Find the value of x in the triangle above

Answer:

1. 90 sq. cm

2. 96 sq. cm

3. 72 sq. cm

4. 72 sq. cm

5. 92 sq. cm

6. 68 sq. cm

Step-by-step explanation:

Answer:

  Equation 3: y = 12x + 17

Step-by-step explanation:

Only a linear equation (degree 1) will have a graph that is a straight line.

The degree of the equation is the highest power of any of the variables. If different variables are in the same term, it is the sum of the powers of those variables.

Answer:

Equation 3: y = 12x + 17

Step-by-step explanation:

It is the answer because all of the variables have an exponent of 1.

Answer:

  11.2 miles

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Tan = Opposite/Adjacent

The side you are given is adjacent to the given angle, and the side you are asked to find is opposite the given angle. You can fill in the given values and solve for the required measure.

  tan(66°) = BC/(5 mi)

Multiplying by 5 mi gives ...

  BC = (5 mi)·tan(66°) = (5 mi)·2.246 = 11.23 mi ≈ 11.2 mi

Answer:

x=2

Step-by-step explanation:

Answer:

D. An exponential function, because exponential functions increase at a nonconstant rate

Step-by-step explanation:

Each month Tai's brother grows more than he grew the previous month.

We can't model his growth by a linear function, because linear functions increase at a constant rate.

The model must be an exponential function.

For example, if the boy's height at Month 0 were 100 units, a model like h = 100(1.1)ⁿ would give the following results.

[tex]\begin{array}{ccc}\textbf{Month} & \textbf{Height} & \textbf{Diff.}\\0 & 100 & \\1 & 110 & 10\\2 & 121 & 11\\3 & 133 & 12\\4 & 146 & 13\\\end{array}[/tex]

An [tex]\boxed{\textbf{ exponential function }}[/tex] is consistent with a monthly change in height that increases each month.

Answer:

D. 5000 kg

Step-by-step explanation:

We assume the second train was standing still and that momentum is conserved. The the product of mass and velocity before the collision is

(5000 kg)·(100 m/s) = 500,000 kg·m/s.

After the collision, where M is the mass of the second train, the momentum is ...

((5000+M) kg)·(50 m/s) = 500,000 kg·m/s

Dividing by 50 m/s and subtracting 5000 kg, we have ...

(5000 +M) kg = 10,000 kg

M kg = 5000 kg

The mass of the second train is 5000 kg.

Answer:

D. 5000 kg

Step-by-step explanation:

Answer:

10 friends

Step-by-step explanation:

we know that

The formula of the sum is equal to

[tex]sum=\frac{n}{2}[2a1+(n-1)d][/tex]

where

a1 is the first term

n is the number of terms (number of friends)

d is the common difference in the arithmetic sequence

In this problem we have

[tex]sum=275\ stickers[/tex]

[tex]a1=5\ stickers[/tex]

[tex]d=5[/tex] ----> the common difference

substitute in the formula and solve for n

[tex]275=\frac{n}{2}[2(5)+(n-1)(5)][/tex]

[tex]550=n[10+5n-5]\\ \\550=10n+5n^{2} -5n\\ \\5n^{2}+5n-550=0[/tex]

Solve the quadratic equation by graphing

The solution is n=10

see the attached figure

therefore

She had 10 friends who got stickers

Answer:

the blue and green marbles are evenly matched, fifty and fifty

each time a single colored pair is drawn, there is now an "extra" unpaired marble of the other color this extra marble must eventually be drawn along with one of the same color

the number of marbles in the A and B boxes can be anywhere from zero to fifty, but it is the SAME for both boxes

Answer:

A. The graph of the function increases and decreases over its domain.

Step-by-step explanation:

The graph is attached. Some places, it has positive slope (is increasing); other places it has negative slope (is decreasing).

Answer:

[tex]14\ candles[/tex]

Step-by-step explanation:

step 1

Find the volume of the cylindrical mold

The volume is equal to

[tex]V=\pi r^{2} h[/tex]

we have

[tex]r=3.4\ cm[/tex]

[tex]h=6\ cm[/tex]

assume

[tex]\pi=3.14[/tex]

substitute

[tex]V=(3.14)(3.4)^{2}(6)[/tex]

[tex]V=217.79\ cm^{3}[/tex]

step 2

Find the volume of the wax

The volume is equal to

[tex]V=(15)(12)(18)[/tex]

[tex]V=3,240\ cm^{3}[/tex]

step 3

Divide the volume of the wax by the volume of the cylindrical mold, to calculate the number of candles

[tex]3,240/217.79=14.9\ candles[/tex]

Round down

[tex]14\ candles[/tex]

Answer:

The average rate of change is [tex]=-4[/tex]

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

[tex]=\frac{f(b)-f(a)}{b-a}[/tex]

We want to find the average rate of change of the function represented in the table  from x=-2 to x=2.

[tex]=\frac{f(2)-f(-2)}{2--2}[/tex]

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

[tex]=\frac{9-25}{2--2}[/tex]

[tex]=\frac{-16}{4}[/tex]

[tex]=-4[/tex]

Answer:

-4

Step-by-step explanation:

Answer:

156.25% =P

Step-by-step explanation:

Is means equals and of means multiply

50 = P * 32

Divide each side by 32

50/32 = 32P/32

1.5625= P

Now we need to change it to percent form by multiplying by 100%

1.5625 * 100% = P

156.25% =P

Answer:

The length of the field is 84 yards

Step-by-step explanation:

Since the area of a rectangle is width times the length, we can write a simple equation.

Let w be the width

Let l be the length

W*L = 4284

Since we know the width of the rectangle is 51 yards, we can plug it in.

51L = 4284

Dividing 51 on both sides,

L = 84

Answer:

  a) monthly payment: $177.50

  b) total amount paid: $31,950

  c) toward principal: $17,500; toward interest: $14,450

Step-by-step explanation:

a) The amount of the monthly payment (A) is computed from the principal (P), the annual interest rate (r) and the number of years (n) using the formula ...

  A = P·(r/12)/(1 -(1 +r/12)^(-12n))

Filling in your numbers, we can use r/12 = 0.09/12 = 0.0075, and 12n = 12·15 = 180:

  A = $17500·0.0075/(1 - 1.0075^-180) ≈ $177.50

__

b) The total payment over the term of the loan is 180 of these monthly payments:

  180·$177.50 = $31,950

__

c) $17,500 is paid toward the principal.

 $14,450 is paid toward interest.

Answer:

8 E -28

Step-by-step explanation:

Use the 2nd button and the comma button to get the "EE" which puts numbers into scientific notation for you.  I use parenthesis and this is what my screen looks like right before I hit "enter" to get the answer:

[tex](4.4 E-10)/(5.5E17)[/tex]

Hit enter and you get 8 E -28

Answer:

8E -28

.

Step-by-step explanation:

Answer:

The area of one side of the tank is [tex]25ft^{2}[/tex]

Step-by-step explanation:

A cube is a regular Polyhedron limited by six equal squares. It is also known as the regular hexahedron, or simply hexahedron.

The cube is a ortohedron, that is, it has its six faces straight and perpendicular to each other. In addition to being their rectangle faces, they are also square.

It has the following properties:

*Number of faces: 6

*Number of vertices: 6

*Number of edges: 12

*Number of edges from one vertex: 3

Being the length of the edge of the cube, then its Volume (V) is expressed by the formula: [tex]v=a^{3}[/tex] Being a the length of the edge of the cube

A fish tank is the shape of a cube. Its volume is [tex]125ft^{3}[/tex], to calculate the are of one side of the tank, we know that each faces has the form of a square of area [tex]a^{2}[/tex].

To calculate the value of a.

[tex]a=\sqrt[3]{125ft^{3} } =5ft[/tex]

Then the area of square is [tex]a^{2}[/tex]

Substituting the value of a

[tex](5ft)^{2} =25ft^{2}[/tex]

Answer:

25 feet squared

Step-by-step explanation:

Answer:

#3. (x-7)(x-4)   #5. (2k+7)(k-2)

Step-by-step explanation:

For #3 you have to first get all the terms on one side of the equals sign and set it equal to 0.  So that gives us

[tex]x^{2} -11x+28=0[/tex].

Our a value is 1 and our c value is 28, so the product of those is 28.  Find the factors of 28 and the combination of those factors that add up to equal the linear term -11x is the combination we need for our problem.  The factors of 28 are:  1, 28; 2, 14; 4, 7.  4 and 7 give us 11 when we add them, but since we need a -11, we have to use the negative of both the factors since -7 + -4 = -11.  Set up your equation now using the -7 and the -4, "larger" number first (the absolute value which makes the 7 larger):

[tex]x^{2} -7x-4x+28[/tex].  This is the pattern that you will use to factor the next problem, as well.

Group the terms in groups of 2 to get:

[tex](x^{2} -7x)-(4x-28)=0[/tex].  Notice the sign change in front of the 28 in the second set of parenthesis.  This is because if I distribute the negative infront of the parenthesis back in, negative times a negative will give us the +28 in the original problem.  The same will apply again in #5 when we get there.

Now factor out whatever is common from each set of parenthesis:

[tex]x(x-7)-4(x-7)=0[/tex].

Now the common term is the factor (x-7) so that can be factored out now, leaving behind:

(x-7)(x-4).  That's the answer for #3.

Now for #5:

We will start by getting everything on one side (I am changing the k's to x's):

[tex]2x^{2} +3x-14=0[/tex].

The product of our a value and c value is again 28.  Find the combination of the factors of 28 that will add to give us the middle (linear) term of 3:  That is again 7 and 4, with the 7 needing to be positive and the 4 needing to be negative since 7 - 4 = 3.  Set up our expanded quadratic as follows, "larger" number (the absolute value of) first:

[tex]2x^{2} +7x-4x-14=0[/tex].

Group them into groups of 2 again:

[tex](2x^{2} +7x)-(4x+14)=0[/tex]

Again, notice the necessary sign change so when we distribute the negative back into the parenthesis we get the -14 we started with in the original problem.

Now factor out what is common from each set of parenthesis:

[tex]x(2x+7)-2(2x+7)=0[/tex].

What's common now is the factor (2x+7) so that can be factored out leaving behind

(2x+7)(x-2)=0

And you're done!!!

Is there more to the question,

Answer:

Option D. $1 million

Step-by-step explanation:

we know that

Reserve Ratio, it is the percentage of deposits which commercial banks are required to keep as cash

Find the 20% of $5 million

20%=20/100=0.20

0.20*5,000,000=$1,000,000

so

$1 million

The required reserve ratio is what banks must keep from a deposit. Given a 20% reserve ratio and a $5 million deposit, banks must reserve $1 million. Using the money multiplier formula, the remaining funds could theoretically create as much as $25 million in money supply.

The required reserve ratio is the percentage of deposits that a bank must hold as reserves. In this case, the required reserve ratio is 20 percent. The rest of the deposit (80 percent) can be loaned out or invested by the bank, which will create additional deposits and thus increase the money supply.

If a commercial bank receives a $5 million deposit and the required reserve ratio is 20 percent, the bank must keep $1 million (20 percent of $5 million) as reserve. The rest, $4 million, can be loaned out or invested.

However, this doesn't simply stop at $4 million. This loaned money will eventually be deposited back into the banking system (let's assume to another bank), which can then loan out 80% of that deposited money, and this cycle can continue. In an extremely simplified scenario, you can continue this process until the banks can no longer lend out money.

To simplify this scenario, the money multiplier formula can be used. The money multiplier formula is 1 divided by the reserve ratio. In this case, it's 1 / 0.20 = 5.  Therefore, a $5 million deposit can potentially lead to a $25 million increase in the money supply, so the answer is (a) $25 million.

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i would pick D as the answer.

The events of Lynn choosing a shirt and choosing a necklace are independent. The choice of one item does not affect the choice of the other. The correct answer is D) Independent - Randomly selecting a shirt does not affect randomly selecting a necklace.

The question asks whether the events of Lynn choosing a shirt and necklace are dependent or independent. In general, events are called independent if the outcome of one does not affect the outcome of another. In this scenario, picking a shirt does not change the options of necklaces and vice versa. Thus, the selection of a shirt has no effect on the selection of a necklace.

The correct answer is therefore: Independent. Randomly selecting a shirt does not affect randomly selecting a necklace. Even if Lynn picked a red, blue, or yellow shirt first, it wouldn't affect her choice of necklace. She will still have the same two necklaces to choose from regardless of what shirt she picks.

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Answer:

D

Step-by-step explanation:

Congruent means the same. Translating it just moves it somewhere else.

Answer: D) The two triangles are congruent because a translation does not change size and shape.

Step-by-step explanation:

Since all rigid motions create congruent figures , it means it do not change the shape and size of the figure.

So, translation does not change size and shape.

If a triangle is drawn and then translated, then they are congruent because a translation does not change size and shape.

Answer:

It is the last one. It is clearly less than 90 degrees.

Step-by-step explanation:

Could you please elaborate? Is there an equation?

Answer: What do you need to know?

Step-by-step explanation:

Answer:

3 feet long

Step-by-step explanation:

Answer: Brad's shadow is 3 feet long

Answer:

Part a) The polynomial for the area including the frame is

[tex](4x^{2}+72x+320)\ ft^{2}[/tex]

Part b) The polynomial for the perimeter including the frame is

[tex](72+8x)\ ft[/tex]

Part c) The perimeter of the picture including the frame when the width of the frame is 2 inches is equal to [tex]88\ ft[/tex]

Part d) The area of the picture including the frame when the width of the frame is 2 inches is equal to [tex]480\ ft^{2}[/tex]

Step-by-step explanation:

Let

x-----> the width of the frame

L-----> the length of the picture

W-----> the width of the picture

Part a) What is a polynomial for the area including the frame?

we have

The dimensions of the picture are

[tex]L=20\ in[/tex]

[tex]W=16\ in[/tex]

The area including the frame is equal to

[tex]A=(20+2x)(16+2x)\\ \\A=320+40x+32x+4x^{2}\\ \\A=(4x^{2}+72x+320)\ ft^{2}[/tex]

Part b) What is a polynomial for the perimeter including the frame?

we have

The dimensions of the picture are

[tex]L=20\ in[/tex]

[tex]W=16\ in[/tex]

The perimeter including the frame is equal to

[tex]P=2[(20+2x)+(16+2x)]\\ \\P=2[36+4x]\\ \\P=(72+8x)\ ft[/tex]

Part c) What is the perimeter of the picture including the frame when the width of the frame is 2 inches

we have

[tex]P=(72+8x)\ ft[/tex]

For x=2 in

substitute

[tex]P=72+8(2)=88\ ft[/tex]

Part d) What is the area of the picture including the frame when the width of the frame is 2 inches

we have

[tex]A=(4x^{2}+72x+320)\ ft^{2}[/tex]

For x=2 in

substitute

[tex]A=(4(2)^{2}+72(2)+320)=480\ ft^{2}[/tex]

The perimeter of a two-dimensional figure is the distance covered around it.

The polynomial for the area including the frame is [tex]\rm 4x^2+72x +320[/tex].

The polynomial for the perimeter including frame is [tex]\rm 72+8x[/tex].

The perimeter of the picture including the frame when the width of the frame is 2 inches is 88 feet.

The area of the picture including the frame when the width of the frame is 2 inches is 480 feet.

You are framing a picture with a frame of equal width on each side.

The width of the frame is 2 inches.

The length is 20 inches and the width is 16 inches.

The width of the frame is 2 inches.

The perimeter of a two-dimensional figure is the distance covered around it.

Let the width of the frame be x.

The length of the picture be L.

The width of the picture is W.

1. What is a polynomial for the area including the frame?

[tex]\rm Area \ of \ the \ frame = length \times width\\\\ Area \ of \ the \ frame = (20+2x) (16+2x)\\\\ Area \ of \ the \ frame = 320+40x+32x+4x^2\\\\ Area \ of \ the \ frame = 4x^2+72x +320[/tex]

The polynomial for the area including the frame is [tex]\rm 4x^2+72x +320[/tex].

2. What is a polynomial for the perimeter including the frame?

[tex]\rm Perimeter \ of \ the \ picture = 2 (length + width)\\\\ Perimeter \ of \ the \ picture = 2(20+2x+16+2x)\\\\ Perimeter \ of \ the \ picture = 2(36+4x)\\\\ Perimeter \ of \ the \ picture = 72+8x[/tex]

The polynomial for the perimeter including frame is [tex]\rm 72+8x[/tex].

3. What is the perimeter of the picture including the frame when the width of the frame is 2 inches.

[tex]\rm Perimeter \ of \ the \ picture = 72+8x\\\\Perimeter \ of \ the \ picture = 72+8(2)\\\\ Perimeter \ of \ the \ picture = 72+16\\\\Perimeter \ of \ the \ picture = 88\\\\[/tex]

The perimeter of the picture including the frame when the width of the frame is 2 inches is 88 feet.

4. What is the area of the picture including the frame when the width of the frame is 2 inches.

[tex]\rm Area \ of \ the \ frame = 4x^2+72x +320\\\\ Area \ of \ the \ frame = 4(2)^2+72(2)+320\\\\ Area \ of \ the \ frame=480[/tex]

The area of the picture including the frame when the width of the frame is 2 inches is 480 feet.

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Answer:

the answer is 1/5 because y/x gives you k

The constant of proportionality [tex]k[/tex] is [tex]\frac{1}{5}[/tex].

What is constant of proportionality.

The constant of proportionality is the constant value of the ratio between two proportional quantities.

                                                [tex]$k=\frac{y}{x}$[/tex]

Where [tex]k[/tex] is the constant of proportionality.

It is given that the table which shows the relationship [tex]y=kx[/tex] is,

x y

60 12

45 9

30 6

15 3

We have to find the value of [tex]k[/tex].

According to the formula of constant of proportionality,

Let,

[tex]${{k}_{1}}=\frac{{{y}_{1}}}{{{x}_{1}}}$[/tex]

[tex]${{k}_{1}}=\frac{12}{60}[/tex]

[tex]$\therefore {{k}_{1}}=\frac{1}{5}$[/tex]

Now,

Let,

[tex]${{k}_{2}}=\frac{{{y}_{2}}}{{{x}_{2}}}$[/tex]

[tex]${{k}_{2}}=\frac{9}{45}[/tex]

[tex]$\therefore {{k}_{2}}=\frac{1}{5}$[/tex]

The third is,

[tex]${{k}_{3}}=\frac{6}{30}[/tex]

[tex]$\therefore {{k}_{3}}=\frac{1}{5}$[/tex]

and

[tex]${{k}_{4}}=\frac{3}{15}[/tex]

[tex]$\therefore {{k}_{4}}=\frac{1}{5}$[/tex]

Hence, the Option [tex]$C$[/tex] is correct answer.

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Answer:

15%

Step-by-step explanation:

29,400-25,000 = 4,400

4,400/29,400 =0.14965

0.14965 x 100 = 14.965%

or round up to 15%

Final answer:

The rate of depreciation for Hugo's car is approximately 14.97%, calculated using the formula for the rate of depreciation and the given values of the original and the selling price.

Explanation:

To solve for the rate of depreciation of Hugo's car, we can use the following equation:

R = ((P - S) / P) × 100

Where:
R = rate of depreciation (%)
P = original price of the car
S = selling price of the car after one year

Given:
P = $29,400
S = $25,000

Substituting the values into the equation:

R = (($29,400 - $25,000) / $29,400) × 100

R = ($4,400 / $29,400) × 100

R = 0.14966 × 100

R = 14.966%

Hence, the annual rate of depreciation for Hugo's car is approximately 14.97%.

let's use engineering notation for the sake of brevity.

1 trillion is 1,000,000,000,000, or just 1E12, twelve zeros.

1 million is then 1E6, six zeros.

we know the discharge for one day is 3E12 gallons, and that'd do just fine for country A for 5 months.  How many gallons in 1 month only?

[tex]\bf \begin{array}{ccll} gallons&months\\ \cline{1-2} 3E12&5\\ x&1 \end{array}\implies \cfrac{3E12}{x}=\cfrac{5}{1}\implies 3E12=5x \\\\\\ \cfrac{3E12}{5}=x\implies 6E11=x\implies 600000000000=x[/tex]

if there are 200million inhabitants in A, namely 200E6 or 2E8 inhabitants, how many gallons per inhabitant from all those 6E11 gallons?

[tex]\bf \begin{array}{ccll} gallons&households\\ \cline{1-2} 6E11&2E8\\ x&1 \end{array}\implies \cfrac{6E11}{x}=\cfrac{2E8}{1}\implies 6E11=2E8x \\\\\\ \cfrac{6E11}{2E8}=x\implies \cfrac{600000000000}{200000000}=x\implies 3000=x[/tex]

Answer:

b.

Step-by-step explanation:

x-intercepts are found by factoring.  We will use standard factoring here since this one is straightforeward and has real zeros as its solutions.  

In our equation,

a = 2

b = 2

c = -4

The rules are to take a * c and then find the factors that number, determine which combination of those factors will give you the linear term (the term with the single x on it), and rearrange those signs accordingly.  Let's start with that:

Our a * c is 2 * -4 = -8.

We need the factors of |-8|:  1,8 and 2,4

Some combination of those factors needs to give us a +2x.  2,4 will work as long as the 4 is positive and the 2 is negative.

Now we put them back into the equation, the absolute value of the larger number first:

[tex]2x^2+4x-2x-4=0[/tex]

Now group the terms in sets of 2 without moving any of them around:

[tex](2x^2+4x)-(2x-4)=0[/tex]

In each set of parenthesis, pull out what is common to both terms.  In the first set, the 2x is common, and in the second set, the 2 is common:

[tex]2x(x+2)-2(x+2)[/tex]

Now what is common between both terms is the (x + 2), so pull that out, grouping what is remaining in its own set of parenthesis:

[tex](x+2)(2x-2)=0[/tex]

To find the zeros, remember that the Zero Product Property tells us that for that equation above to equal zero, one of those factors has to equal zero, so:

x + 2 = 0 or 2x - 2 = 0.  Solve both for x:

x = -2 so the coordinate is (-2, 0)

2x - 2 = 0 and

2x = 2 so

x = 1 so the coordinate is (1, 0)

Answer:

0.3

Step-by-step explanation:

To calculate the dilation factor of two similar figures, you simply need to establish the ratio of the dilated figure (in our case PQRS) to the original figure (ABCD) using the same relative side.  

In our case, we'll take the longest of the sides provided in each figure.

So, we divide 12.6 by 42 to know the dilation factor of the longest side, it will be the same for all other sides:

d = 12.6 / 42 = 0.3