

Step-by-step explanation:

So if you multipy the dimentions given, you get 750 inches squred. You now take 15,000 and divide it by 750 to get 20. This is your answer.

A company makes 20 concrete bricks.

How many bricks did the company make?

Given:

A company makes concrete bricks shaped like rectangular prisms.Each brick is 15 inches long, 10 inches wide, and5 inches tall.They used 15000 in cubed concrete.

Find:

How many bricks did they make?

Solution:

A company makes concrete bricks shaped like rectangular prisms.

So, the volume of the brick = 15*10*5 = 750[tex]inches^{3}[/tex]

Now, to find how many bricks they make we have to divide 750[tex]inches^{3}[/tex] from 15000.

Number of brick = 15000/750 = 20

Hence, the number of bricks that the company makes is 20.

To learn more about rectangular shape, refer to:

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#SPJ2

what value is needed to complete the square?

1. x^2-2x+___

2. x^2-6x+___

Answers

Answer:

1 and 9

Step-by-step explanation:

To complete the square

add ( half the coefficient of the x- term)²

1

x² + 2(- 1)x + (- 1)² = x² - 2x + 1 = (x - 1)²

2

x² + 2(- 3)x + (- 3)² = x² - 6x + 9 = (x - 3)²

To complete the square for the expressions x² - 2x + ___ and x² - 6x + ___, the required values are 1 and 9, respectively, because these are the squares of half the coefficients of the x terms.

To complete the square for a quadratic expression, we need to add a term that will turn the expression into a perfect square trinomial. For the general form x² + bx + c, the value needed to complete the square is (b/2)².

In the case of x² - 2x + ___, the value of b is -2. Therefore, you need to add (-2/2)² = (1)² = 1.

For the second expression, x² - 6x + ___, the value of b is -6. Here, you add (-6/2)² = (3)² = 9.

So, the values needed to complete the square are:

For x² - 2x + ___, the value is 1.

For x² - 6x + ___, the value is 9.

When Mario has to leave the house for a while, he tethers his mischievous puppy to the corner of a 12 ft-by-8 ft shed in the middle of his large backyard. The tether is 18 feet long. Which description fits the boundary of the locus of points in the yard that the puppy can reach?

A a three-quarter circle of radius 18 ft, quarter circles of radii 10 ft and 6 ft

B a three-quarter circle of radius 18 ft, quarter circles of radii 12 ft and 8 ft

C semicircles of radii 18 ft, 10 ft, and 6 ft

D semicircles of radii 18 ft, 12 ft, and 8 ft

Answers

Answer:

a three-quarter circle of radius 18 ft, quarter circles of radii 10 ft and 6 ft

Step-by-step explanation:

i took the test and i got this as the right answer

Answer:

A a three-quarter circle of radius 18 ft, quarter circles of radii 10 ft and 6 ft

Step-by-step explanation:

In order to calculate this, you have to remember that you have a tether that is 18 ft long, thetered to a point, this would make a circle with a radius of 18 ft, but as the center of the circle would be where the theter is knotted, the shed forbids to make a full circle, it rather creates a 3/4 circle, and the dog can acces the other points of the shed, with le length of the theter, that is 8 ft after the long side, and 12 feet after the short side, creating another quarter circle with a radius of 8 and 12 ft.

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.

r = 4 cos 3θ

Answers

Answer:

It is symmetric about the x-axis because cos(3θ) = cos(-3θ).

It is not symmetric about the y-axis because cos(3θ) is not equal to cos(3(pi-θ)).

It is not symmetric about the origin because cos(3θ) is not equal to -cos(3θ).

Answer:

The graph is symmetric about x- axis.

Step-by-step explanation:

We are given that an equation

[tex]r=4 cos 3\theta[/tex]

We have to find the graph is symmetric  about x- axis , y-axis or origin.

We taking r along y-axis and [tex\theta [/tex] along x- axis

When the graph is symmetric about x= axis then (x,y)=(-x,y)

[tex] \theta [/tex] is replaced by [tex]-\theta[/tex] and r remain same then we get

[tex] r=4cos (-3\theta)[/tex]

We know that cos (-x)=cos x

Therefore, [tex] r=4cos 3\theta[/tex]

Hence, the graph is symmetric about x- axis.

When the graph is symmetric about y- axis then (x,y)=(x,-y)

Now, r is replaced by -r then we get

[tex]-r=4cos 3\theta [/tex]

[tex] r=-4 cos {3\theta}[/tex]

[tex] r=4 cos {\pi-3\theta}[/tex]

Therefore, the graph is not symmetric about y-axis.

When the graph is symmetric about y- axis then (x,y)=(x,-y)

Now, r is replaced by -r then we get

[tex]-r=4cos 3\theta [/tex]

[tex] r=-4 cos3\theta[/tex]

[tex] r=4 cos (\pi-3\theta)[/tex]

[tex](\theta,r)\neq (\theta,-r)[/tex]

Therefore, the graph is not symmetric about y-axis.

When the graph is symmetric about origin then (-x,-y)=(x,y)

Replaced r by -r and [tex]\theta [/tex] by-[tex]\theta[/tex]

Then we get [tex] -r=4cos3(-\theta)[/tex]

[tex] -r= 4 cos 3\theta[/tex]

Because cos(-x)=cos x

[tex] r=-4 cos 3\theta [/tex]

[tex](-\theta,-r)\neq(\theta,r)[/tex]

Hence, the graph is not symmetric about origin.

Stefan's family rented a rototiller to prepare an area in their backyard for spring planting. The rental company charged an initial fee of $43 with an additional fee per hour. If they paid $64 after renting the rototiller for 7 hours, what was the hourly fee?

Answers

Answer:

The hourly fee is $ 3.

Step-by-step explanation:

Given,

The initial fee = $ 43,

Let x be the additional hourly fee ( in dollars ),

Thus, the total additional fee for 7 hours = 7x dollars,

And, the total fee for 7 hours = Initial fee + Additional fee for 7 hours

= ( 43 + 7x ) dollars,

According to the question,

43 + 7x = 64

7x = 21      ( Subtracting 43 on both sides )

x = 3          ( Divide both sides by 7 )

Hence, the hourly fee is $ 3.

Answer:

7h+43=64

$3

Step-by-step explanation:

did it on edge

The dairy cows on Mr. Aaron's farm eat 9,315 pounds of grain in 3 months.How many pounds of grain will the cows eat in one month.

Answers

Answer:

3,105

Step-by-step explanation:

the answer is 3,105 because you simply take the total number that was eaten in 3 months and divide it by 3 since they only want to know what was eaten in 1 month

Convert 135 degrees to radians.

Question 2 options:

2π/3radians

π radians

π/2radians

3π/4radians

Answers

ANSWER

[tex] \frac{3\pi}{4} \: radians[/tex]

EXPLANATION

To convert an angle from degrees measure to radians, we multiply by:

[tex] \frac{\pi}{180 \degree} [/tex]

We want to convert 135° to radians.

This implies that,

[tex]135 \degree = 135\degree \times \frac{\pi}{180 \degree} = \frac{3\pi}{4} \: radians[/tex]

The last option is correct.

The function[tex]f(x)=-3x^{3} +x^{2} +2x[/tex] rises as x grows very small.

A. True
B. False

Answers

Answer:

True

Step-by-step explanation:

True.

Like the cubic term -3x^3 is negative, for small values of "x", the dependent variable "y" will rise. All this can be verified by looking at the graph.

40 POINTS PLEASE HURRY
Pete grabbed 18 mixed nuts, 2/9 of which were almonds. Which equation shows how to determine the number of almonds Pete grabbed?
A.18 divided by 2/9 =81
B. 18 x 2/9 = 4
C. 2/9 divided by 18=1/81
D. 9/2 divided by 18=1/4

Answers

Answer:

B 18*2/9 =4

Step-by-step explanation:

To determine the number of mixed nuts that were almonds, take the number of nuts and multiply by the fraction that were almonds

nuts * 2/9= almonds

18 * 2/9

36/9

4

Matrix X is shown below.


If matrices X and Y are equal, what is the value of y12+y13+y32+y33?
7.5
27
40
49.5

Answers

Answer:

option C

40

Step-by-step explanation:

[tex]x_{nm}[/tex]

here n = number of row

        m = number of column

so the labelled 3x3 matrix would be like this

[tex]y=\left[\begin{array}{ccc}y11&y12&y13\\y21&y22&y23\\y31&y32&y33\end{array}\right][/tex]

Given in the question matrixX since matrixY is eaxctly same as matrixX so,  

[tex]y=\left[\begin{array}{ccc}1&6&-7\\-5&0&8.5\\-1&14&27\end{array}\right][/tex]

so

y12 = 6

+

y13 = -7

+

y32 = 14

+

y33 = 27

=

40

Answer:

The answer C, is right!

Step-by-step explanation:





What is the quotient (x3 – 3x2 + 5x – 3) ÷ (x – 1)?















What is the quotient (x3 + 3x2 + 5x + 3) ÷ (x + 1)?

Answers

Answer:

x^2 -2x +3x^2 +2x +3

Step-by-step explanation:

The quotient in each case can be found by any of several means, including synthetic division (possibly the easiest), polynomial long division, or graphing.

1. The graph shows you the quotient is (x-1)^2 +2 = x^2 -2x +3.

2. The graph shows you the quotient is (x+1)^2 +2 = x^2 +2x +3.

Graph each function. Label x-axis.​

Answers

Answer:

Here's what I get.

Step-by-step explanation:

Question 4

The general equation for a sine function is

y = a sin[b(x - h)] + k

where a, b, h, and k are the parameters.

Your sine wave is

y = 3sin[4(x + π/4)] - 2

Let's examine each of these parameters.

Case 1. a = 1; b = 1; h = 0; k = 0

y = sin x

This is a normal sine curve (the red line in Fig. 1).

(Sorry. I forgot to label the x-axis, but it's always the horizontal axes)

Case 2. a = 3; b = 1; h = 0; k = 0

y = 3sin x

The amplitude changes from 1 to 3.

The parameter a controls the amplitude of the wave (the blue line in Fig. 1).

Case 3. a = 3; b = 1; h = 0; k = 2

y = 3sin x - 2

The graph shifts down two units.

The parameter k controls the vertical shift of the wave (the green line

in Fig. 1).

Case 4. a = 3; b = 4; h = 0; k = 2

y = 3sin(4x) - 2

The period decreases by a factor of four, from 2π to π/2.

The parameter b controls the period of the wave (the purple line in Fig. 2).

Case 5. a = 3; b = 4; h = -π/4; k = 2

y = 3sin[4(x + π/4)] - 2

The graph shifts π/4 units to the left.

The parameter h controls the horizontal shift of the wave (the black dotted line in Fig. 2).

[tex]\boxed{a = 3; b = 4; h = \frac{\pi}{2}; k = -2}}[/tex]

[tex]\text{amplitude = 3; period = } \dfrac{\pi}{2}}[/tex]

[tex]\textbf{Transformations:}\\\text{1. Dilate across x-axis by a scale factor of 3}\\\text{2. Translate down two units}\\\text{3. Dilate across y-axis by a scale factor of } \frac{1}{4}\\\text{4. Translate left by } \frac{\pi}{4}[/tex]

Question 6

y = -1cos[1(x – π)] + 3

[tex]\boxed{a = -1, b = 1, h = \pi, k = 3}[/tex]

[tex]\boxed{\text{amplitude = 1; period = } \pi}[/tex]

Effect of parameters

Refer to Fig. 3.

Original cosine: Solid red line

m = -1: Dashed blue line (reflected across x-axis)

 k = 3: Dashed green line (shifted up three units)

 b = 1: No change

h = π: Orange line (shifted right by π units)

[tex]\textbf{Transformations:}\\\text{1. Reflect across x-axis}\\\text{2. Translate up three units}\\\text{3. Translate right by } \pi[/tex]

Which of the following functions is quadratic?

Answers

Answer:sd

D. [tex]f\left(x\right)=2x^2+3x-5[/tex]

Step-by-step explanation:

Given choices are:

[tex]f\left(x\right)=\frac{2}{x^2}[/tex]

[tex]f\left(x\right)=3\left(3-x\right)[/tex]

[tex]f\left(x\right)=7^2[/tex]

[tex]f\left(x\right)=2x^2+3x-5[/tex]

Now we need to find about which of them is the quadratic function.

We know that quadratic function is written in form of [tex]f\left(x\right)=ax^2+bx+c[/tex]

Last choice looks similar to that form.

Hence coorect choice is D. [tex]f\left(x\right)=2x^2+3x-5[/tex]

Answer:

D. f(x) = 2x^2 + 3x - 5

Step-by-step explanation:

Which expression has a negative value?

Answers

Answer:

im pretty sure its d

Step-by-step explanation:

-35/5 is the answer

** WILL GIVE 15 POINTS FOR THIS ONE QUESTION + BRAINLIEST **

The graph below shows the solution to a system of inequalities:

Which of the following any qualities is modeled by the graph?

Answers

Answer:

  x + 4y ≤ 15; y ≥ 0

Step-by-step explanation:

The graph doesn't do a very good job of modeling any of the given equations. However, the equations listed above seem the best fit.

The slope of the top (left) line is negative, so the equation will be of the form ...

  x + 4y = something

When y=0, x=15, so the "something" is expected to be 15.

However, the line appears to go through points (6, 2) and (-2, 4). Both of these points are on the line x + 4y = 14.

The graph is shaded below the line so the values of x and y that are in the shaded area will add to less than 15 (or 14). Hence, the inequality will be ...

  x + 4y ≤ something . . . . . part of the 3rd answer choice

The fact that the shading does not go below y=0 means the other limit is ...

  y ≥ 0 . . . . . part of every answer choice.

A rectangular ower garden is 5.3 yards wide and 9.4 yards long. A uniform path of

width 2 yards is laid around the garden. Find the area of the path.

Answers

Answer:

  74.8 square yards

Step-by-step explanation:

The centerline of the path is a rectangle 5.3+2 = 7.3 yards wide and 9.4+2 = 11.4 yards long. The perimeter of that rectangle is 2(7.3+11.4) = 37.4 yards long. The area of the path is this length times the width of the path:

  path area = (37.4 yd)(2 yd) = 74.8 yd²

The area of the path is 74.8 square yards.

First, we calculate the area of the garden:

[tex]\[ A_{\text{garden}} = \text{length} \times \text{width} = 9.4 \text{ yards} \times 5.3 \text{ yards} \][/tex]

[tex]\[ A_{\text{garden}} = 49.82 \text{ square yards} \][/tex]

Next, we need to find the area of the entire region including the path. The path adds an additional width of 2 yards on all sides of the garden.

The total length and width of the region including the path are:

[tex]\[ \text{Total length} = 9.4 \text{ yards} + 2 \times 2 \text{ yards} = 13.4 \text{ yards} \][/tex]

[tex]\[ \text{Total width} = 5.3 \text{ yards} + 2 \times 2 \text{ yards} = 9.3 \text{ yards} \][/tex]

Now we calculate the area of the entire region including the path:

[tex]\[ A_{\text{total}} = \text{Total length} \times \text{Total width} = 13.4 \text{ yards} \times 9.3 \text{ yards} \][/tex]

[tex]\[ A_{\text{total}} = 124.62 \text{ square yards} \][/tex]

Finally, we subtract the area of the garden from the total area to find the area of the path:

[tex]\[ A_{\text{path}} = A_{\text{total}} - A_{\text{garden}} \][/tex]

[tex]\[ A_{\text{path}} = 124.62 \text{ square yards} - 49.82 \text{ square yards} \][/tex]

[tex]\[ A_{\text{path}} = 74.8 \text{ square yards} \][/tex].

Jacob has 24 pieces of gum. He gives 3/4 of them away. How many pieces of gum does he have remaining?

Answers

Answer:

Step-by-step explanation: 6?

A company mixes pecans, cashews, peanuts, and walnuts to make a batch of mixed nuts. About 15.4% of the mixed nuts in a batch are pecans. If a batch contains 77 pounds of pecans, how many pounds of mixed nuts are in a batch altogether? Enter your answer in the box.

Answers

Answer:

500 lb

Step-by-step explanation:

You have to make a proportion:

[tex]\frac{part}{whole} = \frac{percent}{100}[/tex]

77 lb is part of the whole weight ( which we don't know) so 77 will go on top

The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

[tex]\frac{77}{x} = \frac{15.4}{100}[/tex]

Then you cross multiply giving you: 7700 = 15.4x

then you divide 15.4 to both sides to isolate x which will give you 500

Final answer:

To find the total weight of a batch of mixed nuts where pecans make up 15.4% and weigh 77 pounds, we set up a proportion and solve for the total weight, resulting in 500 pounds for the whole batch.

Explanation:

The question asks how many pounds of mixed nuts are in a batch altogether if 77 pounds are pecans, which represent 15.4% of the mix. To find the total weight, we need to set up a proportion where 15.4% corresponds to 77 pounds, and we want to find 100% (the whole mix).

We can set up the equation like so: 15.4 / 100 = 77 / x, where x stands for the total weight of the mixed nuts. To find x, we solve for x using algebra: x = 77 / (15.4 / 100). When you perform the calculation, the result is x = 500 pounds. So, the batch of mixed nuts weighs 500 pounds in total.

Solve the problem by writing an inequality. A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work.

Answers

Hello there i hope you are having good day :) Question : Solve the problem by writing an inequality. =  A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work? = So firstly  the each of the shirt cost $12 and the money made for the shirt equals 12$ so the cost per the shirt would be 20 + 8x that lead to needing at least 100$  amount made - cost = profit would equal to 12x - (20-8x) ≥ 100 then you would do 12x-20-8x = 100 then you would also do 4x-20 = 100 then you add 20 and add 20 again that would equal 4x/4x = 120/4  that would finally lead you to the answer that would be x = 30 --->  x ≥ 30Hopefully this help you.

If sin θ = 3 over 7 and tan θ < 0, what is the value of cos θ? negative square root of 10 negative 2 square root of 10 2 square root of 10 over 7 negative 2 square root of 10 over 7

Answers

Answer:

negative 2 square root of 10 over 7

Step-by-step explanation:

A certain forest covers an area of 2600 km 2 suppose that each year this area decreases by 9% . What will the area be after 5 years ?

Answers

Answer:

Final answer is approx 1622.48 square kilometers.

Step-by-step explanation:

Given that a certain forest covers an area of 2600 km 2 suppose that each year this area decreases by 9% . Now we need to find about what will the area be after 5 years.

So we need to plug these values into decay formula which is given by:

[tex]A=P(1-r)^t[/tex]

Where P=2600

r= rate = 9%= 0.09

t=time = 5 years

Plug these values into above formula, we get:

[tex]A=2600(1-0.09)^5[/tex]

[tex]A=2600(0.91)^5[/tex]

[tex]A=2600(0.6240321451)[/tex]

[tex]A=1622.48357726[/tex]

Hence final answer is approx 1622.48 square kilometers.

Final answer:

Using the exponential decay formula, A = A_0 (1-r)^t, the forest area after 5 years with an annual decrease of 9% is approximately 1622.4 km².

Explanation:

To calculate the forest area after 5 years with an annual decrease of 9%, we can use the formula for exponential decay. The original area of the forest is 2600 km2.

Formula for exponential decay: A = A_0 (1-r)^t, where A is the area after time t, A_0 is the original area, r is the rate of decrease, and t is time in years.Convert the percentage to a decimal: r = 9% or r = 0.09.Substitute the values into the formula: A = 2600 (1-0.09)^5.Calculate: A ≈ 2600 (0.91)^5.Compute the final area: A ≈ 2600 * 0.624 ≈ 1622.4 km2.

So, if the forest continues to decrease by 9% annually, the area will be approximately 1622.4 km2 after 5 years.

MATH HELP

use distance = rate time (d=rt) to find the number of miles per hour Etty must drive to go 45 miles in 35 minutes. ( remember time is written in hours?

Answers

Answer:

rate=1.28571428571.. (1.29) miles per minute, or 77.1428571429.. (77.14) mph

Step-by-step explanation:

"use distance = rate time (d=rt) to find the number of miles per hour Etty must drive to go 45 miles in 35 minutes. ( remember time is written in hours?"

distance=rate*time--- we know distance and time

45 mi= rate*35

rate=45/35

rate=1.28571428571 miles per minute, or 77.1428571429 mph

Answer:

Step-by-step explanation:

77/14mph

Let A = {x | x < 5} and B = {x | x ≤ 7}. Find A B.

Answers

Answer:

A B = {x | x < 5}

Step-by-step explanation:

The domain of A B will be given by {x | x < 5}

The domain of A is given as  {x | x < 5} while that of B is {x | x ≤ 7}. From this we can infer that the domain of A is a subset of B since A is contained in B. The domain of A B is simply the intersection of these two sets which is A.

Which solid does NOT have the net form? hexagonal prism hexagonal pyramid rectangular prism rectangular pyramid

Answers

Answer:

hexagonal pyramid

Step-by-step explanation:

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